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  • Run a shell command from Django

    - by Badifunky
    Hello, I'm developing a web page in Django (using apache server) that needs to call a shell command to enable/dissable some daemons. I'm try to do it with os.system(service httpd restart 1>$HOME/out 2>$HOME/error) and this command doesn't return anything. Any idea how can i fix this?

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  • onmouseover problems with JavaScript (rendered using django and django-imagekit)

    - by Michael Moreno
    I'm using Imagekit. View.py includes: def pics(request): p = Photo.objects.all() return render_to_response('Shots.html', {'p': p}) The following simple code in the template will generate associated images: {% for p in p %} <img src = "{{ p.display.url }}"> <img src = "{{ p.thumbnail_image.url }}"> {% endfor %} I'm attempting to generate a series of thumbnails {{ p.thumbnail_image.url }} which, when mouseover'd, will generate the slightly larger version of the image, {{ p.display.url }} via Javascript. The following code in the template attempts to do so: <html> <head> <HEAD> <script language="Javascript"> { image1 = new Image image2 = new Image image1.src = {{ p.thumbnail_image.url }} image2.src = {{ p.display.url }} </script> </head> <body> {% for p in p %} <a href="" onMouseOver="document.rollover.src= image2.src onMouseOut="document.rollover.src= image1.src"> <img src="{{ p.thumbnail_image.url }}" border=0 name="rollover"></a> {% endfor %} </body> </html> This will display the series of thumbnails, but the larger image will not display when mouseover'd. I believe it has to do with how I'm specifying the variable {{ p.display.url }}.

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  • Web App fails when moved to production environment. Which server permissions do I need?

    - by Ashley Ward
    I have developed a small web app. This app allows users to upload images. It also produces text files with the names of those images (the names are stored and retrieved to/from an MySQL Database.) I have developed this app using MAMP. To create the uploaded image files I use the PHP function imagejpeg('my/path/name.jpg') and to delete the files I use the PHP function unlink('folder1/folder2/name.jpg') to write to the text document I am using the function fopen('folder1/folder2/name.txt', 'w') all three of these functions produce errors related to permissions - now the site has been moved to a live hosting environment. Why is this? and what permissions do I need to set the folder's folder1 and folder2 to? I know that permission 777 is generally bad because it opens up your server to the public. However what I have found is that the functions fail to work unless I use 777 on the folders. Can anyone shed any light on my dilemma?

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  • How can i add Active Directory security groups to a SharePoint site to control permissions, rather than individual user accounts

    - by user574811
    SharePoint does integrate active directory accounts, of course, but how about security groups? Have a few sites where I'm fairly confident access is going through an existing Active Directory (AD) security groups (i.e. only an AD security group has been granted permissions through the 'People and Groups') In another situation, where I created the AD group and granted it permissions to a site, the customers were not able to access immediately. Eventually had to fast-track it and add the individuals to the People and Groups to keep the project going, but hoping not to have to maintain it that way. Any specific requirements of the security group in AD? Universal, Global, or domain local? Is there any time delay between modifying group members in AD and having that take effect in SharePoint?

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  • What permission(s) does an application pool identity required to manage other application pools?

    - by Mr Shoubs
    I have a web site (used to manage various parts of our software) that needs the permissions required to start/stop other application pools. I've created a user and set the app pool identity to custom, however the web app still can't start/stop the app pools. I get the following Error: System.UnauthorizedAccessException: Filename: redirection.config Error: Cannot read configuration file due to insufficient permissions at Microsoft.Web.Administration.Interop.AppHostWritableAdminManager.GetAdminSection(String bstrSectionName, String bstrSectionPath) at Microsoft.Web.Administration.Configuration.GetSectionInternal(ConfigurationSection section, String sectionPath, String locationPath) at Microsoft.Web.Administration.ServerManager.get_ApplicationPoolsSection() at Microsoft.Web.Administration.ServerManager.get_ApplicationPools() Discussion here suggests setting the application pool to local system or administrator, this does work, but I don't want to do this for security reasons (external support will need access this site). I did give the user higher permissions (as suggested here), starting by making it part of the local administrators group, but initially this didn't work, and giving the user read/write/mod permission on C:\Windows\System32\inetsrv\config also didn't work. I must have done something wrong as local administrator now works, however this still isn't what I want. So can anyone suggest the permissions I need to add to this user, and how can I apply them? An answer my problem (but different question) is here, but to clarify, I think I need to give an individual user "IIS Runtime Operation Permissions", does anyone know how to do this, if indeed this is the permissions I require?

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  • Why is it necessary to chmod o+r parent directory to fix 403 access forbidden error with Nginx and P

    - by davenolan
    This may be an Nginx wrinkle, or it may be because I don't understand Unix permissions. We're using Hudson CI to deploy our staging instance. So RAILS_ROOT is /var/lib/hudson/jobs/JOBNAME/workspace. Hudson runs as hudson user Nginx runs as www-data user hudson and nginx are both members of the www group root of my nginx conf points to RAILS_ROOT/public as per normal. RAILS_ROOT/config/environment.rb is owned by www-data (so Passenger runs as www-data) RAILS_ROOT and everything in it is owned by the www group and group has r/w/x permissions As it stood, Nginx threw 403 permission denied when requesting any url. error.log contained entries like this: public/index.html" is forbidden (13: Permission denied). These did not fix the or change the error (each with a stop/start of Ngnix): chmod 777 -R RAILS_ROOT chgrp www -R /var/lib/hudson I also tried Nginx as root, and passenger complained that it could not find config/environment (despite the path displayed on the error page being correct). The fix was to ensure everybody has read permissions on each directory in the heirachy. In this case chmod o+r /var/lib/hudson. But if the group has read permissions on the directory, and nginx is a member of the owner group of the directory, why was it necessary to allow everyone read permissions? Is there something have not grokked about permissions? $nginx -V nginx version: nginx/0.7.61 built by gcc 4.4.1 (Ubuntu 4.4.1-4ubuntu8) configure arguments: --prefix=/opt/nginx --add-module=/usr/lib/ruby/gems/1.8/gems/passenger-2.2.5/ext/nginx --with-http_ssl_module --with-pcre=~/src/pcre-8.00/ --with-http_stub_status_module $cat /etc/lsb-release DISTRIB_ID=Ubuntu DISTRIB_RELEASE=9.10 DISTRIB_CODENAME=karmic DISTRIB_DESCRIPTION="Ubuntu 9.10"

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  • apache2: Could not open configuration file /etc/apache2/apache2.conf: Permission denied

    - by AntonChanning
    I recently upgraded Ubuntu to the latest LTS edition on my work laptop, which I use as a LAMP development platform. The upgrade was from 12.4 to 14.4. Now I'm having trouble getting apache up and running again. Here is the output from an attempt: antonc@antonc-laptop:/etc/apache2$ sudo service apache2 restart * Restarting web server apache2 * The apache2 configtest failed. Output of config test was: apache2: Could not open configuration file /etc/apache2/apache2.conf: Permission denied Action 'configtest' failed. The Apache error log may have more information. Here is a list of permissions and ownership in /etc/apache, showing that apache2.conf is currently owned by root with permissions 644. I changed this temporarily to 777, but this made no difference, so I changed it back to 644. antonc@antonc-laptop:/etc/apache2$ ls -l total 80 -rw-r--r-- 1 root root 7115 Jan 7 2014 apache2.conf ... What do I need to do to get apache running again? Is the problem really with apache2.conf or some other setting? Should the conf file be owned by a user other than root?

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  • SQL SERVER – Difference Between GRANT and WITH GRANT

    - by pinaldave
    This was very interesting question recently asked me to during my session at TechMela Nepal. The question is what is the difference between GRANT and WITH GRANT when giving permissions to user. Let us first see syntax for the same. GRANT: USE master; GRANT VIEW ANY DATABASE TO username; GO WITH GRANT: USE master; GRANT VIEW ANY DATABASE TO username WITH GRANT OPTION; GO The difference between both of this option is very simple. In case of only GRANT – username can not grant the same permission to other users. In case, of the option of WITH GRANT – username will be able to give the permission it has received to other users. This is very basic definition of the subject. I would like to request my readers to come up with working script to prove this scenario. If can submit your script to me by email (pinal ‘at’ sqlauthority.com) or in comment field. Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Query, SQL Scripts, SQL Security, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: SQL Permissions

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  • sudo: /usr/lib/sudo/sudoers.so must be owned by uid 0

    - by 7UR7L3
    Whenever I try to do anything at all that requires my password it returns this: u7ur7l3@ubuntu:~$ sudo sudo: /usr/lib/sudo/sudoers.so must be owned by uid 0 sudo: fatal error, unable to load plugins u7ur7l3@ubuntu:~$ So I can't install anything from the Software Center / package manager or run any commands in terminal that require my password. I can log in, but that's pretty much it. I accidentally changed the permissions of some files, then changed some more trying to fix it :/. Now I'm completely lost as to what to do. This is what happened when I tried to get sudo working again using pkexec: u7ur7l3@ubuntu:~$ pkexec chown root /usr/lib/sudo/sudoers.so Error getting authority: Error initializing authority: Error calling StartServiceByName for org.freedesktop.PolicyKit1: GDBus.Error:org.freedesktop.DBus.Error.Spawn.ExecFailed: Failed to execute program /usr/lib/dbus-1.0/dbus-daemon-launch-helper: Success u7ur7l3@ubuntu:~$ sudo ls sudo: /usr/lib/sudo/sudoers.so must be owned by uid 0 sudo: fatal error, unable to load plugins And to change permissions I was using Root Actions as a dolphin service/ plugin thing, so history doesn't show me the permission changes. I just realized that sounds don't work at all anymore. When I go into Phonon my default settings and playback devices aren't even there. Also I don't have the option to shutdown, I can only log out or leave.

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  • System boots in console + login loop

    - by Imagicien
    I messed up my system while trying to fix permission problems for setting up a LAMP local server. I tried this solution: How to avoid using sudo when working in /var/www? without success. Then I saw this solution: Permissions issue: how can Apache access files in my Home directory? I understood that I had to change the permissions of my root directory (among others), so I executed: sudo chmod 710 / I also changed the user group on / to www-data. I also did these operations on /home. I'm pretty sure one of those commands broke something, because it's the last commands I executed, and after that, my system showed strange/broken behavior: Firefox stopped showing pages Some icons got replaced by an red X icon (meaning "Icon not found" I guess) Applications refused to launch (no reaction) After rebooting: I got a strange graphical message talking about not being able to mount something, asking me if I wanted to wait, and talking about /tmp (I forgot the message since I was in shock) My system now boots in console, and when I login, it flashes unsignificant stuff* before re-asking me to login. My important data is on Ubuntu One. I'd prefer not having to reinstall from scratch. Is there a way to regain access to my system? Thanks a lot for your help. *Looks like a terminal header with the name of the OS and other info. Doesn't seem important.

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  • Set default owner/user

    - by Daniel Hollands
    I'm a web developer, and so have set-up an old machine in the office as an Ubuntu Server, for the purposes of testing websites. I've set-up LAMP and have created a /var/www folder, from which all my local sites are served. The issue is that of user permissions, i.e. any files that I copy into that folder (from my Windows machine via the network) automatically take on me (daniel) as their owner. The problem is that I want www-data to become the owner. I did some research and saw that it should be possible to use setuid (and setgid) to automatically set www-data as the owner of all files put into /var/www automatically, so far I've not had any luck making it work. Can someone help please? Thank you UPDATE: Would this do what I want it to do? Default file permissions for php user www-data UPDATE 2: I've kinda fixed my issue by changing my samba settings. Using Webmin, I was able to go in and change the default settings (as seen here: http://imageshack.us/photo/my-images/521/captureon.png/)

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  • I deleted all files and folders (including hidden) from /home/username/ now in big trouble

    - by jeffery_the_wind
    I am logged into a remote ubuntu server, and I accidentally erased the entire /home/username/ directory for the current user. The only thing left is a hidden directory called .gvfs. I don't need anything of the Documents/Music/etc. Now it is not letting me cd into the /var/www/ directory, which has permissions 666 and it is owned by the current user. I am afraid to disconnect from my ssh session because I don't know if I will be able to get back on. Have I permanently created a problem? Is there a way I can replace the most important files to the /home/username/ directory? Thanks! ** EDIT ** Thanks everyone for the help. I figured the problem with cd into the /var/www/ was actually my permissions in the /var/www/ directory. It was set to 666, changed it to 755 and everything was good again. It doesn't look like anything systematic was ruined by deleting the contents of the user folder.

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  • Dynamic model choice field in django formset using multiple select elements

    - by Aryeh Leib Taurog
    I posted this question on the django-users list, but haven't had a reply there yet. I have models that look something like this: class ProductGroup(models.Model): name = models.CharField(max_length=10, primary_key=True) def __unicode__(self): return self.name class ProductRun(models.Model): date = models.DateField(primary_key=True) def __unicode__(self): return self.date.isoformat() class CatalogItem(models.Model): cid = models.CharField(max_length=25, primary_key=True) group = models.ForeignKey(ProductGroup) run = models.ForeignKey(ProductRun) pnumber = models.IntegerField() def __unicode__(self): return self.cid class Meta: unique_together = ('group', 'run', 'pnumber') class Transaction(models.Model): timestamp = models.DateTimeField() user = models.ForeignKey(User) item = models.ForeignKey(CatalogItem) quantity = models.IntegerField() price = models.FloatField() Let's say there are about 10 ProductGroups and 10-20 relevant ProductRuns at any given time. Each group has 20-200 distinct product numbers (pnumber), so there are at least a few thousand CatalogItems. I am working on formsets for the Transaction model. Instead of a single select menu with the several thousand CatalogItems for the ForeignKey field, I want to substitute three drop-down menus, for group, run, and pnumber, which uniquely identify the CatalogItem. I'd also like to limit the choices in the second two drop-downs to those runs and pnumbers which are available for the currently selected product group (I can update them via AJAX if the user changes the product group, but it's important that the initial page load as described without relying on AJAX). What's the best way to do this? As a point of departure, here's what I've tried/considered so far: My first approach was to exclude the item foreign key field from the form, add the substitute dropdowns by overriding the add_fields method of the formset, and then extract the data and populate the fields manually on the model instances before saving them. It's straightforward and pretty simple, but it's not very reusable and I don't think it is the right way to do this. My second approach was to create a new field which inherits both MultiValueField and ModelChoiceField, and a corresponding MultiWidget subclass. This seems like the right approach. As Malcolm Tredinnick put it in a django-users discussion, "the 'smarts' of a field lie in the Field class." The problem I'm having is when/where to fetch the lists of choices from the db. The code I have now does it in the Field's __init__, but that means I have to know which ProductGroup I'm dealing with before I can even define the Form class, since I have to instantiate the Field when I define the form. So I have a factory function which I call at the last minute from my view--after I know what CatalogItems I have and which product group they're in--to create form/formset classes and instantiate them. It works, but I wonder if there's a better way. After all, the field should be able to determine the correct choices much later on, once it knows its current value. Another problem is that my implementation limits the entire formset to transactions relating to (CatalogItems from) a single ProductGroup. A third possibility I'm entertaining is to put it all in the Widget class. Once I have the related model instance, or the cid, or whatever the widget is given, I can get the ProductGroup and construct the drop-downs. This would solve the issues with my second approach, but doesn't seem like the right approach.

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  • IntegrityError: foreign key violation upon delete

    - by Lukasz Korzybski
    I have Order and Shipment model. Shipment has a foreign key to Order. class Order(...): ... class Shipment() order = m.ForeignKey('Order') ... Now in one of my views I want do delete order object along with all related objects. So I invoke order.delete(). I have Django 1.0.4, PostgreSQL 8.4 and I use transaction middleware, so whole request is enclosed in single transaction. The problem is that upon order.delete() I get: ... File "/usr/local/lib/python2.6/dist-packages/django/db/backends/__init__.py", line 28, in _commit return self.connection.commit() IntegrityError: update or delete on table "main_order" violates foreign key constraint "main_shipment_order_id_fkey" on table "main_shipment" DETAIL: Key (id)=(45) is still referenced from table "main_shipment". I checked in connection.queries that proper queries are executed in proper order. First shipment is deleted, after that django executes delete on order row: {'time': '0.000', 'sql': 'DELETE FROM "main_shipment" WHERE "id" IN (17)'}, {'time': '0.000', 'sql': 'DELETE FROM "main_order" WHERE "id" IN (45)'} Foreign key have ON DELETE NO ACTION (default) and is initially deferred. I don't know why I get foreign key constraint violation. I also tried to register pre_delete signal and manually delete shipment objects before delete on order is called, but it resulted in the same error. I can change ON DELETE behaviour for this key in Postgres but it would be just a hack, I wonder if anyone has a better idea what's going on here. There is also a small detail, my Order model inherits from Cart model, so it actually doesn't have id field but cart_ptr_id and after DELETE on order is executed there is also DELETE on cart, but it seems unrelated? to the shipment-order problem so I simplified it in the example.

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  • Autodiscovery for inclusion tags

    - by Ludwik Trammer
    The title may be a little confusing, but I don't know how else to call it. I would like to create a Django project with a large set of applications you could arbitrary turn on or off using INSTALLED_APPS option in settings.py (you would obviously also need to edit urls.py and run syncdb). After being turned on an app should be able to automatically: Register it's content in site-wide search. Luckily django-haystack has this built-in, so it's not a problem. Register cron jobs. django-cron does exactly that. Not a problem. Register a widget that should be displayed on the homepage. The homepage should include a list of boxes with widgets form different applications. I thought about inclusion tags, because you can put them anywhere on a page and they control both content and presentation. The problem is I don't know how to automatically get a list of inclusion tags provided by my applications, and display them one by one on a homepage. I need a way to register them somehow, and then display all registered tags.

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  • Render multiple Form instances

    - by vorpyg
    I have a simple application where users are supposed to bet on outcome of a match. A match consists of two teams, a result and a stake. Matches with teams are created in the Django admin, and participants are to fill in result and stake. The form must be generated dynamically, based on the matches in the database. My idea is to have one (Django) Form instance for each match and pass these instances to the template. It works fine when I do it from django shell, but the instances aren't rendered when I load my view. The form looks like this: class SuggestionForm(forms.Form): def __init__(self, *args, **kwargs): try: match = kwargs.pop('match') except KeyError: pass super(SuggestionForm, self).__init__(*args, **kwargs) label = match self.fields['result'] = forms.ChoiceField(label=label, required=True, choices=CHOICES, widget=forms.RadioSelect()) self.fields['stake'] = forms.IntegerField(label='', required=True, max_value=50, min_value=10, initial=10) My (preliminary) view looks like this: def suggestion_form(request): matches = Match.objects.all() form_collection = {} for match in matches: f = SuggestionForm(request.POST or None, match=match) form_collection['match_%s' % match.id] = f return render_to_response('app/suggestion_form.html', { 'forms': form_collection, }, context_instance = RequestContext(request) ) My initial thought was that I could pass the form_collection to the template and the loop throught the collection like this, but id does not work: {% for form in forms %} {% for field in form %} {{ field }} {% endfor %} {% endfor %} (The output is actually the dict keys with added spaces in between each letter - I've no idea why…) It works if I only pass one Form instance to the template and only runs the inner loop. Suggestions are greatly appreciated.

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  • Testing InlineFormset clean methods

    - by Rory
    I have a Django project, with 2 models, a Structure and Bracket, the Bracket has a ForeignKey to a Structure (i.e. one-to-many, one Structure has many Brackets). I created a TabularInline for the admin site, so that there would be a table of Brackets on the Structure. I added a custom formset with some a custom clean method to do some extra validation, you can't have a Bracket that conflicts with another Bracket on the same Structure etc. The admin looks like this: class BracketInline(admin.TabularInline): model = Bracket formset = BracketInlineFormset class StructureAdmin(admin.ModelAdmin): inlines = [ BracketInline ] admin.site.register(Structure, StructureAdmin) That all works, and the validation works. However now I want to write some unittest to test my complex formset validation logic. My first attempt to validate known-good values is: data = {'form-TOTAL_FORMS': '1', 'form-INITIAL_FORMS': '0', 'form-MAX_NUM_FORMS': '', 'form-0-field1':'good-value', … } formset = BracketInlineFormset(data) self.assertTrue(formset.is_valid()) However that doesn't work and raises the exception: ====================================================================== ERROR: testValid (appname.tests.StructureTestCase) ---------------------------------------------------------------------- Traceback (most recent call last): File "/paht/to/project/tests.py", line 494, in testValid formset = BracketInlineFormset(data) File "/path/to/django/forms/models.py", line 672, in __init__ self.instance = self.fk.rel.to() AttributeError: 'BracketInlineFormset' object has no attribute 'fk' ---------------------------------------------------------------------- The Django documentation (for formset validation) implies one can do this. How come this isn't working? How do I test the custom clean()/validation for my inline formset?

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  • Automatically use inclusion tags (?) in a template, depending on installed apps

    - by Ludwik Trammer
    The title may be a little confusing, but I don't know how else to call it. I would like to create a Django project with a large set of applications you could arbitrary turn on or off using INSTALLED_APPS option in settings.py (you would obviously also need to edit urls.py and run syncdb). After being turned on an app should be able to automatically: Register it's content in site-wide search. Luckily django-haystack has this built-in, so it's not a problem. Register cron jobs. django-cron does exactly that. Not a problem. Register a widget that should be displayed on the homepage. The homepage should include a list of boxes with widgets form different applications. I thought about inclusion tags, because you can put them anywhere on a page and they control both content and presentation. The problem is I don't know how to automatically get a list of inclusion tags provided by my applications, and display them one by one on a homepage. I need a way to register them somehow, and then display all registered tags.

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  • Get Username from a Cookie

    - by craphunter
    Hi, I use the backend solution from django. I just want to get a username from the cookie or the session_key to get to know the user. How I can do it? from django.contrib.auth.models import User from django.contrib.sessions.models import Session def start(request, template_name="registration/my_account.html"): user_id = request.session.get('session_key') if user_id: name = request.user.username return render_to_response(template_name, locals()) else: return render_to_response('account/noauth.html') Only else is coming up. What am I doing wrong? Am I right then that authenticated means he is logged in? -- Okay this I got! Firstly, if you have some clarification to a question, update the question, don't post an answer or (even worse) another question, as you have done. Secondly, if the user is logged out, by definition he doesn't have a username. I mean the advantage of Cookies is to identify a user again. I just want to place his name on the webpage. Even if he is logged out. Or isnt't it possible?

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  • Umbraco directory permissions | umbPermissions Script

    - by Vizioz Limited
    It has bugged me since I first used Umbraco that if I was doing a manual installation I had to set the directory permissionsI just downloaded a backup of one of my clients Umbraco sites and I was setting up a copy locally and of course I had to set the directory permissions, so I thought there must be a better way!I did a bit of Googling and had a look on the Umbraco forum but I could not find a script to perform this task, then I came across Set ACL on Source Forge and I set about writing my own little script.Save the following script as umbpermissions.bat and save it in the same directory as Set ACLecho offREM Script to setup the Security Permissions for an Umbraco siteREM This script will give your machine Network Service full rights to the appropriate directoriesREM **** Pre-requisites ****REM You will need to download - http://setacl.sourceforge.net/REM **** Usage ****REM You need to pass in the path for the root of your Umbraco directoryREM E.g. umbPermissions.bat C:\inetpub\umbracoroot@echo umbPermissions.bat - Script to set Umbraco File and Directory Permissions@echo Published by Chris Houston - 29th May 2009@echo http://blog.vizioz.comSetACL.exe -on "%1\web.config" -ot file -actn ace -ace "n:%computername%\NETWORK SERVICE;p:full"SetACL.exe -on "%1\bin" -ot file -actn ace -ace "n:%computername%\NETWORK SERVICE;p:full"SetACL.exe -on "%1\config" -ot file -actn ace -ace "n:%computername%\NETWORK SERVICE;p:full"SetACL.exe -on "%1\css" -ot file -actn ace -ace "n:%computername%\NETWORK SERVICE;p:full"SetACL.exe -on "%1\data" -ot file -actn ace -ace "n:%computername%\NETWORK SERVICE;p:full"SetACL.exe -on "%1\masterpages" -ot file -actn ace -ace "n:%computername%\NETWORK SERVICE;p:full"SetACL.exe -on "%1\scripts" -ot file -actn ace -ace "n:%computername%\NETWORK SERVICE;p:full"SetACL.exe -on "%1\umbraco" -ot file -actn ace -ace "n:%computername%\NETWORK SERVICE;p:full"SetACL.exe -on "%1\umbraco_client" -ot file -actn ace -ace "n:%computername%\NETWORK SERVICE;p:full"SetACL.exe -on "%1\usercontrols" -ot file -actn ace -ace "n:%computername%\NETWORK SERVICE;p:full"SetACL.exe -on "%1\xslt" -ot file -actn ace -ace "n:%computername%\NETWORK SERVICE;p:full"Feel free to comment if I missed anything!

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  • Django/PIL Error - Caught an exception while rendering: The _imagingft C module is not installed

    - by kenok
    I'm trying to run a webapp/site on my machine, it's running on OSX 10.6.2 and I'm having some problems: Caught an exeption while rending: The _imagingft C module is not installed Doing import _imagingft in python gives me this: >>> import _imagingft Traceback (most recent call last): File "<stdin>", line 1, in <module> ImportError: dlopen(/Library/Python/2.6/site-packages/PIL/_imagingft.so, 2): Symbol not found: _FT_Done_Face Referenced from: /Library/Python/2.6/site-packages/PIL/_imagingft.so Expected in: flat namespace in /Library/Python/2.6/site-packages/PIL/_imagingft.so It's seems that the Freetype library is the one having problems. No errors so far when installing PIL or when I compiled(?) the jpeg and freetype libraries so far. I'm on django 1.1.1, python 2.6.2.

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  • Django CMS malfunction: Site matching query does not exist

    - by culebrón
    I've installed all apps in a project, then added a site in the sites section, and deleted example.com. Now Pages section in Django CMS 2.0 isn't working: it raises a DoesNotExist exception: Site matching query does not exist. at http://127.0.0.1:8000/admin/cms/page/ The section worked normally before I deleted the example.com site. In settings.py I have SITE_ID = 2 line. Still, in this call: return Site.objects.get(pk=site_pk) in traceback, site_pk=1. How can I fix this?

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  • Django Forms, Foreign Key and Initial retuen all associated values

    - by gramware
    I a working with Django forms. The issue I have is that Foreign Key fields and those using initial take all associated entries (all records associated with that record other then the one entry i wanted e.g instead of getting a primary key, i get the primary key, post subject, post body and all other values attributed with that record). The form and the other associated queries still work well, but this behaviour is clogging my database. How do i get the specific field i want instead of all records. An example of my models is here: A form field for childParentId returns postID, postSubject and postBody instead of postID alone. Also form = ForumCommentForm(initial = {'postSubject':forum.objects.get(postID = postID), }) returns all records related to postID. class forum(models.Model): postID = models.AutoField(primary_key=True) postSubject = models.CharField(max_length=25) postBody = models.TextField() postPoster = models.ForeignKey(UserProfile) postDate = models.DateTimeField(auto_now_add=True) child = models.BooleanField() childParentId = models.ForeignKey('self',blank=True, null=True) deleted = models.BooleanField() def __unicode__(self): return u'%s %s %s %s %s' % (self.postSubject, self.postBody, self.postPoster, self.postDate, self.postID

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  • Django URL regex question

    - by shawnjan
    Hey all! I had a quick question about Django URL configuration, and I guess REGEX as well. I have a small configuration application that takes in environments and artifacts in the following way: url(r'^env/(?P<env>\w+)/artifact/(?P<artifact>\w+)/$', 'config.views.ipview', name="bothlist"), Now, this works fine, but what I would like to do is have it be able to have additional parameters that are optional, such as a verbose mode or no formating mode. I know how to do this just fine in the views, but I can't wrap my head around the regex. the call would be something like GET /env/<env>/artifact/<artifact>/<opt:verbose>/<opt:noformat> Any help would be appreciated, thanks! -Shawn

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  • How do I create sub-applications in Django?

    - by jamida
    I'm a Django newbie, but fairly experienced at programming. I have a set of related applications that I'd like to group into a sub-application but can not figure out how to get manage.py to do this for me. Ideally I'll end up with a structure like: project/ app/ subapp1/ subapp2/ I've tried: manage.py startapp app.subapp1 manage.py startapp app/subapp1 but this tells me that / and . are invalid characters for app names I've tried changing into the app directory and running ../manage.py subapp1 but that makes supapp1 at the top level. NOTE, I'm not trying to directly make a stand-alone application. I'm trying to do all this from within a project.

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