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  • MySQL: Limit output according to associated ID

    - by Jess
    So here's my situation. I have a books table and authors table. An author can have many books... In my authors page view, the user (logged in) can click an author in a tabled row and be directed to a page displaying the author's books (collected like this URI format: viewauthorbooks.php?author_id=23), very straight forward... However, in my query, I need to display the books for the author only, and not all books stored in the books table (as i currently have!) As I am a complete novice, I used the most simple query of: SELECT * FROM tasks_tb This returns the books for me, but returns every single value (book) in the database, and not ones associated with the selected author. And when I click a different author the same books are displayed for them...I think everyone gets what I'm trying to achieve, I just don't know how to perform the query. I'm guessing that I need to start using more advanced query clauses like INNER JOIN etc. Anyone care to help me out :)

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  • Mod_Rewrite: Insert "/" between variables and values in URL

    - by Abs
    Hello all, I am attempting clean useful URLs using mod_rewrite. I am sure this is a common question but I am not so hot with mod_rewrite: I have this URL: http://mysite.com/user.php?user=fatcatmat&sort=popularv I want to be able to rewrite it like this: http://mysite.com/user/user/fatcatmat/sort/popularv (Is there a way to remove duplicates in a URL?) I think I have managed to do the removal of the PHP extension. RewriteRule ^(.*)\$ $1.php [nc] Is the above correct? For the separate pages, I would have something like this. RewriteRule ^/?user(/)?$ user.php Main Question: Its a bit tedious to do all the above but is there a MEGA rewrite rule that will just place "/" in between variables and their values and remove the .php extension from all pages? Thank you for any help.

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  • how to insert page view of a node in another page in drupal

    - by sprugman
    I have a list of node ids and I want to display the 'page' view of each one. For various reasons, I don't want to do this with views, and don't think I should need a module. Just an API call to theme('node'). Something like: $nids = array(3,4,5); foreach ($nids as $nid) { $node = node_load($nid); $result .= theme('node', $node); } but I'm not getting back the full page view of the node. I added this to my node-[type].tpl.php file: if ($page) print "PAGE MODE "; else print "NOT PAGE "; if ($teaser) print "TEASER MODE "; else print "NOT TEASER "; and got: NOT PAGE NOT TEASER I seem to be in some kind of limbo. I suspect there's an argument that I add to the theme function, but the terms are all so general (theme, teaser, page, node), I'm having trouble with my google-fu.

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  • mail function not working for yahoo mail id

    - by Akash
    Hello all, I have written a code to send mail on yahoo or gmail.Mail is sending on gmail but i m not seeing any message in yahoo mail. And in gmail i m seeing all html content with message. here is my code... $headers = "From: \"".$from_name."\" <".$from_email.">\n"; $headers .= "To: \"".$to_name."\" <".$to_email.">\n"; $headers .= "Return-Path: <".$from_email.">\n"; $headers .= "MIME-Version: 1.0\n"; $headers .= "Content-Type: text/HTML; charset=ISO-8859-1\n"; // message $message = ' <html> <head> <title>Registration</title> </head> <body> <table><tr> <td> <a href="#'> Click Here To Activate Your account</a> Thanks To visit site.com </td> </tr> </table> </body> </html>'; if(mail('', $subject, $message, $headers)) echo "successfully register !! please check your mail and clik on confirmation link";

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  • Export MySQL Data as Insert Statements

    - by gav
    Hi All, I'm working in Ubuntu with MySql and I also have Query Browser and Administrator installed, I'm not afraid of the command line either if it helps. I want simply to be able to run a query and see a result set but then convert that result set into a series of commands that could be used to create the same rows in a table of an identical schema. I hope the question makes sense, it's quite a simple problem and one that must have been solved but I can't for the life of me work out where this kind of conversion is made available. Thanks in advance, Gav

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  • Get the identity value from an insert via a .net dataset update call

    - by DeveloperMCT
    Here is some sample code that inserts a record into a db table: Dim ds As DataSet = New DataSet() da.Fill(ds, "Shippers") Dim RowDatos As DataRow RowDatos = ds.Tables("Shippers").NewRow RowDatos.Item("CompanyName") = "Serpost Peru" RowDatos.Item("Phone") = "(511) 555-5555" ds.Tables("Shippers").Rows.Add(RowDatos) Dim custCB As SqlCommandBuilder = New SqlCommandBuilder(da) da.Update(ds, "Shippers") It inserts a row in the Shippers Table, the ShippersID is a Indentity value. My question is how can i retrieve the Identity value generated when the new row is inserted in the Shippers table. I have done several web searches and the sources I've seen on the net don't answer it speccifically or go on to talk about stored procedures. Any help would be appreciated. Thanks!

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) objects = OpenCvManager() the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • jQuery - getting the id of the item selected

    - by John Leonard
    I have a basic jQuery selector question. Let's say I'm parsing JSON and generating a row of data for each item in my result set. On each item row, I want an action button. What is the best practice to script that button so its click action can reference the data specific to that row? Starting with the block below, how do I generate a 'Click Me' button that when clicked will alert with its json data? $.getJSON(url,params,function(json){ if(json.items){ $.each(json.items, function(i, n){ var item = json.items[i];

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  • jQuery: How to collect values from sliders into simple object with id as keys

    - by Svish
    I have several jQuery UI Sliders and I want to collect their values. Thought it would be a simple task, but when I was going to do it I got stuck and not quite sure what to do anymore :p The object I would like to end up with should look something like this: { a: 80, b: 90, c: 20, ... } I can do it manually like this: var values = { a: $('#a').slider('value'), b: $('#b').slider('value'), c: $('#c').slider('value'), ... }; But that's a bit tedious, especially if I need to add or remove or rename. Was hoping I could do something with the map or each function or something like that, but I can't figure it out. Anyone have some clever ideas?

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  • I insert new parent row and child rowstate changes from Added to unchanged

    - by Joel
    rowsUpdated is an int32 to count how many rows are updated rowsToUpdate = dataset.ParentTable.Select("", "", dataviewRowState.Added) if rowsToUpdate isNot Nothing then for each row as datarow in RowsToUpdate changes the rowstate: rowsUpdated = rowsUpdated + ParentTableAdapter.update(row) Next row End if I'm sure it's something I'm over looking but I just can't see it. Thanks in advance, Joel

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  • Unable to Hide Update Button in GridView Editing

    - by nitinkhanna
    Hi, I am using commandfield edit button to edit the row of the gridview. But unable to perform the basics. This gridview is in update panel. When I press Edit button it shows UPDATE and CANCEL button but when I press UPDATE button it updates the DB but UPDATE button doesn't go back to EDIT one. While Cancel is working as it should. Like on pressing CANCEL it goes back to EDIT button, What I am doing worng. Thanks.

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  • Customizing Bugzilla 4.0.2 Bug ID numbers

    - by Marcus Polk
    Is it possible to customize Bugzilla bug numbers and add a letter designator, to immediately know it came from Bugzilla? My company is evaluating Bugzilla and has now added many new bugs. We also use 2 other bug databases. This wasn't my decision and I believe they were trying to incorporate better reporting, etc. I read an answer here about "seeding" Bugzilla bug numbers, by setting the "AUTO_INCREMENT" field in the "bugs" table to a different value. I wish I would've thought about this sooner and found this board. Setting that value to start at 9000 or some extraordinary value would have ensured that we knew exactly which bugs came from Bugzilla. However, would it be possible to change the field in the "bugs" table to accept letters, as well? Of course that would probably just mess up the whole auto incrementing of the numbers. Any help or advice is greatly appreciated. Thank you.

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  • greasemonkey insert javascript

    - by Kaartz
    I have a bookmarklet, clicking the bookmarklet includes a PHP script (evaluated as a JavaScript file) to the page few table values and select values passed as GET parameters. The PHP script writes the page data to the MySQL database, and outputs a success message that is treated as JavaScript code and executed by the browser. Is there any possibility to do this using greasemonkey and call this function when a existing button is clicked on the web page. I wrote the above bookmarklet inspired by this tutorial. http://tutorialzine.com/2010/04/simple-bookmarking-app-php-javascript-mysql/ This is the bookmarklet code: (function () { var jsScript = document.createElement('script'); jsScript.setAttribute('type', 'text/javascript'); jsScript.setAttribute('src', '/bookmark.php?url=' + encodeURIComponent(location.href) + '&title=' + encodeURIComponent(document.title)); document.getElementsByTagName('head')[0].appendChild(jsScript); })(); Please help me.

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  • J2EE _ Eclipse Id Exception

    - by user347672
    i import an existing simple stateless session bean project in to my eclipse Galileo workspace. it uses Jboss 4.2 server. The problem is, while try to congiure the project into server it will not shown in servers's available project list. later i try to add the project by right clicking the server but it says " there are no resources that can be added or removed from the server"... can anyone tell me the solution to run the project?

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  • LinkedList insert tied to inserted object

    - by wrongusername
    I have code that looks like this: public class Polynomial { List<Term> term = new LinkedList<Term>(); and it seems that whenever I do something like term.add(anotherTerm), with anotherTerm being... another Term object, it seems anotherTerm is referencing the same thing as what I've just inserted into term so that whenever I try to change anotherTerm, term.get(2) (let's say) get's changed too. How can I prevent this from happening?

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  • How to insert URL parameter in DIV?

    - by rajesh
    Hi, my code is <a href="#" target="_blank" class="floatLeft" onclick="change('http://localhost/allwidgets/widgets.html');" > function change(url) { alert(url); document.getElementById("mainOuter").innerHTML=url; } Actually I want that url should go in innerHTML of mainOuter div and that page should display in that. Please suggest.... Thanks

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  • How to insert variables in R twitteR updates?

    - by analyticsPierce
    Hello, I am using the twitteR package in R to update my twitter status with results from analysis. The static tweet function works: library(twitteR) sess = initSession('username','password') tweet = tweet('I am a tweet', sess) However, when I add a variable to display some specific results I get an error. library(twitteR) sess = initSession('username','password') res = c(3,5,8) msg = cat('Results are: ', res, ', that is nice right?') tweet = tweet(msg, sess) Results in: Error in twFromJSON(rawToChar(out)) : Error: Client must provide a 'status' parameter with a value. Any suggestions are appreciated.

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