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  • loading record into detailview

    - by summer
    please please i need help..i think i am lost somewhere..basically i followed the example http://www.iphonesdkarticles.com/2008/10/sqlite-tutorial-loading-data-as.html, but i was stuck with error on reading description..something must had gone wrong some well but i am not very sure how should i solve it. this is my code, actually i dun really have an idea on wat's really going in this code..help please..2days!! no solution!! - (void) hydrateDetailViewData { //if detail view is hydrated then do not get it from database if(isDetailViewHydrated) return; if(detailStmt == nil) { const char *sql = "select snapTitle, snapDesc from Snap where snapID =?"; if(sqlite3_prepare_v2(database, sql, -1, &detailStmt, NULL) != SQLITE_OK) NSAssert1(0, @"Error while creating detail view statement. '%s'", sqlite3_errmsg(database)); NSLog(@"SQLite= %d", sqlite3_step(detailStmt)); } if(SQLITE_DONE != sqlite3_step(detailStmt)) { // NSString *descStr = [[NSString alloc] //initWithString:sqlite3_column_text(detailStmt, 2)]; NSString *descStr = [NSString stringWithUTF8String:(char *)sqlite3_column_text(detailStmt,2)]; self.snapDescription = descStr; [descStr release]; } else NSAssert1(0, @"Error getting description of snap2play. '%s'", sqlite3_errmsg(database)); sqlite3_reset(detailStmt); isDetailViewHydrated = YES; //if hydrated, make sure do not get from database again. } }

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  • SQLite3 - select date range not working

    - by iFloh
    yet anotherone that gives me grief. In a SQLite3 DB Select I query for a date range specified in (NSDate *)fromDate to (NSDate *)toDate const char *sql = "SELECT * FROM A, B WHERE A.key = B.key AND A.date between ? and ?"; After opening the DB I run the query in Objective-C as follows: NSDateFormatter *tmpDatFmt = [[[NSDateFormatter alloc] init] autorelease]; [tmpDatFmt setDateFormat:@"dd-MM-yyyy"]; sqlite3_stmt *stmt; if(sqlite3_prepare_v2(db, sql, -1, &stmt, NULL) == SQLITE_OK) { NSLog(@"From %s to %s;", [[tmpDatFmt stringFromDate:fromDate] UTF8String], [[tmpDatFmt stringFromDate:toDate] UTF8String]); sqlite3_bind_text(stmt, 1, [[tmpDatFmt stringFromDate:fromDate] UTF8String], -1, SQLITE_STATIC); // first '?' sqlite3_bind_text(stmt, 2, [[tmpDatFmt stringFromDate:toDate] UTF8String], -1, SQLITE_STATIC); // second '?' while(sqlite3_step(stmt) == SQLITE_ROW) { NSLog(@"Success");} In the database I have several records that match the date range: 12-04-2010 = in seconds 1271059200 13-04-2010 = in seconds 1271145600 13-04-2010 = in seconds 1271152800 14-04-2010 = in seconds 1271267100 When I run it the first NSLog shows From 2010-04-01 to 2010-04-30 my problem is the records are not selected (no "Success" shows in the log) and I don't understand why. earlier I had miscalculated the dates 2 days later as 14-04-2010 = in seconds 1271232000 15-04-2010 = in seconds 1271318400 15-04-2010 = in seconds 1271325600 16-04-2010 = in seconds 1271439936 These dates worked fine (4 x "Success in the log). I am puzzled ...

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  • problem during data fetch

    - by nectar
    here is my code $sql="SELECT * FROM $tbl_name WHERE ownerId='$UserId'"; $result=mysql_query($sql,$link)or die(mysql_error()); $row = mysql_fetch_array($result, MYSQL_ASSOC); <?php while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { echo "<tr>"; echo "<td>".$row['pinId']."</td>"; echo "<td>".$row['usedby']."</td>"; echo "<td>".$row['status']."</td>"; echo "</tr>"; } ?> it is ignoring the first record means if 4 rows are in $row its ignoring the 1st one rest three are coming on page. ownerId is not primary key.

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  • Array Intersect giving wrong output

    - by Pankaj Khurana
    Hi, I need to find common elements between two arrays. My code is: $sql="SELECT DISTINCT fk_paytbl_discounts_discountid as discountid from paytbl_discounts_students WHERE fk_vtiger_cf_601='".$categoryid."'"; $discountstudentinfo=$objdb->customQuery($sql,false); $sql1="SELECT DISTINCT fk_paytbl_discounts_discountid as discountid from paytbl_discounts_variants WHERE fk_vtiger_products_productid='".$variantid."'"; $discountvariantinfo=$objdb->customQuery($sql1,false); $commondiscount=array_intersect($discountvariantinfo,$discountstudentinfo); First array Array ( [0] => Array ( [discountid] => 2 ) [1] => Array ( [discountid] => 8 ) [2] => Array ( [discountid] => 5 ) [3] => Array ( [discountid] => 4 ) ) Second array Array ( [0] => Array ( [discountid] => 1 ) [1] => Array ( [discountid] => 5 ) ) Common array Array ( [0] => Array ( [discountid] => 1 ) [1] => Array ( [discountid] => 5 ) ) Common array should have only discountid 5 but its showing 1 also. Please help me on this Thanks

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  • What considerations should be made when creating a reporting framework for a business?

    - by Andrew Dunaway
    It's a pretty classic problem. The company I work for has numerous business reports that are used to track sales, data feeds, and various other metrics. Of course this also means that there is a conglomerate of disparate frameworks, ASP.net pages, and areas where these reports can be found. There have been some attempts at consolidating these into a single entity, but nothing has stuck yet. Since this is a common problem, and I am sure solved innumerable times, I wanted to see what others have done. For the most part these can be boiled down to the following pieces: A SQL query against our database to gather data A presentation of data, generally in a data grid Filtering that can vary based on data types and the business needs Some way to organize the reports, a single drop down gets long and unmanageable quickly A method to download data to alter further, perhaps a csv file My first thought was to create a framework in Silverlight with Linq to Sql. Mainly just because I like it and want to play with it which probably is not the best reason. I also thought the controls grant a lot of functionality like sorting, dragging columns, etc. I was also curious about the printing in Silverlight 4. Which brings me around to my original question, what is the best way to do this? Is there a package out there I can just buy that will do it for me? The Silverlight approach seems pretty easy, after it's setup and templated, but maybe it's a bad idea and I can learn from someone else?

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  • Should I change $_REQUEST to $_POST

    - by Scarface
    Hey guys quick question, I have a checkbox system where a list of items can be checked and deleted on the click of a button. I currently use request and it does the job but I was wondering if $_REQUEST was some sort of security risk or improper. If anyone has any advice I would appreciate it. Should I change to $_POST? If so, what is the best way to go about it? foreach ($_REQUEST as $key=>$value) { if (substr($key,0,3)==="img") { $id = substr($key,3); if(isset($_REQUEST['Delete'])) { $sql = 'SELECT file_name,username FROM images WHERE id=?'; $stmt = $conn->prepare($sql); $result=$stmt->execute(array($id)); while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { $image=$row['file_name']; $user=$row['username']; $myFile = "$user/images/$image"; unlink($myFile); } <input id=\"img".$id."\" name=\"img".$id."\" type=\"checkbox\">

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  • Create 2nd tables and add data

    - by Tyler Matema
    I have this task from school, and I am confuse and lost on how I got to do this. So basically I have to create 2 tables to the database but I have to created from php. I have created the first table, but not the second one for some reason. And then, I have to populate first and second tables with 10 and 20 sample records respectively, populate, does it mean like adding more fake users? if so is it like the code shown below? *I got error on the populating second part as well Thank you so much for the help. <?php $host = "host"; $user = "me"; $pswd = "password"; $dbnm = "db"; $conn = @mysqli_connect($host, $user, $pswd, $dbnm); if (!$conn) die ("<p>Couldn't connect to the server!<p>"); $selectData = @mysqli_select_db ($conn, $dbnm); if(!$selectData) { die ("<p>Database Not Selected</p>"); } //1st table $sql = "CREATE TABLE IF NOT EXISTS `friends` ( `friend_id` INT NOT NULL auto_increment, `friend_email` VARCHAR(20) NOT NULL, `password` VARCHAR(20) NOT NULL, `profile_name` VARCHAR(30) NOT NULL, `date_started` DATE NOT NULL, `num_of_friends` INT unsigned, PRIMARY KEY (`friend_id`) )"; //2nd table $sqlMyfriends = "CREATE TABLE `myfriends` ( `friend_id1` INT NOT NULL, `friend_id2` INT NOT NULL, )"; $query_result1 = @mysqli_query($conn, $sql); $query_result2 = @mysqli_query($conn, $sqlMyfriends); //populating 1st table $sqlSt3="INSERT INTO friends (friend_id, friend_email, password, profile_name, date_started, num_of_friends) VALUES('NULL','[email protected]','123','abc','2012-10-25', 5)"; $queryResult3 = @mysqli_query($dbConnect,$sqlSt3) //populating 2nd table $sqlSt13="INSERT INTO myfriends VALUES(1,2)"; $queryResult13=@mysqli_query($dbConnect,$sqlSt13); mysqli_close($conn); ?>

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  • How do I manipulate the format on a DataGridView that is bound to a Data Source?

    - by Jack Johnstone
    I´m using SQL Server 2005 and Visual Studio 2008, C#. In the data source (the SQL Server data table) I use the DateTime format mm/dd/yyyy, however, in a forms overview (DataGridView) users would like to see a completely other format, with year, week number and day number of week (yyww,d) which is in string format. I´ve created an algorithm for the transformation between values (date to weekday), but can I populate the affected cells with yyww,d (string) instead of mm/dd/yyyy (DateTime)? This is what I´ve been testing out, without success (and note, it´s on the last line the problem becomes obvious, as the cell value won´t accept a string on runtime - it still wants to be a DateTime...) private void DataGridViewQueryFindRequests_CellFormatting( object sender, DataGridViewCellFormattingEventArgs e) { string weekAndDay = ""; DataGridViewCell cell = DataGridViewQueryFindRequests.Rows[e.RowIndex].Cells[e.ColumnIndex]; if (cell.ColumnIndex == 13 && cell.Value == null) mEmptyRow = true; if ((cell.ColumnIndex == 14 || cell.ColumnIndex == 15) && !mEmptyRow) { weekAndDay = ClassWeeksAndDates.dateToWeekNumber(Convert.ToDateTime(cell.Value)); cell.ValueType = typeof(string); cell.Value = weekAndDay; } }

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  • Unable to retrieve data, mysql php pdo

    - by Kyle Hudson
    Hi, I have an issue, i cannot get any results from mysql on a production box but can on a development box, we use PHP 5.3 with MySQL (pdo). $sd = $this->dbh->quote($sd); $si_sql = "SELECT COUNT(*) FROM tbl_wl_data WHERE (site_domain = $sd OR siteDomainMasked = $sd);"; if($this->dbh->query($si_sql)->rowCount() > 0) { //gets to here, just doesnt get through the loop $sql = "SELECT pk_aid, site_name, site_css, site_img_sw, supportPhone FROM tbl_wl_data WHERE (site_domain = $sd OR siteDomainMasked = $sd);"; foreach($this->dbh->query($sql) as $wlsd) { //-- fails here if($wlsd['wl_status'] != '1') { require "_domainDisabled.php"; exit; } $this->pk_aid = $wlsd['pk_aid']; $this->siteTitle = $wlsd['site_name']; $this->siteCSS = $wlsd['site_css']; $this->siteImage = $wlsd['site_img_sw']; $this->siteSupportPhone = $wlsd['supportPhone']; } } else { throw new ERR_SITE_NOT_LINKED; } It just doesnt seem to get into the loopk, i ran the query in navicat and it returns the data. Really confused :S

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  • How to properly manage a complex DB structure?

    - by errr
    Let's say you have several systems using the same DB - each uses several schemes (sometimes same as the other). This structure of these schemes is somewhat very big and complicated. Now, how could you possibly manage such scheme structure? Obviously using some sort of "configuration" - the simplest would be SQL scripts, but a more reasonable solution would be XMLs which can be easily converted into SQL, or some other readable solution (for example, JPA's XMLs or Annotations). This solution though, causes a problem where you can't really tell if your configuration matches the structure of the DB schemes exactly. You can't say if those two are synchronized. Why wouldn't they? Well, in such big structure there are going to be many changes, and you won't always remember to save/commit your configuration after you've altered the schemes, or maybe you did save/commit it, but eventually didn't altered anything in the schemes and forgot to undo the changes to the configuration. More than that, another problem (not caused by the configuration, but isn't addressed by it either) is versioning. I don't see any good way of managing the DB schemes versions (say our last alteration makes 3 systems crash - not good, how to "rollback"?). And thoughts? thx.

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  • php memory how much is too much

    - by Rob
    I'm currently re-writing my site using my own framework (it's very simple and does exactly what I need, i've no need for something like Zend or Cake PHP). I've done alot of work in making sure everything is cached properly, caching pages in files so avoid sql queries and generally limiting the number of sql queries. Overall it looks like it's very speedy. The average time taken for the front page (taken over 100 times) is 0.046152 microseconds. But one thing i'm not sure about is whether i've done enough to reduce php memory usage. The only time i've ever encountered problems with it is when uploading large files. Using memory_get_peak_usage(TRUE), which I THINK returns the highest amount of memory used whilst the script has been running, the average (taken over 100 times) is 1572864 bytes. Is that good? I realise you don't know what it is i'm doing (it's rather simple, get the 10 latest articles, the comment count for each, get the user controls, popular tags in the sidebar etc). But would you be at all worried with a script using that sort of memory getting hit 50,000 times a day? Or once every second at peak times? I realise that this is a very open ended question. Hopefully you can understand that it's a bit of a stab in the dark and i'm really just looking for some re-assurance that it's not going to die horribly come re-launch day.

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  • Error in inserting data into database

    - by Matthew
    When I try to run this code it will not insert the data into the database? <?php class Database { private $dsn; function __construct($dbname, $host, $user, $password, $enckey) { $this->dsn = "mysql:dbname=" . $dbname . ';host=' . $host; $this->user = $user; $this->password = $password; } private function createDSN() { return $this->dsn; } public function createConnection() { try { $dbh = new PDO(self::createDSN(), $this->user, $this->password); } catch (PDOException $e) { echo 'Connection failed: ' . $e->getMessage(); } return $dbh; } } $db = new Database('mytest', 'localhost', 'root', 'hashedpassword', null); $dbh = $db->createConnection(); $sql = $dbh->prepare("INSERT INTO contacts (firstname, lastname) VALUES (?,?)"); $sql->execute(array("abc", "xyz")); ?>

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  • PHP Session doesn't get read in next page after login validation, Why?

    - by NetStar
    I have a web site and when my users login it takes them to verify.php (where it connects to the DataBase and matches email and password to the user input and if OK puts client data into sessions and take the client to /memberarea/index.php ELSE back to login page with message "Invalid Email or password!") <?php ob_start(); session_start(); $email=$_POST['email']; $pass=md5($_POST['pass']); include("conn.php"); // connects to Database $sql="SELECT * FROM `user` WHERE email='$email' AND pass='$pass'"; $result=mysql_query($sql); $new=mysql_fetch_array($result); $_SESSION['fname']=$new['fname']; $_SESSION['lname']=$new['lname']; $_SESSION['email1']=$new['email1']; $_SESSION['passwrd']=$new['passwrd']; $no=mysql_num_rows($result); if ($no==1){ header('Location:memberarea/index.php'); }else { header("Location:login.php?m=$msg"); //msg="Invalid Login" } ?> then after email id and password is verified it takes them to ` /memberarea/index.php (This is where the problem happens.) where in index.php it checks if a session has been created in-order to block hackers to enter member area and sends them back to the login page. <? session_start(); isset($_SESSION['email'])` && `isset($_SESSION['passwrd'])` The problem is the client gets verified in verify.php (the code is above) In varify.php only after I put ob_start(); ontop of session_start(); It moves on to /memberarea/index.php , If I remove ob_start() It keeps the client on the verify.php page and displays error header is alredy SENT. after I put ob_start() it goes in to /memberarea/index.php but the session is blank, so it goes back to the login page and displays the error ($msg) "Invalid Login" which I programed to display. Can anyone tell me why the session cant pass values from verify.php to /memberarea/index.php

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  • EF 4 Query - Issue with Multiple Parameters

    - by Brian
    Hello, A trick to avoiding filtering by nullable parameters in SQL was something like the following: select * from customers where (@CustomerName is null or CustomerName = @CustomerName) This worked well for me in LINQ to SQL: string customerName = "XYZ"; var results = (from c in ctx.Customers where (customerName == null || (customerName != null && c.CustomerName == customerName)) select c); But that above query, when in ADO.NET EF, doesn't work for me; it should filter by customer name because it exists, but it doesn't. Instead, it's querying all the customer records. Now, this is a simplified example, because I have many fields that I'm utilizing this kind of logic with. But it never actually filters, queries all the records, and causes a timeout exception. But the wierd thing is another query does something similarly, with no issues. Any ideas why? Seems like a bug to me, or is there a workaround for this? I've since switched to extension methods which works. Thanks.

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  • Ordering by number of rows?

    - by Rob
    Alright, so I have a table outputting data from a MySQL table in a while loop. Well one of the columns it outputs isn't stored statically in the table, instead it's the sum of how many times it appears in a different MySQL table. Sorry I'm not sure this is easy to understand. Here's my code: $query="SELECT * FROM list WHERE added='$addedby' ORDER BY time DESC"; $result=mysql_query($query); while($row=mysql_fetch_array($result, MYSQL_ASSOC)){ $loghwid = $row['hwid']; $sql="SELECT * FROM logs WHERE hwid='$loghwid' AND time < now() + interval 1 hour"; $query = mysql_query($sql) OR DIE(mysql_error()); $boots = mysql_num_rows($query); //Display the table } The above is the code displaying the table. As you can see it's grabbing data from two different MySQL tables. However I want to be able to ORDER BY $boots DESC. But as its a counting of a completely different table, I have no idea of how to go about doing that. I would appreciate any help, thank you.

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  • Delete file using a link

    - by user329394
    Hi all, i want to have function like delete file from database by using link instead of button. how can i do that? do i need to use href/unlink or what? Can i do like popup confirmation wther yes or no. i know how to do that, but where should i put the code? this is the part how where system will display all filename and do direct upload. Beside each files, there will be a function for 'Remove': $qry = "SELECT * FROM table1 a, table2 b WHERE b.id = '".$rs[id]."' AND a.ptkid = '".$rs[id]."' "; $sql = get_records_sql($qry); foreach($sql as $rs){ ?> <?echo '<a href="download.php?f='.$rs->faillampiran.'">'. basename($rs->faillampiran).'</a>'; ?><td><?echo '<a href=""> [Remove]</a>';?></td><? ?><br> <? } ?> thankz all

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  • num_rows is 0 when it should be >0 for php mysqli code

    - by jpporterVA
    My num_rows is coming back as 0, and I've tried calling it several ways, but I'm stuck. Here is my code: $conn = new mysqli($dbserver, "dbuser", "dbpass", $dbname); // get the data $sql = 'SELECT AT.activityName, AT.createdOn FROM userActivity UA, users U, activityType AT WHERE U.userId = UA.userId and AT.activityType = UA.activityType and U.username = ? order by AT.createdOn'; $stmt = $conn->stmt_init(); $stmt->prepare($sql); $stmt->bind_param('s', $requestedUsername); $stmt->bind_result($activityName, $createdOn); $stmt->execute(); // display the data $numrows = $stmt->num_rows; $result=array("user activity report for: " . $requestedUsername . " with " . $numrows . " rows:"); $result[]="Created On --- Activity Name"; while ($stmt->fetch()) { $msg = " " . $createdOn . " --- " . $activityName . " "; $result[] = $msg; } $stmt->close(); There are multiple rows found, and the fetch loop process them just fine. Any suggestions on what will enable me to get the number of rows returned in the query? Suggestions are much appreciated. Thanks in advance.

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  • MySQLi Wrapper -- will this slow down performance?

    - by Kerry
    I found the following code on php.net. I'm trying to write a wrapper for the MySQLi library to make things incredibly simple. If this is going to slow down performance, I'll skip it and find another way, if this works, then I'll do that. I have a single query function, if someone passes in more than one variable, I assume the function has to be prepared. The function that I would use to pass in an array to mysqli_stmt_bind_param is call_user_func_array, I have a feeling that is going to slow things down. Am I right? <?php /* just explaining how to call mysqli_stmt_bind_param with a parameter array */ $sql_link = mysqli_connect('localhost', 'my_user', 'my_password', 'world'); $type = "isssi"; $param = array("5", "File Description", "File Title", "Original Name", time()); $sql = "INSERT INTO file_detail (file_id, file_description, file_title, file_original_name, file_upload_date) VALUES (?, ?, ?, ?, ?)"; $sql_stmt = mysqli_prepare ($sql_link, $sql); call_user_func_array('mysqli_stmt_bind_param', array_merge (array($sql_stmt, $type), $param); mysqli_stmt_execute($sql_stmt); ?>

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  • PHP Array to CSV

    - by JohnnyFaldo
    I'm trying to convert an array of products into a CSV file, but it doesn't seem to be going to plan. The CSV file is one long line, here is my code: for($i=0;$i<count($prods);$i++) { $sql = "SELECT * FROM products WHERE id = '".$prods[$i]."'"; $result = $mysqli->query($sql); $info = $result->fetch_array(); } $header = ''; for($i=0;$i<count($info);$i++) { $row = $info[$i]; $line = ''; for($b=0;$b<count($row);$b++) { $value = $row[$b]; if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } header("Content-type: application/octet-stream"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$data"; Also, the header doesn't force a download. I've been copy and pasting the output and saving as .csv

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  • why this condition not work

    - by migo
    *strong text*I noticed that the first condition does not work if (empty($ss)) { echo "please write your search words"; } but the second work else if ($num < 1 ) { echo "not found any like "; full code if (empty($ss)) { echo "please write your search words"; } else if ($num < 1 ) { echo "not found any like "; }else { $sql=("SELECT * FROM student WHERE snum = $ss "); $rs = mysql_query($sql) or die(mysql_error()); while($data=mysql_fetch_array($rs)){ ? ??????? ????? ????? ???? ???? ?????? 100 100 100 100 100 ?????? ???????? ????? ?????? ????? ??????? ?????? ??????? } }; ?

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  • NSPredicate (Core Data fetch) to filter on an attribute value being present in a supplied set (list)

    - by starbaseweb
    I'm trying to create a fetch predicate that is the analog to the SQL "IN" statement, and the syntax to do so with NSPredicate escapes me. Here's what I have so far (the relevant excerpt from my fetching routine): NSFetchRequest *request = [[[NSFetchRequest alloc] init] autorelease]; NSEntityDescription *entity = [NSEntityDescription entityForName: @"BodyPartCategory" inManagedObjectContext:_context]; [request setEntity:entity]; NSPredicate *predicate = [NSPredicate predicateWithFormat:@"(name IN %@)", [RPBodyPartCategory defaultBodyPartCategoryNames]]; [request setPredicate:predicate]; The entity "BodyPartCategory" has a string attribute "name". I have a list of names (just NSString objects) in an NSArray as returned by: [RPBodyPartCategory defaultBodyPartCategoryNames] So let's say that array has string such as {@"Liver", @"Kidney", @"Thyroid"} ... etc. I want to fetch all 'BodyPartCategory' instances whose name attribute matches one of the strings in the set provided (technically NSArray but I can make it an NSSet). In SQL, this would be something like: SELECT * FROM BodyPartCategories WHERE name IN ('Liver', 'Kidney', 'Thyroid') I've gone through various portions of the Predicate Programming Guide, but I don't see this simple use case covered. Pointers/help much appreciated!

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  • Error while saving csv file generated by PHP

    - by user1667374
    I have created below script which is saving the csv file in the same path of this script but when I am saving it to different directory, it gives me error. Can somebody please help me on this? This is the error: Warning: fopen(/store/secure/mas/) [function.fopen]: failed to open stream: No such file or directory in /getdetails.php on line 15 Warning: fputs(): supplied argument is not a valid stream resource in /getdetails.php on line 36 Warning: fclose(): supplied argument is not a valid stream resource in /getdetails.php on line 39 This is the script: <?php $MYSQL_HOST="localhost"; $MYSQL_USERNAME="***"; $MYSQL_PASSWORD="***"; $MYSQL_DATABASE="shop"; $MYSQL_TABLE="ds_orders"; mysql_connect( "$MYSQL_HOST", "$MYSQL_USERNAME", "$MYSQL_PASSWORD" ) or die( mysql_error( ) ); mysql_select_db( "$MYSQL_DATABASE") or die( mysql_error( $conn ) ); $filename="Order_Details"; $directory = "/store/secure/mas/"; $csv_filename = $filename.".csv"; $fd = fopen ( "$directory" . $cvs_filename, "w"); $today="2009-03-17"; $disp_date="05122008"; $sql = "SELECT * FROM $MYSQL_TABLE where cDate='$today'"; $result=mysql_query($sql); $rows=mysql_num_rows($result); echo $rows; if(mysql_num_rows($result)>0){ $fileContent="Record ID,Discount Percent\n"; while($data=mysql_fetch_array($result)) { $fileContent.= "".$data['oID'].",".$data['discount']."\n"; } $fileContent=str_replace("\n\n","\n",$fileContent); fputs($fd, $fileContent); } fclose($fd); ?>

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  • how to retrieve data from db and display it in list?

    - by raji
    In the below code I am passing catID to db.getNews(catID) super.onCreate(savedInstanceState); setContentView(R.layout.newslist); Bundle extras = getIntent().getExtras(); int catID = extras.getInt("cat_id"); mInflater = (LayoutInflater)getSystemService(Context.LAYOUT_INFLATER_SERVICE); final ListView lv = (ListView) findViewById(R.id.category); lv.setAdapter(new ArrayAdapter<String>(this, R.layout.newslist, db.getNews(catID)){ public View getView(int position, View convertView, ViewGroup parent) { View row; if (null == convertView) { row = mInflater.inflate(R.layout.newslist, null); } else { row = convertView; } TextView tv = (TextView) row.findViewById(R.id.newslist_text); tv.setText(getItem(position)); return row; } }); the getnews(int catid) function is below: public NewsItemCursor getNews(int catID) { String sql = "SELECT title FROM news WHERE catid = " + catID + " ORDER BY id ASC"; SQLiteDatabase d = getReadableDatabase(); NewsItemCursor c = (NewsItemCursor) d.rawQueryWithFactory( new NewsItemCursor.Factory(), sql, null, null); c.moveToFirst(); d.close(); return c; } But I'm getting bug as array adapter undefined... Can anyone help me to resolve this, and retrieve data to make it display in list.

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  • How to make cakePHP retreive the data represented by a foreign key?

    - by XL
    Greetings cake experts, I have a question that I think would really help a lot of people getting started with cakePHP. I have a feeling it will be easy for some of you, but it is quite challenging to me. I have a simple database with multiple tables. I can't figure out how to make cakePHP display the values associated with a foreign key in an index view. Or create a view where the fields of my choice (the ones that make sense to users like location name - not location_id can be updated or viewed on a single page). I have created an example at http://lovecats.cakeapp.com that illustrate the question. If you look at the page and click the "list cats", you will notice that it shows the location_id field from the locations table. You will also notice that when you click "add cats", you must choose a location_id from the locations table. This is the automagic way that cakePHP builds the app. I want this to be the field location_name. The database is setup so that the table cats has a foreign key called location_id that has a relationship to a table called locations. This is my problem: I want these pages to display the location_name instead of the location_id. If you want to login to the application, you can go to http://cakeapp.com/sqldesigners/sql/lovecats and the password 'password' to look at the db relationships, etc. How do I have a page that shows the fields that I want? And is it possible to create a page that updates fields from all of the tables at once? This is the slice of cake that I have been trying to figure out and this would REALLY get me over a hump. You can download the app and sql from the above url.

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  • What is an efficient way to serve images (PHP)?

    - by Scarface
    Hey guys currently I am thinking of serving images using an image handler script. I have two sources of images. One is from my web images folder where images that are used to construct my site interface are served. The other is in each users images folder where they can store their own images. I was thinking of giving each user image a unique id and then searching that id with the image handler script and serving the image, and changing the file name. The problem is that my site images folder does not have any information in the database and thus has no ids, should I just serve directly? Also this way of serving user images does not seem like the most efficient. If anyone has any suggestions I would really appreciate it. $sql="SELECT username,file_name FROM images WHERE id=?"; $stmt=$conn->prepare($sql); $result=$stmt->execute(array($ID)); while($row = $stmt->fetch(PDO::FETCH_ASSOC)){ $image_name = $row['file_name']; $username = $row['username']; } $path="$username/images/$image_name"; header("Expires: -1"); header("Cache-Control: no-store, no-cache, must-revalidate"); header("Cache-Control: post-check=0, pre-check=0", false); readfile($path);

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