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  • need a help regarding android 1.5 and 2.1 (beginner)

    - by piemesons
    I am new to android and last year i bought two books of android 1.5. But at that time i was busy in my project so was not able to work on android. Now i want to start android again. Should i go for those books or should i buy new editions Is there any major change regarding basic learnings? Please let me know. Thanks

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  • How to implement Android l10n ?

    1.How to implement Android system l10n ?It has been l10n in German.What is different between Android and Linux in realizing system localization? 2.What is Operational process of implementing Android l10n ? 3.What is needed to implement Android system localization? such as Unicode UTF8, charset,other anything else?

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  • Cross Platform Data Access with Xamarin & C# For iPhone, iPad, and Android - Local, Web Services, & Sql Server

    - by Wallym
    The following is a link to cross platform data access training with Xamarin & C#.   It is intended for use on iPhone, iPad, and Android devices.  The course covers local data in Sqlite, calling Web Services via REST and JSON, and calling Sql Server. Url: http://www.learnnowonline.com/course/cpx2/xamarin-cross-platform-data-access/  Course Data  Applications live on data. These applications can vary from an online social network service, to a company’s internal database, to simple data, and all points in between. This Course will focus on how to easily access data on the device, communicate back and forth with a web service, and then finally to a SQL server database. Outline Local Data (27:36) Introduction (00:36) Problem (01:57) Solution (02:01) LINQ (02:03) LINQ Status (00:48) SQLite (02:18) SQLite - .Net Developers (00:50) SQLite-net (01:07) SQLite-net Attributes (02:10) Getting Started (01:09) CRUD (01:05) SQLite Platforms (01:17) Demo: SQLite – Android (04:53) Demo: SQLite – iOS (04:56) Summary (00:20) Web Services Data (32:43) Introduction (00:19) Async Commands (03:15) HttpClient (01:26) HTTP Verbs (01:29) Notes (00:58) GET Operation (01:37) JSON.NET (01:50) Images (01:16) Other Http Verbs (01:27) Post (03:18) Demo: Http – iOS prt1 (05:26) Demo: Http – iOS prt2 (05:28) Demo: Http – Android (04:20) Summary (00:27) Direct Data (12:33) Introduction (00:23) Remote Data - Direct (02:47) Sql Server (01:15) Demo: Sql Server – iOS (04:15) Demo: Sql Server – Android (01:49) "codepage 1252 not supported" (01:03) Other Resources (00:43) Summary (00:15) Note: Thanks to Frank Kreuger for his data access library Sqlite-Net.  It is very helpful and I have used it in some other projects beyond just this training session.

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  • File format for animated scene

    - by stephelton
    I've got a custom OpenGL based rendering engine and I'd like to add support for cinema-type scene animation. The artist that is helping me uses primarily 3DSMax. I'd like a file format for exporting and importing this data. I'm also in need of a file format for skeletal animation data, which may have an impact here. I've been looking at MAXScript to manually export this stuff, which would buy me the most flexibility, but I have virtually no experience with 3DSMax itself, so I get a little lost when it comes to terminology. So I'd like to know what file formats exist for animated scene data, and whether they are appropriate for my use (my fear is that they will be way too broad for my fairly simple needs.) The way I view animated scene data is basically a bunch of references to [animated] models with keyframe-based matrices describing their orientation over time. And probably some special camera stuff to handle perspective. I might also want some event type stuff for adding/removing objects. Is this a sane concept?

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  • How do you manage the testing of your Android software on physical devices?

    - by Philip Regan
    I'm in charge of managing mobile application development at my company, and I am currently building a mobile device "library" for testing. Essentially, we want to have a representative device in-house for each of the OSes we are developing for, currently iOS (iPhone-only), Blackberry, and Android. Simulators only go so far, but I'm placing into the process a step to test software on the devices themselves. The problem we're finding is with Android. I don't think any of us here ever really understood just how fragmented the whole platform is until we started looking at devices to acquire. We are going to wait until v2.3 of Android is released, but which products to choose? Do we go by the most popular by market share? Do we get a small range of products by specs from least to most powerful overall? We're trying to avoid having to manage a dozen different devices to test each app, if not because of cost if only for the repeated time sink. How do you manage the testing of your Android software on physical devices?

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  • How can I transform a Point2f with a matrix on Android?

    - by Vivendi
    I'm developing for Android and I'm using the android.renderscript.Matrix3f class to do some calculations. What I need to do now is to now is to do something like mat.tranform(pointIn, pointOut); So I need to transform a matrix by a given Point class. In awt I would simply do this: AffineTransform t = new AffineTransform(); Point2D.Float p = new Point2D.Float(); t.transform( p, p ); But in Android I now have this: Matrix3f t = new Matrix3f(); PointF p = new PointF(); // Now I need to tranform it somehow.. But the Matrix3f class in Android doesn't have a Matrix.transform(Point2D ptSrc, Point2D ptDst) method. So I guess I have to do the transformation manually. But I'm not really sure how that works. From what I've seen it's something like a translate and then a rotate? Could anyone please tell me how to do this in code?

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  • CyanogenMod Updates; Rolls out Android 2.3 to the Less Fortunate

    - by ETC
    If you’re one of the less fortunate (namely those forgotten by their carrier when it comes to phone OS upgrade time) you’ve got a friend in Cyanogen. They’ve rolled out a new Release Candidate update that includes Android 2.3 and a host of performance tweaks. First thing to note is that this is an RC and if you upgrade from CyanogenMod 6 to CyanogenMod 7 RC you’ll be trading a little bit of stability and a few features that haven’t made the jump from 6 to 7 in return for the newest features of Android 2.3. If you’re not comfortable with that wait for CyanogenMod 7 to update to a final release. For the intrepid, hit up the link below to read more and grab a copy. CyanogenMod-7 Release Candidates! [Cyanogen via Download Squad] Latest Features How-To Geek ETC Ask How-To Geek: How Can I Monitor My Bandwidth Usage? Internet Explorer 9 RC Now Available: Here’s the Most Interesting New Stuff Here’s a Super Simple Trick to Defeating Fake Anti-Virus Malware How to Change the Default Application for Android Tasks Stop Believing TV’s Lies: The Real Truth About "Enhancing" Images The How-To Geek Valentine’s Day Gift Guide CyanogenMod Updates; Rolls out Android 2.3 to the Less Fortunate MyPaint is an Open-Source Graphics App for Digital Painters Can the Birds and Pigs Really Be Friends in the End? [Angry Birds Video] Add the 2D Version of the New Unity Interface to Ubuntu 10.10 and 11.04 MightyMintyBoost Is a 3-in-1 Gadget Charger Watson Ties Against Human Jeopardy Opponents

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  • copying same file name from client to server using tcp protocol with same size of file

    - by user3686570
    This is the client and server program where a client sends a file to server to save in the server. There is a issuse in that same file name is not getting copied on the server with same file size Please help me in this Client program import socket import sys s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.connect(("localhost",9999)) path=raw_input("Please enter the complete PATH of your file : ") f=open (path, "rb") l = f.read(256) while (l): s.sendall(l) l = f.read(10000) s.close() Server Program import socket import sys s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.bind(("localhost",9999)) s.listen(10) while True: s, address = s.accept() print address i=1 f = open( str(i),'wb') #open in binary #i=i+1 while (True): l=s.recv(256) #while (l): f.write(l) l=s.recv(256) print 'File recieve succesfully' f.close() #sc.close() s.close() Thanks in advance

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  • Java desktop programmer starting to learn Android development: how different is it?

    - by Prog
    I'm a Java programmer. All of my experience is on desktop applications, using Swing for the GUI. I spend a lot of time studying OOP, I have decent understanding of OO concepts and I design and program by the OO approach. I'm thinking of starting to learn Android development soon, and I'm wondering how different it is from desktop development. Obviously the GUI libraries will be different (not Swing), but other than that, I want to know if there are significant differences. I will divide this question to two parts: Apart from the GUI libraries, am I still going to use the standard Java libarary I'm used to? Aka same data structues, same utility classes, etc.? If not, what are the main differences between the libraries I'm used to and the libraries I'll be using? How different is Android development in regard to OO design? Are all of the familiar principles, design patterns, techniques and best pratices just as valid and used? Or is OOP and OOD in Android development significantly different than OO in desktop development? To summarize: apart from GUI design, how different is Java Android development than Java desktop development?

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  • How to limit concurrent file access on a Samba share?

    - by JPbuntu
    I have a Ubuntu 12.04 file server running Samba. There are 6 windows machines that access the server, as well as two people that will occasionally access files remotely. The problem that I am having is that the CAD/CAM software we are using doesn't seem to request file locks, meaning if two people open a file at the same time, the first person to close the file will get their changes overwritten if the second person saves the file. I tried changing the smb.conf to strict locking = yes but this doesn't seem to have any effect. File locking with excel seems to work fine, so I know that Samba is using the file locks...if they were put on the file in the first place. Is there a way (either in Samba or Ubuntu) to only allow one user to have a file open at a time? If not does anyone have any suggestions for managing a problem like this?

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  • File Access problems with SLES 10 SP2 OES2 SP1

    - by Blackhawk131
    We have identified a couple of repeatable, demonstrable scenarios with unexplained rejected folder access on our servers for Mac users. Hopefully, this can be presented to Novell for a solution. What we did to demonstrate scenario 1; 1. setup a PC and Mac side-by-side 2. login to our server and open up to a central location on both Mac and PC 3. on the PC in that central location create a folder 4. on the Mac in that central location drag the created folder to the Mac desktop, this should work fine, no problem 5. on the PC rename that folder 6. on the Mac drag a file to that renamed folder, this should error with the following message; a. You cannot copy some of these items to the destination because their names are too long for the destination. Do you want to skip copying these items and continue copying the other items? b. Select skip, response is the filename is copied to the location with zero or small byte size. Try opening it and you get file is corrupted error message. What we did to demonstrate scenario 2; 1. setup a PC and Mac side-by-side 2. login to our server and open up to a central location on both Mac and PC 3. on the PC in that central location create a folder then create a subfolder 4. copy some content into the subfolder 5. on the Mac in that central location drag the created top level folder to the Mac desktop, this should work fine, no problem 6. on the PC rename that subfolder 7. on the Mac drag that top level folder to the Mac desktop, this should error on the Mac with the following; a. The operation cannot be completed because you do not have sufficient privileges for b. The operation cannot be completed because you do not have sufficient privileges for 8. on the Mac, if you open that subfolder you can see the file copied in step 4 above but, you can not open that file, you get the following message if you try; a. There was an error opening this document. You do not have permission to open this file. 9. on the PC drag some content into the top level folder 10. on the Mac you can open that file directly from the server or copy it locally, no problem, however-the subfolder is still corrupted or locked, whichever 11. on the PC rename the top level folder 12. on the Mac that same file just opened in step 10 above is now not accessible, get the following message; a. The document could not be opened. I have observed some variances in the above. For instance, a change on the PC side may take a moment before you can observer or act on the Mac side - kind of like the server is slow to respond. Also, the error message may vary. However, the key is once a folder, or subfolder, gets renamed by a PC, Mac problems commence. The solution is to create a new folder from a PC and copy the contents of the corrupted folder to the new folder and not rename the folder name. This has to be done on a PC because the corrupted folder is not accessible by a Mac user. Another problem that dovetails with the above is that we know certain characters are not allowed for PC folder or filenames. If a Mac user creates a folder with a slash in the file name, from the PC the user does not see that slash in the name. As soon as the PC user copies a file to that folder, the Mac user is locked from that folder. Will get the following error message; - Sorry, the operation could not be completed because an unexpected error occurred. - (Error code - 50) In addition to the above mentioned character issue with folders, the problem is more evil with filenames. If, for example, you create a file with a slash in the filename on a Mac and copy it to the server you will get the following error message; - You cannot copy some of these items to the destination because their names are too long for the destination. Do you want to skip copying these items and continue copying the other items? Select either Stop or Skip buttons. It does not matter which button is selected. The file name gets copied to the destination location at a reduced size. Depending on the file type, the icon associated with the file may or may not be present. Furthermore, if you open that file on the server you will get the following message; - Couldnt open the file. It may be corrupt or a file format that doesnt recognize. From the users perspective, if they are not observant of the icon or file size, they may disregard the error message and think their file has copied as intended. Only later do they discover the file is corrupt if they open that file. I want to make a note on this problem. It is the PC causing the issue. You can change folder and file names all day on a MAC and you don't have a problem as long as a character is not the issue. Once you change the file name or folder name from a PC the entire folder structure from that level down is corrupted. But it has to be resolved from a PC by creating a new folder and copying the contents to the new folder like stated above. Is something not configured correctly? SUSE Linux Enterprise Server 10 (x86_64) VERSION = 10 PATCHLEVEL = 2 LSB_VERSION="core-2.0-noarch:core-3.0-noarch:core-2.0-x86_64:core-3.0-x86_64" Novell Open Enterprise Server 2.0.1 (x86_64) VERSION = 2.0.1 PATCHLEVEL = 1 BUILD Note: We use Novell clients on all windows systems to connect to the servers for file access and network storage. We use AFP to allow OSx systems to connect to servers.

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  • File Access problems with SLES 10 SP2 OES2 SP1

    - by Blackhawk131
    We have identified a couple of repeatable, demonstrable scenarios with unexplained rejected folder access on our servers for Mac users. Hopefully, this can be presented to Novell for a solution. What we did to demonstrate scenario 1; 1. setup a PC and Mac side-by-side 2. login to our server and open up to a central location on both Mac and PC 3. on the PC in that central location create a folder 4. on the Mac in that central location drag the created folder to the Mac desktop, this should work fine, no problem 5. on the PC rename that folder 6. on the Mac drag a file to that renamed folder, this should error with the following message; a. You cannot copy some of these items to the destination because their names are too long for the destination. Do you want to skip copying these items and continue copying the other items? b. Select skip, response is the filename is copied to the location with zero or small byte size. Try opening it and you get file is corrupted error message. What we did to demonstrate scenario 2; 1. setup a PC and Mac side-by-side 2. login to our server and open up to a central location on both Mac and PC 3. on the PC in that central location create a folder then create a subfolder 4. copy some content into the subfolder 5. on the Mac in that central location drag the created top level folder to the Mac desktop, this should work fine, no problem 6. on the PC rename that subfolder 7. on the Mac drag that top level folder to the Mac desktop, this should error on the Mac with the following; a. The operation cannot be completed because you do not have sufficient privileges for b. The operation cannot be completed because you do not have sufficient privileges for 8. on the Mac, if you open that subfolder you can see the file copied in step 4 above but, you can not open that file, you get the following message if you try; a. There was an error opening this document. You do not have permission to open this file. 9. on the PC drag some content into the top level folder 10. on the Mac you can open that file directly from the server or copy it locally, no problem, however-the subfolder is still corrupted or locked, whichever 11. on the PC rename the top level folder 12. on the Mac that same file just opened in step 10 above is now not accessible, get the following message; a. The document could not be opened. I have observed some variances in the above. For instance, a change on the PC side may take a moment before you can observer or act on the Mac side - kind of like the server is slow to respond. Also, the error message may vary. However, the key is once a folder, or subfolder, gets renamed by a PC, Mac problems commence. The solution is to create a new folder from a PC and copy the contents of the corrupted folder to the new folder and not rename the folder name. This has to be done on a PC because the corrupted folder is not accessible by a Mac user. Another problem that dovetails with the above is that we know certain characters are not allowed for PC folder or filenames. If a Mac user creates a folder with a slash in the file name, from the PC the user does not see that slash in the name. As soon as the PC user copies a file to that folder, the Mac user is locked from that folder. Will get the following error message; - Sorry, the operation could not be completed because an unexpected error occurred. - (Error code - 50) In addition to the above mentioned character issue with folders, the problem is more evil with filenames. If, for example, you create a file with a slash in the filename on a Mac and copy it to the server you will get the following error message; - You cannot copy some of these items to the destination because their names are too long for the destination. Do you want to skip copying these items and continue copying the other items? Select either Stop or Skip buttons. It does not matter which button is selected. The file name gets copied to the destination location at a reduced size. Depending on the file type, the icon associated with the file may or may not be present. Furthermore, if you open that file on the server you will get the following message; - Couldnt open the file. It may be corrupt or a file format that doesnt recognize. From the users perspective, if they are not observant of the icon or file size, they may disregard the error message and think their file has copied as intended. Only later do they discover the file is corrupt if they open that file. I want to make a note on this problem. It is the PC causing the issue. You can change folder and file names all day on a MAC and you don't have a problem as long as a character is not the issue. Once you change the file name or folder name from a PC the entire folder structure from that level down is corrupted. But it has to be resolved from a PC by creating a new folder and copying the contents to the new folder like stated above. Is something not configured correctly? SUSE Linux Enterprise Server 10 (x86_64) VERSION = 10 PATCHLEVEL = 2 LSB_VERSION="core-2.0-noarch:core-3.0-noarch:core-2.0-x86_64:core-3.0-x86_64" Novell Open Enterprise Server 2.0.1 (x86_64) VERSION = 2.0.1 PATCHLEVEL = 1 BUILD Note: We use Novell clients on all windows systems to connect to the servers for file access and network storage. We use AFP to allow OSx systems to connect to servers.

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  • android geting data from sql

    - by sagar
    Hello i m new to android. i wont to connect to sql server for store and get data so so me one can help me sending code of android for do it.. i had tried to do tht with java nd it was workink but now i wont to create a aplication for android my java code is :: import java.sql.*; public class MysqlTest { public static void main (String[] args) { Connection conn = null; try { String userName = "pietro"; //change it to your username String password = "pietro"; //change it to your password String url = "jdbc:mysql://192.168.0.67:3306/registro"; Class.forName("com.mysql.jdbc.Driver").newInstance(); conn = DriverManager.getConnection(url, userName, password); Statement s = (Statement) conn.createStatement(); // code for create a tabel in server s.execute("create table School2 (rolno integer,sub text)"); // code for create a tabel in server s.execute("insert into School2(rolno,sub)values(10,'java')"); //code for add value in tabel s.execute("select rolno,sub from School2");//code for add value in tabel s.close(); System.out.println("Database connection established"); } catch (Exception e) { System.err.println("Cannot connect to database server"); } finally { if (conn != null) { try { conn.close (); System.out.println("Database connection terminated"); } catch (Exception e) { /* ignore close errors */ } } } } }

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  • How to make my Ubuntu an internet gateway for my Android phone

    - by yacine
    I want to use the internet of my school on my Android, the problem is they have a Squid proxy, and many applications on my phone don't use the proxy at all. The obvious solution is to install a transparent proxy on my Android to force all applications to connect through it. The problem is that I need to root the phone to make it work, and I don't want to do it because it's not really my phone and rooting is a little risky- Another solution, which is safer, is to make my computer run as a gateway, so I put my Ubuntu IP in the gateway parameter of the phone. I'm running a small proxy on my ubuntu (cntlm), so I redirect the Android traffic to it. I did it with "iptables" as follows: iptables -t nat -A PREROUTING -s 10.0.1.118 -p tcp -j REDIRECT --to-ports 8888 iptables -t nat -A PREROUTING -s 10.0.1.118 -p udp -j REDIRECT --to-ports 8888 10.0.1.118 is the IP of the phone, 8888 is the port of cntlm (proxy on my PC). Now, on the phone: When I enter www.google.com on the navigator I get nothing (web site not found, error message of Firefox). But, when I enter http://74.125.143.101 (IP of Google) I get an error message from the school proxy (so it worked in some way – my PC redirected the traffic of the phone to the Squid proxy). The error message is : The requested URL could not be retrieved while trying to process the request get / http/1.1 host 74.125.143.101 user-Agent ... ... I think the problem is in the "GET" header,it should be GET 74.125.143.101 HTTP/1.1. But I don't understand what's happening, and I'm a certified CCNA.

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  • "Unable to open file", when the program tries to open file in /proc

    - by tristartom
    Hi, I try to read file /proc/'pid'/status, using c program. The code is as follows, and even I use sudo to run it, the prompt still keeps throwing "Unable to open file". Please let me know if you have any ideas on how to fix this. thanks Richard ... int main (int argc, char* argv[]) { string line; char* fileLoc; if(argc != 2) { cout << "a.out file_path" << endl; fileLoc = "/proc/net/dev"; } else { sprintf(fileLoc, "/proc/%d/status", atoi(argv[1])); } cout<< fileLoc << endl; ifstream myfile (fileLoc); if (myfile.is_open()) { while (! myfile.eof() ) { getline (myfile,line); cout << line << endl; } myfile.close(); } else cout << "Unable to open file"; return 0; }

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  • jQuery: get the file name selected from <input type="file" />

    - by ConNen
    This code should work in IE (don't even test it in Firefox), but it doesn't. What I want is to display the name of the attached file. Any help? <html> <head> <title>example</title> <script type="text/javascript" src="../js/jquery.js"></script> <script type="text/javascript"> $(document).ready( function(){ $("#attach").after("<input id='fakeAttach' type='button' value='attach a file' />"); $("#fakeAttach").click(function() { $("#attach").click(); $("#maxSize").after("<div id='temporary'><span id='attachedFile'></span><input id='remove' type='button' value='remove' /></div>"); $('#attach').change(function(){ $("#fakeAttach").attr("disabled","disabled"); $("#attachedFile").html($(this).val()); }); $("#remove").click(function(e){ e.preventDefault(); $("#attach").replaceWith($("#attach").clone()); $("#fakeAttach").attr("disabled",""); $("#temporary").remove(); }); }) }); </script> </head> <body> <input id="attach" type="file" /><span id="maxSize">(less than 1MB)</span> </body> </html>

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  • Problem when trying to connect to a desktop server from android on wifi

    - by thiagolee
    Hello, I am trying to send a file from the phone running Android 1.5 to a server on a desktop. I wrote some code, which works on emulator, but on the phone it doesn't. I'm connecting to the network through WiFi. It works, I can access the internet through my phone and I've configured my router. The application stops when I'm trying to connect. I have the permissions. Someone have any ideas, below is my code. Running on Android package br.ufs.reconhecimento; import java.io.DataInputStream; import java.io.DataOutputStream; import java.io.File; import java.io.FileInputStream; import java.io.IOException; import java.net.Socket; import android.app.Activity; import android.app.AlertDialog; import android.content.DialogInterface; import android.content.Intent; import android.os.Bundle; import android.util.Log; import android.view.View; import android.view.View.OnClickListener; import android.widget.EditText; import android.widget.ImageButton; /** * Sample code that invokes the speech recognition intent API. */ public class Reconhecimento extends Activity implements OnClickListener { static final int VOICE_RECOGNITION_REQUEST_CODE = 1234; static final String LOG_VOZ = "UFS-Reconhecimento"; final int INICIAR_GRAVACAO = 01; int porta = 5158; // Porta definida no servidor int tempoEspera = 1000; String ipConexao = "172.20.0.189"; EditText ipEdit; /** * Called with the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); // Inflate our UI from its XML layout description. setContentView(R.layout.main); // Get display items for later interaction ImageButton speakButton = (ImageButton) findViewById(R.id.btn_speak); speakButton.setPadding(10, 10, 10, 10); speakButton.setOnClickListener(this); //Alerta para o endereço IP AlertDialog.Builder alerta = new AlertDialog.Builder(this); alerta.setTitle("IP");//+mainWifi.getWifiState()); ipEdit = new EditText(this); ipEdit.setText(ipConexao); alerta.setView(ipEdit); alerta.setMessage("Por favor, Confirme o endereço IP."); alerta.setPositiveButton("OK", new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int which) { ipConexao = ipEdit.getText().toString(); Log.d(LOG_VOZ, "Nova Atribuição do Endreço IP: " + ipConexao); } }); alerta.create(); alerta.show(); } /** * Handle the click on the start recognition button. */ public void onClick(View v) { if (v.getId() == R.id.btn_speak) { //startVoiceRecognitionActivity(); Log.d(LOG_VOZ, "Iniciando a próxima tela"); Intent recordIntent = new Intent(this, GravacaoAtivity.class); Log.d(LOG_VOZ, "Iniciando a tela (instancia criada)"); startActivityForResult(recordIntent, INICIAR_GRAVACAO); Log.d(LOG_VOZ, "Gravação iniciada ..."); } } /** * Handle the results from the recognition activity. */ @Override protected void onActivityResult(int requestCode, int resultCode, Intent data) { Log.d(LOG_VOZ, "Iniciando onActivityResult()"); if (requestCode == INICIAR_GRAVACAO && resultCode == RESULT_OK) { String path = data.getStringExtra(GravacaoAtivity.RETORNO); conexaoSocket(path); } else Log.e(LOG_VOZ, "Resultado Inexperado ..."); } private void conexaoSocket(String path) { Socket socket = SocketOpener.openSocket(ipConexao, porta, tempoEspera); if(socket == null) return; try { DataOutputStream conexao = new DataOutputStream(socket.getOutputStream()); Log.d(LOG_VOZ, "Acessando arquivo ..."); File file = new File(path); DataInputStream arquivo = new DataInputStream(new FileInputStream(file)); Log.d(LOG_VOZ, "Iniciando Transmissão ..."); conexao.writeLong(file.length()); for(int i = 0; i < file.length(); i++) conexao.writeByte(arquivo.readByte()); Log.d(LOG_VOZ, "Transmissão realizada com sucesso..."); Log.d(LOG_VOZ, "Fechando a conexão..."); conexao.close(); socket.close(); Log.d(LOG_VOZ, "============ Processo finalizado com Sucesso =============="); } catch (IOException e) { Log.e(LOG_VOZ, "Erro ao fazer a conexão via Socket. " + e.getMessage()); // TODO Auto-generated catch block } } } class SocketOpener implements Runnable { private String host; private int porta; private Socket socket; public SocketOpener(String host, int porta) { this.host = host; this.porta = porta; socket = null; } public static Socket openSocket(String host, int porta, int timeOut) { SocketOpener opener = new SocketOpener(host, porta); Thread t = new Thread(opener); t.start(); try { t.join(timeOut); } catch(InterruptedException e) { Log.e(Reconhecimento.LOG_VOZ, "Erro ao fazer o join da thread do socket. " + e.getMessage()); //TODO: Mensagem informativa return null; } return opener.getSocket(); } public void run() { try { socket = new Socket(host, porta); }catch(IOException e) { Log.e(Reconhecimento.LOG_VOZ, "Erro na criação do socket. " + e.getMessage()); //TODO: Mensagem informativa } } public Socket getSocket() { return socket; } } Running on the desktop Java: import java.io.BufferedReader; import java.io.DataInputStream; import java.io.DataOutputStream; import java.io.File; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStreamReader; import java.net.ServerSocket; import java.net.Socket; public class ServidorArquivo { private static int porta = 5158; static String ARQUIVO = "voz.amr"; /** * Caminho que será gravado o arquivo de audio */ static String PATH = "/home/iade/Trabalho/lib/"; public static void main(String[] args) { int i = 1; try { System.out.println("Iniciando o Servidor Socket - Android."); ServerSocket s = new ServerSocket(porta); System.out.println("Servidor Iniciado com Sucesso..."); System.out.println("Aguardando conexões na porta: " + porta); while(true) { Socket recebendo = s.accept(); System.out.println("Aceitando conexão de nº " + i); new ThreadedHandler(recebendo).start(); i++; } } catch (Exception e) { System.out.println("Erro: " + e.getMessage()); e.printStackTrace(); } } } class ThreadedHandler extends Thread { private Socket socket; public ThreadedHandler(Socket so) { socket = so; } public void run() { DataInputStream entrada = null; DataOutputStream arquivo = null; try { entrada = new DataInputStream(socket.getInputStream()); System.out.println("========== Iniciando a leitura dos dados via Sockets =========="); long tamanho = entrada.readLong(); System.out.println("Tamanho do vetor " + tamanho); File file = new File(ServidorArquivo.PATH + ServidorArquivo.ARQUIVO); if(!file.exists()) file.createNewFile(); arquivo = new DataOutputStream(new FileOutputStream(file)); for(int j = 0; j < tamanho; j++) { arquivo.write(entrada.readByte()); } System.out.println("========== Dados recebidos com sucesso =========="); } catch (Exception e) { System.out.println("Erro ao tratar do socket: " + e.getMessage()); e.printStackTrace(); } finally { System.out.println("**** Fechando as conexões ****"); try { entrada.close(); socket.close(); arquivo.close(); } catch (IOException e) { System.out.println("Erro ao fechar conex&#65533;es " + e.getMessage()); e.printStackTrace(); } } System.out.println("============= Fim da Gravação ==========="); // tratar o arquivo String cmd1 = "ffmpeg -i voz.amr -ab 12288 -ar 16000 voz.wav"; String cmd2 = "soundstretch voz.wav voz2.wav -tempo=100"; String dir = "/home/iade/Trabalho/lib"; File workDir = new File(dir); File f1 = new File(dir+"/voz.wav"); File f2 = new File(dir+"/voz2.wav"); f1.delete(); f2.delete(); try { executeCommand(cmd1, workDir); System.out.println("realizou cmd1"); executeCommand(cmd2, workDir); System.out.println("realizou cmd2"); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); } } private void executeCommand(String cmd1, File workDir) throws IOException, InterruptedException { String s; Process p = Runtime.getRuntime().exec(cmd1,null,workDir); int i = p.waitFor(); if (i == 0) { BufferedReader stdInput = new BufferedReader(new InputStreamReader(p.getInputStream())); // read the output from the command while ((s = stdInput.readLine()) != null) { System.out.println(s); } } else { BufferedReader stdErr = new BufferedReader(new InputStreamReader(p.getErrorStream())); // read the output from the command while ((s = stdErr.readLine()) != null) { System.out.println(s); } } } } Thanks in advance.

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  • Tail the filename, not the file

    - by Craig Walker
    In UNIX (OS X BSD to be precise), I have a "tail -f" command on a log file. From time to time I want to delete this log file so I can more easily review it in my text editor. I delete the file, and then my program recreates it after new activity. However, my tail command (and anything else that was watching the old log file) doesn't update; it's still watching the old, deleted log file. I think I understand why this is (file names simply being pointers to blocks of file data). I'd like to know how I can work around this. Ideally, my tail command (and anything else I point to the file) would be able to read the data from the new file when the file name has been deleted and recreated. How would I do this?

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  • rsync to EC2: Identity file not accessible

    - by Richard
    I'm trying to rsync a file over to my EC2 instance: rsync -Paz --rsh "ssh -i ~/.ssh/myfile.pem" --rsync-path "sudo rsync" file.pdf [email protected]:/home/ubuntu/ This gives the following error message: Warning: Identity file ~/.ssh/myfile.pem not accessible: No such file or directory. [email protected]'s password: The pem file is definitely located at the path ~/.ssh/myfile.pem, though: vi ~/.ssh/myfile.pem shows me the file. If I remove the remote path from the very end of the rsync command: rsync -Paz --rsh "ssh -i ~/.ssh/myfile.pem" --rsync-path "sudo rsync" file.pdf [email protected] Then the command appears to work... building file list ... 1 file to consider file.pdf 41985 100% 8.79MB/s 0:00:00 (xfer#1, to-check=0/1) sent 41795 bytes received 42 bytes 83674.00 bytes/sec total size is 41985 speedup is 1.00 ...but when I go to the remote server, nothing has actually been transferred. What am I doing wrong?

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  • Viewing file: protocol requests made from a swf

    - by Erik Vold
    I've got a swf file in a index.html file, the swf is basically loading images, but it requests a xml file which details where the image/asset files are located. Now the index file (which is just html, js, and css) works (ie: the swf file is working) when used on this url: http://localhost:8500/core/index.html which I'm able to do with Coldfusion 8 single server development environment. But when I access the file directly with this url: file:///C:/ColdFusion8/wwwroot/core/index.html the swf file does not work. So I'm guessing that the swf is having trouble locating the files that it needs. The problem is I have no idea what file urls it is try to access atm, and both Firebug and Fiddler are not able to inform me what requests are made on the file: protocol. So is there another tool that I can use?

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  • Android - Custom Adapter Problem

    - by Ryan
    Hello, I seem to be having a problem with my Custom Adapter view. When I display the list, it only displays a white screen. Here is how it works: 1.) I send a JSON request 2.) populate the ArrayList with the returned results 3.) create a custom adapter 4.) then bind the adapter. Here is steps 2-4 private void updateUI() { ListView myList = (ListView) findViewById(android.R.id.list); itemList = new ArrayList(); Iterator it = data.entrySet().iterator(); while (it.hasNext()) { //Get the key name and value for it Map.Entry pair = (Map.Entry)it.next(); String keyName = (String) pair.getKey(); String value = pair.getValue().toString(); if (value != null) { ListItem li = new ListItem(keyName, value, false); itemList.add(li); } } CustomAdapter mAdapter = new CustomAdapter( mContext, itemList); myList.setAdapter(mAdapter); //Bind the adapter to the list //Tell the dialog it's cool now. dismissDialog(0); //Show next screen flipper.setInAnimation(inFromRightAnimation()); flipper.setOutAnimation(outToRightAnimation()); flipper.showNext(); } And here is my CustomAdapter class: import java.util.List; import android.R.color; import android.content.Context; import android.view.View; import android.view.ViewGroup; import android.widget.BaseAdapter; import android.widget.ImageView; import android.widget.RelativeLayout; import android.widget.TextView; class MyAdapterView extends RelativeLayout { public MyAdapterView(Context c, ListItem li) { super( c ); RelativeLayout rL = new RelativeLayout(c); RelativeLayout.LayoutParams containerParams = new RelativeLayout.LayoutParams( ViewGroup.LayoutParams.FILL_PARENT, ViewGroup.LayoutParams.FILL_PARENT); rL.setLayoutParams(containerParams); rL.setBackgroundColor(color.white); ImageView img = new ImageView (c); img.setImageResource(li.getImage()); img.setPadding(5, 5, 10, 5); rL.addView(img, 48, 48); TextView top = new TextView(c); top.setText(li.getTopText()); top.setTextColor(color.black); top.setTextSize(20); top.setPadding(0, 20, 0, 0); rL.addView(top,ViewGroup.LayoutParams.FILL_PARENT, ViewGroup.LayoutParams.WRAP_CONTENT); TextView bot = new TextView( c ); bot.setText(li.getBottomText()); bot.setTextColor(color.black); bot.setTextSize(12); bot.setPadding(0, 0, 0, 10); bot.setAutoLinkMask(1); rL.addView(bot,ViewGroup.LayoutParams.FILL_PARENT, ViewGroup.LayoutParams.WRAP_CONTENT); } } public class CustomAdapter extends BaseAdapter { private Context context; private List itemList; public CustomAdapter(Context c, List itemL ) { this.context = c; this.itemList = itemL; } public int getCount() { return itemList.size(); } public Object getItem(int position) { return itemList.get(position); } public long getItemId(int position) { return position; } @Override public View getView(int position, View convertView, ViewGroup parent) { ListItem li = itemList.get(position); return new MyAdapterView(this.context, li); } } Does anyone have any idea why this displays a white screen upon completion?? Thanks in advance!

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  • Android: Retrieving Password via registered Email on My Server

    - by Raghavan'G'
    i am working on retrieving password to the user when he submits his mail id that he registered on my server. I need to check whether he entered correct registered id and give him response by sending password to his corresponding mail and set dialog as password sent to your mail or if he entered wrong mail id i have to show mail id not registered... Any Idea? This is my code... package com.soap; import java.util.regex.Matcher; import java.util.regex.Pattern; import org.ksoap2.SoapEnvelope; import org.ksoap2.serialization.PropertyInfo; import org.ksoap2.serialization.SoapObject; import org.ksoap2.serialization.SoapSerializationEnvelope; import org.ksoap2.transport.HttpTransportSE; import android.app.Activity; import android.app.Dialog; import android.app.ProgressDialog; import android.os.Bundle; import android.util.Log; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText public class Register extends Activity { /** Called when the activity is first created. */ // static Spinner operator = null; private static final String SOAP_ACTION = "......"; private static final String METHOD_NAME = "......"; private static final String NAMESPACE = "......"; private static final String URL = "My site"; private static final String TAG = "HELLO"; Thread t; ProgressDialog dialog; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.forgotpasswordpage); Button signin = (Button) findViewById(R.id.fpwdsubmit); signin.setOnClickListener(new OnClickListener() { public void onClick(View v) { showDialog(0); t = new Thread() { public void run() { register(); } }; t.start(); } }); } @Override protected Dialog onCreateDialog(int id) { switch (id) { case 0: { dialog = new ProgressDialog(this); dialog.setMessage("Please wait while connecting..."); dialog.setIndeterminate(true); dialog.setCancelable(true); return dialog; } } return null; } public void register() { Log.v(TAG, "Trying to Login"); EditText etxt_user = (EditText)findViewById(R.id.fpedtext); String email_id = etxt_user.getText().toString(); SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); request.addProperty("Email", email_id); Pattern EMAIL_ADDRESS_PATTERN =Pattern.compile( "[a-zA-Z0-9\\+\\.\\_\\%\\-\\+]{1,256}" + "\\@" + "[a-zA-Z0-9][a-zA-Z0-9\\-]{0,64}" + "(" + "\\." + "[a-zA-Z0-9][a-zA-Z0-9\\-]{0,25}" + ")+"); Matcher matcher = EMAIL_ADDRESS_PATTERN.matcher(email_id); if(matcher.matches()){ Log.v(TAG, "Your email id is valid ="+email_id); // System.out.println("Your email id is valid ="+email); } else{ // System.out.println("enter valid email id"); Log.v(TAG, "enter valid email id" ); } SoapSerializationEnvelope soapEnvelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); soapEnvelope.dotNet = true; soapEnvelope.setOutputSoapObject(request); HttpTransportSE aht = new HttpTransportSE(URL); try { aht.setXmlVersionTag("<?xml version=\"1.0\" encoding=\"UTF-8\"?>"); aht.call(SOAP_ACTION, soapEnvelope); SoapObject resultsRequestSOAP = (SoapObject) soapEnvelope.bodyIn; Log.v("TAG", String.valueOf(resultsRequestSOAP)); } catch (Exception e) { e.printStackTrace(); } } }

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  • Is there an Android remote app compatible with LibreOffice Impress under Ubuntu?

    - by WarriorIng64
    I have an upcoming presentation I want to make in LibreOffice Impress on my Ubuntu 12.10 laptop. I was wondering if I could get ahold of an Android app which would act like a remote control, allowing me to switch between slides from my phone over WiFi without having to stay near the laptop (I've been told I need to move around more during my presentations). A quick look on the Google Play store seemed to turn up a handful of PowerPoint remote apps for Windows or maybe Mac. I also took a look at Can an Android phone control Ubuntu like a remote?, but that seems more for controlling an Ubuntu media center. Is there anything which will work with LibreOffice Impress on Ubuntu? My phone is a Samsung Galaxy Precedent on Straight Talk, running Android 2.2.2 (latest available version from the carrier). It's not rooted, and there's not much memory on it either, so the smaller and simpler the app the better. Also, it has to be free because I currently don't have a means to pay for an app I may/may not like.

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  • How can I make a permanently updated copy of a file in a different place to the original file?

    - by Mark
    I use two computers, a Linux one for coding and building and a Windows one which has the programming application to load the built program onto the hardware. Both computers have access to a network drive which I use to pass the files from Linux to Windows. My problem is, that every time I build I have to copy the files from where the are created to the network drive. How can I make some sort of file in the network drive on Ubuntu that always mirrors the file which is built in the different location, like a pointer? Thanks!

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  • Cannot access system after deleting passwd file

    - by joao rodrigo leao
    I was trying to change my user name and also my /home/username and my system started to crash. I deleted the passwd file but I had a backup named passwd_bkp. I tried to rename this passwd_bkp as passwd and it did not work. No commands were being executed... I was in a terminal window. I re-started my system and now I cannot login. The GRub loads two options: Linux and recovery mode. I tried to open a sessions as root but it says the file system is corrupted. I cannot access my files. Did I lose all my files?

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