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  • Indexing a method return (depending on Internationalization)

    - by Hedde
    Consider a django model with an IntegerField with some choices, e.g. COLORS = ( (0, _(u"Blue"), (1, _(u"Red"), (2, _(u"Yellow"), ) class Foo(models.Model): # ...other fields... color = models.PositiveIntegerField(choices=COLOR, verbose_name=_(u"color")) My current (haystack) index: class FooIndex(SearchIndex): text = CharField(document=True, use_template=True) color = CharField(model_attr='color') def prepare_color(self, obj): return obj.get_color_display() site.register(Product, ProductIndex) This obviously only works for keyword "yellow", but not for any (available) translations. Question: What's would be a good way to solve this problem? (indexing method returns based on the active language) What I have tried: I created a function that runs a loop over every available language (from settings) appending any translation to a list, evaluating this against the query, pre search. If any colors are matched it converts them backwards into their numeric representation to evaluate against obj.color, but this feels wrong.

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  • Not quite nested inlines?

    - by Lynden Shields
    Not quite sure what to call this, it's not quite nested inlines, but is probably related. I have a 3 level hierarchy of objects, A one-to-many B one-to-many C. Therefore, every C implicitly also belongs to an A. class A(models.Model): stuff = models.CharField("Stuff", max_length=50) class B(models.Model): a = models.ForeignKey(A) class C(models.Model): b = models.ForeignKey(B) I would like all C's that belong to an A to be listed on the admin page for A in an in-line. They do not have to show which B they belong to on the same page. Is this possible or is it the same problem as nested inlines anyway? If it's possible, how do I do it? I'm using django 1.3

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  • NHibernate - Mapping tagging of entities

    - by ZNS
    Hi! I've been wrecking my mind on how to get my tagging of entities to work. I'll get right into some database structuring: tblTag TagId - int32 - PK Name tblTagEntity TagId - PK EntityId - PK EntityType - string - PK tblImage ImageId - int32 - PK tblBlog BlogId - int32 - PK class Image Id EntityType { get { return "MyNamespace.Entities.Image"; } IList Tags; class Blog Id EntityType { get { return "MyNamespace.Entities.Blog"; } IList Tags; The obvious problem I have here is that EntityType is an identifer but doesn't exist in the database. If anyone could help with the this mapping I'd be very grateful.

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  • Implementing tagging in JDO

    - by Julie Paltrow
    I am implementing a tagging system for a website that uses JDO . I would like to use this method. However I am new to relationships in JDO. To keep it simple, what I have looks like this: @PersistentCapable class Post { @Persistent String title; @Persistent String body; } @PersistentCapable class Tag { @Persistent String name; } What kind of JDO relationships do I need and how to implement them? I want to be able to list all Tags that belong to a Post, and also be able to list all Posts that have a given Tag. So in the end I would like to have something like this: Table: Post Columns: PostID, Title, Body Table: Tag Columns: TagID, name Table: PostTag Columns: PostID, TagID

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  • Celery tasks not works with gevent

    - by Novarg
    When i use celery + gevent for tasks that uses subprocess module i'm getting following stacktrace: Traceback (most recent call last): File "/home/venv/admin/lib/python2.7/site-packages/celery/task/trace.py", line 228, in trace_task R = retval = fun(*args, **kwargs) File "/home/venv/admin/lib/python2.7/site-packages/celery/task/trace.py", line 415, in __protected_call__ return self.run(*args, **kwargs) File "/home/webapp/admin/webadmin/apps/loggingquarantine/tasks.py", line 107, in release_mail_task res = call_external_script(popen_obj.communicate) File "/home/webapp/admin/webadmin/apps/core/helpers.py", line 42, in call_external_script return func_to_call(*args, **kwargs) File "/usr/lib64/python2.7/subprocess.py", line 740, in communicate return self._communicate(input) File "/usr/lib64/python2.7/subprocess.py", line 1257, in _communicate stdout, stderr = self._communicate_with_poll(input) File "/usr/lib64/python2.7/subprocess.py", line 1287, in _communicate_with_poll poller = select.poll() AttributeError: 'module' object has no attribute 'poll' My manage.py looks following (doing monkeypatch there): #!/usr/bin/env python from gevent import monkey import sys import os if __name__ == "__main__": if not 'celery' in sys.argv: monkey.patch_all() os.environ.setdefault("DJANGO_SETTINGS_MODULE", "webadmin.settings") from django.core.management import execute_from_command_line sys.path.append(".") execute_from_command_line(sys.argv) Is there a reason why celery tasks act like it wasn't patched properly? p.s. strange thing that my local setup on Macos works fine while i getting such exceptions under Centos (all package versions are the same, init and config scripts too)

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  • Using map() on a _set in a template?

    - by Stuart Grimshaw
    I have two models like this: class KPI(models.Model): """KPI model to hold the basic info on a Key Performance Indicator""" title = models.CharField(blank=False, max_length=100) description = models.TextField(blank=True) target = models.FloatField(blank=False, null=False) group = models.ForeignKey(KpiGroup) subGroup = models.ForeignKey(KpiSubGroup, null=True) unit = models.TextField(blank=True) owner = models.ForeignKey(User) bt_measure = models.BooleanField(default=False) class KpiHistory(models.Model): """A historical log of previous KPI values.""" kpi = models.ForeignKey(KPI) measure = models.FloatField(blank=False, null=False) kpi_date = models.DateField() and I'm using RGraph to display the stats on internal wallboards, the handy thing is Python lists get output in a format that Javascript sees as an array, so by mapping all the values into a list like this: def f(x): return float(x.measure) stats = map(f, KpiHistory.objects.filter(kpi=1) then in the template I can simply use {{ stats }} and the RGraph code sees it as an array which is exactly what I want. [87.0, 87.5, 88.5, 90] So my question is this, is there any way I can achieve the same effect using Django's _set functionality to keep the amount of data I'm passing into the template, up until now I've been passing in a single KPI object to be graphed but now I want to pass in a whole bunch so is there anything I can do with _set {{ kpi.kpihistory_set }} dumps the whole model out, but I just want the measure field. I can't see any of the built in template methods that will let me pull out just the single field I want. How have other people handled this situation?

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  • What's the best way to run Drupal and Django sites behind the same Varnish server?

    - by Alexis Bellido
    I have a high traffic website running with Drupal and Apache, five web servers behind a Varnish server load balancing. Let's say this site is example.com. I'm using five backends and a director like this in my default.vcl: director balancer round-robin { { .backend = web1; } { .backend = web2; } { .backend = web3; } { .backend = web4; } { .backend = web5; } } Now I'm working on a new Django project that will be a new section of this site running on example.com/new-section. After checking the documentation I found I can do something like this: sub vcl_recv { if (req.url ~ "^/new-section/") { set req.backend = newbackend; } else { set req.backend = default; } } That is, using a different backend for a subdirectory /new-section under the same domain. My question is, how do I make something like this work with my director and load balancing setup? I'm probably going to run two or more web servers (backends) with my new Django project, each one with a mix of Gunicorn, Nginx, and a few Python packages, and would like to put all of those in their own Varnish director to load balance. Is it possible to do use the above approach to decide which director to use?, like this: sub vcl_recv { if (req.url ~ "^/new-section/") { set req.director = newdirector; } else { set req.director = balancer; } } All suggestions welcome. Thanks!

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  • Mercurial Tagging/Branching Strategy

    - by Tony Trozzo
    My current project is broken down into 3 parts: Website, Desktop Client, and a Plug-in for a third party program. We had started out originally with Subversion for our source control but decided to try Mercurial after reading Joel Spolsky's final post. Considering we haven't really used the majority of svn's potential before, we figured starting fresh with some basic ideas of how source control worked would make this transition easy. However, after setting up our initial repository, we're lost as to how tagging and branching should work on a project like this. Essentially, we're working on all 3 of these parts at the same time. We want a release to be a combination of the 3 parts. Currently we're working in one repository. For the Plug-in part, we have the first iteration finished which we've been referring to as Plug-In v0.1. For the first official build of the other two parts, we'd also like to refer to them as Website v0.1 and Desktop Client v0.1. When all three parts are at v0.1, we'd like to have a Full Project v0.1. Our problem is we're not sure how to manage all of this in the Hg repository. Would the best way to handle this be to create 3 separate repositories for the 3 stable versions and then 3 more repositories for the current developments? Currently we have this all in one repository. Should we do this in branches (are branches any different from cloning repositories?) and tags? Any help is greatly appreciated.

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  • How do I duplicate Facebook picture tagging functionality?

    - by marcamillion
    I asked this question in another post - http://stackoverflow.com/questions/2597773/how-do-i-put-a-div-box-around-my-cursor-on-click I got a wonderful answer. See the code below: <script type="text/javascript"> $(document).ready(function() { $("#image-wrapper").click(function(e){ var ele = $("<div>"); ele.css({width:"50px", height:"50px", border:"1px solid green", position:"absolute", left: e.pageX - 25, top: e.pageY -25}); $("body").append(ele); }); }); </script> <div id="image-wrapper" style="border: 1px solid red; width: 300px; height: 200px;"> </div> The issue I am having is that when I implement this snippet, on every click a box appears and stays there. So if I click on the image 10 times, I get 10 boxes. How do I get the previous box to disappear once I click somewhere else (i.e. have the box move to another place on the image (just like with Facebook Picture Tagging))? Thanks.

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  • Facebook Tagging friends to the picture

    - by Rajesh Dante
    Below code tag only first uid then then its shows Fatal error: Uncaught OAuthException: (#100) Invalid parameter and can i use exact location for tagging.. as in below code x and y values are in pixel $facebook = new Facebook ( array ( 'appId' => FBAPPID, 'secret' => FBSECRETID ) ); $facebook->setFileUploadSupport ( true ); if (isset ( $_POST ['image'] ) && isset ( $_POST ['tname'] )) { $path_to_image = encrypt::instance ()->decode ( $_POST ['image'] ); $tags = (array)encrypt::instance ()->decode ( $_POST ['tname'] ); /* * Output $tags = array ( 0 => '[{"tag_uid":"100001083191675","x":100,"y":100},{"tag_uid":"100001713817872","x":100,"y":230},{"tag_uid":"100000949945144","x":100,"y":360},{"tag_uid":"100001427144227","x":230,"y":100},{"tag_uid":"100000643504257","x":230,"y":230},{"tag_uid":"100001155130231","x":230,"y":360}]' ); */ $args = array ( 'message' => 'Von ', 'source' => '@' . $path_to_image, 'access_token' => $this->user->fbtoken ) ; $photo = $facebook->api ( $this->user->data->fbid . '/photos', 'post', $args ); // upload works but not tags if (is_array ( $photo ) && ! empty ( $photo ['id'] )) { echo 'Photo uploaded. Check it on Graph API Explorer. ID: ' . $photo ['id']; foreach ( $tags as $key => $t ) { $tagRe = json_encode ( $t ); $args = array ( 'tags' => $tagRe, 'access_token' => $this->user->fbtoken ); $facebook->api ( '/' . $photo ['id'] . '/tags', 'post', $args ); } } }

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  • Go for Zend framework or Django for a modular web application?

    - by dr. squid
    I am using both Zend framework and Django, and they both have they strengths and weakness, but they are both good framworks in their own way. I do want to create a highly modular web application, like this example: modules: Admin cms articles sections ... ... ... I also want all modules to be self contained with all confid and template files. I have been looking into a way to solve this is zend the last days, but adding one omer level to the module setup doesn't feel right. I am sure this could be done, but should I? I have also included Doctrine to my zend application that could give me even more problems in my module setup! When we are talking about Django this is easy to implement (Easy as in concept, not in implementation time or whatever) and a great way to create web apps. But one of the downsides of Django is the web hosing part. There are some web hosts offering Django support, but not that many.. So then I guess the question is what have the most value; rapid modular development versus hosting options! Well, comments are welcome! Thanks

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  • Django: How can I identify the calling view from a template?

    - by bryan
    Short version: Is there a simple, built-in way to identify the calling view in a Django template, without passing extra context variables? Long (original) version: One of my Django apps has several different views, each with its own named URL pattern, that all render the same template. There's a very small amount of template code that needs to change depending on the called view, too small to be worth the overhead of setting up separate templates for each view, so ideally I need to find a way to identify the calling view in the template. I've tried setting up the views to pass in extra context variables (e.g. "view_name") to identify the calling view, and I've also tried using {% ifequal request.path "/some/path/" %} comparisons, but neither of these solutions seems particularly elegant. Is there a better way to identify the calling view from the template? Is there a way to access to the view's name, or the name of the URL pattern? Update 1: Regarding the comment that this is simply a case of me misunderstanding MVC, I understand MVC, but Django's not really an MVC framework. I believe the way my app is set up is consistent with Django's take on MVC: the views describe which data is presented, and the templates describe how the data is presented. It just happens that I have a number of views that prepare different data, but that all use the same template because the data is presented the same way for all the views. I'm just looking for a simple way to identify the calling view from the template, if this exists. Update 2: Thanks for all the answers. I think the question is being overthought -- as mentioned in my original question, I've already considered and tried all of the suggested solutions -- so I've distilled it down to a "short version" now at the top of the question. And right now it seems that if someone were to simply post "No", it'd be the most correct answer :) Update 3: Carl Meyer posted "No" :) Thanks again, everyone.

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  • What's the next steps for moving from appengine to full django?

    - by tomcritchlow
    Hey guys, I'm super new to programming and I've been using appengine to help me learn python and general coding. I'm getting better quickly and I'm loving it all the way :) Appengine was awesome for allowing me to just dive into writing my app and getting something live that works (see http://www.7bks.com/). But I'm realising that the longer I continue to learn on appengine the more I'm constraining myself and locking myself into a single system. I'd like to move to developing on full django (since django looks super cool!). What are my next steps? To give you a feel for my level of knowledge: I'm not a unix user I'm not familiar with command line controls (I still use appengine/python completely via the appengine SDK) I've never programmed in anything other than python, anywhere other than appengine I know the word SQL, but don't know what MySQL is really or how to use it. So, specifically: What are the skills I need to learn to get up and running with full django/python? If I'm going to host somewhere else I suppose I'll need to learn some sysadmin type skills (maybe even unix?). Is there anywhere that offers easy hosting (like appengine) but that supports django? I hear such great things about heroku I'm considering switching to RoR and going there I appreciate that I'm likely not quite ready to move away from appengine just yet but I'm a fiercely passionate learner (http://www.7bks.com/blog/179001) and would love it if I knew all the steps I needed to learn so I could set about learning them. At the moment, I don't even know what the steps are I need to learn! Thank you very much. Sorry this isn't a specific programming question but I've looked around and haven't found a good how-to for someone of my level of experience and I think others would appreciate a good roadmap for the things we need to learn to get up and running. Thanks, Tom PS - if anyone is in London and fancies showing me the ropes in person that would be super awesome :)

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  • How to manage feeds with subclassed object in Django 1.2?

    - by Matteo
    Hi, I'm trying to generate a feed rss from a model like this one, selecting all the Entry objects: from django.db import models from django.contrib.sites.models import Site from django.contrib.auth.models import User from imagekit.models import ImageModel import datetime class Entry(ImageModel): date_pub = models.DateTimeField(default=datetime.datetime.now) author = models.ForeignKey(User) via = models.URLField(blank=True) comments_allowed = models.BooleanField(default=True) icon = models.ImageField(upload_to='icon/',blank=True) class IKOptions: spec_module = 'journal.icon_specs' cache_dir = 'icon/resized' image_field = 'icon' class Post(Entry): title = models.CharField(max_length=200) description = models.TextField() slug = models.SlugField(unique=True) def __unicode__(self): return self.title class Photo(Entry): alt = models.CharField(max_length=200) description = models.TextField(blank=True) original = models.ImageField(upload_to='photo/') class IKOptions: spec_module = 'journal.photo_specs' cache_dir = 'photo/resized' image_field = 'original' def __unicode__(self): return self.alt class Quote(Entry): blockquote = models.TextField() cite = models.TextField(blank=True) def __unicode__(self): return self.blockquote When I use the render_to_response in my views I simply call: def get_journal_entries(request): entries = Entry.objects.all().order_by('-date_pub') return render_to_response('journal/entries.html', {'entries':entries}) And then I use a conditional template to render the right snippets of html: {% extends "base.html" %} {% block main %} <hr> {% for entry in entries %} {% if entry.post %}[...]{% endif %}[...] But I cannot do the same with the Feed Framework in django 1.2... Any suggestion, please?

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  • How can I get sessions to work if I'm using Google App Engine + Django 1.1?

    - by user341642
    Is there a way for me to get sessions working? I know Django has built in session management, and GAE has some tools for it if you're using their watered down version of Django 0.96, but is there a way to get sessions to work if you're trying to use GAE w/ Django 1.1 (i.e. use_library() call). I assume using a db-backed session doesn't work, and a file system backed one won't work b/c we don't have access to the filesystem if we deploy to the Google production servers. This kinda worked (as in didn't crap out) when I used SessionMiddleware backed by a local-memory backed cache and a non-persistent cache (i.e. setting SESSION_ENGINE to django.contrib.sessions.backends.cache). But the session never seems to persist in this case, no matter how I set the timeouts. A new session key is generated on every page reload. Maybe this is b/c the GAE assumes complete statelessness with each request and blows away my local cache? Apologies in advance, I'm pretty new to Python. Any suggestions would be greatly appreciated.

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  • In practice, what are the key differences between Heroku and webfaction? [closed]

    - by jdotjdot
    I've been building and hosting webapps, mainly in Django and Flask, for some time now. Mainly, I've been hosting them on Heroku, because of the free tier and the ease of git-enabled application updating. I have seen that a lot of Django users prefer Webfaction. I looked through their offerings, and they seem to me like a standard web hosting service. Questions: Why might be webfaction considered a good hosting service for Django apps? If Heroku is generally called a "Platform-as-a-Service," what does that make Webfaction? Does it have any important similiarities/distinctions from Heroku that I might somehow be missing?

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  • Facial recognition/detection PHP or software for photo and video galleries

    - by Peter
    I have a very large photo gallery with thousands of similar people, objects, locations, things. The majority of the people in the photos have their own user accounts and avatar photos to match. There are also logical short lists of people potentially in the photo based on additional data available for each photo. I allow users to tag photos with their friends and people they know but an automated process would be better. I've used photo tagger/finder from face.com integrating with Facebook photos and the Google Picasa photo tagger for personal albums also does the same thing and is exactly what I'm looking to do. Is there a PHP script, API for Google Picasa, face.com or other recognition service or any other open source project that provides server-side facial recognition and/or grouping photos by similarity? Examples: As you can see, various photo sharing sites offer the feature, but are there any that provide an API for images stored on my own server or something extensive enough to link into my own gallery and tagging system? viewdle - Face recognition/Tagging for video PHP - Face detection in pure PHP Xarg OpenCV Face.com - app for finding and tagging photos in Facebook Google Picasa - photo sharing TeraSnaps - photo sharing site Google Portrait - photo grouping from Google Image results FaceOnIt - Video face recognition PittPatt - Detection, Recognition, Video Face Mining BetaFace ChaosFace - Real-time Face Detector

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  • How hard is it to modify the Django Models?

    - by alex
    I am doing geolocation, and Django does not have a PointField. So, I am forced to writing in RAW SQL. GeoDjango, the Django library, does not support the following query for MYSQL databases (can someone verify that for me?) cursor.execute("SELECT id FROM l_tag WHERE\ (GLength(LineStringFromWKB(LineString(asbinary(utm),asbinary(PointFromWKB(point(%s, %s)))))) < %s + accuracy + %s)\ I don't nkow why GeoDjango library cannot do this in MYSQL database. I hate writing RAW SQL for calculating distances between two points. Is there a way I can create my own library for Django that can handle this? If so, how hard is it?

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  • After extending the User model in django, how do you create a ModelForm?

    - by mlissner
    I extended the User model in django to include several other variables, such as location, and employer. Now I'm trying to create a form that has the following fields: First name (from User) Last name (from User) Location (from UserProfile, which extends User via a foreign key) Employer (also from UserProfile) I have created a modelform: from django.forms import ModelForm from django.contrib import auth from alert.userHandling.models import UserProfile class ProfileForm(ModelForm): class Meta: # model = auth.models.User # this gives me the User fields model = UserProfile # this gives me the UserProfile fields So, my question is, how can I create a ModelForm that has access to all of the fields, whether they are from the User model or the UserProfile model? Hope this makes sense. I'll be happy to clarify if there are any questions.

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  • How to create an exception folder in a django site?

    - by ninja123
    There are a few folders where I house my django site that I want to be rendered as it would on any other non-django site. Namely, forum (vbulletin) and cpanel. I currently run the site with fastcgi. My .htaccess looks like this: AddHandler application/x-httpd-php5 .htm AddHandler application/x-httpd-php5 .html AddHandler fastcgi-script .fcgi Options +FollowSymLinks RewriteEngine On RewriteBase / AddHandler application/x-httpd-php5 .htm RewriteCond %{REQUEST_URI} !(mysite.fcgi) RewriteRule ^(.*)$ mysite.fcgi/$1 [QSA,L] What are lines I can add so www.mysite.com/forum can not be picked up by django url and be rendered as it would do normally. Thanks.

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  • How do I configure the Python logging module in Django?

    - by mipadi
    I'm trying to configure logging for a Django app using the Python logging module. I have placed the following bit of configuration code in my Django project's settings.py file: import logging import logging.handlers import os date_fmt = '%m/%d/%Y %H:%M:%S' log_formatter = logging.Formatter(u'[%(asctime)s] %(levelname)-7s: %(message)s (%(filename)s:%(lineno)d)', datefmt=date_fmt) log_dir = os.path.join(PROJECT_DIR, "var", "log", "my_app") log_name = os.path.join(log_dir, "nyrb.log") bytes = 1024 * 1024 # 1 MB if not os.path.exists(log_dir): os.makedirs(log_dir) handler = logging.handlers.RotatingFileHandler(log_name, maxBytes=bytes, backupCount=7) handler.setFormatter(log_formatter) handler.setLevel(logging.DEBUG) logging.getLogger().setLevel(logging.DEBUG) logging.getLogger().addHandler(handler) logging.getLogger(__name__).info("Initialized logging subsystem") At startup, I get a couple Django-related messages, as well as the "Initialized logging subsystem", in the log files, but then all the log messages end up going to the web server logs (/var/log/apache2/error.log, since I'm using Apache), and use the standard log format (not the formatter I designated). Am I configuring logging incorrectly?

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  • django-lfs upload Image doesn't work on some environment ?

    - by vernomcrp
    yesterday, after I complete setup django-lfs without buildout. Happlily create categories and products but while I upload image to product after I push upload button its stay always 'pendings'. I use fedora django==1.1.2,PIL==1.1.7. but its work on osx. Now I try on Ubuntu9.10 with completely PIL==1.1.7 and Django==1.1.2 and its won't work. Anyone hav some good solution for this ? (i may think of flash version because upload part looklike its come from flash)

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