Search Results

Search found 4921 results on 197 pages for 'django transactions'.

Page 88/197 | < Previous Page | 84 85 86 87 88 89 90 91 92 93 94 95  | Next Page >

• Initial form data from model - Django

  - by alexBrand

  I am trying to create an edit form for my model. I did not use a model form because depending on the model type, there are different forms that the user can use. (For example, one of the forms has a Tinymce widget, while the other doesn't.) Is there any way of setting the initial data of a form (not a ModelForm) using a model? I tried the following but getting an error: b = get_object_or_404(Business, user=request.user) form = f(initial = b) where f is a subclass of forms.Form The error I am getting is AttributeError: 'Business' object has on attribute 'get'

  Read the article

• Django call function when an object gets added

  - by dotty

  Hay, i have a simple model class Manufacturer(models.Model): name = models.CharField() car_count = models.IntegerField() class Car(models.Model): maker = ForeignKey(Manufacturer) I want to update the car_count field when a car is added to a manufacturer, I'm aware i could just count the Manufacturer.car_set() to get the value, but i want the value to be stored within that car_count field. How would i do this? EDIT Would something like this work? def save(self): if self.id: car_count = self.car_set.count() self.save()

  Read the article

• add new records using signal in django admin

  - by ganesh

  I've a model called broadcastinfo, It has fields viz.. info,userid...userid is excluded. when i add an new info, my broadcastinfo table should get the records of all userid from user table and the given message. Im trying this via signal.Any idea is highly appreciated. Thanks

  Read the article

• Finding object count where a field is unique in Django

  - by Johnd

  I have a model that is something like this: class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() A user can submit many arguments, per case. I want to be able to say how many users have submitted side=true arguments. I mean if 1 user had 10 arguments and another user had 2 arguments (both side=true) I'd want the count to be 2, not 12.

  Read the article

• django update object

  - by John

  Hi, How do I run an update and select statement on the same queryset rather than having to do 2 querys, ones to select the object and one to update the object? the sql would be something like update my_table set field_1 = 'some value' where pk_field = some_value Thanks

  Read the article

• Django: Save an uploaded file to a FileField

  - by David Wolever

  I feel a little stupid for having to ask this… But I can't seem find it documented anywhere. If I've got a Model with FileField, how can I stuff an uploaded FILE into that FileField? For example, I'd like to do something like this: class MyModel(Model): file = FileField(...) def handle_post(request, ...): mymodel = MyModel.objects.get(...) if request.FILES.get("newfile"): mymodel.file = request.FILES["newfile"] But that doesn't appear to work.

  Read the article

• Django: Inject errors into already validated form?

  - by Parand

  After my form.Form validates the user input values I pass them to a separate (external) process for further processing. This external process can potentially find further errors in the values. Is there a way to inject these errors into the already validated form so they can be displayed via the usual form error display methods? Or, are there better alternative approaches? One suggestions was to include the external processing in the form validation. I'm not crazy about this since the external process does a lot more than just validate.

  Read the article

• sending the data from form to db in django

  - by BharatKrishna

  I have a form in which I can input text through text boxes. How do I make these data go into the db on clicking submit. this is the code of the form in the template. <form method="post" action="app/save_page"> <p> Title:<input type="text" name="title"/> </p> <p> Name:<input type="text" name="name"/> </p> <p> Phone:<input type="text" name="phone"/> </p> <p> Email:<input type="text" name="email"/> </p> <p> <textarea name="description" rows=20 cols=60> </textarea><br> </p> <input type="submit" value="Submit"/> </form> I have a function in the views.py for saving the data in the page. But I dont know how to impliment it properly: def save_page(request): title = request.POST["title"] name = request.POST["name"] phone = request.POST["phone"] email = request.POST["email"] description = request.POST["description"] Now how do I send these into the db? And what do I put in views.py so that those data goes into the db? so how do I open a database connection and put those into the db and save it? should I do something like : connection=sqlite3.connect('app.db') cursor= connection.cursor() ..... ..... connection.commit() connection.close() Thank you.

  Read the article

• Django: optimizing queries

  - by Josh

  I want to list the number of items for each list. How can I find this number in a single query, rather than a query for each list? Here is a simplified version of my current template code: {% for list in lists %} <li> {{ listname }}: {% with list.num_items as item_count %} {{ item_count }} item{{ item_count|pluralize }} {% endwith %} </li> {% endfor %} lists is passed as: List.objects.filter(user=user) and num_items is a property of the List model: def _get_num_items(self): return self.item_set.filter(archived=False).count() num_items = property(_get_num_items) This queries SELECT COUNT(*) FROM "my_app_item" WHERE... n times, where n is the number of lists. Is it possible to make a single query here?

  Read the article

• JSON | Django passing python list

  - by MMRUser

  Hi, I'm trying to send a Python list in to client side (encoded as JSON), this is the code snippet which I have written: array_to_js = [vld_id, vld_error, False] array_to_js[2] = True jsonValidateReturn = simplejson.dumps(array_to_js) return HttpResponse(jsonValidateReturn, mimetype='application/json') So my question is how to access it form client side, can I access it like this: jsonValidateReturn[0] or how I assign a name to the returned JSON array in order to access it?

  Read the article

• How to verify object creation in Django ?

  - by Martin

  So.. this never crossed my head before but now I just can't figure out how to do that !! I want to verify that the object I created was really created, and return True or False according to that : obj = object(name='plop') try: obj.save() return True except ???: return False Any idea ? Cheers, -M

  Read the article

• send encripted parameters to a view in django

  - by nadeem

  I want to send a project_id veriable in a edit_project view in djnago. can any one tell me that how can I do that ........

  Read the article

• Django query - join on the same table

  - by dana

  i have a mini blog app, and a 'timeline' . there i want to be displayed all the posts from all the friends of a user, plus the posts of that user himself. For that, i have to make some kind of a 'join' between the results of two queries (queries on the same table) , so that the final result will be the combination of the user - posesor of the account, and all his friends. My query looks like this: blog = New.objects.filter(created_by = following,created_by = request.user) By that ',' i wanted to make a 'join' -i found something like this on a doc- but this method is not correct- i'm getting an error. How else could be done this 'join' ? Thanks!

  Read the article

• How to join the results of two tables in django python

  - by user1787524

  I have two models class Weather(model.model): region = models.ForeignKey(Region) district = models.ForeignKey(District) temp_max = models.IntegerField(blank=True, null=True, verbose_name='Max temperature (C)') temp_min = models.IntegerField(blank=True, null=True, verbose_name='Min temperature (C)') and class Plan(model.model): name = tinymce_models.HTMLField(blank=True, null=True) region = models.ForeignKey(Region) district = models.ForeignKey(District) Provided for every region and district have unique row. I want to combine the result so that i can get all the columns of both tables These two Models are not related to each other. ' I need to make the join like join weather w on w.region = A.region and w.distric = A.district so that result contains all the columns in everyobject like obj.temp_max etc

  Read the article

• Django user get_all_permissions() is empty while user_permissions is set

  - by Murkin

  Hello I added some permissions to a user via the admin interface. From some reason all the perm functions fail, e.g >>> user.get_all_permissions() set([]) But accessing the table directly, works: >>> user.user_permissions.all() (list of permissions as expected) What can cause the "get_all_permissions" (and all the perm functions like has_perm()) to fail ? Thanks

  Read the article

• Python/Django tests running only one test at a time

  - by user2876296

  I have a unittest for my view class TestFromAllAdd(TestCase): fixtures = ['staging_accounts_user.json', 'staging_main_category.json', 'staging_main_dashboard.json', 'staging_main_location.json', 'staging_main_product.json', 'staging_main_shoppinglist.json'] def setUp(self): self.factory = RequestFactory() self.c = Client() self.c.login(username='admin', password='admin') def from_all_products_html404_test(self): request = self.factory.post('main/adding_from_all_products', {'product_id': ''}) request.user = User.objects.get(username= 'admin') response = adding_from_all_products(request) self.assertEqual(response.status_code, 404) But I have a few more classes with tests and I cant run them all at the same time: python manage.py test main doesnt run tests, but if i run; python manage.py test main.TestFromAllAdd.from_all_products_html404_test , runs one test;

  Read the article

• good django source browser app?

  - by Nick

  I need that works at least with svn, that reads your svn repository and displays information about files and folders contained in it as well as maybe revision info too.

  Read the article

• How do I query for this in Django?

  - by alex

  | random_code | varchar(200) | YES | UNI | NULL | | MyTable.objects.filter(random_code = None) Is this correct? Will this SELECT where there is no random code set? Above is my table.

  Read the article

• Django forms: where is POST data received?

  - by Rosarch

  I have a widget that allows user to enter data for a model field. The data in the form can't be directly converted to Python - it requires some coercion. Where do I put this code? Is the widget responsible for translating its post data to a python value? The field itself? I thought that maybe value_from_datadict() would be correct, but now it looks like that serves a different purpose. (I'm using the form in the admin interface, if it makes any difference.)

  Read the article

• Django template tag for Model query result

  - by dynback.com

  I wonna simple tag, for showing table of any model arrays like: {% table city_list %} Do anybody see such things?

  Read the article

• Django get() query not working

  - by pimcoooooooo

  this_category = Category.objects.get(name=cat_name) gives error: get() takes exactly 2 non-keyword arguments (1 given) I am using the appengine helper, so maybe that is causing problems. Category is my model. Category.objects.all() works fine. Filter is also similarily not working. Thanks,

  Read the article

• Deleting files associated with model - django

  - by alexBrand

  I have the following code in one of my models class PostImage(models.Model): post = models.ForeignKey(Post, related_name="images") # @@@@ figure out a way to have image folders per user... image = models.ImageField(upload_to='images') image_infowindow = models.ImageField(upload_to='images') image_thumb = models.ImageField(upload_to='images') image_web = models.ImageField(upload_to='images') description = models.CharField(max_length=100) order = models.IntegerField(null=True) IMAGE_SIZES = { 'image_infowindow':(70,70), 'image_thumb':(100,100), 'image_web':(640,480), } def delete(self, *args, **kwargs): # delete files.. self.image.delete(save=False) self.image_thumb.delete(save=False) self.image_web.delete(save=False) self.image_infowindow.delete(save=False) super(PostImage, self).delete(*args, **kwargs) I am trying to delete the files when the delete() method is called on PostImage. However, the files are not being removed. As you can see, I am overriding the delete() method, and deleting each ImageField. For some reason however, the files are not being removed.

  Read the article

• Hooking up Sproutcore frontend and custom Python backend

  - by Suvir

  Hello everyone, I am building a web-based application. The frontend has been designed in Sproutcore. For the backend, we have our own python API which handles all transactions with multiple databases. What is the best way to hook up the front-end with the back-end. AFAIK django is pretty monolithic (correct me if i am wrong) and it would be cumbersome if I dont use its native ORM...I would prefer a python-based solution..any ideas? thanks! Suvir

  Read the article

• Django, wsgi, py. what's the difference?

  - by Kenny

  I'm trying to get a django application up and running on my cpanel system. I've installed mod_wsgi, and am following the guide here: http://www.nerdydork.com/setting-up-django-on-a-whm-cpanel-vps-liquidweb.html However, I'm now confused as I don't know what to do next. The application has .py files, and I am able to run it via this: python manage.py runserver 211.144.131.148:8000 However, that's via command line and binds to port 8000. I want to use Apache instead. The question is, that tutorial doesn't go further into how to get apache to recognize .py files and run the application as I want it. What do I do next?

  Read the article

• How to setup a django site with Cherokee, DynDNS and virtual_env?

  - by e-satis

  I have a django project running with the dev server, and would like to try run it in a production environment. I wanted to try Cherokee for a change, so I installed it. We don't have a domain name yet, so I set up a DynDNS looking like stuff.gotdns.org. It works fine, I can see the Cherokee welcome page (so red, I first believed I got an error :-p). I ran the wizard to create a new virtual server for Django. No everything is setup, but I have nothing. Still the default Cherokee welcome page. What should I do now if I want to go to "http://stuff.gotdns.org" and see my website? What should I do now if I next want to make it available only at "http://project.stuff.gotdns.org"? Important fact, I use virtual_env, so your can call Python directly, you have to activate it first.

  Read the article

< Previous Page | 84 85 86 87 88 89 90 91 92 93 94 95  | Next Page >