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  • Whois list of Top Level Domain against their corresponding registrar

    - by Daniel
    I'm trying to find a list of TLD's to their corresponding whois server, for example .com americanWhoisServer .net someOtherWhoisServer .au australianWhoisServer In the end i'm aiming for something like a Dictionary where the key is the TLD and the value is the whois server address (eg whois.apnic.net). Ah snap, i just realised that i am given the IP addresses and not domain names but a list could still come in handy. How can i determine which whois server to use given a IP address? Guess and check?

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  • Converting List<String> to String[] in Java

    - by Christian
    How do I convert a list into an array? The following code returns an error. public static void main(String[] args) { List<String> strlist = new ArrayList<String>(); strlist.add("sdfs1"); strlist.add("sdfs2"); String[] strarray = (String[]) strlist.toArray(); System.out.println(strarray); }

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  • dataset to List<T>using linq

    - by bharat
    I have the dataset and I want to convert the dataset into List<T> T - type object How do I do it my dataset? It has 10 columns, with all 10 properties my object has and it's returning over 15000 rows. I want to return that dataset into List<obj> and loop it how do I do that?

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  • Collect a list in JS with regex?

    - by acidzombie24
    Basically i want to output a div with all the ids in it. I know how to do that especially with jquery but collecting the ids is the problem not the list. I failed at regex although i know how to use it in .NET. How do i write this regex properly? so i can get a list of ids and display it as i want. http://jsfiddle.net/NgmGf/

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  • Difference between the List and Enumeration

    - by harigm
    I have a written a method to get all the records and return in the List Type, but I got out of memory error. So I changed return type from List to Enumeration, in the method, instead of ArrayList, uses Vector and return vector.elements at the end of the method. It works without any error. but I did not understand why. Could someone explain Why this Enumeration worked?

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  • List as a key to a dictionary

    - by williamx
    Let's say I have a list: a = ['apple', 'orange'] and a dictionary: d ={'apple': [2,4], 'carrot': [44,33], 'orange': [345,667]} How can I use the list a as a key to lookup in the dictionary d? I want the result to be written to a comma-separated textfile like this apple, orange 2, 44 4, 33

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  • How to access current item from a sharepoint list in Visual Studio 2010

    - by Damir
    Hello, When using sharepoint designer you can quite easily use current item and perform different actions with it when using workflows etc. However, the options available are limited. I am wondering how to access current item in a list through visual studio 2010 and use and assign values from its fields to variables or items in another list automatically using C# code. Any help would be most appreciated. Thanks

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  • List All Google Map Marker Images

    - by Dau Thanh Hai
    Do you often use image marker from google or copy it to your server? Where I can get all images list of available markers from google? The list of images such as : http://maps.gstatic.com/intl/en_ALL/mapfiles/dd-end.png http://maps.gstatic.com/intl/en_ALL/mapfiles/dd-start.png

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  • List to CSV in Python

    - by Steve
    Hi, I am creating a CSV from a list of values. CSV File gets created but the csv is formed as a single column. Actually it should be multiple rows with multiple columns, instead it forms as a multiple rows with a single column. I am using the following code from random import choice import csv fileObject = csv.writer(open('Insurance.csv','w'),dialect='excel',delimiter=' ') for i in range(0,175): current_list = list(choice(master_list)) fileObject.writerows(current_list) current_list = [] Thanks

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  • Acess itemRenderer in List

    - by dede
    How to access List itemRenderer and its properties (Spark - Flex 4)? I want to iterate through list and do something like (note it's pseudo code): for (var i=0;i<NUMBER_OF_ITEMS_IN_LIST; i++){ myList.getItemRenderer[i].property }

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  • Getting a full list of the URLS in a rails application

    - by Laurie Young
    How do I get a a complete list of all the urls that my rails application could generate? I don't want the routes that I get get form rake routes, instead I want to get the actul URLs corrosponding to all the dynmically generated pages in my application... Is this even possible? (Background: I'm doing this because I want a complete list of URLs for some load testing I want to do, which has to cover the entire breadth of the application)

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  • LINQ/C#: Where & Foreach using index in a list/array

    - by Andrew White
    Hi, I have a list/array and need to process certain elements, but also need the index of the element in the processing. Example: List Names = john, mary, john, bob, simon Names.Where(s = s != "mary").Foreach(MyObject.setInfo(s.index, "blah") But cannot use the "index" property with lists, inversely if the names were in an Array I cannot use Foreach... Any suggestions?

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  • Getting Dictionary<string,string> from List<Control>

    - by codymanix
    I want a dictionary containing the names and text of all controls. Is it possible with predefined framework methods/LINQ/colection initializers or do I have to make a loop and add all entries by myself? This gives me an error message: List<Control> controls; // .. initialize list .. controls.ToDictionary((Control child,string k)=>new KeyValuePair<string,string>(child.Name, child.Text));

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  • How to remove list of words from strings

    - by zeljko
    What I would like to do (in Clojure): For example, I have a vector of words that need to be removed: (def forbidden-words [":)" "the" "." "," " " ...many more...]) ... and a vector of strings: (def strings ["the movie list" "this.is.a.string" "haha :)" ...many more...]) So, each forbidden word should be removed from each string, and the result, in this case, would be: ["movie list" "thisisastring" "haha"]. How to do this ?

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  • Computation on db data then list them using either SimpleCursorAdapter or ArrayAdapter

    - by kc2uno
    Hi all, I juststarted programming in android a few weeks ago, so I am not entirely sure how to deal with listing values. Please help me out! I have some questions regarding displaying data sets from db in a list. Currently I have a cursor returned by my db points to a list of rows and I want display 2 columns values in a single row of the list. The row xml looks like this: <TextView android:id="@+id/text1" android:textSize="16sp" android:textStyle="bold" android:layout_width="fill_parent" android:layout_height="wrap_content"/> <TextView android:id="@+id/text2" android:textSize="14sp" android:layout_width="fill_parent" android:layout_height="wrap_content"/> so I was thinking using simplecursoradapter which supposedly makes my life easier by displaying the data in a list. However that is only true if I want to display the raw data. For the purpose of my program I need to do some computations on the raw data sets, then display them. I am not sure how to do that using SimpleCursorAdapter. Here's how I display the raw data: String[] from = new String[]{BtDbAdapter.KEY_EX_TYPE,BtDbAdapter.KEY_EX_TIMESTAMP}; int[] to = new int[]{R.id.text1, R.id.text2}; // Now create a simple cursor adapter and set it to display SimpleCursorAdapter records = new SimpleCursorAdapter(this, R.layout.exset_row, mExsetCursor, from, to); setListAdapter(records); Is there a way to do computation on the data in those rows before I bind it with the SimpleCursorAdapter? I was trying to use an alternative way of doing this by using arraylist and arrayadapter, but that way I dont know to how achieve displaying 2 items in a single row. This is my code for using arrayadapter which only display 1 text in a row instead of 2 textviews in a row: //fill in the array timestamp_arr = new ArrayList<String>(); type_arr = new ArrayList<String>(); fillRecord(); Log.d(TAG,"setting now in recordlist"); setListAdapter(new ArrayAdapter<String>(this, R.layout.list_item,timestamp_arr)); setListAdapter(new ArrayAdapter<String>(this, R.layout.list_item2,type_arr)); It's very obvious that it only displays one textview in a row because I set the second arrayadapter overwrites the first one! I was trying to use R.id.text1 and R.id.text2 for them, but it gave me some errors saying 04-23 01:40:58.658: ERROR/AndroidRuntime(3309): android.content.res.Resources$NotFoundException: Resource ID #0x7f070008 type #0x12 is not valid I believe the second method can achieve this, but I'm not sure how do deal with the layout problems, so if you any suggestions, please post them out. Thank you!!

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  • Multiple views and source list in a Core Data app

    - by Ellie P.
    I'm working on my first major Cocoa app for an undergraduate research project. The application is document-based and uses Core Data. One of the entities is an abstract entity, Page. Page is parent of several types of pages: ie PageWithHeaderAndFooter, PageWithTwoColumns, BasicPage etc. Page has attributes, such as title and author, that all pages have in common. Each specific type of page has a certain number of layout blocks (PageWithHeaderAndFooter has three: header, footer, body. BasicPage has one: body. etc.) Additionally, all Page subclasses define layout-specific implementations of certain methods. The other relevant entity is Style, which defines the visual look of a Page. (Think of Pages as HTML and Style as CSS.) I would like my app to have an iTunes/Mail-like source list with sections. (One section would be Pages, the other would be Styles.) I have a pretty good idea how to do the sectioned source list (this was a great help). However, after hours of headbanging and fruitless googling, here's what I can't figure out: Pages and Styles listed in the source list, and when you select one of them, all of the relevant fields for that object appear at the right (mostly NSTextViews, pop up menus, etc). I laid that out and did all of the bindings in Interface Builder. The problem is, if my source list contains different types of pages, how do I get a different view to display at the right depending on the type of page selected? For example, if a BasicPage is selected, I want just what you see above: the general page stuff and one NSTextView that corresponds to the one field body of BasicPage. But if I select a PageWithHeaderAndFooter, I want to display the general page stuff plus three NSTextViews (one for header, body, and footer.) If I have a Style selected, I want to display various pop up menus, color wells, etc. For the pages at least, we're only talking about one or more NSTextViews, each of which corresponds to a String attribute of the respective entity. How would you do this? Thank you for your help!

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  • [sql server 2005]how to list all table name in T-SQL

    - by shrimpy
    SELECT name FROM sys.databases -- this can list all database name in the server user database SELECT * FROM INFORMATION_SCHEMA.TABLES -- these two line can list the table for one particular database but how to do something in order can have the result like the following Database Table --------- ------------- db1 t1 db1 t2 db2 t1 ... ... -thx

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  • after shuffle a list get array with jquery

    - by robertdd
    i want after i shuffle a list of images to get all the alt="" value in one array! but i get always the save value!why? $('ul').shuffle(); //this will shuffle the list var a = {}; $("ul img").each(function() { a[this.alt] = $(this).attr("alt"); }); $.operation(a, shuffle);

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