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  • Why ajax doesn't work unless I refresh or use location.href?

    - by Connor Tang
    I am working on a html project, which will eventually package by Phonegap. So I am trying to encode the data from html form to JSON format, then use ajax send to a php file resides on server, and receive the response to do something else. Now I use <a href='login.html'> in my index.html to open the login page. In my login page, I have this <script> $(document).ready(function(e) { $('#loginform').submit(function(){ var jData = { "email": $('#emailLogin').val(), "password": $('#Password').val()}; $.ajax({ url: 'PHP/login.php', type:'POST', data: jData, dataType: 'json', async: false, error: function(xhr,status){ //reload(); location.href='index.html'; alert('Wrong email and password'); }, success: function(data){ if(data[1] == 1){ var Id_user = data[0]; location.href='loginSuccess.html'; } } }); }); }); </script> to send my data to server. But I found that it won't work, it's still in the login page. I tried to enter data and submit again, it's still nothing happen. Until I refresh the login page and enter data again, it can give an error message or go to the loginsuccess page. However, when I use <script> function loadLogin(){ location.href='login.html'; } </script> to open the login page, everything works well. So what cause this? How can I modify this piece of code to make it better?

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  • Need help on HttpWebrequest

    - by ASPUSER
    HI Guys I have the same issue and I am looking to solve it. Here is detail I have two web sites WebsiteA and WebSiteB (WebsiteB is not in my control, A type of black box for me.). Both websites have seprate login page I have alist of users,password of websiteB which I stored in database. I want a kind of common login page. If user is login to websiteA and he want to go to websiteB, he dont have to enter the login and password information again. I can not touch the code of websiteB. it's alredy deployed and runing. In websiteB in login form they have a Userid textbox and Password textbox and and a login Button. This butoon is not a submit button. It has a click event which calls a function to validate the user. it's not a simple post. WebsiteB has one webpage which has different frames. After login sucessfull. The pages doesnt go to any other page it remain on the same page but load the different frame. According to my knowledge. I can use httpwebrequest class. But faceing the following problem. Can not click the button. Response.Redirect does not work. It seems that WebsiteB is not storing any thing in cookies as cookies always return me a empty string I really appriciate if anyone can help me on it. How Can I use response.Redirect . As when I redirect it shows me the same login page.

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  • deployd authentification using jquery ajax

    - by user2507987
    I have installed deployd in my debian 7.0.0 64 bit, I have also succesfully installed mongodb in it, I have create some collection and user collection in deployd dashboard, then using user guide how to connect and query the table in deployd, I choose jquery ajax to log in to deployd from my localhost site and after login success I try to get/post some data, but somehow deployd return access denied. I have create collection name it people, and then at the GET, POST, PUT Event I have write this code : cancelUnless(me, "You are not logged in", 401); then using this ajax code, I try to login and POST new people data: $(document).ready(function(){ /* Create query for username and password for login */ var request = new Object; request.username = 'myusername'; request.password = 'mypassword'; submitaddress = "http://myipaddress:myport/users/login"; $.ajax({ type: "POST", url: submitaddress, data: request, cache: false, success: function(data){ var returndata = eval(data); /* After Login success try to post people data */ if (returndata){ var request2 = new Object; request2.name = 'People Name'; submitaddress2 = "http://myipaddress:myport/people"; $.ajax({ type: "POST", url: submitaddress2, data: request2, cache: false, success: function(){ } }) } } } }); }) The login process success, it's return session id and my user id, but after login success and I try to POST people data it's return "You are not logged in", can anyone help me, what is the correct way to login to deployd using jquery from other website(cross domain)?

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  • form.has_errors tag not working

    - by John
    Hello, Im using Django 1.2.3. I have login functionality in my site using django.contrib.auth.views.login. The user is able to login after entering correct username and password. But, form.has_errors is not working i.e. if the login credentials entered are incorrect i dont see the error message. My login.html in templates/registration is as follows : <html> <head> <title>Login</title> </head> <body> <h1>User Login</h1> {% if form.has_errors %} <p>Your username and password didn't match. Please try again.</p> {% endif %} <form method="post" action="."> {% csrf_token %} <p><label for="id_username">Username:</label> {{ form.username }}</p> <p><label for="id_password">Password:</label> {{ form.password }}</p> <input type="hidden" name="next" value="/" /> <input type="submit" value="login" /> </form> </body> </html> Any way to fix this problem? Please Help Thank You.

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  • The type or namespace cannot be found (are you missing a using directive or an assembly reference?)

    - by Kumu
    I get the following error when I try to compile my C# program: The type or namespace name 'Login' could not be found (are you missing a using directive or an assembly reference?) using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace FootballLeague { public partial class MainMenu : Form { FootballLeagueDatabase footballLeagueDatabase; Game game; Team team; Login login; //Error here public MainMenu() { InitializeComponent(); changePanel(1); } public MainMenu(FootballLeagueDatabase footballLeagueDatabaseIn) { InitializeComponent(); footballLeagueDatabase = footballLeagueDatabaseIn; } private void Form_Loaded(object sender, EventArgs e) { } private void gameButton_Click(object sender, EventArgs e) { int option = 0; changePanel(option); } private void scoreboardButton_Click(object sender, EventArgs e) { int option = 1; changePanel(option); } private void changePanel(int optionIn) { gamePanel.Hide(); scoreboardPanel.Hide(); string title = "Football League System"; switch (optionIn) { case 0: gamePanel.Show(); this.Text = title + " - Game Menu"; break; case 1: scoreboardPanel.Show(); this.Text = title + " - Display Menu"; break; } } private void logoutButton_Click(object sender, EventArgs e) { login = new Login(); login.Show(); this.Hide(); } Login.cs class: using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace FootballLeagueSystem { public partial class Login : Form { MainMenu menu; public Login() { InitializeComponent(); } private void administratorLoginButton_Click(object sender, EventArgs e) { string username1 = "08247739"; string password1 = "08247739"; if ((userNameTxt.Text.Length) == 0) MessageBox.Show("Please enter your username!"); else if ((passwordTxt.Text.Length) == 0) MessageBox.Show("Please enter your password!"); else if (userNameTxt.Text.Equals("") || passwordTxt.Text.Equals("")) MessageBox.Show("Invalid Username or Password!"); else { if (this.userNameTxt.Text == username1 && this.passwordTxt.Text == password1) MessageBox.Show("Welcome Administrator!", "Administrator Login"); menu = new MainMenu(); menu.Show(); this.Hide(); } } private void managerLoginButton_Click(object sender, EventArgs e) { { string username2 = "1111"; string password2 = "1111"; if ((userNameTxt.Text.Length) == 0) MessageBox.Show("Please enter your username!"); else if ((passwordTxt.Text.Length) == 0) MessageBox.Show("Please enter your password!"); else if (userNameTxt.Text.Equals("") && passwordTxt.Text.Equals("")) MessageBox.Show("Invalid Username or Password!"); else { if (this.userNameTxt.Text == username2 && this.passwordTxt.Text == password2) MessageBox.Show("Welcome Manager!", "Manager Login"); menu = new MainMenu(); menu.Show(); this.Hide(); } } } private void cancelButton_Click(object sender, EventArgs e) { this.Close(); } } } Where is the error? What am I doing wrong?

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  • dovecot imap ssl certificate issues

    - by mulllhausen
    i have been trying to configure my dovecot imap server (version 1.0.10 - upgrading is not an option at this stage) with a new ssl certificate on ubuntu like so: $ grep ^ssl /etc/dovecot/dovecot.conf ssl_disable = no ssl_cert_file = /etc/ssl/certs/mydomain.com.crt.20120904 ssl_key_file = /etc/ssl/private/mydomain.com.key.20120904 $ /etc/init.t/dovecot stop $ sudo dovecot -p $ [i enter the ssl password here] it doesn't show any errors and when i run ps aux | grep dovecot i get root 21368 0.0 0.0 12452 688 ? Ss 15:19 0:00 dovecot -p root 21369 0.0 0.0 71772 2940 ? S 15:19 0:00 dovecot-auth dovecot 21370 0.0 0.0 14140 1904 ? S 15:19 0:00 pop3-login dovecot 21371 0.0 0.0 14140 1900 ? S 15:19 0:00 pop3-login dovecot 21372 0.0 0.0 14140 1904 ? S 15:19 0:00 pop3-login dovecot 21381 0.0 0.0 14280 2140 ? S 15:19 0:00 imap-login dovecot 21497 0.0 0.0 14280 2116 ? S 15:29 0:00 imap-login dovecot 21791 0.0 0.0 14148 1908 ? S 15:48 0:00 imap-login dovecot 21835 0.0 0.0 14148 1908 ? S 15:53 0:00 imap-login dovecot 21931 0.0 0.0 14148 1904 ? S 16:00 0:00 imap-login me 21953 0.0 0.0 5168 944 pts/0 S+ 16:02 0:00 grep --color=auto dovecot which looks like it is all running fine. so then i test to see if i can telnet to the dovecot server, and this works fine: $ telnet localhost 143 Trying 127.0.0.1... Connected to localhost. Escape character is '^]'. * OK Dovecot ready. but when i test whether dovecot has configured the ssl certificates properly, it appears to fail: $ sudo openssl s_client -connect localhost:143 -starttls imap CONNECTED(00000003) depth=0 /description=xxxxxxxxxxxxxxxxx/C=AU/ST=xxxxxxxx/L=xxxx/O=xxxxxx/CN=*.mydomain.com/[email protected] verify error:num=20:unable to get local issuer certificate verify return:1 depth=0 /description=xxxxxxxxxxx/C=AU/ST=xxxxxx/L=xxxx/O=xxxx/CN=*.mydomain.com/[email protected] verify error:num=27:certificate not trusted verify return:1 depth=0 /description=xxxxxxxx/C=AU/ST=xxxxxxxxxx/L=xxxx/O=xxxxx/CN=*.mydomain.com/[email protected] verify error:num=21:unable to verify the first certificate verify return:1 --- Certificate chain 0 s:/description=xxxxxxxxxxxx/C=AU/ST=xxxxxxxxxx/L=xxxxxxxx/O=xxxxxxx/CN=*.mydomain.com/[email protected] i:/C=IL/O=StartCom Ltd./OU=Secure Digital Certificate Signing/CN=StartCom Class 2 Primary Intermediate Server CA --- Server certificate -----BEGIN CERTIFICATE----- xxxxxxxxxxxxxxxxxxxx xxxxxxxxxxxxxxxxxxxx . . . xxxxxxxxxxxxxxxxxxxx xxxxxxxxxxxxxxxxxx== -----END CERTIFICATE----- subject=/description=xxxxxxxxxx/C=AU/ST=xxxxxxxxx/L=xxxxxxx/O=xxxxxx/CN=*.mydomain.com/[email protected] issuer=/C=IL/O=StartCom Ltd./OU=Secure Digital Certificate Signing/CN=StartCom Class 2 Primary Intermediate Server CA --- No client certificate CA names sent --- SSL handshake has read 2831 bytes and written 342 bytes --- New, TLSv1/SSLv3, Cipher is DHE-RSA-AES256-SHA Server public key is 2048 bit Compression: NONE Expansion: NONE SSL-Session: Protocol : TLSv1 Cipher : DHE-RSA-AES256-SHA Session-ID: xxxxxxxxxxxxxxxxxxxx Session-ID-ctx: Master-Key: xxxxxxxxxxxxxxxxxx Key-Arg : None Start Time: 1351661960 Timeout : 300 (sec) Verify return code: 21 (unable to verify the first certificate) --- . OK Capability completed. at least, i'm assuming this is a failure???

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  • How to: SSH private key authentication on OS X

    - by dan
    Hi, I need to ssh into a linux box. The server admin gave me a public and private ssh key. When I'm trying to login with the private key the login times out ("Operation timed out"). I'm using this command to login: ssh -v -i /path/to/private_key host What would be the right way to login? Do I need the public key for authentication? Thanks for any help.

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  • Ubuntu 9.10 as VMWare guest OS, X won't start

    - by vava
    I have Ubuntu 9.10 installed on it's own partition. Once in a while I would like to start it as a guest OS under Windows XP. While it starts and working fine, I can't login with gdm, after I enter login and password, X crashes and I'm at login prompt again. I can login with console just fine. Is there anything I can do prevent X from crashing?

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  • Custom Glassfish Security Realm does not work (unable to find LoginModule)

    - by ifischer
    I'm trying to get a Custom Security Realm in Glassfish working (i tried 3.0.1 final and 3.1 B33). I read nearly all tutorials about this, but it doesn not work on my System. I'm getting the error Login failed: javax.security.auth.login.LoginException: unable to find LoginModule class: de.company.security.utility.CustomLoginModule when trying to login. Here is what i did: I created a little Maven project, which contains the needed Realm class, CustomRealm, and the corresponding LoginModule, CustomLoginModule. My pom.xml: <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>com.mycompany</groupId> <artifactId>CustomJDBCRealm</artifactId> <version>1.0-SNAPSHOT</version> <packaging>jar</packaging> <name>Custom JDBCRealm</name> <url>http://maven.apache.org</url> <properties> <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding> </properties> <dependencies> <dependency> <groupId>org.glassfish.security</groupId> <artifactId>security</artifactId> <version>3.1-b33</version> </dependency> </dependencies> <build> <plugins> <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-compiler-plugin</artifactId> <configuration> <source>1.6</source> <target>1.6</target> <optimise>true</optimise> <debug>true</debug> <encoding>UTF-8</encoding> </configuration> </plugin> </plugins> </build> </project> My Custom Realm class: package de.company.security.utility; import com.sun.appserv.security.AppservRealm; import com.sun.enterprise.security.auth.realm.BadRealmException; import com.sun.enterprise.security.auth.realm.InvalidOperationException; import com.sun.enterprise.security.auth.realm.NoSuchRealmException; import com.sun.enterprise.security.auth.realm.NoSuchUserException; import java.util.Enumeration; import java.util.Properties; import java.util.Vector; /** * * @author ifischer */ public class CustomRealm extends AppservRealm { Vector<String> groups = new Vector<String>(); private String jaasCtxName; private String startWith; @Override public void init(Properties properties) throws BadRealmException, NoSuchRealmException { jaasCtxName = properties.getProperty("jaas-context", "customRealm"); startWith = properties.getProperty("startWith", "z"); groups.add("dummy"); } @Override public String getAuthType() { return "Custom Realm"; } public String[] authenticate(String username, char[] password) { // if (isValidLogin(username, password)) return (String[]) groups.toArray(); } @Override public Enumeration getGroupNames(String username) throws InvalidOperationException, NoSuchUserException { return groups.elements(); } @Override public String getJAASContext() { return jaasCtxName; } public String getStartWith() { return startWith; } } My LoginModule class: /* * Copyright (c) 2010 ProfitBricks GmbH. All Rights Reserved. */ package de.company.security.utility; import com.sun.appserv.security.AppservPasswordLoginModule; import com.sun.enterprise.security.auth.login.common.LoginException; import java.util.Set; import org.glassfish.security.common.PrincipalImpl; /** * * @author ifischer */ public class CustomLoginModule extends AppservPasswordLoginModule { @Override protected void authenticateUser() throws LoginException { _logger.info("CustomRealm : authenticateUser for " + _username); final CustomRealm realm = (CustomRealm)_currentRealm; if ( (_username == null) || (_username.length() == 0) || !_username.startsWith(realm.getStartWith())) throw new LoginException("Invalid credentials"); String[] grpList = realm.authenticate(_username, getPasswordChar()); if (grpList == null) { throw new LoginException("User not in groups"); } _logger.info("CustomRealm : authenticateUser for " + _username); Set principals = _subject.getPrincipals(); principals.add(new PrincipalImpl(_username)); this.commitUserAuthentication(grpList); } } I compiled this Maven project and copyied the resulting JAR-file to the Glassfish/lib directory. Then i added the Security Realm "customRealm" to my Glassfish with asadmin: asadmin create-auth-realm --classname de.company.security.utility.CustomRealm --property jaas-context=customRealm:startWith=a customRealm I even referenced the LoginModule class for the JAAS context of my Custom Realm, therefore i inserted this into the login.conf of my domain: customRealm { de.company.security.utility.CustomLoginModule required; }; Although this LoginModule SHOULD BE on the Glassfish classpath, as it's classfiled is packaged in the JAR that i put into the Glassfish/lib-dir, it cannot be found when i try to login. For login, i build a really simple JSF-project, which calls the HttpServletRequest-login-method of Servlet 3.0. When trying to login i'm getting the following Exception: 2010-12-24T14:41:31.613+0100|WARNING|glassfish3.0.1| javax.enterprise.system.container.web.com.sun.web.security|_ThreadID=25; _ThreadName=Thread-1;|Web login failed: Login failed: javax.security.auth.login.LoginException: unable to find LoginModule class: de.company.security.utility.CustomLoginModule Anybody got an idea what i can do that Glassfish loads the LoginModule-class?

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  • How to use Windows login for single-sign-on and for Active Directory entries for Desktop Java applic

    - by Touko
    I'd like to have my desktop Java application to have single sign on related to Active Directory users. In two steps, I'd like to : Be sure that the particular user has logged in to Windows with some user entry. Check out some setup information for that user from the Active Directory With http://stackoverflow.com/questions/31394/java-programatic-way-to-determine-current-windows-user I can get the name of the current Windows user but can I rely to that? I think the System.getProperty("user.name") won't be secure enough? ("user.name" seems to be got from environment variables, so I can't rely on that, I think?) Question http://stackoverflow.com/questions/390150/authenticating-against-active-directory-with-java-on-linux provides me the authentication for given name+pass but I'd like to authenticate based on the Windows logon? For the Active Directory access, the LDAP would probably be the choise? I'm not totally sure if I'm asking the right questions but hopefully somebody has some ideas to forward me on.

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  • Is it possible to store credentials for auotmatic Team Foundation Server login?

    - by marco.ragogna
    Is it possible to store the credentials that I use to connect to my Team Foundation Server directly in Visual Studio 2010? I would like to avoid to insert them at every VS launch. The problem is that the machine that host TFS is not in the domain and I am conneting using the credentials of a user created on that machine. Suppose that the machine name is TOOLS and the user is Marco, I need to insert every time User name: TOOLS\Marco Password: * Can you suggest a possible fix, if exists?

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  • SecurityException when accessing (ejb2-) session bean via local interface in JBoss 5

    - by sme
    I have the following problem with an EJB 2 SessionBean when deploying in JBoss 5: The SessionBean (called LVSKeepAliveDispatcher) requires a specific user role (called "LVSUser"), specified by <method-permission > <description></description> <role-name>LVSUser</role-name> <method > <description></description> <ejb-name>LVSKeepAliveDispatcher</ejb-name> <method-name>*</method-name> </method> </method-permission> in ejb-jar.xml. I now want to access this SessionBean from a Service (i.e. a class implementing the org.jboss.varia.scheduler.Schedulable interface that is then registered as a service) running inside the same JBoss instance. This is my jboss-service.xml: <server> <mbean code="org.jboss.varia.scheduler.Scheduler" name="lvs:service=TranslationService"> <attribute name="StartAtStartup">true</attribute> <attribute name="SchedulableClass">de.repower.lvs.server.service.translation.TranslationService</attribute> <attribute name="SchedulableArguments"></attribute> <attribute name="SchedulableArgumentTypes"></attribute> <attribute name="InitialStartDate">NOW</attribute> <attribute name="SchedulePeriod">60000</attribute> <attribute name="InitialRepetitions">1</attribute> <attribute name="TimerName">jboss:service=Timer,name=TranslationServiceTimer</attribute> <depends><mbean code="javax.management.timer.Timer" name="jboss:service=Timer,name=TranslationServiceTimer"/></depends> <depends>jboss.j2ee:service=EJB,jndiName=de/repower/lvs/i18n/sessionbeans/LVSTranslation</depends> </mbean> As the service is deployed in the same vm as the session bean I want to call the session bean via the local interface, but I get a SecurityException when I try to create an instance. When instead I do a lookup of the RemoteInterface it works. This is the code inside the perform method of my service class: public void perform(Date now, long remainingRepetitions) { try { final UsernamePasswordHandler handler = new UsernamePasswordHandler(USERNAME, PASSWORD); final LoginContext lc = new LoginContext("client-login", handler); lc.login(); // Trying to instantiate an LVSKeepAliveDispatcher via remote interface // This part works LVSKeepAliveDispatcher localvHome = LVSKeepAliveDispatcherUtil.getHome().create(); LOGGER.info("Successfully instantiated an LVSKeepAliveDispatcher " + localvHome.toString()); // Trying to instantiate an LVSKeepAliveDispatcherLocal via local interface LVSKeepAliveDispatcherLocal localvLocalHome = LVSKeepAliveDispatcherUtil.getLocalHome().create(); // this code is unforunately never reached LOGGER.info("Successfully instantiated an LVSKeepAliveDispatcherLocal " + localvLocalHome.toString()); lc.logout(); } catch (final Exception ex) { LOGGER.error("Error: ", ex); } } Exception: 2009-02-17 10:38:02,266 INFO [lvsi18n] (Timer-2) Successfully instantiated an LVSKeepAliveDispatcher de/repower/lvs/server/service/alive/sessionbeans/LVSKeepAliveDispatcher:Stateless 2009-02-17 10:38:02,297 ERROR [org.jboss.ejb.plugins.SecurityInterceptor] (Timer-2) Error in Security Interceptor java.lang.SecurityException: Authentication exception, principal=internalSystemUser at org.jboss.ejb.plugins.SecurityInterceptor.checkSecurityContext(SecurityInterceptor.java:321) at org.jboss.ejb.plugins.SecurityInterceptor.process(SecurityInterceptor.java:243) at org.jboss.ejb.plugins.SecurityInterceptor.invokeHome(SecurityInterceptor.java:205) at org.jboss.ejb.plugins.security.PreSecurityInterceptor.process(PreSecurityInterceptor.java:136) at org.jboss.ejb.plugins.security.PreSecurityInterceptor.invokeHome(PreSecurityInterceptor.java:88) at org.jboss.ejb.plugins.LogInterceptor.invokeHome(LogInterceptor.java:132) at org.jboss.ejb.plugins.ProxyFactoryFinderInterceptor.invokeHome(ProxyFactoryFinderInterceptor.java:107) at org.jboss.ejb.SessionContainer.internalInvokeHome(SessionContainer.java:639) at org.jboss.ejb.Container.invoke(Container.java:1046) at org.jboss.ejb.plugins.local.BaseLocalProxyFactory.invokeHome(BaseLocalProxyFactory.java:362) at org.jboss.ejb.plugins.local.LocalHomeProxy.invoke(LocalHomeProxy.java:133) at $Proxy193.create(Unknown Source) at de.repower.lvs.server.service.translation.TranslationService.perform(TranslationService.java:68) at org.jboss.varia.scheduler.Scheduler$PojoScheduler.invoke(Scheduler.java:1267) at org.jboss.varia.scheduler.Scheduler$BaseListener.handleNotification(Scheduler.java:1235) at sun.reflect.GeneratedMethodAccessor281.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.jboss.mx.notification.NotificationListenerProxy.invoke(NotificationListenerProxy.java:153) at $Proxy87.handleNotification(Unknown Source) at javax.management.NotificationBroadcasterSupport.handleNotification(NotificationBroadcasterSupport.java:257) at javax.management.NotificationBroadcasterSupport$SendNotifJob.run(NotificationBroadcasterSupport.java:322) at javax.management.NotificationBroadcasterSupport$1.execute(NotificationBroadcasterSupport.java:307) at javax.management.NotificationBroadcasterSupport.sendNotification(NotificationBroadcasterSupport.java:229) at javax.management.timer.Timer.sendNotification(Timer.java:1234) at javax.management.timer.Timer.notifyAlarmClock(Timer.java:1203) at javax.management.timer.TimerAlarmClock.run(Timer.java:1286) at java.util.TimerThread.mainLoop(Timer.java:512) at java.util.TimerThread.run(Timer.java:462) To further diagnose the error I debugged through the SecurityInterceptor and found that in the first case (successful creating an instance via the remote interface) the security context "lvs-security" (which I defined in login-config.xml) is being used whereas in the second case (failure when creating an instance via the local interface) the generic security context "CLIENT-LOGIN" is being used. This is the definition of the securit context "lvs-security" in login-config.xml: <application-policy name = "lvs-security"> <authentication> <login-module code = "org.jboss.security.ClientLoginModule" flag = "required"> </login-module> <login-module code = "de.repower.lvs.security.UsersRolesLoginModule" flag = "sufficient"> </login-module> <login-module code = "de.repower.lvs.security.login.LVSLoginModule" flag = "required"> <module-option name = "lvs-jboss-host">localhost</module-option> <module-option name = "lvs-jboss-jndi-port">1099</module-option> </login-module> </authentication> </application-policy> I'm now kind of stuck and hope someone can give me a hint about where to further look for the cause of the problem. This worked fine in JBoss 3.2.7. Edit: My current workaround for this problem: create a new container configuration in jboss.xml and remove the security interceptor stuff from this configuration use this newly created container configuration for all my session beans that I only use locally (i.e. via local interface).

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  • ASP.NET MVC Users unable to login after password change, and being locked out.

    - by Russell Kay
    All, I have a website that is in use and has several users, using the MySqlMembershipProvider. We have had a few users that have been locked out (for some reason) and recently I unlocked them and reset the passwords, using the MembershipUser.UnlockUser and MembershipUser.ResetPassword methods. Now they are definitely marked in the database as Unlocked and the password has been reset, but they still cannot log in. Does anyone have any ideas why this might happen?

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  • Integrating Simple Machines Forum in my custom membership site - login not working?

    - by Ali
    Hi guys I'm trying to integrate simple machines forum into my custom made membership website. I'm using the SMF API which is available here at http://download.simplemachines.org/?tools. The thing is that its working on my localhost testing server - however on my online server where the system is hosted - its not working. I have set it up so that when the user log into my own custom CMS membership site, he/she is logged in automatically to his/her corresponding account on the forum. However it works on my localhost but online its not working at all.. I log into my site and then browse to the forum to find out I havent been logged in there :( - I think its not creating the cookies or registering the session.. where should I look here. Please do help.

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  • undefined symbols when compiling libjingle for Mac OS X

    - by wwh37
    Compiling libjinge-0.4.0 on my Leopard returned the following errors: /bin/sh ../../../libtool --silent --tag=CXX --mode=link g++ -g -o login login-login_main.o login-xmppsocket.o login-xmppthread.o login-xmpppump.o login-xmppauth.o ../../../talk/xmpp/libcricketxmpp.la ../../../talk/xmllite/libcricketxmllite.la ../../../talk/base/libcricketbase.la -lexpat -lpthread -lssl -lcrypto Undefined symbols: "_BIO_clear_flags", referenced from: socket_read(bio_st*, char*, int)in libcricketbase.a(openssladapter.o) socket_write(bio_st*, char const*, int)in libcricketbase.a(openssladapter.o) "_BIO_set_flags", referenced from: socket_read(bio_st*, char*, int)in libcricketbase.a(openssladapter.o) socket_write(bio_st*, char const*, int)in libcricketbase.a(openssladapter.o) Any ideas? I couldn't find an answer... Thanks!

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  • Select from multiple tables, remove duplicates

    - by staze
    I have two tables in a SQLite DB, and both have the following fields: idnumber, firstname, middlename, lastname, email, login One table has all of these populated, the other doesn't have the idnumber, or middle name populated. I'd LIKE to be able to do something like: select idnumber, firstname, middlename, lastname, email, login from users1,users2 group by login; But I get an "ambiguous" error. Doing something like: select idnumber, firstname, middlename, lastname, email, login from users1 union select idnumber, firstname, middlename, lastname, email, login from users2; LOOKS like it works, but I see duplicates. my understanding is that union shouldn't allow duplicates, but maybe they're not real duplicates since the second user table doesn't have all the fields populated (e.g. "20, bob, alan, smith, [email protected], bob" is not the same as "NULL, bob, NULL, smith, [email protected], bob"). Any ideas? What am I missing? All I want to do is dedupe based on "login". Thanks!

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  • Log off from Remote Desktop Session does not closing Session, showing the login screen again on Wind

    - by Santhosha
    Hi As per requirement we have written one custom GINA. I have observed one interesting behavior in Windows XP 32 Bit(SP2). Customized GINA internally calls windows default Windows GINA(msgina.dll) and shows one extra window as per our requirement. I used to do remote desktop to XP machine from my machine. After replacing Windows GINA with customized GINA I tried to log off from the XP Machine(I am Using Remote Desktop Connection to log in), Log off completes successfully(After showing saving your settings, Closing network connections etc) and I will get log in screen which we get during log on, this is not expected comapred to other flavors of Windows OD. Where as in other operating systems such as Windows XP 64 Bit/ Windows 2003 32/64 Bit even after replacing the Windows Gina with custom GINA remote desktop session closes after log off from the machine. I have tried installing Novell GINA on Windows XP 32 Bit but i have not find any issue with that. I have Tried upgrading XP SP2 to SP3, still i am facing the same issue. Whether anyone faced Such issues when worked with Windows GINA? Thanks in advance Santhosha K S

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  • Is there a Rails authentication library which separates users from login methods?

    - by Gareth
    In my mental model of authentication, a user should be distinct from the way they log in. So for example, a User could have an associated EmailLogin (with an email/password), or they could have many (or none). Similarly they could have 0..* associated OpenIDLogin credentials. Are there any existing authentication libraries for Rails which use this method? Alternatively, is this a really terrible idea?

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  • Why Shouldn't I Programmatically Submit Username/Password to Facebook/Twitter/Amazon/etc?

    - by viatropos
    I wish there was a central, fully customizable, open source, universal login system that allowed you to login and manage all of your online accounts (maybe there is?)... I just found RPXNow today after starting to build a Sinatra app to login to Google, Facebook, Twitter, Amazon, OpenID, and EventBrite, and it looks like it might save some time. But I keep wondering, not being an authentication guru, why couldn't I just have a sleek login page saying "Enter username and password, and check your login service", and then in the background either scrape the login page from say EventBrite and programmatically submit the form with Mechanize, or use an API if there was one? It would be so much cleaner and such a better user experience if they didn't have to go through popups and redirects and they could use any previously existing accounts. My question is: What are the reasons why I shouldn't do something like that? I don't know much about the serious details of cookies/sessions/security, so if you could be descriptive or point me to some helpful links that would be awesome. Thanks!

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  • One click login to my google apps solution how can I do it?

    - by Ali
    Hi guys I'm developing a google apps solution and I'm building on the tutorial application give by google at http://code.google.com/googleapps/marketplace/tutorial_php.html - the thing is that the example given sets up the application such that the user has to enter in manually the email address or username and then it takes the user through an authentication process whereby it asks the user if they wish to allow the application to be given access to the services mentioned in the manifest.xml file. Isn't there a better way to do this I mean like I want that when the user upon logging into his google apps account just has to click in the application link installed and straight on should be able to enter the application. Can't the process of authentication and all be transparent in the backdrop. I need help on this asap. Thanks a bunch!

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  • Using GET Method to Maintain Variables After Logging In

    - by John
    Hello, I am using a login system. When I navigate to comments/index.php without logging in, some variables get passed along using the GET method just fine. Then, if I log in while I am on this page, these variables disappear. The variables that disappear are $submission, $submissionid, and $url. I thought I could use the GET method to keep them live after logging in by appending ?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.' to the URL of the login form action as seen below. But the variables still disappeared after I made this addition. The relevant code I am trying to use is below. Any idea what I can do to make it do what I want? Thanks in advance, John In comments/index.php: require_once "header.php"; include "login.php"; include "comments.php"; In login.php: if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } In comments.php: $url = mysql_real_escape_string($_GET['url']); echo '<div class="subcommenttitle"><a href="http://www.'.$url.'">'.$submission.'</a></div>'; $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); The login function: function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.'"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/sandbox/register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/sandbox/lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; }

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  • How to login as another user and then log out in bash script?

    - by Neuquino
    Hi, I need to write a bash script to do something as another user and then return to the initial user... Suppose I run the following as root: #!/bin/bash USER=zaraza su - "${USER}" #do some stuff as zaraza ________ #here I should logout zaraza #continue doing things as root In the console I should write "exit", but in bash is a keyword and it exits the script... Thanks in advance,

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