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  • How do I convert RGB into HSV in Cocoa Touch?

    - by Evelyn
    I want to set the background color of a label using HSV instead of RGB. How do I implement this into code? Code: //.m file #import "IBAppDelegate.h" @implementation IBAppDelegate @synthesize label; { self.label.backgroundColor = [UIColor colorWithRed:1.0f green:0.8f blue:0.0f alpha:1.0f]; }

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  • Java anonymous class efficiency implications

    - by Po
    Is there any difference in efficiency (e.g. execution time, code size, etc.) between these two ways of doing things? Below are contrived examples that create objects and do nothing, but my actual scenarios may be creating new Threads, Listeners, etc. Assume the following pieces of code happen in a loop so that it might make a difference. Using anonymous objects: void doSomething() { for (/* Assume some loop */) { final Object obj1, obj2; // some free variables IWorker anonymousWorker = new IWorker() { doWork() { // do things that refer to obj1 and obj2 } }; } } Defining a class first: void doSomething() { for (/* Assume some loop */) { Object obj1, obj2; IWorker worker = new Worker(obj1, obj2); } } static class Worker implements IWorker { private Object obj1, obj2; public CustomObject(Object obj1, Object obj2) {/* blah blah */} @Override public void doWork() {} }; Thank you :)

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  • CMYK + CMYK = ? CMYK / 2 = ?

    - by Pete
    Suppose there are two colors defined in CMYK: color1 = 30, 40, 50, 60 color2 = 50, 60, 70, 80 If they were to be printed what values would the resulting color have? color_new = min(cyan1 + cyan2, 100), min(magenta1 + magenta2, 100), min(yellow1 + yellow2, 100), min(black1 + black2, 100)? Suppose there is a color defined in CMYK: color = 40, 30, 30, 100 It is possible to print a color at partial intensity, i.e. as a tint. What values would have a 50% tint of that color? color_new = cyan / 2, magenta / 2, yellow / 2, black / 2? I'm asking this to better understand the "tintTransform" function in PDF Reference 1.7, 4.5.5 Special Color Spaces, DeviceN Color Spaces Update: To better clarify: I'm not entirely concerned with human perception or how the CMYK dyies react to the paper. If someone specifies 90% tint which, when printed, looks like full intensity colorant, that's ok. In other words, if I asking how to compute 50% of cmyk(40, 30, 30, 100) I'm asking how to compute the new values, regardless of whether the result looks half-dark or not. Update 2: I'm confused now. I checked this in InDesign and Acrobat. For example Pantone 3005 has CMYK 100, 34, 0, 2, and its 25% tint has CMYK 25, 8.5, 0, 0.5. Does it mean I can "monkey around in a linear way"?

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  • How can I use the HSL colorspace in Java?

    - by Eric
    I've had a look at the ColorSpace class, and found the constant TYPE_HLS (which presumably is just HSL in a different order). Can I use this constant to create a Color from hue, saturation, and luminosity? If not, are there any Java classes for this, or do I need to write my own?

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  • Batch file to map a drive when the folder name contains spaces

    - by Santiago
    I am trying to map a drive using a batch file. I have tried: net use m: \Server01\myfolder /USER:mynetwork\Administrator "Mypassword" /persistent:yes It works fine. The problem comes when I try to map a folder with spaces on its name: net use m: \Server01\my folder /USER:mynetwork\Administrator "Mypassword" /persistent:yes I have tried using quotes, using myfold~1 but nothing works. An easy way would be renaming the folder but I have it mapped in more than 300 workstations so is not a very good idea. PLEASE HELP!!!

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  • more efficient way to pickle a string

    - by gatoatigrado
    The pickle module seems to use string escape characters when pickling; this becomes inefficient e.g. on numpy arrays. Consider the following z = numpy.zeros(1000, numpy.uint8) len(z.dumps()) len(cPickle.dumps(z.dumps())) The lengths are 1133 characters and 4249 characters respectively. z.dumps() reveals something like "\x00\x00" (actual zeros in string), but pickle seems to be using the string's repr() function, yielding "'\x00\x00'" (zeros being ascii zeros). i.e. ("0" in z.dumps() == False) and ("0" in cPickle.dumps(z.dumps()) == True)

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  • Function for creating color wheels

    - by lbrandy
    This is something I've pseudo-solved many times and never quite found a solution that's stuck with me. The problem is to come up with a way to generate N colors that are as distinguishable as possible where N is a parameter.

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  • write cache and write sequence order

    - by excanoe
    ok, here i have some weird question: let say we have some binary file (.log), and sequence of write operations, for example log1, log2, log3 and each has some block size n (raw data). question: can I be sure that log1,log2 and log3 sequences can be written in the correct order in ONE file, even if i have few cache levels (disk hardware and os level)? update very interested in what will be with records order (not with records) if we have software or hardware failure (reboot or another reason). update there can be some percent of write failures, but main question is: will write order stay correct?

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  • Unicode generated by toEscapedUnicode method is without spaces

    - by vishvesha
    For this word ????????????? the Unicode is== \u0938\u0941\u0916\u091A\u0948\u0928\u093E\u0928\u0940 \u0930\u0940\u091D\u0941\u092E\u0932 \u091C\u093F\u0935\u0924\u0930\u093E\u092E and look it has spaces before \u0930 and \u091C But when I am trying in my code String tempString=Strings.toEscapedUnicode(strString); This method to convert to Unicode gives a result without spaces: \u0938\u0941\u0916\u091A\u0948\u0928\u093E\u0928\u0940\u0930\u0940\u091D\u0941\u092E\u0932\u091C\u093F\u0935\u0924\u0930\u093E\u092E and that's why they are not matching. My 'toEscapeUnicode' method generates Unicode without spaces. I want the spaces, so how to do it?

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  • remove the spaces...

    - by tekknolagi
    !/usr/bin/python import random lower_a = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'] upper_a = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'] num = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'] all = [] all = " ".join("".join(lower_a) + "".join(upper_a) + "".join(num)) all = all.split() x = 0 while x < 10: for i in range(7): a = random.choice(all) print a, print x += 1 what i want to do is remove the spaces from the output what it gives now is Z 3 a A I K R G B i N 9 c E v g E r A N 8 e B 6 d v H O c a V 8 c x y b g 2 W a T T f 8 H T r 6 E p D K l 5 p u x q 8 P Z 9 T n I W X n B Q

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  • New Dell PE R710 - Storage Question

    - by rihatum
    Hi All, Dell PE R710, received from Dell in the following state : Windows Disk 0 1800GB ( Volume C & D ) Windows Disk 1 526 GB (Volume E ) Perc6i Integrated Raid Controller 6 x 500GB Nearline SAS 7200RPM HDDs Raid 5 Configuration with two Virtual Disks I have installed Dell open Manage and it shows the following : Virtual Disk 0 - State : Background Initialization ( 7% ) Virtual Disk 1 - State : Background Initialization ( 25% ) Now when I click on Virtual Disk 0 it shows me all 6 Disks and the same happens when I click on Virtual Disk 1 it displays all 6 disks. But when I click on Storage Perc6i Connector 0 I get 4 Physical disks with the following numbers : Physical Disk 0:0:0 Physical Disk 0:0:1 Physical Disk 0:0:2 Physical Disk 0:0:3 When I click on Storage Perc6i Connector 1 I get 2 Physical Disks Listed in the following way : Physical Disk 1:0:4 Physical Disk 1:0:5 I am a little confused in this description, does this 1:0:4 interprets to Controller1, Disk4. Does this integrated raid card have two controllers coming out of it ? Also, When I first switched on the machine, the boot partition was showing 1GB Available out of 40GB, now its showing 38GB available out of 40GB. Is this because the Virtual Disks are still Initializing ? Any recommendations or suggestions ? Also, this server have 6 x 500GB NearLine SAS Hard drives, what would be a good raid config ? We are planning to use it for Hyper-V with quite a few (7 or 8) virtual servers, your suggestions would be helpful. Also, while the virtual disks are in a initialization state, can I destroy and re-create the raid configuration ? I would have to do it at the BIOS CTRL-M ? Thanks and Regards

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  • Reinserted a RAID disk. Defined as foreign. Is import or clear the correct choice?

    - by Petrus
    I have re-inserted a RAID disk, on a DELL server with Windows Server 2008. The drive-status indicator was changing between a green and amber light, and the monitor gave the following message: There are offline or missing virtual drives with preserved cache. Please check the cables and ensure that all drives are present. Press any key to enter the configuration utility. I pressed a key and the PERC 6/I Integrated BIOS Configuration Utility showed that the RAID Status for that disk was Offline. After reinsertion of the disk the monitor is giving the following message: Foreign configuration(s) found on adapter. Press any key to continue or ‘C’ load the configuration utility, or press ‘F’ to import foreign configuration(s) and continue. After checking around on the net I am uncertain if I should choose import or clear. I cannot find out if an import means importing information from the array/system to the now foreign disk or the other way, i.e. importing information from the foreign disk to the array/system that was actually working fine. Also; if clear is a necessary thing to do ahead of a rebuild of that disk, or if clear means to clear the system to somehow make it ready to import the information from the foreign disk to the array/system, which is not what I want. I imagine that making the wrong choice here might be fatal. Please help clearing this out by telling what to choose and why.

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  • Cluster Node Recovery Using Second Node in Solaris Cluster

    - by Onur Bingul
    Assumptions:Node 0a is the cluster node that has crashed and could not boot anymore.Node 0b is the node in cluster and in production with services active.Both nodes have their boot disk mirrored via SDS/SVM.We have many options to clone the boot disk from node 0b:- make a copy via network using the ufsdump command and pipe to ufsrestore - make a copy inserting the disk locally on node 0b and creating the third mirror with SDS- make a copy inserting the disk locally on node 0b using dd commandIn this procedure we are going to use dd command (from my experience this is the best option).Bare in mind that in the examples provided we work on Sun Fire V240 systems which have SCSI internal disks. In the case of Fibre Channel (FC) internal disks you must pay attention to the unique identifier, or World Wide Name (WWN), associated with each FC disk (in this case take a look at infodoc #40133 in order to recreate the device tree correctly).Procedure:On node 0b the boot disk is c1t0d0 (c1t1d0 mirror) and this is the VTOC:* Partition  Tag  Flags    Sector     Count    Sector  Mount Directory      0      2    00          0   2106432   2106431      1      3    01    2106432  74630784  76737215      2      5    00          0 143349312 143349311      4      7    00   76737216  50340672 127077887      5      4    00  127077888  14683968 141761855      6      0    00  141761856   1058304 142820159      7      0    00  142820160    529152 143349311We will insert the new disk on node 0b and it will be seen as c1t2d0.1) On node 0b we make a copy via dd from disk c1t0d0s2 to disk c1t2d0s2# dd if=/dev/rdsk/c1t0d0s2 of=/dev/rdsk/c1t2d0s2 bs=8192kA copy of a 72GB disk will take approximately about 45 minutes.Note: as an alternative to make identical copy of root over network follow Document ID: 47498Title: Sun[TM] Cluster 3.0: How to Rebuild a node with Veritas Volume Manager2) Perform an fsck on disk c1t2d0 data slices:   1.  fsck -o f /dev/rdsk/c1t2d0s0 (root)   2.  fsck -o f /dev/rdsk/c1t2d0s4 (/var)   3.  fsck -o f /dev/rdsk/c1t2d0s5 (/usr)   4.  fsck -o f /dev/rdsk/c1t2d0s6 (/globaldevices)3) Mount the root file system in order to edit following files for changing the node name:# mount /dev/dsk/c1t2d0s0 /mntChange the hostname from 0b to 0a:# cd /mnt/etc# vi hosts # vi hostname.bge0 # vi hostname.bge2 # vi nodename 4) Change the /mnt/etc/vfstab from the actual:/dev/md/dsk/d201        -       -       swap    -       no      -/dev/md/dsk/d200        /dev/md/rdsk/d200       /       ufs     1       no      -/dev/md/dsk/d205        /dev/md/rdsk/d205       /usr    ufs     1       no      logging/dev/md/dsk/d204        /dev/md/rdsk/d204       /var    ufs     1       no      logging#/dev/md/dsk/d206       /dev/md/rdsk/d206       /globaldevices  ufs     2       yes     loggingswap    -       /tmp    tmpfs   -       yes     -/dev/md/dsk/d206        /dev/md/rdsk/d206       /global/.devices/node@2 ufs     2       noglobalto this (unencapsulate disk from SDS/SVM):/dev/dsk/c1t0d0s1        -       -       swap    -       no      -/dev/dsk/c1t0d0s0       /dev/rdsk/c1t0d0s0       /       ufs     1       no      -/dev/dsk/c1t0d0s5       /dev/rdsk/c1t0d0s5       /usr    ufs     1       no      logging/dev/dsk/c1t0d0s4       /dev/rdsk/c1t0d0s4       /var    ufs     1       no      logging#/dev/md/dsk/d206       /dev/md/rdsk/d206       /globaldevices  ufs     2       yes     loggingswap    -       /tmp    tmpfs   -       yes     -/dev/dsk/c1t0d0s6       /dev/rdsk/c1t0d0s6       /global/.devices/node@1 ufs     2       no globalIt is important that global device partition (slice 6) in the new vfstab will point to the physical partition of the disk (in our case slice 6).Be careful with the name you use for the new disk. In this case we define it as c1t0d0 because we will insert it as target 0 in node 0a.But this could be different based on the configuration you are working on.5) Remove following entry from /mnt/etc/system (part of unencapsulation procedure):rootdev:/pseudo/md@0:0,200,blk6) Correct the link shared -> ../../global/.devices/node@2/dev/md/shared in order to point to the nodeid of node 0a (in our case nodeid 1):# cd /mnt/dev/mdhow it is now.... node 0b has nodeid 2lrwxrwxrwx   1 root     root          42 Mar 10  2005 shared ->../../global/.devices/node@2/dev/md/shared# rm shared# ln -s ../../global/.devices/node@1/dev/md/shared sharedhow is going to be... with nodeid 1 for node 0alrwxrwxrwx   1 root     root          42 Mar 10  2005 shared ->../../global/.devices/node@1/dev/md/shared7) Change nodeid (in our case from 2 to 1):# cd /mnt/etc/cluster# vi nodeid8) Change the file /mnt/etc/path_to_inst in order to reflect the correct nodeid for node 0a:# cd /mnt/etc# vi path_to_instChange entries from node@2 to node@1 with the vi command ":%s/node@2/node@1/g"9) Write the bootblock to the disk... just in case:# /usr/sbin/installboot /usr/platform/sun4u/lib/fs/ufs/bootblk /dev/rdsk/c1t2d0s0Now the disk is ready to be inserted in node 0a in order to bootup the node.10) Bootup node 0a with command "boot -sx"... this is becasue we need to make some changes in ccr files in order to recreate did environment.11) Modify cluster ccr:# cd /etc/cluster/ccr# rm did_instances# rm did_instances.bak# vi directory - remove the did_instances line.# /usr/cluster/lib/sc/ccradm -i /etc/cluster/ccr/directory # grep ccr_gennum /etc/cluster/ccr/directory ccr_gennum -1 # /usr/cluster/lib/sc/ccradm -i /etc/cluster/ccr/infrastructure # grep ccr_gennum /etc/cluster/ccr/infrastructure ccr_gennum -112) Bring the node 0a down again to the ok prompt and then issue the command "boot -r"Now the node will join the cluster and from scstat and metaset command you can verify functionality. Next step is to encapsulate the boot disk in SDS/SVM and create the mirrors.In our case node 0b has metadevice name starting from d200. For this reason on node 0a we need to create metadevice starting from d100. This is just an example, you can have different names.The important thing to remember is that metadevice boot disks have different names on each node.13) Remove metadevice pointing to the boot and mirror disks (inherit from node 0b):# metaclear -r -f d200# metaclear -r -f d201# metaclear -r -f d204# metaclear -r -f d205# metaclear -r -f d206verify from metastat that no metadevices are set for boot and mirror disks.14) Encapsulate the boot disk:# metainit -f d110 1 1 c1t0d0s0# metainit d100 -m d110# metaroot d10015) Reboot node 0a.16) Create all the metadevice for slices remaining on boot disk# metainit -f d111 1 1 c1t0d0s1# metainit d101 -m d111# metainit -f d114 1 1 c1t0d0s4# metainit d104 -m d114# metainit -f d115 1 1 c1t0d0s5# metainit d105 -m d115# metainit -f d116 1 1 c1t0d0s6# metainit d106 -m d11617) Edit the vfstab in order to specifiy metadevices created:old:/dev/dsk/c1t0d0s1        -       -       swap    -       no      -/dev/md/dsk/d100        /dev/md/rdsk/d100       /       ufs     1       no      -/dev/dsk/c1t0d0s5       /dev/rdsk/c1t0d0s5       /usr    ufs     1       no      logging/dev/dsk/c1t0d0s4       /dev/rdsk/c1t0d0s4       /var    ufs     1       no      logging#/dev/md/dsk/d206       /dev/md/rdsk/d206       /globaldevices  ufs     2       yes     loggingswap    -       /tmp    tmpfs   -       yes     -/dev/dsk/c1t0d0s6       /dev/rdsk/c1t0d0s6       /global/.devices/node@1 ufs      2       no  globalnew:/dev/md/dsk/d101        -       -       swap    -       no      -/dev/md/dsk/d100        /dev/md/rdsk/d100       /       ufs     1       no      -/dev/md/dsk/d105        /dev/md/rdsk/d105       /usr    ufs     1       no      logging/dev/md/dsk/d104        /dev/md/rdsk/d104       /var    ufs     1       no      logging#/dev/md/dsk/106       /dev/md/rdsk/d106       /globaldevices  ufs     2       yes     loggingswap    -       /tmp    tmpfs   -       yes     -/dev/md/dsk/d106        /dev/md/rdsk/d106       /global/.devices/node@1 ufs     2       noglobal18) Reboot node 0a in order to check new SDS/SVM boot configuration.19) Label the mirror disk c1t1d0 with the VTOC of boot disk c1t0d0:# prtvtoc /dev/dsk/c1t0d0s2 > /var/tmp/VTOC_c1t0d0 # fmthard -s /var/tmp/VTOC_c1t0d0 /dev/rdsk/c1t1d0s220) Put DB replica on slice 7 of disk c1t1d0:# metadb -a -c 3 /dev/dsk/c1t1d0s721) Create metadevice for mirror disk c1t1d0 and attach the new mirror side:# metainit d120 1 1 c1t1d0s0# metattach d100 d120# metainit d121 1 1 c1t1d0s1# metattach d101 d121# metainit d124 1 1 c1t1d0s4# metattach d104 d124# metainit d125 1 1 c1t1d0s5# metattach d105 d125# metainit d126 1 1 c1t1d0s6# metattach d106 d126

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  • Finding a shared HDD attached to the network from my F-13 machine

    - by Ramy
    Sorry for the slew of n00bie questions, but here is one more. I recently partitioned my 1.5TB harddrive according to this question I then bought this to attach the harddrive to my network. The problem is, how do I navigate to the hard drive to move files over the network to the HDD. should this be moved to serverfault? update: the disk isn't even showing up when i call "fdisk -l" (as root). How can I mount it if I can't even find it? [root@Moonface ~]# /sbin/fdisk -l Disk /dev/sda: 160.0 GB, 160041885696 bytes 255 heads, 63 sectors/track, 19457 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00018598 Device Boot Start End Blocks Id System /dev/sda1 * 1 64 512000 83 Linux Partition 1 does not end on cylinder boundary. /dev/sda2 64 19458 155777024 8e Linux LVM Disk /dev/dm-0: 53.7 GB, 53687091200 bytes 255 heads, 63 sectors/track, 6527 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-0 doesn't contain a valid partition table Disk /dev/dm-1: 4764 MB, 4764729344 bytes 255 heads, 63 sectors/track, 579 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-1 doesn't contain a valid partition table Disk /dev/dm-2: 101.0 GB, 101032394752 bytes 255 heads, 63 sectors/track, 12283 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-2 doesn't contain a valid partition table

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  • How to create partition when growing raid5 with mdadm.

    - by hometoast
    I have 4 drives, 2x640GB, and 2x1TB drives. My array is made up of the four 640GB partitions and the beginning of each drive. I want to replace both 640GB with 1TB drives. I understand I need to 1) fail a disk 2) replace with new 3) partition 4) add disk to array My question is, when I create the new partition on the new 1TB drive, do I create a 1TB "Raid Auto Detect" partition? Or do I create another 640GB partition and grow it later? Or perhaps the same question could be worded: after I replace the drives how to I grow the 640GB raid partitions to fill the rest of the 1TB drive? fdisk info: Disk /dev/sdb: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Disk identifier: 0xe3d0900f Device Boot Start End Blocks Id System /dev/sdb1 1 77825 625129281 fd Linux raid autodetect /dev/sdb2 77826 121601 351630720 83 Linux Disk /dev/sdc: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Disk identifier: 0xc0b23adf Device Boot Start End Blocks Id System /dev/sdc1 1 77825 625129281 fd Linux raid autodetect /dev/sdc2 77826 121601 351630720 83 Linux Disk /dev/sdd: 640.1 GB, 640135028736 bytes 255 heads, 63 sectors/track, 77825 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Disk identifier: 0x582c8b94 Device Boot Start End Blocks Id System /dev/sdd1 1 77825 625129281 fd Linux raid autodetect Disk /dev/sde: 640.1 GB, 640135028736 bytes 255 heads, 63 sectors/track, 77825 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Disk identifier: 0xbc33313a Device Boot Start End Blocks Id System /dev/sde1 1 77825 625129281 fd Linux raid autodetect Disk /dev/md0: 1920.4 GB, 1920396951552 bytes 2 heads, 4 sectors/track, 468846912 cylinders Units = cylinders of 8 * 512 = 4096 bytes Disk identifier: 0x00000000

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  • recursive grep started at / hangs

    - by Martin
    I have used following grep search pattern on multiple platforms: grep -r -I -D skip 'string_to_match' / For example on FreeBSD 8.0, FreeBSD 6.4 and Debian 6.0(squeeze). Command does a recursive search starting from root directory, assumes that binary files do not have the 'string_to_match' and skips devices, sockets and named pipes. FreeBSD 8.0 and FreeBSD 6.4 use GNU grep version 2.5.1 and Debian 6.0 uses GNU grep version 2.6.3. On FreeBSD 6.4, last information printed to stderr was "grep: /dev/cuad0: Device busy". After this grep just idles as according to "top -m io -o total" the I/O usage of grep is nonexistent. Same behavior is true under FreeBSD 8.0, but last information sent to stderr is "grep: /tmp/.wine-0: Permission denied" on my installation. In case of Debian, last output to stderr is "grep: /proc/sysrq-trigger: Input/output error". If I check the I/O usage of grep process under Debian, it is following: root@Debian:~# iotop -bp 22439 Total DISK READ: 0.00 B/s | Total DISK WRITE: 0.00 B/s TID PRIO USER DISK READ DISK WRITE SWAPIN IO COMMAND 22439 be/4 root 0.00 B/s 0.00 B/s 0.00 % 0.00 % grep -r -I -D skip 10.10.10.99 / Total DISK READ: 0.00 B/s | Total DISK WRITE: 0.00 B/s TID PRIO USER DISK READ DISK WRITE SWAPIN IO COMMAND 22439 be/4 root 0.00 B/s 0.00 B/s 0.00 % 0.00 % grep -r -I -D skip 10.10.10.99 / Total DISK READ: 0.00 B/s | Total DISK WRITE: 0.00 B/s TID PRIO USER DISK READ DISK WRITE SWAPIN IO COMMAND 22439 be/4 root 0.00 B/s 0.00 B/s 0.00 % 0.00 % grep -r -I -D skip 10.10.10.99 / ^Croot@Debian:~# What might cause this? Is there a way to view which file grep is currently processing in case lsof is not present? I'm able to use lsof under Debian and looks like the problematic file name there is "0xc6b2c230 file struct, ty=0, op=0xc0d34120". I'm not sure what this is.. I'm not able to use lsof or fstat under FreeBSD. PS: I know I could use find utility, but this is not the question.

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  • Recover RAID 5 data after created new array instead of re-using

    - by Brigadieren
    Folks please help - I am a newb with a major headache at hand (perfect storm situation). I have a 3 1tb hdd on my ubuntu 11.04 configured as software raid 5. The data had been copied weekly onto another separate off the computer hard drive until that completely failed and was thrown away. A few days back we had a power outage and after rebooting my box wouldn't mount the raid. In my infinite wisdom I entered mdadm --create -f... command instead of mdadm --assemble and didn't notice the travesty that I had done until after. It started the array degraded and proceeded with building and syncing it which took ~10 hours. After I was back I saw that that the array is successfully up and running but the raid is not I mean the individual drives are partitioned (partition type f8 ) but the md0 device is not. Realizing in horror what I have done I am trying to find some solutions. I just pray that --create didn't overwrite entire content of the hard driver. Could someone PLEASE help me out with this - the data that's on the drive is very important and unique ~10 years of photos, docs, etc. Is it possible that by specifying the participating hard drives in wrong order can make mdadm overwrite them? when I do mdadm --examine --scan I get something like ARRAY /dev/md/0 metadata=1.2 UUID=f1b4084a:720b5712:6d03b9e9:43afe51b name=<hostname>:0 Interestingly enough name used to be 'raid' and not the host hame with :0 appended. Here is the 'sanitized' config entries: DEVICE /dev/sdf1 /dev/sde1 /dev/sdd1 CREATE owner=root group=disk mode=0660 auto=yes HOMEHOST <system> MAILADDR root ARRAY /dev/md0 metadata=1.2 name=tanserv:0 UUID=f1b4084a:720b5712:6d03b9e9:43afe51b Here is the output from mdstat cat /proc/mdstat Personalities : [linear] [multipath] [raid0] [raid1] [raid6] [raid5] [raid4] [raid10] md0 : active raid5 sdd1[0] sdf1[3] sde1[1] 1953517568 blocks super 1.2 level 5, 512k chunk, algorithm 2 [3/3] [UUU] unused devices: <none> fdisk shows the following: fdisk -l Disk /dev/sda: 80.0 GB, 80026361856 bytes 255 heads, 63 sectors/track, 9729 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000bf62e Device Boot Start End Blocks Id System /dev/sda1 * 1 9443 75846656 83 Linux /dev/sda2 9443 9730 2301953 5 Extended /dev/sda5 9443 9730 2301952 82 Linux swap / Solaris Disk /dev/sdb: 750.2 GB, 750156374016 bytes 255 heads, 63 sectors/track, 91201 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000de8dd Device Boot Start End Blocks Id System /dev/sdb1 1 91201 732572001 8e Linux LVM Disk /dev/sdc: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00056a17 Device Boot Start End Blocks Id System /dev/sdc1 1 60801 488384001 8e Linux LVM Disk /dev/sdd: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000ca948 Device Boot Start End Blocks Id System /dev/sdd1 1 121601 976760001 fd Linux raid autodetect Disk /dev/dm-0: 1250.3 GB, 1250254913536 bytes 255 heads, 63 sectors/track, 152001 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-0 doesn't contain a valid partition table Disk /dev/sde: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x93a66687 Device Boot Start End Blocks Id System /dev/sde1 1 121601 976760001 fd Linux raid autodetect Disk /dev/sdf: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xe6edc059 Device Boot Start End Blocks Id System /dev/sdf1 1 121601 976760001 fd Linux raid autodetect Disk /dev/md0: 2000.4 GB, 2000401989632 bytes 2 heads, 4 sectors/track, 488379392 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 524288 bytes / 1048576 bytes Disk identifier: 0x00000000 Disk /dev/md0 doesn't contain a valid partition table Per suggestions I did clean up the superblocks and re-created the array with --assume-clean option but with no luck at all. Is there any tool that will help me to revive at least some of the data? Can someone tell me what and how the mdadm --create does when syncs to destroy the data so I can write a tool to un-do whatever was done? After the re-creating of the raid I run fsck.ext4 /dev/md0 and here is the output root@tanserv:/etc/mdadm# fsck.ext4 /dev/md0 e2fsck 1.41.14 (22-Dec-2010) fsck.ext4: Superblock invalid, trying backup blocks... fsck.ext4: Bad magic number in super-block while trying to open /dev/md0 The superblock could not be read or does not describe a correct ext2 filesystem. If the device is valid and it really contains an ext2 filesystem (and not swap or ufs or something else), then the superblock is corrupt, and you might try running e2fsck with an alternate superblock: e2fsck -b 8193 Per Shanes' suggestion I tried root@tanserv:/home/mushegh# mkfs.ext4 -n /dev/md0 mke2fs 1.41.14 (22-Dec-2010) Filesystem label= OS type: Linux Block size=4096 (log=2) Fragment size=4096 (log=2) Stride=128 blocks, Stripe width=256 blocks 122101760 inodes, 488379392 blocks 24418969 blocks (5.00%) reserved for the super user First data block=0 Maximum filesystem blocks=0 14905 block groups 32768 blocks per group, 32768 fragments per group 8192 inodes per group Superblock backups stored on blocks: 32768, 98304, 163840, 229376, 294912, 819200, 884736, 1605632, 2654208, 4096000, 7962624, 11239424, 20480000, 23887872, 71663616, 78675968, 102400000, 214990848 and run fsck.ext4 with every backup block but all returned the following: root@tanserv:/home/mushegh# fsck.ext4 -b 214990848 /dev/md0 e2fsck 1.41.14 (22-Dec-2010) fsck.ext4: Invalid argument while trying to open /dev/md0 The superblock could not be read or does not describe a correct ext2 filesystem. If the device is valid and it really contains an ext2 filesystem (and not swap or ufs or something else), then the superblock is corrupt, and you might try running e2fsck with an alternate superblock: e2fsck -b 8193 <device> Any suggestions? Regards!

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  • The volume "filesystem root" has only 0 bytes disk space remaining?

    - by radek
    I installed 11.10 ~two weeks ago and run into some strange troubles recently. Installation was on brand new laptop with clear 128GB SSD. I opted for encrypting home directory. Apart from that I accepted defaults during the installation. There is no other OS on my laptop. I had circa 40GB in use when (for the third time) I got to see this very unpleasant window: Twice situation was pretty bad and whole system slowed down considerably. After reboot I could not login to graphical interface (with an error message informing about insufficient space) and had to remove some files from command line first. Third time I still managed to quickly delete some files and it helped. My laptop is mainly work environment: so no torrents, games, just two movies. Only media filling space are ~20GB of pictures, and bunch of pdfs. Working mostly on PostgreSQL & PostGIS, GeoServer and QGIS recently. Although I had lots of opportunities to test and practice my backups I would be extremely grateful if somebody could point me to any potential solutions to this problem. My laptop has been bought just before I installed Ubuntu, and it came without OS. Could that be hardware issue? Or is the encrypted home causing me headaches? Thanks for help! Update: As suggested by @maniat1k, here is current output of fdisk -l: WARNING: GPT (GUID Partition Table) detected on '/dev/sda'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sda: 160.0 GB, 160041885696 bytes 255 heads, 63 sectors/track, 19457 cylinders, total 312581808 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/sda1 1 312581807 156290903+ ee GPT

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  • Can't shrink Windows Boot NTFS disk: ERROR(5): Could not map attribute 0x80 in inode, Input/output error

    - by arcyqwerty
    Ubuntu 12.04 LTS, all updates current as of 7/3/2012 gksudo gparted Shrink /dev/sda2 from 367GB to 307GB GParted 0.11.0 --enable-libparted-dmraid Libparted 2.3 Shrink /dev/sda2 from 367.00 GiB to 307.00 GiB 00:32:57 ( ERROR ) calibrate /dev/sda2 00:00:00 ( SUCCESS ) path: /dev/sda2 start: 20,484,096 end: 790,142,975 size: 769,658,880 (367.00 GiB) check file system on /dev/sda2 for errors and (if possible) fix them 00:00:53 ( SUCCESS ) ntfsresize -P -i -f -v /dev/sda2 ntfsresize v2012.1.15AR.1 (libntfs-3g) Device name : /dev/sda2 NTFS volume version: 3.1 Cluster size : 4096 bytes Current volume size: 394065338880 bytes (394066 MB) Current device size: 394065346560 bytes (394066 MB) Checking for bad sectors ... Checking filesystem consistency ... Accounting clusters ... Space in use : 327950 MB (83.2%) Collecting resizing constraints ... Estimating smallest shrunken size supported ... File feature Last used at By inode $MFT : 389998 MB 0 Multi-Record : 394061 MB 386464 $MFTMirr : 314823 MB 1 Compressed : 394064 MB 1019521 Sparse : 330887 MB 752454 Ordinary : 393297 MB 706060 You might resize at 327949758464 bytes or 327950 MB (freeing 66116 MB). Please make a test run using both the -n and -s options before real resizing! shrink file system 00:32:04 ( ERROR ) run simulation 00:32:04 ( ERROR ) ntfsresize -P --force --force /dev/sda2 -s 329640837119 --no-action ntfsresize v2012.1.15AR.1 (libntfs-3g) Device name : /dev/sda2 NTFS volume version: 3.1 Cluster size : 4096 bytes Current volume size: 394065338880 bytes (394066 MB) Current device size: 394065346560 bytes (394066 MB) New volume size : 329640829440 bytes (329641 MB) Checking filesystem consistency ... Accounting clusters ... Space in use : 327950 MB (83.2%) Collecting resizing constraints ... Needed relocations : 13300525 (54479 MB) Schedule chkdsk for NTFS consistency check at Windows boot time ... Resetting $LogFile ... (this might take a while) Relocating needed data ... Updating $BadClust file ... Updating $Bitmap file ... ERROR(5): Could not map attribute 0x80 in inode 1667593: Input/output error ======================================== Windows has run chkdsk successfully (on boot) several times now

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  • Platform for Efficiency: Boeing Defense, Space & Security integrates supply chain processes using Oracle Business Process Management solutions. by Fred Sandsmark

    - by JuergenKress
    Like most companies, aerospace giant Boeing has its jargon - words and phrases that uniquely define its products and processes. Take the word platform. It is used at Boeing to mean a family of aircraft - the F/A-18 fighter, for example, or the 777 jetliner. Boeing Defense, Space & Security since August 2009, employees in the Global Services & Support (GS&S) division of Boeing Defense, Space & Security have been talking about a different sort of platform: a supply chain technology platform, based on Oracle Business Process Management (Oracle BPM) solutions and Oracle SOA Suite. That platform, built with the assistance of Oracle Diamond Partner Capgemini, is serving as a jumping-off point for Boeing's GS&S staff to deploy radically improved business processes supported by Oracle Fusion Applications to build a high-visibility, end-to-end supply chain. This business process-driven technology platform has ambitious goals: to help GS&S respond more quickly and accurately to its customers' needs, to make business processes at all GS&S sites more consistent and less expensive, and to create a foundation for further improvement and efficiency. Read the full article here. Want to publish your BPM11g success story - request for a partner/customer reference? BPM Center of Excellent & First 100 Days of BPM documents to our SOA Community Workspace MWD_bpm_si_Centre_of_Excellence_0811.pdf First 100 Days of BPM whitepaper.pdf Please visit our SOA Community Workspace (SOA Community membership required). SOA & BPM Partner Community For regular information on Oracle SOA Suite become a member in the SOA & BPM Partner Community for registration please visit  www.oracle.com/goto/emea/soa (OPN account required) If you need support with your account please contact the Oracle Partner Business Center. Blog Twitter LinkedIn Mix Forum Technorati Tags: BPM,BPM reference,BPM Capgemini,BPM first 100 days,BPM center of Excellence,SOA Community,Oracle SOA,Oracle BPM,Community,OPN,Jürgen Kress

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  • What is the advantage to using a factor of 1024 instead of 1000 for disk size units?

    - by Joe Z.
    When considering the disk space of a storage medium, normally the computer or operating system will represent it in terms of powers of 1024 - a kilobyte is 1,024 bytes, a megabyte is 1,048,576 bytes, a gigabyte is 1,073,741,824 bytes, and so on. But I don't see any practical reason why this convention was adopted. Usually when disk size is represented in kilo-, mega-, or giga-bytes, it has to be converted into decimal first. In places where a power-of-two byte count actually matters (like the block size on a file system), the size is given in bytes anyway (e.g. 4096 bytes). Was it just a little aesthetic novelty that computer makers decided to adopt, but storage medium vendors decided to disregard? Whenever you buy a hard drive, there's always a disclaimer nowadays that says "One gigabyte means one billion bytes". It would feel like using the binary definition of "gigabyte" would artificially inflate the byte count of a device, making drive-makers have to pack 1.1 terabytes into a drive in order to have it show up as "1 TB", or to simply pack 1 terabyte in and have it show up as "931 GB" (and most of them do the latter). Some people have decided to use units like "KiB" or "MiB" in favour of "KB" and "MB" in order to distinguish the two. But is there any merit to the binary prefixes in the first place? There's probably a bit of old history I'm not aware of on this topic, and if there is, I'm looking for somebody to explain it. (Apologies if this is in the wrong place. I felt that a question on best practice might belong here, but I have faith that it will be migrated to the right place if it's incorrect.)

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