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  • Convert executed SQL result to a list of Model object

    - by huynq9
    I'm wondering that is it possible to convert the executed query result to a list of models. I'm using Ruby with ActiveRecord and need to execute custom SQL query to join two or many tables. The code looks like below: connection = ActiveRecord::Base.connection sql = "select T1.f1, T2.f2 from T1 left join T2 on T1.id = T2.id" @result = connection.execute(sql) In Ruby code, I defined a models to manage the executed SQL result: class Model property :f1, :f2 end Is there any way to convert @result to list of Model object? so I can deal with each item in the list as following @result.each do |item| puts item.f1 puts item.f2 end

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  • convert string data array to list

    - by prince23
    hi, i have an string data array which contains data like this 5~kiran 2~ram 1~arun 6~rohan now a method returns an value like string [] data public string [] names() { return data.Toarray() } public class Person { public string Name { get; set; } public int Age { get; set; } } List persons = new List(); string [] names =names(); now i need to copy all the data from an string array to an list and finally bind to grid view gridview.datasoutrce= persons how can i do it. is there any built in method to do it thanks in advance prince

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  • Load list of image from folder

    - by marc-andre menard
    I have a folder of images, from 10 to 200, a webpage, a jquery fade and a php script that read folder full of images Is there any way to make the php script scan a folder, get a list of image (in an array ?) and pass it to jquery script ? (first question) Now, i can make a xml file from the result php list of files found or make a html <li> from the list in the html. is there ANY other way to do that ? (question #2)

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  • LINQ2SQL: how to merge two columns from the same table into a single list

    - by TomL
    this is probably a simple question, but I'm only a beginner so... Suppose I have a table containing home-work locations (cities) certain people use. Something like: ID(int), namePerson(string), homeLocation(string), workLocation(string) where homeLocation and workLocation can both be null. Now I want all the different locations that are used merged into a single list. Something like: var homeLocation = from hm in Places where hm.Home != null select hm.Home; var workLocation = from wk in Places where wk.Work != null select wk.Work; List<string> locationList = new List<string>(); locationList = homeLocation.Distinct().ToList<string>(); locationList.AddRange(workLocation.Distinct().ToList<string>()); (which I guess would still allow duplicates if they have the same value in both columns, which I don't really want...) My question: how this be put into a single LINQ statement? Thanks in advance for your help!

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  • Algorithm to classify a list of products?

    - by Martin
    I have a list representing products which are more or less the same. For instance, in the list below, they are all Seagate hard drives. Seagate Hard Drive 500Go Seagate Hard Drive 120Go for laptop Seagate Barracuda 7200.12 ST3500418AS 500GB 7200 RPM SATA 3.0Gb/s Hard Drive New and shinny 500Go hard drive from Seagate Seagate Barracuda 7200.12 Seagate FreeAgent Desk 500GB External Hard Drive Silver 7200RPM USB2.0 Retail For a human being, the hard drives 3 and 5 are the same. We could go a little bit further and suppose that the products 1, 3, 4 and 5 are the same and put in other categories the product 2 and 6. We have a huge list of products that I would like to classify. Does anybody have an idea of what would be the best algorithm to do such thing. Any suggestions? I though of a Bayesian classifier but I am not sure if it is the best choice. Any help would be appreciated! Thanks.

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  • Java threads not working correctly with linkedlist

    - by user69514
    Hi I am working on the sleeping barber problem. with the addition of having priority customer when they arrive they go in the front of the line and they are the next ones to get a haircut. I'm using a linkedlist and if I see a priority customer I put him in the beginning of the list, if the customer is not priority he goes to the end of the list. then I call the wantHaircut method getting the first element of the list. my problem is that the customer are being processed in the order they arrive, and the priority customer have to wait. here is the code where it all happens. any ideas what I am doing wrong? thanks public void arrivedBarbershop(Customer c){ if(waiting < numChairs && c.isPriority()){ System.out.println("Customer " + c.getID() + ": is a priority customer - SITTING -"); mutex.up(); customer_list.addFirst(c); } else if(waiting >= numChairs && c.isPriority()){ System.out.println("Customer " + c.getID() + ": is a priority customer - STANDING -"); mutex.up(); customer_list.addFirst(c); } else if(waiting < numChairs && !c.isPriority()){ waiting++; System.out.println("Customer " + c.getID() + ": arrived, sitting in the waiting room"); customer_list.addLast(c); customers.up(); // increment waiting customers } else if(waiting >= numChairs && !c.isPriority()) { System.out.println("Customer " + c.getID() + ": went to another barber because waiting room was full - " + waiting + " waiting"); mutex.up(); } if(!customer_list.isEmpty()){ this.wantHairCut(customer_list.removeFirst()); } } public void wantHairCut(Customer c) { mutex.up(); barber.down(); // waits for being allowed in barber chair System.out.println("Customer " + c.getID() + ": getting haircut"); try { /** haircut takes between 1 and 2 seconds **/ Thread.sleep(Barbershop.randomInt(1, 2) * 1000); } catch (InterruptedException e) { } System.out.println("Barber: finished cutting customer " + c.getID() + "'s hair"); c.gotHaircut = true; cutting.up(); // signals cutting has finished /** customer must pay now **/ this.wantToCashout(c); }

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  • Definition list disc not showing up

    - by aslum
    CSS: .about dt { list-style-type:none; font-weight:bold; } .about dd { list-style-type: disc; list-style-position: outside; margin-left: 0px; padding-left: 30px; } And the html <dl class="about"> <dt>Current topics and titles </dt> <dd>Fulfilling community residents&rsquo; appetite for information about popular cultural and social trends and their desires for satisfying recreational experiences</dd> ... I want a disc before the DD, but it's not showing up in Chrome or IE. Any ideas what I've done wrong? Thanks!

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  • List of drugs to parse in application

    - by Skoder
    Hey, Not sure if that has been asked before, but semantics causes difficulty in searching. Are there any sites which have a list of items for developers to use in applications? For example, you can download Dictionaries in specific formats (e.g. XML) for use in word games. In particular, I was hoping that there might be a list of common medical drugs so that I can use display a list in an application I'm working on as researching and typing 150+ drug names would be quite inefficient. Thanks

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  • Python 3.1 - Memory Error during sampling of a large list

    - by jimy
    The input list can be more than 1 million numbers. When I run the following code with smaller 'repeats', its fine; def sample(x): length = 1000000 new_array = random.sample((list(x)),length) return (new_array) def repeat_sample(x): i = 0 repeats = 100 list_of_samples = [] for i in range(repeats): list_of_samples.append(sample(x)) return(list_of_samples) repeat_sample(large_array) However, using high repeats such as the 100 above, results in MemoryError. Traceback is as follows; Traceback (most recent call last): File "C:\Python31\rnd.py", line 221, in <module> STORED_REPEAT_SAMPLE = repeat_sample(STORED_ARRAY) File "C:\Python31\rnd.py", line 129, in repeat_sample list_of_samples.append(sample(x)) File "C:\Python31\rnd.py", line 121, in sample new_array = random.sample((list(x)),length) File "C:\Python31\lib\random.py", line 309, in sample result = [None] * k MemoryError I am assuming I'm running out of memory. I do not know how to get around this problem. Thank you for your time!

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  • Jquery getting list of values of hidden inputs within a div

    - by RandyMarsh
    I am trying to get a list of values within a div that I will format later using the .each() method. They are input values which are hidden my html and jquery call looks like this. <div id="container_0"> <input type="hidden" id="check_data" value=10> <input type="hidden" id="check_data" value=20> </div> Jquery: var list = $('#container_0 input#check_data'); $(list).each( function() { alert($(this).val()); } ); This however is not returning any values. Any help would be greatly appreciated.

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  • iPhone programming guideline : List / detail / modify

    - by Oliver
    Hello, I have a program that displays a list (a TableView). When the user clicks an item, it's detail is shown. On the detail view, the user can ask to modify it so a modify window is shown. Here, the user can ask to delete the item. I would like at this time return to the list with the item deleted from the list and from the data source. There may be thousands of methods to do this, but I wonder which is the best / good one. Could you help me, and/or give me a good reference to read about this ? Thank you.

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  • Selecting an item in an HTML SELECT list using keyboard doesnt trigger the CLICK event

    - by Jimbo
    I have an HTML select list which, when an item is selected, must show different information beneath it. The onclick or JQuery change events are triggered when a select list item is selected by being clicked on (mouse), but not when the user uses key presses (keyboard). Any idea what event to watch in order to determine when the selected list item has changed? Here is a BASIC test example: <select id="mylist" name="mylist"> <option value="">(none)</option> <option value="1">Test 1</option> <option value="2">Test 2</option> <option value="3">Test 3</option> </select> <span id="myspan"></span> <script type="text/javascript"> $("#mylist").change(function() { $("#myspan").html($("#mylist").attr("selectedIndex")); }); </script>

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  • emacs list-buffers behavior

    - by Stephen
    In GNU emacs, every time I hit Ctrl-x Ctrl-b to see all of my buffers, the window is split to show the buffer list, or if I have my window already split in 2 (for instance, I will have a shell running in the lower window), the buffer list appears in the other window. My desired behavior is for the buffer list to appear in my active window so that I can select the buffer I want and continue to working in the same window, rather than having to Ctrl-x Ctrl-o to the other buffer, selecting the buffer (with enter) and editing that buffer in the other window... I've googled for it but it doesn't seem to be a common desire? I wonder if anyone has an elispy (or other) solution?

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  • Removing Redundant Data from a List<T>

    - by Mark
    I have a List of objects which are ordered. I would like to remove redundant objects where redundant does not necessarily mean duplicate. Here is an example: List<Point> points = new List<Point> { new Point(0, 10), new Point(1, 12), new Point(2, 16), new Point(3, 16), new Point(4, 16), new Point(5, 13), new Point(6, 16), }; I am interested in removing the new Point(3, 16) entry because it doesn't provide useful information; I already know that the element at 2=16 and the element at 4=16. The information that 3=16 doesn't do me any good in my application (because I already have the bounds {2,4}=16), so I would like to remove that entry. I'd also like to not that I want to keep the 5th and 6th entry because there are not consecutive entries where Y=16. Is there a slick way to do this with linq?

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  • python - from matrix to dictionary in single line

    - by Sanich
    matrix is a list of lists. I've to return a dictionary of the form {i:(l1[i],l2[i],...,lm[i])} Where the key i is matched with a tuple the i'th elements from each list. Say matrix=[[1,2,3,4],[9,8,7,6],[4,8,2,6]] so the line: >>> dict([(i,tuple(matrix[k][i] for k in xrange(len(matrix)))) for i in xrange(len(matrix[0]))]) does the job pretty well and outputs: {0: (1, 9, 4), 1: (2, 8, 8), 2: (3, 7, 2), 3: (4, 6, 6)} but fails if the matrix is empty: matrix=[]. The output should be: {} How can i deal with this?

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  • Is it possible to match with decomposed sequences in F#?

    - by Ball
    I seem to remember an older version of F# allowing structural decomposition when matching sequences just like lists. Is there a way to use the list syntax while keeping the sequence lazy? I'm hoping to avoid a lot of calls to Seq.head and Seq.skip 1. I'm hoping for something like: let decomposable (xs:seq<'a>) = match xs with | h :: t -> true | _ -> false seq{ 1..100 } |> decomposable But this only handles lists and gives a type error when using sequences. When using List.of_seq, it seems to evaluate all the elements in the sequence, even if it is infinite.

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  • Groovy: Sorting Columns in a view: list

    - by Luixv
    I have a Groovy application. I am rendering the view list using the following statement: render (view: 'list', model:[reportingInstanceList: reportingInstanceList, reportingInstanceTotal: i, params: params]) The list.gsp is as follows: The view is rendered but the default sorting is not working. <g:sortableColumn class="tabtitle" property="id" title="Id" titleKey="reporting.id" /> <g:sortableColumn class="tabtitle" property="company" title="Company" titleKey="reporting.company" /> Unfortunately the default sorting (by id, by company, etc) are not working. Any hint why? Thanks a lot in advance. Luis

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  • error string list handle in C#

    - by Chelsea_cole
    Same namespace: 2 forms. public class Account //frm1 { public string Username; public string Password; } public class ListAcc { public static List<Account> UserList; } private void button1_Click(object sender, EventArgs e) { List<Account> UserList = new List<Account>(); Account acc = new Account(); acc.Username = textBox1.Text; acc.Password = textBox2.Text; UserList.Add(acc); } private void button2_Click(object sender, EventArgs e) //frm2 { string p = frmDangky.ListAcc.UserList[0].Username; // null ->error string p = frmDangky.ListAcc.UserList[0].Password; // null ->error } Someone help me? :( why my string is NULL???????? The textBox is not empty... Thanks!

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  • Can my tortoise vs. hare race be improved?

    - by FredOverflow
    Here is my code for detecting cycles in a linked list: do { hare = hare.next(); if (hare == back) return; hare = hare.next(); if (hare == back) return; tortoise = tortoise.next(); } while (tortoise != hare); throw new AssertionError("cyclic linkage"); Is there a way to get rid of the code duplication inside the loop? Am I right in assuming that I don't need a check after making the tortoise take a step forward? As I see it, the tortoise can never reach the end of the list before the hare (contrary to the fable). Any other ways to simplify/beautify this code?

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  • Relationships via Email Rather Than User List

    - by Bob Lerner
    I'm new at Drupal, so I may have missed a solution despite a lot of research: I want users to be able to invite non-users and other users into a named relationship they've set up (using e.g. the Friendlist or User Relationships module) using only email addresses and not the user list. I believe that invitations from both of those modules are done only after the inviter selects the invitee after selecting the invitee from a list of all users. Frankly, I would be surprised if no email solution exists since a large site's user list would be daunting. Does anyone know if this is possible using Organic Groups? Thanks very much.

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  • How can I use STL sort in c++ to sort some values in the class?

    - by Morteza M.
    I have a class named Graph, in this class I have a member named V, it is a vector. I have a struct named Edge, and a list of Edges. like below: struct Edge{ int u; int v; Edge(int u,int v){ this-u=u; this-v=v; } }; class Graph{ vector < Vertex > V; . . . int edgeCmp(Edge* x,Edge* y){ return (V[x-v].dv].d)?1:0; } void someFunction(){ list backEdges; backEdges.sort(&Graph::edgeCmp); } } But it doesn't work!! may someone help me to do such a thing?

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  • removing the single quote from a list of

    - by tanky
    I need to append/format a url with a list of ids for an api call however, when i put the list at the end of the api https://api.twitter.com/1.1/users/lookup.json?user_id=%s'%a i just get an empty string as a response. i have tried turning the list into a string and removing the square brackets doing a = str(followers['ids'])[1:-1] but i still get the same problem. and im assuming that its being caused by the single quote at the start. i have tried removing the apostrophe from the string doing a.replace("'", "") and now i have run out of ideas thanks

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  • converting result set to list

    - by akshay
    how can i conver result set to list? i am using following code but its not working properly private List<User> convertToList(ResultSet rs) { List<User> userList = new ArrayList(); User user = new User(); try { while (rs.next()) { user.setId(rs.getInt("id")); user.setUsername(rs.getString("username")); user.setFname(rs.getString("fname")); user.setLname(rs.getString("lname")); user.setUsertype(rs.getInt("usertype")); user.setPasswd(rs.getString("passwd")); user.setEmail(rs.getString("email")); userList.add(user); } } catch (SQLException ex) { Logger.getLogger(UserDAO.class.getName()).log(Level.SEVERE, null, ex); } finally { closeConnection(); } return userList; }

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  • CSS3: Top align of list item

    - by Irishgirl
    CSS3: Top align of list item. See image as below. How can I align a blue arrow to align on top of a senetence of each list. I'm using jQuery 1.7 and it is for iOS (iPhone). ul.lists{ padding:0 0 15px 0;} ul.lists li{ line-height:18px; border-bottom:1px #bfeaf0 solid; padding:6px 12px; background:url(../images/arrow_cyan.svg) no-repeat left; } /* no-repeat left top; */ I've tried to include a js as offset $("li:last").offset({ top: -15 }); but it did not work properly because I don't know how to move all blue arrows to align each list even the sentence might might run into more than one line.

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  • Give users permissions on item in other list

    - by Nomz
    Hello everyone, This is what im working on: i have two lists, first one: collumn user and collumn project that the user is assigend to. second one (library): a list of all the projects I was wondering, how, by every row that is created in the first list (so adding a user and a project) it is possible to grant the user permissions on this project's reference in the second library (the projects library). Example: ProjectLibrary: Project1 Project2 Project3 the first list: user1 project1 user1 project2 user2 project2 user2 project3 user3 project3 now i want to give each user permission to see the project he's assigned to so that when he opens a third form, a combobox filled with projects will only show the projects he has permissions on. thank you so much!

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