Search Results

Search found 19495 results on 780 pages for 'xml parse'.

Page 89/780 | < Previous Page | 85 86 87 88 89 90 91 92 93 94 95 96  | Next Page >

  • XSLT Transforming sequential XML to hierarchical XML

    - by Jean-Paul Smit
    I have a requirement to transform a sequential XML node list into a hierarchical, but I run into some XSLT specific knowledge gap. The input XML contains articles, colors and sizes. In the sample below 'Record1' is an article, 'Record2' represents a color and 'Record3' are the sizes. The number of colors and sizes (record2 and record3) elements can vary. <root> <Record1>...</Record1> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record1>...</Record1> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> </root> All fields are on the same hierarchical level, but still I have to create this structure as output: <root> <article> -> Record1 <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> </article> <article> -> Record1 <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> </article> </root> I've tried to iterate the nodes sequentially but for example the 'article' (=record1) node tag needs to remain unclosed while 'color' (=record2) nodes are processed. The same counts for processing 'size' (=record3) having 'color' unclosed, but that is not allowed by XSLT. My next idea was to call a template for every article, color and size level, but I don't know how to select for example all 'record3' nodes between the current 'record2' and the next article represented by 'record1'. I've also got a limitation on the XSLT version because I need this transformation in BizTalk Server which only supports XSLT 1.0 Can someone push me in the right direction?

    Read the article

  • How do you traverse and store XML in Blackberry Java app?

    - by Greg
    I'm having a problem accessing the contents of an XML document. My goal is this: Take an XML source and parse it into a fair equivalent of an associative array, then store it as a persistable object. the xml is pretty simple: <root> <element> <category_id>1</category_id> <name>Cars</name> </element> <element> <category_id>2</category_id> <name>Boats</name> </element> </root> Basic java class below. I'm pretty much just calling save(xml) after http response above. Yes, the xml is properly formatted. import java.io.IOException; import java.util.Hashtable; import org.w3c.dom.Document; import org.w3c.dom.Node; import org.w3c.dom.NodeList; import java.util.Vector; import net.rim.device.api.system.PersistentObject; import net.rim.device.api.system.PersistentStore; import net.rim.device.api.xml.parsers.DocumentBuilder; import net.rim.device.api.xml.parsers.DocumentBuilderFactory; public class database{ private static PersistentObject storeVenue; static final long key = 0x2ba5f8081f7ef332L; public Hashtable hashtable; public Vector venue_list; String _node,_element; public database() { storeVenue = PersistentStore.getPersistentObject(key); } public void save(Document xml) { venue_list = new Vector(); storeVenue.setContents(venue_list); Hashtable categories = new Hashtable(); try{ DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory. newInstance(); DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder(); docBuilder.isValidating(); xml.getDocumentElement ().normalize (); NodeList list=xml.getElementsByTagName("*"); _node=new String(); _element = new String(); for (int i=0;i<list.getLength();i++){ Node value=list.item(i).getChildNodes().item(0); _node=list.item(i).getNodeName(); _element=value.getNodeValue(); categories.put(_element, _node); } } catch (Exception e){ System.out.println(e.toString()); } venue_list.addElement(categories); storeVenue.commit(); } The code above is the work in progress, and is most likely heavily flawed. However, I have been at this for days now. I can never seem to get all child nodes, or the name / value pair. When I print out the vector as a string, I usually end up with results like this: [{ = root, = element}] and that's it. No "category_id", no "name" Ideally, I would end up with something like [{1 = cars, 2 = boats}] Any help is appreciated. Thanks

    Read the article

  • Cannot parse persistence unit from class path resource

    - by Grzegorz S
    so I have this problem in running my Spring WS app which implements JPA ( or should implement..) I have a problem with running a WS, it looks like my Spring context can't find file persistence.xml Which i am able to believe because i did not have generated META-INF folder in my template (which is Maven project template with archetype org.springframework.ws) I have created META-INF manually. Here is the HTTP 500: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'caChainDao' defined in file [E:\STS\vfabric-tc-server-developer-2.7.2.RELEASE\zz\wtpwebapps\FCAWSv4\WEB-INF\classes\pl\famoc\test\ws\db\dao\caChainDao.class]: Initialization of bean failed; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in ServletContext resource [/WEB-INF/spring-ws-servlet.xml]: Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Cannot parse persistence unit from class path resource [persistence.xml] org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:527) org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:456) org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:294) org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:225) org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:291) org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:193) org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:609) org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:918) org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:469) org.springframework.web.servlet.FrameworkServlet.configureAndRefreshWebApplicationContext(FrameworkServlet.java:631) org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:588) org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:645) org.springframework.web.servlet.FrameworkServlet.initWebApplicationContext(FrameworkServlet.java:508) org.springframework.web.servlet.FrameworkServlet.initServletBean(FrameworkServlet.java:449) org.springframework.web.servlet.HttpServletBean.init(HttpServletBean.java:133) javax.servlet.GenericServlet.init(GenericServlet.java:160) org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:472) org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:99) org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:929) org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:407) org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1002) org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:585) org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:310) java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1110) java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:603) java.lang.Thread.run(Thread.java:722) Here it is my persistence.xml <?xml version="1.0" encoding="UTF-8" ?> <persistence xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd" version="2.0" xmlns="http://java.sun.com/xml/ns/persistence"> <persistence-unit name="persistenceUnit" transaction-type="RESOURCE_LOCAL" /> </persistence> here it is where i am looking for it <property name="persistenceXmlLocation" value="classpath:persistence.xml" /> and here it is path to this xml in my classpath: src/main/webapp/META-INF/persistence.xml Could anyone give me a hint what am i missing?

    Read the article

  • What is the recommended way of parsing an XML feed with multiple namespaces with ActionScript 3.0?

    - by dafko
    I have seen the following methods to be used in several online examples, but haven't found any documentation on the recommended way of parsing an XML feed. Method 1: protected function xmlResponseHandler(event:ResultEvent):void { var atom:Namespace = new Namespace("http://www.w3.org/2005/Atom"); var microsoftData:Namespace = new Namespace("http://schemas.microsoft.com/ado/2007/08/dataservices"); var microsoftMetadata:Namespace = new Namespace("http://schemas.microsoft.com/ado/2007/08/dataservices/metadata"); var ac:ArrayCollection = new ArrayCollection(); var keyValuePairs:KeyValuePair; var propertyList:XMLList = (event.result as XML)..atom::entry.atom::content.microsoftMetadata::properties; for each (var properties:XML in propertyList) { keyValuePairs = new KeyValuePair(properties.microsoftData::FieldLocation, properties.microsoftData::Locationid); ac.addItem(keyValuePairs); } cb.dataProvider = ac; } Method 2: protected function xmlResponseHandler(event:ResultEvent):void { namespace atom = "http://www.w3.org/2005/Atom"; namespace d = "http://schemas.microsoft.com/ado/2007/08/dataservices"; namespace m = "http://schemas.microsoft.com/ado/2007/08/dataservices/metadata"; use namespace d; use namespace m; use namespace atom; var ac:ArrayCollection = new ArrayCollection(); var keyValuePairs:KeyValuePair; var propertyList:XMLList = (event.result as XML)..entry.content.properties; for each (var properties:XML in propertyList) { keyValuePairs = new KeyValuePair(properties.FieldLocation, properties.Locationid); ac.addItem(keyValuePairs); } cb.dataProvider = ac; } Sample XML feed: <?xml version="1.0" encoding="iso-8859-1" standalone="yes"?> <feed xml:base="http://www.test.com/Test/my.svc/" xmlns:d="http://schemas.microsoft.com/ado/2007/08/dataservices" xmlns:m="http://schemas.microsoft.com/ado/2007/08/dataservices/metadata" xmlns="http://www.w3.org/2005/Atom"> <title type="text">Test_Locations</title> <id>http://www.test.com/test/my.svc/Test_Locations</id> <updated>2010-04-27T20:41:23Z</updated> <link rel="self" title="Test_Locations" href="Test_Locations" /> <entry> <id>1</id> <title type="text"></title> <updated>2010-04-27T20:41:23Z</updated> <author> <name /> </author> <link rel="edit" title="Test_Locations" href="http://www.test.com/id=1" /> <category term="MySQLModel.Test_Locations" scheme="http://schemas.microsoft.com/ado/2007/08/dataservices/scheme" /> <content type="application/xml"> <m:properties> <d:FieldLocation>Test Location</d:FieldLocation> <d:Locationid>test0129</d:Locationid> </m:properties> </content> </entry> <entry> <id>2</id> <title type="text"></title> <updated>2010-04-27T20:41:23Z</updated> <author> <name /> </author> <link rel="edit" title="Test_Locations" href="http://www.test.com/id=2" /> <category term="MySQLModel.Test_Locations" scheme="http://schemas.microsoft.com/ado/2007/08/dataservices/scheme" /> <content type="application/xml"> <m:properties> <d:FieldLocation>Yet Another Test Location</d:FieldLocation> <d:Locationid>test25</d:Locationid> </m:properties> </content> </entry> </feed>

    Read the article

  • Java Plist XML Parsing

    - by Jannis
    Hello everyone, I'm parsing a (not well formed) Apple Plist File with java. My Code looks like this: InputStream in = new FileInputStream( "foo" ); XMLInputFactory factory = XMLInputFactory.newInstance(); XMLEventReader parser = factory.createXMLEventReader( in ); while (parser.hasNext()){ XMLEvent event = parser.nextEvent(); //code to navigate the nodes } The parts I"m parsing are looking like this: <dict> <key>foo</key><integer>123</integer> <key>bar</key><string>Boom &amp; Shroom</string> </dict> My problem is now, that nodes containing a ampersand are not parsed like they should because the ampersand is representing a entity. What can i do to get the value of the node as a complete String, instead of broken parts? Thank you in advance.

    Read the article

  • Java XML Unmarshalling fails on ampersand (&amp;) using JAXB

    - by ryanprayogo
    I have the following XML: <?xml version="1.0" encoding="UTF-8"?> <details> ... <address1>Test&amp;Address</address1> ... </details> When I try to unmarshal it using JAXB, it throws the following exception: Caused by: org.xml.sax.SAXParseException: The reference to entity "Address" must end with the ';' delimiter. at org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source) at org.apache.xerces.util.ErrorHandlerWrapper.fatalError(Unknown Source) at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source) at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source) at org.apache.xerces.impl.XMLScanner.reportFatalError(Unknown Source) at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanEntityReference(Unknown Source) at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl$FragmentContentDispatcher.dispatch(Unknown Source) at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source) at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source) at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source) at org.apache.xerces.parsers.XMLParser.parse(Unknown Source) at org.apache.xerces.parsers.AbstractSAXParser.parse(Unknown Source) at org.apache.xerces.jaxp.SAXParserImpl$JAXPSAXParser.parse(Unknown Source) at com.sun.xml.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:194) But when I changed the &amp; in the XML to &apos;, it works. Looks like the problem is only with ampersand &amp; and I cannot understand why. The code to unmarshal is: JAXBContext context = JAXBContext.newInstance("some.package.name", this.getClass().getClassLoader()); Unmarshaller unmarshaller = context.createUnmarshaller(); obj = unmarshaller.unmarshal(new StringReader(xml)); Anyone have some insight?

    Read the article

  • Manually iterating over a selection of XML elements (C#, XDocument)

    - by user316117
    What is the “best practice” way of manually iterating (i.e., one at a time with a “next” button) over a set of XElements in my XDocument? Say I select the set of elements I want thusly: var elems = from XElement el in m_xDoc.Descendants() where (el.Name.LocalName.ToString() == "q_a") select el; I can use an IEnumerator to iterate over them, i.e., IEnumerator m_iter; But when I get to the end and I want to wrap around to the beginning if I call Reset() on it, it throws a NotSupportedException. That’s because, as the Microsoft C# 2.0 Specification under chapter 22 "Iterators" says "Note that enumerator objects do not support the IEnumerator.Reset method. Invoking this method causes a System.NotSupportedException to be thrown ." So what IS the right way of doing this? And what if I also want to have bidirectional iteration, i.e., a “back” button, too? Someone on a Microsoft discussion forum said I shouldn’t be using IEnumerable directly anyway. He said there was a way to do what I want with LINQ but I didn’t understand what. Someone else suggested dumping the XElements into a List with ToList(), which I think would work, but I wasn’t sure it was “best practice”. Thanks in advance for any suggestions!

    Read the article

  • .net XML serialization: how to specify an array's root element and child element names

    - by Jeremy
    Consider the following serializable classes: class Item {...} class Items : List<Item> {...} class MyClass { public string Name {get;set;} public Items MyItems {get;set;} } I want the serialized output to look like: <MyClass> <Name>string</Name> <ItemValues> <ItemValue></ItemValue> <ItemValue></ItemValue> <ItemValue></ItemValue> </ItemValues> </MyClass> Notice the element names ItemValues and ItemValue doesn't match the class names Item and Items, assuming I can't change the Item or Items class, is there any why to specify the element names I want, by modifying the MyClass Class?

    Read the article

  • amazon mws orders help simplify, flatten xml

    - by Scott Kramer
    XDocument doc = XDocument.Load( filename ); var ele = doc.Elements("AmazonEnvelope") //.Elements("Header") .Elements("Message") .Elements("OrderReport") .Elements("Item") .Select(element => new { AmazonOrderItemCode = (string)element.Element("AmazonOrderItemCode"), SKU = (string)element.Element("SKU"), Title = (string)element.Element("Title"), Quantity = (string)element.Element("Quantity"), }) //.Elements("ItemPrice") //.Elements("Component") //.Select(element => new //{ // Type = (string)element.Element("Type"), // Amount = (string)element.Element("Amount"), // }) .ToList(); foreach (var x in ele) { Console.WriteLine(x.ToString()); }

    Read the article

  • Using Android SAXParser, one my my XML Elements is mysteriously breaking in half.

    - by Drennen
    And its not '&' Im using the SAXParser object do parse the actual XML. This is normally done by passing a URL to the XMLReader.Parse method. Because my XML is coming from a POST request to a webservice, I am saving that result as a String and then employing StringReader / InputSource to feed this string back to the XMLReader.Parse method. However, something strange is happening at the 2001st character of the XMLstring. The 'characters' method of the document handler is being called TWICE in between the startElement and endElement methods, effectively breaking my string (in this case a project title) into two pieces. Because I am instantiating objects in my characters method, I am getting two objects instead of one. This line, about 2000 chars into the string fires 'characters' two times, breaking between "Lower" and "Level" <title>SUMC-BOOKSTORE, LOWER LEVEL RENOVATIONS</title> When I bypass the StringReader / InputSource workaround and feed a flat XML file to XMLReader.Parse, it works absolutely fine. Something about StringReader and or InputSource is somehow screwing this up. Here is my method that takes and XML string and parses is through the SAXParser. public void parseXML(String XMLstring) { try { SAXParserFactory spf = SAXParserFactory.newInstance(); SAXParser sp = spf.newSAXParser(); XMLReader xr = sp.getXMLReader(); xr.setContentHandler(this); // Something is happening in the StringReader or InputSource // That cuts the XML element in half at the 2001 character mark. StringReader sr = new StringReader(XMLstring); InputSource is = new InputSource(sr); xr.parse(is); } catch (IOException e) { Log.e("CMS1", e.toString()); } catch (SAXException e) { Log.e("CMS2", e.toString()); } catch (ParserConfigurationException e) { Log.e("CMS3", e.toString()); } } I would greatly appreciate any ideas on how to not have 'characters' firing off twice when I get to this point in the XML String. Or, show me how to use a POST request and still pass off the URL to the Parse function. THANK YOU.

    Read the article

  • not able to Deserialize xml into object

    - by Ravisha
    I am having following peice of code ,where in i am trying to serialize and deserailize object of StringResource class. Please note Resource1.stringXml = its coming from resource file.If i pass strelemet.outerXMl i get the object from Deserialize object ,but if i pass Resource1.stringXml i am getting following exception {"< STRING xmlns='' was not expected."} System.Exception {System.InvalidOperationException} class Program { static void Main(string[] args) { StringResource str = new StringResource(); str.DELETE = "CanDelete"; str.ID= "23342"; XmlElement strelemet = SerializeObjectToXmlNode (str); StringResource strResourceObject = DeSerializeXmlNodeToObject<StringResource>(Resource1.stringXml); Console.ReadLine(); } public static T DeSerializeXmlNodeToObject<T>(string objectNodeOuterXml) { try { TextReader objStringsTextReader = new StringReader(objectNodeOuterXml); XmlSerializer stringResourceSerializer = new XmlSerializer(typeof(T),string.Empty); return (T)stringResourceSerializer.Deserialize(objStringsTextReader); } catch (Exception excep) { return default(T); } } public static XmlElement SerializeObjectToXmlNode(object obj) { using (MemoryStream memoryStream = new MemoryStream()) { try { XmlSerializerNamespaces xmlNameSpace = new XmlSerializerNamespaces(); xmlNameSpace.Add(string.Empty, string.Empty); XmlWriterSettings writerSettings = new XmlWriterSettings(); writerSettings.CloseOutput = false; writerSettings.Encoding = System.Text.Encoding.UTF8; writerSettings.Indent = false; writerSettings.OmitXmlDeclaration = true; XmlWriter writer = XmlWriter.Create(memoryStream, writerSettings); XmlSerializer xmlserializer = new XmlSerializer(obj.GetType()); xmlserializer.Serialize(writer, obj, xmlNameSpace); writer.Close(); memoryStream.Position = 0; XmlDocument serializeObjectDoc = new XmlDocument(); serializeObjectDoc.Load(memoryStream); return serializeObjectDoc.DocumentElement; } catch (Exception excep) { return null; } } } } public class StringResource { [XmlAttribute] public string DELETE; [XmlAttribute] public string ID; } < STRING ID="1" DELETE="True" /

    Read the article

  • Getting XQuery [modify()]: Top-level attribute nodes are not supported error while modifying xml

    - by sam
    DECLARE @mycur CURSOR DECLARE @id int DECLARE @ParentNodeName varchar(max) DECLARE @NodeName varchar(max) DECLARE @NodeText varchar(max) SET @mycur = CURSOR FOR SELECT * FROM @temp OPEN @mycur FETCH NEXT FROM @mycur INTO @id,@ParentNodeName,@NodeName,@NodeText WHILE @@FETCH_STATUS = 0 BEGIN PRINT @id -- sample statements PRINT @ParentNodeName PRINT @NodeName SET @x.modify (' insert attribute status {sql:variable("@status")} as first into (/@ParentNodeName/@NodeName/child::*[position()=sql:variable("@status")])[1] ') FETCH NEXT FROM @mycur INTO @id,@ParentNodeName,@NodeName,@NodeText END DEALLOCATE @mycur Any idea why I am getting this error as query works fine if I manually insert path

    Read the article

  • Sending Illegal XML Characters in Soap Request

    - by SK
    I am trying to send special (&, ' (single quote)) characters in the Soap Request. I am using axis 1.4. The webservice client is in weblogic server and the webservice server is an ibm mainframe (COBOL program). The request data from the client contains special character (& symbol) which is converted to &amp; I tried to enclose it with CDATA as <![CDATA[Some Name & Some Data ]]> which got converted to &lt;![CDATA[Some Name &amp; Some Data]]&gt; The webservice client is generated from wsdl, so I couldn't use CDATA api to construct the request. I am able to set it as string value, and it is getting converted. Any help on this would be greatly appreciated. Please let me know if you need any more information on this.

    Read the article

  • @ in AndroidManifest.xml file

    - by C.W.Holeman II
    From the O'Reilly book "Android Application Development " by Rick Rogers, John Lombardo, Zigurd Mednieks & Blake Meike: page 23: <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="@string/hello" /> page 44: <application android:icon="@drawable/icon2"> What is the meaning of the "@" in each of the above fragments?

    Read the article

  • How to unencode escaped XML with xQuery

    - by mbrevoort
    I have a variable in xQuery of type xs:string with the value of an encoded HTML snippet (the content of a twitter tweet). It looks like this: Headlines-Today &#8226; AP sources: &lt;b&gt;Obama&lt;/b&gt; pick for Justice post withdraws : News - Rest Of World - &lt;a href=&quot;http://shar.es/mqMAG&quot;&gt;http://shar.es/mqMAG&lt;/a&gt; When I try to write this out in an HTML block, I need the string to be unescaped so that the HTML snippet will be interpreted by the browser. Instead the string is getting written out as is and the browser is rendering it as just text (so you see <a href="blah.... ). Here's how I'm writing out this string: {$entry/atom:content/text()} How can I have the escaped characters unencoded so it writes < rather tha &lt; ? I've tried to do a replacelike this but it always replaces the &lt; with &lt; ! fn:replace($s, "&lt;", "<")

    Read the article

  • Simple XML variable returns "0"

    - by Warren Haskins
    Ok, so im working with tumblr's API and im using SimpleXMLElement with php and ive run into a problem. Basically, when I call on a variable it just prints a zero. for instance : <?php echo $data->posts->post[0]->photo-url[5]; ?> This just breaks the page, and when I leave out the [5] it just prints zero I want to echo the photo-url with the number [5] but I cant get my head around this and its killing me. I just dont understand why it wont work. Heres a sample of the simpleXMLElement print-out : SimpleXMLElement Object ( [@attributes] = Array ( [version] = 1.0 ) [posts] => SimpleXMLElement Object ( [@attributes] => Array ( [type] => photo ) [post] => Array ( [0] => SimpleXMLElement Object ( [@attributes] => Array ( [id] => 574166180 [url] => http://young-n-reckless.tumblr.com/post/574166180 [url-with-slug] => http://young-n-reckless.tumblr.com/post/574166180 [type] => photo [date-gmt] => 2010-05-05 19:52:46 GMT [date] => Wed, 05 May 2010 15:52:46 [unix-timestamp] => 1273089166 [format] => html [reblog-key] => vc9EfT7d [slug] => [tumblelog] => young-n-reckless [bookmarklet] => true ) [tumblelog] => SimpleXMLElement Object ( [@attributes] => Array ( [title] => Young & Reckless [name] => young-n-reckless [url] => http://young-n-reckless.tumblr.com/ [timezone] => US/Eastern [avatar-url-16] => http://24.media.tumblr.com/avatar_424f776dd55c_16.png [avatar-url-24] => http://24.media.tumblr.com/avatar_424f776dd55c_24.png [avatar-url-30] => http://24.media.tumblr.com/avatar_424f776dd55c_30.png [avatar-url-40] => http://25.media.tumblr.com/avatar_424f776dd55c_40.png [avatar-url-48] => http://24.media.tumblr.com/avatar_424f776dd55c_48.png [avatar-url-64] => http://26.media.tumblr.com/avatar_424f776dd55c_64.png [avatar-url-96] => http://25.media.tumblr.com/avatar_424f776dd55c_96.png [avatar-url-128] => http://24.media.tumblr.com/avatar_424f776dd55c_128.png [avatar-url-512] => http://29.media.tumblr.com/avatar_424f776dd55c_512.png ) ) [photo-link-url] => http://www.flickr.com/photos/katiemabey/3429588812/ [photo-url] => Array ( [0] => http://30.media.tumblr.com/tumblr_l1w1qd7Zcg1qatgoto1_500.jpg [1] => http://30.media.tumblr.com/tumblr_l1w1qd7Zcg1qatgoto1_500.jpg [2] => http://25.media.tumblr.com/tumblr_l1w1qd7Zcg1qatgoto1_400.jpg [3] => http://28.media.tumblr.com/tumblr_l1w1qd7Zcg1qatgoto1_250.jpg [4] => http://30.media.tumblr.com/tumblr_l1w1qd7Zcg1qatgoto1_100.jpg [5] => http://30.media.tumblr.com/tumblr_l1w1qd7Zcg1qatgoto1_75sq.jpg ) ) Any help would be greatly appreciated, and thanks in advance. Warren

    Read the article

  • XML String into a DataGridView (C#)

    - by Justin Daniels
    I am currently working with a webservice to pull a report about users in a remote support system. After pulling my report and receiving the result, I am given the following string back by the method: <report><header><field id="0">Source</field><field id="1">Session ID</field><field id="2">Date</field><field id="3">Name</field><field id="24">Technician Name</field><field id="25">Technician ID</field></header><data><row><field id="0">Email</field><field id="1">55037806</field><field id="2">4/13/2010 2:28:06 AM</field><field id="3">Bill Gates</field><field id="24">John</field><field id="25">1821852</field></row><row><field id="0">Telephone</field><field id="1">55034548</field><field id="2">4/13/2010 12:59:44 AM</field><field id="3">Steve Jobs</field><field id="24">John</field><field id="25">1821852</field></row></data></report> After receiving this string, I need to take it and display the actual data in a datagridview. I've tried putting it into an XMLDocument then reading that, but it seems to keep failing. Just interested in another set of eyes :) Application is written in C# in VS2010.

    Read the article

  • Union with LINQ to XML

    - by Ryan Riley
    I need to union two sets of XElements into a single, unique set of elements. Using the .Union() extension method, I just get a "union all" instead of a union. Am I missing something? var elements = xDocument.Descendants(w + "sdt") .Union(otherDocument.Descendants(w + "sdt") .Select(sdt => new XElement( sdt.Element(w + "sdtPr") .Element(w + "tag") .Attribute(w + "val").Value, GetTextFromContentControl(sdt).Trim()) ) );

    Read the article

  • XML invoice specification

    - by stimms
    I am writing an application which produces invoices. Yes, it sucks. I was wondering it there was any agreed upon DTD for invoices? It seems like everybody has their own format. Perhaps there is a collection of XSLTs for tranforming a common standard into lesser known formats?

    Read the article

  • Exclude css & image resources in web.xml Security Constraint

    - by Tiggles
    I am using JSF2.1 and Glassfish 3.1.2. I specify a security constraint to block everything: <security-constraint> <web-resource-collection> <web-resource-name>Secured Content</web-resource-name> <!-- Block all --> <url-pattern>/*</url-pattern> </web-resource-collection> <!-- only users with at least one of these roles are allowed to access the secured content --> <auth-constraint> <role-name>ADMINISTRATOR</role-name> </auth-constraint> </security-constraint> and have another to allow access a subset of pages and the resources: <security-constraint> <web-resource-collection> <web-resource-name>Open Content</web-resource-name> <!-- Allow subscribe --> <url-pattern>/subscribe/*</url-pattern> <url-pattern>/javax.faces.resource/*</url-pattern> </web-resource-collection> <!-- No Auth Contraint! --> </security-constraint> This works fine. However, is the following <url-pattern>/javax.faces.resource/*</url-pattern> the correct way to allow all resources? I only did this by looking at the url that Facelets injects into the xhtml. Is there security holes with this approach? Thanks.

    Read the article

  • Using two namespaces when defining a new xml file (XDocument, XElement, XAttribute)

    - by Manchuwook
    XNamespace xnRD = "http://schemas.microsoft.com/SQLServer/reporting/reportdesigner"; XNamespace xnNS = "http://schemas.microsoft.com/sqlserver/reporting/2008/01/reportdefinition"; XAttribute xaRD = new XAttribute(XNamespace.Xmlns + "rd", xnRD); XAttribute xaNS = new XAttribute("xmlns", xnNS); XElement x = new XElement("Report", xaRD, xaNS, new XElement("DataSources"), new XElement("DataSets"), new XElement("Body"), new XElement("Width"), new XElement("Page"), new XElement("ReportID", xaRD), new XElement("ReportUnitType", xaRD) ); XDocument doc = new XDocument(new XDeclaration("1.0", "utf-8", "yes")); doc.Add(x); Console.WriteLine(doc.ToString()); Results in runtime error: {"The prefix '' cannot be redefined from '' to 'http://schemas.microsoft.com/sqlserver/reporting/2008/01/reportdefinition' within the same start element tag."} What I am trying to do is just make the DataSources and DataSets write out to the Debug.Console to build ObjectDataSources since VS2010 neglected to add them for ASPX. EDIT: new XElement(xaRD + "ReportID"), new XElement(xaRD + "ReportUnitType") Changed and got : Additional information: The ':' character, hexadecimal value 0x3A, cannot be included in a name. Instead

    Read the article

  • replace xml element

    - by snorlaks
    Hello, Im doing something like that: var results = from d in myDocument.Elements().Descendants("myName") select d; foreach (var result in results){ if (sth...){ result.replace(myXElement); } } The problem is that when I replace an element I cant iterate to the next element cause there is null reference. (var result in results). Is there any other way to replace that element with another one and still be able to iterate through that document ? thanks for help

    Read the article

  • C# LINQ XML Query with duplicate element names that have attributes

    - by ncain187
    <Party id="Party_1"> <PartyTypeCode tc="1">Person</PartyTypeCode> <FullName>John Doe</FullName> <GovtID>123456789</GovtID> <GovtIDTC tc="1">Social Security Number US</GovtIDTC> <ResidenceState tc="35">New Jersey</ResidenceState> <Person> <FirstName>Frank</FirstName> <MiddleName>Roberts</MiddleName> <LastName>Madison</LastName> <Prefix>Dr.</Prefix> <Suffix>III</Suffix> <Gender tc="1">Male</Gender> <BirthDate>1974-01-01</BirthDate> <Age>35</Age> <Citizenship tc="1">United States of America</Citizenship> </Person> <Address> <AddressTypeCode tc="26">Bill Mailing</AddressTypeCode> <Line1>2400 Meadow Lane</Line1> <Line2></Line2> <Line3></Line3> <Line4></Line4> <City>Somerset</City> <AddressStateTC tc="35">New Jersey</AddressStateTC> <Zip>07457</Zip> <AddressCountryTC tc="1">United States of America</AddressCountryTC> </Address> </Party> <!-- *********************** --> <!-- Insured Information --> <!-- *********************** --> <Party id="Party_2"> <PartyTypeCode tc="1">Person</PartyTypeCode> <FullName>Dollie Robert Madison</FullName> <GovtID>123956239</GovtID> <GovtIDTC tc="1">Social Security Number US</GovtIDTC> <Person> <FirstName>Dollie</FirstName> <MiddleName>R</MiddleName> <LastName>Madison</LastName> <Suffix>III</Suffix> <Gender tc="2">Female</Gender> <BirthDate>1996-10-12</BirthDate> <Citizenship tc="1">United States of America</Citizenship> </Person> <!-- Insured Address --> <Address> <AddressTypeCode tc="26">Bill Mailing</AddressTypeCode> <Line1>2400 Meadow Lane</Line1> <City>Somerset</City> <AddressStateTC tc="35">New Jersey</AddressStateTC> <Zip>07457</Zip> <AddressCountryTC tc="1">United States of America</AddressCountryTC> </Address> <Risk> <!-- Disability Begin Effective Date --> <DisabilityEffectiveStartDate>2006-01-01</DisabilityEffectiveStartDate> <!-- Disability End Effective Date --> <DisabilityEffectiveStopDate>2008-01-01</DisabilityEffectiveStopDate> </Risk> </Party> <!-- ******************************* --> <!-- Company Information --> <!-- ****************************** --> <Party id="Party_3"> <PartyTypeCode tc="2">Organization</PartyTypeCode> <Organization> <DTCCMemberCode>1234</DTCCMemberCode> </Organization> <Carrier> <CarrierCode>105</CarrierCode> </Carrier> </Party> Here is my code which doesn't work because party 3 doesn't contain FullName, I know that partyelements contains 3 parties if I only return the name attribute. Is there a way to loop through each tag seperate? var partyElements = from party in xmlDoc.Descendants("Party") select new { Name = party.Attribute("id").Value, PartyTypeCode = party.Element("PartyTypeCode").Value, FullName = party.Element("FullName").Value, GovtID = party.Element("GovtID").Value, };

    Read the article

< Previous Page | 85 86 87 88 89 90 91 92 93 94 95 96  | Next Page >