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  • C++ Set Erase Entry Question

    - by Wallace
    Hi. I encountered a problem here. I'm using C++ multiset. This is the test file. Score: 3-1 Ben Steven Score: 1-0 Ben Score: 0-0 Score: 1-1 Cole Score: 1-2 Ben I'm using while loop and ifstream (fin1) to read in from the test file above. multiset<string, less<string> > myset; while(!fin1.eof()) { fin1 >> scoreName; if(scoreName == "Score:") { //calculates number of matches played } else { goalCheck = scoreName.substr(1,1); if(goalCheck == "-") { string lGoal, rGoal; lGoal = scoreName.substr(0,1); rGoal = scoreName.substr(2,1); int leftGoal, rightGoal; leftGoal = atoi(lGoal.c_str()); rightGoal = atoi(rGoal.c_str()); if(leftGoal > rightGoal) //if team wins { //some computations } else if(leftGoal < rightGoal) //if team loses { //computations } else if(leftGoal == rightGoal) //if team draws { //computations } else { myset.insert(myset.begin(), scoreName); } } } I'm inserting all names into myset (regardless of wins/loses/draws) in my last else statement. But I only require the names of those matches who won/draw. Those names whose matches lost will not be included in myset. In the test file above, there's only one match that lost (1-2) and I wanted to remove "Ben". How can I do that? I tried to use myset.erase(), but I'm not sure how to get it point to Ben and remove it from myset. Any help is much appreciated. Thanks.

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  • Lots of questions about file I/O (reading/writing message strings)

    - by Nazgulled
    Hi, For this university project I'm doing (for which I've made a couple of posts in the past), which is some sort of social network, it's required the ability for the users to exchange messages. At first, I designed my data structures to hold ALL messages in a linked list, limiting the message size to 256 chars. However, I think my instructors will prefer if I save the messages on disk and read them only when I need them. Of course, they won't say what they prefer, I need to make a choice and justify the best I can why I went that route. One thing to keep in mind is that I only need to save the latest 20 messages from each user, no more. Right now I have an Hash Table that will act as inbox, this will be inside the user profile. This Hash Table will be indexed by name (the user that sent the message). The value for each element will be a data structure holding an array of size_t with 20 elements (20 messages like I said above). The idea is to keep track of the disk file offsets and bytes written. Then, when I need to read a message, I just need to use fseek() and read the necessary bytes. I think this could work nicely... I could use just one single file to hold all messages from all users in the network. I'm saying one single file because a colleague asked an instructor about saving the messages from each user independently which he replied that it might not be the best approach cause the file system has it's limits. That's why I'm thinking of going the single file route. However, this presents a problem... Since I only need to save the latest 20 messages, I need to discard the older ones when I reach this limit. I have no idea how to do this... All I know is about fread() and fwrite() to read/write bytes from/to files. How can I go to a file offset and say "hey, delete the following X bytes"? Even if I could do that, there's another problem... All offsets below that one will be completely different and I would have to process all users mailboxes to fix the problem. Which would be a pain... So, any suggestions to solve my problems? What do you suggest?

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  • C#: Sum of even fibonacci numbers

    - by user300484
    Hello you all! im developping an application that will find the sum of all even terms of the fibonacci sequence. The last term of this sequence is 4,000,000 . There is something wrong in my code but I cannot find the problem since it makes sense to me. Can you please help me? using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { long[] arr = new long [1000000] ; long i= 2; arr[i-2]=1; arr[i-1]=2; long n= arr[i]; long s=0; for (i=2 ; n <= 4000000; i++) { arr[i] = arr[(i - 1)] + arr[(i - 2)]; } for (long f = 0; f <= arr.Length - 1; f++) { if (arr[f] % 2 == 0) s += arr[f]; } Console.Write(s); Console.Read(); } } }

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  • Dijstra shortest path algorithm with edge cost.

    - by Svisstack
    Hello, I have a directed, positive weighted graph. Each edge have a cost of use. I have only A money, i want to calculate shortest paths with dijkstra algorithm, but sum of edges costs on route must be less or equal to A. I want to do this with most smallest Dijstra modification (if I can do it with small modification of Dijkstra). Anyone can help me with this?

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  • Binary Trees in Scheme

    - by Javier
    Consider the following BNF defining trees of numbers. Notice that a tree can either be a leaf, a node-1 with one subtrees, or a node-2 with two subtrees. tree ::= (’leaf number) | (’node-1 tree) | (’node-2 tree tree) a. Write a template for recursive procedures on these trees. b. Define the procedure (leaf-count t) that returns the number of leaves in t > (leaf-count ’(leaf 5)) 1 > (leaf-count ’(node-2 (leaf 25) (leaf 17))) 2 > (leaf-count ’(node-1 (node-2 (leaf 4) (node-2 (leaf 2) (leaf 3))))) 3 Here's what I have so far: ;define what a leaf, node-1, and node-2 is (define leaf list) (define node-1 list) (define node-2 list) ;procedure to decide if a list is a leaf or a node (define (leaf? tree) (number? (car tree))) (define (node? tree) (pair? (car tree))) (define (leaf-count tree) (cond ((null? tree) 0) ((number? tree) 0) ((leaf? tree) 1) (else (+ (leaf-count (car tree)) (leaf-count (cdr tree)))))) It looks like it should run just fine, but when I try to run it using a simple test case like (leaf-count '(leaf 5)) I get the following error message: car: expects argument of type pair; given leaf What does this error message mean? I am defining a leaf as a list. But for some reason, it's not seeing that and gives me that error message.

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  • Using Taylor Series to Avoid Loss of Precision

    - by Zachary
    I'm trying to use Taylor series to develop a numerically sound algorithm for solving a function. I've been at it for quite a while, but haven't had any luck yet. I'm not sure what I'm doing wrong. The function is f(x)=1 + x - sin(x)/ln(1+x) x~0 Also: why does loss of precision even occur in this function? when x is close to zero, sin(x)/ln(1+x) isn't even close to being the same number as x. I don't see where significance is even being lost. In order to solve this, I believe that I will need to use the Taylor expansions for sin(x) and ln(1+x), which are x - x^3/3! + x^5/5! - x^7/7! + ... and x - x^2/2 + x^3/3 - x^4/4 + ... respectfully. I have attempted to use like denominators to combine the x and sin(x)/ln(1+x) components, and even to combine all three, but nothing seems to work out correctly in the end. Any help is appreciated.

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  • This program runs but not correctly; the numbers aren't right.

    - by user320950
    this program runs but not correctly numbers arent right, i read numbers from a file and then when i am using them in the program they are not right.:brief decription of what i am trying to do can someone tell me if something doesnt look right. this is what i have to do: write a program that determines the grade dispersal for 100 students You are to read the exam scores into three arrays, one array for each exam. You must then calculate how many students scored A’s (90 or above), B’s (80 or above), C’s (70 or above), D’s (60 or above), and F’s (less than 60). Do this for each exam and write the distribution to the screen. // basic file operations #include <iostream> #include <fstream> using namespace std; int read_file_in_array(double exam[100][3]); double calculate_total(double exam1[], double exam2[], double exam3[]); // function that calcualates grades to see how many 90,80,70,60 //void display_totals(); double exam[100][3]; int main() { double go,go2,go3; double exam[100][3],exam1[100],exam2[100],exam3[100]; go=read_file_in_array(exam); go2=calculate_total(exam1,exam2,exam3); //go3=display_totals(); cout << go,go2,go3; return 0; } /* int display_totals() { int grade_total; grade_total=calculate_total(exam1,exam2,exam3); return 0; } */ double calculate_total(double exam1[],double exam2[],double exam3[]) { int calc_tot,above90=0, above80=0, above70=0, above60=0,i,j, fail=0; double exam[100][3]; calc_tot=read_file_in_array(exam); for(i=0;i<100;i++) { for (j=0; j<3; j++) { exam1[i]=exam[100][0]; exam2[i]=exam[100][1]; exam3[i]=exam[100][2]; if(exam[i][j] <=90 && exam[i][j] >=100) { above90++; { if(exam[i][j] <=80 && exam[i][j] >=89) { above80++; { if(exam[i][j] <=70 && exam[i][j] >=79) { above70++; { if(exam[i][j] <=60 && exam[i][j] >=69) { above60++; { if(exam[i][j] >=59) { fail++; } } } } } } } } } } } return 0; } int read_file_in_array(double exam[100][3]) { ifstream infile; int exam1[100]; int exam2[100]; int exam3[100]; infile.open("grades.txt");// file containing numbers in 3 columns if(infile.fail()) // checks to see if file opended { cout << "error" << endl; } int num, i=0,j=0; while(!infile.eof()) // reads file to end of line { for(i=0;i<100;i++) // array numbers less than 100 { for(j=0;j<3;j++) // while reading get 1st array or element infile >> exam[i][j]; infile >> exam[i][j]; infile >> exam[i][j]; cout << exam[i][j] << endl; { if (! (infile >> exam[i][j]) ) cout << exam[i][j] << endl; } exam[i][j]=exam1[i]; exam[i][j]=exam2[i]; exam[i][j]=exam3[i]; } infile.close(); } return 0; }

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  • C++ reading and writing and writing files

    - by user320950
    Write a program that processes a list of items purchased with a receipt List in itemlist.txt just items different numbers Prices in pricelist.txt have items and prices in them, different # Make file output file that has receipt Print message saying program ran- have not done If item not in pricelist, report error, count errors display at end Don't know how many items or prices Close file and clear because of running many these files many times This program wont write to the files like so the above is what i have to do #include<iostream>`enter code here` #include<fstream> #include<cstdlib> #include<iomanip> using namespace std; int main() { ifstream in_stream; // reads itemlist.txt ofstream out_stream1; // writes in items.txt ifstream in_stream2; // reads pricelist.txt ofstream out_stream3;// writes in plist.txt ifstream in_stream4;// read recipt.txt ofstream out_stream5;// write display.txt double price=' ',curr_total=0.0; int wrong=0; int itemnum=' '; char next; in_stream.open("ITEMLIST.txt", ios::in); // list of avaliable items out_stream1.open("listWititems.txt", ios::out); // list of avaliable items in_stream2.open("PRICELIST.txt", ios::in); out_stream3.open("listWitdollars.txt", ios::out); in_stream4.open("display.txt", ios::in); out_stream5.open("showitems.txt", ios::out); in_stream.setf(ios::fixed); while(!in_stream.eof()) { in_stream >> itemnum; cin.clear(); cin >> next; } out_stream1.setf(ios::fixed); while (!out_stream1.eof()) { out_stream1 << itemnum; cin.clear(); cin >> next; } in_stream2.setf(ios::fixed); in_stream2.setf(ios::showpoint); in_stream2.precision(2); while (!in_stream2.eof()) // reads file to end of file { while((price== (price*1.00)) && (itemnum == (itemnum*1))) { in_stream2 >> itemnum >> price; itemnum++; price++; curr_total= price++; in_stream2 >> curr_total; cin.clear(); // allows more reading cin >> next; return itemnum, price; } } out_stream3.setf(ios::fixed); out_stream3.setf(ios::showpoint); out_stream3.precision(2); while (!out_stream3.eof()) // reads file to end of file { while((price== (price*1.00)) && (itemnum == (itemnum*1))) { out_stream3 << itemnum << price; itemnum++; price++; curr_total= price++; out_stream3 << curr_total; cin.clear(); // allows more reading cin >> next; return itemnum, price; } } in_stream4.setf(ios::fixed); in_stream4.setf(ios::showpoint); in_stream4.precision(2); while (!in_stream4.eof()) { in_stream4 >> itemnum >> price >> curr_total; cin.clear(); cin >> next; } out_stream5.setf(ios::fixed); out_stream5.setf(ios::showpoint); out_stream5.precision(2); out_stream5 <<setw(5)<< " itemnum " <<setw(5)<<" price "<<setw(5)<<" curr_total " <<endl; // sends items and prices to receipt.txt out_stream5 << setw(5) << itemnum << setw(5) <<price << setw(5)<< curr_total; // sends items and prices to receipt.txt out_stream5 << " You have a total of " << wrong++ << " errors " << endl; in_stream.close(); // closing files. out_stream1.close(); in_stream2.close(); out_stream3.close(); in_stream4.close(); out_stream5.close(); system("pause"); }

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  • algorithm analysis - orders of growth question

    - by cchampion
    I'm studing orders of growth "big oh", "big omega", and "big theta". Since I can't type the little symbols for these I will denote them as follows: ORDER = big oh OMEGA = big omega THETA = big theta For example I'll say n = ORDER(n^2) to mean that the function n is in the order of n^2 (n grows at most as fast n^2). Ok for the most part I understand these: n = ORDER(n^2) //n grows at most as fast as n^2 n^2 = OMEGA(n) //n^2 grows atleast as fast as n 8n^2 + 1000 = THETA(n^2) //same order of growth Ok here comes the example that confuses me: what is n(n+1) vs n^2 I realize that n(n+1) = n^2 + n; I would say it has the same order of growth as n^2; therefore I would say n(n+1) = THETA(n^2) but my question is, would it also be correct to say: n(n+1) = ORDER(n^2) please help because this is confusing to me. thanks.

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  • Casting interfaces in java

    - by owca
    I had two separate interfaces, one 'MultiLingual' for choosing language of text to return, and second 'Justification' to justify returned text. Now I need to join them, but I'm stuck at 'java.lang.ClassCastException' error. Class Book is not important here. Data.length and FormattedInt.width correspond to the width of the line. The code : public interface MultiLingual { static int ENG = 0; static int PL = 1; String get(int lang); int setLength(int length); } class Book implements MultiLingual { private String title; private String publisher; private String author; private int jezyk; public Book(String t, String a, String p, int y){ this(t, a, p, y, 1); } public Book(String t, String a, String p, int y, int lang){ title = t; author = a; publisher = p; jezyk = lang; } public String get(int lang){ jezyk = lang; return this.toString(); } public int setLength(int i){ return 0; } @Override public String toString(){ String dane; if (jezyk == ENG){ dane = "Author: "+this.author+"\n"+ "Title: "+this.title+"\n"+ "Publisher: "+this.publisher+"\n"; } else { dane = "Autor: "+this.author+"\n"+ "Tytul: "+this.title+"\n"+ "Wydawca: "+this.publisher+"\n"; } return dane; } } class Data implements MultiLingual { private int day; private int month; private int year; private int jezyk; private int length; public Data(int d, int m, int y){ this(d, m, y, 1); } public Data(int d, int m, int y, int lang){ day = d; month = m; year = y; jezyk = lang; } public String get(int lang){ jezyk = lang; return this.toString(); } public int setLength(int i){ length = i; return length; } @Override public String toString(){ String dane=""; String miesiac=""; String dzien=""; switch(month){ case 1: miesiac="January"; case 2: miesiac="February"; case 3: miesiac="March"; case 4: miesiac="April"; case 5: miesiac="May"; case 6: miesiac="June"; case 7: miesiac="July"; case 8: miesiac="August"; case 9: miesiac="September"; case 10: miesiac="October"; case 11: miesiac="November"; case 12: miesiac="December"; } if(day==1){ dzien="st"; } if(day==2 || day==22){ dzien="nd"; } if(day==3 || day==23){ dzien="rd"; } else{ dzien="th"; } if(jezyk==ENG){ dane =this.day+dzien+" of "+miesiac+" "+this.year; } else{ dane = this.day+"."+this.month+"."+this.year; } return dane; } } interface Justification { static int RIGHT=1; static int LEFT=2; static int CENTER=3; String justify(int just); } class FormattedInt implements Justification { private int liczba; private int width; private int wyrownanie; public FormattedInt(int s, int i){ liczba = s; width = i; wyrownanie = 2; } public String justify(int just){ wyrownanie = just; String wynik=""; String tekst = Integer.toString(liczba); int len = tekst.length(); int space_left=width - len; int space_right = space_left; int space_center_left = (width - len)/2; int space_center_right = width - len - space_center_left -1; String puste=""; if(wyrownanie == LEFT){ for(int i=0; i<space_right; i++){ puste = puste + " "; } wynik = tekst+puste; } else if(wyrownanie == RIGHT){ for(int i=0; i<space_left; i++){ puste = puste + " "; } wynik = puste+tekst; } else if(wyrownanie == CENTER){ for(int i=0; i<space_center_left; i++){ puste = puste + " "; } wynik = puste + tekst; puste = " "; for(int i=0; i< space_center_right; i++){ puste = puste + " "; } wynik = wynik + puste; } return wynik; } } And the test code that shows this casting "(Justification)gatecrasher[1]" which gives me errors : MultiLingual gatecrasher[]={ new Data(3,12,1998), new Data(10,6,1924,MultiLingual.ENG), new Book("Sekret","Rhonda Byrne", "Nowa proza",2007), new Book("Tuesdays with Morrie", "Mitch Albom", "Time Warner Books",2003, MultiLingual.ENG), }; gatecrasher[0].setLength(25); gatecrasher[1].setLength(25); Justification[] t={ new FormattedInt(345,25), (Justification)gatecrasher[1], (Justification)gatecrasher[0], new FormattedInt(-7,25) }; System.out.println(" 10 20 30"); System.out.println("123456789 123456789 123456789"); for(int i=0;i < t.length;i++) System.out.println(t[i].justify(Justification.RIGHT)+"<----\n");

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  • for my project I have problem in report

    - by pink rose
    public stack(int size) { this.size=size; Array = new int[size]; } public void push(int j) { if (top < size) { Array[++top] = j; } } public int pop() { return Array[top--]; } public int top() { return Array[top]; } public boolean isEmpty() { return (top == -1); } } import javax.swing.JOptionPane; public class menu { private static stack s; private static int numbers[]; public static void main(String args[]) { start(); } public static void start() { int i = Integer.parseInt(JOptionPane.showInputDialog("1. size of array\n2. data entry\n3. display content\n4. exit")); switch (i) { case 1: setSize(); break; case 2: addElement(); break; case 3: showElements(); break; case 4: exit(); } } public static void setSize() { int size = Integer.parseInt(JOptionPane.showInputDialog("Please Enter The Size")); s = new stack(size); numbers = new int[10]; start(); } public static void addElement() { for(int x=0;x<s.size;x++) { int e = Integer.parseInt(JOptionPane.showInputDialog("Please Enter The Element")); numbers[e]++; s.push(e); } start(); } public static void showElements() { String result = ""; int temp; while (!s.isEmpty()) { temp = s.pop(); if (numbers[temp] == 1) { result = temp+result; } } JOptionPane.showMessageDialog(null, result); start(); } public static void exit() { System.exit(0); } } This my project I was finished but I have problem in question in my report Conclusion. It should summarize the state of your project and indicate which part of your project is working and which part is not working or with limitations. You may also provide your suggestions and comments to this project what I can answer I didn't have any idea

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  • user input question

    - by jdbeverly87
    My program checks to test if a word or phrase is a palindrome (reads the same both backward and forward, ex "racecar"). The issue I'm having is after someone enters in "racecar" getting it to actually test. In the below code, I marked where if I type in "racecar" and run, Java returns the correct answer so I know I'm right there. But what am I missing as far as entering it into the console. I think my code is ok, but maybe I have something missing or in the wrong spot? Not really looking for a new answer unless I'm missing something, but if possible perhaps a pro at this moving my code to the correct area bc I'm stuck! `import java.util.*; public class Palindrome { public static void main(String[] args) { String myInput; Scanner in = new Scanner(System.in); System.out.println("Enter a word or phrase: "); **//this asks user for input but doesn't check for whether or not it is a palindrome** myInput = in.nextLine(); in.close(); System.out.println("You entered: " + myInput); } { String s="racecar"; **//I can type a word here and it works but I need** int i; **//I need it to work where I ask for the input** int n=s.length(); String str=""; for(i=n-1;i>=0;i--) str=str+s.charAt(i); if(str.equals(s)) System.out.println(s+ " is a palindrome"); else System.out.println(s+ " is not a palindrome"); } }` I'm new at programming so I'm hoping what I got is ok. I know the palindrome test works I'm just needing helping having it test thru where I'm entering it into the console. Thanks

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  • perl one liner alternative to this bash "chain"?

    - by Michael Mao
    Hello everyone: I am trying to comprehend Perl following the way describe in the book "Minimal Perl". I've uploaded all source txt files onto my own server : results folder I got the output from using several bash commands in a "chain" like this: cat run*.txt | grep '^Bank[[:space:]]Balance'| cut -d ':' -f2 | grep -E '\$[0-9]+' I know this is far from the most concise and efficient, but at least it works... As our uni subject now moves onto the Perl part, I'd like to know if there is a way to get the same results in one line? I am trying something like the following code but stuck in the middle: Chenxi Mao@chenxi-a6b123bb /cygdrive/c/eMarket/output $ perl -wlne 'print; if $n=~/^Bank Balance/' syntax error at -e line 1, near "if $n" Execution of -e aborted due to compilation errors.

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  • Implementing Naïve Bayes algorithm in Java - Need some guidance

    - by techventure
    hello stackflow people As a School assignment i'm required to implement Naïve Bayes algorithm which i am intending to do in Java. In trying to understand how its done, i've read the book "Data Mining - Practical Machine Learning Tools and Techniques" which has a section on this topic but am still unsure on some primary points that are blocking my progress. Since i'm seeking guidance not solution in here, i'll tell you guys what i thinking in my head, what i think is the correct approach and in return ask for correction/guidance which will very much be appreciated. please note that i am an absolute beginner on Naïve Bayes algorithm, Data mining and in general programming so you might see stupid comments/calculations below: The training data set i'm given has 4 attributes/features that are numeric and normalized(in range[0 1]) using Weka (no missing values)and one nominal class(yes/no) 1) The data coming from a csv file is numeric HENCE * Given the attributes are numeric i use PDF (probability density function) formula. + To calculate the PDF in java i first separate the attributes based on whether they're in class yes or class no and hold them into different array (array class yes and array class no) + Then calculate the mean(sum of the values in row / number of values in that row) and standard divination for each of the 4 attributes (columns) of each class + Now to find PDF of a given value(n) i do (n-mean)^2/(2*SD^2), + Then to find P( yes | E) and P( no | E) i multiply the PDF value of all 4 given attributes and compare which is larger, which indicates the class it belongs to In temrs of Java, i'm using ArrayList of ArrayList and Double to store the attribute values. lastly i'm unsure how to to get new data? Should i ask for input file (like csv) or command prompt and ask for 4 values? I'll stop here for now (do have more questions) but I'm worried this won't get any responses given how long its got. I will really appreciate for those that give their time reading my problems and comment.

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  • easiest to code algorithm for rubik's cube

    - by kokokok
    edit : I should rephrase this,what would be a relatively easy algorithm to code in java for solving a rubik's cube. Efficiency is also important but a secondary consideration. orig : what is the easiest algorithm to code for solving a rubik's cube? it could be the least efficient but I am looking for something easy to code right now

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  • Proving f (f bool) = bool

    - by Marcus Whybrow
    How can I in coq, prove that a function f that accepts a bool true|false and returns a bool true|false (shown below), when applied twice to a single bool true|false would always return that same value true|false: (f:bool -> bool) For example the function f can only do 4 things, lets call the input of the function b: Always return true Always return false Return b (i.e. returns true if b is true vice versa) Return not b (i.e. returns false if b is true and vice vera) So if the function always returns true: f (f bool) = f true = true and if the function always return false we would get: f (f bool) = f false = false For the other cases lets assum the function returns not b f (f true) = f false = true f (f false) = f true = false In both possible input cases, we we always end up with with the original input. The same holds if we assume the function returns b. So how would you prove this in coq? Goal forall (f:bool -> bool) (b:bool), f (f b) = f b.

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  • Word Anagram Hashing Algorithm?

    - by Ahmed Said
    Given set of words, we need to find the anagram words and display each category alone using the best algorithm input: man car kile arc none like output: man car arc kile like none the best solution I am developing now is based on a hashtable, but I am thinking about equation to convert anagram word into integer value exmaple: man = 'm'+'a'+'n' but this will not give unique values any suggestions?

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  • (1 2 3 . #<void>)- heapsort

    - by superguay
    Hello everybody: I tried to implement a "pairing heap" with all the regular operations (merge, delete-min etc.), then I've been requested to write a function that would sort a list using my newly constructed heap implementation. Unfortunately it seems that someting goes wrong... Here's the relevant code: (define (heap-merge h1 h2) (cond ((heap-empty? h1) h2) ((heap-empty? h2) h1) (else (let ((min1 (heap-get-min h1)) (min2 (heap-get-min h2))) (if ((heap-get-less h1) min1 min2) (make-pairing-heap (heap-get-less h1) min1 (cons h2 (heap-get-subheaps h1))) (make-pairing-heap (heap-get-less h1) min2 (cons h1 (heap-get-subheaps h2)))))))) (define (heap-insert element h) (heap-merge (make-pairing-heap (heap-get-less h) element '()) h)) (define (heap-delete-min h) (define (merge-in-pairs less? subheaps) (cond ((null? subheaps) (make-heap less?)) ((null? (cdr subheaps)) (car subheaps)) (else (heap-merge (heap-merge (car subheaps) (cadr subheaps)) (merge-in-pairs less? (cddr subheaps)))))) (if (heap-empty? h) (error "expected pairing-heap for first argument, got an empty heap ") (merge-in-pairs (heap-get-less h) (heap-get-subheaps h)))) (define (heapsort l less?) (let aux ((h (accumulate heap-insert (make-heap less?) l))) (if (not (heap-empty? h)) (cons (heap-get-min h) (aux (heap-delete-min h)))))) And these are some selectors that may help you to understand the code: (define (make-pairing-heap less? min subheaps) (cons less? (cons min subheaps))) (define (make-heap less?) (cons less? '())) (define (heap-get-less h) (car h)) (define (heap-empty? h) (if (null? (cdr h)) #t #f)) Now lets get to the problem: When i run 'heapsort' it returns the sorted list with "void", as you can see: (heapsort (list 1 2 3) <) (1 2 3 . #)..HOW CAN I FIX IT? Regards, Superguay

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  • How to change Matlab program for solving equation with finite element method?

    - by DSblizzard
    I don't know is this question more related to mathematics or programming and I'm absolute newbie in Matlab. Program FEM_50 applies the finite element method to Laplace's equation -Uxx(x, y) - Uyy(x, y) = F(x, y) in Omega. How to change it to apply FEM to equation -Uxx(x, y) - Uyy(x, y) + U(x, y) = F(x, y)? At this page: http://sc.fsu.edu/~burkardt/m_src/fem_50/fem_50.html additional code files in case you need them. function fem_50 ( ) %% FEM_50 applies the finite element method to Laplace's equation. % % Discussion: % % FEM_50 is a set of MATLAB routines to apply the finite % element method to solving Laplace's equation in an arbitrary % region, using about 50 lines of MATLAB code. % % FEM_50 is partly a demonstration, to show how little it % takes to implement the finite element method (at least using % every possible MATLAB shortcut.) The user supplies datafiles % that specify the geometry of the region and its arrangement % into triangular and quadrilateral elements, and the location % and type of the boundary conditions, which can be any mixture % of Neumann and Dirichlet. % % The unknown state variable U(x,y) is assumed to satisfy % Laplace's equation: % -Uxx(x,y) - Uyy(x,y) = F(x,y) in Omega % with Dirichlet boundary conditions % U(x,y) = U_D(x,y) on Gamma_D % and Neumann boundary conditions on the outward normal derivative: % Un(x,y) = G(x,y) on Gamma_N % If Gamma designates the boundary of the region Omega, % then we presume that % Gamma = Gamma_D + Gamma_N % but the user is free to determine which boundary conditions to % apply. Note, however, that the problem will generally be singular % unless at least one Dirichlet boundary condition is specified. % % The code uses piecewise linear basis functions for triangular elements, % and piecewise isoparametric bilinear basis functions for quadrilateral % elements. % % The user is required to supply a number of data files and MATLAB % functions that specify the location of nodes, the grouping of nodes % into elements, the location and value of boundary conditions, and % the right hand side function in Laplace's equation. Note that the % fact that the geometry is completely up to the user means that % just about any two dimensional region can be handled, with arbitrary % shape, including holes and islands. % clear % % Read the nodal coordinate data file. % load coordinates.dat; % % Read the triangular element data file. % load elements3.dat; % % Read the quadrilateral element data file. % load elements4.dat; % % Read the Neumann boundary condition data file. % I THINK the purpose of the EVAL command is to create an empty NEUMANN array % if no Neumann file is found. % eval ( 'load neumann.dat;', 'neumann=[];' ); % % Read the Dirichlet boundary condition data file. % load dirichlet.dat; A = sparse ( size(coordinates,1), size(coordinates,1) ); b = sparse ( size(coordinates,1), 1 ); % % Assembly. % for j = 1 : size(elements3,1) A(elements3(j,:),elements3(j,:)) = A(elements3(j,:),elements3(j,:)) ... + stima3(coordinates(elements3(j,:),:)); end for j = 1 : size(elements4,1) A(elements4(j,:),elements4(j,:)) = A(elements4(j,:),elements4(j,:)) ... + stima4(coordinates(elements4(j,:),:)); end % % Volume Forces. % for j = 1 : size(elements3,1) b(elements3(j,:)) = b(elements3(j,:)) ... + det( [1,1,1; coordinates(elements3(j,:),:)'] ) * ... f(sum(coordinates(elements3(j,:),:))/3)/6; end for j = 1 : size(elements4,1) b(elements4(j,:)) = b(elements4(j,:)) ... + det([1,1,1; coordinates(elements4(j,1:3),:)'] ) * ... f(sum(coordinates(elements4(j,:),:))/4)/4; end % % Neumann conditions. % if ( ~isempty(neumann) ) for j = 1 : size(neumann,1) b(neumann(j,:)) = b(neumann(j,:)) + ... norm(coordinates(neumann(j,1),:) - coordinates(neumann(j,2),:)) * ... g(sum(coordinates(neumann(j,:),:))/2)/2; end end % % Determine which nodes are associated with Dirichlet conditions. % Assign the corresponding entries of U, and adjust the right hand side. % u = sparse ( size(coordinates,1), 1 ); BoundNodes = unique ( dirichlet ); u(BoundNodes) = u_d ( coordinates(BoundNodes,:) ); b = b - A * u; % % Compute the solution by solving A * U = B for the remaining unknown values of U. % FreeNodes = setdiff ( 1:size(coordinates,1), BoundNodes ); u(FreeNodes) = A(FreeNodes,FreeNodes) \ b(FreeNodes); % % Graphic representation. % show ( elements3, elements4, coordinates, full ( u ) ); return end

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  • java palindrome help

    - by jdbeverly87
    I'm creating a program that checks if a word or phrase is a palindrome. I have the actual "palindrome tester" figured out. What I'm stuck with is where and what to place in my code to have the console read out "Enter palindrome..." and then text. I've tried with IO but it doesnt work out right. Also, how do I create a loop to keep going? This code only allows one at a time `public class Palindrome { public static void main(String args[]) { String s=""; int i; int n=s.length(); String str=""; for(i=n-1;i>=0;i--) str=str+s.charAt(i); if(str.equals(s)) System.out.println(s+ " is a palindrome"); else System.out.println(s+ " is not a palindrome"); } }

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  • a pdf reader - please guide - a step by step guidence - reference to guidence-

    - by user287745
    have to make a hardware project using micro controller, memory, screens, etc. is it possible to make an independent .dpf / documents reader, which is capable of running on battery power.? please note dont want to use any technology which needs licensing all free wares readers etc and programing say assembly and c or flash or any. please help, have submitted proposal of pdf reader project (independent hardware), many say its impossible, wht should i do??

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  • What's wrong with this conditional?

    - by David
    I am trying to make a method that tests to see if 3 lengths can make a triangle. I think i'm making some kind of syntax error but i can't figure out what it is. Here is the relevant bit of code: (its in java) public static void trya (int a, int b, int c) { if (c>(a+b)) { System.out.println ("yes") ; } else { if (b>(a+c)) { System.out.println ("yes") ; } } else { if (a>(b+c)) { System.out.println ("yes") ; } } else { System.out.println ("no") ; } } this is the error message i get: tryangle.java:17: 'else' without 'if' else ^

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  • Need help with basic ASM

    - by Malfist
    Hello, I'm trying to convert some c code to assmebly, and I need some help. char encode(char plain){ __asm{ mov eax, plain add eax, 2 ret } //C code /* char code; code = plain+2; return code;*/ } First problem is that visual studio complains that the register size doesn't match, i.e. eax is too small/large for char. I was under the impression that they were both DWORDs. Also, if I leave the variable in eax, and ret in assembly, it'll actually return that variable, right?

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