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• Doing a count over a filter query efficiently in django

  - by apple_pie

  Hello, Django newbie here, I need to do a count over a certain filter in a django model. If I do it like so: my_model.objects.filter(...).count() I'm guessing it does the SQL query that retrieves all the rows and only afterwards does the count. To my knowledge it's much more efficient to do the count without retrieving those rows like so "SELECT COUNT(*) FROM ...". Is there a way to do so in django?

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• Do image backlinks count as backlinks?

  - by sam

  If i have lots of images appearing tumblr blogs, the sort of tumblogs with very little text just reams and reams of images for people to browse through (example - http://whereisthecool.com/). If my image is embeded in their site like this : <a href="http://mysite.com" target="blank"> <img src="cutecatblog.com/cat.jpg" alt="cute cat"/> </a> so the image was a link back to my site. Although there is no anchor text to speak of does google take into account the alt text of the image ? Would this still count in googles eyes as a backlink ?

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• USB file transfer preparing to copy, but file count climbs indefinitely

  - by Alex

  I have downloaded Ubuntu 12.04 to back up my Windows machine that won't boot and am running Ubuntu from the CD. I copied and pasted a volume of about 160GB to my external HDD. The transfer has been stuck in the "preparing to copy" stage for several hours and is displaying a file/GB count about twice as high as the volume of data actually being copied! The number is now larger than the entire partition that's being copied from! However I know it's doing something because occasionally it pops up with a minor I/O error on this or that file which I then have to click through. I've not had this problem before so I can only assume it's a Linux/Ubuntu thing. More importantly what I want to know is is there any other way to copy it across that will actually work?

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• Number of Classes in a Namespace - Code Smell?

  - by Tim Claason

  I have a C# library that's used by several executables. There's only a couple namespaces in the library, and I just noticed that one of the namespaces has quite a few classes in it. I've always avoided having too many classes in a single namespace because of categorization, and because subconsciously, I think it looks "prettier" to have a deeper hierarchy of namespaces. My question is: does anyone else consider it a "code smell" when a namespace has many classes - even if the classes relate to each other? Would you put in a lot of effort to find nuances in the classes that allows for subcategorization?

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• How to get multiple counts with one SQL query?

  - by Crobzilla

  I am wondering how to write this query. I know this actual syntax is bogus, but it will help you understand what I am wanting. I need it in this format, because it is part of a much bigger query. SELECT distributor_id, COUNT(*) AS TOTAL, COUNT(*) WHERE level = 'exec', COUNT(*) WHERE level = 'personal' I need this all returned in one query. Also, it need to be in one row, so the following won't work: 'SELECT distributor_id, COUNT(*) GROUP BY distributor_id'

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• mysql thread count

  - by Ryan M.

  We have a web application that uses apache and mysql. Generally (according to Munin) our MySQL thread count sits between 2 and 4 at all times. The other day, our server almost came to a halt. HTTP requests were slow or wouldn't go through at all, SSH would work, but would take 30+ seconds to register keystrokes, etc.. So we pull up Munin and the only thing that's out of normal boundaries is the Mysql thread count. CPU usage was under 1%, load was under 1.0, plenty of available RAM. As mentioned before, the thread count floats around 2 to 4. At the time of our slow downs it had spiked to 14. So I start poking around the Internet and I see that in most cases, you'll start to see a higher thread count when you start running into slow queries. If I understand it correctly, the request comes in that takes a while to process, in the mean time other requests are coming in, so a new thread will be created to work on the request (yes?). But at the time of the slow down, we had 0 slow queries. My question is: What else can cause mysql to create additional threads. And would this sudden spike in threads possibly cause the server to slow down? To fix the issue, we restarted apache and everything went back to it's beautiful, normal self. Considering the the Server Vitals (CPU, RAM, Network, etc) were all ideal, and the thread count was the only thing out of place, this seems like the most logical thing to pursue as the possible cause. If it matters, we're on Mysql 5.1.40. Server is FreeBSD 7.2 and the server in question is inside a jail.

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• Count query with 3 coloumn iin SQL

  - by asher baig

  I have one database Library with table named called Medien. Having multiple columns named as Fname,Mname,Lname and ISBN. I want to calculate database records with ISBN and without ISBN? I have execute following command Select COUNT(ISBN) as Verf1 FROM library.MEDIEN where verf1 = isbn; Select COUNT(ISBN) as Verf2 FROM library.MEDIEN where verf2 = isbn; Select COUNT(ISBN) as Verf3 FROM library.MEDIEN where verf3 = isbn; Select COUNT(ISBN) as Ntverf1 FROM library.MEDIENwhere verf1 != isbn; Select COUNT(ISBN) as Ntverf2 FROM library.MEDIENwhere verf2 != isbn; Select COUNT(ISBN) as Ntverf3 FROM library.MEDIENwhere verf3 != isbn; I am not sure i execute correct command or not. Because some ISBN records have Fname,Mname or Fname,Lname or Mname,Lname or Fname , Lname,Mname only respectively. Please kindly help me solving this query

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• sql query question / count

  - by scheibenkleister

  Hi, I have houses that belongs to streets. A user can buy several houses. How do I find out, if the user owns an entire street? street table with columns (id/name) house table with columns (id/street_id [foreign key] owner table with columns (id/house_id/user_id) [join table with foreign keys] So far, I'm using count which returns the result: select count(*), street_id from owner left join house on owner.house_id = house.id group by street_id where user_id = 1 count(*) | street_id 3 | 1 2 | 2 A more general count: select count(*) from house group by street_id returns: count(*) | street_id 3 | 1 3 | 2 How can I find out, that user 1 owns the entire street 1 but not street 2? Thanks.

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• MySQL: Count occurrences of known (or enumerated) distinct values

  - by Eilidh

  After looking at how to count the occurrences of distinct values in a field, I am wondering how to count the occurrences of each distinct value if the distinct values are known (or enumerated). For example, if I have a simple table - TrafficLight Colour ------------ ------ 1 Red 2 Amber 3 Red 4 Red 5 Green 6 Green where one column (in this case Colour) has known (or enumerated) distinct values, how could I return the count for each colour as a separate value, rather than as an array, as in the linked example. To return an array with a count of each colour (using the same method as in the linked example), the query would be something like SELECT Colour COUNT(*) AS ColourCount FROM TrafficLights GROUP BY Colour, and return an array - Colour ColourCount ------ ----------- Red 3 Amber 1 Green 2 What I would like to do is to return the count for each Colour AS a separate total (e.g. RedCount). How can I do this?

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• Mysql query: count and distinct

  - by Azevedo

  I have this hypotetical MySQL table: TABLE cars: (year, color, brand) How do I count # of cars grouped by brand and year? I mean, how can I get to know how many colors are there grouped by brand like: brand "GM": total # of colors: 8. brand "GM": total # of years (grouped together): 14 (meaning there are count of 14 different years). brand "TOYOTA": total # of colors: 3. brand "TOYOTA": total # of years (grouped together): 10 (meaning there are count of 14 different years) I tried playing some queries with COUNT, DISTINCT, GROUP BY but I can't get to it. Actually I'm trying to get the 2 queries... +-------+---------------+ | brand | count(colors) | +-------+---------------+ +-------+--------------+ | brand | count(years) | +-------+--------------+ thanks a lot!

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• numberOfSectionsInTable isn't called when [arr count] is returned

  - by user315471

  When I try returning the count of my newsItems array it breaks my application. I used NSLog to find out what the value of the newsItems count was when I returned 1. Here is from NSLog 2010-04-13 07:48:40.656 RSS Feed[453:207] Values of num items 31 2010-04-13 07:48:40.656 RSS Feed[453:207] Number of items 31 Does anyone know why returning [newsItems count] would cause my application to break? - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { NSLog(@"Values of num items %d",[newsItems count]); NSInteger *length = (NSInteger *)[newsItems count]; NSLog(@"Number of items %d",length); return 1; //return [newsItems count]; //This keeps breaking it for some reason }

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• MDX using EXISTING, AGGREGATE, CROSSJOIN and WHERE

  - by James Rogers

  It is a well-published approach to using the EXISTING function to decode AGGREGATE members and nested sub-query filters.  Mosha wrote a good blog on it here and a more recent one here.  The use of EXISTING in these scenarios is very useful and sometimes the only option when dealing with multi-select filters.  However, there are some limitations I have run across when using the EXISTING function against an AGGREGATE member:   The AGGREGATE member must be assigned to the Dimension.Hierarchy being detected by the EXISTING function in the calculated measure. The AGGREGATE member cannot contain a crossjoin from any other dimension or hierarchy or EXISTING will not be able to detect the members in the AGGREGATE member.   Take the following query (from Adventure Works DW 2008):   With   member [Week Count] as 'count(existing([Date].[Fiscal Weeks].[Fiscal Week].members))'    member [Date].[Fiscal Weeks].[CM] as 'AGGREGATE({[Date].[Fiscal Weeks].[Fiscal Week].&[47]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[48]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[49]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[50]&[2004]})'   select   {[Week Count]} on columns from   [Adventure Works]     where   [Date].[Fiscal Weeks].[CM]   Here we are attempting to count the existing fiscal weeks in slicer.  This is useful to get a per-week average for another member. Many applications generate queries in this manner (such as Oracle OBIEE).  This query returns the correct result of (4) weeks. Now let's put a twist in it.  What if the querying application submits the query in the following manner:   With   member [Week Count] as 'count(existing([Date].[Fiscal Weeks].[Fiscal Week].members))'    member [Customer].[Customer Geography].[CM] as 'AGGREGATE({[Date].[Fiscal Weeks].[Fiscal Week].&[47]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[48]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[49]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[50]&[2004]})'   select   {[Week Count]} on columns from   [Adventure Works]     where   [Customer].[Customer Geography].[CM]   Here we are attempting to count the existing fiscal weeks in slicer.  However, the AGGREGATE member is built on a different dimension (in name) than the one EXISTING is trying to detect.  In this case the query returns (174) which is the total number of [Date].[Fiscal Weeks].[Fiscal Week].members defined in the dimension.   Now another twist, the AGGREGATE member will be named appropriately and contain the hierarchy we are trying to detect with EXISTING but it will be cross-joined with another hierarchy:   With   member [Week Count] as 'count(existing([Date].[Fiscal Weeks].[Fiscal Week].members))'    member [Date].[Fiscal Weeks].[CM] as 'AGGREGATE({[Date].[Fiscal Weeks].[Fiscal Week].&[47]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[48]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[49]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[50]&[2004]}*    {[Customer].[Customer Geography].[Country].&[Australia],[Customer].[Customer Geography].[Country].&[United States]})'  select   {[Week Count]} on columns from   [Adventure Works]    where   [Date].[Fiscal Weeks].[CM]   Once again, we are attempting to count the existing fiscal weeks in slicer.  Again, in this case the query returns (174) which is the total number of [Date].[Fiscal Weeks].[Fiscal Week].members defined in the dimension. However, in 2008 R2 this query returns the correct result of 4 and additionally , the following will return the count of existing countries as well (2):   With   member [Week Count] as 'count(existing([Date].[Fiscal Weeks].[Fiscal Week].members))'   member [Country Count] as 'count(existing([Customer].[Customer Geography].[Country].members))'  member [Date].[Fiscal Weeks].[CM] as 'AGGREGATE({[Date].[Fiscal Weeks].[Fiscal Week].&[47]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[48]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[49]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[50]&[2004]}*    {[Customer].[Customer Geography].[Country].&[Australia],[Customer].[Customer Geography].[Country].&[United States]})'  select   {[Week Count]} on columns from   [Adventure Works]    where   [Date].[Fiscal Weeks].[CM]   2008 R2 seems to work as long as the AGGREGATE member is on at least one of the hierarchies attempting to be detected (i.e. [Date].[Fiscal Weeks] or [Customer].[Customer Geography]). If not, it seems that the engine cannot find a "point of entry" into the aggregate member and ignores it for calculated members.   One way around this would be to put the sets from the AGGREGATE member explicitly in the WHERE clause (slicer).  I realize this is only supported in SSAS 2005 and 2008.  However, after talking with Chris Webb (his blog is here and I highly recommend following his efforts and musings) it is a far more efficient way to filter/slice a query:   With   member [Week Count] as 'count(existing([Date].[Fiscal Weeks].[Fiscal Week].members))'    select   {[Week Count]} on columns from   [Adventure Works]    where   ({[Date].[Fiscal Weeks].[Fiscal Week].&[47]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[48]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[49]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[50]&[2004]}   ,{[Customer].[Customer Geography].[Country].&[Australia],[Customer].[Customer Geography].[Country].&[United States]})   This query returns the correct result of (4) weeks.  Additionally, we can count the cross-join members of the two hierarchies in the slicer:   With   member [Week Count] as 'count(existing([Date].[Fiscal Weeks].[Fiscal Week].members)*existing([Customer].[Customer Geography].[Country].members))'    select   {[Week Count]} on columns from   [Adventure Works]    where   ({[Date].[Fiscal Weeks].[Fiscal Week].&[47]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[48]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[49]&[2004],[Date].[Fiscal Weeks].[Fiscal Week].&[50]&[2004]}   ,{[Customer].[Customer Geography].[Country].&[Australia],[Customer].[Customer Geography].[Country].&[United States]})   We get the correct number of (8) here.

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• Left Join only returning one row

  - by Adam

  I am trying to join two tables. I would like all the columns from the product_category table (there are a total of 6 now) and count the number of products, CatCount, that are in each category from the products_has_product_category table. My query result is 1 row with the first category and a total count of 68, when I am looking for 6 rows with each individual category's count. <?php $result = mysql_query(" SELECT a.*, COUNT(b.category_id) AS CatCount FROM `product_category` a LEFT JOIN `products_has_product_category` b ON a.product_category_id = b.category_id "); while($row = mysql_fetch_array($result)) { echo ' <li class="ui-shadow" data-count-theme="d"> <a href="' . $row['product_category_ref_page'] . '.php" data-icon="arrow-r" data-iconpos="right">' . $row['product_category_name'] . '</a><span class="ui-li-count">' . $row['CatCount'] . '</span></li>'; } ?> I have been working on this for a couple of hours and would really appreciate any help on what I am doing wrong.

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• Checking for empty arrays: count vs empty

  - by Dan McG

  This question on 'How to tell if a PHP array is empty' had me thinking of this question Is there a reason that count should be used instead of empty when determining if an array is empty or not? My personal thought would be if the 2 are equivalent for the case of empty arrays you should use empty because it gives a boolean answer to a boolean question. From the question linked above, it seems that count($var) == 0 is the popular method. To me, while technically correct, makes no sense. E.g. Q: $var, are you empty? A: 7. Hmmm... Is there a reason I should use count == 0 instead or just a matter of personal taste? As pointed out by others in comments for a now deleted answer, count will have performance impacts for large arrays because it will have to count all elements, whereas empty can stop as soon as it knows it isn't empty. So, if they give the same results in this case, but count is potentially inefficient, why would we ever use count($var) == 0?

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• 2D Histogram in R: Converting from Count to Frequency within a Column

  - by Jac

  Would appreciate help with generating a 2D histogram of frequencies, where frequencies are calculated within a column. My main issue: converting from counts to column based frequency. Here's my starting code: # expected packages library(ggplot2) library(plyr) # generate example data corresponding to expected data input x_data = sample(101:200,10000, replace = TRUE) y_data = sample(1:100,10000, replace = TRUE) my_set = data.frame(x_data,y_data) # define x and y interval cut points x_seq = seq(100,200,10) y_seq = seq(0,100,10) # label samples as belonging within x and y intervals my_set$x_interval = cut(my_set$x_data,x_seq) my_set$y_interval = cut(my_set$y_data,y_seq) # determine count for each x,y block xy_df = ddply(my_set, c("x_interval","y_interval"),"nrow") # still need to convert for use with dplyr # convert from count to frequency based on formula: freq = count/sum(count in given x interval) ################ TRYING TO FIGURE OUT ################# # plot results fig_count <- ggplot(xy_df, aes(x = x_interval, y = y_interval)) + geom_tile(aes(fill = nrow)) # count fig_freq <- ggplot(xy_df, aes(x = x_interval, y = y_interval)) + geom_tile(aes(fill = freq)) # frequency I would appreciate any help in how to calculate the frequency within a column. Thanks! jac EDIT: I think the solution will require the following steps 1) Calculate and store overall counts for each x-interval factor 2) Divide the individual bin count by its corresponding x-interval factor count to obtain frequency. Not sure how to carry this out though. .

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• LinqtoSql Pre-compile Query problem with Count() on a group by

  - by Joe Pitz

  Have a LinqtoSql query that I now want to precompile. var unorderedc = from insp in sq.Inspections where insp.TestTimeStamp > dStartTime && insp.TestTimeStamp < dEndTime && insp.Model == "EP" && insp.TestResults != "P" group insp by new { insp.TestResults, insp.FailStep } into grp select new { FailedCount = (grp.Key.TestResults == "F" ? grp.Count() : 0), CancelCount = (grp.Key.TestResults == "C" ? grp.Count() : 0), grp.Key.TestResults, grp.Key.FailStep, PercentFailed = Convert.ToDecimal(1.0 * grp.Count() / tcount * 100) }; I have created this delegate: public static readonly Funct<SQLDataDataContext, int, string, string, DateTime, DateTime, IQueryable<CalcFailedTestResult>> GetInspData = CompiledQuery.Compile((SQLDataDataContext sq, int tcount, string strModel, string strTest, DateTime dStartTime, DateTime dEndTime, IQueryable<CalcFailedTestResult> CalcFailed) => from insp in sq.Inspections where insp.TestTimeStamp > dStartTime && insp.TestTimeStamp < dEndTime && insp.Model == strModel && insp.TestResults != strTest group insp by new { insp.TestResults, insp.FailStep } into grp select new { FailedCount = (grp.Key.TestResults == "F" ? grp.Count() : 0), CancelCount = (grp.Key.TestResults == "C" ? grp.Count() : 0), grp.Key.TestResults, grp.Key.FailStep, PercentFailed = Convert.ToDecimal(1.0 * grp.Count() / tcount * 100) }); The syntax error is on the CompileQuery.Compile() statement It appears to be related to the use of the select new {} syntax. In other pre-compiled queries I have written I have had to just use the select projection by it self. In this case I need to perform the grp.count() and the immediate if logic. I have searched SO and other references but cannot find the answer.

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• Where am I going wrong with the count in Hql

  - by Bipul

  So I only want the count of the results not the results themselves therefore I am using count in hql. So, below is the query (int) Session.CreateQuery("select count(*) from TableName where Lhs=Rhs").UniqueResult(); But it is giving me the error Specified cast is not valid.. So, can any body tell me how to cast the count to int. Any help is very much appreciated.

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• MySQL count statements error - operand should contain 1 column(s)

  - by jason

  I am trying to do multiple counts everyone was working accept the first sub select (list1) I get an error that reads "Operand should contain 1 column(s)" i'm guessing it has something to do with the AND, but i'm not sure how I would fix this one. Select Count(list0.ustatus) AS finished_count, (Select list1.ustatus, Count(*) From listofupdates list1 Where list1.ustarted != '0000-00-00 00:00:00' AND list1.ustatus != 1) AS start_count, (Select Count(list2.udifficulty) From listofupdates list2 Where list2.udifficulty = 2) AS recheck_count, (Select Count(list3.udifficulty) From listofupdates list3 Where list3.udifficulty = 4) AS question_count From listofupdates list0 Where list0.ustatus = 1

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• unmet dependencies and broken count>0 problem

  - by Simon

  I tried installing fbreader, following all the steps, but ended up with unmet dependencies, i also think a file is referenced in two locations at once and hence killing it.. any ideas how I can fix it? i've done alot of research and tried: simon@simon-Studio-1558:~$ sudo apt-get -f install Reading package lists... Done Building dependency tree Reading state information... Done Correcting dependencies... Done The following packages were automatically installed and are no longer required: dkms patch Use 'apt-get autoremove' to remove them. The following extra packages will be installed: libzlcore0.12 The following NEW packages will be installed: libzlcore0.12 0 upgraded, 1 newly installed, 0 to remove and 61 not upgraded. 6 not fully installed or removed. Need to get 0 B/270 kB of archives. After this operation, 811 kB of additional disk space will be used. Do you want to continue [Y/n]? y (Reading database ... 179860 files and directories currently installed.) Unpacking libzlcore0.12 (from .../libzlcore0.12_0.12.10dfsg-4_i386.deb) ... dpkg: error processing /var/cache/apt/archives/libzlcore0.12_0.12.10dfsg-4_i386.deb (--unpack): trying to overwrite '/usr/lib/libzlcore.so.0.12.10', which is also in package libzlcore 0.12.10-1 No apport report written because MaxReports is reached already dpkg-deb: error: subprocess paste was killed by signal (Broken pipe) Errors were encountered while processing: /var/cache/apt/archives/libzlcore0.12_0.12.10dfsg-4_i386.deb E: Sub-process /usr/bin/dpkg returned an error code (1) sorry for the formatting, but it basically isn't liking: dpkg: error processing /var/cache/apt/archives/libzlcore0.12_0.12.10dfsg-4_i386.deb (--unpack): trying to overwrite '/usr/lib/libzlcore.so.0.12.10', which is also in package libzlcore 0.12.10-1 Any ideas? Also I don't care about keeping the program, but the error is stopping sudo apt-get remove fbreader from working too.

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• how to rename files with count

  - by nkint

  i have a directory like this: randomized_quad015.png randomized_quad030.png randomized_quad045.png randomized_quad060.png randomized_quad075.png randomized_quad090.png randomized_quad1005.png randomized_quad1020.png randomized_quad1035.png randomized_quad1050.png randomized_quad105.png randomized_quad1065.png randomized_quad1080.png randomized_quad1095.png randomized_quad1110.png randomized_quad1125.png randomized_quad1140.png and i want to rename the first files adding 0 in front of number, like: randomized_quad0015.png but i don't know how.. some help?

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• Using a PivotTable to Count Items in Access

  - by Sandra

  I have a list of text entries and I want to count how often each entry appears in the list. e.g. Berlin Paris London London Paris Paris Paris The result would be Berlin 1 Paris 4 London 2 This result easy do to achieve with an pivot table in MS Excel (see: Count Items in Excel). My data not in spreadsheet in Excel but in a MS Access database table. So in order to avoid constant switching between Access and Excel and I would like to handle everything in Access (either Access 2007 or 2010). I know there are pivot tables in Access and I know how to display one, but I was unable to find out how to count the number of occurrences. Thank you!

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• When Quality, Security Count

  Static code analysis can make a big difference Static code analysis - Security - Consultants - Business - United States

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• SQL SERVER Find Max Worker Count using DMV 32 Bit and 64 Bit

  During several recent training courses, I found it very interesting that Worker Thread is not quite known to everyone despite the fact that it is a very important feature. At some point in the discussion, one of the attendees mentioned that we can double the Worker Thread if we double the CPU (add the same [...]...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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• Distinct Count of Customers in a SCD Type 2 in #DAX

  - by Marco Russo (SQLBI)

  If you have a Slowly Changing Dimension (SCD) Type 2 for your customer and you want to calculate the number of distinct customers that bought a product, you cannot use the simple formula: Customers := DISTINCTCOUNT( FactTable[Customer Id] ) ) because it would return the number of distinct versions of customers. What you really want to do is to calculate the number of distinct application keys of the customers, that could be a lower number than the number you’ve got with the previous formula. Assuming that a Customer Code column in the Customers dimension contains the application key, you should use the following DAX formula: Customers := COUNTROWS( SUMMARIZE( FactTable, Customers[Customer Code] ) ) Be careful: only the version above is really fast, because it is solved by xVelocity (formerly known as VertiPaq) engine. Other formulas involving nested calculations might be more complex and move computation to the formula engine, resulting in slower query. This is absolutely an interesting pattern and I have to say it’s a killer feature. Try to do the same in Multidimensional…

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• Do first impressions really count?

  - by Matt

  So, i am currently writing something up for a college class. Problem is everything is hypothetical. I need some proof. I believe a first impression on a website is imperative so that people actually use it and in my case, buy your product or services as well. Basically I'm wondering has there been any studies that shows how a better web design will increase revenue for any kind of services? I don't just mean selling products like a T-shirt, but labor services as well. If someone wanted their computer fixed and searched for companies that can do so, will a first impression on the website help them make their decision to use your company? Are there any studies like this? White papers maybe? Thanks!

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