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  • Conditional attribute in XML - most concise solution?

    - by Lech Rzedzicki
    I am tasked with setting up conditional profiling - a method of tagging chunks of XML with an attribute, which will then be used as a conditional value to extract subset of that XML. Have a look at another definition/example: DITA profiling The XML is documents that are equivalent to printed books - i.e. documents that are often looked at by a human, even if indirectly. Therefore I am looking at a few requirements here: 1. keeping the value list brief - so it doesn't affect the readability of the document 2. be able to process with standard XML tools - a space-separated list inside an attribute is still probably fine, but I'd rather not use too much regexp for this 3. be obvious for various users, including 3rd parties, which content goes where 4. Be easy to maintain going forward Therefore one easy solution is: The problem with this: 1. As the list grows the value of the attribute can be a bit verbose 2. One needs to explicitly state every value even if it's a scenario of this vs everything else Therefore I am also looking at other approaches such as: 1. Using + and - modifiers, Apache htaccess style to override the default cascading of profiling - by default all content goes everywhere and if we want to exclude a bit we just say "-kindle". It does require parsing the whole tree, is not supported by editing tools and one needs to regexp the attribute value a bit deeper... 2. Using an intermediate file to define groups of values such as "other" or "non-print", example of this in DITA. It allows concise XML as well as different grouping and values for each document but it does create a certain level of abstraction which may make it a little less obvious for a 3rd party? Altogether, if you received such XML and were tasked to process it, which option you'd rather receive? If you have any experiences like that, even in an unrelated areas such a builds, don't hesitate to comment!

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  • Loop through XML::Simple structure

    - by David
    So I have some xml file like this: <?xml version="1.0" encoding="ISO-8859-1"?> <root result="0" > <settings user="anonymous" > <s n="blabla1" > <v>true</v> </s> <s n="blabla2" > <v>false</v> </s> <s n="blabla3" > <v>true</v> </s> </settings> </root> I want to go through all the settings using the XML Simple. Here's what I have when I print the output with Data::Dumper: $VAR1 = { 'settings' => { 'user' => 'anonymous', 's' => [ { 'n' => 'blabla1', 'v' => 'true' }, { 'n' => 'blabla2', 'v' => 'false' }, { 'n' => 'blabla3', 'v' => 'true' } ] }, 'result' => '0' }; And here's my code $xml = new XML::Simple; $data = $xml->XMLin($file); foreach $s (keys %{ $data->{'settings'}->{'s'} }) { print "TEST: $s $data->{'settings'}->{'s'}->[$s]->{'n'} $data->{'settings'}->{'s'}->[$s]->{'v'}<br>\n"; } And it returns these 2 lines, without looping: TEST: n blabla1 true TEST: v blabla1 true I also tried to do something like this: foreach $s (keys %{ $data->{'settings'}->{'s'} }) { Without any success: Type of arg 1 to keys must be hash (not array dereference) How can I procede? What am I doing wrong? Thanks a lot!

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  • 'Binary XML' for game data?

    - by bluescrn
    I'm working on a level editing tool that saves its data as XML. This is ideal during development, as it's painless to make small changes to the data format, and it works nicely with tree-like data. The downside, though, is that the XML files are rather bloated, mostly due to duplication of tag and attribute names. Also due to numeric data taking significantly more space than using native datatypes. A small level could easily end up as 1Mb+. I want to get these sizes down significantly, especially if the system is to be used for a game on the iPhone or other devices with relatively limited memory. The optimal solution, for memory and performance, would be to convert the XML to a binary level format. But I don't want to do this. I want to keep the format fairly flexible. XML makes it very easy to add new attributes to objects, and give them a default value if an old version of the data is loaded. So I want to keep with the hierarchy of nodes, with attributes as name-value pairs. But I need to store this in a more compact format - to remove the massive duplication of tag/attribute names. Maybe also to give attributes native types, so, for example floating-point data is stored as 4 bytes per float, not as a text string. Google/Wikipedia reveal that 'binary XML' is hardly a new problem - it's been solved a number of times already. Has anyone here got experience with any of the existing systems/standards? - are any ideal for games use - with a free, lightweight and cross-platform parser/loader library (C/C++) available? Or should I reinvent this wheel myself? Or am I better off forgetting the ideal, and just compressing my raw .xml data (it should pack well with zip-like compression), and just taking the memory/performance hit on-load?

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  • How do I speed up XML parsing operation?

    - by absentx
    I currently have a php script set up to do some xml parsing. Sometimes the script is set as an on page include and other times it is accessed via an ajax call. The problem is the load time for this particular page is very long. I started to think that the php I had written to find what I need in the XML was written poorly and my script is very resource intense. After much research and testing the problem is indeed not my scripting (well perhaps you could consider it a problem with my scripting), but it looks like it takes a long time to load the particular xml sources. My code is like such: $source_recent = 'my xml feed'; $source_additional = 'the other feed I need'; $xmlstr_recent = file_get_contents($source_recent); $feed_recent = new SimpleXMLElement($xmlstr_recent); $xmlstr_additional = file_get_contents($source_additional); $feed_additional = new SimpleXMLElement($xmlstr_additional); In all my testing, the above code is what takes the time, not the additional processing I do below. Is there anyway around this or am I at the mercy of the load time of the xml URL's? One crazy thought I had to get around it is to load the xml contents into a db every so often, then just query the db for what I need. Thoughts? Ideas?

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  • Permissions error for a signed Java applet when including external JAR files

    - by sri
    I have a signed Java applet. And it works fine. But now I have to integrate some 3rd party JAR files with it. When I test it from Eclipse, the whole thing works correctly. But when I test it as an applet, it gives me a FilePermission error. I thought this was because those 3rd party JAR files don't have a java.policy.applet within them. But manually adding the policy file doesn't get rid of the error. What am I missing? Thanks! ============================ All the 3rd party JAR files sit on the server filesystem like so: A.jar, B.jar, C.jar. And I include them in the applet tag like so: <applet archive="my.jar,A.jar,B.jar,C.jar"> </applet> Also, in the MANIFEST/MANIFEST.MF file in my.jar, I include those JAR files like so: Class-Path: A.jar,B.jar,C.jar

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  • Iterate through deserialized xml object

    - by Bruce Adams
    I have a deserialized xml c# objet. I need to iterate through the oject to display all items, in this case there's just one, and display the name, colors and sizes for each item. The xml: <?xml version="1.0" encoding="utf-8"?> <Catalog Name="Example"> <Items> <Item Name="ExampleItem"> <Colors> <Color Name="Black" Value="#000" /> <Color Name="White" Value="#FFF" /> </Colors> <Sizes> <Size Name="Small" Value="10" /> <Size Name="Medium" Value="20" /> </Sizes> </Item> </Items> </Catalog> xsd.exe generated classes: //------------------------------------------------------------------------------ // <auto-generated> // This code was generated by a tool. // Runtime Version:2.0.50727.4927 // // Changes to this file may cause incorrect behavior and will be lost if // the code is regenerated. // </auto-generated> //------------------------------------------------------------------------------ using System.Xml.Serialization; // // This source code was auto-generated by xsd, Version=2.0.50727.42. // /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] [System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=false)] public partial class Catalog { private CatalogItemsItem[][] itemsField; private string nameField; /// <remarks/> [System.Xml.Serialization.XmlArrayAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] [System.Xml.Serialization.XmlArrayItemAttribute("Item", typeof(CatalogItemsItem[]), Form=System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable=false)] public CatalogItemsItem[][] Items { get { return this.itemsField; } set { this.itemsField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Name { get { return this.nameField; } set { this.nameField = value; } } } /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] public partial class CatalogItemsItem { private CatalogItemsItemColorsColor[][] colorsField; private CatalogItemsItemSizesSize[][] sizesField; private string nameField; /// <remarks/> [System.Xml.Serialization.XmlArrayAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] [System.Xml.Serialization.XmlArrayItemAttribute("Color", typeof(CatalogItemsItemColorsColor[]), Form=System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable=false)] public CatalogItemsItemColorsColor[][] Colors { get { return this.colorsField; } set { this.colorsField = value; } } /// <remarks/> [System.Xml.Serialization.XmlArrayAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] [System.Xml.Serialization.XmlArrayItemAttribute("Size", typeof(CatalogItemsItemSizesSize[]), Form=System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable=false)] public CatalogItemsItemSizesSize[][] Sizes { get { return this.sizesField; } set { this.sizesField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Name { get { return this.nameField; } set { this.nameField = value; } } } /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] public partial class CatalogItemsItemColorsColor { private string nameField; private string valueField; /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Name { get { return this.nameField; } set { this.nameField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Value { get { return this.valueField; } set { this.valueField = value; } } } /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] public partial class CatalogItemsItemSizesSize { private string nameField; private string valueField; /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Name { get { return this.nameField; } set { this.nameField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Value { get { return this.valueField; } set { this.valueField = value; } } } /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] [System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=false)] public partial class NewDataSet { private Catalog[] itemsField; /// <remarks/> [System.Xml.Serialization.XmlElementAttribute("Catalog")] public Catalog[] Items { get { return this.itemsField; } set { this.itemsField = value; } } } Deserialization code: System.Xml.Serialization.XmlSerializer xSerializer = new System.Xml.Serialization.XmlSerializer(typeof(Catalog)); TextReader reader = new StreamReader("catalog.xml"); Catalog catalog = (Catalog)xSerializer.Deserialize(reader); foreach (var item in catalog.Items) { } reader.Close(); When I setp through the code there is one item present in catalog.items, but it is empty, no name, colors or sizes. Any ideas what I need to do? Thanks

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  • Merging two XML files into one XML file using Java

    - by dmurali
    I am stuck with how to proceed with combining two different XML files(which has the same structure). When I was doing some research on it, people say that XML parsers like DOM or StAX will have to be used. But cant I do it with the regular IOStream? I am currently trying to do with the help of IOStream but this is not solving my purpose, its being more complex. For example, What I have tried is; public class GUI { public static void main(String[] args) throws Exception { // Creates file to write to Writer output = null; output = new BufferedWriter(new FileWriter("C:\\merged.xml")); String newline = System.getProperty("line.separator"); output.write(""); // Read in xml file 1 FileInputStream in = new FileInputStream("C:\\1.xml"); BufferedReader br = new BufferedReader(new InputStreamReader(in)); String strLine; while ((strLine = br.readLine()) != null) { if (strLine.contains("<MemoryDump>")){ strLine = strLine.replace("<MemoryDump>", "xmlns:xsi"); } if (strLine.contains("</MemoryDump>")){ strLine = strLine.replace("</MemoryDump>", "xmlns:xsd"); } output.write(newline); output.write(strLine); System.out.println(strLine); } // Read in xml file 2 FileInputStream in = new FileInputStream("C:\\2.xml"); BufferedReader br1 = new BufferedReader(new InputStreamReader(in)); String strLine1; while ((strLine1 = br1.readLine()) != null) { if (strLine1.contains("<MemoryDump>")){ strLine1 = strLine1.replace("<MemoryDump>", ""); } if (strLine1.contains("</MemoryDump>")){ strLine1 = strLine1.replace("</MemoryDump>", ""); } output.write(newline); output.write(strLine1); I request you to kindly let me know how do I proceed with merging two XML files by adding additional content as well. It would be great if you could provide me some example links as well..! Thank You in Advance..! System.out.println(strLine1); } }

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  • Raw XML Push from input stream captures only the first line of XML

    - by pqsk
    I'm trying to read XML that is being pushed to my java app. I originally had this in my glassfish server working. The working code in glassfish is as follows: public class XMLPush implements Serializable { public void processXML() { StringBuilder sb = new StringBuilder(); BufferedReader br = null; try { br = ((HttpServletRequest)FacesContext.getCurrentInstance().getExternalContext().getRequest()).getReader (); String s = null; while((s = br.readLine ()) != null) { sb.append ( s ); } //other code to process xml ........... ............................. }catch(Exception ex) { XMLCreator.exceptionOutput ( "processXML","Exception",ex); } .... ..... }//processXML }//class It works perfect, but my client is unable to have glassfish on their server. I tried grabbing the raw xml from php, but I couldn't get it to work. I decided to open up a socket and listen for the xml push manually. Here is my code for receiving the push: public class ListenerService extends Thread { private BufferedReader reader = null; private String line; public ListenerService ( Socket connection )thows Exception { this.reader = new BufferedReader ( new InputStreamReader ( connection.getInputStream () ) ); this.line = null; }//ListenerService @Override public void run () { try { while ( (this.line = this.reader.readLine ()) != null) { System.out.println ( this.line ); ........ }//while } System.out.println ( ex.toString () ); } } catch ( Exception ex ) { ... }//catch }//run I haven't done much socket programing, but from what I read for the past week is that passing the xml into a string is bad. What am I doing wrong and why is it that in glassfish server it works, and when I just open a socket myself it doesn't? this is all that I receive from the push: PUT /?XML_EXPORT_REASON=ResponseLoop&TIMESTAMP=1292559547 HTTP/1.1 Host: ************************ Accept: */* Content-Length: 470346 Expect: 100-continue <?xml version="1.0" encoding="UTF-8" ?> Where did the xml go? Is it because I am placing it in a string? I just need to grab the xml and save it into a file and then process it. Everything else works, but this.Any help would be greatly appreciated.

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  • Why it's failed to load main-class manifest attribute from jar-file?

    - by Roman
    I have created a jar file in this way jar cf jar-file input-files. Now I try to run it. This does not work: jre -cp app.jar MainClass (jre command is not found). This java -jar main.jar also does not work (Failed to load Main-Class manifest attribute from main.jar). I also found out that To run an application packaged as a JAR file (version 1.2 -- requires Main-Class manifest header) What is the "Main-Class manifest header" how do I create it and where do I put it? ADDED I made a mistake in my original question. The second command I tried was: java -jar main.jar.

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  • java.lang.NoSuchMethodException: javax.ejb.EJBHome.getHomeHandle()

    - by brianegge
    I'm trying to figure out why I'm getting the following exception when a client app is connecting to JBoss. I happens on startup, when the client attempts to connect to the server. java.lang.ExceptionInInitializerError at org.jboss.proxy.ejb.HomeInterceptor.<clinit>(HomeInterceptor.java:77) at sun.misc.Unsafe.ensureClassInitialized(Native Method) at sun.reflect.UnsafeFieldAccessorFactory.newFieldAccessor(UnsafeFieldAccessorFactory.java:25) at sun.reflect.ReflectionFactory.newFieldAccessor(ReflectionFactory.java:122) at java.lang.reflect.Field.acquireFieldAccessor(Field.java:917) at java.lang.reflect.Field.getFieldAccessor(Field.java:898) at java.lang.reflect.Field.getLong(Field.java:527) at java.io.ObjectStreamClass.getDeclaredSUID(ObjectStreamClass.java:1559) at java.io.ObjectStreamClass.access$600(ObjectStreamClass.java:47) at java.io.ObjectStreamClass$2.run(ObjectStreamClass.java:381) at java.security.AccessController.doPrivileged(Native Method) at java.io.ObjectStreamClass.<init>(ObjectStreamClass.java:373) at java.io.ObjectStreamClass.lookup(ObjectStreamClass.java:268) at java.io.ObjectStreamClass.initNonProxy(ObjectStreamClass.java:504) at java.io.ObjectInputStream.readNonProxyDesc(ObjectInputStream.java:1546) at java.io.ObjectInputStream.readClassDesc(ObjectInputStream.java:1460) at java.io.ObjectInputStream.readOrdinaryObject(ObjectInputStream.java:1693) at java.io.ObjectInputStream.readObject0(ObjectInputStream.java:1299) at java.io.ObjectInputStream.readObject(ObjectInputStream.java:339) at org.jboss.proxy.ClientContainer.readExternal(ClientContainer.java:142) at java.io.ObjectInputStream.readExternalData(ObjectInputStream.java:1753) at java.io.ObjectInputStream.readOrdinaryObject(ObjectInputStream.java:1711) at java.io.ObjectInputStream.readObject0(ObjectInputStream.java:1299) at java.io.ObjectInputStream.defaultReadFields(ObjectInputStream.java:1912) at java.io.ObjectInputStream.readSerialData(ObjectInputStream.java:1836) at java.io.ObjectInputStream.readOrdinaryObject(ObjectInputStream.java:1713) at java.io.ObjectInputStream.readObject0(ObjectInputStream.java:1299) at java.io.ObjectInputStream.readObject(ObjectInputStream.java:339) at java.rmi.MarshalledObject.get(MarshalledObject.java:135) at org.jnp.interfaces.MarshalledValuePair.get(MarshalledValuePair.java:57) at org.jnp.interfaces.NamingContext.lookup(NamingContext.java:637) at org.jnp.interfaces.NamingContext.lookup(NamingContext.java:572) at javax.naming.InitialContext.lookup(InitialContext.java:351) at ...start of my code... Caused by: java.lang.NoSuchMethodException: javax.ejb.EJBHome.getHomeHandle() at java.lang.Class.getMethod(Class.java:1581) at org.jboss.proxy.ejb.HomeInterceptor.<clinit>(HomeInterceptor.java:64) ... 39 more

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  • Maven problem with invalid jar file which is actually html

    - by fei
    i'm running into a problem in my maven build recently, that it downloads a jar file for the javamail-1.4.jar or something, but it turns out the file is not a real jar file, it's actually a html with a link to where to get the correct jar. it seems to be the repo has changed for that. but in my maven setting everything is supposely to go to our internal repo, i don't know how did that happen. but anyways, more importantly, how do i fix this problem so that it will download the correct jar file on a fresh install? thanks!

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  • Java Applet in JAR File

    - by Jared Revik
    I have created a java applet (.class file) and made a .jar with it and digitally signed the .jar file. Now I need to run the .jar as an applet in firefox. What do I put in the html code to run the .jar file as an applet? I tried and it doesn't work, it tries to get a .class file, how do I load and run my applet as a .jar file using the applet tag in Internet Explorer and Firefox? I searched on the internet and could not find an answer.

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  • resource-ref at application scope in EJB 2.1 Project

    - by Mike Deck
    Is it possible to define resource references that are applicable to all EJBs in an application? Currently I have an ejb-jar.xml that looks something like this: <ejb-jar> <enterprise-beans> <session id="foo"> <!-- snip --> <resource-ref> <res-ref-name>jdbc/myDatasource</res-ref-name> <res-type>javax.sql.DataSource</res-type> <res-auth>Container</res-auth> </resource-ref> </session> <session id="bar"> <!-- snip --> <resource-ref> <res-ref-name>jdbc/myDatasource</res-ref-name> <res-type>javax.sql.DataSource</res-type> <res-auth>Container</res-auth> </resource-ref> </session> </enterprise-beans> </ejb-jar> You'll notice that both EJBs have the same resource-ref defined for both of them. Is there a way to factor this duplication out within a J2EE 1.4 application? Ideally I should be able to define the jdbc/myDatasource resource once within the application and have anything running inside that container be able to access it by doing a JNDI lookup for "java:comp/env/jdbc/myDatasource". Is there any way to accomplish this?

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  • Android Jar libraries

    - by Jeremy Edwards
    How do you setup a project that can result in a jar library file that can be used for android? I want to create a custom library across all projects. Few other questions: Does it need to be compiled against a specific version of android sdk? When an android package is compiled against a jar library does the classes necessary to work with the code get compiled with main code into the apk or does the entire jar get included? Any notable optimizations or pitfalls I need to know about with using a jar instead of integrating the code directly? Does the jar have to be signed like the apk needs to?

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  • ???????/?????????XML?? ~Oracle????XML~

    - by Yusuke.Yamamoto
    ????? ??:2010/08/25 ??:??????/?? Oracle Database ?XML???????????????????????????????????????????? Oracle Database ?XML???????Oracle Database ? XPath ???Oracle Database ? XQuery ???Oracle Database ????????????XML???????Oracle Database ?XML??????????????????"2?"?????? ????????? ????????????????? http://otndnld.oracle.co.jp/ondemand/otn-seminar/movie/XML2_08251330.wmv http://www.oracle.com/technetwork/jp/content/open-0825-xmlfesta2-251028-ja.pdf

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  • Build XML document using Linq To XML

    - by JasonDR
    Given the following code: string xml = ""; //alternativley: string xml = "<people />"; XDocument xDoc = null; if (!string.IsNullOrEmpty(xml)) { xDoc = XDocument.Parse(xml); xDoc.Element("people").Add( new XElement("person", "p 1") ); } else { xDoc = new XDocument(); xDoc.Add(new XElement("people", new XElement("person", "p 1") )); } As you can see, if the xml variable is blank, I need to create the rood node manually, and append the person the root node, whereas if it is not, I simple add to the people element My question is, is there any way to generically create the document, where it will add all referenced node automatically if they do not already exists?

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  • running scala apps with java -jar

    - by paintcan
    Yo dawgs, I got some problems with the java. Check it out. sebastian@sebastian-desktop:~/scaaaaaaaaala$ java -cp /home/sebastian/.m2/repository/org/scala-lang/scala-library/2.8.0.RC3/scala-library-2.8.0.RC3.jar:target/scaaaaaaaaala-1.0.jar scaaalaaa.App Hello World! That's cool, right, but how bout this: sebastian@sebastian-desktop:~/scaaaaaaaaala$ java -cp /home/sebastian/.m2/repository/org/scala-lang/scala-library/2.8.0.RC3/scala-library-2.8.0.RC3.jar -jar target/scaaaaaaaaala-1.0.jar Exception in thread "main" java.lang.NoClassDefFoundError: scala/Application at java.lang.ClassLoader.defineClass1(Native Method) at java.lang.ClassLoader.defineClassCond(ClassLoader.java:632) at java.lang.ClassLoader.defineClass(ClassLoader.java:616) at java.security.SecureClassLoader.defineClass(SecureClassLoader.java:141) at java.net.URLClassLoader.defineClass(URLClassLoader.java:283) at java.net.URLClassLoader.access$000(URLClassLoader.java:58) at java.net.URLClassLoader$1.run(URLClassLoader.java:197) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:190) at java.lang.ClassLoader.loadClass(ClassLoader.java:307) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) at java.lang.ClassLoader.loadClass(ClassLoader.java:248) at scaaalaaa.App.main(App.scala) Caused by: java.lang.ClassNotFoundException: scala.Application at java.net.URLClassLoader$1.run(URLClassLoader.java:202) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:190) at java.lang.ClassLoader.loadClass(ClassLoader.java:307) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) at java.lang.ClassLoader.loadClass(ClassLoader.java:248) ... 13 more Wat the heck? Any idea why the first works and not the 2nd? How do I -jar my scala?? Thanks in advance bro.

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  • How to load a library that depends on another library, all from a jar file

    - by Philip
    I would like to ship my application as a self-contained jar file. The jar file should contain all the class files, as well as two shared libraries. One of these shared libraries is written for the JNI and is essentially an indirection to the other one (which is 100% C). I have first tried running my jar file without the libraries, but having them accessible through the LD_LIBRARY_PATH environment variable. That worked fine. I then put the JNI library into the jar file. I have read about loading libraries from jar files by copying them first to some temporary directory, and that worked well for me (note that the 100% C library was, I suppose, loaded as before). Now I want to put both libraries into the jar, but I don't understand how I can make sure that they will both be loaded. Sure I can copy them both to a temporary directory, but when I load the "indirection" one, it always gives me: java.lang.UnsatisfiedLinkError: /tmp/.../libindirect.so: /libpure.so: cannot open shared object file: No such file or directory I've tried to force the JVM to load the "100% C" library first by explicitely calling System.load(...) on its temporary file, but that didn't work better. I suspect the system is looking for it when resolving the links in libindirect.so but doesn't care about what the JVM loaded. Can anyone help me on that one? Thanks

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  • Experiences wanted: producing a jar artifact in IntelliJ

    - by skiaddict1
    Developing with IntelliJ 9.0.2 Community Edition, on the Mac. This is a follow-up to this post about including jar files in an artifact, which has not received any replies. I'm hoping that the reason is that somehow, in creating my artifact (or setting my project settings), I unwittingly did something which people don't tend to do, and which is causing my problem, and that by asking people here to share how they create jar artifacts and set up projects, I will discover what it is. To recap: I have a Java project which depends on two library files. I need to package up the entire thing, with the jars inlined (such that on doing jar -tfv <filename> I see ALL the classes listed, including the ones in the two libraries), into a single jar file. I can make an artifact, I can add the library files to the Output Layout pane, but I CANNOT, no matter what I do, I cannot get the "Inline Artifact" item in the context menu to be selectable (i.e. non-grey) when I right-click on one or other library file. The thing is, making a jar which contains library files as well as the project code is NOT an unusual situation in the Java world! So I figure there are lots of IntelliJ folks out there who have done what I need to do. And I would really like to hear from you folks. What project settings do you use? (be specific, please :-) And exactly how do you set up your jar artifacts? (again, as many specific details as possible, please :-) Clearly, I'd be particularly interested to hear from folks with similar setups to mine (above) who are successfully doing what I need to do. Grateful thanks in advance, folks.

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  • android sdk main.out.xml parsing error?

    - by mobibob
    I just started a new Android project, "WeekendStudy" to continue learning Android development and I got stumped compiling the default 'hello weekendstudy' compile / run. I think that I missed a step in configuration and setup, but I am at a loss to find out where. I have an AVD configured, set and launched. When I press 'run', the SDK is building a file main.out.xml and then fails as this: [2010-03-06 09:46:47 - WeekendStudy]Error in an XML file: aborting build. [2010-03-06 09:46:48 - WeekendStudy]res/layout/main.xml:0: error: Resource entry main is already defined. [2010-03-06 09:46:48 - WeekendStudy]res/layout/main.out.xml:0: Originally defined here. [2010-03-06 09:46:48 - WeekendStudy]/Users/mobibob/Projects/workspace-weekend/WeekendStudy/res/layout/main.out.xml:1: error: Error parsing XML: no element found [2010-03-06 09:48:16 - WeekendStudy]Error in an XML file: aborting build. [2010-03-06 09:48:16 - WeekendStudy]res/layout/main.xml:0: error: Resource entry main is already defined. [2010-03-06 09:48:16 - WeekendStudy]res/layout/main.out.xml:0: Originally defined here. [2010-03-06 09:48:16 - WeekendStudy]/Users/mobibob/Projects/workspace-weekend/WeekendStudy/res/layout/main.out.xml:1: error: Error parsing XML: no element found [2010-03-06 09:55:29 - WeekendStudy]res/layout/main.xml:0: error: Resource entry main is already defined. [2010-03-06 09:55:29 - WeekendStudy]res/layout/main.out.xml:0: Originally defined here. [2010-03-06 09:55:29 - WeekendStudy]/Users/mobibob/Projects/workspace-weekend/WeekendStudy/res/layout/main.out.xml:1: error: Error parsing XML: no element found [2010-03-06 09:55:49 - WeekendStudy]Error in an XML file: aborting build. [2010-03-06 09:55:49 - WeekendStudy]res/layout/main.xml:0: error: Resource entry main is already defined. [2010-03-06 09:55:49 - WeekendStudy]res/layout/main.out.xml:0: Originally defined here. [2010-03-06 09:55:49 - WeekendStudy]/Users/mobibob/Projects/workspace-weekend/WeekendStudy/res/layout/main.out.xml:1: error: Error parsing XML: no element found

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  • Element was not expected While Deserializing an Array with XML Serialization

    - by Anthony Shaw
    OK. I'm trying to work on communicating with the Pivotal Tracker API, which only returns data in an XML format. I have the following XML that I'm trying to deserialize into my domain model. <?xml version="1.0" encoding="UTF-8"? <stories type="array" count="2" total="2" <story <id type="integer"2909137</id <project_id type="integer"68153</project_id <story_typebug</story_type <urlhttp://www.pivotaltracker.com/story/show/2909137</url <current_stateunscheduled</current_state <description</description <nameTest #2</name <requested_byAnthony Shaw</requested_by <created_at type="datetime"2010/03/23 20:05:58 EDT</created_at <updated_at type="datetime"2010/03/23 20:05:58 EDT</updated_at </story <story <id type="integer"2909135</id <project_id type="integer"68153</project_id <story_typefeature</story_type <urlhttp://www.pivotaltracker.com/story/show/2909135</url <estimate type="integer"-1</estimate <current_stateunscheduled</current_state <description</description <nameTest #1</name <requested_byAnthony Shaw</requested_by <created_at type="datetime"2010/03/23 20:05:53 EDT</created_at <updated_at type="datetime"2010/03/23 20:05:53 EDT</updated_at </story </stories My 'story' object is created as follows: public class story { public int id { get; set; } public int estimate { get; set; } public int project_id { get; set; } public string story_type { get; set; } public string url { get; set; } public string current_state { get; set; } public string description { get; set; } public string name { get; set; } public string requested_by { get; set; } public string labels { get; set; } public string lighthouse_id { get; set; } public string lighthouse_url { get; set; } public string owned_by { get; set; } public string accepted_at { get; set; } public string created_at { get; set; } public attachment[] attachments { get; set; } public note[] notes { get; set; } } When I execute my deserialization code, I receive the following exception: Exception: There is an error in XML document (2, 2). Inner Exception: <stories xmlns='' was not expected. I can deserialize the individual stories just fine, I just cannot deserialize this xml into an array of 'story' objects And my deserialization code (value is a string of the xml) var byteArray = Encoding.ASCII.GetBytes(value); var stream = new MemoryStream(byteArray); var deserializedObject = new XmlSerializer(typeof (story[])).Deserialize(stream) Does anybody have any ideas?

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  • Convert xml as string

    - by hakish
    i have a scenario where in i need to send an xml as a tag content in a SOAP request message to a webservice for example <arg_1><xml version="1.0" encoding="UTF-8"?><sometag><somemoretag>abcd</somemoretag></sometag></arg_1></code> arg_1 happens to be an String parameter to a webservice. So i bring in a CDATA section for this <arg_1><![CDATA[<xml version="1.0" encoding="UTF-8"?><sometag><somemoretag>abcd</somemoretag></sometag>]]></arg_1> But this keeps throwing me an exception org.xml.sax.SAXException: WSWS3084E: Error: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize. Message being parsed: I keep getting this exception. Has anyone seen this before??

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  • Parsing XML in a non-XML column

    - by slugster
    Hi, i am reasonably proficient with SQLServer, but i'm not a DBA so i'm not sure how to approach this. I have an XML chunk stored in an ntext column. Due to it being a legacy database and the requirements of the project i cannot change the table (yet). This is an example of the data i need to manipulate: <XmlSerializableHashtable xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Entries> <Entry> <key xsi:type="xsd:string">CurrentYear</key><value xsi:type="xsd:string">2010</value> </Entry> <Entry> <key xsi:type="xsd:string">CurrentMonth</key><value xsi:type="xsd:string">4</value> </Entry> </Entries> </XmlSerializableHashtable> each row will have a chunk like this, but obviously with different keys/values in the XML. Is there any clever way i can parse this XML in to a name/value pairs style view? Or should i be using SQLServer's XML querying abilities even though it isn't an XML column? If so, how would i query a specific value out of that column? (Note: adding a computed XML column on the end of the table is a possibility, if that helps). Thanks for any assistance!

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