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  • C# - Converting a float to an int... and changing the int depending on the remainder

    - by Django Reinhardt
    Hi, this is probably the really newbie question (well, I'm pretty sure it is), but I have a float that's being returned and I need a quick and efficient way of turning it into an int. Pretty simple, but I have an exception. If the remainder of the float is anything other than .0 then I want to increment the int. Some quick examples: Float = 98.0, Int = 98 Float = 98.1, Int = 99 Float = 6.6, Int = 7 etc. Thanks for any help!

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  • Convert user input into ToString() method inside FlowDocument in Workflow 4.0

    - by Jon Ownbey
    I have a Workflow 4.0 app that generates emails. In a dialog for creating the email body the user needs to be able to input some string value representing an existing wf instance variable to be inserted as a string at runtime. So they input something like: Email body text including <. (say ExistingVariable is an int or something like that) Any helpful hints for how to convert this text with a ToString() at runtime?

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  • Double.ToString with N Number of Decimal Places

    - by Ngu Soon Hui
    I know that if we want to display a double as a two decimal digit, one would just have to use public void DisplayTwoDecimal(double dbValue) { Console.WriteLine(dbValue.ToString("0.00")); } But how to extend this to N decimal places, where N is determined by the user? public void DisplayNDecimal(double dbValue, int nDecimal) { // how to display }

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  • template; operator (int)

    - by Oops
    Hi, regarding my Point struct already mentioned here: http://stackoverflow.com/questions/2794369/template-class-ctor-against-function-new-c-standard is there a chance to replace the function toint() with a cast-operator (int)? namespace point { template < unsigned int dims, typename T > struct Point { T X[ dims ]; //umm??? template < typename U > Point< dims, U > operator U() const { Point< dims, U > ret; std::copy( X, X + dims, ret.X ); return ret; } //umm??? Point< dims, int > operator int() const { Point<dims, int> ret; std::copy( X, X + dims, ret.X ); return ret; } //OK Point<dims, int> toint() { Point<dims, int> ret; std::copy( X, X + dims, ret.X ); return ret; } }; //struct Point template < typename T > Point< 2, T > Create( T X0, T X1 ) { Point< 2, T > ret; ret.X[ 0 ] = X0; ret.X[ 1 ] = X1; return ret; } }; //namespace point int main(void) { using namespace point; Point< 2, double > p2d = point::Create( 12.3, 34.5 ); Point< 2, int > p2i = (int)p2d; //äähhm??? std::cout << p2d.str() << std::endl; char c; std::cin >> c; return 0; } I think the problem is here that C++ cannot distinguish between different return types? many thanks in advance. regards Oops

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  • int.Parse of "8" fails. int.Parse always requires CultureInfo.InvariantCulture?

    - by Henrik Carlsson
    We develop an established software which works fine on all known computers except one. The problem is to parse strings that begin with "8". It seems like "8" in the beginning of a string is a reserved character. Parsing: int.Parse("8") -> Exception message: Input string was not in a correct format. int.Parse("80") -> 0 int.Parse("88") -> 8 int.Parse("8100") -> 100 CurrentCulture: sv-SE CurrentUICulture: en-US The problem is solved using int.Parse("8", CultureInfo.InvariantCulture). However, it would be nice to know the source of the problem. Question: Why do we get this behaviour of "8" if we don't specify invariant culture? Additional information: I did send a small program to my client achieve the result above: private int ParseInt(string s) { int parsedInt = -1000; try { parsedInt = int.Parse(s); textBoxMessage.Text = "Success: " + parsedInt; } catch (Exception ex) { textBoxMessage.Text = string.Format("Error parsing string: '{0}'", s) + Environment.NewLine + "Exception message: " + ex.Message; } textBoxMessage.Text += Environment.NewLine + Environment.NewLine + "CurrentCulture: " + Thread.CurrentThread.CurrentCulture.Name + "\r\n" + "CurrentUICulture: " + Thread.CurrentThread.CurrentUICulture.Name + "\r\n"; return parsedInt; }

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  • Interpretation of int (*a)[3]

    - by kapuzineralex
    When working with arrays and pointers in C, one quickly discovers that they are by no means equivalent although it might seem so at a first glance. I know about the differences in L-values and R-values. Still, recently I tried to find out the type of a pointer that I could use in conjunction with a two-dimensional array, i.e. int foo[2][3]; int (*a)[3] = foo; However, I just can't find out how the compiler "understands" the type definition of a in spite of the regular operator precedence rules for * and []. If instead I were to use a typedef, the problem becomes significantly simpler: int foo[2][3]; typedef int my_t[3]; my_t *a = foo; At the bottom line, can someone answer me the questions as to how the term int (*a)[3] is read by the compiler? int a[3] is simple, int *a[3] is simple as well. But then, why is it not int *(a[3])? EDIT: Of course, instead of "typecast" I meant "typedef" (it was just a typo).

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  • Function pointers uasage

    - by chaitanyavarma
    Hi All, Why these two codes give the same output, Case - 1: #include <stdio.h> typedef void (*mycall) (int a ,int b); void addme(int a,int b); void mulme(int a,int b); void subme(int a,int b); main() { mycall x[10]; x[0] = &addme; x[1] = &subme; x[2] = &mulme; (x[0])(5,2); (x[1])(5,2); (x[2])(5,2); } void addme(int a, int b) { printf("the value is %d\n",(a+b)); } void mulme(int a, int b) { printf("the value is %d\n",(a*b)); } void subme(int a, int b) { printf("the value is %d\n",(a-b)); } Output: the value is 7 the value is 3 the value is 10 Case -2 : #include <stdio.h> typedef void (*mycall) (int a ,int b); void addme(int a,int b); void mulme(int a,int b); void subme(int a,int b); main() { mycall x[10]; x[0] = &addme; x[1] = &subme; x[2] = &mulme; (*x[0])(5,2); (*x[1])(5,2); (*x[2])(5,2); } void addme(int a, int b) { printf("the value is %d\n",(a+b)); } void mulme(int a, int b) { printf("the value is %d\n",(a*b)); } void subme(int a, int b) { printf("the value is %d\n",(a-b)); } Output: the value is 7 the value is 3 the value is 10

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  • Function pointers usage

    - by chaitanyavarma
    Hi All, Why these two codes give the same output, Case 1: #include <stdio.h> typedef void (*mycall) (int a ,int b); void addme(int a,int b); void mulme(int a,int b); void subme(int a,int b); main() { mycall x[10]; x[0] = &addme; x[1] = &subme; x[2] = &mulme; (x[0])(5,2); (x[1])(5,2); (x[2])(5,2); } void addme(int a, int b) { printf("the value is %d\n",(a+b)); } void mulme(int a, int b) { printf("the value is %d\n",(a*b)); } void subme(int a, int b) { printf("the value is %d\n",(a-b)); } Output: the value is 7 the value is 3 the value is 10 Case 2 : #include <stdio.h> typedef void (*mycall) (int a ,int b); void addme(int a,int b); void mulme(int a,int b); void subme(int a,int b); main() { mycall x[10]; x[0] = &addme; x[1] = &subme; x[2] = &mulme; (*x[0])(5,2); (*x[1])(5,2); (*x[2])(5,2); } void addme(int a, int b) { printf("the value is %d\n",(a+b)); } void mulme(int a, int b) { printf("the value is %d\n",(a*b)); } void subme(int a, int b) { printf("the value is %d\n",(a-b)); } Output: the value is 7 the value is 3 the value is 10

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  • return new string vs .ToString()

    - by Leroy Jenkins
    Take the following code: public static string ReverseIt(string myString) { char[] foo = myString.ToCharArray(); Array.Reverse(foo); return new string(foo); } I understand that strings are immutable, but what I dont understand is why a new string needs to be called return new string(foo); instead of return foo.ToString(); I have to assume it has something to do with reassembling the CharArray (but thats just a guess). Whats the difference between the two and how do you know when to return a new string as opposed to returning a System.String that represents the current object?

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  • toString() Method question

    - by cdominguez13
    I've been working on this assignemnt here's code: public class Student { private String fname; private String lname; private String studentId; private double gpa; public Student(String studentFname,String studentLname,String stuId,double studentGpa) { fname = studentFname; lname = studentLname; studentId = stuId; gpa = studentGpa; } public double getGpa() { return gpa; } public String getStudentId() { return studentId; } public String getName() { return lname + ", " + fname; } public void setGpa(double gpaReplacement) { if (gpaReplacement >= 0.0 && gpaReplacement <= 4.0) gpa = gpaReplacement; else System.out.println("Invalid GPA! Please try again."); System.exit(0); } } Now I need to create a toString() method that returns a String formatted something like this: Name: Wilson, Mary Ann ID number: 12345 GPA: 3.5

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  • C++ Little Wonders: The C++11 auto keyword redux

    - by James Michael Hare
    I’ve decided to create a sub-series of my Little Wonders posts to focus on C++.  Just like their C# counterparts, these posts will focus on those features of the C++ language that can help improve code by making it easier to write and maintain.  The index of the C# Little Wonders can be found here. This has been a busy week with a rollout of some new website features here at my work, so I don’t have a big post for this week.  But I wanted to write something up, and since lately I’ve been renewing my C++ skills in a separate project, it seemed like a good opportunity to start a C++ Little Wonders series.  Most of my development work still tends to focus on C#, but it was great to get back into the saddle and renew my C++ knowledge.  Today I’m going to focus on a new feature in C++11 (formerly known as C++0x, which is a major move forward in the C++ language standard).  While this small keyword can seem so trivial, I feel it is a big step forward in improving readability in C++ programs. The auto keyword If you’ve worked on C++ for a long time, you probably have some passing familiarity with the old auto keyword as one of those rarely used C++ keywords that was almost never used because it was the default. That is, in the code below (before C++11): 1: int foo() 2: { 3: // automatic variables (allocated and deallocated on stack) 4: int x; 5: auto int y; 6:  7: // static variables (retain their value across calls) 8: static int z; 9:  10: return 0; 11: } The variable x is assumed to be auto because that is the default, thus it is unnecessary to specify it explicitly as in the declaration of y below that.  Basically, an auto variable is one that is allocated and de-allocated on the stack automatically.  Contrast this to static variables, that are allocated statically and exist across the lifetime of the program. Because auto was so rarely (if ever) used since it is the norm, they decided to remove it for this purpose and give it new meaning in C++11.  The new meaning of auto: implicit typing Now, if your compiler supports C++ 11 (or at least a good subset of C++11 or 0x) you can take advantage of type inference in C++.  For those of you from the C# world, this means that the auto keyword in C++ now behaves a lot like the var keyword in C#! For example, many of us have had to declare those massive type declarations for an iterator before.  Let’s say we have a std::map of std::string to int which will map names to ages: 1: std::map<std::string, int> myMap; And then let’s say we want to find the age of a given person: 1: // Egad that's a long type... 2: std::map<std::string, int>::const_iterator pos = myMap.find(targetName); Notice that big ugly type definition to declare variable pos?  Sure, we could shorten this by creating a typedef of our specific map type if we wanted, but now with the auto keyword there’s no need: 1: // much shorter! 2: auto pos = myMap.find(targetName); The auto now tells the compiler to determine what type pos should be based on what it’s being assigned to.  This is not dynamic typing, it still determines the type as if it were explicitly declared and once declared that type cannot be changed.  That is, this is invalid: 1: // x is type int 2: auto x = 42; 3:  4: // can't assign string to int 5: x = "Hello"; Once the compiler determines x is type int it is exactly as if we typed int x = 42; instead, so don’t' confuse it with dynamic typing, it’s still very type-safe. An interesting feature of the auto keyword is that you can modify the inferred type: 1: // declare method that returns int* 2: int* GetPointer(); 3:  4: // p1 is int*, auto inferred type is int 5: auto *p1 = GetPointer(); 6:  7: // ps is int*, auto inferred type is int* 8: auto p2 = GetPointer(); Notice in both of these cases, p1 and p2 are determined to be int* but in each case the inferred type was different.  because we declared p1 as auto *p1 and GetPointer() returns int*, it inferred the type int was needed to complete the declaration.  In the second case, however, we declared p2 as auto p2 which means the inferred type was int*.  Ultimately, this make p1 and p2 the same type, but which type is inferred makes a difference, if you are chaining multiple inferred declarations together.  In these cases, the inferred type of each must match the first: 1: // Type inferred is int 2: // p1 is int* 3: // p2 is int 4: // p3 is int& 5: auto *p1 = GetPointer(), p2 = 42, &p3 = p2; Note that this works because the inferred type was int, if the inferred type was int* instead: 1: // syntax error, p1 was inferred to be int* so p2 and p3 don't make sense 2: auto p1 = GetPointer(), p2 = 42, &p3 = p2; You could also use const or static to modify the inferred type: 1: // inferred type is an int, theAnswer is a const int 2: const auto theAnswer = 42; 3:  4: // inferred type is double, Pi is a static double 5: static auto Pi = 3.1415927; Thus in the examples above it inferred the types int and double respectively, which were then modified to const and static. Summary The auto keyword has gotten new life in C++11 to allow you to infer the type of a variable from it’s initialization.  This simple little keyword can be used to cut down large declarations for complex types into a much more readable form, where appropriate.   Technorati Tags: C++, C++11, Little Wonders, auto

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  • e.Row.Tag .ToString

    - by prince23
    hi, Child data grid is not showing the values in the page for the child datagrid I am binding with an list <sdk:DataGrid MinHeight="100" x:Name="contacts" Margin="51,21,88,98" RowDetailsVisibilityChanged="contacts_RowDetailsVisibilityChanged" LoadingRowDetails="contacts_LoadingRowDetails" RowDetailsVisibilityMode="VisibleWhenSelected" MouseLeftButtonUp="contacts_MouseLeftButtonUp" MouseLeftButtonDown="contacts_MouseLeftButtonDown"> <sdk:DataGrid.Columns> <sdk:DataGridTextColumn Binding="{Binding EmployeeID}" Header="ID" /> <sdk:DataGridTextColumn Binding="{Binding EmployeeFName}" Header="Fname" /> <sdk:DataGridTextColumn Binding="{Binding EmployeeLName}" Header="LName" /> <sdk:DataGridTextColumn Binding="{Binding EmployeeMailID}" Header="MailID" /> </sdk:DataGrid.Columns> <sdk:DataGrid.RowDetailsTemplate> <DataTemplate> <sdk:DataGrid x:Name="dgrdRowDetail" Width="200" AutoGenerateColumns="False" HorizontalAlignment="Center" IsReadOnly="True"> <sdk:DataGrid.Columns> <sdk:DataGridTextColumn Header="CompanyName" Binding="{Binding Company name}"/> <sdk:DataGridTextColumn Header="CompanyName" Binding="{Binding EmpID}"/> </sdk:DataGrid.Columns> </sdk:DataGrid> </DataTemplate> </sdk:DataGrid.RowDetailsTemplate> </sdk:DataGrid> I am having 2 grids "contacts" and "dgrdRowDetail" globally i have defined an variable like this:- DataGrid dgrdRowDetail; in the contacts_RowDetailsVisibilityChanged event I have this code if (e.Row.DataContext != null) { string strEmpID = ((SilverlightApplication1.DBServiceEMP.Employee)((e.DetailsElement).DataContext)).EmployeeID; dgrdRowDetail = (DataGrid)e.DetailsElement.FindName("dgrdRowDetail"); // here i am finding the child datgrid control in contacts datagrid // then in dgrdRowDetail i will be binding this grid with new values if (strEmpID != null) { int EmpID = Convert.ToInt32(strEmpID.ToString()); DBServiceEmp.GetEmployeeIDCompleted += new EventHandler<GetEmployeeIDCompletedEventArgs>(DBServiceEmp_GetEmployeeIDCompleted); DBServiceEmp.GetEmployeeIDAsync(EmpID); } } this is my method void DBServiceEmp_GetEmployeeIDCompleted(object sender, GetEmployeeIDCompletedEventArgs e) { // List<Employee> Employes = new List<Employee>(); List<Employee> rows = new List<Employee>(); for (int i = 0; i < e.Result.Count; i++) { rows.Add(e.Result[i]); } dgrdRowDetail.ItemsSource = rows; // here i am binding the child datagrid with new data source } dgrdRowDetail.ItemsSource = rows// what ever rows i am binding to dgrdRowDetail are not shown in the page if i check the rows i am able to see the value ther. but in the child grid it is not reflecting plz plz help me out i am struck thanks in advance prince

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  • Is this technically thread safe despite being mutable?

    - by Finbarr
    Yes, the private member variable bar should be final right? But actually, in this instance, it is an atomic operation to simply read the value of an int. So is this technically thread safe? class foo { private int bar; public foo(int bar) { this.bar = bar; } public int getBar() { return bar; } } // assume infinite number of threads repeatedly calling getBar on the same instance of foo.

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  • Multiplying char and int together in C

    - by teehoo
    Today I found the following: #include <stdio.h> int main(){ char x = 255; int z = ((int)x)*2; printf("%d\n", z); //prints -2 return 0; } So basically I'm getting an overflow because the size limit is determined by the operands on the right side of the = sign?? Why doesn't casting it to int before multiplying work? In this case I'm using a char and int, but if I use "long" and "long long int" (c99), then I get similar behaviour. Is it generally advised against doing arithmetic with operands of different sizes?

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  • C++11 VS 2012 functor seems to choke when I have more than 5 parameters

    - by bobobobo
    function <void ( int a, int b, int ia, int ib, bool rev, const Vector4f& color )> benchTris = [&pts]( int a, int b, int ia, int ib, bool rev, const Vector4f& color ) { } The error is: error C2027: use of undefined type 'std::_Get_function_impl<_Tx>' with [ _Tx=void (int,int,int,int,bool,const Vector4f &) ] main.cpp(374) : see reference to class template instantiation 'std::function<_Fty>' being compiled with [ _Fty=void (int,int,int,int,bool,const Vector4f &) ] Works ok if I remove ONE parameter, for example a from the front: function <void ( int b, int ia, int ib, bool rev, const Vector4f& color )> benchTris = [&pts]( int b, int ia, int ib, bool rev, const Vector4f& color ) { // ok } Is there some parameter limit I don't know about?

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  • Multiplying char and int together in C part 2

    - by teehoo
    If I do the following: int c0 = CHAR_MAX; //8 bit int c1 = CHAR_MAX; //8-bit int i = c0*c1; //store in 32-bit variable printf("%d\n", i); //prints 16129 We can see that there is no problem with to 8-bit numbers being multiplied together, and producing a 32-bit output. However, if I do int i0 = INT_MAX; //32-bit int i1 = INT_MAX; //32 bit variable long long int ll = i0*i1; //store in 64-bit variable printf("%lld\n", ll); //prints 1..overflow!! In this case, two 32-bit variables were multiplied together, overflowed, and then were assigned to the 64-bit variable. So why did this overflow happen when multiplying the ints, but not the chars? Is it dependent on the default word-size of my machine? (32-bits)

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  • int cannot be dereferenced

    - by Overlord
    Hello, I am beginning in java (I'm learning in microedition) and I got this error: "int cannot be dereferenced" in the following class: class DCanvas extends Canvas{ public DCanvas(){ } public void drawString(String str, int x, int y, int r, int g, int b){ g.setColor(r, g, b); //The error is here g.drawString(str, x, y, 0); //and here } public void paint(Graphics g){ g.setColor(100, 100, 220); g.fillRect(0, 0, getWidth(), getHeight()); } } What am I doing wrong here? Well I came from PHP and ECMAScripts where I was able to pass my function arguments this way so I really don't understand this error.

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  • C: Recursive function for inverting an int

    - by Jorge
    I had this problem on an exam yesterday. I couldn't resolve it so you can imagine the result... Make a recursive function: int invertint( int num) that will receive an integer and return it but inverted, example: 321 would return as 123 I wrote this: int invertint( int num ) { int rest = num % 10; int div = num / 10; if( div == 0 ) { return( rest ); } return( rest * 10 + invert( div ) ) } Worked for 2 digits numbers but not for 3 digits or more. Since 321 would return 1 * 10 + 23 in the last stage. Thanks a lot! PS: Is there a way to understand these kind of recursion problems in a faster manner or it's up to imagination of one self?

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  • int[] to string c#

    - by Robin Webdev
    Hi I'm developing an client application in C# and the server is written in c++ the server uses: inline void StrToInts(int *pInts, int Num, const char *pStr) { int Index = 0; while(Num) { char aBuf[4] = {0,0,0,0}; for(int c = 0; c < 4 && pStr[Index]; c++, Index++) aBuf[c] = pStr[Index]; *pInts = ((aBuf[0]+128)<<24)|((aBuf[1]+128)<<16)|((aBuf[2]+128)<<8)|(aBuf[3]+128); pInts++; Num--; } // null terminate pInts[-1] &= 0xffffff00; } to convert an string to int[] in my c# client i recieve: int[4] { -14240, -12938, -16988, -8832 } How do I convert the array back to an string? I don't want to use unsafe code (e.g. pointers) Any of my tries resulted in unreadable strings.

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  • C++0x error : variable 'std::packaged_task<int> pt1' has initializer but incomplete type

    - by Eternal Learner
    Hi All, Below is a simple program in c++0x that makes use of packaged_task and futures. while compiling the program i get error : variable 'std::packaged_task pt1' has initializer but incomplete type the program is below #include #include using namespace std; int printFn() { for(int i = 0; i < 100; i++) { cout << "thread " << i << endl; } return 1; } int main() { packaged_task<int> pt1(&printFn); future<int> fut = pt1.get_future(); thread t(move(pt1)); t.detach(); int value = fut.get(); return 0; }

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