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• Is it legal to stub the #class method of a Mock object when using RSpec in a Ruby on Rails applicati

  - by MiniQuark

  I would like to stub the #class method of a mock object: describe Letter do before(:each) do @john = mock("John") @john.stub!(:id).and_return(5) @john.stub!(:class).and_return(Person) # is this ok? @john.stub!(:name).and_return("John F.") Person.stub!(:find).and_return(@john) end it.should "have a valid #to field" do letter = Letter.create!(:to=>@john, :content => "Hello John") letter.to_type.should == @john.class.name letter.to_id.should == @john.id end [...] end On line 5 of this program, I stub the #class method, in order to allow things like @john.class.name. Is this the right way to go? Will there be any bad side effect? Edit: The Letter class looks like this: class Letter < ActiveRecord::Base belongs_to :to, :polymorphic => true [...] end I wonder whether ActiveRecord gets the :to field's class name with to.class.name or by some other means. Maybe this is what the class_name method is ActiveRecord::Base is for?

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• Post SQL 2008 R2 Launch Thurs 15th London - UK SQL Server User Group is having a Social Event @ the

  - by tonyrogerson

  The UK SQL Server User Group is organising a Social event for SQL and SQL Server professionals, the event will be held after the SQL Server 2008 R2 launch event and is a short walk from that venue. See site for more information: http://sqlserverfaq.com/events/222/Social-for-SQL-and-SQL-Server-professionals-SQL-quiz-meet-your-peers-ask-the-group-Q-A.aspx We are putting some light bites on, if you are coming then do let us know through the site. Neil Hambly who is the London UK SQL Server User Group...(read more)

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• SSIS Design Patterns Training in London 8-11 Sep!

  - by andyleonard

  A few seats remain for my course SQL Server Integration Services 2012 Design Patterns to be delivered in London 8-11 Sep 2014. Register today to learn more about: New features in SSIS 2012 and 2014 Advanced patterns for loading data warehouses Error handling The (new) Project Deployment Model Scripting in SSIS The (new) SSIS Catalog Designing custom SSIS tasks Executing, managing, monitoring, and administering SSIS in the enterprise Business Intelligence Markup Language (Biml) BimlScript ETL Instrumentation...(read more)

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• Why isn't my query using any indices when I use a subquery?

  - by sfussenegger

  I have the following tables (removed columns that aren't used for my examples): CREATE TABLE `person` ( `id` int(11) NOT NULL, `name` varchar(1024) NOT NULL, `sortname` varchar(1024) NOT NULL, PRIMARY KEY (`id`), KEY `sortname` (`sortname`(255)), KEY `name` (`name`(255)) ); CREATE TABLE `personalias` ( `id` int(11) NOT NULL, `person` int(11) NOT NULL, `name` varchar(1024) NOT NULL, PRIMARY KEY (`id`), KEY `person` (`person`), KEY `name` (`name`(255)) ) Currently, I'm using this query which works just fine: select p.* from person p where name = 'John Mayer' or sortname = 'John Mayer'; mysql> explain select p.* from person p where name = 'John Mayer' or sortname = 'John Mayer'; +----+-------------+-------+-------------+---------------+---------------+---------+------+------+----------------------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+-------------+---------------+---------------+---------+------+------+----------------------------------------------+ | 1 | SIMPLE | p | index_merge | name,sortname | name,sortname | 767,767 | NULL | 3 | Using sort_union(name,sortname); Using where | +----+-------------+-------+-------------+---------------+---------------+---------+------+------+----------------------------------------------+ 1 row in set (0.00 sec) Now I'd like to extend this query to also consider aliases. First, I've tried using a join: select p.* from person p join personalias a where p.name = 'John Mayer' or p.sortname = 'John Mayer' or a.name = 'John Mayer'; mysql> explain select p.* from person p join personalias a on p.id = a.person where p.name = 'John Mayer' or p.sortname = 'John Mayer' or a.name = 'John Mayer'; +----+-------------+-------+--------+-----------------------+---------+---------+-------------------+-------+-----------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+--------+-----------------------+---------+---------+-------------------+-------+-----------------+ | 1 | SIMPLE | a | ALL | ref,name | NULL | NULL | NULL | 87401 | Using temporary | | 1 | SIMPLE | p | eq_ref | PRIMARY,name,sortname | PRIMARY | 4 | musicbrainz.a.ref | 1 | Using where | +----+-------------+-------+--------+-----------------------+---------+---------+-------------------+-------+-----------------+ 2 rows in set (0.00 sec) This looks bad: no index, 87401 rows, using temporary. Using temporary only appears when I use distinct, but as an alias might be the same as the name, I can't really get rid of it. Next, I've tried to replace the join with a subquery: select p.* from person p where p.name = 'John Mayer' or p.sortname = 'John Mayer' or p.id in (select person from personalias a where a.name = 'John Mayer'); mysql> explain select p.* from person p where p.name = 'John Mayer' or p.sortname = 'John Mayer' or p.id in (select id from personalias a where a.name = 'John Mayer'); +----+--------------------+-------+----------------+------------------+--------+---------+------+--------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+--------------------+-------+----------------+------------------+--------+---------+------+--------+-------------+ | 1 | PRIMARY | p | ALL | name,sortname | NULL | NULL | NULL | 540309 | Using where | | 2 | DEPENDENT SUBQUERY | a | index_subquery | person,name | person | 4 | func | 1 | Using where | +----+--------------------+-------+----------------+------------------+--------+---------+------+--------+-------------+ 2 rows in set (0.00 sec) Again, this looks pretty bad: no index, 540309 rows. Interestingly, both queries (select p.* from person ... or p.id in (4711,12345) and select id from personalias a where a.name = 'John Mayer') work extremely well. Why doesn't MySQL use any indices for both of my queries? What else could I do? Currently, it looks best to fetch person.ids for aliases and add them statically as an in(...) to the second query. There certainly has to be another way to do this with a single query. I'm currently out of ideas though. Could I somehow force MySQL into using another (better) query plan?

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• Deck from London UG 20110616 - Building a Reporting Brick capable of 1.2GBytes/sec and 80K IOs/sec for less than £2K

  - by tonyrogerson

  The Reporting Brick concept is not really anything new, it starts the walk toward bringing the work Jim Gray and Tom Barclay et al did on CyberBricks up-to-date in terms of current kit. A reporting brick is simply a box built from commodity kit utilising commodity SSD, namely the OCZ IBIS drives to gain extremely high levels of performance for a fraction of the cost required for typical server and san installs today. I'll write up over the next few months as I work further on the concept, for now the deck attached summarises some of the ideas around it, the deck was presented at last nights London SQL Server User Group, I will be presenting it again in Edinburgh on the 29th June and other locations later in the year. Deck: Commodity Kit.pptx  

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• Chalk Talk with John: What Does User Experience Mean to You?

  - by Tanu Sood

  Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif"; mso-ascii- mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi- mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Author: John Brunswick The "Chalk Talk with John" series will explore the practical value of Middleware in the context of two fictional communities, shared through analogies aligned to enterprise technology.  This format offers business stakeholders and IT a common language for understanding the benefits of technology in support of their business initiatives, regardless of their current level of technical knowledge. I will endeavor to showcase an episode highlighting business use cases and how technology plays a role in business on a bi-weekly basis. The debut episode highlights the benefits of user experience capabilities supplied by Portal technologies, by juxtaposing the communities of Middleware Fields and Codeaway Valley with regard to the time and effort their residents spend performing everyday tasks.  This comparison provides insight into the benefits of leveraging a common user experience foundation to support the tasks that our employees, customers and partners engage in on a daily basis with our organizations. Take a look and let me know your thoughts! Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif"; mso-ascii- mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi- mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} About me: Hi, I am John Brunswick, an Oracle Enterprise Architect. As an Oracle Enterprise Architect, I focus on the alignment of technical capabilities in support of business vision and objectives, as well as the overall business value of technology.  Before coming to Oracle, I was a Practice Manager within BEA System's Business Interaction Division consulting organization, orchestrating enterprise systems in support of line of business goals. Connect with me on Twitter and visit my site for Oracle Fusion Middleware related tips.

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• Should be simple: existing laptop with local user and outlook 2007 migrate on same computer to domain user with outlook 2007 emails intact

  - by bifpowell

  I have Dell Laptop with windows 7 64 bit and for the last year it's been just a machine with an account like: machine\john there are files in folders and stuff in c:\users\john and john uses outlook 2007 as a pop3 client and has identifiable local appdata pst files. Now I installed a server and want to have everything be domain-centric so I added this laptop to the domain with admin credentials and then logged in as a domain user as: domain\john.smith Now I want to duplicate machine\john (outlook emails mostly) to domain\john.smith. In the past I used the Files and Settings Xfer Wizard and done. I tried that here and it crunched away for a while, made the file, but the restore had no effect - it ran for a while, had a progress bar, but it's like nothing happened at all afterwards. I've rebooted the machine, logged in as domain administrator as the first user to log on after the restart and tried: c:\users\john xcopy c:\users\john c:\users\john.smith /V /C /F /H /K /Y /E ...and it copies some of it, but when it gets to c:\users\john.smith\appdata\local\application data it chokes "Access denied, unable to create directory" I also tried logging in as domain\john.smith and copying the entire directory that the PSTs are in from machine\john and a lot of the mail was there when I launched outlook after replacing the PSTs, but not all of them??? I got errors about files in use when doing this method, which I figure must be why not all the old emails are in the inbox?... There must be some extremely simple way to do what must be a very common requirement. Any guidance appreciated.

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• London User Group Meetings this week (19th/20th May); 26th May-Agile Data Warehousing; 17th June-Kim

  - by tonyrogerson

  Got two user group meetings in London for you, we've also started the Cuppa Corner sessions - the first 3 are up on the site - A trip to First Normal Form, Lookup and Cache Transform in SSIS and Pipeline Limiter in SSIS - we are aiming for at least one per week. WhereScape are doing a breakfast meeting on Agile techniques to Data Warehousing and Kimberly Tripp and Paul Randal are over in June for a 1 day master class. Finally a 3 day performance and monitoring workshop on 22- 24th June in London...(read more)

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• Unix mail question

  - by InBetween

  I'm wondering where some information came from in a message I got on my Mac laptop. Here's the message: From [email protected] X-Original-To: john Delivered-To: [email protected] From: [email protected] (Cron Daemon) To: [email protected] ... Where did it get the "[email protected]" I know my username is john, and my computer is leutenberg, but where did it get the horners.org part? Thanks.

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• Webcast: John Fowler Reveals The Next Step In Data Center Consolidation – June 27 At 10 AM PT

  - by Roxana Babiciu

  Completely integrated solutions are just better. But don't take our word for it - encourage your customers and prospects to join this live webcast featuring Oracle EVP John Fowler to find out why. Participants will learn how consolidating their existing data center to this new generation of solutions will simplify architectures, jump start application deployment and improve system performance - with easy self-service and private cloud capabilities.

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• JavaScript Class Patterns

  - by Liam McLennan

  To write object-oriented programs we need objects, and likely lots of them. JavaScript makes it easy to create objects: var liam = { name: "Liam", age: Number.MAX_VALUE }; But JavaScript does not provide an easy way to create similar objects. Most object-oriented languages include the idea of a class, which is a template for creating objects of the same type. From one class many similar objects can be instantiated. Many patterns have been proposed to address the absence of a class concept in JavaScript. This post will compare and contrast the most significant of them. Simple Constructor Functions Classes may be missing but JavaScript does support special constructor functions. By prefixing a call to a constructor function with the ‘new’ keyword we can tell the JavaScript runtime that we want the function to behave like a constructor and instantiate a new object containing the members defined by that function. Within a constructor function the ‘this’ keyword references the new object being created -  so a basic constructor function might be: function Person(name, age) { this.name = name; this.age = age; this.toString = function() { return this.name + " is " + age + " years old."; }; } var john = new Person("John Galt", 50); console.log(john.toString()); Note that by convention the name of a constructor function is always written in Pascal Case (the first letter of each word is capital). This is to distinguish between constructor functions and other functions. It is important that constructor functions be called with the ‘new’ keyword and that not constructor functions are not. There are two problems with the pattern constructor function pattern shown above: It makes inheritance difficult The toString() function is redefined for each new object created by the Person constructor. This is sub-optimal because the function should be shared between all of the instances of the Person type. Constructor Functions with a Prototype JavaScript functions have a special property called prototype. When an object is created by calling a JavaScript constructor all of the properties of the constructor’s prototype become available to the new object. In this way many Person objects can be created that can access the same prototype. An improved version of the above example can be written: function Person(name, age) { this.name = name; this.age = age; } Person.prototype = { toString: function() { return this.name + " is " + this.age + " years old."; } }; var john = new Person("John Galt", 50); console.log(john.toString()); In this version a single instance of the toString() function will now be shared between all Person objects. Private Members The short version is: there aren’t any. If a variable is defined, with the var keyword, within the constructor function then its scope is that function. Other functions defined within the constructor function will be able to access the private variable, but anything defined outside the constructor (such as functions on the prototype property) won’t have access to the private variable. Any variables defined on the constructor are automatically public. Some people solve this problem by prefixing properties with an underscore and then not calling those properties by convention. function Person(name, age) { this.name = name; this.age = age; } Person.prototype = { _getName: function() { return this.name; }, toString: function() { return this._getName() + " is " + this.age + " years old."; } }; var john = new Person("John Galt", 50); console.log(john.toString()); Note that the _getName() function is only private by convention – it is in fact a public function. Functional Object Construction Because of the weirdness involved in using constructor functions some JavaScript developers prefer to eschew them completely. They theorize that it is better to work with JavaScript’s functional nature than to try and force it to behave like a traditional class-oriented language. When using the functional approach objects are created by returning them from a factory function. An excellent side effect of this pattern is that variables defined with the factory function are accessible to the new object (due to closure) but are inaccessible from anywhere else. The Person example implemented using the functional object construction pattern is: var john = new Person("John Galt", 50); console.log(john.toString()); var personFactory = function(name, age) { var privateVar = 7; return { toString: function() { return name + " is " + age * privateVar / privateVar + " years old."; } }; }; var john2 = personFactory("John Lennon", 40); console.log(john2.toString()); Note that the ‘new’ keyword is not used for this pattern, and that the toString() function has access to the name, age and privateVar variables because of closure. This pattern can be extended to provide inheritance and, unlike the constructor function pattern, it supports private variables. However, when working with JavaScript code bases you will find that the constructor function is more common – probably because it is a better approximation of mainstream class oriented languages like C# and Java. Inheritance Both of the above patterns can support inheritance but for now, favour composition over inheritance. Summary When JavaScript code exceeds simple browser automation object orientation can provide a powerful paradigm for controlling complexity. Both of the patterns presented in this article work – the choice is a matter of style. Only one question still remains; who is John Galt?

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• the best way to convert delimited to fixed width

  - by ehosca

  What is the BEST way to convert this : FirstName,LastName,Title,BirthDate,HireDate,City,Region Nancy,Davolio,Sales Representative,1948-12-08,1992-05-01,Seattle,WA Andrew,Fuller,Vice President Sales,1952-02-19,1992-08-14,Tacoma,WA Janet,Leverling,Sales Representative,1963-08-30,1992-04-01,Kirkland,WA Margaret,Peacock,Sales Representative,1937-09-19,1993-05-03,Redmond,WA Steven,Buchanan,Sales Manager,1955-03-04,1993-10-17,London,NULL Michael,Suyama,Sales Representative,1963-07-02,1993-10-17,London,NULL Robert,King,Sales Representative,1960-05-29,1994-01-02,London,NULL Laura,Callahan,Inside Sales Coordinator,1958-01-09,1994-03-05,Seattle,WA Anne,Dodsworth,Sales Representative,1966-01-27,1994-11-15,London,NULL to this : FirstName LastName Title BirthDate HireDate City Region ---------- -------------------- ------------------------------ ----------- ---------- --------------- --------------- Nancy Davolio Sales Representative 1948-12-08 1992-05-01 Seattle WA Andrew Fuller Vice President, Sales 1952-02-19 1992-08-14 Tacoma WA Janet Leverling Sales Representative 1963-08-30 1992-04-01 Kirkland WA Margaret Peacock Sales Representative 1937-09-19 1993-05-03 Redmond WA Steven Buchanan Sales Manager 1955-03-04 1993-10-17 London NULL Michael Suyama Sales Representative 1963-07-02 1993-10-17 London NULL Robert King Sales Representative 1960-05-29 1994-01-02 London NULL Laura Callahan Inside Sales Coordinator 1958-01-09 1994-03-05 Seattle WA Anne Dodsworth Sales Representative 1966-01-27 1994-11-15 London NULL

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• Convince developer to use IDE

  - by artjom

  There is a developer, lets call him John (currently on probationary period) in company(pretty small company approx. 10 persons, 3 developers, one of them works long in this company know business process around and can be consider as Team leader) who didn't want to use any IDE at all(he is using some text editor). Application this team working on is medium size Java application with Spring Hibernate technology stack and refactoring/adding new features to launch new version of that application in near future. John performance working without IDE on this application is lower then desirable, team leader's (lets call him Bill) assumption is this happens because John is not using IDE. Bill try to persuade John to use IDE, but this idea meets a lot of resistance and main reason is "I want to be in total control of what I am doing, so I need to write all code by myself". How can Bill convince John to try to use IDE? (considering the fact what Bill already protected John from company owner several complaints about John performance)

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• Search 2 Columns with 1 Input Field

  - by Norbert

  I have a db with two columns: first name and last name. The first name can have multiple words. Last name can contain hyphenated words. Is there a way to search both columns with only one input box? Database ID `First Name` `Last Name` 1 John Peter Doe 2 John Fubar 3 Michael Doe Search john peter returns id 1 john returns id 1,2 doe returns id 1,3 john doe returns id 1 peter john returns id 1 peter doe returns id 1 doe john returns id 1 I previously tried the following. Searching for John Doe: SELECT * FROM names WHERE ( `first` LIKE '%john%' OR `first` LIKE '%doe%' OR `last` LIKE '%john%' OR `last` LIKE '%doe%' ) which returns both 1 and 3

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• Save the dates &ndash; Tech.Days 2011 23rd to 25th of May in London

  - by Eric Nelson

  In May Microsoft UK (and specifically my group) will be delivering Tech.Days – a week of day long technical events plus evening activities. We will be covering Windows Phone 7, Silverlight, IE 9, Windows Azure Platform and more. I’m working right now on the details of what we will be covering around the Windows Azure Platform – and it is shaping up very nicely. There is a little more detail over on TechNet – but for the moment, keep the dates clear if you can. P.S. I think the above is called a “teaser” in marketing speak.

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• New London based .NET User Group &ndash; first meeting June 2nd on MEF

  - by Eric Nelson

  A new .NET User Group is starting up in Canary Wharf - CWDNUG. It plans to focus on technology for financial services such as: WPF & Silverlight. F# & other alternative languages. High volume systems & complex event processing. Agile tools, methodologies and experiences. Open source systems that you can use (or that need your help!). Upcoming releases from Microsoft (WP7, VS2010, TPL). The first meeting is on June 2nd and Marlon (WPF MVP) will be speaking about MEF. Register today as there are only 15 spots left :-) (as of Thursday 20th May)

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• "ldap_add: Naming violation (64)" error when configuring OpenLDAP

  - by user3215

  I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: john[email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

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• How to Configure OpenLDAP on Ubuntu 10.04 Server

  - by user3215

  I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: john[email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

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• How to configure ldap on ubuntu 10.04 server

  - by user3215

  I am following the link to configure ldap on ubuntu 10.04 server but could not. when I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: john[email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Anybody could help me?

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• Select From MySQL PHP

  - by Liju

  Sir, I have one Database Table named "table1" with 8 column, that is Date, Time, Name, t1, t2, t3, t4, t5. I want to update the same table like the following... my existing table:- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 10/11/2010 09:00 bob 10/11/2010 10:00 bob 10/11/2010 13:00 bob 10/11/2010 10:00 john 10/11/2010 12:00 john 10/11/2010 14:00 john 12/11/2010 08:00 bob 12/11/2010 09:00 bob 12/11/2010 10:00 bob 12/11/2010 13:00 bob 12/11/2010 10:00 john 12/11/2010 12:00 john 12/11/2010 14:00 john 12/11/2010 16:00 john I want to update this as follows :- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 08:00 09:00 10:00 13:00 10/11/2010 10:00 john 10:00 12:00 14:00 12/11/2010 08:00 bob 08:00 09:00 10:00 13:00 12/11/2010 10:00 john 10:00 12:00 14:00 16:00 is it posible to update like this please help me.. Liju

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• Select and copy to MySQL table PHP

  - by Liju

  Can insert the table1 value to Table2 like the follows.. based on Name Date. Table1 Id Date Name time 1 20/11/2010 Tom 08:00 2 20/11/2010 Tom 08:30 3 20/11/2010 Tom 09:00 4 20/11/2010 Tom 09:30 5 20/11/2010 Tom 10:00 6 20/11/2010 Tom 10:30 7 20/11/2010 Tom 11:30 8 20/11/2010 Tom 14:30 9 20/11/2010 John 08:10 10 20/11/2010 John 09:30 11 20/11/2010 John 11:00 12 20/11/2010 John 13:00 13 20/11/2010 John 14:30 14 20/11/2010 John 16:00 15 20/11/2010 John 17:30 16 20/11/2010 John 19:00 17 20/11/2010 Ram 08:05 18 20/11/2010 Ram 08:30 19 20/11/2010 Ram 09:00 20 20/11/2010 Ram 09:45 21 20/11/2010 Ram 12:00 22 20/11/2010 Ram 13:30 23 20/11/2010 Ram 15:00 Table2 Id Date Name Time In1 Time Out1 Time In1 Time Out1 Time In1 Time Out1 Time In4 Time Out4 1 20/11/2010 Tom 08:00 08:30 09:00 09:30 10:00 10:30 11:30 14:30 2 20/11/2011 John 08:10 09:30 11:00 13:00 14:30 16:00 17:30 19:00 3 20/11/2012 Ram 08:05 08:30 09:00 09:45 12:00 13:30 15:00 Null Help me Please... Liju

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• backlink anchor text / keyword stratergy post penguin

  - by sam

  Ive heard allot recently about over optimisation regarding backlink anchor text ofsite. What ive heard from seomoz was sites most effected by the penguin update had over 60% of their backlinks anchor text the same, so google saw this is unnatural and penalized them. Which kind of makes sense as its not normal to have such high density on one word / phrase. If i where building links for a gastro pub in london. (this is purely hypothetical). The sort of keywords i would go after are "gastro pub in london" and "london gastro pub" If i where to mix up the anchor text by having: gastro pub gastro pub in london london gastro pub would this be seen as ok ? or would these all be seen as broad match keywords and counted as one phrase, making me fall foul of the penguin update ?

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• How to reliably synchronise file servers between London and Shanghai?

  - by Andy S

  We have two offices, one in London and one in Shanghai, each needing to be able to access the same set of files. This means we need a solid, speedy means of synchronising a set of folders between servers at either office. They're likely to be Windows servers, but we could look at Linux boxes if the software side makes more sense on *nix. We've considered Rsync, Unison, Gluster, and a few other options, but none of them seem capable of reliably keeping the servers in sync between such distant office locations. Each office is on DSL connectivity over the open internet, so encryption is also a factor. Does anyone have any hints for getting the servers synchronising in as close to real time as possible, without dying constantly? Andy

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• change owner/uid of mount point upon mount

  - by Shiplu

  The scenario is like this. Bob has a computer. It crashed. Now he only has the hdd. The hdd is in ext3 format. He go to his office and told the sys admin John to mount this hdd and put the mount point in his home directory. John used the following fstab entries. # Bobs harddisk /media/TAPE4/Bobs-hdd.img /home/bob/myhdd/windows ntfs ro,loop,offset=32256 0 0 /media/TAPE4/Bobs-hdd.img /home/bob/myhdd/linux ext3 ro,loop,offset=14048810496 0 0 /media/TAPE4/Bobs-hdd.img /home/bob/myhdd/extra ntfs ro,loop,offset=28015335936 0 0 Bob was happy. He could access his old extra and windows. Specially the Documents and Settings in windows was helpful for him. But he found a problem. He is a web developer and all his websites are in linux/home/bob/public_html directory. When he tried to access that public_html directory he got permission_denied. He executed ls -lh he saw this. drwxr-xr-x 2 john john 4.0K Nov 9 2011 Desktop drwxr-xr-x 3 john john 4.0K Aug 12 2011 Documents drwxr-xr-x 3 john john 4.0K Aug 21 2011 public_html He contacted John thinking he might be mistakenly did this. But John couldn't find a way why this happend? Then one thing came into his mind file system hardly store username. They store uids. So he executed ls -ln drwxr-xr-x 2 1000 1000 4096 Nov 9 2011 Desktop drwxr-xr-x 3 1000 1000 4096 Aug 12 2011 Documents drwxr-xr-x 3 1000 1000 4096 Aug 21 2011 public_html John thinks 1000 is the first uid on a linux system. As he is the admin of the current system. He created his account first. so Johns uid was 1000. Bob also setup his private system and crated his account first. So Bobs uid was 1000 too. So thats an expected behavior. But problem remains. How can Bob access those websites in public_html?

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• Looking for equivalent of ProxyPassReverseMatch in Apache to fix missing trailing forward slash issue

  - by Alex Man

  I have two web servers, www.example.com and www.userdir.com. I'm trying to make www.example.com as the front end proxy server to serve requests like in the format of http://www.example.com/~username such as http://www.example.com/~john/ so that it sends an internal request of http://www.userdir.com/~john/ to www.userdir.com. I can achieve this in Apache with ProxyPass /~john http://www.userdir.com/~john ProxyPassReverse /~john http://www.userdir.com/~john The ProxyPassReverse is necessary as without it a request like http://www.example.com/~john without the trailing forward slash will be redirected as http://www.userdir.com/~john/ and I want my users to stay in the example.com space. Now, my problem is that I have a lot of users and I cannot list all those user names in httpd.conf. So, I use ProxyPassMatch ^(/~.*)$ http://www.userdir.com$1 but there is no such thing as ProxyPassReverseMatch in Apache. Without it, whenever the trailing forward slash is missing in the URL, one will be directed to www.userdir.com, and that's not what I want. I also tried the following to add the trailing forward slash RewriteCond %{REQUEST_URI} ^/~[^./]*$ RewriteRule ^/(.*)$ http://www.userdir.com/$1/ [P] but then it will render a page with broken image and CSS because they are linked to http://www.example.com/images/image.gif while it should be http://www.example.com/~john/images/image.gif. I have been googling for a long time and still can't figure out a good solution for this. Would really appreciate it if any one can shed some light on this issue. Thank you!

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