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  • PHP math gets crazy, need explanation, my brain is melting

    - by derei
    I know that playing with php float can give strange results if you try to add "goats + apples", but please take a look to the following case: $val = 1232.81; $p1 = 1217.16; $p2 = 15.65; $sum = $p1 + $p2; $dif = $val - $sum; echo $dif; It will give you -2.2737367544323E-13 ... yeah, ALMOST zero, but then why it doesn't say 0 ? This freaks me out big time. Please, I need some valid explanation.

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  • Step math function

    - by ekapek
    Hi I need function which returns: for any number from range = result [0.001,0.01) => 0.01 [0.01,0.1) => 0.1 [0.1,1) => 1 [1,10) => 10 [10,100) => 100 etc. My first idea was to use if, but this the worst way. Is there a simple solution?

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  • Math Looping Between Min and Max Using Mod?

    - by TheDarkIn1978
    i'm attempting to build a tiny (or perhaps not so tiny) formula that will contain numbers between a set min and max, but also loop these numbers so they are not clipped if they are outside of the range. so far, this is what i have. min1 = 10 max1 = 90 val1 = 92 //will make 12, which is what i want since it loops formula: min(max(min1,min(val1,max1)),mod(val1,max1)+min1) however, i'd like it to loop the other direction also, so that if val1 is 5, which is -5 outside of min1, it will become 85. another problem i'm running into is that max1 % max1 != max1 as i want it to, since the max is part of the range trying to be clear, here are some examples of desired output based on a range with looping min1 = 10 max1 = 90 ---------------------------------------------- val1 = 30 //within range: stays as 30 val1 = 90 //within range: stays as 90 val1 = -6 //below range: loops to becomes 84 val1 = 98 //above range: loops to becomes 18 i'd like not to resort to using a series of if/else statements, but one would be fine if it's absolutely required. is that even possible?

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  • Delphi Math: Why is 0.7<0.70?

    - by Al C
    If I have variables a, b, an c of type double, let c:=a/b, and give a and b values of 7 and 10, then c's value of 0.7 registers as being LESS THAN 0.70. On the other hand, if the variables are all type extended, then c's value of 0.7 does not register as being less than 0.70. This seems strange. What information am I missing?

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  • Math Mod Containing Numbers

    - by TheDarkIn1978
    i would like to write a simple line of code, without resorting to if statements, that would evaluate whether a number is within a certain range. i can evaluate from 0 - Max by using the modulus. 30 % 90 = 30 //great however, if the test number is greater than the maximum, using modulus will simply start it at 0 for the remaining, where as i would like to limit it to the maximum if it's past the maximum 94 % 90 = 4 //i would like answer to be 90 it becomes even more complicated, to me anyway, if i introduce a minimum for the range. for example: minimum = 10 maximum = 90 therefore, any number i evaluate should be either within range, or the minimum value if it's below range and the maximum value if it's above range -76 should be 10 2 should be 10 30 should be 30 89 should be 89 98 should be 90 23553 should be 90 is it possible to evaluate this with one line of code without using if statements?

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  • [MATH]Project an axis to a plane

    - by Robert
    how do i project the X axis to a plane if the plane is defined by three points? see pic here: http://129.25.16.135:2080/v6.5/books/usb/graphics/iconventions-local-surfaces.png The default local 1-direction is the projection of the global x-axis onto the surface. If the global x-axis is within 0.1° of being normal to the surface, the local 1-direction is the projection of the global z-axis onto the surface. let's suppose that these points are: t1 = [-0.362879991531372, 0.357021987438202, -0.373737007379532] t2 = [-0.383525013923645, 0.371621012687683, -0.383549988269806] t3 = [-0.383534014225006, 0.34629300236702, -0.38544899225235] is the vector [0.78280971952246, -0.0307519963686645, 0.411184845614438] correct answer in this case? i've calculated the angle between the surf and x (1,0,0) is ~28°. and can you give the entire procedure for the calculation, because i'm just puzzled.

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  • optimization math computation (multiplication and summing)

    - by wiso
    Suppose you want to compute the sum of the square of the differences of items: $\sum_{i=1}^{N-1} (x_i - x_{i+1})^2$, the simplest code (the input is std::vector<double> xs, the ouput sum2) is: double sum2 = 0.; double prev = xs[0]; for (vector::const_iterator i = xs.begin() + 1; i != xs.end(); ++i) { sum2 += (prev - (*i)) * (prev - (*i)); // only 1 - with compiler optimization prev = (*i); } I hope that the compiler do the optimization in the comment above. If N is the length of xs you have N-1 multiplications and 2N-3 sums (sums means + or -). Now suppose you know this variable: sum = $x_1^2 + x_N^2 + 2 sum_{i=2}^{N-1} x_i^2$ Expanding the binomial square: $sum_i^{N-1} (x_i-x_{i+1})^2 = sum - 2\sum_{i=1}^{N-1} x_i x_{i+1}$ so the code becomes: double sum2 = 0.; double prev = xs[0]; for (vector::const_iterator i = xs.begin() + 1; i != xs.end(); ++i) { sum2 += (*i) * prev; prev = (*i); } sum2 = -sum2 * 2. + sum; Here I have N multiplications and N-1 additions. In my case N is about 100. Well, compiling with g++ -O2 I got no speed up (I try calling the inlined function 2M times), why?

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  • PHP Math issue with negatives [closed]

    - by user1269625
    Possible Duplicate: PHP negatives keep adding I have this code here.... $remaining = 0; foreach($array as $value=>$row){ $remaining = $remaining + $row['remainingbalance']; } What its doing is that it is going through all the remaining balances in the array which are -51.75 and -17.85 with the code above I get -69.60 which is correct. But I am wondering how when its two negatives if they could subtract? Is that possible? I tried this $remaining = 0; foreach($clientArrayInvoice as $value=>$row){ $remaining = $remaining + abs($row['remainingbalance']); } but it gives me 69.60 without the negative. Anyone got any ideas? my goal is to take -51.75 and -17.85 and come up with -33.90 only when its a negative to do subtract. otherwise add

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  • Open Source Survey: Oracle Products on Top

    - by trond-arne.undheim
    Oracle continues to work with the open source community to bring the most innovative and productive software to market (more). Oracle products received the most votes in several key categories of the 2010 Linux Journal Reader's Choice Awards. With over 12,000 technologists reporting, these product earned top spots: Best Office Suite: OpenOffice.org Best Single Office Program: OpenOffice.org Writer Best Database: MySQL Best Virtualization Solution: VirtualBox "As the leading open source technology and service provider, Oracle continues to work with the community stakeholders to rapidly innovate many open source products for use in fully tested production environments," says Edward Screven, Oracle's chief corporate architect. "Supporting open source is important to Oracle and our customers, and we continue to invest in it." According to a recent report by the Linux Foundation, Oracle is one of the top ten contributors to the Linux Kernel. Oracle also contributes millions of lines of code to these important projects: OpenJDK: 7,002,579 Eclipse: 1,800,000 (#3 in active committers) MySQL: 5,073,113 NetBeans: 7,870,446 JSF: 701,980 Apache MyFaces Trinidad: 1,316,840 Hudson: 1,209,779 OpenOffice.org: 7,500,000

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  • Extending OpenOffice.org

    <b>The Linux Box: </b>"Statistically OpenOffice.org is used somewhere between 0.2% and 22% depending as to where you live. I am seeing more and more OOo use. My intention with this article is not to proselytize OOo, but instead to show some good ways to extend the use of OOo."

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  • Ten Years of OpenOffice.org

    <b>WorksWithU:</b> "But much more importantly, 2010 marks OpenOffice.org&#8217;s tenth year of existence. To celebrate, here&#8217;s a look&#8211;literally, because there are a lot of screenshots&#8211;at how OOo has evolved throughout the decade."

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  • Turbocharge OpenOffice.org Writer with AuthorSupportTool

    <b>Worldlabel:</b> "The AuthorSupportTool (AST) extension belongs to the latter category. AST not just adds some random features to OpenOffice.org Writer, it dramatically enhances the word processor&#8217;s functionality, turning it into a powerful tool for working on research papers and complex documents."

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  • Report: 8 Advanced OpenOffice.org Add-ons

    OpenOffice is the best cross-platform office productivity suite, but it misses a few popular features like a clipart gallery, Google Docs integration, PDF import, and more than basic templates. But they're out there if you know where to look, and Eric Geier shows the way.

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  • 8 Advanced OpenOffice.org Add-ons

    <b>Linux Planet:</b> "OpenOffice is the best cross-platform office productivity suite, but it misses a few popular features like a clipart gallery, Google Docs integration, PDF import, and more than basic templates. But they're out there if you know where to look, and Eric Geier shows the way."

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  • L'utilisation d'OpenOffice et LibreOffice en entreprise chute, Microsoft Office domine largement, selon un rapport de Forrester

    L'utilisation d'OpenOffice et LibreOffice en entreprise chute Microsoft Office domine largement, selon un rapport de ForresterLes suites bureautiques et de productivité Open Source Open Office et Libre Office font pâle figure devant Microsoft Office, selon un récent rapport publié par le cabinet d'analyse Forrester.L'étude de Forrester montre qu'Office 2010, la version d'Office qui a connu le plus fort taux d'adoption, domine largement dans les entreprises avec une part de marché de 85 %. Office...

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  • PDF Export in OpenOffice.org

    <b>Linux Journal:</b> "The latest versions of OpenOffice.org provide, for no cost, most of the features available in Acrobat Standard for $299 -- to say nothing of a few features that even Acrobat Pro Extended does not include even at $699."

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  • Small Business Software: OpenOffice.org vs. Google Docs

    <b>Small Business Computing:</b> "Microsoft is getting ready to ship Office 2010, but a lot of small businesses realize they don't need all the features (or licensing costs) that come with Microsoft Office. The front-runners for Office replacements are OpenOffice.org and Google Docs, but which one is right for your business?"

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  • Point inside Oriented Bounding Box?

    - by Milo
    I have an OBB2D class based on SAT. This is my point in OBB method: public boolean pointInside(float x, float y) { float newy = (float) (Math.sin(angle) * (y - center.y) + Math.cos(angle) * (x - center.x)); float newx = (float) (Math.cos(angle) * (x - center.x) - Math.sin(angle) * (y - center.y)); return (newy > center.y - (getHeight() / 2)) && (newy < center.y + (getHeight() / 2)) && (newx > center.x - (getWidth() / 2)) && (newx < center.x + (getWidth() / 2)); } public boolean pointInside(Vector2D v) { return pointInside(v.x,v.y); } Here is the rest of the class; the parts that pertain: public class OBB2D { private Vector2D projVec = new Vector2D(); private static Vector2D projAVec = new Vector2D(); private static Vector2D projBVec = new Vector2D(); private static Vector2D tempNormal = new Vector2D(); private Vector2D deltaVec = new Vector2D(); private ArrayList<Vector2D> collisionPoints = new ArrayList<Vector2D>(); // Corners of the box, where 0 is the lower left. private Vector2D corner[] = new Vector2D[4]; private Vector2D center = new Vector2D(); private Vector2D extents = new Vector2D(); private RectF boundingRect = new RectF(); private float angle; //Two edges of the box extended away from corner[0]. private Vector2D axis[] = new Vector2D[2]; private double origin[] = new double[2]; public OBB2D(float centerx, float centery, float w, float h, float angle) { for(int i = 0; i < corner.length; ++i) { corner[i] = new Vector2D(); } for(int i = 0; i < axis.length; ++i) { axis[i] = new Vector2D(); } set(centerx,centery,w,h,angle); } public OBB2D(float left, float top, float width, float height) { for(int i = 0; i < corner.length; ++i) { corner[i] = new Vector2D(); } for(int i = 0; i < axis.length; ++i) { axis[i] = new Vector2D(); } set(left + (width / 2), top + (height / 2),width,height,0.0f); } public void set(float centerx,float centery,float w, float h,float angle) { float vxx = (float)Math.cos(angle); float vxy = (float)Math.sin(angle); float vyx = (float)-Math.sin(angle); float vyy = (float)Math.cos(angle); vxx *= w / 2; vxy *= (w / 2); vyx *= (h / 2); vyy *= (h / 2); corner[0].x = centerx - vxx - vyx; corner[0].y = centery - vxy - vyy; corner[1].x = centerx + vxx - vyx; corner[1].y = centery + vxy - vyy; corner[2].x = centerx + vxx + vyx; corner[2].y = centery + vxy + vyy; corner[3].x = centerx - vxx + vyx; corner[3].y = centery - vxy + vyy; this.center.x = centerx; this.center.y = centery; this.angle = angle; computeAxes(); extents.x = w / 2; extents.y = h / 2; computeBoundingRect(); } //Updates the axes after the corners move. Assumes the //corners actually form a rectangle. private void computeAxes() { axis[0].x = corner[1].x - corner[0].x; axis[0].y = corner[1].y - corner[0].y; axis[1].x = corner[3].x - corner[0].x; axis[1].y = corner[3].y - corner[0].y; // Make the length of each axis 1/edge length so we know any // dot product must be less than 1 to fall within the edge. for (int a = 0; a < axis.length; ++a) { float l = axis[a].length(); float ll = l * l; axis[a].x = axis[a].x / ll; axis[a].y = axis[a].y / ll; origin[a] = corner[0].dot(axis[a]); } } public void computeBoundingRect() { boundingRect.left = JMath.min(JMath.min(corner[0].x, corner[3].x), JMath.min(corner[1].x, corner[2].x)); boundingRect.top = JMath.min(JMath.min(corner[0].y, corner[1].y),JMath.min(corner[2].y, corner[3].y)); boundingRect.right = JMath.max(JMath.max(corner[1].x, corner[2].x), JMath.max(corner[0].x, corner[3].x)); boundingRect.bottom = JMath.max(JMath.max(corner[2].y, corner[3].y),JMath.max(corner[0].y, corner[1].y)); } public void set(RectF rect) { set(rect.centerX(),rect.centerY(),rect.width(),rect.height(),0.0f); } // Returns true if other overlaps one dimension of this. private boolean overlaps1Way(OBB2D other) { for (int a = 0; a < axis.length; ++a) { double t = other.corner[0].dot(axis[a]); // Find the extent of box 2 on axis a double tMin = t; double tMax = t; for (int c = 1; c < corner.length; ++c) { t = other.corner[c].dot(axis[a]); if (t < tMin) { tMin = t; } else if (t > tMax) { tMax = t; } } // We have to subtract off the origin // See if [tMin, tMax] intersects [0, 1] if ((tMin > 1 + origin[a]) || (tMax < origin[a])) { // There was no intersection along this dimension; // the boxes cannot possibly overlap. return false; } } // There was no dimension along which there is no intersection. // Therefore the boxes overlap. return true; } public void moveTo(float centerx, float centery) { float cx,cy; cx = center.x; cy = center.y; deltaVec.x = centerx - cx; deltaVec.y = centery - cy; for (int c = 0; c < 4; ++c) { corner[c].x += deltaVec.x; corner[c].y += deltaVec.y; } boundingRect.left += deltaVec.x; boundingRect.top += deltaVec.y; boundingRect.right += deltaVec.x; boundingRect.bottom += deltaVec.y; this.center.x = centerx; this.center.y = centery; computeAxes(); } // Returns true if the intersection of the boxes is non-empty. public boolean overlaps(OBB2D other) { if(right() < other.left()) { return false; } if(bottom() < other.top()) { return false; } if(left() > other.right()) { return false; } if(top() > other.bottom()) { return false; } if(other.getAngle() == 0.0f && getAngle() == 0.0f) { return true; } return overlaps1Way(other) && other.overlaps1Way(this); } public Vector2D getCenter() { return center; } public float getWidth() { return extents.x * 2; } public float getHeight() { return extents.y * 2; } public void setAngle(float angle) { set(center.x,center.y,getWidth(),getHeight(),angle); } public float getAngle() { return angle; } public void setSize(float w,float h) { set(center.x,center.y,w,h,angle); } public float left() { return boundingRect.left; } public float right() { return boundingRect.right; } public float bottom() { return boundingRect.bottom; } public float top() { return boundingRect.top; } public RectF getBoundingRect() { return boundingRect; } public boolean overlaps(float left, float top, float right, float bottom) { if(right() < left) { return false; } if(bottom() < top) { return false; } if(left() > right) { return false; } if(top() > bottom) { return false; } return true; } public static float distance(float ax, float ay,float bx, float by) { if (ax < bx) return bx - ay; else return ax - by; } public Vector2D project(float ax, float ay) { projVec.x = Float.MAX_VALUE; projVec.y = Float.MIN_VALUE; for (int i = 0; i < corner.length; ++i) { float dot = Vector2D.dot(corner[i].x,corner[i].y,ax,ay); projVec.x = JMath.min(dot, projVec.x); projVec.y = JMath.max(dot, projVec.y); } return projVec; } public Vector2D getCorner(int c) { return corner[c]; } public int getNumCorners() { return corner.length; } public boolean pointInside(float x, float y) { float newy = (float) (Math.sin(angle) * (y - center.y) + Math.cos(angle) * (x - center.x)); float newx = (float) (Math.cos(angle) * (x - center.x) - Math.sin(angle) * (y - center.y)); return (newy > center.y - (getHeight() / 2)) && (newy < center.y + (getHeight() / 2)) && (newx > center.x - (getWidth() / 2)) && (newx < center.x + (getWidth() / 2)); } public boolean pointInside(Vector2D v) { return pointInside(v.x,v.y); } public ArrayList<Vector2D> getCollsionPoints(OBB2D b) { collisionPoints.clear(); for(int i = 0; i < corner.length; ++i) { if(b.pointInside(corner[i])) { collisionPoints.add(corner[i]); } } for(int i = 0; i < b.corner.length; ++i) { if(pointInside(b.corner[i])) { collisionPoints.add(b.corner[i]); } } return collisionPoints; } }; What could be wrong? When I getCollisionPoints for 2 OBBs I know are penetrating, it returns no points. Thanks

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  • How can I do two columns in OpenOffice.org Writer?

    - by Sanoj
    I would like to structure my document with two columns in the middle of the page, and one column in the top and in the bottom. Like my example below. How can I do two columns like this in OpenOffice.org Writer? My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document My document

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  • Can you reference an entire column in OpenOffice Calc (like A:A in Excel)?

    - by Andy
    I'd like to refer to an entire column, like you can in Excel by using A:A. I found a discussion on the openoffice.org forums which is a few years old, and suggests there is/was no neat way to do it. The options presented are Use A1:A65536. Use OFFSET($A$1;0;0;65536;1) as the previous range may get altered if you insert or remove rows. Use Data - Define Range... to name the column range (but which for me still just equates to $A$1:$A$1048576). These approaches seem over-complicated and still don't achieve my goal perfectly. Does anyone know of a way? Thanks, Andy

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