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• Percentage calculation around 0.5 (0.4 = -20% and 0.6 = +20%)

  - by Micheal

  I'm in a strange situation where I have a value of 0.5 and I want to convert the values from 0.5 to 1 to be a percentage and from 0.5 to 0 to be a negative percentage. As it says in the title 0.4 should be -20%, 0.3 should be -40% and 0.1 should be -80%. I'm sure this is a simple problem, but my mind is just refusing to figure it out :) Can anyone help? :)

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• Calculation route length

  - by Paul Peelen

  Hi, I have a map with about 80 annotations. I would like to do 3 things. 1) From my current location, I would like to know the actual route distance to that position. Not the linear distance. 2) I want to be able to show a list of all the annotations, but for every annotation (having lon/lat) I would like to know the actual route distance from my position to that position. 3) I would like to know the closest annotation to my possition using route distance. Not linear distance. I think the answer to all these three points will be the same. But please keep in mind that I don't want to create a route, I just want to know the distance to the annotation. I hope someone can help me. Best regards, Paul Peelen

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• Temperature anomaly calculation of time series data

  - by neel

  I have a time series like following: Data <- structure(list(Year = c(1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L), Month = c(8L, 9L, 9L, 9L, 10L, 10L, 10L, 11L, 11L, 11L, 12L, 12L, 12L, 1L, 1L, 1L, 2L, 2L, 2L, 3L, 3L, 3L, 4L, 4L, 4L, 5L, 5L, 5L, 6L, 6L, 6L, 7L, 7L, 7L, 8L, 8L, 8L, 9L, 9L, 9L, 10L, 10L, 10L, 11L, 11L, 11L, 12L, 12L, 12L), Day = c(30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 28L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L), Hour = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), temperature = c(72.5, 64, 62.5, 64, 64, 53, 52, 52, 45.5, 49, 50, 50, 59, 63.5, 69.5, 61, 61, NaN, NaN, 39.5, 37, 45.5, 45, 39, 43.5, 52, 53, 56, 64, 66, 66.5, 73.5, 81, 85, 89.5, 87.5, 88.5, 83, 84.5, 74, 60.5, 59, 53, 60.5, 62.5, 64.5, 63, 62, 65.5)), .Names = c("Year", "Month", "Day", "Hour", "temperature"), class = "data.frame", row.names = c(NA, -49L)) and I have to calculate standardized anomaly. The steps to calculate the anomalies are following: Monthly premature departures from the long-term (1991-2007) average are obtained. Then standardized by dividing by the standard deviation of monthly temperature. The standardized monthly anomalies are then weighted by multiplying by the fraction of the average temperature for the given month. These weighted anomalies are then summed over 3 month time period. Can you please help me?

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• Calculation of charged traffic in GPRS network

  - by TyBoer

  I am working with a distributed application communicating over GPRS. I use UDP packets to send business data and ICMP pings to verify connectivity. And now I have a problem with calculating a traffic for which I will be charged by the provider. I have to consider following factors: UDP payload: that is obvious. UDP overhead: UDP header + IP header = 8 + 20 bytes. ICMP echo request without data: IP header + ICMP payload = 28 bytes. ICMP echo reply: as in 3. Above means that for evey data packet I am charged for payload + 28 bytes and for every ping 56 bytes. Am I right or I am missing/misunderstanding something?

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• Javascript/jQuery height calculation

  - by danit

  Im looking for a way, in javascript, to calculate the size of the browser (px) then calculate the size of a <div> taking away 50px from that full screen size: E.g. Browser screen size: 800px (Height) Existing <div> that is always 50px (Height) Leaves 750px (Height) for the remaining <div> to fill the page. Then take that 750px and apply it as inline style: <div style="height: 50px"> <img src="banner.png" /> </div> <div style="height: x"> This fills the remainder of the page </div>

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• MS Word Macro - Numeric field insertion with automatic calculation at end of page

  - by Will

  Hi, I am trying to duplicate a feature that exists in Multimate (Ashton Tate) word processor. Yes, the one that hasnt been supported for 20 years! If I can duplicate this one feature I can get all the users off MM and onto Word. The documents they create are billing documents. they consist of a descriptive paragraph of any length on the left side of the page, and a billing amount at the end of the paragraph over on the right hand side, like this (excuse the imperfect formatting).... +-----------------whole page--------------------+ |                                                                    | |    pppp-para 1-pppppppppp                   | |    p                                         p                   | |    p                                         p                   | |    p                                         p                   | |    p                                         p                   | |    p                                         p                   | |    p                                         p                   | |    pppppppppppppppppppp      $$$$$  | |                                                                    |  |                                                                    |  |    pppp-para 2-pppppppppp                   | |    p                                         p                   | |    p                                         p                   | |    p                                         p                   | |    p                                         p                   | |    p                                         p                   | |    p                                         p                   | |    pppppppppppppppppppp      $$$$$  | |                                                                    |  |                                                                    |  |                             etc                                  | +-----------------------------------------------------+ some of these bills can be a few hundred pages and have a dozen or so paragraphs on each page, which is why none of the users will leave MM until this efficient little feature can be duplicated. The thing that MM does really easily is that there is a function key that they can press at any time that will - - jump the cursor from the paragraph they are writing over to the right hand side - create a numeric field - allow them to enter a number into the numeric field - return them to the left hand side to start a new paragraph What MM also does is automatically total the numeric fields on each page and create a subtotal in the page footer. it also creates a total for the entire document and puts this in the footer of the last page. I would like to duplicate this feature in word with a macro, but have no idea where to start. Any suggestions or code would be great, thanks, will.

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• Python MD5 Hash Faster Calculation

  - by balgan

  Hi everyone. I will try my best to explain my problem and my line of thought on how I think I can solve it. I use this code for root, dirs, files in os.walk(downloaddir): for infile in files: f = open(os.path.join(root,infile),'rb') filehash = hashlib.md5() while True: data = f.read(10240) if len(data) == 0: break filehash.update(data) print "FILENAME: " , infile print "FILE HASH: " , filehash.hexdigest() and using start = time.time() elapsed = time.time() - start I measure how long it takes to calculate an hash. Pointing my code to a file with 653megs this is the result: root@Mars:/home/tiago# python algorithm-timer.py FILENAME: freebsd.iso FILE HASH: ace0afedfa7c6e0ad12c77b6652b02ab 12.624 root@Mars:/home/tiago# python algorithm-timer.py FILENAME: freebsd.iso FILE HASH: ace0afedfa7c6e0ad12c77b6652b02ab 12.373 root@Mars:/home/tiago# python algorithm-timer.py FILENAME: freebsd.iso FILE HASH: ace0afedfa7c6e0ad12c77b6652b02ab 12.540 Ok now 12 seconds +- on a 653mb file, my problem is I intend to use this code on a program that will run through multiple files, some of them might be 4/5/6Gb and it will take wayy longer to calculate. What am wondering is if there is a faster way for me to calculate the hash of the file? Maybe by doing some multithreading? I used a another script to check the use of the CPU second by second and I see that my code is only using 1 out of my 2 CPUs and only at 25% max, any way I can change this? Thank you all in advance for the given help.

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• UDP checksum calculation

  - by Deepak Konidena

  Hi, The UDP header struct defined at /usr/include/netinet/udp.h is as follows struct udphdr { u_int16_t source; u_int16_t dest; u_int16_t len; u_int16_t check; }; What value is stored in the check field of the header? How to verify if the checksum is correct? I meant on what data is the checksum computed? (Is it just the udp header or udp header plus the payload that follows it?) Thanks.

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• Calculation with RESTful web service with MySQL database

  - by Dobby

  I am now making some RESTful web services with MySQL database. I used NetBeans to create the resources of RESTful service with MySQL, and now I can now use GET and POST/PUT to list and add/modify data entities in the MySQL server. Currently, I wish to make some calculations right after a client makes the POST activities, then the posted data with calculated results will be inserted into the MySQL database. I am very new to this, I guess I need to add some functions and call them to calculate but I don't know where and how to do that : ( Could any one help me on this issue? Thanks a lot in advance! : )

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• An algorithm for pavement usage calculation

  - by student

  Given an area of specific size I need to find out how many pavement stones to use to completely pave the area. Suppose that I have an empty floor of 100 metre squares and stones with 20x10 cm and 30x10 cm sizes. I must pave the area with minimum usage of stones of both sizes. Anyone knows of an algorithm that calculates this? (Sorry if my English is bad) C# is preferred.

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• Optimization of running total calculation in SQL for multiple values per join condition

  - by Kiril

  I have the following table (test_table): date value --------------- d1 10.0 d1 20.0 d2 60.0 d2 10.0 d2 -20.0 d3 40.0 I calculate the running total as follows. I use the same query twice, because first I need to calculate the values for a specifi date, and afterwards I can calculate the running total. Otherwise, joining the two tables where date is not unique, I would get too many results from the join: SELECT t1.date, SUM(t2.value) AS total FROM (SELECT date, SUM(value) AS value FROM test_table GROUP BY date) AS t1 JOIN (SELECT date, SUM(value) AS value FROM test_table GROUP BY date) AS t2 ON t1.date >= t2.date GROUP BY t1.date ORDER BY t1.date This gives me (which is fine): date total ------------- d1 30.0 d2 80.0 d3 120.0 BUT, this query isn't very efficient, because I need to change conditions in two places, if necessary. In production, the test_table is a lot bigger ( 4 Mio. rows), and the query takes too much time to complete. Question: How can I avoid using the same query twice?

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• How to use Linq to group DateTime by month and days calculation

  - by Daoming Yang

  Hi all, I have two questions: First one: I have a order list and want to group them by the created month for the reports. Each order's created datetime will be like "2010-03-13 11:17:16.000" How can I make them only group by date like "2010-03"? Note: the DateCreated is the DateTime tpye The following code is not correct. var items = orderList.GroupBy(t => t.DateCreated.Month) .Select(g => new Order() { DateCreated = g.Key }) .OrderByDescending(x => x.OrderID).ToList(); Second one: Output the full months between two dates in C# If an user choose 2010-04-08 and 2010-06-04, I want to output the 2010-04-01 and 2010-06-30. I can always get the first day and last day of the months, but I want to find out some other options Many thanks. Many thanks.

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• Code optimization on minutes pr hour calculation

  - by corger

  Hi All, The following code takes a timeframe in minutes since midnight and creates an array with minutes pr hour. But, it's slow. Any better suggestions out there? (no, changing language is not an option :-) ) Const clDeparture As Long = 123 Const clArrival As Long = 233 Dim lHour As Long Dim lMinute As Long Dim alHour(25) As Long For lMinute = 0 To 1440 If lMinute >= clDeparture And lMinute < clArrival Then alHour(Int(lMinute / 60)) = alHour(Int(lMinute / 60)) + 1 End If Next The array should now contain: (0,0) (1,0) (2,57) (3,53) (4,0) ..... Regards

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• More complex view matrix calculation required to composite 3d models with 2d video

  - by lzcd

  I'm utilising some 2d / 3d tracking data (provided by pfHoe) to help integrate some 3d models into the playback of some 2d video. Things are working.... okay... but there's still some visible 'slipping' of the models against the video background and I suspect this is may be because the XNA CreatePerspective helper method isn't taking into account some of the additional data supplied by pfHoe such as independent horizontal / vertical field of view angles and focal length. Would anyone be able to point me towards some examples of constructing view matrices that include such details?

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• Doing will_paginate pages calculation around a record

  - by Anderson De Andrade

  I'm displaying a list of events. I wanted displayed the page with the events for today by default. That was easy accomplished by: page = number_of_records_before_RECORD / number_of_pages + 1 Now I want to display the first item of today's events as the first item in that page. Maybe there is a way to generate page numbers around a record with negative values to get back.

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• Haskell compile time function calculation

  - by egon

  I would like to precalculate values for a function at compile-time. Example (real function is more complex, didn't try compiling): base = 10 mymodulus n = n `mod` base -- or substitute with a function that takes -- too much to compute at runtime printmodules 0 = [mymodulus 0] printmodules z = (mymodulus z):(printmodules (z-1)) main = printmodules 64 I know that mymodulus n will be called only with n < 64 and I would like to precalculate mymodulus for n values of 0..64 at compile time. The reason is that mymodulus would be really expensive and will be reused multiple times.

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• Paypal IPN setup...Ship to Zipcode and auto calculation

  - by Kunal

  Hi I have successfully setup paypal IPN on my site and its working fine. From my paypal account I have set options to ass shipping and tax calculations(only if it's Iowa). But the only issue is, on the paypal checkout page it's asking me to enter the "Ship to Zipcode" manually...if I enter and update only then the net payable is getting updated with the shipping and tax charges. Is there any variable via which I could send the ship to zip code which will work directly on the cart and make it auto calculate the charges and show it? I have tried both "zip" and "address_zip" variables. None of them worked. By the way I have multiple items on my cart so I am using the "cart" transaction type. Thanks in advance for your help.

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• Excel UDF calculation should return 'original' value

  - by LeChe

  Hi all, I've been struggling with a VBA problem for a while now and I'll try to explain it as thoroughly as possible. I have created a VSTO plugin with my own RTD implementation that I am calling from my Excel sheets. To avoid having to use the full-fledged RTD syntax in the cells, I have created a UDF that hides that API from the sheet. The RTD server I created can be enabled and disabled through a button in a custom Ribbon component. The behavior I want to achieve is as follows: If the server is disabled and a reference to my function is entered in a cell, I want the cell to display Disabled If the server is disabled, but the function had been entered in a cell when it was enabled (and the cell thus displays a value), I want the cell to keep displaying that value If the server is enabled, I want the cell to display Loading Sounds easy enough. Here is an example of the - non functional - code: Public Function RetrieveData(id as Long) Dim result as String // This returns either 'Disabled' or 'Loading' result = Application.Worksheet.Function.RTD("SERVERNAME", "", id) RetrieveData = result If(result = "Disabled") Then // Obviously, this recurses (and fails), so that's not an option If(Not IsEmpty(Application.Caller.Value2)) Then // So does this RetrieveData = Application.Caller.Value2 End If End If End Function The function will be called in thousands of cells, so storing the 'original' values in another data structure would be a major overhead and I would like to avoid it. Also, the RTD server does not know the values, since it also does not keep a history of it, more or less for the same reason. I was thinking that there might be some way to exit the function which would force it to not change the displayed value, but so far I have been unable to find anything like that. Any ideas on how to solve this are greatly appreciated! Thanks, Che EDIT: By popular demand, some additional info on why I want to do all this: As I said, the function will be called in thousands of cells and the RTD server needs to retrieve quite a bit of information. This can be quite hard on both network and CPU. To allow the user to decide for himself whether he wants this load on his machine, he or she can disable the updates from the server. In that case, he or she should still be able to calculate the sheets with the values currently in the fields, yet no updates are pushed into them. Once new data is required, the server can be enabled and the fields will be updated. Again, since we are talking about quite a bit of data here, I would rather not store it somewhere in the sheet. Plus, the data should be usable even if the workbook is closed and loaded again.

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• Float compile-time calculation not happening?

  - by Klaim

  A little test program: #include <iostream> const float TEST_FLOAT = 1/60; const float TEST_A = 1; const float TEST_B = 60; const float TEST_C = TEST_A / TEST_B; int main() { std::cout << TEST_FLOAT << std::endl; std::cout << TEST_C << std::endl; std::cin.ignore(); return 0; } Result : 0 0.0166667 Tested on Visual Studio 2008 & 2010. I worked on other compilers that, if I remember well, made the first result like the second result. Now my memory could be wrong, but shouldn't TEST_FLOAT have the same value than TEST_C? If not, why? Is TEST_C value resolved at compile time or at runtime? I always assumed the former but now that I see those results I have some doubts...

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• recursion tree and binary tree cost calculation

  - by Tony

  Hi all, I've got the following recursion: T(n) = T(n/3) + T(2n/3) + O(n) The height of the tree would be log3/2 of 2. Now the recursion tree for this recurrence is not a complete binary tree. It has missing nodes lower down. This makes sense to me, however I don't understand how the following small omega notation relates to the cost of all leaves in the tree. "... the total cost of all leaves would then be Theta (n^log3/2 of 2) which, since log3/2 of 2 is a constant strictly greater then 1, is small omega(n lg n)." Can someone please help me understand how the Theta(n^log3/2 of 2) becomes small omega(n lg n)?

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• Optimal two variable linear regression calculation

  - by Dave Jarvis

  Problem Am looking to apply the y = mx + b equation (where m is SLOPE, b is INTERCEPT) to a data set, which is retrieved as shown in the SQL code. The values from the (MySQL) query are: SLOPE = 0.0276653965651912 INTERCEPT = -57.2338357550468 SQL Code SELECT ((sum(t.YEAR) * sum(t.AMOUNT)) - (count(1) * sum(t.YEAR * t.AMOUNT))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as SLOPE, ((sum( t.YEAR ) * sum( t.YEAR * t.AMOUNT )) - (sum( t.AMOUNT ) * sum(power(t.YEAR, 2)))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as INTERCEPT, FROM (SELECT D.AMOUNT, Y.YEAR FROM CITY C, STATION S, YEAR_REF Y, MONTH_REF M, DAILY D WHERE -- For a specific city ... -- C.ID = 8590 AND -- Find all the stations within a 15 unit radius ... -- SQRT( POW( C.LATITUDE - S.LATITUDE, 2 ) + POW( C.LONGITUDE - S.LONGITUDE, 2 ) ) < 15 AND -- Gather all known years for that station ... -- S.STATION_DISTRICT_ID = Y.STATION_DISTRICT_ID AND -- The data before 1900 is shaky; insufficient after 2009. -- Y.YEAR BETWEEN 1900 AND 2009 AND -- Filtered by all known months ... -- M.YEAR_REF_ID = Y.ID AND -- Whittled down by category ... -- M.CATEGORY_ID = '001' AND -- Into the valid daily climate data. -- M.ID = D.MONTH_REF_ID AND D.DAILY_FLAG_ID <> 'M' GROUP BY Y.YEAR ORDER BY Y.YEAR ) t Data The data is visualized here: Question The following results (to calculate the start and end points of the line) appear incorrect. Why are the results off by ~10 degrees (e.g., outliers skewing the data)? (1900 * 0.0276653965651912) + (-57.2338357550468) = -4.66958228 (2009 * 0.0276653965651912) + (-57.2338357550468) = -1.65405406 I would have expected the 1900 result to be around 10 (not -4.67) and the 2009 result to be around 11.50 (not -1.65). Related Sites Least absolute deviations Robust regression Thank you!

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• Efficient calculation of matrix cumulative standard deviation in r

  - by Abiel

  I recently posted this question on the r-help mailing list but got no answers, so I thought I would post it here as well and see if there were any suggestions. I am trying to calculate the cumulative standard deviation of a matrix. I want a function that accepts a matrix and returns a matrix of the same size where output cell (i,j) is set to the standard deviation of input column j between rows 1 and i. NAs should be ignored, unless cell (i,j) of the input matrix itself is NA, in which case cell (i,j) of the output matrix should also be NA. I could not find a built-in function, so I implemented the following code. Unfortunately, this uses a loop that ends up being somewhat slow for large matrices. Is there a faster built-in function or can someone suggest a better approach? cumsd <- function(mat) { retval <- mat*NA for (i in 2:nrow(mat)) retval[i,] <- sd(mat[1:i,], na.rm=T) retval[is.na(mat)] <- NA retval } Thanks.

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• Mips Data layout calculation

  - by Michael Z

  I am self studying computer architecture offer at Michigan university. I do not understand why the memory layout for d . Maybe I did not understanding the here well.

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• PL/SQL time segment calculation

  - by Steve

  Hi, I need to figure how much time passed between 2 times. For example: (14:00:00 - 13:15:00) * 24 = .75 I need this to later on convert KW to KWh, but that's not the point. I can not find out how to do this in PL/SQL. My date/time fields look like this in the DB: 1/23/2010 21:00:00 I would appreciate any suggestions. Steve

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• Python Ephem / Datetime calculation

  - by dassouki

  the output should process the first date as "day" and second as "night". I've been playing with this for a few hours now and can't figure out what I'm doing wrong. Any ideas? Edit I assume that the problem is due to my date comparison implementation Output: $ python time_of_day.py * should be day: event date: 2010/4/6 16:00:59 prev rising: 2010/4/6 09:24:24 prev setting: 2010/4/5 23:33:03 next rise: 2010/4/7 09:22:27 next set: 2010/4/6 23:34:27 day * should be night: event date: 2010/4/6 00:01:00 prev rising: 2010/4/5 09:26:22 prev setting: 2010/4/5 23:33:03 next rise: 2010/4/6 09:24:24 next set: 2010/4/6 23:34:27 day time_of_day.py import datetime import ephem # install from http://pypi.python.org/pypi/pyephem/ #event_time is just a date time corresponding to an sql timestamp def type_of_light(latitude, longitude, event_time, utc_time, horizon): o = ephem.Observer() o.lat, o.long, o.date, o.horizon = latitude, longitude, event_time, horizon print "event date ", o.date print "prev rising: ", o.previous_rising(ephem.Sun()) print "prev setting: ", o.previous_setting(ephem.Sun()) print "next rise: ", o.next_rising(ephem.Sun()) print "next set: ", o.next_setting(ephem.Sun()) if o.previous_rising(ephem.Sun()) <= o.date <= o.next_setting(ephem.Sun()): return "day" elif o.previous_setting(ephem.Sun()) <= o.date <= o.next_rising(ephem.Sun()): return "night" else: return "error" print "should be day: ", type_of_light('45.959','-66.6405','2010/4/6 16:01','-4', '-6') print "should be night: ", type_of_light('45.959','-66.6405','2010/4/6 00:01','-4', '-6')

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