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  • SQL: GROUP BY after JOIN without overriding rows?

    - by krismeld
    I have a table of basketball leagues, a table af teams and a table of players like this: LEAGUES ID | NAME | ------------------ 1 | NBA | 2 | ABA | TEAMS: ID | NAME | LEAGUE_ID ------------------------------ 20 | BULLS | 1 21 | KNICKS | 2 PLAYERS: ID | TEAM_ID | FIRST_NAME | LAST_NAME | --------------------------------------------- 1 | 21 | John | Starks | 2 | 21 | Patrick | Ewing | Given a League ID, I would like to retrieve all the players' names and their team ID from all the teams in that league, so I do this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 which returns: [0] => stdClass Object ( [team_id] => 21 [player_id] => 1 [first_name] => John [last_name] => Starks ) [1] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) + around 500 more objects... Since I will use this result to populate a dropdown menu for each team containing each team's list of players, I would like to group my result by team ID, so the loop to create these dropdowns will only have to cycle through each team ID instead of all 500+ players each time. But when I use the GROUP BY like this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 GROUP BY t.id it only returns one player from each team like this, overriding all the other players on the same team because of the use of the same column names. [0] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) [1] => stdClass Object ( [team_id] => 22 [player_id] => 31 [first_name] => Shawn [last_name] => Kemp ) etc... I would like to return something like this: [0] => stdClass Object ( [team_id] => 2 [player_id1] => 1 [first_name1] => John [last_name1] => Starks [player_id2] => 2 [first_name2] => Patrick [last_name2] => Ewing +10 more players from this team... ) +25 more teams... Is it possible somehow?

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  • SQL GROUP BY with "default values"

    - by Christoph Schiessl
    I'm trying to create SELECT statement with a GROUP BY clause, which should return "default values". Imagine the following simple MySQL table: CREATE TABLE `tracker` ( `id` INTEGER PRIMARY KEY auto_increment, `date` DATETIME NOT NULL, `customer_id` INTEGER NOT NULL ); The table contains only one record: INSERT INTO `tracker` (`date`, `customer_id`) VALUES('2010-05-03', 1); After wards I'm executing the following SQL query: SELECT DATE(`date`), COUNT(customer_id) FROM tracker WHERE DATE(`date`) >= '2010-05-01' AND DATE(`date`) <= '2010-05-05' GROUP BY DATE(`date`) ORDER BY DATE(`date`); And get the expected result set: +----+---------------------+-------------+ | id | date | customer_id | +----+---------------------+-------------+ | 1 | 2010-05-10 00:00:00 | 1 | +----+---------------------+-------------+ However, I would like the result set to look like this: +--------------+--------------------+ | DATE(`date`) | COUNT(customer_id) | +--------------+--------------------+ | 2010-05-01 | 0 | | 2010-05-02 | 0 | | 2010-05-03 | 1 | | 2010-05-04 | 0 | | 2010-05-05 | 0 | +--------------+--------------------+ Is it possible to achieve this behavior?

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  • Determining Cross Domain Active Directory Group Membership

    - by thecaptain0220
    I am currently working on a project where I need to query Active Directory to determine group membership of a user. I initially was locating the user and retrieving the memberOf attribute. The problem with this is that there is a domain and a child domain. The groups are universal groups so they can be used in both domains and they don't show up in the memberOf attribute. Unfortunately there doesn't seem to be much info around for Active Directory access with C++. Is there anyway to determine group membership in this case in C++?

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  • Nhibernate linq group by duplicate fields

    - by jaspion
    Hello, I have a simple query like: from e in endContratoRepository.GetAll() where e.Contrato.idContrato == contrato.idContrato && e.Volume.idVolume == 1 && group e by new { e.dpto.idDepartamento, e.centroCusto.idCentroCusto } into grp select new Entidade { Contagem = grp.Count(), centroCusto = grp.Key.idCentroCusto, dpto = grp.Key.idDepartamento } and the problem: The fields that are in the group by, are duplicated in the generated query. The fields centroCusto and dpto appears twice, so when I try to get the field centroCusto, I get dpto. Anyone know how to solve this? thanks a lot!

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  • MySQL GROUP BY with three tables

    - by Psaniko
    I have the following tables: posts (post_id, content, etc) comments (comment_id, post_id, content, etc) posts_categories (post_category_id, post_id, category_id) and this query: SELECT `p`.*, COUNT(comments.comment_id) AS cmts, posts_categories.*,comments.* FROM `posts` AS `p` LEFT JOIN `posts_categories` ON `p`.post_id = `posts_categories`.post_id LEFT JOIN `comments` ON `p`.post_id = `comments`.post_id GROUP BY `p`.`post_id` There are three comments on post_id=1 and four in total. In posts_categories there are two rows, both assigned to post_id=1. I have four rows in posts. But if I query the statement above I get a result of 6 for COUNT(comments.comment_id) at post_id=1. How is this possible? I guess the mistake is somewhere in the GROUP BY clause but I can't figure out where. Any suggestions?

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  • SELECT * , COUNT( * ) FROM GROUP BY ORDER BY DESC

    - by quanganh_developer
    I have a table like: gold gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-01-01 city1 | type 1 | 2012-02-02 city1 | type 1 | 2012-03-03 city2 | type 2 | 2012-01-01 city2 | type 2 | 2012-02-02 city2 | type 2 | 2012-03-03 city3 | type 3 | 2012-01-01 city3 | type 3 | 2012-02-02 city3 | type 3 | 2012-03-03 How can I get 1 last result order by gold_selltime desc each group by gold_city and gold_type I used this: SELECT * , COUNT( * ) FROM gold_2012 GROUP BY gold_type , gold_city ORDER BY gold_selltime DESC but it did work. I only have result like: gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-01-01 city2 | type 2 | 2012-01-01 city3 | type 3 | 2012-01-01 but I need it like: gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-03-03 city2 | type 2 | 2012-03-03 city3 | type 3 | 2012-03-03

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  • Concatenate and group multiple rows in Oracle

    - by user1693347
    Suppose I have a table like this: NAME GROUP name1 groupA name2 groupB name5 groupC name4 groupA name3 groupC I'd like to have a result like this: GROUP NAMES groupA name1,name4 groupB name2 groupC name3,name5 If there were only one column in the table, I could concatenate the records by doing the following, but with grouping in the context, I really don't have much idea. Any suggestion is welcome, thanks in advance! Concatatenating one column table: SELECT names FROM (SELECT SYS_CONNECT_BY_PATH(names,' ') names, level FROM name_table START WITH names = (SELECT names FROM name_table WHERE rownum = 1) CONNECT BY PRIOR names < names ORDER BY level DESC) WHERE rownum = 1

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  • Creative, busy Devoxx week

    - by JavaCecilia
    I got back from my first visit to the developer conference Devoxx in Antwerp. I can't describe the vibes of the conference, it was a developer amusement park, hackergartens, fact sessions, comic relief provided by Java Posse, James Bond and endless hallway discussions.All and all - I had a lot of fun, my main mission was to talk about Oracle's main focus for OpenJDK which besides development and bug fixing is making sure the infrastructure is working out for the full community. My focus was not to hang out at night club the Noxx, but that was came included in the package :)The London Java community leaders Ben Evans and Martijn Verburg are leading discussions in the community to lay out the necessary requirements for the infrastructure for build and test in the open. They called a first meeting at JavaOne gathering 25 people, including people from RedHat, IBM and Oracle. The second meeting at Devoxx included 14 participants and had representatives from Oracle and IBM. I hope we really can find a way to collaborate on this, making sure we deliver an efficient infrastructure for all engineers to contribute to OpenJDK with.My home in all of this was the BOF rooms and the sessions there meeting the JUG leaders, talking about OpenJDK infrastructure and celebrating the Duchess Duke Award together with the others. The restaurants in the area was slower than I've ever seen, so I missed out on Trisha Gee's brilliant replay of the workshop "The Problem with Women in IT - an Agile Approach" where she masterly leads the audience (a packed room, 50-50 gender distribution) to solve the problem of including more diversity in the developer community. A tough and sometimes sensitive topic where she manages to keep the discussion objective with a focus of improving the matter from a business perspective. Mattias Karlsson is organizing the Java developer conference Jfokus in Stockholm and was there talking to Andres Almires planning a Hackergarten with a possible inclusion of an OpenJDK bugathon. That would be really cool, especially as the Oracle Stockholm Java development office is just across the water from the Jfokus venue, some of the local JVM engineers will likely attend and assist, even though the bug smashing theme will likely be more starter level build warnings in Swing or langtools than fixing JVM bugs.I was really happy that I managed to catch a seat for the Java Posse live podcast "the Third Presidential Debate" a lot of nerd humor, a lot of beer, a lot of fun :) The new member Chet had a perfect dead pan delivery and now I just have to listen more to the podcasts! Can't get the most perfect joke out of my head, talking about beer "As my father always said: Better a bottle in front of me than a frontal lobotomy" - hilarious :)I attended the sessions delivered by my Stockholm office colleagues Marcus Lagergren (on dynamic languages on the jvm, JavaScript in particular) and Joel Borggrén-Franck (Annotations) and was happy to see the packed room and all the questions raised at the end.There's loads of stuff to write about the event, but just have to pace myself for now. It was a fantastic event, captain Stephan Janssen with crew should be really proud to provide this forum to the developer community!

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  • Top 5 Creative Link Building Practices For Your Website

    Link building packages are vital to the success of your website. It is not like the old movie says, "If you build it, they will come." Building your own website simply is not enough. In order to succeed, you need to fraternize with others that share your interests. Make sure that you do not come across amateurish.

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  • Grouping by property value and writing group members

    - by Will S
    I need to group the following list by the department value but am having trouble with the LINQ syntax. Here's my list of objects: var people = new List<Person> { new Person { name = "John", department = new List<fields> {new fields { name = "department", value = "IT"}}}, new Person { name = "Sally", department = new List<fields> {new fields { name = "department", value = "IT"}}}, new Person { name = "Bob", department = new List<fields> {new fields { name = "department", value = "Finance"}}}, new Person { name = "Wanda", department = new List<fields> {new fields { name = "department", value = "Finance"}}}, }; I've toyed around with grouping. This is as far as I've got: var query = from p in people from field in p.department where field.name == "department" group p by field.value into departments select new { Department = departments.Key, Name = departments }; So can iterate over the groups, but not sure how to list the Person names - foreach (var department in query) { Console.WriteLine("Department: {0}", department.Department); foreach (var foo in department.Department) { // ?? } } Any ideas on what to do better or how to list the names of the relevant departments?

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  • translate stored procedure - to Linq2SQL (count, max, group, orderby)

    - by Walter
    I've two tables (1:N) CREATE TABLE master (idMaster int identity (1,1) not null, TheName varchar( 100) null, constraint pk_master primary key(idMaster) clustered) and - CREATE TABLE lnk (idSlave int not null, idMaster int not null, constraint pk_lnk_master_slave(idSlave) primary key clustered) link between Master.idMaster and lnk.idMaster I've a SQL query: select max (master.idMaster) as idMaster, master.theName, count (lnk.idSlave) as freq from lnk inner join master ON lnk.idMaster = master.idMaster Group by master.theName order by freq desc, master.theName I need to translate this T-SQL query to a Linq-to-SQL statement, preferably in C#

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  • Better way to do SELECT with GROUP BY

    - by Luca Romagnoli
    Hi i've wrote a query that works: SELECT `comments`.* FROM `comments` RIGHT JOIN (SELECT MAX( id ) AS id, core_id, topic_id FROM comments GROUP BY core_id, topic_id order by id desc) comm ON comm.id = comments.id LIMIT 10 I want know if it is possible (and how) to rewrite it to get better performance. Thanks

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  • cakePHP and GROUP BY

    - by Lizard
    I am trying to solve a hopefully simple problem here is the query I am trying produce: SELECT `categories`.*, COUNT(`entities`.id) FROM `categories` LEFT JOIN `entities` ON (`categories`.`id` = `entities`.`category_id`) GROUP BY `categories`.`id` I am really struggling to do this is in cakePHP 1.2 How would/should I go about doing this... (I am using 'Containable' if that helps) Thanks in advance

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  • How to create entities in one Entity group ?

    - by Gopi
    I am building an app based on google app engine (Java) using JDO for persistence. Can someone give me an example or a point me to some code which shows persisting of multiple entities (of same type) using javax.jdo.PersistenceManager.makePersistentAll() within a transaction. Basically I need to understand how to put multiple entites in one Entity Group so that they can be saved using makePersistentAll() inside transaction.

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  • GROUP BY a date, with ordering by date.

    - by standard
    Take this simple query: SELECT DATE_FORMAT(someDate, '%y-%m-%d') as formattedDay FROM someTable GROUP BY formatterDay This will select rows from a table with only 1 row per date. How do I ensure that the row selected per date is the earliest for that date, without doing an ordered subquery in the FROM? Cheers

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  • MYSQL Select statment Order By with Group By

    - by mouthpiec
    I have the following simple SQL statment SELECT id, name, value_name, value_id FROM table GROUP BY id ORDER BY value_id DESC when grouping I would like to get the value_name and value_id of the tuple where the value_id is the biggest. The way it is i am getting the smallest value. For example 1, name1, valuename, 3 (where i know that there is a value_id of 5) Can you please help?

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  • Better mode for do a select with group by

    - by Luca Romagnoli
    Hi i've wrote a query that works: SELECT `comments`.* FROM `comments` RIGHT JOIN (SELECT MAX( id ) AS id, core_id, topic_id FROM comments GROUP BY core_id, topic_id order by id desc) comm ON comm.id = comments.id LIMIT 10 I want know if is possible and how rewrite it for get better performance. thanks

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  • sql - getting the id from a row based on a group by

    - by user85116
    Table A tableAID tableBID grade Table B tableBID name description Table A links to Table b from the tableBID found in both tables. If I want to find the row in Table A, which has the highest grade, for each row in Table B, I would write my query like this: select max(grade) from TableA group by tableBID However, I don't just want the grade, I want the grade plus id of that row.

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  • MySQL: group by and IF statement

    - by notset
    By default, parent_id = 0. I want to select all records with parent_id = 0 and only the last ones with parent_id 0. I tried this, but it didn't work: SELECT * FROM `articles` IF `parent_id` > 0 THEN GROUP BY `parent_id` HAVING COUNT(`parent_id`) >= 1 END; ORDER BY `time` DESC What could be the solution?

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  • Rails ActiveRecord friendly code from a Complex Join, Sum, and Group query

    - by Chad M
    PROBLEM Hello, I am having no luck trying to break down this SQL statement into ActiveRecord/Rails friendly code and I'd like to learn how I can avoid a find_by_sql statement in this situation. Scenario I have users that create audits when they perform an action. Each audit is of a specific audit_activity. Each audit_activity is worth a certain number of points, based on score_weight. I need to find the total scores of each user, based on their total accumulated audit_activity score_weights. Eventually I'll need to rank them which means adding a sort to this as well. My Code Here is my sql and simplified versions of the tables in question. Any thoughts? SQL with full column names (for clarity) SELECT users.id, u.email, SUM(audit_activity.score_weight) FROM users JOIN audits ON users.id = audits.user_id JOIN audit_activities ON audit_activities.id = audits.audit_activity_id GROUP BY users.id; Models: User, Audit, AuditActivity User fields: id, email class User < ActiveRecord::Base include Clearance::User has_many :audits end Audit fields: id, user_id, audit_activity_id class Audit < ActiveRecord::Base belongs_to :user belongs_to :audit_activity end AuditActivity fields: id, score_weight class AuditActivity < ActiveRecord::Base has_many :audits end Example Data Here is a set of SQL statements so you can play with similar data I'm working with and see what comes up when the concerned query is run. You should just be able to copy/paste the whole thing into a database query browser. CREATE TABLE users( id INTEGER NOT NULL, email TEXT (25), PRIMARY KEY (id) ); CREATE TABLE audits( id INTEGER NOT NULL, user_id INTEGER, audit_activity_id INTEGER, PRIMARY KEY (id) ); CREATE TABLE audit_activities( id INTEGER NOT NULL, score_weight INTEGER, PRIMARY KEY (id) ); INSERT INTO users(id, email) VALUES(1, "[email protected]"); INSERT INTO users(id, email) VALUES(2, "[email protected]"); INSERT INTO users(id, email) VALUES(3, "[email protected]"); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(1, 1, 1); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(2, 1, 2); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(3, 1, 1); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(4, 1, 3); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(5, 1, 1); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(6, 1, 4); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(7, 2, 4); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(8, 2, 4); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(9, 2, 4); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(10, 3, 3); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(11, 3, 2); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(12, 3, 2); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(13, 3, 2); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(14, 3, 3); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(15, 3, 1); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(16, 3, 1); INSERT INTO audit_activities(id, score_weight) VALUES(1, 1); INSERT INTO audit_activities(id, score_weight) VALUES(2, 2); INSERT INTO audit_activities(id, score_weight) VALUES(3, 7); INSERT INTO audit_activities(id, score_weight) VALUES(4, 11); The Query Again, here is the query. SELECT u.id, u.email, SUM(aa.score_weight) FROM users u JOIN audits a ON u.id = a.user_id JOIN audit_activities aa ON aa.id = a.audit_activity_id GROUP BY u.id; Many Thanks, Chad

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