Search Results

Search found 55517 results on 2221 pages for 'set intersection'.

Page 9/2221 | < Previous Page | 5 6 7 8 9 10 11 12 13 14 15 16  | Next Page >

  • How to set a Static Route on a Storage Node

    - by csoto
    To set up a host route to an IP address, here are the procedures for BUI and CLI. You need to know the destination, mask, interface and network. Note that, in this case, the values are just examples. CLI - Log into CLI and run the commands below: configuration net routing create set family=IPv4 set destination=203.246.186.80 set mask=32 set gateway=192.168.100.230 set interface=igb0 commit BUI - Log in to the web ui of the ZFSSA NAS head - Click Configuration - Network - Routing - (+) - In the popup window that will be displayed, enter the values accordingly on the popup window shown on the screenshot below: Any of the two above procedures should get your desired route in place.

    Read the article

  • Ray-triangle intersetion

    - by gamemaker
    Hello! How can I test intersesion ray and triangle, and if it exist how to get distance from ray origin to intersection point?? What optimization I can use, if in my program I've got to check 1 ray to ~10000 triangles ??

    Read the article

  • Intersection of Inner Polygons of MKPolygon being colored - iOS

    - by Josh Glick
    I am trying to create a fog of war style map where areas I have visited are uncovered and the rest of the map is "hidden". I am using a MKPolygonOverlay that covers the whole map and create inner polygons around all the locations I have visited. However in areas where these inner polygons overlap, that portion of the overlay is still being drawn. As a new user I can't post pictures but here is a link to the image: http://dl.dropbox.com/u/13815916/Screen%20Shot%202012-06-29%20at%204.40.20%20AM.png

    Read the article

  • WPF Coordinates of intersection from two Line objects

    - by Becky Franklin
    I have two Line objects in C# WPF, and I'm trying to construct a method to work out the coordinates at which the lines intersect (if at all). After giving myself a headache reminding myself of high school maths to do this, I can't work out how to map it into programming format - anyone know how to do this? Thanks very much, Becky

    Read the article

  • Intersection of two regular expressions

    - by Henry
    Hi, Im looking for function (PHP will be the best), which returns true whether exists string matches both regexpA and regexpB. Example 1: $regexpA = '[0-9]+'; $regexpB = '[0-9]{2,3}'; hasRegularsIntersection($regexpA,$regexpB) returns TRUE because '12' matches both regexps Example 2: $regexpA = '[0-9]+'; $regexpB = '[a-z]+'; hasRegularsIntersection($regexpA,$regexpB) returns FALSE because numbers never matches literals. Thanks for any suggestions how to solve this. Henry

    Read the article

  • Fast rectangle to rectangle intersection

    - by Jeremy Rudd
    What's a fast way to test if 2 rectangles are intersecting? A search on the internet came up with this one-liner (WOOT!), but I don't understand how to write it in Javascript, it seems to be written in an ancient form of C++. struct { LONG left; LONG top; LONG right; LONG bottom; } RECT; bool IntersectRect(const RECT * r1, const RECT * r2) { return ! ( r2->left > r1->right || r2->right left || r2->top > r1->bottom || r2->bottom top ); }

    Read the article

  • Intersection of sets Mongodb

    - by afvasd
    Hi everyone I am new to mongo, this is my db design: product := { name: str group: ref, comments: [ ref, ref, ref, ref ] } comments := { ... a bunch of comments stuff } tag := { _id: int, #Need this for online requests tag: str, products: [ {product: ref, score: float}, ... ], comments: [ {comment: ref, score: float}, ...], } So my usage pattern is: GIVEN a product, find comments that have certain tag and sort them accordingly. My current approach involves: Look for that tag object that has tag=myTag pull all the comments out, sorted look for that product where product.name=myProduct pull all the comments out (which are dbrefs by the way) loop through the result of 2, and checking if they are in 4, (this I can do a limit 10) etc. It's pretty inefficient. Any better methods?

    Read the article

  • Two parallel line segments intersection

    - by Judarkness
    I know there are many algorithms to verify whether two line segments are intersected. But once they encountered parallel condition, they just tell the user a big "No" and pretend there is no overlap, share end point, or end point collusion. I know I can can calculate the distance between 2 lines segments. If the distance is 0, check the end points located in the other line segments or not. And this means I have to use a lot of if else and && || conditions. This is not difficult, but my question is "Is there a trick( or mathematics) method to calculate this special parallel case?"

    Read the article

  • Cone-Line Segment Intersection 2D

    - by nophnoph
    Hi everyone, I would like to know is there any way to determine if a cone is intersecting with a (finite)line segment. The cone actually a circle located at P(x,y) with theta degree field of view and radius r. The simple visualization can be found here (sorry i can't post the picture here) I'm trying to do it in C# but I don't have any idea how to that, so for now this is what I'm doing : Check if the line segment is intersecting with the circle If the line segment is intersecting with the circle then I check every single point in the line segment using a function I found here. But I don't think this is the best way to do it. Does anyone have an idea? For additional info, I need this function to make some kind of simple vision simulator. Thanks in advance :)

    Read the article

  • Is there a way to intersect/diff a std::map and a std::set?

    - by Jack
    I'm wondering if there a way to intersect or make the differences between two structures defined as std::set<MyData*> and std::map<MyData*, MyValue> with standard algorithms (like std::set_intersect) The problem is that I need to compute the difference between the set and the keyset of the map but I would like to avoid reallocating it (since it's something that is done many times per second with large data structures). Is there a way to obtain a "key view" of the std::map? After all what I'm looking is to consider just the keys when doing the set operation so from an implementation point it should be possible but I haven't been able to find anything.

    Read the article

  • How to set density for each shape in PhysX 3.1

    - by hywei
    I'm using PhysX 3.1 as my game's physics engine. One requirement is that I need set different density for each shape(there are server shapes for my single rigid actor). I know that the shape's density can be set by NxShapeDesc::density in PhysX 2.8, but I can't find such interface in PhysX 3.1. I know that the mass properties can be set in PhysX 3.1 just as the snowman example in the SDK, but I don't know whether there exists a direct interface to set density for each shape.

    Read the article

  • Multiple Set Peer for VPN Failover

    - by Kyle Brandt
    I will have two Cisco routers at Location A serving the same internal networks, and one router in location B. Currently, I have one router in each location with a IPSec site-to-site tunnel connecting them. It looks something like: Location A: crypto map crypto-map-1 1 ipsec-isakmp description Tunnel to Location B set peer 12.12.12.12 set transform-set ESP-3DES-SHA match address internal-ips Location B: crypto map crypto-map-1 1 ipsec-isakmp description Tunnel to Location A set peer 11.11.11.11 set transform-set ESP-3DES-SHA match address internal-ips Can I achieve fail over by simply adding another set peer at location B?: Location A (New secondary Router, configuration on previous router stays the same): crypto map crypto-map-1 1 ipsec-isakmp description Tunnel to Location B set peer 12.12.12.12 set transform-set ESP-3DES-SHA match address internal-ips Location B (Configuration Changed): crypto map crypto-map-1 1 ipsec-isakmp description Tunnel to Location A set peer 11.11.11.11 ! 11.11.11.100 is the ip of the new second router at location A set peer 11.11.11.100 set transform-set ESP-3DES-SHA match address internal-ips Cisco Says: For crypto map entries created with the crypto map map-name seq-num ipsec-isakmp command, you can specify multiple peers by repeating this command. The peer that packets are actually sent to is determined by the last peer that the router heard from (received either traffic or a negotiation request from) for a given data flow. If the attempt fails with the first peer, Internet Key Exchange (IKE) tries the next peer on the crypto map list. But I don't fully understand that in the context of a failover scenerio (One of the routers as Location A blowing up).

    Read the article

  • std::set<T>::erase(key). What if key isn't there?

    - by Armen Tsirunyan
    if I erase an element from an std::set and pass the key, not the iterator, and the key isn't in the set right now, will an exception be thrown? The thing is every second sentence in the MSDN documentation says: "this does blah blah, but it doesn't conform to the standard". So I need to know the standard behaviour. I just couldn't find it in the standard. Redirecting to the relevant clause will do as well. Thanks.

    Read the article

  • Patch Set 11.2.0.2 for Win32 and Win64 now available

    - by Mike Dietrich
    Oracle Database Patch Set 11.2.0.2 for Windows (Patch: 10098816) is now available for download from support.oracle.com: Oracle Database 11.2.0.2 Patch Set for Windows 32bit Oracle Database 11.2.0.2 Patch Set for Windows 64bit Please keep in mind: It's a full install - you don't have to download 11.2.0.1 first, you can start right with 11.2.0.2 You'll get it just from support.oracle.com - no download from OTN or eDelivery as this is a patch set Installation will be done by default into a separate %ORACLE_HOME% .- and this is our strong recommendation. If you'd like to install into your existing 11.2.0.1 %ORACLE_HOME% then you'll have to detach your 11.2.0.1 home from the OUI inventory first (runInstaller -detachHome ORACLE_HOME=c:\orahomes\11.2.0), save the contents of ?\network\admin and ?\database, clean up, install 11.2.0.2 and copy the saved network\admin and \database content back. Btw, Oracle Database Patch Set 10.2.0.5 for HP-UX - Patch:8202632 is available for download as well since today.

    Read the article

  • How can I fix the "TERM environment variable not set" warning in eclipse

    - by Robert
    I'm running ubuntu 12.04 LTS and working with eclipse (juno) on a c++ project. I keep getting "TERM environment variable not set" in the console while trying to run the program. I realize this means the variable needs to get set. My question is what should it be set to and how do I set it? I've read that it should be 'xterm' in a few places. So I added export TERM=xterm in my .profile and while eclipse stopped giving me the warning, instead it would output unreadable garbage everynow and then (not a side effect of the program). It did display the program output but intermixed were weird characters. This leads me to believe it's not 'xterm' I should be setting TERM to. Or I'm setting it in an incorrect way. Any help is appreciated. Sample output: **TERM environment variable not set.** Please make a selection ----------------------- 1. Create a budget 2. Edit a budget 3. Display a budget 4. Save a budget 5. Load a budget 6. Exit What is your selection: 1 **TERM environment variable not set.** Enter the name of your budget: etc The program continues to execute as expected but the message is highly annoying As someone has commented, I do use system("clear") which is likely the source of the warning? Either way, is this likely just an eclipse issue or something I can fix in ubuntu/linux

    Read the article

  • Ruby on Rails: What are partial hash arguments and full set arguments?

    - by williamjones
    I'm using asserts_redirected_to in my unit tests, and I'm receiving this warning: DEPRECATION WARNING: Using assert_redirected_to with partial hash arguments is deprecated. Specify the full set arguments instead. What is a partial hash argument, and what is a full set argument? These aren't terms that I've seen used in the Rails community before, and the only relevant results I can find on Google for these are in reference to this deprecation warning. Here is my code: assert_redirected_to :controller => :user, :action => :search also tried: assert_redirected_to({:controller => :user, :action => :search}) I might have guessed that it feels I'm missing some parameters or something like that, but the API documentation explicitly says that not all parameters need to be included: http://rails.rubyonrails.org/classes/ActionController/Assertions/ResponseAssertions.html

    Read the article

  • Set iPhone Style Location Based Alerts On Your Android Device With Google Now

    - by Gopinath
    Location based alerts of iPhone are very useful. You can set an alert to popup as soon as you reach a specific location like “Pickup milk and eggs” when I’m near a grocery store. This feature was missing in Android for a long time, but last week at Google I/O conference Google released an update to Google Now which supports location based alerts. To setup a location based alert 1. Launch Google Now 2. Type or say add reminder 3. By default it shows time based alert interface, switch it location based by touching Location icon 4. Set reminder text, choose a location and touch Set reminder 5. Your alert is set now and as soon as you are close by the specified location, you’ll see an alert on your device. This is a nice feature and I’m using it quite often for the past couple of days.  There are couple of things missing from the current version of Google Now location based alerts– recurring alerts and ability to set alerts on leaving a specific location. It is not possible to recur location based alerts. You will be alerted only once as soon as you reach the location and it is not possible to repeat the alert next time you visit the location. Lets say you want to be reminded to say hi to friend’s parents whenever you are travelling close by their home. It does not work. The second missing feature is something basic and some how Google did not incorporate in their first iteration. Lets say you are at office now and you want to set up alert to pickup flowers when you leave office. Sounds like a simple use case for location based alerts right? But there is no way to set this type of alerts. Google Now alerts you as soon as you reach a location, but not when you leave a location. Do you have an Android that supports Google Now? If so what are your thoughts on location based alerts?

    Read the article

  • What is a simple C library for a set of integer sets?

    - by conradlee
    I've got to modify a C program and I need to include a set of unsigned integer sets. That is, I have millions of sets of integers (each of these integer sets contains between 3 and 100 integers), and I need to store these in some structure, lets call it the directory, that can in logarithmic time tell me whether a given integer set already exists in the directory. The only operations that need to be defined on the directory is lookup and insert. This would be easy in languages with built-in support for useful data structures, but I'm a foreigner to C and looking around on Google did (surprisingly) not answer my question satisfactorily. This project looks about right: http://uthash.sourceforge.net/ but I would need to come up with my own hash key generator. This is a standard, simple problem, so I hope there is a standard and simple solution.

    Read the article

  • How do I wrap a repeatbale set of elements in jQuery?

    - by Globalz
    In jQuery how would I go about wrapping a repeatable set of elements with a div? For example I have: img h4 p img h4 p img h4 p I need to wrap each img, h4, p set with a div class="container". So it will look like: <div> class="container" img h4 p </div> <div> class="container" img h4 p </div> <div> class="container" img h4 p </div> Any ideas on how I can achieve this as its driving me nuts! I keep getting nested div.containers! Thanks!

    Read the article

< Previous Page | 5 6 7 8 9 10 11 12 13 14 15 16  | Next Page >