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  • Why does Ubuntu 12.10 only see 8 cores?

    - by tunnuz
    In our lab we just bought a new machine with two 8-cores Intel(R) Xeon(R) CPU E5-2660 0 @ 2.20GHz processors which also support Hyper-Threading. I would expect Ubuntu to see 32 processing units, however it only detects 8 of them (the equivalent of just one processor with Hyper-Threading disabled). The bios correctly reports a total of 32 processing units. I am using Ubuntu 12.10 desktop 32 bit. Any idea about how to solve this?

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  • Unit turning in navmesh-based pathfinding

    - by Haddayn
    I'm working on an RTS game, and I'm using navmeshes for unit pathfinding. I do know how to find a general path within a navmesh, but how do you determine if the unit have enough space to turn? I have units of different shapes (mostly rectangles with different dimensions), and with different turn radii. Additionally some of units can turn in place, and some can move in reverse. So, how to find a path which unit can follow, considering that it can not rotate easily?

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  • FlyWeight

    You are developing some gaming software. Your write Web client and on each of response you are parsing entire XML to get your game Units. You have some set of types of Units, for example 50 different animals, but when you parse your XML you can get dozens of instances. Memory issue? - FLYWEIGHT will

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  • Formula to format a cell to subtract one decimal place from another cell and have the calculated results displayed

    - by user242618
    I have a value in one cell that has four decimal places, in the cell below, I have the metric conversion formula. I want the cell below, with the metric conversion formula to display one less decimal place than the cell above. For example, if the English measurement is .#### (4 decimal places), I need the conversion cell to display .### (3 decimal places) and if the English measurement is .### (3 decimal places), I need the conversion cell to display .### ( decimal places), and so on. How can I do this?

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  • Filter Queryset in Django inlineformset_factory

    - by Dave
    I am trying to use inlineformset_factory to generate a formset. My models are defined as: class Measurement(models.Model): subject = models.ForeignKey(Animal) experiment = models.ForeignKey(Experiment) assay = models.ForeignKey(Assay) values = models.CommaSeparatedIntegerField(blank=True, null=True) class Experiment(models.Model): date = models.DateField() notes = models.TextField(max_length = 500, blank=True) subjects= models.ManyToManyField(Subject) in my view i have: def add_measurement(request, experiment_id): experiment = get_object_or_404(Experiment, pk=experiment_id) MeasurementFormSet = inlineformset_factory(Experiment, Measurement, extra=10, exclude=('experiment')) if request.method == 'POST': formset = MeasurementFormSet(request.POST,instance=experiment) if formset.is_valid(): formset.save() return HttpResponseRedirect( experiment.get_absolute_url() ) else: formset = MeasurementFormSet(instance=experiment) return render_to_response("data_entry_form.html", {"formset": formset, "experiment": experiment }, context_instance=RequestContext(request)) but i want to restrict the Measurement.subject field to only subjects defined in the Experiment.subjects queryset. I have tried a couple of different ways of doing this but I am a little unsure what the best way to accomplish this is. I tried to over-ride the BaseInlineFormset class with a new queryset, but couldnt figure out how to correctly pass the experiment parameter.

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  • How to define an array inside a function in C?

    - by Arunav Dev
    So in my source file I have the folowin function: void update(state* old_state, state* measurement, uint32_t size) { state new_state[size]; //some function using measurement and old_state and returning the result in newstate arm_fadd_32(measurement,old_state,newstate,size); // rest of the code } Now the compiler throws an error saying that error#28:expression must have a constant value. I think it's due to the fact that even though inside the method the size local variable is not changing the compiler is expecting a constant while defining the size. I have tried the following: int const a = size; and then tried to reinitialize it says constant value is not known. I did some research in internet and it appears that there is no easier way without using malloc, which I don't want to since I am using the code for some embedded application. Is there a way to avoid this problem without really using malloc? Thanks in advance guys!

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  • Finding a shared HDD attached to the network from my F-13 machine

    - by Ramy
    Sorry for the slew of n00bie questions, but here is one more. I recently partitioned my 1.5TB harddrive according to this question I then bought this to attach the harddrive to my network. The problem is, how do I navigate to the hard drive to move files over the network to the HDD. should this be moved to serverfault? update: the disk isn't even showing up when i call "fdisk -l" (as root). How can I mount it if I can't even find it? [root@Moonface ~]# /sbin/fdisk -l Disk /dev/sda: 160.0 GB, 160041885696 bytes 255 heads, 63 sectors/track, 19457 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00018598 Device Boot Start End Blocks Id System /dev/sda1 * 1 64 512000 83 Linux Partition 1 does not end on cylinder boundary. /dev/sda2 64 19458 155777024 8e Linux LVM Disk /dev/dm-0: 53.7 GB, 53687091200 bytes 255 heads, 63 sectors/track, 6527 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-0 doesn't contain a valid partition table Disk /dev/dm-1: 4764 MB, 4764729344 bytes 255 heads, 63 sectors/track, 579 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-1 doesn't contain a valid partition table Disk /dev/dm-2: 101.0 GB, 101032394752 bytes 255 heads, 63 sectors/track, 12283 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-2 doesn't contain a valid partition table

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  • disk partition centos

    - by FlourishDNA
    I am setting up server for hosting two WordPress which has size of around 70GB. I have already installed CentOS as OS and I would like to partition the Disk. Is there any tool which can help me or can someone guide me though the process as I am not expert is SSH commands. Here are some output that might help. OS: CentOS release 6.3 fdisk -l Disk /dev/xvdb: 214.7 GB, 214748364800 bytes 255 heads, 63 sectors/track, 26108 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000b91e0 Device Boot Start End Blocks Id System Disk /dev/xvda: 21.5 GB, 21474836480 bytes 255 heads, 63 sectors/track, 2610 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000e542c Device Boot Start End Blocks Id System /dev/xvda1 * 1 64 512000 83 Linux Partition 1 does not end on cylinder boundary. /dev/xvda2 64 2611 20458496 8e Linux LVM Disk /dev/mapper/vg_flourish-lv_root: 16.7 GB, 16718495744 bytes 255 heads, 63 sectors/track, 2032 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/mapper/vg_flourish-lv_swap: 4227 MB, 4227858432 bytes 255 heads, 63 sectors/track, 514 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 df Filesystem 1K-blocks Used Available Use% Mounted on /dev/mapper/vg_flourish-lv_root 16070076 758184 14495560 5% / tmpfs 958500 0 958500 0% /dev/shm /dev/xvda1 495844 31926 438318 7% /boot df -h Filesystem Size Used Avail Use% Mounted on /dev/mapper/vg_flourish-lv_root 16G 741M 14G 5% / tmpfs 937M 0 937M 0% /dev/shm /dev/xvda1 485M 32M 429M 7% /boot Thanks

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  • In 3D camera math, calculate what Z depth is pixel unity for a given FOV

    - by badweasel
    I am working in iOS and OpenGL ES 2.0. Through trial and error I've figured out a frustum to where at a specific z depth pixels drawn are 1 to 1 with my source textures. So 1 pixel in my texture is 1 pixel on the screen. For 2d games this is good. Of course it means that I also factor in things like the size of the quad and the size of the texture. For example if my sprite is a quad 32x32 pixels. The quad size is 3.2 units wide and tall. And the texcoords are 32 / the size of the texture wide and tall. Then the frustum is: matrixFrustum(-(float)backingWidth/frustumScale,(float)backingWidth/frustumScale, -(float)backingHeight/frustumScale, (float)backingHeight/frustumScale, 40, 1000, mProjection); Where frustumScale is 800 for a retina screen. Then at a distance of 800 from camera the sprite is pixel for pixel the same as photoshop. For 3d games sometimes I still want to be able to do this. But depending on the scene I sometimes need the FOV to be different things. I'm looking for a way to figure out what Z depth will achieve this same pixel unity for a given FOV. For this my mProjection is set using: matrixPerspective(cameraFOV, near, far, (float)backingWidth / (float)backingHeight, mProjection); With testing I found that at an FOV of 45.0 a Z of 38.5 is very close to pixel unity. And at an FOV of 30.0 a Z of 59.5 is about right. But how can I calculate a value that is spot on? Here's my matrixPerspecitve code: void matrixPerspective(float angle, float near, float far, float aspect, mat4 m) { //float size = near * tanf(angle / 360.0 * M_PI); float size = near * tanf(degreesToRadians(angle) / 2.0); float left = -size, right = size, bottom = -size / aspect, top = size / aspect; // Unused values in perspective formula. m[1] = m[2] = m[3] = m[4] = 0; m[6] = m[7] = m[12] = m[13] = m[15] = 0; // Perspective formula. m[0] = 2 * near / (right - left); m[5] = 2 * near / (top - bottom); m[8] = (right + left) / (right - left); m[9] = (top + bottom) / (top - bottom); m[10] = -(far + near) / (far - near); m[11] = -1; m[14] = -(2 * far * near) / (far - near); } And my mView is set using: lookAtMatrix(cameraPos, camLookAt, camUpVector, mView); * UPDATE * I'm going to leave this here in case anyone has a different solution, can explain how they do it, or why this works. This is what I figured out. In my system I use a 10th scale unit to pixels on non-retina displays and a 20th scale on retina displays. The iPhone is 640 pixels wide on retina and 320 pixels wide on non-retina (obsolete). So if I want something to be the full screen width I divide by 20 to get the OpenGL unit width. Then divide that by 2 to get the left and right unit position. Something 32 units wide centered on the screen goes from -16 to +16. Believe it or not I have an excel spreadsheet do all this math for me and output all the vertex data for my sprite sheet. It's an arbitrary thing I made up to do .1 units = 1 non-retina pixel or 2 retina pixels. I could have made it .01 units = 2 pixels and someday I might switch to that. But for now it's the other. So the width of the screen in units is 32.0, and that means the left most pixel is at -16.0 and the right most is at 16.0. After messing a bit I figured out that if I take the [0] value of an identity modelViewProjection matrix and multiply it by 16 I get the depth required to get 1:1 pixels. I don't know why. I don't know if the 16 is related to the screen size or just a lucky guess. But I did a test where I placed a sprite at that calculated depth and varied the FOV through all the valid values and the object stays steady on screen with 1:1 pixels. So now I'm just calculating the unityDepth that way. If someone gives me a better answer I'll checkmark it.

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  • Formal Languages, Inductive Proofs &amp; Regular Expressions

    - by MarkPearl
    So I am slogging away at my UNISA stuff. I have just finished doing the initial once non stop read through the first 11 chapters of my COS 201 Textbook - “Introduction to Computer Theory 2nd Edition” by Daniel Cohen. It has been an interesting couple of days, with familiar concepts coming up as well as some new territory. In this posting I am going to cover the first couple of chapters of the book. Let start with Formal Languages… What exactly is a formal language? Pretty much a no duh question for me but still a good one to ask – a formal language is a language that is defined in a precise mathematical way. Does that mean that the English language is a formal language? I would say no – and my main motivation for this is that one can have an English sentence that is correct grammatically that is also ambiguous. For example the ambiguous sentence: "I once shot an elephant in my pyjamas.” For this and possibly many other reasons that I am unaware of, English is termed a “Natural Language”. So why the importance of formal languages in computer science? Again a no duh question in my mind… If we want computers to be effective and useful tools then we need them to be able to evaluate a series of commands in some form of language that when interpreted by the device no confusion will exist as to what we were requesting. Imagine the mayhem that would exist if a computer misinterpreted a command to print a document and instead decided to delete it. So what is a Formal Language made up of… For my study purposes a language is made up of a finite alphabet. For a formal language to exist there needs to be a specification on the language that will describe whether a string of characters has membership in the language or not. There are two basic ways to do this: By a “machine” that will recognize strings of the language (e.g. Finite Automata). By a rule that describes how strings of a language can be formed (e.g. Regular Expressions). When we use the phrase “string of characters”, we can also be referring to a “word”. What is an Inductive Proof? So I am not to far into my textbook and of course it starts referring to proofs and different types. I have had to go through several different approaches of proofs in the past, but I can never remember their formal names , so when I saw “inductive proof” I thought to myself – what the heck is that? Google to the rescue… An inductive proof is like a normal proof but it employs a neat trick which allows you to prove a statement about an arbitrary number n by first proving it is true when n is 1 and then assuming it is true for n=k and showing it is true for n=k+1. The idea is that if you want to show that someone can climb to the nth floor of a fire escape, you need only show that you can climb the ladder up to the fire escape (n=1) and then show that you know how to climb the stairs from any level of the fire escape (n=k) to the next level (n=k+1). Does this sound like a form of recursion? No surprise then that in the same chapter they deal with recursive definitions. An example of a recursive definition for the language EVEN would the 3 rules below: 2 is in EVEN If x is in EVEN then so is x+2 The only elements in the set EVEN are those that be produced by the rules above. Nothing to exciting… So if a definition for a language is done recursively, then it makes sense that the language can be proved using induction. Regular Expressions So I am wondering to myself what use is this all – in fact – I find this the biggest challenge to any university material is that it is quite hard to find the immediate practical applications of some theory in real life stuff. How great was my joy when I suddenly saw the word regular expression being introduced. I had been introduced to regular expressions on Stack Overflow where I was trying to recognize if some text measurement put in by a user was in a valid form or not. For instance, the imperial system of measurement where you have feet and inches can be represented in so many different ways. I had eventually turned to regular expressions as an easy way to check if my parser could correctly parse the text or not and convert it to a normalize measurement. So some rules about languages and regular expressions… Any finite language can be represented by at least one if not more regular expressions A regular expressions is almost a rule syntax for expressing how regular languages can be formed regular expressions are cool For a regular expression to be valid for a language it must be able to generate all the words in the language and no other words. This is important. It doesn’t help me if my regular expression parses 100% of my measurement texts but also lets one or two invalid texts to pass as well. Okay, so this posting jumps around a bit – but introduces some very basic fundamentals for the subject which will be built on in later postings… Time to go and do some practical examples now…

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  • Analysing and measuring the performance of a .NET application (survey results)

    - by Laila
    Back in December last year, I asked myself: could it be that .NET developers think that you need three days and a PhD to do performance profiling on their code? What if developers are shunning profilers because they perceive them as too complex to use? If so, then what method do they use to measure and analyse the performance of their .NET applications? Do they even care about performance? So, a few weeks ago, I decided to get a 1-minute survey up and running in the hopes that some good, hard data would clear the matter up once and for all. I posted the survey on Simple Talk and got help from a few people to promote it. The survey consisted of 3 simple questions: Amazingly, 533 developers took the time to respond - which means I had enough data to get representative results! So before I go any further, I would like to thank all of you who contributed, because I now have some pretty good answers to the troubling questions I was asking myself. To thank you properly, I thought I would share some of the results with you. First of all, application performance is indeed important to most of you. In fact, performance is an intrinsic part of the development cycle for a good 40% of you, which is much higher than I had anticipated, I have to admit. (I know, "Have a little faith Laila!") When asked what tool you use to measure and analyse application performance, I found that nearly half of the respondents use logging statements, a third use performance counters, and 70% of respondents use a profiler of some sort (a 3rd party performance profilers, the CLR profiler or the Visual Studio profiler). The importance attributed to logging statements did surprise me a little. I am still not sure why somebody would go to the trouble of manually instrumenting code in order to measure its performance, instead of just using a profiler. I personally find the process of annotating code, calculating times from log files, and relating it all back to your source terrifyingly laborious. Not to mention that you then need to remember to turn it all off later! Even when you have logging in place throughout all your code anyway, you still have a fair amount of potentially error-prone calculation to sift through the results; in addition, you'll only get method-level rather than line-level timings, and you won't get timings from any framework or library methods you don't have source for. To top it all, we all know that bottlenecks are rarely where you would expect them to be, so you could be wasting time looking for a performance problem in the wrong place. On the other hand, profilers do all the work for you: they automatically collect the CPU and wall-clock timings, and present the results from method timing all the way down to individual lines of code. Maybe I'm missing a trick. I would love to know about the types of scenarios where you actively prefer to use logging statements. Finally, while a third of the respondents didn't have a strong opinion about code performance profilers, those who had an opinion thought that they were mainly complex to use and time consuming. Three respondents in particular summarised this perfectly: "sometimes, they are rather complex to use, adding an additional time-sink to the process of trying to resolve the existing problem". "they are simple to use, but the results are hard to understand" "Complex to find the more advanced things, easy to find some low hanging fruit". These results confirmed my suspicions: Profilers are seen to be designed for more advanced users who can use them effectively and make sense of the results. I found yet more interesting information when I started comparing samples of "developers for whom performance is an important part of the dev cycle", with those "to whom performance is only looked at in times of crisis", and "developers to whom performance is not important, as long as the app works". See the three graphs below. Sample of developers to whom performance is an important part of the dev cycle: Sample of developers to whom performance is important only in times of crisis: Sample of developers to whom performance is not important, as long as the app works: As you can see, there is a strong correlation between the usage of a profiler and the importance attributed to performance: indeed, the more important performance is to a development team, the more likely they are to use a profiler. In addition, developers to whom performance is an important part of the dev cycle have a higher tendency to use a much wider range of methods for performance measurement and analysis. And, unsurprisingly, the less important performance is, the less varied the methods of measurement are. So all in all, to come back to my random questions: .NET developers do care about performance. Those who care the most use a wider range of performance measurement methods than those who care less. But overall, logging statements, performance counters and third party performance profilers are the performance measurement methods of choice for most developers. Finally, although most of you find code profilers complex to use, those of you who care the most about performance tend to use profilers more than those of you to whom performance is not so important.

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  • Recover a lost IBM DS4300 SAN password?

    - by Daniel
    I have a pair of IBM DS4300 SAN units that I need to perform a firmware upgrade on. Unfortunately the admin passwords on these units have been lost and now need to be reset. I had hoped the default password of 'infiniti' would work but it seems that it must have been changed. I know the method here is to contact IBM but the cost of that phone call is ludicrous if someone out here knows what they're going to tell me to do. These units are out of warranty and the cost of support is beyond what we have the budget for. Is there an interrupt I can enter during the boot process (similar to a cisco password recovery) or is there a hardware/software tool I require? Please, if anyone has ever gone through the process of an IBM password recovery I’m asking for a little help. EDIT: Just to clarify, the password I need to reset is the one used for serial cable access and not for storage manager. Sorry if I have caused more confusion.

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  • Implementing fog of war in opengl es 2.0 game

    - by joxnas
    Hi game development community, this is my first question here! ;) I'm developing a tactics/strategy real time android game and I've been wondering for some time what's the best way to implement an efficient and somewhat nice looking fog of war to incorporate in it. My experience with OpenGL or Android is not vast by any means, but I think it is sufficient for what I'm asking here. So far I have thought in some solutions: Draw white circles to a dark background, corresponding to the units visibility, then render to a texture, and then drawing a quad with that texture with blend mode set to multiply. Will this approach be efficient? Will it take too much memory? (I don't know how to render to texture and then use the texture. Is it too messy?) Have a grid object with a vertex shader which has an array of uniforms having the coordinates of all units, and another array which has their visibility range. The number of units will very probably never be bigger then 100. The vertex shader needs to test for each considered vertex, if there is some unit which can see it. In order to do this it, will have to loop the array with the coordinates and do some calculations based on distance. The efficiency of this is inversely proportional to the looks of it. A more dense grid will result in a more beautiful fog of war... but will require a greater amount of vertexes to be checked. Is it possible to find a nice compromise or is this a bad solution from the start? Which solution is the best? Are there better alternatives? Which ones? Thank you for your time.

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  • How to format FAT32 filesystem infected with windows virus and that is write protected

    - by explorex
    Hi, I have a pendrive with FAT32 filesystem. it is infected with virus dont know which but has autorun.inf and create exe file within folder. I tried to format it with various filesystems and even try to delete it with GParted but couldn't because it says it is write protected i can't even delete files. How to format it? user@explorerx:~$ sudo fdisk -l Disk /dev/sda: 160.0 GB, 160041885696 bytes 255 heads, 63 sectors/track, 19457 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xbd04bd04 Device Boot Start End Blocks Id System /dev/sda1 * 1 498 3998720 82 Linux swap / Solaris Partition 1 does not end on cylinder boundary. /dev/sda2 499 19457 152287585+ f W95 Ext'd (LBA) /dev/sda5 5100 10198 40957686 7 HPFS/NTFS /dev/sda6 10199 14787 36861111 7 HPFS/NTFS /dev/sda7 14788 19457 37511743+ 7 HPFS/NTFS /dev/sda8 499 5099 36956160 83 Linux Partition table entries are not in disk order Disk /dev/sdc: 160.0 GB, 160041885696 bytes 255 heads, 63 sectors/track, 19457 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xc13bc13b Device Boot Start End Blocks Id System /dev/sdc1 1 9729 78143488 7 HPFS/NTFS /dev/sdc2 9729 19457 78143488 7 HPFS/NTFS Disk /dev/sdb: 4194 MB, 4194304000 bytes 112 heads, 47 sectors/track, 1556 cylinders Units = cylinders of 5264 * 512 = 2695168 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/sdb1 2 1557 4091904 b W95 FAT32

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  • How to manage a multiplayer asynchronous environment in a game

    - by Phil
    I'm working on a game where players can setup villages, which can contain defending units. Any of these units (each on their own tiles) can be set to "campaign" which means they are no longer defending but can now be used to attack other villages. And each unit on a tile can have up to a 100 health. So far so good. Oh and it's all asynchronous so even though the server will be aware that your village is being attacked, you won't be until the attack is over. The issue I'm struggling with, is the following situation. Let's say a unit on a tile is being attacked by a player from another village. The other player see's your village and is attacking your units. You don't know this is happening though, so you set your unit to campaign and off you go to attack another village, with the unit which itself is actually being attacked by this other player. The other player stops attacking your village and leaves your unit with say a health of 1, which is then saved to the server. You however have this same unit are attacking another village with it, but now you discover that even though it started off with a 100 health, now mysteriously it only has 1... Solutions? Ideas? Edit The simplest solutions are often the best. I referred to Clash of clans below, well after a bit more digging it seems that in CoC you can only attack players that are offline! ha, that almost solves the problem. I say almost because there's still the situation where a players village could be in the process of being attacked when they come back online, still need to address that. Edit 2 A solution to the "What happens when a player is attacking your village and you come online" issue, could be the attacking player just get's kicked out of the village at that point and just get's whatever they had won up to that point, it's a bit of a fudge but it might work.

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  • Skanska Builds Global Workforce Insight with Cloud-Based HCM System

    - by HCM-Oracle
    By David Baum - Originally posted on Profit Peter Bjork grew up building things. He started his work life learning all sorts of trades at his father’s construction company in the northern part of Sweden. So in college, it was natural for him to pursue a bachelor’s degree in construction engineering—but he broke new ground when he added a master’s degree in finance to his curriculum vitae. Written on a traditional résumé, Bjork’s current title (vice president of information systems strategies) doesn’t reveal the diversity of his experience—that he’s adept with hammer and nails as well as rows and columns. But a big part of his current job is to work with his counterparts in human resources (HR) designing, building, and deploying the systems needed to get a complete view of the skills and potential of Skanska’s 22,000-strong white-collar workforce. And Bjork believes that complete view is essential to Skanska’s success. “Our business is really all about people,” says Bjork, who has worked with Skanska for 16 years. “You can have equipment and financial resources, but to truly succeed in a business like ours you need to have the right people in the right places. That’s what this system is helping us accomplish.” In a global HR environment that suffers from a paradox of high unemployment and a scarcity of skilled labor, managers need to have a complete understanding of workforce capabilities to develop management skills, recruit for open positions, ensure that staff is getting the training they need, and reduce attrition. Skanska’s human capital management (HCM) systems, based on Oracle Talent Management Cloud, play a critical role delivering that understanding. “Skanska’s philosophy of having great people, encouraging their development, and giving them the chance to move across business units has nurtured a culture of collaboration, but managing a diverse workforce spread across the globe is a monumental challenge,” says Annika Lindholm, global human resources system owner in the HR department at Skanska’s headquarters just outside of Stockholm, Sweden. “We depend heavily on Oracle’s cloud technology to support our HCM function.” Construction, Workers For Skanska’s more than 60,000 employees and contractors, managing huge construction projects is an everyday job. Beyond erecting signature buildings, management’s goal is to build a corporate culture where valuable talent can be sought out and developed, bringing in the right mix of people to support and grow the business. “Of all the companies in our space, Skanska is probably one of the strongest ones, with a laser focus on people and people development,” notes Tom Crane, chief HR and communications officer for Skanska in the United States. “Our business looks like equipment and material, but all we really have at the end of the day are people and their intellectual capital. Without them, second only to clients, of course, you really can’t achieve great things in the high-profile environment in which we work.” During the 1990s, Skanska entered an expansive growth phase. A string of successful acquisitions paved the way for the company’s transformation into a global enterprise. “Today the company’s focus is on profitable growth,” continues Crane. “But you can’t really achieve growth unless you are doing a very good job of developing your people and having the right people in the right places and driving a culture of growth.” In the United States alone, Skanska has more than 8,000 employees in four distinct business units: Skanska USA Building, also known as the Construction Manager, builds everything at ground level and above—hospitals, educational facilities, stadiums, airport terminals, and other massive projects. Skanska USA Civil does everything at ground level and below, such as light rail, water treatment facilities, power plants or power industry facilities, highways, and bridges. Skanska Infrastructure Development develops public-private partnerships—projects in which Skanska adds equity and also arranges for outside financing. Skanska Commercial Development acts like a commercial real estate developer, acquiring land and building offices on spec or build-to-suit for its clients. Skanska's international portfolio includes construction of the new Meadowlands Stadium. Getting the various units to operate collaboratatively helps Skanska deliver high value to clients and shareholders. “When we have this collaboration among units, it allows us to enrich each of the business units and, at the same time, develop our future leaders to be more facile in operating across business units—more accepting of a ‘one Skanska’ approach,” explains Crane. Workforce Worldwide But HR needs processes and tools to support managers who face such business dynamics. Oracle Talent Management Cloud is helping Skanska implement world-class recruiting strategies and generate the insights needed to drive quality hiring practices, internal mobility, and a proactive approach to building talent pipelines. With their new cloud system in place, Skanska HR leaders can manage everything from recruiting, compensation, and goal and performance management to employee learning and talent review—all as part of a single, cohesive software-as-a-service (SaaS) environment. Skanska has successfully implemented two modules from Oracle Talent Management Cloud—the recruiting and performance management modules—and is in the process of implementing the learn module. Internally, they call the systems Skanska Recruit, Skanska Talent, and Skanska Learn. The timing is apropos. With high rates of unemployment in recent years, there have been many job candidates on the market. However, talent scarcity continues to frustrate recruiters. Oracle Taleo Recruiting Cloud Service, one of the applications in the Oracle Talent Management cloud portfolio, enables Skanska managers to create more-intelligent recruiting strategies, pulling high-performer profile statistics to create new candidate profiles and using multitiered screening and assessments to ensure that only the best-suited candidate applications make it to the recruiter’s desk. Tools such as applicant tracking, interview management, and requisition management help recruiters and hiring managers streamline the hiring process. Oracle’s cloud-based software system automates and streamlines many other HR processes for Skanska’s multinational organization and delivers insight into the success of recruiting and talent-management efforts. “The Oracle system is definitely helping us to construct global HR processes,” adds Bjork. “It is really important that we have a business model that is decentralized, so we can effectively serve our local markets, and interact with our global ERP [enterprise resource planning] systems as well. We would not be able to do this without a really good, well-integrated HCM system that could support these efforts.” A key piece of this effort is something Skanska has developed internally called the Skanska Leadership Profile. Core competencies, on which all employees are measured, are used in performance reviews to determine weak areas but also to discover talent, such as those who will be promoted or need succession plans. This global profiling system brings consistency to the way HR professionals evaluate and review talent across the company, with a consistent set of ratings and a consistent definition of competencies. All salaried employees in Skanska are tied to a talent management process that gives opportunity for midyear and year-end reviews. Using the performance management module, managers can align individual goals with corporate goals; provide clear visibility into how each employee contributes to the success of the organization; and drive a strategic, end-to-end talent management strategy with a single, integrated system for all talent-related activities. This is critical to a company that is highly focused on ensuring that every employee has a development plan linked to his or her succession potential. “Our approach all along has been to deploy software applications that are seamless to end users,” says Crane. “The beauty of a cloud-based system is that much of the functionality takes place behind the scenes so we can focus on making sure users can access the data when they need it. This model greatly improves their efficiency.” The employee profile not only sets a competency baseline for new employees but is also integrated with Skanska’s other back-office Oracle systems to ensure consistency in the way information is used to support other business functions. “Since we have about a dozen different HR systems that are providing us with information, we built a master database that collects all the information,” explains Lindholm. “That data is sent not only to Oracle Talent Management Cloud, but also to other systems that are dependent on this information.” Collaboration to Scale Skanska is poised to launch a new Oracle module to link employee learning plans to the review process and recruitment assessments. According to Crane, connecting these processes allows Skanska managers to see employees’ progress and produce an updated learning program. For example, as employees take classes, supervisors can consult the Oracle Talent Management Cloud portal to monitor progress and align it to each individual’s training and development plan. “That’s a pretty compelling solution for an organization that wants to manage its talent on a real-time basis and see how the training is working,” Crane says. Rolling out Oracle Talent Management Cloud was a joint effort among HR, IT, and a global group that oversaw the worldwide implementation. Skanska deployed the solution quickly across all markets at once. In the United States, for example, more than 35 offices quickly got up to speed on the new system via webinars for employees and face-to-face training for the HR group. “With any migration, there are moments when you hold your breath, but in this case, we had very few problems getting the system up and running,” says Crane. Lindholm adds, “There has been very little resistance to the system as users recognize its potential. Customizations are easy, and a lasting partnership has developed between Skanska and Oracle when help is needed. They listen to us.” Bjork elaborates on the implementation process from an IT perspective. “Deploying a SaaS system removes a lot of the complexity,” he says. “You can downsize the IT part and focus on the business part, which increases the probability of a successful implementation. If you want to scale the system, you make a quick phone call. That’s all it took recently when we added 4,000 users. We didn’t have to think about resizing the servers or hiring more IT people. Oracle does that for us, and they have provided very good support.” As a result, Skanska has been able to implement a single, cost-effective talent management solution across the organization to support its strategy to recruit and develop a world-class staff. Stakeholders are confident that they are providing the most efficient recruitment system possible for competent personnel at all levels within the company—from skilled workers at construction sites to top management at headquarters. And Skanska can retain skilled employees and ensure that they receive the development opportunities they need to grow and advance.

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  • Sending changes to a terrain heightmap over UDP

    - by Floomi
    This is a more conceptual, thinking-out-loud question than a technical one. I have a 3D heightmapped terrain as part of a multiplayer RTS that I would like to terraform over a network. The terraforming will be done by units within the gameworld; the player will paint a "target heightmap" that they'd like the current terrain to resemble and units will deform towards that on their own (a la Perimeter). Given my terrain is 257x257 vertices, the naive approach of sending heights when they change will flood the bandwidth very quickly - updating a quarter of the terrain every second will hit ~66kB/s. This is clearly way too much. My next thought was to move to a brush-based system, where you send e.g. the centre of a circle, its radius, and some function defining the influence of the brush from the centre going outwards. But even with reliable UDP the "start" and "stop" messages could still be delayed. I guess I could compare timestamps and compensate for this, although it'd likely mean that clients would deform verts too much on their local simulations and then have to smooth them back to the correct heights. I could also send absolute vert heights in the "start" and "stop" messages to guarantee correct data on the clients. Alternatively I could treat brushes in a similar way to units, and do the standard position + velocity + client-side prediction jazz on them, with the added stipulation that they deform terrain within a certain radius around them. The server could then intermittently do a pass and send (a subset of) recently updated verts to clients as and when there's bandwidth to spare. Any other suggestions, or indications that I'm on the right (or wrong!) track with any of these ideas would be greatly appreciated.

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  • disk space worngly displayed after installing LVM disk

    - by Ubuntuser
    I installed ubuntu server using LVM partitioning on a 1 TB hard disk. However, after installation, i can only see 10 Gig space here is the fidsk output ` # fdisk -l Disk /dev/sda: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00041507 Device Boot Start End Blocks Id System /dev/sda1 * 1 10 71680 83 Linux Partition 1 does not end on cylinder boundary. /dev/sda2 10 121602 976689152 8e Linux LVM Disk /dev/dm-0: 10.7 GB, 10737418240 bytes 255 heads, 63 sectors/track, 1305 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-0 doesn't contain a valid partition table Disk /dev/dm-1: 2147 MB, 2147483648 bytes 255 heads, 63 sectors/track, 261 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-1 doesn't contain a valid partition table You have new mail in /var/mail/root and df -h output df -h Filesystem Size Used Avail Use% Mounted on /dev/mapper/system-root 9.9G 6.6G 2.8G 71% / devtmpfs 1.9G 232K 1.9G 1% /dev tmpfs 1.9G 4.0K 1.9G 1% /dev/shm /dev/sda1 68M 22M 43M 34% /boot tmpfs 6.0G 0 6.0G 0% /var/spool/asterisk/monitor You have new mail in /var/mail/root ` any way to increase this space without reisntalling?

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  • How should I show shared resources during a Shared Resource game in the Galaxy Editor?

    - by Mag Roader
    One of my favorite ways to play the original StarCraft was in a "Team" game. In this game type, multiple players on the same "team" would share control, resources, supply, and even the same starting location. It was like playing as 1 player, only 2 humans were controlling it. It was a lot of fun. I want to do something very similar in StarCraft 2, but I need to create a custom map in the Galaxy Editor to do it. I found the editor can quite easily emulate this behavior. There is a Trigger action "Set Alliance for Player Group" to "...treat each other as Ally With Shared Vision, Control, And Spending." To use this, I create units for only 1 of the players, and then set all players to be allied with each other in this way. All the other players get no units and no resources. This makes it so 1 player is the actual owner of all the units and everyone else is tagging along with full control. This nearly works! The problem is that if I am not the actual owning player, I can't actually see how many minerals/gas/supply the team has. This makes it pretty difficult to build stuff. What would be the best way to display to the other players how many Minerals/Gas/Supply the team has?

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  • Raid Shows Up as Multiple Drives - Can't Mount

    - by manyxcxi
    I have a single hard drive that the OS is installed on and I have Sil raid card installed with two matching 500GB hdds set up in Raid 0 and formatted- they're completely empty. For whatever reason they are showing up as /dev/sdb and /dev/sdc and not as a single hard drive. I used fdisk to format both raid drives as Linux raid auto (fd) but I cannot mount either device and dmraid doesn't seem to want to work, what step am I missing? When I installed 9.04 oh so long ago it seems like it recognized and automatically did everything that needed to be done, now I'm stuck. dmraid Output root@tripoli:~# dmraid -r /dev/sdc: sil, "sil_biaebhadcfcb", stripe, ok, 976771072 sectors, data@ 0 /dev/sdb: sil, "sil_biaebhadcfcb", stripe, ok, 976771072 sectors, data@ 0 root@tripoli:~# dmraid -ay RAID set "sil_biaebhadcfcb" already active fdisk Output root@tripoli:~# fdisk -l Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000b9b01 Device Boot Start End Blocks Id System /dev/sda1 * 1 32 248832 83 Linux Partition 1 does not end on cylinder boundary. /dev/sda2 32 60802 488134657 5 Extended /dev/sda5 32 60802 488134656 8e Linux LVM Disk /dev/sdb: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x6ead5c9a Device Boot Start End Blocks Id System /dev/sdb1 1 60801 488384001 fd Linux raid autodetect Disk /dev/sdc: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xe6e2af28 Device Boot Start End Blocks Id System /dev/sdc1 1 60801 488384001 fd Linux raid autodetect

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  • Unable to mount USBDRIVE Error creating moint point: Permission denied

    - by steve
    Whenever I plug a usb into my computer a window pops up and says Unable to mount [Name of USB] Error creating moint point: Permission denied steve@goliath:/$ uname -a Linux goliath 3.2.0-32-generic #51-Ubuntu SMP Wed Sep 26 21:33:09 UTC 2012 x86_64 x86_64 x86_64 GNU/Linux steve@goliath:/$ sudo fdisk -l WARNING: GPT (GUID Partition Table) detected on '/dev/sda'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sda: 120.0 GB, 120034123776 bytes 255 heads, 63 sectors/track, 14593 cylinders, total 234441648 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x0f716ee1 Device Boot Start End Blocks Id System /dev/sda1 1 234441647 117220823+ ee GPT WARNING: GPT (GUID Partition Table) detected on '/dev/sdb'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sdb: 1500.3 GB, 1500301910016 bytes 255 heads, 63 sectors/track, 182401 cylinders, total 2930277168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x0f710ee1 Device Boot Start End Blocks Id System /dev/sdb1 1 2930277167 1465138583+ ee GPT Disk /dev/sdc: 16.0 GB, 16005464064 bytes 74 heads, 10 sectors/track, 42244 cylinders, total 31260672 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xc3072e18 Device Boot Start End Blocks Id System /dev/sdc1 8064 31260671 15626304 c W95 FAT32 (LBA) steve@goliath:/$ sudo mkdir /media/external mkdir: cannot create directory `/media/external': Permission denied steve@goliath:/$ sudo mkdir /media/usb0 mkdir: cannot create directory `/media/usb0': Permission denied steve@goliath:/$ sudo ls -l / | grep media drwxr-xr-x 3 root root 4096 Oct 3 22:48 media steve@goliath:/$ ls /media/ -a . .. MediaShare MediaShare is the the directory on my server that has all my movies and music. If there is any information I left out please let me know.

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  • No MAU required on a T4

    - by jsavit
    Cryptic background One of the powerful features of the T-series servers is its hardware crypto acceleration, which dramatically speeds up the compute intensive algorithms needed to encrypt and decrypt data. Previously, administrators setting up logical domains on older T-series servers had to explicitly assign crypto resources (called "MAU" for historical reasons from the T1 chip that had "modular arithmetic units") to domains that had a significant crypto workload (say, an SSL based web server). This could be an administrative burden, as you had to choose which domains got the crypto units, and issue the appropriate ldm set-mau N mydomain commands. The T4 changes things The T4 is fast. Really fast. Its clock rate and out-of-order (OOO) execution that provides the single-thread performance that T-series machines previously did not have. If you have any preconceptions about T-series performance, or SPARC in general, based on the older servers (which, it must be said, were absolutely outstanding for multi-threaded applications), those assumptions are now obsolete. The T4 provides outstanding. performance for all kinds of workload, as illustrated at https://blogs.oracle.com/bestperf. While we all focused on this (did I mention the T4 is fast?), another feature of the T4 went largely unnoticed: The T4 servers have crypto acceleration "just built in" so administrators no longer have to assign crypto accelerator units to domains - it "just happens". This is way way better since you have crypto everywhere by default without having to manage it like a discrete and limited resource. It's a feature of the processor, like doing an integer add. With T4, there is no management necessary, you just have HW crypto everywhere all the time seamlessly. This change hasn't been widely advertised, and some administrators have wondered why there were unable to assign a MAU to a domain as they did with T2 and T3 machines. The answer is that there is no longer any separate MAU, so you don't have to take any action at all - just leave the default of 0. Summary Besides being much faster than its predecessors, the T4 also integrates hardware crypto acceleration so its seamlessly available to applications, whether domains are being used or not. Administrators no longer have to control how they are allocated - it "just happens"

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  • Win7 no longer available after installing 12.04

    - by Michael
    I have installed Ubuntu 12.04 but my Windows 7 partition seems to have been lost. It is in sda2. Can anyone help me how to get this Windows 7 partition back without having to reinstall Windows 7? Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders, total 976773168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xd45cd45c Device Boot Start End Blocks Id System /dev/sda1 2048 61433855 30715904 83 Linux /dev/sda2 * 61433856 122873855 30720000 7 HPFS/NTFS/exFAT /dev/sda3 122873856 976769023 426947584 7 HPFS/NTFS/exFAT Disk /dev/sdb: 203.9 GB, 203928109056 bytes 255 heads, 63 sectors/track, 24792 cylinders, total 398297088 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x03ee03ee Device Boot Start End Blocks Id System /dev/sdb1 * 63 20482874 10241406 c W95 FAT32 (LBA) /dev/sdb2 20482875 40965749 10241437+ 1c Hidden W95 FAT32 (LBA) /dev/sdb3 40965750 398283479 178658865 f W95 Ext'd (LBA) /dev/sdb5 40965813 76694309 17864248+ 7 HPFS/NTFS/exFAT /dev/sdb6 76694373 108856439 16081033+ 7 HPFS/NTFS/exFAT /dev/sdb7 108856503 398283479 144713488+ 7 HPFS/NTFS/exFAT Disk /dev/sdc: 1000.2 GB, 1000204886016 bytes 240 heads, 63 sectors/track, 129201 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000001 Device Boot Start End Blocks Id System /dev/sdc1 * 63 20480543 10240240+ 82 Linux swap / Solaris /dev/sdc2 20480605 1953519119 966519257+ f W95 Ext'd (LBA) /dev/sdc5 20480607 1953519119 966519256+ 7 HPFS/NTFS/exFAT

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  • Dual Boot Windows 8 and Ubuntu

    - by Nick
    My laptop has two hard drives, one 320GB HDD and a 30GB SSD. I installed Windows 8 on the HDD and Ubuntu on the SSD. However, after I installed Ubuntu, Windows 8 did not appear on the boot list. I tried boot-repair, but this didn't help.Here is the output of my fdisk -l: Disk /dev/sda: 320.1 GB, 320072933376 bytes 255 heads, 63 sectors/track, 38913 cylinders, total 625142448 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x6cd9314a Device Boot Start End Blocks Id System /dev/sda1 * 2048 625139711 312568832 7 HPFS/NTFS/exFAT Disk /dev/sdb: 30.0 GB, 30016659456 bytes 255 heads, 63 sectors/track, 3649 cylinders, total 58626288 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x6cd93132 Device Boot Start End Blocks Id System /dev/sdb1 * 2048 207126 102539+ 83 Linux /dev/sdb2 208894 58626047 29208577 5 Extended /dev/sdb5 208896 4112383 1951744 82 Linux swap / Solaris /dev/sdb6 4114432 58626047 27255808 83 Linux Disk /dev/mmcblk0: 3965 MB, 3965190144 bytes 49 heads, 48 sectors/track, 3292 cylinders, total 7744512 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x0009c694 Device Boot Start End Blocks Id System /dev/mmcblk0p1 * 8192 7744511 3868160 b W95 FAT32 I also tried sudo grub-update, but that also did nothing.

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