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  • Java iterative vs recursive

    - by user1389813
    Can anyone explain why the following recursive method is faster than the iterative one (Both are doing it string concatenation) ? Isn't the iterative approach suppose to beat up the recursive one ? plus each recursive call adds a new layer on top of the stack which can be very space inefficient. private static void string_concat(StringBuilder sb, int count){ if(count >= 9999) return; string_concat(sb.append(count), count+1); } public static void main(String [] arg){ long s = System.currentTimeMillis(); StringBuilder sb = new StringBuilder(); for(int i = 0; i < 9999; i++){ sb.append(i); } System.out.println(System.currentTimeMillis()-s); s = System.currentTimeMillis(); string_concat(new StringBuilder(),0); System.out.println(System.currentTimeMillis()-s); } I ran the program multiple time, and the recursive one always ends up 3-4 times faster than the iterative one. What could be the main reason there that is causing the iterative one slower ?

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  • What SQL query should I perform to get the result set expected?

    - by texai
    What SQL query should I perform to get the result set expected, giving the first element of the chain (2) as input data, or any of them ? table name: changes +----+---------------+---------------+ | id | new_record_id | old_record_id | +----+---------------+---------------+ | 1| 4| 2| | -- non relevant data -- | | 6| 7| 4| | -- non relevant data -- | | 11| 13| 7| | 12| 14| 13| | -- non relevant data -- | | 31| 20| 14| +----+---------------+---------------+ Result set expected: +--+ | 2| | 4| | 7| |13| |14| |20| +--+ I know I should consider change my data model, but: What if I couldn't? Thank you in advance!

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  • Scala: recursive search avoiding cycles

    - by user1826663
    How can I write a recursive search that I avoid cycles. My class is this: class Component(var name: String, var number: Int, var subComponent: Set[Component]) Now I need a way to check whether a component is contained within its subcomponent or between subcomponent of its subcomponent and so on.Avoiding possible cycles caused by other Component. My method of recursive search must have the following signature, where subC is the Set [component] of comp. def content (comp: Component, subC: Set[Component]) : Boolean = { } Thanks for the help.

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  • Segmentation fault in a function to reverse a singly linked list recursivley.

    - by Amanda
    I am implementing a function to recursively reverse a linked-list, but getting seg-fault. typedef struct _node { int data; struct _node *next; } Node, *NodeP; NodeP recursiveReverseList(NodeP first){ if(first == NULL) return NULL; if(first->next == NULL) return first; NodeP rest = recursiveReverseList(first->next); rest->next = first; first->next = NULL; return first; } Can you please help? P.S. The iterative version is working fine though. Its not homework. Just practicing C. Thank you all :)

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  • Returning binomal as a tuple

    - by Mike
    I want to save the results of my function binomal_aux to a tuple but I don't have an idea how to, here is my code I have right now. def binomal (n): i=0 for i in range(n): binomal_aux(n,i) #want this to be in a tuple so, binomal (2) = (1,2,1) return def binomal_aux (n,k): if (k==0): return 1 elif (n==k): return 1 else: return (binomal_aux(n-1,k) + binomal_aux(n-1,k-1))

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  • OutOfMemoryError creating a tree recursively?

    - by Alexander Khaos Greenstein
    root = new TreeNode(N); constructTree(N, root); private void constructTree(int N, TreeNode node) { if (N > 0) { node.setLeft(new TreeNode(N-1)); constructTree(N-1, node.getLeft()); } if (N > 1) { node.setMiddle(new TreeNode(N-2)); constructTree(N-2, node.getMiddle()); } if (N > 2) { node.setRight(new TreeNode(N-3)); constructTree(N-3, node.getRight()); } Assume N is the root number, and the three will create a left middle right node of N-1, N-2, N-3. EX: 5 / | \ 4 3 2 /|\ 3 2 1 etc. My GameNode class has the following variables: private int number; private GameNode left, middle, right; Whenever I construct a tree with an integer greater than 28, I get a OutOfMemoryError. Is my recursive method just incredibly inefficient or is this natural? Thanks!

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  • Testing for Adjacent Cells In a Multi-level Grid

    - by Steve
    I'm designing an algorithm to test whether cells on a grid are adjacent or not. The catch is that the cells are not on a flat grid. They are on a multi-level grid such as the one drawn below. Level 1 (Top Level) | - - - - - | | A | B | C | | - - - - - | | D | E | F | | - - - - - | | G | H | I | | - - - - - | Level 2 | -Block A- | -Block B- | | 1 | 2 | 3 | 1 | 2 | 3 | | - - - - - | - - - - - | | 4 | 5 | 6 | 4 | 5 | 6 | ... | - - - - - | - - - - - | | 7 | 8 | 9 | 7 | 8 | 9 | | - - - - - | - - - - - | | -Block D- | -Block E- | | 1 | 2 | 3 | 1 | 2 | 3 | | - - - - - | - - - - - | | 4 | 5 | 6 | 4 | 5 | 6 | ... | - - - - - | - - - - - | | 7 | 8 | 9 | 7 | 8 | 9 | | - - - - - | - - - - - | . . . . . . This diagram is simplified from my actual need but the concept is the same. There is a top level block with many cells within it (level 1). Each block is further subdivided into many more cells (level 2). Those cells are further subdivided into level 3, 4 and 5 for my project but let's just stick to two levels for this question. I'm receiving inputs for my function in the form of "A8, A9, B7, D3". That's a list of cell Ids where each cell Id has the format (level 1 id)(level 2 id). Let's start by comparing just 2 cells, A8 and A9. That's easy because they are in the same block. private static RelativePosition getRelativePositionInTheSameBlock(String v1, String v2) { RelativePosition relativePosition; if( v1-v2 == -1 ) { relativePosition = RelativePosition.LEFT_OF; } else if (v1-v2 == 1) { relativePosition = RelativePosition.RIGHT_OF; } else if (v1-v2 == -BLOCK_WIDTH) { relativePosition = RelativePosition.TOP_OF; } else if (v1-v2 == BLOCK_WIDTH) { relativePosition = RelativePosition.BOTTOM_OF; } else { relativePosition = RelativePosition.NOT_ADJACENT; } return relativePosition; } An A9 - B7 comparison could be done by checking if A is a multiple of BLOCK_WIDTH and whether B is (A-BLOCK_WIDTH+1). Either that or just check naively if the A/B pair is 3-1, 6-4 or 9-7 for better readability. For B7 - D3, they are not adjacent but D3 is adjacent to A9 so I can do a similar adjacency test as above. So getting away from the little details and focusing on the big picture. Is this really the best way to do it? Keeping in mind the following points: I actually have 5 levels not 2, so I could potentially get a list like "A8A1A, A8A1B, B1A2A, B1A2B". Adding a new cell to compare still requires me to compare all the other cells before it (seems like the best I could do for this step is O(n)) The cells aren't all 3x3 blocks, they're just that way for my example. They could be MxN blocks with different M and N for different levels. In my current implementation above, I have separate functions to check adjacency if the cells are in the same blocks, if they are in separate horizontally adjacent blocks or if they are in separate vertically adjacent blocks. That means I have to know the position of the two blocks at the current level before I call one of those functions for the layer below. Judging by the complexity of having to deal with mulitple functions for different edge cases at different levels and having 5 levels of nested if statements. I'm wondering if another design is more suitable. Perhaps a more recursive solution, use of other data structures, or perhaps map the entire multi-level grid to a single-level grid (my quick calculations gives me about 700,000+ atomic cell ids). Even if I go that route, mapping from multi-level to single level is a non-trivial task in itself.

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  • Writing a recursive sorting algorithm of an array of integers

    - by 12345
    I am trying to write a recursive sorting algorithm for an array of integers. The following codes prints to the console: 3, 5, 2, 1, 1, 2, 6, 7, 8, 10, 20 The output should be sorted but somehow "it doesn't work". public static void main(String[] args) { int[] unsortedList = {20, 3, 1, 2, 1, 2, 6, 8, 10, 5, 7}; duplexSelectionSort(unsortedList, 0, unsortedList.length-1); for (int i = 0; i < unsortedList.length; i++) { System.out.println(unsortedList[i]); } } public static void duplexSelectionSort( int[] unsortedNumbers, int startIndex, int stopIndex) { int minimumIndex = 0; int maximumIndex = 0; if (startIndex < stopIndex) { int index = 0; while (index <= stopIndex) { if (unsortedNumbers[index] < unsortedNumbers[minimumIndex]) { minimumIndex = index; } if (unsortedNumbers[index] > unsortedNumbers[maximumIndex]) { maximumIndex = index; } index++; } swapEdges(unsortedNumbers, startIndex, stopIndex, minimumIndex, maximumIndex); duplexSelectionSort(unsortedNumbers, startIndex + 1, stopIndex - 1); } } public static void swapEdges( int[] listOfIntegers, int startIndex, int stopIndex, int minimumIndex, int maximumIndex) { if ((minimumIndex == stopIndex) && (maximumIndex == startIndex)) { swap(listOfIntegers, startIndex, stopIndex); } else { if (maximumIndex == startIndex) { swap(listOfIntegers, maximumIndex, stopIndex); swap(listOfIntegers, minimumIndex, startIndex); } else { swap(listOfIntegers, minimumIndex, startIndex); swap(listOfIntegers, maximumIndex, stopIndex); } } } public static void swap(int[] listOfIntegers, int index1, int index2) { int savedElementAtIndex1 = listOfIntegers[index1]; listOfIntegers[index1] = listOfIntegers[index2]; listOfIntegers[index2] = savedElementAtIndex1; }

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  • Java keep printing a new line in my recursive method

    - by Abra Grace Libretto White
    I am trying to write a recursive method to print n number of asteriks in a line and create a new line at the end. So, TriangleOps.line(5); would print ***** This is the code I wrote: public static void line (int n){ if(n>0){ System.out.println("*"); line(n-1); }} instead it prints * * * * * with a lot of space at the end. Can anyone tell me how to remove the line breaks?

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  • Reset array keys in multidimensional array

    - by nbaumann
    I've been looking around for a solution to this with no real success. I have a multidimensional array of parents and children with no limits on depth. This is generated from a database but the issue is that the item ID becomes the key using my way of arranging a flat array into a multidimensional array like so: Array( [28] => Array ( [id] => 28 [color] => #ff24e5 [name] => Personal [parent_id] => [children] => Array ( [23] => Array ( [id] => 23 [color] => #41c3a3 [name] => Shopping [parent_id] => 28 [children] => Array ( [22] => Array ( [id] => 22 [color] => #8be32b [name] => Deals [parent_id] => 23 [children] => Array ( ) ) ) ) [150] => Array ( [id] => 150 [color] => #e9a3f0 [name] => Orders [parent_id] => 28 [children] => Array ( ) ) ) ) ) What I would like, is a function that does the following: Array ( [0] => Array ( [id] => 28 [color] => #ff24e5 [name] => Personal [parent_id] => [children] => Array ( [0] => Array ( [id] => 23 [color] => #41c3a3 [name] => Shopping [parent_id] => 28 [children] => Array ( [0] => Array ( [id] => 22 [color] => #8be32b [name] => Deals [user_id] => 1 [selected] => 0 [parent_id] => 23 [children] => Array ( ) ) ) ) [1] => Array ( [id] => 150 [color] => #e9a3f0 [name] => Orders [parent_id] => 28 [children] => Array ( ) ) ) ) ) Essentially reassign keys starting from 0. I've tried numerous methods, but I'm assuming that I need to find a recursive solution and when I tried that, it destroyed my array. I was reading up on the array_walk_recursive() function, but I don't quite know what to do beyond that. Essentially, is there a way to reset numeric keys in a multidimensional array? Thanks for the help!

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  • Recursive MySQL function call eats up too much memory and dies.

    - by kylex
    I have the following recursive function which works... up until a point. Then the script asks for more memory once the queries exceed about 100, and when I add more memory, the script typically just dies (I end up with a white screen on my browser). public function returnPArray($parent=0,$depth=0,$orderBy = 'showOrder ASC'){ $query = mysql_query("SELECT *, UNIX_TIMESTAMP(lastDate) AS whenTime FROM these_pages WHERE parent = '".$parent."' AND deleted = 'N' ORDER BY ".$orderBy.""); $rows = mysql_num_rows($query); while($row = mysql_fetch_assoc($query)){ // This uses my class and places the content in an array. MyClass::$_navArray[] = array( 'id' => $row['id'], 'parent' => $row['parent'] ); MyClass::returnPArray($row['id'],($depth+1)); } $i++; } Can anyone help me make this query less resource intensive?

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  • PHP make all possible variants of 4char A-Z,a-z,0-9

    - by Mike
    I have to make a list of all possible permurations of 4characters A-Z,a-z,0-9 and conbination of all this.How can i pass thru all of the possible combinations and printf them ? what's it for:I need to make this in a html document that i can then print and give all this as random unique usernames for our university, so that students can provide feedback based on one unique id that will be invalidated when used. i can not change this procedure into a better one!

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  • Repeated host lookups failing in urllib2

    - by reve_etrange
    I have code which issues many HTTP GET requests using Python's urllib2, in several threads, writing the responses into files (one per thread). During execution, it looks like many of the host lookups fail (causing a name or service unknown error, see appended error log for an example). Is this due to a flaky DNS service? Is it bad practice to rely on DNS caching, if the host name isn't changing? I.e. should a single lookup's result be passed into the urlopen? Exception in thread Thread-16: Traceback (most recent call last): File "/usr/lib/python2.6/threading.py", line 532, in __bootstrap_inner self.run() File "/home/da/local/bin/ThreadedDownloader.py", line 61, in run page = urllib2.urlopen(url) # get the page File "/usr/lib/python2.6/urllib2.py", line 126, in urlopen return _opener.open(url, data, timeout) File "/usr/lib/python2.6/urllib2.py", line 391, in open response = self._open(req, data) File "/usr/lib/python2.6/urllib2.py", line 409, in _open '_open', req) File "/usr/lib/python2.6/urllib2.py", line 369, in _call_chain result = func(*args) File "/usr/lib/python2.6/urllib2.py", line 1170, in http_open return self.do_open(httplib.HTTPConnection, req) File "/usr/lib/python2.6/urllib2.py", line 1145, in do_open raise URLError(err) URLError: <urlopen error [Errno -2] Name or service not known>

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  • Website hosting from home - IIS6 [closed]

    - by Paul
    I'm wanting to host a few websites from home, primarily because I'm using some BETA Microsoft software (.NET 4 and EF) and don't want to install it on my production server which is hosted at eukhost.com. Basically, I'm completely new to this sort of thing. So far, here is what I've done: Registered the domain name at namecheap.com (let's call it mydomain.com) Gone to "Nameserver Registration" in the panel and entered my IP address for the NS1 and NS2 records (let's say the IP is 0.0.0.0). Gone to "Domain Name Server Setup" and entered ns1.mydomain.com & ns2.mydomain.com Forwarded requests from port 80 to my internal IP (let's say 192.168.1.254) Created the website in IIS (I'm just testing with a single website so far, so have not created any host header values) Now, if I type in the IP address (http://0.0.0.0) I get the site as expected. However, if I enter http://www.mydomain.com I get an error saying "DNS Error - Cannot find server". I'm aware that there is a service from DynDNS that will automatically change the IP if I have a dynamic address, however my IP has remained static since I installed the ISP (since October) so I don't need this. Is there any way that I can get the DNS to work just by configuring IIS or something in Windows? I don't really want to have to pay for any 3rd party service. Thanks,

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  • iptables is not allowing me to contact my dns nameservers

    - by user1272737
    I have the follwing iptables rules: Chain INPUT (policy DROP) target prot opt source destination ACCEPT tcp -- anywhere anywhere tcp dpt:ssh ACCEPT tcp -- anywhere anywhere tcp dpt:http ACCEPT tcp -- anywhere anywhere tcp dpt:https ACCEPT tcp -- localhost.localdomain anywhere tcp dpt:mysql ACCEPT tcp -- anywhere anywhere tcp dpt:14443 ACCEPT tcp -- anywhere anywhere tcp dpt:ftp ACCEPT tcp -- anywhere anywhere tcp dpt:ftp-data ACCEPT tcp -- anywhere anywhere tcp dpt:xxxxxxx Chain FORWARD (policy ACCEPT) target prot opt source destination Chain OUTPUT (policy ACCEPT) target prot opt source destination When I turn off iptables I am able to use wget and all other commands. When these rules are enabled I cannot connect to any address. Any idea why this would be?

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  • How do I install and use the cli53 tools on Windows?

    - by pavlos
    I'm trying to find the simplest way to import a large number of BIND zone files in to Route 53. I've had a quick look at the AWS CLI and AWS Tools for Windows PowerShell but they don't seem to include a zone file import option like the AWS Route53 GUI does. The cli53 utility on the other hand does, but is written in Python and appears to have a series of pre-requisites to get going which I'm having troubles working out for Windows. I can find plenty of examples of setting it up under Linux but only one reference to a PowerShell example here, but it doesn't explain how to install cli53 in the first place. The other option I'm exploring is to use the BIND to Amazon Route 53 Conversion Tool perl script to first convert the zone files to the Route53 CreateHostedZoneRequest XML format and then use the AWS New-R53HostedZone PowerShell cmdlet to import the zones. After the zones have been imported I'll be looking at running a script to validate what has been created in Route53 matches with the existing nameserver prior to updating each domains nameserver records - I was planning on whipping something up using the new PS4.0 Resolve-DnsName cmdlet, but let me know if you have any better suggestions. Any assistance would be greatly appreciated - thanks. (By the way, I had more reference links in my post but ServerFault won't allow me to post more than 2 links being a new member; and for this same reason I also can't comment on Vasili's example in the other linked thread)

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  • Changing Apple Mac environment www record

    - by chairish
    Apple server gurus? I have a Mac OSX Snow Leopard server question. How to be able to view a company's externally hosted website from inside the company? I inherited a company using Mac OSX Snow Leopard server. We moved the website away from MobileMe and into an environment that offers PHP etc. Although the site shows up correctly outside of the company, internally it looks to the MobileMe page and shows an error. I need to change the www record to reflect the change. Where do I do this on OSX Server?

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  • Networking setup for three systems

    - by srihari
    Hi, I want to setup a client server environment. I have three systems one with Solaris and the other two with windows. I want to install all the database and other software on the Server and enable the client systems a limited access to the system resources. Can anyone help me how to setup this and also the hardware requirements to setup such an environment. Your replies will be mostly appreciable and helpful to others who has similar thoughts or requirements. As we have more programmatical knowledge and less networking knowledge ,please explain in detail Please provide any vedio tutorials links or documents which will be helpfull in this regard. Thanks in Advance, Srihari.

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  • Getting mydomain.com/subdomain to resolve to subdomain.mydomain.com

    I have content on subdomain1.mydomain.com which can't reside on mydomain.com/subdomain1. Nevertheless, all my other content resides in folders of the mydomain.com/subdomain* type. For the sake of consistency, I'd like the content actually located at subdomain1.mydomain.com to appear as if it were on mydomain.com/subdomain1 — Is there any way, using .htaccess, that I can achieve this, bearing in mind that: (1) the subdomain itself also has a nested permalink structure, meaning that there are additional folders in the directory structure of the subdomain; (2) I want the browser to display the address as mydomain/subdomain1 after the redirect.

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  • Hosting 2 Sites Under 1 DiscountASP.Net Hosting Account

    - by Gav
    I've currently got an ASP.Net site hosted with DiscountASP.Net what I would like to do now is put a second site in a subdirectory of this original site and register a new domain to point at the subfolder, so to the end user its 2 completely seperate sites. I've asked DiscountASP support if they could do this and they just say they dont support it and wont help. If I registered the second domain with someone like 123-reg is it possible to make that domain point to a subdirectory in my main site? If not I may have to put some sort of redirect on my route index page that sends you to the right page based on the URL you requested but I would really rather not have to go there. I don't want to buy an additional account as the second site is just a bit of a side project that may well go no where.

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  • What's required for a nameserver to be registered?

    - by Lin
    I'm trying to change nameservers for some of my domains at GoDaddy, but I occasionally run into "Nameserver not registered" problems, and then I'm not allowed to set the nameservers. Here are the cases I've tried, and I still don't understand what it takes to have a registered nameserver. With ns1 and ns2 pointing to my nameservers, I can set the nameservers successfully when I set up domains as follows: Host Summary entries for ns1 and ns2 at GoDaddy .co.cc domains with A records for ONLY ns1 and ns2 Hosted with other nameservers. Have only A records for ns1 and ns2 But these do NOT work (nameserver not registered error): .info domains at GoDaddy with A records for ONLY ns1 and ns2 Hosts with dyndns.org that point to IP of nameservers Also, when I dig any domains hosted at my nameservers using any of the above, I get the correct response. So what's the deal here? Why do the last two cases get "nameserver not registered errors"? Thanks!

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  • How to make xxx.one.com load content from yyy.two.com

    - by Roy Peleg
    Hello, I'm currently in need to have xxx.one.com load the content of yyy.two.com. That means that when someone will enter xxx.one.com they'll actually see the content of yyy.two.com (URL in the browser won't change and will remain xxx.one.com). The domains are hosted on separate hosting company. yyy.two.com is on a cPanel and xxx.one.com is on an unknown hosting plan, though I can get its details. yyy.two.com have the same IP of www.two.com and this cannot be changed (as the hosting company told me). Any ideas on how do I tackle this issue? Thanks, Roy

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  • Can a CNAME be a hostname

    - by pulegium
    This is bit of a theological question, but nonetheless... So, a server has a hostname, let's say the fqdn is hostname.example.com (to be really precise about what I mean, this is the name that is set in /etc/sysconfig/network). The very same server has multiple interfaces on different subnets. Let's say the IPs are 10.0.0.1 and 10.0.1.1. Now the question is, is it theoretically (mind you, this is important, I know that practically it works, but I'm interested in purely academic answer) allowed to have the following setup: interface1.example.com. IN A 10.0.0.1 interface2.example.com. IN A 10.0.1.1 hostname.example.com. IN CNAME interface1.example.com. OR should it rather be: hostname.example.com. IN A 10.0.0.1 interface2.example.com. IN A 10.0.1.1 interface1.example.com. IN CNAME hostname.example.com. I guess it's obvious which one is making more sense from the management/administration POV, but is it technically correct? The argument against the first setup is that a reverse lookup to 10.0.0.1 returns interface1.example.com and not what one might expect (ie the hostname: hostname.example.com), so the forward request and then sub sequential reverse lookups would return different results. Now, as I said, I want a theoretical answer. Links to RFC sections etc, that explicitly allows or disallows use of CNAME name as a hostname. If there's none, that's fine too, I just need to confirm. I failed to find any explicit statements so far, bar this book, where this situation is given as an example and implies that it can be done as one of the ways to avoid MX records pointing to a CNAME.

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