should std::auto_ptr<>::operator = reset / deallocate its existing pointee ?
- by afriza
I read here about std::auto_ptr<::operator=
Notice however that the left-hand side
object is not automatically
deallocated when it already points to
some object. You can explicitly do
this by calling member function reset
before assigning it a new value.
However, when I read the source code for header file C:\Program Files\Microsoft Visual Studio 8\VC\ce\include\memory
template<class _Other>
auto_ptr<_Ty>& operator=(auto_ptr<_Other>& _Right) _THROW0()
{ // assign compatible _Right (assume pointer)
reset(_Right.release());
return (*this);
}
auto_ptr<_Ty>& operator=(auto_ptr<_Ty>& _Right) _THROW0()
{ // assign compatible _Right (assume pointer)
reset(_Right.release());
return (*this);
}
auto_ptr<_Ty>& operator=(auto_ptr_ref<_Ty> _Right) _THROW0()
{ // assign compatible _Right._Ref (assume pointer)
_Ty **_Pptr = (_Ty **)_Right._Ref;
_Ty *_Ptr = *_Pptr;
*_Pptr = 0; // release old
reset(_Ptr); // set new
return (*this);
}
What is the correct/standard behavior? How do other STL implementations behave?
