Setting variables in shell script by running commands
- by rajya vardhan
>cat /tmp/list1
john
jack
>cat /tmp/list2
smith
taylor
It is guaranteed that list1 and list2 will have equal number of lines.
f(){
i=1
while read line
do
var1 = `sed -n '$ip' /tmp/list1`
var2 = `sed -n '$ip' /tmp/list2`
echo $i,$var1,$var2
i=`expr $i+1`
echo $i,$var1,$var2
done < $INFILE
}
So output of f() should be:
1,john,smith
2,jack,taylor
But getting
1,p,p
1+1,p,p
If i replace following:
var1 = `sed -n '$ip' /tmp/list1`
var2 = `sed -n '$ip' /tmp/list2`
with this:
var1=`head -$i /tmp/vip_list|tail -1`
var2=`head -$i /tmp/lb_list|tail -1`
Then output:
1,john,smith
1,john,smith
Not an expert of shell, so please excuse if sounds childish :)
