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  • BlackBerry 10 : premières fonctionnalités et premières images exclusives de l'OS fondé sur QNX qui doit sauver RIM

    BlackBerry 10 : premières fonctionnalités et premières images exclusives Du futur OS mobile qui doit sauver RIM RIM a profité de sa conférence pour développeurs, le BlackBerry Jam, de passage à Paris pour dévoiler les premières informations sur son prochain OS. Si certains participants sont repartis avec des téléphones expérimentaux, des BlackBerry Dev Alpha - mélange de tablette PlayBook miniature et d'iPhone sans aucun bouton - ces appareils ne donnent cependant pas beaucoup d'indices sur ce que sera le système. Ces appareils ne sont en effet équipés que d'un simple navigateur. C'est en aparté que David Derrida, Directeur produit chez RIM France, a fait une première démon...

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  • Windows 8 : « un évènement technique grandiose pour les développeurs va marquer les esprit début juin », entretien avec Microsoft France

    Windows 8 : « Un évènement technique grandiose pour les développeurs va marquer les esprit début juin » Entretien avec Microsoft France David Catuhe est responsable, au sein de Microsoft France, des relations techniques avec les développeurs. Jovial et décontracté, il s'est entretenu avec nous des nombreuses initiatives que nous réserve Microsoft autour de Windows 8. Tour de France (actuellement en cours dans le cadre des Dev Camps), accélérateur et soirées spéciales, Microsoft entend visiblement mettre les bouchées doubles pour accompagner (et divertir) les développeurs jusqu'à la sortie officielle de so...

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  • How can give privilege for DB to a user [ ERROR 1044 (42000): Access denied for user ''@'localhost']

    - by Ahn
    I have created user in mysql 5.1 and given the ALL privilege, details given below, mysql> show GRANTS FOR test; +-------------------------------------------------------------+ | Grants for test@% | +-------------------------------------------------------------+ | GRANT ALL PRIVILEGES ON *.* TO 'test'@'%' WITH GRANT OPTION | | GRANT ALL PRIVILEGES ON `tt`.* TO 'test'@'%' | +-------------------------------------------------------------+ 2 rows in set (0.00 sec) But the show databases is not showing the databases on the mysql. It only shows as given below. How can give privilege for other DB s tables as well for the user 'test'? mysql> show databases; +--------------------+ | Database | +--------------------+ | information_schema | | test | +--------------------+ Error while I tried to use the mysql DB as user test: mysql> use mysql; ERROR 1044 (42000): Access denied for user ''@'localhost' to database 'mysql'

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  • BlackBerry 10 en images (4/9) : la Home, des vignettes dynamiques mais pas personnalisables

    BlackBerry 10 en images (1/9) : BlackBerry Flow RIM dévoile les nouveautés au compte-goutte et promet de très grosses surprises Deux jours après les annonces officielles du PDG de RIM, la filiale Française nous a conviés à une démonstration pour nous dévoiler « en vrai » quelques nouveautés supplémentaires de son prochain BlackBerry 10. « Son plus gros lancement de tous les temps », selon David Derrida, le responsable produit. Les voici en images au moment où le code est officiellement gelé. BlackBerry Flow C'est la nouvelle manière d'interagir avec l'OS. ...

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  • BlackBerry 10 en images (9/9) : et maintenant des surprises ? De très grosses, promet un porte-parole de RIM France

    BlackBerry 10 en images (1/9) : BlackBerry Flow RIM dévoile les nouveautés au compte-goutte et promet de très grosses surprises Deux jours après les annonces officielles du PDG de RIM, la filiale Française nous a conviés à une démonstration pour nous dévoiler « en vrai » quelques nouveautés supplémentaires de son prochain BlackBerry 10. « Son plus gros lancement de tous les temps », selon David Derrida, le responsable produit. Les voici en images au moment où le code est officiellement gelé. BlackBerry Flow C'est la nouvelle manière d'interagir avec l'OS. ...

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  • BlackBerry 10 en images : RIM dévoile ses nouveautés au compte-goutte et promet de très grosses surprises

    BlackBerry 10 en images (1/9) : BlackBerry Flow RIM dévoile les nouveautés au compte-goutte et promet de très grosses surprises Deux jours après les annonces officielles du PDG de RIM, la filiale Française nous a conviés à une démonstration pour nous dévoiler « en vrai » quelques nouveautés supplémentaires de son prochain BlackBerry 10. « Son plus gros lancement de tous les temps », selon David Derrida, le responsable produit. Les voici en images au moment où le code est officiellement gelé. BlackBerry Flow C'est la nouvelle manière d'interagir avec l'OS. ...

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  • E-commerce and Online Purchase Success

    The advent of the Internet technology opens another yet effective way of buying products. E-commerce websites are growing exponentially ? businesses understand its power for income and profit generat... [Author: David white - Computers and Internet - June 13, 2010]

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  • Zeroing SSD drives

    - by jtnire
    We host VPSes for customers. Each customer VPS is given an LVM LV on a standard spindle hard disk. If the customer were to leave, we zero out this LV ensuring that their data does not leak over to another customers. We are thinking of going with SSDs for our hosting business. Given that SSDs have the "wear levelling" technology, does that make zeroing pointless? Does this make this SSD idea unfeasable, given we can't allow customer data to leak over to another customer? Thanks

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  • BlackBerry 10 en images (6/9) : le navigateur champion toutes catégories du HTML5 ?

    BlackBerry 10 en images (1/9) : BlackBerry Flow RIM dévoile les nouveautés au compte-goutte et promet de très grosses surprises Deux jours après les annonces officielles du PDG de RIM, la filiale Française nous a conviés à une démonstration pour nous dévoiler « en vrai » quelques nouveautés supplémentaires de son prochain BlackBerry 10. « Son plus gros lancement de tous les temps », selon David Derrida, le responsable produit. Les voici en images au moment où le code est officiellement gelé. BlackBerry Flow C'est la nouvelle manière d'interagir avec l'OS. ...

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  • Best method to implement a filtered search

    - by j0N45
    I would like to ask you, your opinion when it comes to implement a filtered search form. Let's imagine the following case: 1 Big table with lots of columns It might be important to say that this SQL Server You need to implement a form to search data in this table, and in this form you'll have several check boxes that allow you to costumize this search. Now my question here is which one of the following should be the best way to implement the search? Create a stored procedure with a query inside. This stored procedure will check if the parameters are given by the application and in the case they are not given a wildcard will be putted in the query. Create a dynamic query, that is built accordingly to what is given by the application. I am asking this because I know that SQL Server creates an execution plan when the stored procedure is created, in order to optimize its performance, however by creating a dynamic query inside of the stored procedure will we sacrifice the optimization gained by the execution plan? Please tell me what would be the best approach in your oppinion.

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  • Windows 8 : « un évènement technique grandiose pour les développeurs va marquer les esprits début juin », entretien avec Microsoft France

    Windows 8 : « Un évènement technique grandiose pour les développeurs va marquer les esprits début juin » Entretien avec Microsoft France David Catuhe est responsable, au sein de Microsoft France, des relations techniques avec les développeurs. Jovial et décontracté, il s'est entretenu avec nous des nombreuses initiatives que nous réserve Microsoft autour de Windows 8. Tour de France (actuellement en cours dans le cadre des Dev Camps), accélérateur et soirées spéciales, Microsoft entend visiblement mettre les bouchées doubles pour accompagner (et divertir) les développeurs jusqu'à la sortie officielle de s...

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  • Can a DNS server return NXDOMAIN and an unresolved CNAME even though the alias exists?

    - by Martin
    I'm trying to understand why one given DNS server is not resolving our domain correctly. When I look up www.foo.com from this name server, a CNAME foo.bar.cc is correctly returned but there's no attached A record and the response status is NXDOMAIN. I understand that this could happen if the DNS server can not resolve the alias foo.bar.cc. However, if I use the same DNS server and look up foo.bar.cc directly, I always get the correct A record. When using any other DNS servers I've tested (different ISPs, Google DNS, Open DNS) our domain resolves correctly. Given this situation, is there some possible problem in our DNS that could cause this? Or does it seem like this given DNS server is to blame? The DNS server in question is used by a lot of people and it seems more likely that the problem is caused by us, but I don't see how - any clues?

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  • Tool to create unscaled call-out from a thumbnail image?

    - by Mal Ross
    I'm creating an online tutorial for some software and need to include screenshots. In particular, I want to highlight the position and appearance of a given control in a large screen. Given that I haven't got the space to show the screen at full resolution (at least, not alongside the tutorial text), I figured I would use a kind of call-out from a thumbnail. Here's my poor first effort, made in Paint.NET: Given how long this took me to craft, I'd really like to find a tool to speed things up (and make them look a little more professional!). Preferably a free one, too - or one that has a downloadable trial. The exact style it produces isn't that important, provided it achieves the desired effect. Can anyone help me out? Thanks, Mal. P.S. I'm using Windows Vista.

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  • Integer type or not [closed]

    - by kira
    I am writing a program (in cpp) to check the primality of a given number The point where i am struck is , I need to check in between the program wether the value i obtained upon some arithmetic operations on the input is an integer or not i.e lets say input is 'a' I want to know how to check if 'b' is integer or not (FYI, b=(a+1)/6 ) My attempt for this : int main() { using std::cin; using std::cout; int b,c; int a; cout<<"enter the number"; cin>>a; b=(a+1)/6; c=(a-1)/6; if (b is an integer) cout << "The given number is prime"; else if (c is an integer) cin << "The given number is prime!"; else cout<<"The number is not prime"; return 0; }

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  • BlackBerry 10 en images (8/9) : un téléphone ? Non, six ! A tous les prix, avec et sans clavier

    BlackBerry 10 en images (1/9) : BlackBerry Flow RIM dévoile les nouveautés au compte-goutte et promet de très grosses surprises Deux jours après les annonces officielles du PDG de RIM, la filiale Française nous a conviés à une démonstration pour nous dévoiler « en vrai » quelques nouveautés supplémentaires de son prochain BlackBerry 10. « Son plus gros lancement de tous les temps », selon David Derrida, le responsable produit. Les voici en images au moment où le code est officiellement gelé. BlackBerry Flow C'est la nouvelle manière d'interagir avec l'OS. ...

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  • BlackBerry 10 en images (5/9) : le clavier apprenant complétif et prédictif à auto-detection multilingue, en fait c'est simple

    BlackBerry 10 en images (1/9) : BlackBerry Flow RIM dévoile les nouveautés au compte-goutte et promet de très grosses surprises Deux jours après les annonces officielles du PDG de RIM, la filiale Française nous a conviés à une démonstration pour nous dévoiler « en vrai » quelques nouveautés supplémentaires de son prochain BlackBerry 10. « Son plus gros lancement de tous les temps », selon David Derrida, le responsable produit. Les voici en images au moment où le code est officiellement gelé. BlackBerry Flow C'est la nouvelle manière d'interagir avec l'OS. ...

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  • BlackBerry 10 en images (2/9) : Pick, un glisser de la gauche pour ne pas sortir des applications

    BlackBerry 10 en images (1/9) : BlackBerry Flow RIM dévoile les nouveautés au compte-goutte et promet de très grosses surprises Deux jours après les annonces officielles du PDG de RIM, la filiale Française nous a conviés à une démonstration pour nous dévoiler « en vrai » quelques nouveautés supplémentaires de son prochain BlackBerry 10. « Son plus gros lancement de tous les temps », selon David Derrida, le responsable produit. Les voici en images au moment où le code est officiellement gelé. BlackBerry Flow C'est la nouvelle manière d'interagir avec l'OS. ...

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  • Unable to debug javascript?

    - by linkme69
    I’m having some problems debugging an encoded javacscript. This script I’m referring to given in this link over here. The encoding here is simple and it works by shifting the unicodes values to whatever Codekey was use during encoding. The code that does the decoding is given here in plain English below:- <script language="javascript"> function dF(s){ var s1=unescape(s.substr(0,s.length-1)); var t=''; for(i=0;i<s1.length;i++)t+=String.fromCharCode(s1.charCodeAt(i)-s.substr(s.length-1,1)); document.write(unescape(t)); } I’m interested in knowing or understanding the values (e.g s1,t). Like for example when the value of i=0 what values would the following attributes / method would hold s1.charCodeAt(i) and s.substr(s.length-1,1) The reason I’m doing this is to understand as to how a CodeKey function really works. I don’t see anything in the code above which tells it to decode on the basis of codekey value. The only thing I can point in the encoding text is the last character which is set to 1 , 2 ,3 or 4 depending upon the codekey selected during encoding process. One can verify using the link I have given above. However, to debug, I’m using firebug addon with the script running as localhost on my wamp server. I’m able to put a breakpoint on the js using firebug but I’m unable to retrieve any of the user defined parameters or functions I mentioned above. I want to know under this context what would be best way to debug this encoded js.

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  • BlackBerry 10 en images (3/9) : BlackBerry Balance, une session Pro et une session privée hermétiquement séparées

    BlackBerry 10 en images (1/9) : BlackBerry Flow RIM dévoile les nouveautés au compte-goutte et promet de très grosses surprises Deux jours après les annonces officielles du PDG de RIM, la filiale Française nous a conviés à une démonstration pour nous dévoiler « en vrai » quelques nouveautés supplémentaires de son prochain BlackBerry 10. « Son plus gros lancement de tous les temps », selon David Derrida, le responsable produit. Les voici en images au moment où le code est officiellement gelé. BlackBerry Flow C'est la nouvelle manière d'interagir avec l'OS. ...

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  • Google App Engine - Secure Cookies

    - by tponthieux
    I'd been searching for a way to do cookie based authentication/sessions in Google App Engine because I don't like the idea of memcache based sessions, and I also don't like the idea of forcing users to create google accounts just to use a website. I stumbled across someone's posting that mentioned some signed cookie functions from the Tornado framework and it looks like what I need. What I have in mind is storing a user's id in a tamper proof cookie, and maybe using a decorator for the request handlers to test the authentication status of the user, and as a side benefit the user id will be available to the request handler for datastore work and such. The concept would be similar to forms authentication in ASP.NET. This code comes from the web.py module of the Tornado framework. According to the docstrings, it "Signs and timestamps a cookie so it cannot be forged" and "Returns the given signed cookie if it validates, or None." I've tried to use it in an App Engine Project, but I don't understand the nuances of trying to get these methods to work in the context of the request handler. Can someone show me the right way to do this without losing the functionality that the FriendFeed developers put into it? The set_secure_cookie, and get_secure_cookie portions are the most important, but it would be nice to be able to use the other methods as well. #!/usr/bin/env python import Cookie import base64 import time import hashlib import hmac import datetime import re import calendar import email.utils import logging def _utf8(s): if isinstance(s, unicode): return s.encode("utf-8") assert isinstance(s, str) return s def _unicode(s): if isinstance(s, str): try: return s.decode("utf-8") except UnicodeDecodeError: raise HTTPError(400, "Non-utf8 argument") assert isinstance(s, unicode) return s def _time_independent_equals(a, b): if len(a) != len(b): return False result = 0 for x, y in zip(a, b): result |= ord(x) ^ ord(y) return result == 0 def cookies(self): """A dictionary of Cookie.Morsel objects.""" if not hasattr(self,"_cookies"): self._cookies = Cookie.BaseCookie() if "Cookie" in self.request.headers: try: self._cookies.load(self.request.headers["Cookie"]) except: self.clear_all_cookies() return self._cookies def _cookie_signature(self,*parts): self.require_setting("cookie_secret","secure cookies") hash = hmac.new(self.application.settings["cookie_secret"], digestmod=hashlib.sha1) for part in parts:hash.update(part) return hash.hexdigest() def get_cookie(self,name,default=None): """Gets the value of the cookie with the given name,else default.""" if name in self.cookies: return self.cookies[name].value return default def set_cookie(self,name,value,domain=None,expires=None,path="/", expires_days=None): """Sets the given cookie name/value with the given options.""" name = _utf8(name) value = _utf8(value) if re.search(r"[\x00-\x20]",name + value): # Don't let us accidentally inject bad stuff raise ValueError("Invalid cookie %r:%r" % (name,value)) if not hasattr(self,"_new_cookies"): self._new_cookies = [] new_cookie = Cookie.BaseCookie() self._new_cookies.append(new_cookie) new_cookie[name] = value if domain: new_cookie[name]["domain"] = domain if expires_days is not None and not expires: expires = datetime.datetime.utcnow() + datetime.timedelta( days=expires_days) if expires: timestamp = calendar.timegm(expires.utctimetuple()) new_cookie[name]["expires"] = email.utils.formatdate( timestamp,localtime=False,usegmt=True) if path: new_cookie[name]["path"] = path def clear_cookie(self,name,path="/",domain=None): """Deletes the cookie with the given name.""" expires = datetime.datetime.utcnow() - datetime.timedelta(days=365) self.set_cookie(name,value="",path=path,expires=expires, domain=domain) def clear_all_cookies(self): """Deletes all the cookies the user sent with this request.""" for name in self.cookies.iterkeys(): self.clear_cookie(name) def set_secure_cookie(self,name,value,expires_days=30,**kwargs): """Signs and timestamps a cookie so it cannot be forged""" timestamp = str(int(time.time())) value = base64.b64encode(value) signature = self._cookie_signature(name,value,timestamp) value = "|".join([value,timestamp,signature]) self.set_cookie(name,value,expires_days=expires_days,**kwargs) def get_secure_cookie(self,name,include_name=True,value=None): """Returns the given signed cookie if it validates,or None""" if value is None:value = self.get_cookie(name) if not value:return None parts = value.split("|") if len(parts) != 3:return None if include_name: signature = self._cookie_signature(name,parts[0],parts[1]) else: signature = self._cookie_signature(parts[0],parts[1]) if not _time_independent_equals(parts[2],signature): logging.warning("Invalid cookie signature %r",value) return None timestamp = int(parts[1]) if timestamp < time.time() - 31 * 86400: logging.warning("Expired cookie %r",value) return None try: return base64.b64decode(parts[0]) except: return None uid=1234|1234567890|d32b9e9c67274fa062e2599fd659cc14 Parts: 1. uid is the name of the key 2. 1234 is your value in clear 3. 1234567890 is the timestamp 4. d32b9e9c67274fa062e2599fd659cc14 is the signature made from the value and the timestamp

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  • Minimum-Waste Print Job Grouping Algorithm?

    - by Matt Mc
    I work at a publishing house and I am setting up one of our presses for "ganging", in other words, printing multiple jobs simultaneously. Given that different print jobs can have different quantities, and anywhere from 1 to 20 jobs might need to be considered at a time, the problem would be to determine which jobs to group together to minimize waste (waste coming from over-printing on smaller-quantity jobs in a given set, that is). Given the following stable data: All jobs are equal in terms of spatial size--placement on paper doesn't come into consideration. There are three "lanes", meaning that three jobs can be printed simultaneously. Ideally, each lane has one job. Part of the problem is minimizing how many lanes each job is run on. If necessary, one job could be run on two lanes, with a second job on the third lane. The "grouping" waste from a given set of jobs (let's say the quantities of them are x, y and z) would be the highest number minus the two lower numbers. So if x is the higher number, the grouping waste would be (x - y) + (x - z). Otherwise stated, waste is produced by printing job Y and Z (in excess of their quantities) up to the quantity of X. The grouping waste would be a qualifier for the given set, meaning it could not exceed a certain quantity or the job would simply be printed alone. So the question is stated: how to determine which sets of jobs are grouped together, out of any given number of jobs, based on the qualifiers of 1) Three similar quantities OR 2) Two quantities where one is approximately double the other, AND with the aim of minimal total grouping waste across the various sets. (Edit) Quantity Information: Typical job quantities can be from 150 to 350 on foreign languages, or 500 to 1000 on English print runs. This data can be used to set up some scenarios for an algorithm. For example, let's say you had 5 jobs: 1000, 500, 500, 450, 250 By looking at it, I can see a couple of answers. Obviously (1000/500/500) is not efficient as you'll have a grouping waste of 1000. (500/500/450) is better as you'll have a waste of 50, but then you run (1000) and (250) alone. But you could also run (1000/500) with 1000 on two lanes, (500/250) with 500 on two lanes and then (450) alone. In terms of trade-offs for lane minimization vs. wastage, we could say that any grouping waste over 200 is excessive. (End Edit) ...Needless to say, quite a problem. (For me.) I am a moderately skilled programmer but I do not have much familiarity with algorithms and I am not fully studied in the mathematics of the area. I'm I/P writing a sort of brute-force program that simply tries all options, neglecting any option tree that seems to have excessive grouping waste. However, I can't help but hope there's an easier and more efficient method. I've looked at various websites trying to find out more about algorithms in general and have been slogging my way through the symbology, but it's slow going. Unfortunately, Wikipedia's articles on the subject are very cross-dependent and it's difficult to find an "in". The only thing I've been able to really find would seem to be a definition of the rough type of algorithm I need: "Exclusive Distance Clustering", one-dimensionally speaking. I did look at what seems to be the popularly referred-to algorithm on this site, the Bin Packing one, but I was unable to see exactly how it would work with my problem. Any help is appreciated. :)

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  • One letter game problem?

    - by Alex K
    Recently at a job interview I was given the following problem: Write a script capable of running on the command line as python It should take in two words on the command line (or optionally if you'd prefer it can query the user to supply the two words via the console). Given those two words: a. Ensure they are of equal length b. Ensure they are both words present in the dictionary of valid words in the English language that you downloaded. If so compute whether you can reach the second word from the first by a series of steps as follows a. You can change one letter at a time b. Each time you change a letter the resulting word must also exist in the dictionary c. You cannot add or remove letters If the two words are reachable, the script should print out the path which leads as a single, shortest path from one word to the other. You can /usr/share/dict/words for your dictionary of words. My solution consisted of using breadth first search to find a shortest path between two words. But apparently that wasn't good enough to get the job :( Would you guys know what I could have done wrong? Thank you so much. import collections import functools import re def time_func(func): import time def wrapper(*args, **kwargs): start = time.time() res = func(*args, **kwargs) timed = time.time() - start setattr(wrapper, 'time_taken', timed) return res functools.update_wrapper(wrapper, func) return wrapper class OneLetterGame: def __init__(self, dict_path): self.dict_path = dict_path self.words = set() def run(self, start_word, end_word): '''Runs the one letter game with the given start and end words. ''' assert len(start_word) == len(end_word), \ 'Start word and end word must of the same length.' self.read_dict(len(start_word)) path = self.shortest_path(start_word, end_word) if not path: print 'There is no path between %s and %s (took %.2f sec.)' % ( start_word, end_word, find_shortest_path.time_taken) else: print 'The shortest path (found in %.2f sec.) is:\n=> %s' % ( self.shortest_path.time_taken, ' -- '.join(path)) def _bfs(self, start): '''Implementation of breadth first search as a generator. The portion of the graph to explore is given on demand using get_neighboors. Care was taken so that a vertex / node is explored only once. ''' queue = collections.deque([(None, start)]) inqueue = set([start]) while queue: parent, node = queue.popleft() yield parent, node new = set(self.get_neighbours(node)) - inqueue inqueue = inqueue | new queue.extend([(node, child) for child in new]) @time_func def shortest_path(self, start, end): '''Returns the shortest path from start to end using bfs. ''' assert start in self.words, 'Start word not in dictionnary.' assert end in self.words, 'End word not in dictionnary.' paths = {None: []} for parent, child in self._bfs(start): paths[child] = paths[parent] + [child] if child == end: return paths[child] return None def get_neighbours(self, word): '''Gets every word one letter away from the a given word. We do not keep these words in memory because bfs accesses a given vertex only once. ''' neighbours = [] p_word = ['^' + word[0:i] + '\w' + word[i+1:] + '$' for i, w in enumerate(word)] p_word = '|'.join(p_word) for w in self.words: if w != word and re.match(p_word, w, re.I|re.U): neighbours += [w] return neighbours def read_dict(self, size): '''Loads every word of a specific size from the dictionnary into memory. ''' for l in open(self.dict_path): l = l.decode('latin-1').strip().lower() if len(l) == size: self.words.add(l) if __name__ == '__main__': import sys if len(sys.argv) not in [3, 4]: print 'Usage: python one_letter_game.py start_word end_word' else: g = OneLetterGame(dict_path = '/usr/share/dict/words') try: g.run(*sys.argv[1:]) except AssertionError, e: print e

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  • unrecognized selector sent to instance in xcode using objective c and sup as backend

    - by user1765037
    I am a beginner in native development.I made a project using xcode in objective C.It builded successfully.But when I run the project ,an error came like 'unrecognized selector sent to instance'.Why this is happening ?can anyone help me to solve this?I am attaching the error that I am getting with this.. And I am posting the code with this.... ConnectionController.m #import "ConnectionController.h" #import "SUPApplication.h" #import "Flight_DetailsFlightDB.h" #import "CallbackHandler.h" @interface ConnectionController() @property (nonatomic,retain)CallbackHandler *callbackhandler; @end @implementation ConnectionController @synthesize callbackhandler; static ConnectionController *appConnectionController; //Begin Application Setup +(void)beginApplicationSetup { if(!appConnectionController) { appConnectionController = [[[ConnectionController alloc]init]retain]; appConnectionController.callbackhandler = [[CallbackHandler getInstance]retain]; } if([SUPApplication connectionStatus] == SUPConnectionStatus_DISCONNECTED) [appConnectionController setupApplicationConnection]; else NSLog(@"Already Connected"); } -(BOOL)setupApplicationConnection { SUPApplication *app = [SUPApplication getInstance]; [app setApplicationIdentifier:@"HWC"]; [app setApplicationCallback:self.callbackhandler]; NSLog(@"inside setupApp"); SUPConnectionProperties *properties = [app connectionProperties]; NSLog(@"server"); [properties setServerName:@"sapecxxx.xxx.com"]; NSLog(@"inside setupAppser"); [properties setPortNumber:5001]; NSLog(@"inside setupApppot"); [properties setFarmId:@"0"]; NSLog(@"inside setupAppfarm"); [properties setUrlSuffix:@"/tm/?cid=%cid%"]; NSLog(@"inside setupAppurlsuff"); [properties setNetworkProtocol:@"http"]; SUPLoginCredentials *loginCred = [SUPLoginCredentials getInstance]; NSLog(@"inside setupAppmac"); [loginCred setUsername:@"mac"]; [loginCred setPassword:nil]; [properties setLoginCredentials:loginCred]; [properties setActivationCode:@"1234"]; if(![Flight_DetailsFlightDB databaseExists]) { [Flight_DetailsFlightDB createDatabase]; } SUPConnectionProfile *connprofile = [Flight_DetailsFlightDB getSynchronizationProfile]; [connprofile setNetworkProtocol:@"http"]; NSLog(@"inside setupAppPort2"); [connprofile setPortNumber:2480]; NSLog(@"inside setupAppser2"); [connprofile setServerName:@"sapecxxx.xxx.com"]; NSLog(@"inside setupAppdom2"); [connprofile setDomainName:@"Development"]; NSLog(@"inside setupAppuser"); [connprofile setUser:@"supAdmin"]; [connprofile setPassword:@"s3pAdmin"]; [connprofile setAsyncReplay:YES]; [connprofile setClientId:@"0"]; // [Flight_DetailsFlightDB beginOnlineLogin:@"supAdmin" password:@"s3pAdmin"]; [Flight_DetailsFlightDB registerCallbackHandler:self.callbackhandler]; [Flight_DetailsFlightDB setApplication:app]; if([SUPApplication connectionStatus] == SUPRegistrationStatus_REGISTERED) { [app startConnection:0]; } else { [app registerApplication:0]; } } @end ViewController.m #import "Demo_FlightsViewController.h" #import "ConnectionController.h" #import "Flight_DetailsFlightDB.h" #import "SUPObjectList.h" #import "Flight_DetailsSessionPersonalization.h" #import "Flight_DetailsFlight_MBO.h" #import "Flight_DetailsPersonalizationParameters.h" @interface Demo_FlightsViewController () @end @implementation Demo_FlightsViewController - (void)viewDidLoad { [super viewDidLoad]; // Do any additional setup after loading the view, typically from a nib. } -(IBAction)Connect:(id)sender { @try { [ConnectionController beginApplicationSetup]; } @catch (NSException *exception) { NSLog(@"ConnectionAborted"); } // synchronise } -(IBAction)Synchronise:(id)sender { @try { [Flight_DetailsFlightDB synchronize]; NSLog(@"SYNCHRONISED"); } @catch (NSException *exception) { NSLog(@"Synchronisation Failed"); } } -(IBAction)findall:(id)sender { SUPObjectList *list = [Flight_DetailsSessionPersonalization findAll]; NSLog(@"no of lines got synchronised is %d",list.size); } -(IBAction)confirm:(id)sender { Flight_DetailsPersonalizationParameters *pp = [Flight_DetailsFlightDB getPersonalizationParameters]; MBOLogInfo(@"personalisation parmeter for airline id= %@",pp.Airline_PK); [pp setAirline_PK:@"AA"]; [pp save]; while([Flight_DetailsFlightDB hasPendingOperations]) { [NSThread sleepForTimeInterval:1]; } NSLog(@"inside confirm............"); [Flight_DetailsFlightDB beginSynchronize]; Flight_DetailsFlight_MBO *flight = nil; SUPObjectList *cl = nil; cl =[Flight_DetailsFlight_MBO findAll]; if(cl && cl.length > 0) { int i; for(i=0;i<cl.length;i++) { flight = [cl item:i]; if(flight) { NSLog(@"details are %@",flight.CITYFROM); } } } } - (void)viewDidUnload { [super viewDidUnload]; // Release any retained subviews of the main view. } - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { return (interfaceOrientation != UIInterfaceOrientationPortraitUpsideDown); } @end SUPConnectionProfile.h #import "sybase_sup.h" #define FROM_IMPORT_THREAD TRUE #define FROM_APP_THREAD FALSE #define SUP_UL_MAX_CACHE_SIZE 10485760 @class SUPBooleanUtil; @class SUPNumberUtil; @class SUPStringList; @class SUPStringUtil; @class SUPPersistenceException; @class SUPLoginCertificate; @class SUPLoginCredentials; @class SUPConnectionProfile; /*! @class SUPConnectionProfile @abstract This class contains fields and methods needed to connect and authenticate to an SUP server. @discussion */ @interface SUPConnectionProfile : NSObject { SUPConnectionProfile* _syncProfile; SUPBoolean _threadLocal; SUPString _wrapperData; NSMutableDictionary* _delegate; SUPLoginCertificate* _certificate; SUPLoginCredentials* _credentials; int32_t _maxDbConnections; BOOL initTraceCalled; } /*! @method @abstract Return a new instance of SUPConnectionProfile. @discussion @result The SUPconnectionprofile object. */ + (SUPConnectionProfile*)getInstance; /*! @method @abstract Return a new instance of SUPConnectionProfile. @discussion This method is deprecated. use getInstance instead. @result The SUPconnectionprofile object. */ + (SUPConnectionProfile*)newInstance DEPRECATED_ATTRIBUTE NS_RETURNS_NON_RETAINED; - (SUPConnectionProfile*)init; /*! @property @abstract The sync profile. @discussion */ @property(readwrite, retain, nonatomic) SUPConnectionProfile* syncProfile; /*! @property @abstract The maximum number of active DB connections allowed @discussion Default value is 4, but can be changed by application developer. */ @property(readwrite, assign, nonatomic) int32_t maxDbConnections; /*! @method @abstract The SUPConnectionProfile manages an internal dictionary of key value pairs. This method returns the SUPString value for a given string. @discussion @param name The string. */ - (SUPString)getString:(SUPString)name; /*! @method @abstract The SUPConnectionProfile manages an internal dictionary of key value pairs. This method returns the SUPString value for a given string. If the value is not found, returns 'defaultValue'. @discussion @param name The string. @param defaultValue The default Value. */ - (SUPString)getStringWithDefault:(SUPString)name:(SUPString)defaultValue; /*! @method @abstract The SUPConnectionProfile manages an internal dictionary of key value pairs. This method returns the SUPBoolean value for a given string. @discussion @param name The string. */ - (SUPBoolean)getBoolean:(SUPString)name; /*! @method @abstract The SUPConnectionProfile manages an internal dictionary of key value pairs. This method returns the SUPBoolean value for a given string. If the value is not found, returns 'defaultValue'. @discussion @param name The string. @param defaultValue The default Value. */ - (SUPBoolean)getBooleanWithDefault:(SUPString)name:(SUPBoolean)defaultValue; /*! @method @abstract The SUPConnectionProfile manages an internal dictionary of key value pairs. This method returns the SUPInt value for a given string. @discussion @param name The string. */ - (SUPInt)getInt:(SUPString)name; /*! @method @abstract The SUPConnectionProfile manages an internal dictionary of key value pairs. This method returns the SUPInt value for a given string. If the value is not found, returns 'defaultValue'. @discussion @param name The string. @param defaultValue The default Value. */ - (SUPInt)getIntWithDefault:(SUPString)name:(SUPInt)defaultValue; /*! @method getUPA @abstract retrieve upa from profile @discussion if it is in profile's dictionary, it returns value for key "upa"; if it is not found in profile, it composes the upa value from base64 encoding of username:password; and also inserts it into profile's dictionary. @param none @result return string value of upa. */ - (SUPString)getUPA; /*! @method @abstract Sets the SUPString 'value' for the given 'name'. @discussion @param name The name. @param value The value. */ - (void)setString:(SUPString)name:(SUPString)value; /*! @method @abstract Sets the SUPBoolean 'value' for the given 'name'. @discussion @param name The name. @param value The value. */ - (void)setBoolean:(SUPString)name:(SUPBoolean)value; /*! @method @abstract Sets the SUPInt 'value' for the given 'name'. @discussion @param name The name. @param value The value. */ - (void)setInt:(SUPString)name:(SUPInt)value; /*! @method @abstract Sets the username. @discussion @param value The value. */ - (void)setUser:(SUPString)value; /*! @method @abstract Sets the password. @discussion @param value The value. */ - (void)setPassword:(SUPString)value; /*! @method @abstract Sets the ClientId. @discussion @param value The value. */ - (void)setClientId:(SUPString)value; /*! @method @abstract Returns the databasename. @discussion @param value The value. */ - (SUPString)databaseName; /*! @method @abstract Sets the databasename. @discussion @param value The value. */ - (void)setDatabaseName:(SUPString)value; @property(readwrite,copy, nonatomic) SUPString databaseName; /*! @method @abstract Gets the encryption key. @discussion @result The encryption key. */ - (SUPString)getEncryptionKey; /*! @method @abstract Sets the encryption key. @discussion @param value The value. */ - (void)setEncryptionKey:(SUPString)value; @property(readwrite,copy, nonatomic) SUPString encryptionKey; /*! @property @abstract The authentication credentials (username/password or certificate) for this profile. @discussion */ @property(retain,readwrite,nonatomic) SUPLoginCredentials *credentials; /*! @property @abstract The authentication certificate. @discussion If this is not null, certificate will be used for authentication. If this is null, credentials property (username/password) will be used. */ @property(readwrite,retain,nonatomic) SUPLoginCertificate *certificate; @property(readwrite, assign, nonatomic) BOOL initTraceCalled; /*! @method @abstract Gets the UltraLite collation creation parameter @discussion @result conllation string */ - (SUPString)getCollation; /*! @method @abstract Sets the UltraLite collation creation parameter @discussion @param value The value. */ - (void)setCollation:(SUPString)value; @property(readwrite,copy, nonatomic) SUPString collation; /*! @method @abstract Gets the maximum cache size in bytes; the default value for iOS is 10485760 (10 MB). @discussion @result max cache size */ - (int)getCacheSize; /*! @method @abstract Sets the maximum cache size in bytes. @discussion For Ultralite, passes the cache_max_size property into the connection parameters for DB connections; For SQLite, executes the "PRAGMA cache_size" statement when a connection is opened. @param cacheSize value */ - (void)setCacheSize:(int)cacheSize; @property(readwrite,assign, nonatomic) int cacheSize; /*! @method @abstract Returns the user. @discussion @result The username. */ - (SUPString)getUser; /*! @method @abstract Returns the password hash value. @discussion @result The password hash value. */ - (NSUInteger)getPasswordHash; /*! @method @abstract Returns the password. @discussion @result The password hash value. */ - (NSString*)getPassword; /*! @method @abstract Adds a new key value pair. @discussion @param key The key. @param value The value. */ - (void)add:(SUPString)key:(SUPString)value; /*! @method @abstract Removes the key. @discussion @param key The key to remove. */ - (void)remove:(SUPString)key; - (void)clear; /*! @method @abstract Returns a boolean indicating if the key is present. @discussion @param key The key. @result The result indicating if the key is present. */ - (SUPBoolean)containsKey:(SUPString)key; /*! @method @abstract Returns the item for the given key. @discussion @param key The key. @result The item. */ - (SUPString)item:(SUPString)key; /*! @method @abstract Returns the list of keys. @discussion @result The keylist. */ - (SUPStringList*)keys; /*! @method @abstract Returns the list of values. @discussion @result The value list. */ - (SUPStringList*)values; /*! @method @abstract Returns the internal map of key value pairs. @discussion @result The NSMutableDictionary with key value pairs. */ - (NSMutableDictionary*)internalMap; /*! @method @abstract Returns the domain name. @result The domain name. @discussion */ - (SUPString)getDomainName; /*! @method @abstract Sets the domain name. @param value The domain name. @discussion */ - (void)setDomainName:(SUPString)value; /*! @method @abstract Get async operation replay property. Default is true. @result YES : if ansync operation replay is enabled; NO: if async operation is disabled. @discussion */ - (BOOL) getAsyncReplay; /*! @method @abstract Set async operation replay property. Default is true. @result value: enable/disable async replay operation. @discussion */ - (void) setAsyncReplay:(BOOL) value; /*! @method @abstract enable or disable the trace in client object API. @param enable - YES: enable the trace; NO: disable the trace. @discussion */ - (void)enableTrace:(BOOL)enable; /*! @method @abstract enable or disable the trace with payload info in client object API. @param enable - YES: enable the trace; NO: disable the trace. @param withPayload = YES: show payload information; NO: not show payload information. @discussion */ - (void)enableTrace:(BOOL)enable withPayload:(BOOL)withPayload; /*! @method @abstract initialize trace levels from server configuration. @discussion */ - (void)initTrace; - (void)dealloc; /* ultralite/mobilink required parameters */ - (SUPString)getNetworkProtocol; - (void)setNetworkProtocol:(SUPString)protocol; - (SUPString)getNetworkStreamParams; - (void)setNetworkStreamParams:(SUPString)stream; - (SUPString)getServerName; - (void)setServerName:(SUPString)name; - (int)getPortNumber; - (void)setPortNumber:(int)port; - (int)getPageSize; - (void)setPageSize:(int)size; @end @interface SUPConnectionProfile(internal) - (void)applyPropertiesFromApplication; @end We are using SUP 2.1.3 library files.Please go through the code and help me...

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  • Parsing line and selecting values corresponding to a key

    - by gagneet
    there is a set of data which is arranged in a specific manner (as a tree), as is given below. basically a key=value pair, with some additional values at the end, which informs how many children does the branch have and some junk value. 11=1 123 2 11=1>1=45 234 1 11=1>1=45>9=16 345 1 11=1>1=45>9=16>2=34 222 1 11=1>1=45>9=16>2=34>7=0 2234 1 11=1>1=45>9=16>2=34>7=0>8=0 22345 1 11=1>1=45>9=16>2=34>7=0>8=0>0=138 22234 1 11=1>1=45>9=16>2=34>7=0>8=0>0=138>5=0 5566 1 11=1>1=45>9=16>2=34>7=0>8=0>0=138>5=0>4=0 664 1 11=1>1=45>9=16>2=34>7=0>8=0>0=138>5=0>4=0>6=10 443 1 11=1>1=45>9=16>2=34>7=0>8=0>0=138>5=0>4=0>6=10>3=11 445 0 11=1>1=47 4453 1 11=1>1=47>9=16 887 1 11=1>1=47>9=16>2=34 67 1 11=1>1=47>9=16>2=340>7=0 98 1 11=1>1=47>9=16>2=34>7=0>8=0 654 1 11=1>1=47>9=16>2=34>7=0>8=0>0=138 5789 1 11=1>1=47>9=16>2=34>7=0>8=0>0=138>5=0 9870 1 11=1>1=47>9=16>2=34>7=0>8=0>0=138>5=0>4=0 3216 1 11=1>1=47>9=16>2=34>7=0>8=0>0=138>5=0>4=0>6=10>3=11 66678 0 my problem is to get the appropriate branch from the above data, which satisfies exactly the values, which i give as the input. suppose, my input value to search in the above data stack are: 5=0 4=0 6=10 3=11 11=1 1=45 0=138 9=16 2=34 7=0 8=0 for the above given list of key-values, the function should return 11=11=459=162=347=08=00=1385=04=06=103=11 as the match. likewise, for another input file, in which another set of keys is given: 5=0 4=0 6=10 3=11 11=1 1=45 9=16 2=34 7=0 8=0 the function should return 11=11=459=162=347=08=0 1 as the match. not the last line; as that would also match all the values given in my input key, but, i want only the exact match. Also, I want to find out how many nodes were selected in the given array. (separated by ). What will be the best way to implement this kind of scenario?

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  • MKMap showing detail of annotations

    - by yeohchan
    I have encountered a problem of populating the description for each annotation. Each annotation works, but there is somehow an area when trying to click on it. Here is the code. the one in bold is the one that has the problem. -(void)viewDidLoad{ FlickrFetcher *fetcher=[FlickrFetcher sharedInstance]; NSArray *rec=[fetcher recentGeoTaggedPhotos]; for(NSDictionary *dic in rec){ NSLog(@"%@",dic); NSDictionary *string = [fetcher locationForPhotoID:[dic objectForKey:@"id"]]; double latitude = [[string objectForKey:@"latitude"] doubleValue]; double longitude = [[string objectForKey:@"longitude"]doubleValue]; if(latitude !=0 && latitude != 0 ){ CLLocationCoordinate2D coordinate1 = { latitude,longitude }; **NSDictionary *adress=[NSDictionary dictionaryWithObjectsAndKeys:[dic objectForKey:@"owner"],[dic objectForKey:@"title"],nil];** MKPlacemark *anArea=[[MKPlacemark alloc]initWithCoordinate:coordinate1 addressDictionary:adress]; [mapView addAnnotation:anArea]; } } } Here is what the Flickr class does: #import <Foundation/Foundation.h> #define TEST_HIGH_NETWORK_LATENCY 0 typedef enum { FlickrFetcherPhotoFormatSquare, FlickrFetcherPhotoFormatLarge } FlickrFetcherPhotoFormat; @interface FlickrFetcher : NSObject { NSManagedObjectModel *managedObjectModel; NSManagedObjectContext *managedObjectContext; NSPersistentStoreCoordinator *persistentStoreCoordinator; } // Returns the 'singleton' instance of this class + (id)sharedInstance; // // Local Database Access // // Checks to see if any database exists on disk - (BOOL)databaseExists; // Returns the NSManagedObjectContext for inserting and fetching objects into the store - (NSManagedObjectContext *)managedObjectContext; // Returns an array of objects already in the database for the given Entity Name and Predicate - (NSArray *)fetchManagedObjectsForEntity:(NSString*)entityName withPredicate:(NSPredicate*)predicate; // Returns an NSFetchedResultsController for a given Entity Name and Predicate - (NSFetchedResultsController *)fetchedResultsControllerForEntity:(NSString*)entityName withPredicate:(NSPredicate*)predicate; // // Flickr API access // NOTE: these are blocking methods that wrap the Flickr API and wait on the results of a network request // // Returns an array of Flickr photo information for photos with the given tag - (NSArray *)photosForUser:(NSString *)username; // Returns an array of the most recent geo-tagged photos - (NSArray *)recentGeoTaggedPhotos; // Returns a dictionary of user info for a given user ID. individual photos contain a user ID keyed as "owner" - (NSString *)usernameForUserID:(NSString *)userID; // Returns the photo for a given server, id and secret - (NSData *)dataForPhotoID:(NSString *)photoID fromFarm:(NSString *)farm onServer:(NSString *)server withSecret:(NSString *)secret inFormat:(FlickrFetcherPhotoFormat)format; // Returns a dictionary containing the latitue and longitude where the photo was taken (among other information) - (NSDictionary *)locationForPhotoID:(NSString *)photoID; @end

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