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• How to setup a django site with Cherokee, DynDNS and virtual_env?

  - by e-satis

  I have a django project running with the dev server, and would like to try run it in a production environment. I wanted to try Cherokee for a change, so I installed it. We don't have a domain name yet, so I set up a DynDNS looking like stuff.gotdns.org. It works fine, I can see the Cherokee welcome page (so red, I first believed I got an error :-p). I ran the wizard to create a new virtual server for Django. No everything is setup, but I have nothing. Still the default Cherokee welcome page. What should I do now if I want to go to "http://stuff.gotdns.org" and see my website? What should I do now if I next want to make it available only at "http://project.stuff.gotdns.org"? Important fact, I use virtual_env, so your can call Python directly, you have to activate it first.

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• Django, wsgi, py. what's the difference?

  - by Kenny

  I'm trying to get a django application up and running on my cpanel system. I've installed mod_wsgi, and am following the guide here: http://www.nerdydork.com/setting-up-django-on-a-whm-cpanel-vps-liquidweb.html However, I'm now confused as I don't know what to do next. The application has .py files, and I am able to run it via this: python manage.py runserver 211.144.131.148:8000 However, that's via command line and binds to port 8000. I want to use Apache instead. The question is, that tutorial doesn't go further into how to get apache to recognize .py files and run the application as I want it. What do I do next?

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• Google App Engine (python): TemplateSyntaxError: 'for' statements with five words should end in 'rev

  - by Phil

  This is using the web app framework, not Django. The following template code is giving me an TemplateSyntaxError: 'for' statements with five words should end in 'reversed' error when I try to render a dictionary. I don't understand what's causing this error. Could somebody shed some light on it for me? {% for code, name in charts.items %} <option value="{{code}}">{{name}}</option> {% endfor %} I'm rendering it using the following: class GenerateChart(basewebview): def get(self): values = {"datepicker":True} values["charts"] = {"p3": "3D Pie Chart", "p": "Segmented Pied Chart"} self.render_page("generatechart.html", values) class basewebview(webapp.RequestHandler): ''' Base class for all webapp.RequestHandler type classes ''' def render_page(self, filename, template_values=dict()): filename = "%s/%s" % (_template_dir, filename) path = os.path.join(os.path.dirname(__file__), filename) self.response.out.write(template.render(path, template_values))

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• Hooking up Sproutcore frontend and custom Python backend

  - by Suvir

  Hello everyone, I am building a web-based application. The frontend has been designed in Sproutcore. For the backend, we have our own python API which handles all transactions with multiple databases. What is the best way to hook up the front-end with the back-end. AFAIK django is pretty monolithic (correct me if i am wrong) and it would be cumbersome if I dont use its native ORM...I would prefer a python-based solution..any ideas? thanks! Suvir

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• Why don't these class attributes register?

  - by slypete

  I have a factory method that generates django form classes like so: def get_indicator_form(indicator, patient): class IndicatorForm(forms.Form): #These don't work! indicator_id = forms.IntegerField(initial=indicator.id, widget=forms.HiddenInput()) patient_id = forms.IntegerField(initial=patient.id, widget=forms.HiddenInput()) def __init__(self, *args, **kwargs): forms.Form.__init__(self, *args, **kwargs) self.indicator = indicator self.patient = patient #These do! setattr(IndicatorForm, 'indicator_id', forms.IntegerField(initial=indicator.id, widget=forms.HiddenInput())) setattr(IndicatorForm, 'patient_id', forms.IntegerField(initial=patient.id, widget=forms.HiddenInput())) for field in indicator.indicatorfield_set.all(): setattr(IndicatorForm, field.name, copy(field.get_field_type())) return type('IndicatorForm', (forms.Form,), dict(IndicatorForm.__dict__)) I'm trying to understand why the top form field declarations don't work, but the setattr method below does work. I'm fairly new to python, so I suspect it's some language feature that I'm misunderstanding. Can you help me understand why the field declarations at the top of the class don't add the fields to the class? In a possibly related note, when these classes are instantiated, instance.media returns nothing even though some fields have widgets with associated media. Thanks, Pete

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• Search over multiple fields

  - by schneck

  Hi there, I think I don't unterstand django-haystack properly: I have a data model containing several fields, and I would to have two of them searched: class UserProfile(models.Model): user = models.ForeignKey(User, unique=True, default=None) twitter_account = models.CharField(max_length=50, blank=False) My search index settings: class UserProfileIndex(SearchIndex): text = CharField(document=True, model_attr='user') twitter_account = CharField(model_attr='twitter_account') def get_queryset(self): """Used when the entire index for model is updated.""" return UserProfile.objects.all() But when I perform a search, only the field "username" is searched; "twitter_account" is ignored. When I select the Searchresults via dbshell, the objects contain the correct values for "user" and "twitter_account", but the result page shows a "no results": {% if query %} <h3>Results</h3> {% for result in page.object_list %} <p> <a href="{{ result.object.get_absolute_url }}">{{ result.object.id }}</a> </p> {% empty %} <p>No results</p> {% endfor %} {% endif %} Any ideas?

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• Cache for everybody except staff members.

  - by Oli

  I have a django site where I want to stick an "admin bar" along the top of every non-admin page for staff members. It would contain useful things like page editing tools, etc. The problem comes from me using the @cache_page decorator on lots of pages. If a normal user hits a page, the cached version comes up without the admin bar (even for admin users) and if an admin hits the page first, normal users see the admin bar. I could tediously step through the templates, adding regional cache blocks but there are a lot of templates, and life is altogether too short. Ideally, there would be a way of telling the caching to ignore cache get/set requests from admin users... But I don't know how to best implement that. How would you tackle this problem?

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• How do I prevent a ManyToManyField('self') from linked an object to itself?

  - by dyve

  Consider this model (simplified for this question): class SecretAgentName(models.Model): name = models.CharField(max_length=100) aliases = ManyToManyField('self') I have three names, "James Bond", "007" and "Jason Bourne". "James Bond" and "007" are aliases of each other. This works exactly like I want it to, except for the fact that every instance can also be an alias of itself. This I want to prevent. So, there can be many SecretAgentNames, all can be aliases of each other as long as "James Bond" does not show up as an alias for "James Bond". Can I prevent this in the model definition? If not, can I prevent it anywhere else, preferably so that the Django Admin understands it?

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• Removing a result from Queryset

  - by Enrico

  Is there a simple way to discard/remove the last result in a queryset without affecting the db? I am trying to paginate results in Django, but don't know the total number of objects for a given query. I was planning on using next/previous or older/newer links, so I only need to know if this is the first and/or last page. First is easy to check. To check for the last page I can compare the number of results with the pagesize or make a second query. The first method fails to detect the last page when the number of results in the last set equals the pagesize (ie 100 records get broken into 10 pages with the last page containing exactly 10 results) and I would like to avoid making a second query. My current thought is that I should fetch pagesize + 1 results from the db. If the queryset length equals 11, I know this is not the last page and I want to discard the last result in the queryset before passing the queryset to the template.

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• Quering distinct values throught related model

  - by matheus.emm

  Hi! I have a simple one-to-many (models.ForeignKey) relationship between two of my model classes: class TeacherAssignment(models.Model): # ... some fields year = models.CharField(max_length=4) class LessonPlan(models.Model): teacher_assignment = models.ForeignKey(TeacherAssignment) # ... other fields I'd like to query my database to get the set of distinct years of TeacherAssignments related to at least one LessonPlan. I'm able to get this set using Django query API if I ignore the relation to LessonPlan: class TeacherAssignment(models.Model): # ... model's fields def get_years(self): year_values = self.objects.all().values_list('year').distinct().order_by('-year') return [yv[0] for yv in year_values if len(yv[0]) == 4] Unfortunately I don't know how to express the condition that the TeacherAssignment must be related to at least one LessonPlan. Any ideas how I'd be able to write the query? Thanks in advance.

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• Is it ok to hardcode dynamic links in a permanent view?

  - by meder

  Let's say I wanted to showcase 2-3 clickable buttons on my homepage which will be there permanently. These are links to the css, html, and javascript tag listing pages. Is it fine to just hardcode href=/tags/css and href=/tags/html right in my django templates/view? I won't change them for at least a year or so, meaning I don't think I need to add a column to the tags table to distinguish them - is this common or should I try to make it somewhat dynamic? These tags are in a table but so are 1000 other tags.

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• Passing session data to ModelForm inside of ModelAdmin

  - by theactiveactor

  I'm trying to initialize the form attribute for MyModelAdmin class inside an instance method, as follows: class MyModelAdmin(admin.ModelAdmin): def queryset(self, request): MyModelAdmin.form = MyModelForm(request.user) My goal is to customize the editing form of MyModelForm based on the current session. When I try this however, I keep getting an error (shown below). Is this the proper place to pass session data to ModelForm? If so, then what may be causing this error? TypeError at ... Exception Type: TypeError Exception Value: issubclass() arg 1 must be a class Exception Location: /usr/lib/pymodules/python2.6/django/forms/models.py in new, line 185

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• Saving related model objects

  - by iHeartDucks

  I have two related models (one to many) in my django app and When I do something like this ObjBlog = Blog() objBlog.name = 'test blog' objEntry1 = Entry() objEntry1.title = 'Entry one' objEntry2 = Entry() objEntry2.title = 'Entry Two' objBlog.entry_set.add(objEntry1) objBlog.entry_set.add(objEntry2) I get an error which says "null value in column and it violates the foreign key not null constraint". None of my model objects have been saved. Do I have to save the "objBlog" before I could set the entries? I was hoping I could call the save method on objBlog to save it all. NOTE: I am not creating a blog engine and this is just an example.

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• Select distinct users with referrals

  - by Mark

  I have a bunch of Users. Since Django doesn't really let me extend the default User model, they each have Profiles. The Profiles have a referred_by field (a FK to User). I'm trying to get a list of Users with = 1 referral. Here's what I've got so far Profile.objects.filter(referred_by__isnull=False).values_list('referred_by', flat=True) Which gives me a list of IDs of the users who have referrals... but I need it to be distinct, and I want the User object, not their ID. Or better yet, it would be nice if it could return the number of referrals a user has. Any ideas?

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• Overwrite queryset which builds filter sidebar

  - by cw

  Hi, I'm writing a hockey database/manager. So I have the following models: class Team(models.Model): name = models.CharField(max_length=60) class Game(models.Model): home_team = models.ForeignKey(Team,related_name='home_team') away_team = models.ForeignKey(Team,related_name='away_team') class SeasonStats(models.Model): team = models.ForeignKey(Team) Ok, so my problem is the following. There are a lot of teams, but Stats are just managed for my Club. So if I use "list_display" in the admin backend, I'd like to modify/overwrite the queryset which builds the sidebar for filtering, to just display our home teams as a filter option. Is this somehow possible in Django? I already made a custom form like this class SeasonPlayerStatsAdminForm(forms.ModelForm): team = forms.ModelChoiceField(Team.objects.filter(club__home=True)) So now just the filtering is missing. Any ideas?

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• Enable export to XML via HTTP on a large number of models with child relations

  - by Vasil

  I've a large number of models (120+) and I would like to let users of my application export all of the data from them in XML format. I looked at django-piston, but I would like to do this with minimum code. Basically I'd like to have something like this: GET /export/applabel/ModelName/ Would stream all instances of ModelName in applabel together with it's tree of related objects . I'd like to do this without writing code for each model. What would be the best way to do this?

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• Errors in Decimal Calcs within def clean method?

  - by allanhenderson

  I'm attempting a few simple calculations in a def clean method following validation (basically spitting out a euro conversion of retrieved uk product price on the fly). I keep getting a TypeError. Full error reads: Cannot convert {'product': , 'invoice': , 'order_discount': Decimal("0.00"), 'order_price': {...}, 'order_adjust': None, 'order_value': None, 'DELETE': False, 'id': 92, 'quantity': 8} to Decimal so I guess django is passing through the entire cleaned_data form to Decimal method. Not sure where I'm going wrong - the code I'm working with is: def clean_order_price(self): cleaned_data = self.cleaned_data data = self.data order_price = cleaned_data.get("order_price") if not order_price: try: existing_price = ProductCostPrice.objects.get(supplier=data['supplier'], product_id=cleaned_data['product'], is_latest=True) except ProductCostPrice.DoesNotExist: existing_price = None if not existing_price: raise forms.ValidationError('No match found, please enter new price') else: if data['invoice_type'] == 1: return existing_price.cost_price_gross elif data['invoice_type'] == 2: exchange = EuroExchangeRate.objects.latest('exchange_date') calc = exchange.exchange_rate * float(existing_price.cost_price_gross) calc = Decimal(str(calc)) return calc return cleaned_data If the invoice is of type 2 (a euro invoice) then the system should grab the latest exchange rate and apply that to the matching UK pound price pulled through to get euro result. Should performing a decimal conversion be a problem within def clean method? Thanks

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• Elegant solution for multiple forms on single page

  - by NFicano

  I'm building a web application (in Django) that will accept a search criteria and display a report - once the user is satisfied with the results, save both the criteria and a reference to these objects back to the database. The problem I'm having is finding an elegant solution for having 2 forms: Display (GET) the results of their criteria. Enter in some descriptions, and save (POST) everything back to the database. I'm leaning towards AJAX for the GET stuff and a POST for the save, but I wanted to make sure there wasn't a more elegant solution first.

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• Indexing a method return (depending on Internationalization)

  - by Hedde

  Consider a django model with an IntegerField with some choices, e.g. COLORS = ( (0, _(u"Blue"), (1, _(u"Red"), (2, _(u"Yellow"), ) class Foo(models.Model): # ...other fields... color = models.PositiveIntegerField(choices=COLOR, verbose_name=_(u"color")) My current (haystack) index: class FooIndex(SearchIndex): text = CharField(document=True, use_template=True) color = CharField(model_attr='color') def prepare_color(self, obj): return obj.get_color_display() site.register(Product, ProductIndex) This obviously only works for keyword "yellow", but not for any (available) translations. Question: What's would be a good way to solve this problem? (indexing method returns based on the active language) What I have tried: I created a function that runs a loop over every available language (from settings) appending any translation to a list, evaluating this against the query, pre search. If any colors are matched it converts them backwards into their numeric representation to evaluate against obj.color, but this feels wrong.

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• Not quite nested inlines?

  - by Lynden Shields

  Not quite sure what to call this, it's not quite nested inlines, but is probably related. I have a 3 level hierarchy of objects, A one-to-many B one-to-many C. Therefore, every C implicitly also belongs to an A. class A(models.Model): stuff = models.CharField("Stuff", max_length=50) class B(models.Model): a = models.ForeignKey(A) class C(models.Model): b = models.ForeignKey(B) I would like all C's that belong to an A to be listed on the admin page for A in an in-line. They do not have to show which B they belong to on the same page. Is this possible or is it the same problem as nested inlines anyway? If it's possible, how do I do it? I'm using django 1.3

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• Preview hidden options on web sites

  - by veili_13

  I want to have hidden options on my web site and be previewed only when the user chooses. I want to animate them from left and right (about 15%). At the moment I have them visible in my html but with width set at 0 and animate it at 15%. In these containers are many options which should disappear to the left/right (with slide effect). But I am not so sure that having all of this in my HTML so I am thinking to create them with jQuery, with 0 width and animating it to it's should be width and setting the other elements to 0 width. Is this approach good, or should I create them and hide the overflow so I would animate position. Or is there a better approach ??

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• How to See What Web Sites Your Computer is Secretly Connecting To

  - by Lori Kaufman

  Has your internet connection become slower than it should be? There may be a chance that you have some malware, spyware, or adware that is using your internet connection in the background without your knowledge. Here’s how to see what’s going on under the hood. Secret Squirrel by akumath HTG Explains: When Do You Need to Update Your Drivers? How to Make the Kindle Fire Silk Browser *Actually* Fast! Amazon’s New Kindle Fire Tablet: the How-To Geek Review

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• Top web-hosting sites with jQuery support?

  - by Anthony Forloney

  I am looking to start building a website and I am looking for some good web hosting companies that gives the best bang for the buck. I had been reading on some websites in regards to some web hosting companies having the inability to run scripts on their servers (jQuery) which causes a big problem since the website I am in the process of making is very jQuery driven. Can anyone recommend some good web hosting companies that they had good experience with? As of now, I checked out Google's web-hosting service and read up on a few companies from Top 10 Web Hosting List but would like a few recommendations.

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• Webcast with Brian Griffin, Ancestry, 2013 Winner 10 Best Web Support Sites

  - by Tuula Fai

  The web is one of the fastest growing channels for providing service, support and information, as seen in The Service Council's (TSC) latest multi-channel research survey. Join TSC's Chief Customer Officer Sumair Dutta as he shares key findings from his current customer experience research from over 200 organizations. Sumair will be joined by Brian Griffin, Senior Program Manager, Global Support Experience, Ancestry.com who will show how Ancestry is using the web as a powerful tool to enhance self-service opportunities and increase customer engagement. Smarter Web Service Educast Thursday, November 14th 2 pm ET / 11 am PT Register: http://bit.ly/1cwz4Ns  

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• Open Multiple Sites Without Reopening the Menus in Firefox

  - by Asian Angel

  Are you frustrated with having to reopen your menus for each website that you need or want to view? Now you can keep those menus open while opening multiple websites with the Stay-Open Menu extension for Firefox. Stay-Open Menu in Action You can start using the extension as soon as you have installed it…simply access your favorite links in the “Bookmarks Menu, Bookmarks Toolbar, Awesome Bar, or History Menu” and middle click on the appropriate entries. Here you can see our browser opening the Productive Geek website and that the “Bookmarks Menu” is still open. As soon as you left click on a link or click outside the menus they will close normally like before. Note: Middle clicked links open in new tabs. The only time during our tests that a newly opened link “remained in the background” was for any links opened from the “Awesome Bar”. But as soon as the “Awesome Bar” was closed the new tabs automatically focused to the front. A link being opened from the “History Menu”…still open while the webpage is loading. Options The options are simple to sort through…enable or disable the additional “stay open” functions and enable automatic menu closing if desired. Conclusion If you get frustrated with having to reopen menus to access multiple webpages at one time then you might want to give this extension a try. Links Download the Stay-Open Menu extension (Mozilla Add-ons) Similar Articles Productive Geek Tips Make Firefox Use Multiple Rows of TabsDisable Web Site Window Resizing in FirefoxQuick Hits: 11 Firefox Tab How-TosPrevent Annoying Websites From Messing With the Right-Click Menu in FirefoxJatecblog Moves to How-To Geek Blogs (Linux Readers Should Subscribe) TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional StockFox puts a Lightweight Stock Ticker in your Statusbar Explore Google Public Data Visually The Ultimate Excel Cheatsheet Convert the Quick Launch Bar into a Super Application Launcher Automate Tasks in Linux with Crontab Discover New Bundled Feeds in Google Reader

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