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  • How to make a div to fill a remaining horizontal space (a very simple but annoying problem for CSS e

    - by janoChen
    I have 2 divs: one in the left side and one in the right side of my page. The one in the left side has fixed width and I want the one of the right side to fill the remaining space. The one on the right side is the navigation and I want it to to fill the remaining space on it right side: My CSS: #search { width: 160px; height: 25px; float: left; background-color: #FFF; } #navigation { width: 780 float: left; /*background-color: url('../images/transparent.png') ;*/ background-color: #A53030; } My Html: <div id="search"> </div> <?php include("navigation.html"); ?> <div id="left-column"> Thank in advance!

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  • Nesting Linq-to-Objects query within Linq-to-Entities query –what is happening under the covers?

    - by carewithl
    var numbers = new int[] { 1, 2, 3, 4, 5 }; var contacts = from c in context.Contacts where c.ContactID == numbers.Max() | c.ContactID == numbers.FirstOrDefault() select c; foreach (var item in contacts) Console.WriteLine(item.ContactID); Linq-to-Entities query is first translated into Linq expression tree, which is then converted by Object Services into command tree. And if Linq-to-Entities query nests Linq-to-Objects query, then this nested query also gets translated into an expression tree. a) I assume none of the operators of the nested Linq-to-Objects query actually get executed, but instead data provider for particular DB (or perhaps Object Services) knows how to transform the logic of Linq-to-Objects operators into appropriate SQL statements? b) Data provider knows how to create equivalent SQL statements only for some of the Linq-to-Objects operators? c) Similarly, data provider knows how to create equivalent SQL statements only for some of the non-Linq methods in the Net Framework class library? EDIT: I know only some Sql so I can't be completely sure, but reading Sql query generated for the above code it seems data provider didn't actually execute numbers.Max method, but instead just somehow figured out that numbers.Max should return the maximum value and then proceed to include in generated Sql query a call to TSQL's build-in MAX function. It also put all the values held by numbers array into a Sql query. SELECT CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN '0X0X' ELSE '0X1X' END AS [C1], [Extent1].[ContactID] AS [ContactID], [Extent1].[FirstName] AS [FirstName], [Extent1].[LastName] AS [LastName], [Extent1].[Title] AS [Title], [Extent1].[AddDate] AS [AddDate], [Extent1].[ModifiedDate] AS [ModifiedDate], [Extent1].[RowVersion] AS [RowVersion], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[CustomerTypeID] END AS [C2], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[InitialDate] END AS [C3], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[PrimaryDesintation] END AS [C4], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[SecondaryDestination] END AS [C5], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[PrimaryActivity] END AS [C6], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[SecondaryActivity] END AS [C7], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[Notes] END AS [C8], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[RowVersion] END AS [C9], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[BirthDate] END AS [C10], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[HeightInches] END AS [C11], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[WeightPounds] END AS [C12], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[DietaryRestrictions] END AS [C13] FROM [dbo].[Contact] AS [Extent1] LEFT OUTER JOIN (SELECT [Extent2].[ContactID] AS [ContactID], [Extent2].[BirthDate] AS [BirthDate], [Extent2].[HeightInches] AS [HeightInches], [Extent2].[WeightPounds] AS [WeightPounds], [Extent2].[DietaryRestrictions] AS [DietaryRestrictions], [Extent3].[CustomerTypeID] AS [CustomerTypeID], [Extent3].[InitialDate] AS [InitialDate], [Extent3].[PrimaryDesintation] AS [PrimaryDesintation], [Extent3].[SecondaryDestination] AS [SecondaryDestination], [Extent3].[PrimaryActivity] AS [PrimaryActivity], [Extent3].[SecondaryActivity] AS [SecondaryActivity], [Extent3].[Notes] AS [Notes], [Extent3].[RowVersion] AS [RowVersion], cast(1 as bit) AS [C1] FROM [dbo].[ContactPersonalInfo] AS [Extent2] INNER JOIN [dbo].[Customers] AS [Extent3] ON [Extent2].[ContactID] = [Extent3].[ContactID]) AS [Project1] ON [Extent1].[ContactID] = [Project1].[ContactID] LEFT OUTER JOIN (SELECT TOP (1) [c].[C1] AS [C1] FROM (SELECT [UnionAll3].[C1] AS [C1] FROM (SELECT [UnionAll2].[C1] AS [C1] FROM (SELECT [UnionAll1].[C1] AS [C1] FROM (SELECT 1 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable1] UNION ALL SELECT 2 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable2]) AS [UnionAll1] UNION ALL SELECT 3 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable3]) AS [UnionAll2] UNION ALL SELECT 4 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable4]) AS [UnionAll3] UNION ALL SELECT 5 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable5]) AS [c]) AS [Limit1] ON 1 = 1 LEFT OUTER JOIN (SELECT TOP (1) [c].[C1] AS [C1] FROM (SELECT [UnionAll7].[C1] AS [C1] FROM (SELECT [UnionAll6].[C1] AS [C1] FROM (SELECT [UnionAll5].[C1] AS [C1] FROM (SELECT 1 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable6] UNION ALL SELECT 2 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable7]) AS [UnionAll5] UNION ALL SELECT 3 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable8]) AS [UnionAll6] UNION ALL SELECT 4 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable9]) AS [UnionAll7] UNION ALL SELECT 5 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable10]) AS [c]) AS [Limit2] ON 1 = 1 CROSS JOIN (SELECT MAX([UnionAll12].[C1]) AS [A1] FROM (SELECT [UnionAll11].[C1] AS [C1] FROM (SELECT [UnionAll10].[C1] AS [C1] FROM (SELECT [UnionAll9].[C1] AS [C1] FROM (SELECT 1 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable11] UNION ALL SELECT 2 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable12]) AS [UnionAll9] UNION ALL SELECT 3 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable13]) AS [UnionAll10] UNION ALL SELECT 4 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable14]) AS [UnionAll11] UNION ALL SELECT 5 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable15]) AS [UnionAll12]) AS [GroupBy1] WHERE [Extent1].[ContactID] IN ([GroupBy1].[A1], (CASE WHEN ([Limit1].[C1] IS NULL) THEN 0 ELSE [Limit2].[C1] END)) Based on this, is it possible that Linq2Entities provider indeed doesn't execute non-Linq and Linq-to-Object methods, but instead creates equivalent SQL statements for some of them ( and for others it throws an exception )? Thank you in advance

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  • 3 column sticky footer

    - by blackessej
    html, body, #box { padding:0px; margin:0px; height:100%; min-height:100%; } body { background-image:url(images/footerbg.png); background-repeat:repeat-x repeat-y scroll; font-size:12px; font-family:Georgia; color:#564b47; } p, h1 { margin:0px 10px 10px 10px; } h1 { font-size:14px; padding-top:10px; text-transform:uppercase; color:#564b47; background-color:transparent; } a { color:#ff66cc; font-size:11px; background-color:transparent; text-decoration:none; } pre { color:#564b47; font-size:11px; background-color:transparent; } #box { position:relative; width:750px; margin:0 auto; text-align:left; height:auto!important; } #shadow { background:url("images/shadow.png") repeat-y scroll 0 0 transparent; width:760px; margin:auto; padding:0px; text-align:left; height:100%; z-index:0; margin-bottom:-40px; } #left { width:175px; float:left; background-color:#ff99cc; height:auto!important; height:100%; min-height:100%; text-align:left; } #content { width:400px; float:left; overflow:auto; background-color:#fff; height:auto!important; } #right { width:175px; float:right; background-color:#ff99cc; height:auto!important; height:100%; min-height:100%; text-align:right; } #head { background-image:url(images/banner.png); background-repeat:no-repeat; background-color:#000; height:125px; text-align:center; margin:auto; } #menu { width:100%; } p a { color:#000; text-decoration:underline; } a { color:#fb0303; text-decoration:none; outline:none; } a:visited { color:#fb0303; } p a:hover { text-decoration:underline!important; } ul#nav { margin:auto; width:100%; } ul#nav li a { display:block; font-size:12px; font-weight:bold; padding:4px; background:#000; } ul#nav li a:hover { background:#000; color:#fff; } li { list-style:none; top:100px; float:left; position:relative; width:110px; text-align:center; } li ul { display:none; position:relative; width:auto; margin-left:6px; border-top:4px dotted #fb0303; } li>ul { top:-102px; left:-40px; } li:hover ul, li.over ul { display:block; } ul#nav li.current a { background:#000; } ul#nav li.current a:hover { background:#000; } #player { width:360px; height:240px; position:absolute; z-index:2; } #head h1 { font-size:11px; text-transform:uppercase; text-align:right; color:#564b47; background-color:#90897a; padding:5px 15px; margin:0px; } #head p { padding:10px; margin:0px; } .footer { position:relative; height:40px; background-color:#444; } I want the three columns to be 100% height so that they go all the way to the footer. Right now, they're only as long as their content. The columns are #left, #right and #content. Pretty new to this stuff. Please feel free to point out sloppy code, redundancy, etc. And thank you.

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  • jQuery hover function

    - by Daniel Hertz
    So I have a hover function that is supposed to move an arrow under the corrent the link that someone hovers over. The problem is, the arrow never returns to the current link when the person stops hovering over the link. However, if I set the left properly with a constant value it works. Anyone have any ideas? var currentId = '#' + $('body').attr('id') + '_link'; var xCordCurrent = $(currentId).offset().left - ($('#arrow').width() / 2); var xCordHover = $(event.target).offset().left + ($(event.target).width() / 2) - ($('#arrow').width() / 2); $('#arrow').animate( { left: xCordHover }, { duration: 'slow', easing: 'easeOutBack' }) }, function(event) { $('#arrow').animate( { left: xCordCurrent }, { duration: 'slow', easing: 'easeOutBack' }) });

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  • 2 columns 100% height. Can the problem ever be solved in html markup???!!

    - by denja
    I'm in despair trying to draw this simple thing. Two columns stretching 100% vertically. Is this ever possible? here there are two tries <html> <head> <title>Columns</title> </head> <body> <style type="text/css"> .wrapper {font-size:900px; width:1200px; margin:0 auto; } .col1 { width:600px; height:100%; float:left; background:#f00; } .col2 { width:600px; height:100%; float:left; background:#00f; } </style> <div class="wrapper"> <div class="col1"> C o l u m n 1 </div> <div class="col2"> C ol u m n 2 </div> </div> </body> </html> and <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-GB"> <head> <title>2 Column CSS Demo - Equal Height Columns with Cross-Browser CSS</title> <style media="screen" type="text/css"> /* <!-- */ *{ margin:0; padding:0; } html { background-color: #ccc; height: 100%; } body { background-color: white; width: 600px; margin: 0 auto; height:100%; position: relative; border-left: 1px solid #888; border-right: 2px solid black; } #footer { clear:both; width:100%; height:0px;font-size:0px; } #container2 { clear:left; float:left; width:600px; overflow:hidden; background:#ffa7a7; } #container1 { float:left; width:600px; position:relative; right:200px; background:#fff689; } #col1 { float:left; width:400px; position:relative; left:200px; overflow:hidden; } #col2 { float:left; width:200px; position:relative; left:200px; overflow:hidden; } /* --> */ </style> </head> <body> <div id="container2"> <div id="container1"> <div id="col1"> aaaa a a a a a a a a a aa aa a a a a a a a a aa aa a a a a a a a a aa aa a a a a a a a aa a a a a aa aa a a a a a a a a aa aa a a a a a a a a aa aa a a a a aa a a a a aa aa a </div> <div id="col2"> fghdfghsfgddn fghdfghsfgddn fghdfghsfgddn fghdfghsfgddn fghdfghsfgddn fghdfghsfgddn fghdfghsfgddn v </div> </div> </div> <div id="footer"> &nbsp; </div> </body>

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  • How do I do JavaScript Array Animation

    - by Henry
    I'm making a game but don't know how to do Array Animation with the png Array and game Surface that I made below. I'm trying to make it so that when the Right arrow key is pressed, the character animates as if it is walking to the right and when the Left arrow key is pressed it animates as if it is walking to the left (kind of like Mario). I put everything on a surface instead of the canvas. Everything is explained in the code below. I couldn't find help on this anywhere. I hope what I got below makes sense. I'm basically a beginner with JavaScript. I'll be back if more is needed: <!doctype html5> <html> <head></head> <script src="graphics.js"></script> <script src="object.js"></script> <body onkeydown ="keyDown(event)" onkeyup ="keyUp(event)" ></body> <script> //"Surface" is where I want to display my animation. It's like the HTML // canvas but it's not that. It's just the surface to where everything in the //game and the game itself will be displayed. var Surface = new Graphics(600, 400, "skyblue"); //here's the array that I want to use for animation var player = new Array("StandsRight.png", "WalksRight.png", "StandsLeft.png","WalksLeft.png" ); //Here is the X coordinate, Y coordinate, the beginning png for the animation, //and the object's name "player." I also turned the array into an object (but //I don't know if I was supposed to do that or not). var player = new Object(50, 100, 40, 115, "StandsRight.png","player"); //When doing animation I know that it requires a "loop", but I don't // know how to connect it so that it works with the arrays so that //it could animate. var loop = 0; //this actually puts "player" on screen. It makes player visible and //it is where I would like the animation to occur. Surface.drawObject(player); //this would be the key that makes "player" animation in the righward direction function keyDown(e) { if (e.keyCode == 39); } //this would be the key that makes "player" animation in the leftward direction function keyUp(e){ if (e.keyCode == 39); } //this is the Mainloop where the game will function MainLoop(); //the mainloop functionized function MainLoop(){ //this is how fast or slow I could want the entire game to go setTimeout(MainLoop, 10); } </script> </html> From here, are the "graphic.js" and the "object.js" files below. In this section is the graphics.js file. This graphics.js part below is linked to the: script src="graphics.js" html script section that I wrote above. Basically, below is a seperate file that I used for Graphics, and to run the code above, make this graphics.js code that I post below here, a separate filed called: graphics.js function Graphics(w,h,c) { document.body.innerHTML += "<table style='position:absolute;font- size:0;top:0;left:0;border-spacing:0;border- width:0;width:"+w+";height:"+h+";background-color:"+c+";' border=1><tr><td> </table>\n"; this.drawRectangle = function(x,y,w,h,c,n) { document.body.innerHTML += "<div style='position:absolute;font-size:0;left:" + x + ";top:" + y + ";width:" + w + ";height:" + h + ";background-color:" + c + ";' id='" + n + "'></div>\n"; } this.drawTexture = function(x,y,w,h,t,n) { document.body.innerHTML += "<img style='position:absolute;font-size:0;left:" + x + ";top:" + y + ";width:" + w + ";height:" + h + ";' id='" + n + "' src='" + t + "'> </img>\n"; } this.drawObject = function(o) { document.body.innerHTML += "<img style='position:absolute;font-size:0;left:" + o.X + ";top:" + o.Y + ";width:" + o.Width + ";height:" + o.Height + ";' id='" + o.Name + "' src='" + o.Sprite + "'></img>\n"; } this.moveGraphic = function(x,y,n) { document.getElementById(n).style.left = x; document.getElementById(n).style.top = y; } this.removeGraphic = function(n){ document.getElementById(n).parentNode.removeChild(document.getElementById(n)); } } Finally, is the object.js file linked to the script src="object.js"" in the html game file above the graphics.js part I just wrote. Basically, this is a separate file too, so thus, in order to run or test the html game code in the very first section I wrote, a person has to also make this code below a separate file called: object.js I hope this helps: function Object(x,y,w,h,t,n) { this.X = x; this.Y = y; this.Velocity_X = 0; this.Velocity_Y = 0; this.Previous_X = 0; this.Previous_Y = 0; this.Width = w; this.Height = h; this.Sprite = t; this.Name = n; this.Exists = true; } In all, this game is made based on a tutorial on youtube at: http://www.youtube.com/watch?v=t2kUzgFM4lY&feature=relmfu I'm just trying to learn how to add animations with it now. I hope the above helps. If not, let me know. Thanks

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  • Finding the heaviest length-constrained path in a weighted Binary Tree

    - by Hristo
    UPDATE I worked out an algorithm that I think runs in O(n*k) running time. Below is the pseudo-code: routine heaviestKPath( T, k ) // create 2D matrix with n rows and k columns with each element = -8 // we make it size k+1 because the 0th column must be all 0s for a later // function to work properly and simplicity in our algorithm matrix = new array[ T.getVertexCount() ][ k + 1 ] (-8); // set all elements in the first column of this matrix = 0 matrix[ n ][ 0 ] = 0; // fill our matrix by traversing the tree traverseToFillMatrix( T.root, k ); // consider a path that would arc over a node globalMaxWeight = -8; findArcs( T.root, k ); return globalMaxWeight end routine // node = the current node; k = the path length; node.lc = node’s left child; // node.rc = node’s right child; node.idx = node’s index (row) in the matrix; // node.lc.wt/node.rc.wt = weight of the edge to left/right child; routine traverseToFillMatrix( node, k ) if (node == null) return; traverseToFillMatrix(node.lc, k ); // recurse left traverseToFillMatrix(node.rc, k ); // recurse right // in the case that a left/right child doesn’t exist, or both, // let’s assume the code is smart enough to handle these cases matrix[ node.idx ][ 1 ] = max( node.lc.wt, node.rc.wt ); for i = 2 to k { // max returns the heavier of the 2 paths matrix[node.idx][i] = max( matrix[node.lc.idx][i-1] + node.lc.wt, matrix[node.rc.idx][i-1] + node.rc.wt); } end routine // node = the current node, k = the path length routine findArcs( node, k ) if (node == null) return; nodeMax = matrix[node.idx][k]; longPath = path[node.idx][k]; i = 1; j = k-1; while ( i+j == k AND i < k ) { left = node.lc.wt + matrix[node.lc.idx][i-1]; right = node.rc.wt + matrix[node.rc.idx][j-1]; if ( left + right > nodeMax ) { nodeMax = left + right; } i++; j--; } // if this node’s max weight is larger than the global max weight, update if ( globalMaxWeight < nodeMax ) { globalMaxWeight = nodeMax; } findArcs( node.lc, k ); // recurse left findArcs( node.rc, k ); // recurse right end routine Let me know what you think. Feedback is welcome. I think have come up with two naive algorithms that find the heaviest length-constrained path in a weighted Binary Tree. Firstly, the description of the algorithm is as follows: given an n-vertex Binary Tree with weighted edges and some value k, find the heaviest path of length k. For both algorithms, I'll need a reference to all vertices so I'll just do a simple traversal of the Tree to have a reference to all vertices, with each vertex having a reference to its left, right, and parent nodes in the tree. Algorithm 1 For this algorithm, I'm basically planning on running DFS from each node in the Tree, with consideration to the fixed path length. In addition, since the path I'm looking for has the potential of going from left subtree to root to right subtree, I will have to consider 3 choices at each node. But this will result in a O(n*3^k) algorithm and I don't like that. Algorithm 2 I'm essentially thinking about using a modified version of Dijkstra's Algorithm in order to consider a fixed path length. Since I'm looking for heaviest and Dijkstra's Algorithm finds the lightest, I'm planning on negating all edge weights before starting the traversal. Actually... this doesn't make sense since I'd have to run Dijkstra's on each node and that doesn't seem very efficient much better than the above algorithm. So I guess my main questions are several. Firstly, do the algorithms I've described above solve the problem at hand? I'm not totally certain the Dijkstra's version will work as Dijkstra's is meant for positive edge values. Now, I am sure there exist more clever/efficient algorithms for this... what is a better algorithm? I've read about "Using spine decompositions to efficiently solve the length-constrained heaviest path problem for trees" but that is really complicated and I don't understand it at all. Are there other algorithms that tackle this problem, maybe not as efficiently as spine decomposition but easier to understand? Thanks.

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  • Android Bitmap : collision Detecting [on hold]

    - by user2505374
    I am writing an Android game right now and I would need some help in the collision of the wall on screen. When I drag the ball in the top and right it able to collide in wall but when I drag it faster it was able to overlap in the wall. public boolean onTouchEvent(MotionEvent event) { int x = (int) event.getX(); int y = (int) event.getY(); switch (event.getAction()) { // if the player moves case MotionEvent.ACTION_MOVE: { if (playerTouchRect.contains(x, y)) { boolean left = false; boolean right = false; boolean up = false; boolean down = false; boolean canMove = false; boolean foundFinish = false; if (x != pLastXPos) { if (x < pLastXPos) { left = true; } else { right = true; } pLastXPos = x; } if (y != pLastYPos) { if (y < pLastYPos) { up = true; } else { down = true; } pLastYPos = y; } plCellRect = getRectFromPos(x, y); newplRect.set(playerRect); newplRect.left = x - (int) (playerRect.width() / 2); newplRect.right = x + (int) (playerRect.width() / 2); newplRect.top = y - (int) (playerRect.height() / 2); newplRect.bottom = y + (int) (playerRect.height() / 2); int currentRow = 0; int currentCol = 0; currentRow = getRowFromYPos(newplRect.top); currentCol = getColFromXPos(newplRect.right); if(!canMove){ canMove = mapManager.getCurrentTile().pMaze[currentRow][currentCol] == Cell.wall; canMove =true; } finishTest = mapManager.getCurrentTile().pMaze[currentRow][currentCol]; foundA = finishTest == Cell.valueOf(letterNotGet + ""); canMove = mapManager.getCurrentTile().pMaze[currentRow][currentCol] != Cell.wall; canMove = (finishTest == Cell.floor || finishTest == Cell.pl) && canMove; if (canMove) { invalidate(); setTitle(); } if (foundA) { mapManager.getCurrentTile().pMaze[currentRow][currentCol] = Cell.floor; // finishTest letterGotten.add(letterNotGet); playCurrentLetter(); /*sounds.play(sExplosion, 1.0f, 1.0f, 0, 0, 1.5f);*/ foundS = letterNotGet == 's'; letterNotGet++; }if(foundS){ AlertDialog.Builder builder = new AlertDialog.Builder(mainActivity); builder.setTitle(mainActivity.getText(R.string.finished_title)); LayoutInflater inflater = mainActivity.getLayoutInflater(); View view = inflater.inflate(R.layout.finish, null); builder.setView(view); View closeButton =view.findViewById(R.id.closeGame); closeButton.setOnClickListener(new OnClickListener() { @Override public void onClick(View clicked) { if(clicked.getId() == R.id.closeGame) { mainActivity.finish(); } } }); AlertDialog finishDialog = builder.create(); finishDialog.show(); } else { Log.d(TAG, "INFO: updated player position"); playerRect.set(newplRect); setTouchZone(); updatePlayerCell(); } } // end of (CASE) if playerTouch break; } // end of (SWITCH) Case motion }//end of Switch return true; }//end of TouchEvent private void finish() { // TODO Auto-generated method stub } public int getColFromXPos(int xPos) { val = xPos / (pvWidth / mapManager.getCurrentTile().pCols); if (val == mapManager.getCurrentTile().pCols) { val = mapManager.getCurrentTile().pCols - 1; } return val; } /** * Given a y pixel position, return the row of the cell it is in This is * used when determining the type of adjacent Cells. * * @param yPos * y position in pixels * @return The cell this position is in */ public int getRowFromYPos(int yPos) { val = yPos / (pvHeight / mapManager.getCurrentTile().pRows); if (val == mapManager.getCurrentTile().pRows) { val = mapManager.getCurrentTile().pRows - 1; } return val; } /** * When preserving the position we need to know which cell the player is in, * so calculate it from the centre on its Rect */ public void updatePlayerCell() { plCell.x = (playerRect.left + (playerRect.width() / 2)) / (pvWidth / mapManager.getCurrentTile().pCols); plCell.y = (playerRect.top + (playerRect.height() / 2)) / (pvHeight / mapManager.getCurrentTile().pRows); if (mapManager.getCurrentTile().pMaze[plCell.y][plCell.x] == Cell.floor) { for (int row = 0; row < mapManager.getCurrentTile().pRows; row++) { for (int col = 0; col < mapManager.getCurrentTile().pCols; col++) { if (mapManager.getCurrentTile().pMaze[row][col] == Cell.pl) { mapManager.getCurrentTile().pMaze[row][col] = Cell.floor; break; } } } mapManager.getCurrentTile().pMaze[plCell.y][plCell.x] = Cell.pl; } } public Rect getRectFromPos(int x, int y) { calcCell.left = ((x / cellWidth) + 0) * cellWidth; calcCell.right = calcCell.left + cellWidth; calcCell.top = ((y / cellHeight) + 0) * cellHeight; calcCell.bottom = calcCell.top + cellHeight; Log.d(TAG, "Rect: " + calcCell + " Player: " + playerRect); return calcCell; } public void setPlayerRect(Rect newplRect) { playerRect.set(newplRect); } private void setTouchZone() { playerTouchRect.set( playerRect.left - playerRect.width() / TOUCH_ZONE, playerRect.top - playerRect.height() / TOUCH_ZONE, playerRect.right + playerRect.width() / TOUCH_ZONE, playerRect.bottom + playerRect.height() / TOUCH_ZONE); } public Rect getPlayerRect() { return playerRect; } public Point getPlayerCell() { return plCell; } public void setPlayerCell(Point cell) { plCell = cell; }

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  • How do I rotate my monitor using xorg?

    - by user1106405
    I have just installed KUbuntu 12.10, and I am attempting to rotate my monitor 90 deg to the left. When I add the option to rotate, the monitor seems to ignore the directive. I'm currently using dual 02:00.0 VGA compatible controller: NVIDIA Corporation GF104 [GeForce GTX 460] (rev a1) 03:00.0 VGA compatible controller: NVIDIA Corporation GF104 [GeForce GTX 460] (rev a1) and NVidia driver version 310 My xorg.conf is as follows: # nvidia-settings: X configuration file generated by nvidia-settings # nvidia-settings: version 304.51 (buildd@komainu) Fri Oct 12 12:53:49 UTC 2012 # nvidia-xconfig: X configuration file generated by nvidia-xconfig # nvidia-xconfig: version 310.14 ([email protected]) Tue Oct 9 13:04:01 PDT 2012 Section "ServerLayout" Identifier "Layout0" Screen 0 "Screen0" 1280 0 Screen 1 "Screen1" RightOf "Screen0" Screen 2 "Screen2" 0 0 InputDevice "Keyboard0" "CoreKeyboard" InputDevice "Mouse0" "CorePointer" Option "Xinerama" "1" EndSection Section "Files" EndSection Section "InputDevice" # generated from default Identifier "Mouse0" Driver "mouse" Option "Protocol" "auto" Option "Device" "/dev/psaux" Option "Emulate3Buttons" "no" Option "ZAxisMapping" "4 5" EndSection Section "InputDevice" # generated from default Identifier "Keyboard0" Driver "kbd" EndSection Section "Monitor" Identifier "Monitor0" VendorName "Unknown" ModelName "Samsung SyncMaster" HorizSync 30.0 - 81.0 VertRefresh 56.0 - 60.0 Option "DPMS" EndSection Section "Monitor" Identifier "Monitor1" VendorName "Unknown" ModelName "DELL 1908WFP" HorizSync 30.0 - 83.0 VertRefresh 56.0 - 75.0 EndSection Section "Monitor" Identifier "Monitor2" VendorName "Unknown" ModelName "DELL 1907FP" HorizSync 30.0 - 81.0 VertRefresh 56.0 - 76.0 EndSection Section "Device" Identifier "Device0" Driver "nvidia" VendorName "NVIDIA Corporation" BoardName "GeForce GTX 460" BusID "PCI:2:0:0" Screen 0 EndSection Section "Device" Identifier "Device1" Driver "nvidia" VendorName "NVIDIA Corporation" BoardName "GeForce GTX 460" BusID "PCI:2:0:0" Screen 1 EndSection Section "Device" Identifier "Device2" Driver "nvidia" VendorName "NVIDIA Corporation" BoardName "GeForce GTX 460" BusID "PCI:3:0:0" EndSection Section "Screen" # Removed Option "metamodes" "DFP-0: nvidia-auto-select +0+0; DFP-0: nvidia-auto-select +0+0; DFP-0: 1920x1200 +0+0; DFP-0: 1920x1200_60 +0+0; DFP-0: 1600x1200 +0+0; DFP-0: 1600x1200_60 +0+0; DFP-0: 1280x1024 +0+0; DFP-0: 1280x1024_60 +0+0; DFP-0: 1280x960 +0+0; DFP-0: 1280x960_60 +0+0; DFP-0: 1024x768 +0+0; DFP-0: 1024x768_60 +0+0; DFP-0: 800x600 +0+0; DFP-0: 800x600_60 +0+0; DFP-0: 800x600_56 +0+0; DFP-0: 640x480 +0+0; DFP-0: 640x480_60 +0+0; DFP-0: nvidia-auto-select @1920x1080 +0+0; DFP-0: nvidia-auto-select @1920x720 +0+0" Identifier "Screen0" Device "Device0" Monitor "Monitor0" DefaultDepth 24 Option "Stereo" "0" Option "metamodes" "DFP-0: nvidia-auto-select +0+0; DFP-0: nvidia-auto-select +0+0; DFP-0: 1920x1200 +0+0; DFP-0: 1920x1200_60 +0+0; DFP-0: 1600x1200 +0+0; DFP-0: 1600x1200_60 +0+0; DFP-0: 1280x1024 +0+0; DFP-0: 1280x1024_60 +0+0; DFP-0: 1280x960 +0+0; DFP-0: 1280x960_60 +0+0; DFP-0: 1024x768 +0+0; DFP-0: 1024x768_60 +0+0; DFP-0: 800x600 +0+0; DFP-0: 800x600_60 +0+0; DFP-0: 800x600_56 +0+0; DFP-0: 640x480 +0+0; DFP-0: 640x480_60 +0+0; DFP-0: nvidia-auto-select +0+0; DFP-0: nvidia-auto-select +0+0" SubSection "Display" Depth 24 EndSubSection EndSection Section "Screen" Identifier "Screen1" Device "Device1" Monitor "Monitor1" DefaultDepth 24 Option "Stereo" "0" Option "metamodes" "DFP-2: nvidia-auto-select +0+0" Option "Rotate" "left" SubSection "Display" Depth 24 EndSubSection EndSection Section "Screen" Identifier "Screen2" Device "Device2" Monitor "Monitor2" DefaultDepth 24 Option "Stereo" "0" Option "metamodes" "nvidia-auto-select +0+0" SubSection "Display" Depth 24 EndSubSection EndSection Section "Extensions" Option "Composite" "Enable" EndSection Edit: If I delete the xorg.conf and reboot, I am able to rotate my monitor, however, my third monitor is not recognized: Screen 0: minimum 8 x 8, current 3360 x 1200, maximum 16384 x 16384 DVI-I-0 disconnected (normal left inverted right x axis y axis) DVI-I-1 disconnected (normal left inverted right x axis y axis) DVI-I-2 connected 1920x1200+0+0 (normal left inverted right x axis y axis) 518mm x 324mm 1920x1200 60.0*+ 1600x1200 60.0 1280x1024 60.0 1280x960 60.0 1024x768 60.0 800x600 60.3 56.2 640x480 59.9 HDMI-0 disconnected (normal left inverted right x axis y axis) DVI-I-3 connected 1440x900+1920+0 (normal left inverted right x axis y axis) 408mm x 255mm 1440x900 59.9*+ 75.0 1280x1024 75.0 60.0 1280x800 59.8 1152x864 75.0 1024x768 75.0 70.1 60.0 800x600 75.0 72.2 60.3 56.2 640x480 75.0 72.8 59.9

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  • Trouble with AABB collision response and physics

    - by WCM
    I have been racking my brain trying to figure out a problem I am having with physics and basic AABB collision response. I am fairly close as the physics are mostly right. Gravity feels good and movement is solid. The issue I am running into is that when I land on the test block in my project, I can jump off of it most of the time. If I repeatedly jump in place, I will eventually get stuck one or two pixels below the surface of the test block. If I try to jump, I can become free of the other block, but it will happen again a few jumps later. I feel like I am missing something really obvious with this. I have two functions that support the detection and function to return a vector for the overlap of the two rectangle bounding boxes. I have a single update method that is processing the physics and collision for the entity. I feel like I am missing something very simple, like an ordering of the physics vs. collision response handling. Any thoughts or help can be appreciated. I apologize for the format of the code, tis prototype code mostly. The collision detection function: public static bool Collides(Rectangle source, Rectangle target) { if (source.Right < target.Left || source.Bottom < target.Top || source.Left > target.Right || source.Top > target.Bottom) { return false; } return true; } The overlap function: public static Vector2 GetMinimumTranslation(Rectangle source, Rectangle target) { Vector2 mtd = new Vector2(); Vector2 amin = source.Min(); Vector2 amax = source.Max(); Vector2 bmin = target.Min(); Vector2 bmax = target.Max(); float left = (bmin.X - amax.X); float right = (bmax.X - amin.X); float top = (bmin.Y - amax.Y); float bottom = (bmax.Y - amin.Y); if (left > 0 || right < 0) return Vector2.Zero; if (top > 0 || bottom < 0) return Vector2.Zero; if (Math.Abs(left) < right) mtd.X = left; else mtd.X = right; if (Math.Abs(top) < bottom) mtd.Y = top; else mtd.Y = bottom; // 0 the axis with the largest mtd value. if (Math.Abs(mtd.X) < Math.Abs(mtd.Y)) mtd.Y = 0; else mtd.X = 0; return mtd; } The update routine (gravity = 0.001f, jumpHeight = 0.35f, moveAmount = 0.15f): public void Update(GameTime gameTime) { Acceleration.Y = gravity; Position += new Vector2((float)(movement * moveAmount * gameTime.ElapsedGameTime.TotalMilliseconds), (float)(Velocity.Y * gameTime.ElapsedGameTime.TotalMilliseconds)); Velocity.Y += Acceleration.Y; Vector2 previousPosition = new Vector2((int)Position.X, (int)Position.Y); KeyboardState keyboard = Keyboard.GetState(); movement = 0; if (keyboard.IsKeyDown(Keys.Left)) { movement -= 1; } if (keyboard.IsKeyDown(Keys.Right)) { movement += 1; } if (Position.Y + 16 > GameClass.Instance.GraphicsDevice.Viewport.Height) { Velocity.Y = 0; Position = new Vector2(Position.X, GameClass.Instance.GraphicsDevice.Viewport.Height - 16); IsOnSurface = true; } if (Collision.Collides(BoundingBox, GameClass.Instance.block.BoundingBox)) { Vector2 mtd = Collision.GetMinimumTranslation(BoundingBox, GameClass.Instance.block.BoundingBox); Position += mtd; Velocity.Y = 0; IsOnSurface = true; } if (keyboard.IsKeyDown(Keys.Space) && !previousKeyboard.IsKeyDown(Keys.Space)) { if (IsOnSurface) { Velocity.Y = -jumpHeight; IsOnSurface = false; } } previousKeyboard = keyboard; } This is also a full download to the project. https://www.box.com/s/3rkdtbso3xgfgc2asawy P.S. I know that I could do this with the XNA Platformer Starter Kit algo, but it has some deep flaws that I am going to try to live without. I'd rather go the route of collision response via an overlay function. Thanks for any and all insight!

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  • How do implement a breadth first traversal?

    - by not looking for answer
    //This is what I have. I thought pre-order was the same and mixed it up with depth first! import java.util.LinkedList; import java.util.Queue; public class Exercise25_1 { public static void main(String[] args) { BinaryTree tree = new BinaryTree(new Integer[] {10, 5, 15, 12, 4, 8 }); System.out.print("\nInorder: "); tree.inorder(); System.out.print("\nPreorder: "); tree.preorder(); System.out.print("\nPostorder: "); tree.postorder(); //call the breadth method to test it System.out.print("\nBreadthFirst:"); tree.breadth(); } } class BinaryTree { private TreeNode root; /** Create a default binary tree */ public BinaryTree() { } /** Create a binary tree from an array of objects */ public BinaryTree(Object[] objects) { for (int i = 0; i < objects.length; i++) { insert(objects[i]); } } /** Search element o in this binary tree */ public boolean search(Object o) { return search(o, root); } public boolean search(Object o, TreeNode root) { if (root == null) { return false; } if (root.element.equals(o)) { return true; } else { return search(o, root.left) || search(o, root.right); } } /** Return the number of nodes in this binary tree */ public int size() { return size(root); } public int size(TreeNode root) { if (root == null) { return 0; } else { return 1 + size(root.left) + size(root.right); } } /** Return the depth of this binary tree. Depth is the * number of the nodes in the longest path of the tree */ public int depth() { return depth(root); } public int depth(TreeNode root) { if (root == null) { return 0; } else { return 1 + Math.max(depth(root.left), depth(root.right)); } } /** Insert element o into the binary tree * Return true if the element is inserted successfully */ public boolean insert(Object o) { if (root == null) { root = new TreeNode(o); // Create a new root } else { // Locate the parent node TreeNode parent = null; TreeNode current = root; while (current != null) { if (((Comparable)o).compareTo(current.element) < 0) { parent = current; current = current.left; } else if (((Comparable)o).compareTo(current.element) > 0) { parent = current; current = current.right; } else { return false; // Duplicate node not inserted } } // Create the new node and attach it to the parent node if (((Comparable)o).compareTo(parent.element) < 0) { parent.left = new TreeNode(o); } else { parent.right = new TreeNode(o); } } return true; // Element inserted } public void breadth() { breadth(root); } // Implement this method to produce a breadth first // search traversal public void breadth(TreeNode root){ if (root == null) return; System.out.print(root.element + " "); breadth(root.left); breadth(root.right); } /** Inorder traversal */ public void inorder() { inorder(root); } /** Inorder traversal from a subtree */ private void inorder(TreeNode root) { if (root == null) { return; } inorder(root.left); System.out.print(root.element + " "); inorder(root.right); } /** Postorder traversal */ public void postorder() { postorder(root); } /** Postorder traversal from a subtree */ private void postorder(TreeNode root) { if (root == null) { return; } postorder(root.left); postorder(root.right); System.out.print(root.element + " "); } /** Preorder traversal */ public void preorder() { preorder(root); } /** Preorder traversal from a subtree */ private void preorder(TreeNode root) { if (root == null) { return; } System.out.print(root.element + " "); preorder(root.left); preorder(root.right); } /** Inner class tree node */ private class TreeNode { Object element; TreeNode left; TreeNode right; public TreeNode(Object o) { element = o; } } }

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  • C# Custom Brush - I want two gradients chaining them together.

    - by Logan
    I am making a bar chart and I want two separate gradients for each bar. First I want a gradient to go from top to bottom solid red to transparent red. I want to paint over the top of that a gradient that goes from right to left, black to opaque. So - In the bottom left we should have; Bottom left - Alpha 0 Bottom right - Alpha 0 Top left - Alpha 255 Colour Red Top Right - Alpha 255 Colour Black So in effect I want to take a solid colour, add a left to right gradient to black then take the output of that and add a top to bottom gradient to transparency. All this and I want it to be in a single brush, is this even possible? Thanks!

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  • make tree in scheme

    - by ???
    (define (entry tree) (car tree)) (define (left-branch tree) (cadr tree)) (define (right-branch tree) (caddr tree)) (define (make-tree entry left right) (list entry left right)) (define (mktree order items_list) (cond ((= (length items_list) 1) (make-tree (car items_list) '() '())) (else (insert2 order (car items_list) (mktree order (cdr items_list)))))) (define (insert2 order x t) (cond ((null? t) (make-tree x '() '())) ((order x (entry t)) (make-tree (entry t) (insert2 order x (left-branch t)) (right-branch t))) ((order (entry t) x ) (make-tree (entry t) (left-branch t) (insert2 order x (right-branch t)))) (else t))) The result is: (mktree (lambda (x y) (< x y)) (list 7 3 5 1 9 11)) (11 (9 (1 () (5 (3 () ()) (7 () ()))) ()) ()) But I'm trying to get: (7 (3 (1 () ()) (5 () ())) (9 () (11 () ()))) Where is the problem?

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  • ModalPopupExtender doesn't work on IE6 frame layout

    - by Joe
    I'm using a "frame" layout similar to the one in this excellent answer: a div #top at the top of the page, a div#left on the left, and a div #main with the main content. The #top and #left divs contain navigation menus. Now I want to use a popup div using the AjaxControlToolkit ModalPopupExtender inside the content (#main) div. This works fine on IE8 (where #top, #left, #main all have position:fixed), but when I run it on IE6, the modal background only covers the #main div - I need it to cover the whole of the page including the #top and #left navigation divs. Looking at the script for ModalPopupExtender, it appears to be searching up the parent hierarchy until it finds a parent with position relative or absolute. And in the IE6 rendering, the #main div has position:absolute because position:fixed is not supported, which I guess explains what is happening. Any suggestions for the best/easiest way to get this working properly on IE6? Ideally without modifying the ModalPopupExtender code, but I'll do this if I have to and it's the best solution.

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  • Custom Brush - I want two gradients chaining them together.

    - by Logan
    I am making a bar chart and I want two separate gradients for each bar. First I want a gradient to go from top to bottom solid red to transparent red. I want to paint over the top of that a gradient that goes from right to left, black to opaque. So - In the bottom left we should have; Bottom left - Alpha 0 Bottom right - Alpha 0 Top left - Alpha 255 Colour Red Top Right - Alpha 255 Colour Black So in effect I want to take a solid colour, add a left to right gradient to black then take the output of that and add a top to bottom gradient to transparency. All this and I want it to be in a single brush, is this even possible?

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  • clear property is not working in ie 7

    - by Mayur
    Hi all, I m using a div in my web site by using float:left and float:right after that is used clear:both, its working fine in all browser except ie7 i have tried a lot of things please tell me a solution to resolve this problem.... css: .clear { clear : both; margin : 0px; } html: <div style="float:left">some text</div> <div style="float:left">some text</div> <div class="clear"></div> <div style="float:left">some text</div> <div style="float:left">some text</div> Thanks

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  • cant get jquery hover to work with .live()

    - by Haroldo
    the second function isnt working? $('.edit_hover').live('hover', function(e){ $(this).stop(); var half_width = ($(this).css('width').slice(0, -2))/2; var half_height = ($(this).css('height').slice(0, -2))*0.3; console.log(half_width); var top = ($(this).position().top) + half_height; var left = ($(this).position().left) + half_width; $('#edit_hover').css('top', top).css('left', left).fadeIn(300); //add overlay $(this).css('position', 'relative').append('<div class="edit_overlay" style="position: absolute; top:0px; left:0px; height:100%; width: 100%; background: #999; opacity: 0.5;"></div> ') }, function(){ $(this).stop(); $(this).find('.edit_overlay').remove(); $('#edit_hover').fadeOut(300); });

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  • jQuery selector - style values

    - by kender
    I got a series of divs like this: <div class="message" style="padding-left: 0px;">...</div> <div class="message" style="padding-left: 20px;">...</div> <div class="message" style="padding-left: 20px;">...</div> <div class="message" style="padding-left: 40px;">...</div> <div class="message" style="padding-left: 20px;">...</div> And I would like to make a selector that would get me the divs with padding greater then 20px. Would it be possible with just using jquery? Or I should modify my html tree and add some attribute that would distinguish those elemenents with high padding value?

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  • How to keep a floating div centered on window resize (jQuery/CSS)

    - by Jimbo
    Is there a way (without binding to the window.resize event) to force a floating DIV to re-center itself when the browser window is resized? To help explain, I imagine the pseudocode would look something like: div.left = 50% - (div.width / 2) div.top = 50% - (div.height / 2) UPDATE My query having been answered below, I wanted to post the final outcome of my quest - a jQuery extension method allowing you to center any block element - hope it helps someone else too. jQuery.fn.center = function() { var container = $(window); var top = -this.height() / 2; var left = -this.width() / 2; return this.css('position', 'absolute').css({ 'margin-left': left + 'px', 'margin-top': top + 'px', 'left': '50%', 'top': '50%' }); } Usage: $('#mydiv').center();

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  • jQuery: How to determine which <li> tag was clicked?

    - by user337909
    I am creating a form with 5 lines of text, and each text I am allowing the user to select if they want the text to be centered, left, or right justified. I have a unnumbered list with list elements x5. <li><img src="images/justify_left.png" alt="left" /><span>Justify Left</span></li> <li><img src="images/justify_center.png" alt="center" /><span>Justify Left</span></li> <li><img src="images/justify_right.png" alt="right" /><span>Justify Left</span></li> Each of the 5 set of <li> items refers to its respective line. With jQuery, how would I go about determining which of the 15 <li> items did the user select so that I can correspond the proper justification as a post method?

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  • How to create animated sliding windows/tabs menu?

    - by Forte
    I have created navigation menu in YUI 2.8 as below : I have also animated tabs using CSS transitions. CSS transitions are not widely supported by browsers and my animations are not working in Opera, IE etc. Since i'm already using YUI 2.8 on that page, can somebody tell me how do i animate those tabs? When i click on any tab, it should expand in vertical dimension smoothly (animated). Below are the properties of tabs which are going to change when i select any tab (Below properties of tabs should be animated) : Paddings Margins Background-Color Borders Please note in above image : There is little space left on right side in case #1 when 1st tab is selected. In case #2 and case #3 there is space left on left as well as right side. In case #4, there is some space left on left side when last tab is selected.

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  • getelementbyid does not work in firefox

    - by gaurab
    hi, this below mentioned code works perfect in internet explorer but not in firefox... i get an error in line in firefox: document.getElementById("supplier_no").value= values_array[0]; that getElementById returns null. how to solve the problem? var winName; //variable for the popup window var g_return_destination = null ; //variable to track where the data gets sent back to. // Set the value in the original pages text box. function f_set_home_value( as_Value ) { if (document.getElementById(g_return_destination[0]).name == "netbank_supplier_name_info" ) { //clear the old values for (selnum = 1; selnum <= 5; selnum++) { document.getElementById("expense_account"+selnum).value = ""; document.getElementById("expense_account_name"+selnum).value = ""; document.getElementById("expense_vat_flag"+selnum).value = "off"; document.getElementById("expense_vat_flag"+selnum).checked = ""; document.getElementById("expense_vat_amount"+selnum).value = ""; document.getElementById("expense_vat_code"+selnum).value = ""; document.getElementById("expense_period"+selnum).value = ""; document.getElementById("expense_date"+selnum).value = ""; if (selnum!=1) {//these are sometimes defaulted in, and in any case you will always have line1 document.getElementById("expense_more_dept"+selnum).value = ""; document.getElementById("expense_more_prj"+selnum).value = ""; document.getElementById("expense_more_subj"+selnum).value = ""; } document.getElementById("expense_amount"+selnum).value = ""; } var values_array = as_Value[0].split("!"); document.getElementById("supplier_no").value= values_array[0]; document.getElementById("supplier_bankAccount_no").value= values_array[1]; str = values_array[2] ; str = str.split(";sp;").join(" "); document.getElementById("default_expense_account").value= str; document.getElementById("expense_account1").value= str; document.getElementById("expense_more_sok1").disabled= false; str = values_array[3] ; str = str.split(";sp;").join(" "); document.getElementById("payment_term").value= str; strPeriod = calcPeriod(str,document.getElementById("due_date").value); document.getElementById("expense_period1").value = (strPeriod); strExpenseDate = calcExpenseDate(str,document.getElementById("due_date").value); document.getElementById("expense_date1").value = (strExpenseDate); str = values_array[4] ; str = str.split(";sp;").join(" "); document.getElementById("expense_account_name1").value= str; str = values_array[5] ; str = str.split(";sp;").join(" "); document.getElementById("expense_vat_code1").value= str; if (str == 0) { document.getElementById("expense_vat_flag1").checked= ''; document.getElementById("expense_vat_flag1").disabled= true; }else{ document.getElementById("expense_vat_flag1").checked= 'yes'; document.getElementById("expense_vat_flag1").value= 'on'; document.getElementById("expense_vat_flag1").disabled= false; } str = values_array[6] ; str = str.split(";sp;").join(" "); document.getElementById("supplier_name").value= str; var str = values_array[7]; str = str.split(";sp;").join(" "); str = str.split("&cr;").join("\r"); document.getElementById("netbank_supplier_name_info").value= str; strx = justNumberNF(document.getElementById("amount").value); document.all["expense_vat_amount1"].value = NetbankToDollarsAndCents(strx * (24/124)) ; document.getElementById("amount").value=NetbankToDollarsAndCents(strx); document.getElementById("expense_amount1").value = document.getElementById("amount").value; document.getElementById("expense_amount2").value = ''; document.getElementById("expense_account2").value= ''; //document.getElementById("expense_vat_flag2").value= ''; document.getElementById("expense_vat_amount2").value= ''; document.getElementById("expense_amount3").value = ''; document.getElementById("expense_account3").value= ''; //.getElementById("expense_vat_flag3").value= ''; document.getElementById("expense_vat_amount3").value= ''; document.getElementById("expense_amount4").value = ''; document.getElementById("expense_account4").value= ''; //document.getElementById("expense_vat_flag4").value= ''; document.getElementById("expense_vat_amount4").value= ''; document.getElementById("expense_amount5").value = ''; document.getElementById("expense_account5").value= ''; //document.getElementById("expense_vat_flag5").value= ''; document.getElementById("expense_vat_amount5").value= ''; str = values_array[8] ; str = str.split(";sp;").join(" "); if (str=="2"){ document.frmName.ButtonSelPeriodisering1.disabled=false; document.frmName.ButtonSelPeriodisering1.click(); } winName.close(); } } //Pass Data Back to original window function f_popup_return(as_Value) { var l_return = new Array(1); l_return[0] = as_Value; f_set_home_value(l_return); } function justNumberNF(val){ val = (val==null) ? 0 : val; // check if a number, otherwise try taking out non-number characters. if (isNaN(val)) { var newVal = parseFloat(val.replace(/[^\d\.\-]/g, '.')); // check if still not a number. Might be undefined, '', etc., so just replace with 0. return (isNaN(newVal) ? 0 : newVal); } // return 0 in place of infinite numbers. else if (!isFinite(val)) { return 0; } return val; }; function NetbankToDollarsAndCents(n) { var s = "" + Math.round(n * 100) / 100 ; var i = s.indexOf('.') ; if (i < 0) {return s + ",00" } ; var t = s.substring(0, i + 1) + s.substring(i + 1, i + 3) ; if (i + 2 == s.length) {t += "0"} ; return t.replace('.',',') ; }

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  • Handling inheritance with overriding efficiently

    - by Fyodor Soikin
    I have the following two data structures. First, a list of properties applied to object triples: Object1 Object2 Object3 Property Value O1 O2 O3 P1 "abc" O1 O2 O3 P2 "xyz" O1 O3 O4 P1 "123" O2 O4 O5 P1 "098" Second, an inheritance tree: O1 O2 O4 O3 O5 Or viewed as a relation: Object Parent O2 O1 O4 O2 O3 O1 O5 O3 O1 null The semantics of this being that O2 inherits properties from O1; O4 - from O2 and O1; O3 - from O1; and O5 - from O3 and O1, in that order of precedence. NOTE 1: I have an efficient way to select all children or all parents of a given object. This is currently implemented with left and right indexes, but hierarchyid could also work. This does not seem important right now. NOTE 2: I have tiggers in place that make sure that the "Object" column always contains all possible objects, even when they do not really have to be there (i.e. have no parent or children defined). This makes it possible to use inner joins rather than severely less effiecient outer joins. The objective is: Given a pair of (Property, Value), return all object triples that have that property with that value either defined explicitly or inherited from a parent. NOTE 1: An object triple (X,Y,Z) is considered a "parent" of triple (A,B,C) when it is true that either X = A or X is a parent of A, and the same is true for (Y,B) and (Z,C). NOTE 2: A property defined on a closer parent "overrides" the same property defined on a more distant parent. NOTE 3: When (A,B,C) has two parents - (X1,Y1,Z1) and (X2,Y2,Z2), then (X1,Y1,Z1) is considered a "closer" parent when: (a) X2 is a parent of X1, or (b) X2 = X1 and Y2 is a parent of Y1, or (c) X2 = X1 and Y2 = Y1 and Z2 is a parent of Z1 In other words, the "closeness" in ancestry for triples is defined based on the first components of the triples first, then on the second components, then on the third components. This rule establishes an unambigous partial order for triples in terms of ancestry. For example, given the pair of (P1, "abc"), the result set of triples will be: O1, O2, O3 -- Defined explicitly O1, O2, O5 -- Because O5 inherits from O3 O1, O4, O3 -- Because O4 inherits from O2 O1, O4, O5 -- Because O4 inherits from O2 and O5 inherits from O3 O2, O2, O3 -- Because O2 inherits from O1 O2, O2, O5 -- Because O2 inherits from O1 and O5 inherits from O3 O2, O4, O3 -- Because O2 inherits from O1 and O4 inherits from O2 O3, O2, O3 -- Because O3 inherits from O1 O3, O2, O5 -- Because O3 inherits from O1 and O5 inherits from O3 O3, O4, O3 -- Because O3 inherits from O1 and O4 inherits from O2 O3, O4, O5 -- Because O3 inherits from O1 and O4 inherits from O2 and O5 inherits from O3 O4, O2, O3 -- Because O4 inherits from O1 O4, O2, O5 -- Because O4 inherits from O1 and O5 inherits from O3 O4, O4, O3 -- Because O4 inherits from O1 and O4 inherits from O2 O5, O2, O3 -- Because O5 inherits from O1 O5, O2, O5 -- Because O5 inherits from O1 and O5 inherits from O3 O5, O4, O3 -- Because O5 inherits from O1 and O4 inherits from O2 O5, O4, O5 -- Because O5 inherits from O1 and O4 inherits from O2 and O5 inherits from O3 Note that the triple (O2, O4, O5) is absent from this list. This is because property P1 is defined explicitly for the triple (O2, O4, O5) and this prevents that triple from inheriting that property from (O1, O2, O3). Also note that the triple (O4, O4, O5) is also absent. This is because that triple inherits its value of P1="098" from (O2, O4, O5), because it is a closer parent than (O1, O2, O3). The straightforward way to do it is the following. First, for every triple that a property is defined on, select all possible child triples: select Children1.Id as O1, Children2.Id as O2, Children3.Id as O3, tp.Property, tp.Value from TriplesAndProperties tp -- Select corresponding objects of the triple inner join Objects as Objects1 on Objects1.Id = tp.O1 inner join Objects as Objects2 on Objects2.Id = tp.O2 inner join Objects as Objects3 on Objects3.Id = tp.O3 -- Then add all possible children of all those objects inner join Objects as Children1 on Objects1.Id [isparentof] Children1.Id inner join Objects as Children2 on Objects2.Id [isparentof] Children2.Id inner join Objects as Children3 on Objects3.Id [isparentof] Children3.Id But this is not the whole story: if some triple inherits the same property from several parents, this query will yield conflicting results. Therefore, second step is to select just one of those conflicting results: select * from ( select Children1.Id as O1, Children2.Id as O2, Children3.Id as O3, tp.Property, tp.Value, row_number() over( partition by Children1.Id, Children2.Id, Children3.Id, tp.Property order by Objects1.[depthInTheTree] descending, Objects2.[depthInTheTree] descending, Objects3.[depthInTheTree] descending ) as InheritancePriority from ... (see above) ) where InheritancePriority = 1 The window function row_number() over( ... ) does the following: for every unique combination of objects triple and property, it sorts all values by the ancestral distance from the triple to the parents that the value is inherited from, and then I only select the very first of the resulting list of values. A similar effect can be achieved with a GROUP BY and ORDER BY statements, but I just find the window function semantically cleaner (the execution plans they yield are identical). The point is, I need to select the closest of contributing ancestors, and for that I need to group and then sort within the group. And finally, now I can simply filter the result set by Property and Value. This scheme works. Very reliably and predictably. It has proven to be very powerful for the business task it implements. The only trouble is, it is awfuly slow. One might point out the join of seven tables might be slowing things down, but that is actually not the bottleneck. According to the actual execution plan I'm getting from the SQL Management Studio (as well as SQL Profiler), the bottleneck is the sorting. The problem is, in order to satisfy my window function, the server has to sort by Children1.Id, Children2.Id, Children3.Id, tp.Property, Parents1.[depthInTheTree] descending, Parents2.[depthInTheTree] descending, Parents3.[depthInTheTree] descending, and there can be no indexes it can use, because the values come from a cross join of several tables. EDIT: Per Michael Buen's suggestion (thank you, Michael), I have posted the whole puzzle to sqlfiddle here. One can see in the execution plan that the Sort operation accounts for 32% of the whole query, and that is going to grow with the number of total rows, because all the other operations use indexes. Usually in such cases I would use an indexed view, but not in this case, because indexed views cannot contain self-joins, of which there are six. The only way that I can think of so far is to create six copies of the Objects table and then use them for the joins, thus enabling an indexed view. Did the time come that I shall be reduced to that kind of hacks? The despair sets in.

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  • How can I change mouse keymapping

    - by zuberuber
    I have Razer DeathAdder(left handed edition) and A4Tech wireless mouse. My problem is I don't know how to change wireless mouse keymapping(swaping left/right click). Can somebody guide me how to do such thing? List of my devices: ? Virtual core pointer id=2 [master pointer (3)] ? ? Virtual core XTEST pointer id=4 [slave pointer (2)] ? ? Logitech Unifying Device. Wireless PID:4004 id=8 [slave pointer (2)] ? ? Razer Razer DeathAdder id=11 [slave pointer (2)] ? ? A4TECH USB Device id=12 [slave pointer (2)] ? ? A4TECH USB Device id=13 [slave pointer (2)] ? Virtual core keyboard id=3 [master keyboard (2)] ? Virtual core XTEST keyboard id=5 [slave keyboard (3)] ? Power Button id=6 [slave keyboard (3)] ? Power Button id=7 [slave keyboard (3)] ? Logitech USB Keyboard id=9 [slave keyboard (3)] ? Logitech USB Keyboard id=10 [slave keyboard (3)] This is my Razer xinput: Device 'Razer Razer DeathAdder': Device Enabled (121): 1 Coordinate Transformation Matrix (123): 1.000000, 0.000000, 0.000000, 0.000000, 1.000000, 0.000000, 0.000000, 0.000000, 1.000000 Device Accel Profile (246): 0 Device Accel Constant Deceleration (247): 5.000000 Device Accel Adaptive Deceleration (248): 1.000000 Device Accel Velocity Scaling (249): 10.000000 Device Product ID (240): 5426, 22 Device Node (241): "/dev/input/event4" Evdev Axis Inversion (250): 0, 0 Evdev Axes Swap (252): 0 Axis Labels (253): "Rel X" (131), "Rel Y" (132), "Rel Vert Wheel" (274) Button Labels (254): "Button Left" (124), "Button Middle" (125), "Button Right" (126), "Button Wheel Up" (127), "Button Wheel Down" (128), "Button Horiz Wheel Left" (129), "Button Horiz Wheel Right" (130), "Button Side" (269), "Button Extra" (270), "Button Forward" (271), "Button Back" (272), "Button Task" (273), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243) Evdev Middle Button Emulation (255): 0 Evdev Middle Button Timeout (256): 50 Evdev Third Button Emulation (257): 0 Evdev Third Button Emulation Timeout (258): 1000 Evdev Third Button Emulation Button (259): 3 Evdev Third Button Emulation Threshold (260): 20 Evdev Wheel Emulation (261): 0 Evdev Wheel Emulation Axes (262): 0, 0, 4, 5 Evdev Wheel Emulation Inertia (263): 10 Evdev Wheel Emulation Timeout (264): 200 Evdev Wheel Emulation Button (265): 4 Evdev Drag Lock Buttons (266): 0 And this is my wireless mouse xinput: Device 'A4TECH USB Device': Device Enabled (121): 1 Coordinate Transformation Matrix (123): 1.000000, 0.000000, 0.000000, 0.000000, 1.000000, 0.000000, 0.000000, 0.000000, 1.000000 Device Accel Profile (246): 0 Device Accel Constant Deceleration (247): 1.000000 Device Accel Adaptive Deceleration (248): 1.000000 Device Accel Velocity Scaling (249): 10.000000 Device Product ID (240): 2522, 1359 Device Node (241): "/dev/input/event16" Evdev Axis Inversion (250): 0, 0 Evdev Axes Swap (252): 0 Axis Labels (253): "Rel X" (131), "Rel Y" (132), "Rel Horiz Wheel" (245), "Rel Vert Wheel" (274) Button Labels (254): "Button Left" (124), "Button Middle" (125), "Button Right" (126), "Button Wheel Up" (127), "Button Wheel Down" (128), "Button Horiz Wheel Left" (129), "Button Horiz Wheel Right" (130), "Button Side" (269), "Button Extra" (270), "Button Forward" (271), "Button Back" (272), "Button Task" (273), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243) Evdev Middle Button Emulation (255): 0 Evdev Middle Button Timeout (256): 50 Evdev Third Button Emulation (257): 0 Evdev Third Button Emulation Timeout (258): 1000 Evdev Third Button Emulation Button (259): 3 Evdev Third Button Emulation Threshold (260): 20 Evdev Wheel Emulation (261): 0 Evdev Wheel Emulation Axes (262): 0, 0, 4, 5 Evdev Wheel Emulation Inertia (263): 10 Evdev Wheel Emulation Timeout (264): 200 Evdev Wheel Emulation Button (265): 4 Evdev Drag Lock Buttons (266): 0

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  • How do I fix my resolution after Directx install through Steam?

    - by Justin
    I'm a bit long-winded so see bottom for quick version and specs. Friendly Hello: Hello all on these askUbuntu pages, I just recently built my own computer and decided to switch to Ubuntu for the extra coolness. I've been learning a lot through all this, and mostly been trying to figure out issues on my own (read: Google searches). However, I couldn't seem to find others with this problem so I've come here for help. Detailed Recount: So I just used WINE and WINETRICKS to install Steam. All went well and it worked. Then I went to trying a game out. I remembered that Orcs Must Die! worked from http://www.steamgamesonlinux.com/ so I tried that out. After selecting to download it, that's when the problem occurred. The screen suddenly zoomed in!!! I think it's the resolution right? Half the screen is cut off and I can't see parts of the right side of windows. My theory is that this is due to Direct X being installed through Steam, as Steam automatically installed it as I chose to download the game. It didn't even ask me to install Direct X or not ): It all happened so fast. This all being said, the game works fine! It looks a little strange, as if the resolution was off, but it plays just fine. What I did so far: Restarted my computer. Didn't work -_- Researched Steam installing DirectX on Ubuntu then messing up resolution and couldn't really find anything. Researched uninstalling DirectX from Ubuntu but only found uninstalling DirectX after having been installed with Wine, not through Steam. Got mad and ate my feelings. Tried "xrandr -s 0" but it didn't do anything. Ran xrandr alone and terminal showed this: Screen 0: minimum 8 x 8, current 640 x 480, maximum 16384 x 16384 DVI-I-0 connected 640x480+0+0 (normal left inverted right x axis y axis) 0mm x 0mm 640x480 59.9*+ 320x240 120.1 DVI-I-1 disconnected (normal left inverted right x axis y axis) HDMI-0 disconnected (normal left inverted right x axis y axis) DP-0 disconnected (normal left inverted right x axis y axis) DVI-D-0 disconnected (normal left inverted right x axis y axis) DP-1 disconnected (normal left inverted right x axis y axis) About now I was mad so I played Odin's Sphere then took a nap. Back to it! I entered the following: xrandr --output DVI-I-0 --mode 1024x768 But I was met with this message: xrandr: cannot find mode 1024x768 I get the same messages for 800x600, 1400x1050, and seemingly any other combination of numbers. I then tried Going into System Settings then Displays, then playing around in there. My Resolution is set to 640x480 and there are no other options for me to choose from. Rotation has Normal, Clockwise, Counter Clockwise, and 180 Degrees. It's set to Normal and I haven't messed with that. Launcher Placement has Unknown and All Displays as its two options. It's set to Unknown, but moving it to All Displays doesn't seem to do anything. Finally, when I click Detect Displays, nothing seems to happen. Quick Version: Linux noob. Steam installed with Wine and Winetricks. Steam downloaded and installed game + DirectX. Resolution messed up now (I think; pretty sure), can't fix it, very annoying, no idea what's going on, halp! Specs: Ubuntu Version 12.04 Wine Version 1.4.1 Have not changed any settings in Wine Using Winetricks Graphics Card: http://www.gigabyte.com/products/pro...px?pid=4361#sp Drivers: Proprietary (Installing those were a LOT of fun) Also let it be known that I have a DVI to VGA cord running from my Graphics card to my monitor. If any more information is needed I am ready to report. Thank You: Thanks a lot for your help and all the work you do to support noob ubuntuers like me (:

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