Search Results

Search found 12992 results on 520 pages for 'password recovery'.

Page 92/520 | < Previous Page | 88 89 90 91 92 93 94 95 96 97 98 99  | Next Page >

  • Flask Admin didn't show all fields

    - by twoface88
    I have model like this: class User(db.Model): __tablename__ = 'users' __table_args__ = {'mysql_engine' : 'InnoDB', 'mysql_charset' : 'utf8'} id = db.Column(db.Integer, primary_key=True) username = db.Column(db.String(80), unique=True) email = db.Column(db.String(120), unique=True) _password = db.Column('password', db.String(80)) def __init__(self, username = None, email = None, password = None): self.username = username self.email = email self._set_password(password) def _set_password(self, password): self._password = generate_password_hash(password) def _get_password(self): return self._password def check_password(self, password): return check_password_hash(self._password, password) password = db.synonym("_password", descriptor=property(_get_password, _set_password)) def __repr__(self): return '<User %r>' % self.username I have ModelView: class UserAdmin(sqlamodel.ModelView): searchable_columns = ('username', 'email') excluded_list_columns = ['password'] list_columns = ('username', 'email') form_columns = ('username', 'email', 'password') But no matter what i do, flask admin didn't show password field when i'm editing user info. Is there any way ? Even just to edit hash code. UPDATE: https://github.com/mrjoes/flask-admin/issues/78

    Read the article

  • Section of website to be protected by a login

    - by shane
    I have a section of my website where I will have forms. I only want people who have registered with the site to be able to use these forms so that I only have serious customers using them. So what i want to have is a way that people can register on the site and once registered the area with the forms will be available to them and I will know who has sent me a form etc.

    Read the article

  • iPhone / ios development - best way to check if password is secure enough?

    - by Pranoy C
    what is the best way to check the strength of a password in iOS development? I came across this post: What is the best way to check the strength of a password? but this is not iOS specific. My question is - Does Apple or third party libraries provide any libraries by default which I can use to check if the user entered a secure password? If not, then as the above post says, is using regular expressions the best way? Does Apple have any requirements which our app needs to implement to make sure user has a secure password? I am planning on using the keychain to store the password.

    Read the article

  • Oracle Flashback Technologies - Overview

    - by Sridhar_R-Oracle
    Oracle Flashback Technologies - IntroductionIn his May 29th 2014 blog, my colleague Joe Meeks introduced Oracle Maximum Availability Architecture (MAA) and discussed both planned and unplanned outages. Let’s take a closer look at unplanned outages. These can be caused by physical failures (e.g., server, storage, network, file deletion, physical corruption, site failures) or by logical failures – cases where all components and files are physically available, but data is incorrect or corrupt. These logical failures are usually caused by human errors or application logic errors. This blog series focuses on these logical errors – what causes them and how to address and recover from them using Oracle Database Flashback. In this introductory blog post, I’ll provide an overview of the Oracle Database Flashback technologies and will discuss the features in detail in future blog posts. Let’s get started. We are all human beings (unless a machine is reading this), and making mistakes is a part of what we do…often what we do best!  We “fat finger”, we spill drinks on keyboards, unplug the wrong cables, etc.  In addition, many of us, in our lives as DBAs or developers, must have observed, caused, or corrected one or more of the following unpleasant events: Accidentally updated a table with wrong values !! Performed a batch update that went wrong - due to logical errors in the code !! Dropped a table !! How do DBAs typically recover from these types of errors? First, data needs to be restored and recovered to the point-in-time when the error occurred (incomplete or point-in-time recovery).  Moreover, depending on the type of fault, it’s possible that some services – or even the entire database – would have to be taken down during the recovery process.Apart from error conditions, there are other questions that need to be addressed as part of the investigation. For example, what did the data look like in the morning, prior to the error? What were the various changes to the row(s) between two timestamps? Who performed the transaction and how can it be reversed?  Oracle Database includes built-in Flashback technologies, with features that address these challenges and questions, and enable you to perform faster, easier, and convenient recovery from logical corruptions. HistoryFlashback Query, the first Flashback Technology, was introduced in Oracle 9i. It provides a simple, powerful and completely non-disruptive mechanism for data verification and recovery from logical errors, and enables users to view the state of data at a previous point in time.Flashback Technologies were further enhanced in Oracle 10g, to provide fast, easy recovery at the database, table, row, and even at a transaction level.Oracle Database 11g introduced an innovative method to manage and query long-term historical data with Flashback Data Archive. The 11g release also introduced Flashback Transaction, which provides an easy, one-step operation to back out a transaction. Oracle Database versions 11.2.0.2 and beyond further enhanced the performance of these features. Note that all the features listed here work without requiring any kind of restore operation.In addition, Flashback features are fully supported with the new multi-tenant capabilities introduced with Oracle Database 12c, Flashback Features Oracle Flashback Database enables point-in-time-recovery of the entire database without requiring a traditional restore and recovery operation. It rewinds the entire database to a specified point in time in the past by undoing all the changes that were made since that time.Oracle Flashback Table enables an entire table or a set of tables to be recovered to a point in time in the past.Oracle Flashback Drop enables accidentally dropped tables and all dependent objects to be restored.Oracle Flashback Query enables data to be viewed at a point-in-time in the past. This feature can be used to view and reconstruct data that was lost due to unintentional change(s) or deletion(s). This feature can also be used to build self-service error correction into applications, empowering end-users to undo and correct their errors.Oracle Flashback Version Query offers the ability to query the historical changes to data between two points in time or system change numbers (SCN) Oracle Flashback Transaction Query enables changes to be examined at the transaction level. This capability can be used to diagnose problems, perform analysis, audit transactions, and even revert the transaction by undoing SQLOracle Flashback Transaction is a procedure used to back-out a transaction and its dependent transactions.Flashback technologies eliminate the need for a traditional restore and recovery process to fix logical corruptions or make enquiries. Using these technologies, you can recover from the error in the same amount of time it took to generate the error. All the Flashback features can be accessed either via SQL command line (or) via Enterprise Manager.  Most of the Flashback technologies depend on the available UNDO to retrieve older data. The following table describes the various Flashback technologies: their purpose, dependencies and situations where each individual technology can be used.   Example Syntax Error investigation related:The purpose is to investigate what went wrong and what the values were at certain points in timeFlashback Queries  ( select .. as of SCN | Timestamp )   - Helps to see the value of a row/set of rows at a point in timeFlashback Version Queries  ( select .. versions between SCN | Timestamp and SCN | Timestamp)  - Helps determine how the value evolved between certain SCNs or between timestamps Flashback Transaction Queries (select .. XID=)   - Helps to understand how the transaction caused the changes.Error correction related:The purpose is to fix the error and correct the problems,Flashback Table  (flashback table .. to SCN | Timestamp)  - To rewind the table to a particular timestamp or SCN to reverse unwanted updates Flashback Drop (flashback table ..  to before drop )  - To undrop or undelete a table Flashback Database (flashback database to SCN  | Restore Point )  - This is the rewind button for Oracle databases. You can revert the entire database to a particular point in time. It is a fast way to perform a PITR (point-in-time recovery). Flashback Transaction (DBMS_FLASHBACK.TRANSACTION_BACKOUT(XID..))  - To reverse a transaction and its related transactions Advanced use cases Flashback technology is integrated into Oracle Recovery Manager (RMAN) and Oracle Data Guard. So, apart from the basic use cases mentioned above, the following use cases are addressed using Oracle Flashback. Block Media recovery by RMAN - to perform block level recovery Snapshot Standby - where the standby is temporarily converted to a read/write environment for testing, backup, or migration purposes Re-instate old primary in a Data Guard environment – this avoids the need to restore an old backup and perform a recovery to make it a new standby. Guaranteed Restore Points - to bring back the entire database to an older point-in-time in a guaranteed way. and so on..I hope this introductory overview helps you understand how Flashback features can be used to investigate and recover from logical errors.  As mentioned earlier, I will take a deeper-dive into to some of the critical Flashback features in my upcoming blogs and address common use cases.

    Read the article

  • Script launching 3 copies of rsync

    - by organicveggie
    I have a simple script that uses rsync to copy a Postgres database to a backup location for use with Point In Time Recovery. The script is run every 2 hours via a cron job for the postgres user. For some strange reason, I can see three copies of rsync running in the process list. Any ideas why this might the case? Here's the cron entry: # crontab -u postgres -l PATH=/bin:/usr/bin:/usr/local/bin 0 */2 * * * /var/lib/pgsql/9.0/pitr_backup.sh And here's the ps list, which shows two copies of rsync running and one sleeping: # ps ax |grep rsync 9102 ? R 2:06 rsync -avW /var/lib/pgsql/9.0/data/ /var/lib/pgsql/9.0/backups/pitr_archives/20110629100001/ --exclude pg_xlog --exclude recovery.conf --exclude recovery.done --exclude pg_log 9103 ? S 0:00 rsync -avW /var/lib/pgsql/9.0/data/ /var/lib/pgsql/9.0/backups/pitr_archives/20110629100001/ --exclude pg_xlog --exclude recovery.conf --exclude recovery.done --exclude pg_log 9104 ? R 2:51 rsync -avW /var/lib/pgsql/9.0/data/ /var/lib/pgsql/9.0/backups/pitr_archives/20110629100001/ --exclude pg_xlog --exclude recovery.conf --exclude recovery.done --exclude pg_log And here's the uber simple script that seems to be the cause of the problem: #!/bin/sh LOG="/var/log/pgsql-pitr-backup.log" base_backup_dir="/var/lib/pgsql/9.0/backups" wal_archive_dir="$base_backup_dir/wal_archives" pitr_archive_dir="$base_backup_dir/pitr_archives" timestamp=`date +%Y%m%d%H%M%S` backup_dir="$pitr_archive_dir/$timestamp" mkdir -p $backup_dir echo `date` >> $LOG /usr/bin/psql -U postgres -c "SELECT pg_start_backup('$backup_dir');" rsync -avW /var/lib/pgsql/9.0/data/ $backup_dir/ --exclude pg_xlog --exclude recovery.conf --exclude recovery.done --exclude pg_log /usr/bin/psql -U postgres -c "SELECT pg_stop_backup();"

    Read the article

  • SQL SERVER – Fix : Error : 3117 : The log or differential backup cannot be restored because no files

    - by pinaldave
    I received the following email from one of my readers. Dear Pinal, I am new to SQL Server and our regular DBA is on vacation. Our production database had some problem and I have just restored full database backup to production server. When I try to apply log back I am getting following error. I am sure, this is valid log backup file. Screenshot is attached. [Few other details regarding server/ip address removed] Msg 3117, Level 16, State 1, Line 1 The log or differential backup cannot be restored because no files are ready to roll forward. Msg 3013, Level 16, State 1, Line 1 RESTORE LOG is terminating abnormally. Screenshot attached. [Removed as it contained live IP address] Please help immediately. Well I have answered this question in my earlier post, 2 years ago, over here SQL SERVER – Fix : Error : Msg 3117, Level 16, State 4 The log or differential backup cannot be restored because no files are ready to rollforward. However, I will try to explain it a little more this time. For SQL Server database to be used it should in online state. There are multiple states of SQL Server Database. ONLINE (Available – online for data) OFFLINE RESTORING RECOVERING RECOVERY PENDING SUSPECT EMERGENCY (Limited Availability) If the database is online, it means it is active and in operational mode. It will not make sense to apply further log from backup if the operations have continued on this database. The common practice during the backup restore process is to specify the keyword RECOVERY when the database is restored. When RECOVERY keyword is specified, the SQL Server brings back the database online and will not accept any further log backups. However, if you want to restore more than one backup files, i.e. after restoring the full back up if you want to apply further differential or log backup you cannot do that when database is online and already active. You need to have your database in the state where it can further accept the backup data and not the online data request. If the SQL Server is online and also accepts database backup file, then there can be data inconsistency. This is the reason that when there are more than one database backup files to be restored, one has to restore the database with NO RECOVERY keyword in the RESTORE operation. I suggest you all to read one more post written by me earlier. In this post, I explained the time line with image and graphic SQL SERVER – Backup Timeline and Understanding of Database Restore Process in Full Recovery Model. Sample Code for reference: RESTORE DATABASE AdventureWorks FROM DISK = 'C:\AdventureWorksFull.bak' WITH NORECOVERY; RESTORE DATABASE AdventureWorks FROM DISK = 'C:\AdventureWorksDiff.bak' WITH RECOVERY; In this post, I am not trying to cover complete backup and recovery. I am just attempting to address one type of error and its resolution. Please test these scenarios on the development server. Playing with live database backup and recovery is always very crucial and needs to be properly planned. Leave a comment here if you need help with this subject. Similar Post: SQL SERVER – Restore Sequence and Understanding NORECOVERY and RECOVERY Note: We will cover Standby Server maintenance and Recovery in another blog post and it is intentionally, not covered this post. Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, Readers Question, SQL, SQL Authority, SQL Backup and Restore, SQL Error Messages, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

    Read the article

  • Windows xp recovery console without Ntfs.sys? (0x00000024 BSOD)

    - by Kalle
    I have two physical disks in a computer, for simlicity lets call them C and D. C: got Windows XP and D: got some data. The problem is that whenever i have D: connected i can't boot windows. I get some BSOD called 0x00000024/NTFS_FILE_SYSTEM. Same thing if i boot up windows with D: disconnected and then connect it once windows has loaded. The KB article about this problem says that i have to run chkdsk but i can't get to somewhere where i can run this because i get a BSOD whenever the disk is connected! Even the recovery-console BSODs if D: is connected. The final option in the KB is to boot the computer on Windows 2000 Setup disks where you edit some file to manually disable the ntfs.sys driver and then run chkdsk. The problem is that i don't have any floppy drive. Is there any way to boot the built in recovery console with ntfs.sys disabled or to burn the floppy version to a cd after you've extracted and modified it on the harddrive? Right now the Windows xp bootable floppy creator(2) is asking me which floppy drive to extract to which i can't answer because i have none :/ Other solutions to the root problem is also appreciated :) (2) ht tp://www.microsoft.com/downloads/details.aspx?FamilyID=55820edb-5039-4955-bcb7-4fed408ea73f&displaylang=en

    Read the article

  • How to restart boot Windows 7 after upgrading to a SSHD on SONY VAIO with recovery discs?

    - by Boris Okun
    The original HDD on my Sony VAIO still works, but has a damaged sector 0 and I was constantly prompted to replace the HDD because of the imminent failure. I created recovery discs as instructed, used a USB external HDD for complete back up (including Windows image back up). After installing the SSHD and using recovery discs to upload Windows and boot, I am getting the Windows welcome screen. Right after that, I'm getting the following message: Windows couldn't complete the installation. To install Windows on this computer, restart the installation. I have tried repeating the process many times all kinds of different ways and I still receive the same message. Also, when I tried to change to partitioning as the other option offered, I get the message: Windows Setup could not configure Windows to run on this computer's hardware. All troubleshooting for hardware and PCU came out solid. I tried to load the image back up from the external drive, but can't load the driver. The computer doesn't see it. Does anyone have a clue or has encountered something similar?

    Read the article

  • How can I tell System Restore in WIndows 7 recovery console to use my recovered backup drive's restore point data?

    - by Rich Shealer
    My Windows 7 desktop PC failed to boot. It would get to a grayish screen with a mouse and would only respond to the power button. After much examination I found that the problem was not a failed drive as running CHKDSK from the Recovery Console on my main drives passed without any errors. I had been installing various Java version in the days before the failure so I decided to use a restore point to roll backwards. I have an external SATA drive controller with two 2 TB drives mirrored using the Windows mirroring function. My system has been backing up to this drive regularly. The problem is I accidently broke the mirror when testing to see if this drive system might have been causing my boot issue. Connecting it to another machine showed two dynamic drives that were invalid. In the end I reformatted one as an NTFS basic disc and used recovery software on the other to copy all of the files to the reformatted drive. I had to copy the restore points into the new drive's System Volume Information folder by granting rights to that user. I moved the drive back to the original machine and rebooted. I can see my new drive, it even uses the same drive letter as it did in normal mode. Running System Restore it lists a new Automatic Restore point created while sitting at the RC along with all of my backups. Selecting the backup I want (or any other) I get a dialog. The backup drive could not be found. System Restore is looking for restore points on your backup. Make sure the backup drive is on and connected to this computer and then click OK. What do I need to do to allow system restore to see the restore points?

    Read the article

  • Am I going the right way to make login system secure with this simple password salting?

    - by LoVeSmItH
    I have two fields in login table password salt And I have this little function to generate salt function random_salt($h_algo="sha512"){ $salt1=uniqid(rand(),TRUE); $salt2=date("YmdHis").microtime(true); if(function_exists('dechex')){ $salt2=dechex($salt2); } $salt3=$_SERVER['REMOTE_ADDR']; $salt=$salt1.$salt2.$salt3; if(function_exists('hash')){ $hash=(in_array($h_algo,hash_algos()))?$h_algo:"sha512"; $randomsalt=hash($hash,md5($salt)); //returns 128 character long hash if sha512 algorithm is used. }else{ $randomsalt=sha1(md5($salt)); //returns 40 characters long hash } return $randomsalt; } Now to create user password I have following $userinput=$_POST["password"] //don't bother about escaping, i have done it in my real project. $static_salt="THIS-3434-95456-IS-RANDOM-27883478274-SALT"; //some static hard to predict secret salt. $salt=random_salt(); //generates 128 character long hash. $password =sha1($salt.$userinput.$static_salt); $salt is saved in salt field of database and $password is saved in password field. My problem, In function random_salt(), I m having this FEELING that I'm just making things complicated while this may not generate secure salt as it should. Can someone throw me a light whether I m going in a right direction? P.S. I do have an idea about crypt functions and like such. Just want to know is my code okay? Thanks.

    Read the article

  • Password security; Is this safe?

    - by Camran
    I asked a question yesterday about password safety... I am new at security... I am using a mysql db, and need to store users passwords there. I have been told in answers that hashing and THEN saving the HASHED value of the password is the correct way of doing this. So basically I want to verify with you guys this is correct now. It is a classifieds website, and for each classified the user puts, he has to enter a password so that he/she can remove the classified using that password later on (when product is sold for example). In a file called "put_ad.php" I use the $_POST method to fetch the pass from a form. Then I hash it and put it into a mysql table. Then whenever the users wants to delete the ad, I check the entered password by hashing it and comparing the hashed value of the entered passw against the hashed value in the mysql db, right? BUT, what if I as an admin want to delete a classified, is there a method to "Unhash" the password easily? sha1 is used currently btw. some code is very much appreciated. Thanks

    Read the article

  • Data Source Security Part 2

    - by Steve Felts
    In Part 1, I introduced the default security behavior and listed the various options available to change that behavior.  One of the key topics to understand is the difference between directly using database user and password values versus mapping from WLS user and password to the associated database values.   The direct use of database credentials is relatively new to WLS, based on customer feedback.  Some of the trade-offs are covered in this article. Credential Mapping vs. Database Credentials Each WLS data source has a credential map that is a mechanism used to map a key, in this case a WLS user, to security credentials (user and password).  By default, when a user and password are specified when getting a connection, they are treated as credentials for a WLS user, validated, and are converted to a database user and password using a credential map associated with the data source.  If a matching entry is not found in the credential map for the data source, then the user and password associated with the data source definition are used.  Because of this defaulting mechanism, you should be careful what permissions are granted to the default user.  Alternatively, you can define an invalid default user to ensure that no one can accidentally get through (in this case, you would need to set the initial capacity for the pool to zero so that the pool is populated only by valid users). To create an entry in the credential map: 1) First create a WLS user.  In the administration console, go to Security realms, select your realm (e.g., myrealm), select Users, and select New.  2) Second, create the mapping.  In the administration console, go to Services, select Data sources, select your data source name, select Security, select Credentials, and select New.  See http://docs.oracle.com/cd/E24329_01/apirefs.1211/e24401/taskhelp/jdbc/jdbc_datasources/ConfigureCredentialMappingForADataSource.html for more information. The advantages of using the credential mapping are that: 1) You don’t hard-code the database user/password into a program or need to prompt for it in addition to the WLS user/password and 2) It provides a layer of abstraction between WLS security and database settings such that many WLS identities can be mapped to a smaller set of DB identities, thereby only requiring middle-tier configuration updates when WLS users are added/removed. You can cut down the number of users that have access to a data source to reduce the user maintenance overhead.  For example, suppose that a servlet has the one pre-defined, special WLS user/password for data source access, hard-wired in its code in a getConnection(user, password) call.  Every WebLogic user can reap the specific DBMS access coded into the servlet, but none has to have general access to the data source.  For instance, there may be a ‘Sales’ DBMS which needs to be protected from unauthorized eyes, but it contains some day-to-day data that everyone needs. The Sales data source is configured with restricted access and a servlet is built that hard-wires the specific data source access credentials in its connection request.  It uses that connection to deliver only the generally needed day-to-day information to any caller. The servlet cannot reveal any other data, and no WebLogic user can get any other access to the data source.  This is the approach that many large applications take and is the reasoning behind the default mapping behavior in WLS. The disadvantages of using the credential map are that: 1) It is difficult to manage (create, update, delete) with a large number of users; it is possible to use WLST scripts or a custom JMX client utility to manage credential map entries. 2) You can’t share a credential map between data sources so they must be duplicated. Some applications prefer not to use the credential map.  Instead, the credentials passed to getConnection(user, password) should be treated as database credentials and used to authenticate with the database for the connection, avoiding going through the credential map.  This is enabled by setting the “use-database-credentials” to true.  See http://docs.oracle.com/cd/E24329_01/apirefs.1211/e24401/taskhelp/jdbc/jdbc_datasources/ConfigureOracleParameters.html "Configure Oracle parameters" in Oracle WebLogic Server Administration Console Help. Use Database Credentials is not currently supported for Multi Data Source configurations.  When enabled, it turns off credential mapping on Generic and Active GridLink data sources for the following attributes: 1. identity-based-connection-pooling-enabled (this interaction is available by patch in 10.3.6.0). 2. oracle-proxy-session (this interaction is first available in 10.3.6.0). 3. set client identifier (this interaction is available by patch in 10.3.6.0).  Note that in the data source schema, the set client identifier feature is poorly named “credential-mapping-enabled”.  The documentation and the console refer to it as Set Client Identifier. To review the behavior of credential mapping and using database credentials: - If using the credential map, there needs to be a mapping for each WLS user to database user for those users that will have access to the database; otherwise the default user for the data source will be used.  If you always specify a user/password when getting a connection, you only need credential map entries for those specific users. - If using database credentials without specifying a user/password, the default user and password in the data source descriptor are always used.  If you specify a user/password when getting a connection, that user will be used for the credentials.  WLS users are not involved at all in the data source connection process.

    Read the article

  • Ruby: backslash all non-alphanumeric characters in a string

    - by HBlend
    I have a script where I need to take a user's password and then run a command line using it. I need to backslash all (could be more then one) non-alphanumeric characters in the password. I have tried several things at this point including the below but getting no where. This has to be easy, just missing it. Tried these and several others: password = password.gsub(/(\W)/, '\\1') password = password.gsub(/(\W)/, '\\\1') password = password.gsub(/(\W)/, '\\\\1')

    Read the article

  • Why doesn't the highlighted part of the JavaScript work?

    - by Dor Cohen
    Why isn't the 'confirm password and password the same' part working? Meaning, the part that uses the 'getElementById' to adress the password and confirmpassword. Every part works but that particular part. It doesn't show a red box around the text fields. Can anyone help me? <html> <head> </head> <script> function submitinfo() { var firstname = document.getElementById("firstname").value; var lastname = document.getElementById("lastname").value; var username = document.getElementById("username").value; var password = document.getElementById("password").value; var confirmpassword = document.getElementById("confirmpassword").value; var email = document.getElementById("email").value; if(firstname !== "" && document.getElementById("firstname").style.borderColor == "red")     {     document.getElementById("firstname").style.border = "none"     } if(lastname !== "" && document.getElementById("lastname").style.borderColor == "red") { document.getElementById("lastname").style.border = "none" } if(username !== "" && document.getElementById("username").style.borderColor == "red") { document.getElementById("username").style.border = "none" } if(password !== "" && document.getElementById("password").style.borderColor == "red") { document.getElementById("password").style.border = "none" } if(confirmpassword !== "" && document.getElementById("confirmpassword").style.borderColor == "red") { document.getElementById("confirmpassword").style.border = "none" } if(email !== "" && document.getElementById("email").style.borderColor == "red") { document.getElementById("email").style.border = "none" } if(firstname == "") { document.getElementById("firstname").style.borderColor = "red"; document.getElementById("firstname").style.borderStyle = "solid"; } if(lastname == "") { document.getElementById("lastname").style.borderColor = "red"; document.getElementById("lastname").style.borderStyle = "solid"; } if(username == "") { document.getElementById("username").style.borderColor = "red"; document.getElementById("username").style.borderStyle = "solid"; } if(password == "") { document.getElementById("password").style.borderColor = "red"; document.getElementById("password").style.borderStyle = "solid"; } if(confirmpassword == "") { document.getElementById("confirmpassword").style.borderColor = "red"; document.getElementById("confirmpassword").style.borderStyle = "solid"; } if(email == "") { document.getElementById("email").style.borderColor = "red"; document.getElementById("email").style.borderStyle = "solid"; } if(password !== "" && confirmpassword !== "" && document.getElementById("password").style.border == "none" && document.getElementById("confirmpassword").style.border == "none" && password !== confirmpassword) { document.getElementById("password").style.border = "red"; document.getElementById("confirmpassword").style.border = "red"; } if(firstname && lastname && username && password && confirmpassword && email !== "") { window.open() } } </script> <h><font size=4 color=3BCCBE><b>Full Name</b></font><h/> <br> <input type="text" id="firstname" size="15px" placeholder="First"> <input type="text" id="lastname" size="15px" placeholder="Last"> <br> <br> <br> <br> <h><font size=4 color=3BCCBE><b>Choose your username</b></font></h> <br> <input type="text" id="username" size="37px"> <br> <p><font size=3 color="grey">atleast 6 characters long</font></p> <br> <h><font size=4 color=3BCCBE><b>Create a password</b></font></h> <br> <input type="password" id="password" size="37px"> <br> <br> <br> <br> <h><font size=4 color=3BCCBE><b>Confirm your password</b></font><h/> <br> <input type="password" id="confirmpassword" size="37px"> <br> <br> <br> <br> <h><font size=4 color=3BCCBE><b>Email address</b></font><h/> <br> <input type="text" id="email" size="37px"> <br> <br> <br> <br> <input type="button" value="Submit" onclick="submitinfo()" style="height:50px; width:85px; font-size:22px;> <br> </body> </html>

    Read the article

  • Indian government department have more unsecure website then others.

    - by Anirudha
    Originally posted on: http://geekswithblogs.net/anirugu/archive/2013/10/26/indian-government-department-have-more-unsecure-website-then-others.aspxOne of my friend share his college experience with me. He is not related with computer science. One day he told me that Ankia Fadia come to their college. In front of many student he show how to hack BSNL website by tricks. he break the flow how BSNL site work. I have told them BSNL is one of the most unsecure website of India   If you logged-in to website maybe it’s run in few seconds but sometime it run in 58 minute. OK this is not grammar mistake 58 minute is less then 1 hour. This means open a tab and put the link to open. it will open in hours. If you are using IE8, Chrome and Firefox you will be forced to use IE7 or downgrade. I simply use Ie7 mode in IE for make it work. This happen because they use something that is called DynaTrace. This site is most unsecure. now guess how !   Suppose my username is xyz and password is abc. How I can reset the password I simply go to website and in their site when I do reset my password he told me to fill password and password will not worked here.you can use here password here to reset my password. Remember that username are different then broadband username and password. Suppose if I want to reset your password I simply need to know your broadband username and I can reset it myself. I just logged in with my username and when I open the page for reset password I can fill your bb username and password will work here. I have not tried this. the broadband username can easily guess. this is depend on same way how people’s broandband username made. IS this Safe ? Nope, There are many thing on the site which make me feel that is 1900 century website. They still lived in popup life.  These site are nothing but a crap. not work most of time and when work it’s run too slowly.

    Read the article

  • Public EC Meeting Today at 15:00; new WebEx password

    - by Heather VanCura
    Update:  Public EC Meeting is today at 15:00 PST; note new WebEx meeting password is 12345; login from https://jcp.webex.com. Audio remains the same: +1 (866) 682-4770 (US) Conference code: 627-9803 Security code: 52732 ("JCPEC" on your phone handset) For global access numbers see http://www.intercall.com/oracle/access_numbers.htm Or +1 (408) 774-4073

    Read the article

  • How can I permanently save a password-protected SSH key?

    - by pl1nk
    I am using Awesome Window Manager How can I permanently add private keys with password? Inspired by the answer here I have added the private keys in ~/.ssh/config Contents of ~/.ssh/config: IdentityFile 'private key full path' Permissions of ~/.ssh/config: 0700 But it doesn't work for me. If I manually add the key in every session, it works but I'm looking for a more elegant way (not in .bashrc)

    Read the article

  • passwordless ssh not working

    - by kuurious
    I've tried to setup a password-less ssh b/w A to B and B to A as well. Generated the public and private key using ssh-keygen -trsa on both the machines. Used the ssh-copy-id utility to copy the public-keys from A to B as well as B to A. The passwordless ssh works from A to B but not from B to A. I've checked the permissions of the ~/ssh/ folder and seems to be normal. A's .ssh folder permissions: -rw------- 1 root root 13530 2011-07-26 23:00 known_hosts -rw------- 1 root root 403 2011-07-27 00:35 id_rsa.pub -rw------- 1 root root 1675 2011-07-27 00:35 id_rsa -rw------- 1 root root 799 2011-07-27 00:37 authorized_keys drwxrwx--- 70 root root 4096 2011-07-27 00:37 .. drwx------ 2 root root 4096 2011-07-27 00:38 . B's .ssh folder permissions: -rw------- 1 root root 884 2011-07-07 13:15 known_hosts -rw-r--r-- 1 root root 396 2011-07-27 00:15 id_rsa.pub -rw------- 1 root root 1675 2011-07-27 00:15 id_rsa -rw------- 1 root root 2545 2011-07-27 00:36 authorized_keys drwxr-xr-x 8 root root 4096 2011-07-06 19:44 .. drwx------ 2 root root 4096 2011-07-27 00:15 . A is an ubuntu 10.04 (OpenSSH_5.3p1 Debian-3ubuntu4, OpenSSL 0.9.8k 25 Mar 2009) B is a debian machine (OpenSSH_5.1p1 Debian-5, OpenSSL 0.9.8g 19 Oct 2007) From A: #ssh B works fine. From B: #ssh -vvv A ... ... debug1: SSH2_MSG_SERVICE_ACCEPT received debug2: key: /root/.ssh/identity ((nil)) debug2: key: /root/.ssh/id_rsa (0x7f1581f23a50) debug2: key: /root/.ssh/id_dsa ((nil)) debug3: Wrote 64 bytes for a total of 1127 debug1: Authentications that can continue: publickey,password debug3: start over, passed a different list publickey,password debug3: preferred gssapi-keyex,gssapi-with-mic,gssapi,publickey,keyboard-interactive,password debug3: authmethod_lookup publickey debug3: remaining preferred: keyboard-interactive,password debug3: authmethod_is_enabled publickey debug1: Next authentication method: publickey debug1: Trying private key: /root/.ssh/identity debug3: no such identity: /root/.ssh/identity debug1: Offering public key: /root/.ssh/id_rsa debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug3: Wrote 368 bytes for a total of 1495 debug1: Authentications that can continue: publickey,password debug1: Trying private key: /root/.ssh/id_dsa debug3: no such identity: /root/.ssh/id_dsa debug2: we did not send a packet, disable method debug3: authmethod_lookup password debug3: remaining preferred: ,password debug3: authmethod_is_enabled password debug1: Next authentication method: password [email protected]'s password: Which essentially means it's not authenticating using the file /root/id_rsa. I ran the ssh-add command in both the machines as well. The authentication part of /etc/ssh/sshd_config file is # Authentication: LoginGraceTime 120 PermitRootLogin yes StrictModes yes RSAAuthentication yes PubkeyAuthentication yes #AuthorizedKeysFile %h/.ssh/authorized_keys # Don't read the user's ~/.rhosts and ~/.shosts files I'm running out of ideas. Any help would be appreciated.

    Read the article

  • From the Tips Box: Xbox Output on Two Screens, High Tech Halloween Props, and Old Flash Drives as Password Reset Disks

    - by Jason Fitzpatrick
    Once a week we round up some great reader tips and share them with everyone, this week we’re looking at outputting your Xbox 360 to two screens, spooky high-tech Halloween props, and recycling old flash drives as password reset disks. HTG Explains: What is the Windows Page File and Should You Disable It? How To Get a Better Wireless Signal and Reduce Wireless Network Interference How To Troubleshoot Internet Connection Problems

    Read the article

  • Data recovery on Ubuntu 11.10?! (after crashing with Seagate 320GB)

    - by Sam
    Just installed 11.10 last week and decided to transfer iTunes music (from Windows dual boot) to my Seagate 320GB. I left it in, restarted, clicked Ubuntu at the boot screen, and then it froze after a few lines of code! I think I got to 3.7086 or something before I pressed CTRL+ALT+DEL and the system restarted after another few lines of code. I am completely new to Ubuntu so after Googling, I made a live CD with 10.04, the most stable release I've heard, and I'm typing this from there now. However, when I go to mount my partition, only the Windows Vista partition (308GB) is there! It has all my Windows files but my Ubuntu 11.10 ones are nowhere to be found. I need to restore these pictures I transferred from my camera using Shotwell the other day... any help is appreciated! p.s. 11.10 has never crashed on me in my trial week, so I'm guessing it's the Seagate hard drive's fault. However, now I'm running it on 10.04 and it works fine.

    Read the article

  • ssh Prompts For Password After Account Unlocked - Despite ssh key?

    - by user1011471
    Here's what happened: I set up ssh key so that user could ssh from A to B without a password. I got user's password wrong in some other context too many times, and user's account got locked out. (IT uses Active Directory here) IT unlocked the account. Concurrent to the unlocking, a script was running, calling something like ssh user@B some-health-check-command every 5 seconds or so -- which seemed to work fine before I caused user to get locked out in step 2. IT reports user reliably gets locked out a short time after each unlock attempt. I thought the ssh key would allow ssh user@B some-command as long as the account is not locked. But it behaves as if, when user gets unlocked, B suddenly asks for a password and since my command repeatedly runs without supplying a password, the account gets locked out after 5 attempts. Account cannot be accessed at this time. Please contact your system administrator. My questions are... Is that what's happening? Or: what's happening? More importantly: How can I reconfigure things such that my script doesn't cause problems? Can I accomplish what I want without having to install Expect? (I don't know if I have permission to do so) Other notes: Not using ssh-agent currently. The ssh command is running on our Jenkins master, a linux box. A and B are Mac OS X. user is managed in Active Directory and normally can sign into all three machines. Other than these things and the ssh key I set up, everything else has the default configuration as far as I know.

    Read the article

  • How to connect to DB2 when the password ends with '!' in Windows

    - by AngocA
    I am facing a problem to use the DB2 tools when using generic account with a generated password which ends with the Bang sign '!' to connect to DB2 database. I am not allowed to change the password because it is already used by other processes. I know the user is valid and I can connect to the database with its credentials, but not from all db2 tools. When using the Control Center it is okay. When using the Command Editor (GUI) or the Command Windows, I got this error message: connect to WAREHOUS user administrator using ! SQL0104N An unexpected token "!" was found following "<identifier>". Expected tokens may include: "NEW". SQLSTATE=42601 Let's say that my password is: pass@! I am trying to use c:\>db2 connect to sample user administrator using "pass@!" or c:\>db2 connect to sample user administrator using pass@! And it both cases I got the same error message. I could change the way I connect but it is not useful for me, for example: c:\>db2 connect to sample user administrator Enter current password for administrator: But I cannot use it from a batch file easily. I would like to know how can I connect from the Command Editor, in order to use this user from the Graphical Tools. BTW, I know that the Control Center is deprecated.

    Read the article

< Previous Page | 88 89 90 91 92 93 94 95 96 97 98 99  | Next Page >