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  • Script to reformat XML file

    - by JonS
    Hello all, I am trying to change an XML file from one format to another and have no clue as to how to write a script for it. Can someone help, please? The source file looks like this: <Record> <FieldValue fieldName="rapportage_nihil" fieldValue="false" fieldValueIsNull="false" fieldValueNatural="false"/> <FieldValue fieldName="periode" fieldValue="2009-23-31" fieldValueIsNull="false" fieldValueNatural="2009-10-31 00:23:23"/> <FieldValue fieldName="formulierid" fieldValue="9001HK1V10" fieldValueIsNull="false" fieldValueNatural="9001HK1V10"/> <FieldValue fieldName="versie" fieldValue="1" fieldValueIsNull="false" fieldValueNatural="1"/> <FieldValue fieldName="frequentie" fieldValue="M" fieldValueIsNull="false" fieldValueNatural="M"/> <FieldValue fieldName="variant_type" fieldValue="Landen" fieldValueIsNull="false" fieldValueNatural="Landen"/> <FieldValue fieldName="value" fieldValue="5F" fieldValueIsNull="false" fieldValueNatural="5F"/> <FieldValue fieldName="post_value" fieldValue="0.00" fieldValueIsNull="false" fieldValueNatural="1.037E-4"/> <FieldValue fieldName="cube" fieldValue="c01" fieldValueIsNull="false" fieldValueNatural="c01"/> <FieldValue fieldName="rij" fieldValue="r_24_100_1_000_0" fieldValueIsNull="false" fieldValueNatural="r_24_100_1_000_0"/> <FieldValue fieldName="kolom" fieldValue="c_2250_SPU" fieldValueIsNull="false" fieldValueNatural="c_2250_SPU"/> </Record> <Record> <FieldValue fieldName="rapportage_nihil" fieldValue="false" fieldValueIsNull="false" fieldValueNatural="false"/> <FieldValue fieldName="periode" fieldValue="2009-23-31" fieldValueIsNull="false" fieldValueNatural="2009-10-31 00:23:23"/> <FieldValue fieldName="formulierid" fieldValue="9001HK1V10" fieldValueIsNull="false" fieldValueNatural="9001HK1V10"/> <FieldValue fieldName="versie" fieldValue="1" fieldValueIsNull="false" fieldValueNatural="1"/> <FieldValue fieldName="frequentie" fieldValue="M" fieldValueIsNull="false" fieldValueNatural="M"/> <FieldValue fieldName="variant_type" fieldValue="Landen" fieldValueIsNull="false" fieldValueNatural="Landen"/> <FieldValue fieldName="value" fieldValue="5F" fieldValueIsNull="false" fieldValueNatural="5F"/> <FieldValue fieldName="post_value" fieldValue="0.00" fieldValueIsNull="false" fieldValueNatural="1.037E-4"/> <FieldValue fieldName="cube" fieldValue="c01" fieldValueIsNull="false" fieldValueNatural="c01"/> <FieldValue fieldName="rij" fieldValue="r_24_108_0_000_0" fieldValueIsNull="false" fieldValueNatural="r_24_108_0_000_0"/> <FieldValue fieldName="kolom" fieldValue="c_2250_SPU" fieldValueIsNull="false" fieldValueNatural="c_2250_SPU"/> </Record> <Record> <FieldValue fieldName="rapportage_nihil" fieldValue="false" fieldValueIsNull="false" fieldValueNatural="false"/> <FieldValue fieldName="periode" fieldValue="2009-23-31" fieldValueIsNull="false" fieldValueNatural="2009-10-31 00:23:23"/> <FieldValue fieldName="formulierid" fieldValue="9001HK1V10" fieldValueIsNull="false" fieldValueNatural="9001HK1V10"/> <FieldValue fieldName="versie" fieldValue="1" fieldValueIsNull="false" fieldValueNatural="1"/> <FieldValue fieldName="frequentie" fieldValue="M" fieldValueIsNull="false" fieldValueNatural="M"/> <FieldValue fieldName="variant_type" fieldValue="Landen" fieldValueIsNull="false" fieldValueNatural="Landen"/> <FieldValue fieldName="value" fieldValue="5F" fieldValueIsNull="false" fieldValueNatural="5F"/> <FieldValue fieldName="post_value" fieldValue="0.00" fieldValueIsNull="false" fieldValueNatural="1.6049E-4"/> <FieldValue fieldName="cube" fieldValue="c01" fieldValueIsNull="false" fieldValueNatural="c01"/> <FieldValue fieldName="rij" fieldValue="r_06_000_1_010_0" fieldValueIsNull="false" fieldValueNatural="r_06_000_1_010_0"/> <FieldValue fieldName="kolom" fieldValue="c_2250_SPU" fieldValueIsNull="false" fieldValueNatural="c_2250_SPU"/> </Record> This is the format that I need as a result: <bestand registratienummer="123"> <rapportage nihil="false" periode="2009-23-31" formulierid="9001HK1V10" versie="1" frequentie="M"> <variant type="Landen" value="5F" /> <post value="0.00" cube="c01" rij="r_24_100_1_000_0" kolom="c_2250_SPU" /> </rapportage> <rapportage nihil="false" periode="2009-23-31" formulierid="9001HK1V10" versie="1" frequentie="M"> <variant type="Landen" value="5F" /> <post value="0.00" cube="c01" rij="r_24_108_0_000_0" kolom="c_2250_SPU" /> </rapportage> <rapportage nihil="false" periode="2009-23-31" formulierid="9001HK1V10" versie="1" frequentie="M"> <variant type="Landen" value="5F" /> <post value="0.00" cube="c01" rij="r_06_000_1_010_0" kolom="c_2250_SPU" /> </rapportage> </bestand> Thanks very much!

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  • C# - Parse HTML source as XML

    - by fonix232
    I would like to read in a dynamic URL what contains a HTML file, and read it like an XML file, based on nodes (HTML tags). Is this somehow possible? I mean, there is this HTML code: <table class="bidders" cellpadding="0" cellspacing="0"> <tr class="bidRow4"> <td>kucik (automata)</td> <td class="right">9 374 Ft</td> <td class="bidders_date">2010-06-10 18:19:52</td> </tr> <tr class="bidRow4"> <td>macszaf (automata)</td> <td class="right">9 373 Ft</td> <td class="bidders_date">2010-06-10 18:19:52</td> </tr> <tr class="bidRow2"> <td>kucik (automata)</td> <td class="right">9 372 Ft</td> <td class="bidders_date">2010-06-10 18:19:42</td> </tr> <tr class="bidRow2"> <td>macszaf (automata)</td> <td class="right">9 371 Ft</td> <td class="bidders_date">2010-06-10 18:19:42</td> </tr> <tr class="bidRow0"> <td>kucik (automata)</td> <td class="right">9 370 Ft</td> <td class="bidders_date">2010-06-10 18:19:32</td> </tr> <tr class="bidRow0"> <td>macszaf (automata)</td> <td class="right">9 369 Ft</td> <td class="bidders_date">2010-06-10 18:19:32</td> </tr> <tr class="bidRow8"> <td>kucik (automata)</td> <td class="right">9 368 Ft</td> <td class="bidders_date">2010-06-10 18:19:22</td> </tr> <tr class="bidRow8"> <td>macszaf (automata)</td> <td class="right">9 367 Ft</td> <td class="bidders_date">2010-06-10 18:19:22</td> </tr> <tr class="bidRow6"> <td>kucik (automata)</td> <td class="right">9 366 Ft</td> <td class="bidders_date">2010-06-10 18:19:12</td> </tr> <tr class="bidRow6"> <td>macszaf (automata)</td> <td class="right">9 365 Ft</td> <td class="bidders_date">2010-06-10 18:19:12</td> </tr> </table> I want to parse this into a ListView (or a Grid) to create rows with the data contained. All tr are different row, and all td in a given td is a column in the given row. And also I want it to be as fast as possible, as it would update itself in 5 seconds. Is there any library for this?

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  • How to Generate XML from Database

    - by Nisarg Mehta
    Hi , I am fetching data from two tables CARRIER_IFTA ,IFTA_NAME. My Select Query is like below.. SELECT t1.IFTA_LICENSE_NUMBER,t1.IFTA_BASE_STATE,t2.NAME_TYPE,t2.NAME from CARRIER_IFTA t1 inner join IFTA_NAME t2 on t1.IFTA_LICENSE_NUMBER=t2.IFTA_LICENSE_NUMBER My Data is coming in this way... IFTA_LICENSE_NUMBER IFTA_BASE_STATE NAME_TYPE NAME -------------------------------------------------------- 630908333 US LG XYZ 630908333 US MG PQR 730908344 US LG ABC Now using XSLT I want to generate XML like this <T0019> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>630908333</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>XYZ</NAME> </IFTA_NAME> <IFTA_NAME> <NAME_TYPE>MG<NAME_TYPE> <NAME>PQR</NAME> <IFTA_NAME> </IFTA_ACCOUNT> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>730908344</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>ABC</NAME> </IFTA_NAME> </IFTA_ACCOUNT> </T0019> i have used below xslt but it is not giveng me desire result ... <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:template match="/ROWSET"> <xsl:element name="T0019"> <xsl:apply-templates select="IFTAACCOUNT"/> </xsl:element> </xsl:template> <xsl:template match="IFTAACCOUNT"> <xsl:element name="IFTAACCOUNT"> <xsl:apply-templates select="IFTA_CARRIER_ID_NUMBER"/> </xsl:element> </xsl:template> <xsl:template match="IFTA_LICENSE_NUMBER"> <xsl:element name="IFTA_LICENSE_NUMBER"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IFTA_BASE_STATE"> <xsl:element name="IFTA_BASE_STATE"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IRP_NAME"> <IRP_NAME> <xsl:apply-templates select="NAME"/> <xsl:apply-templates select="NAME_TYPE"/> </IRP_NAME> </xsl:template> <xsl:template match="NAME"> <xsl:element name="NAME"> <xsl:value-of select="." /> </xsl:element> </xsl:template> <xsl:template match="NAME_TYPE"> <xsl:element name="NAME_TYPE"> <xsl:apply-templates /> </xsl:element> </xsl:template> </xsl:stylesheet> but it is not giving desire result ... Please help me ... Thanks in Advance...

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  • XML and XSD - use element name as replacement of xsi:type for polymorphism

    - by disown
    Taking the W3C vehicle XSD as an example: <schema xmlns="http://www.w3.org/2001/XMLSchema" targetNamespace="http://cars.example.com/schema" xmlns:target="http://cars.example.com/schema"> <complexType name="Vehicle" abstract="true"/> <complexType name="Car"> <complexContent> <extension base="target:Vehicle"/> ... </complexContent> </complexType> <complexType name="Plane"> <complexContent> <extension base="target:Vehicle"/> <sequence> <element name="wingspan" type="integer"/> </sequence> </complexContent> </complexType> </schema> , and the following definition of 'meansOfTravel': <complexType name="MeansOfTravel"> <complexContent> <sequence> <element name="transport" type="target:Vehicle"/> </sequence> </complexContent> </complexType> <element name="meansOfTravel" type="target:MeansOfTravel"/> With this definition you need to specify the type of your instance using xsi:type, like this: <meansOfTravel> <transport xsi:type="Plane"> <wingspan>3</wingspan> </transport> </meansOfTravel> I would just like to acheive a 'name of type' - 'name of element' mapping so that this could be replaced with just <meansOfTravel> <plane> <wingspan>3</wingspan> </plane> </meansOfTravel> The only way I could do this until now is by making it explicit: <complexType name="MeansOfTravel"> <sequence> <choice> <element name="plane" type="target:Plane"/> <element name="car" type="target:Car"/> </choice> </sequence> </complexType> <element name="meansOfTravel" type="target:MeansOfTravel"/> But this means that I have to list all possible sub-types in the 'MeansOfTravel' complex type. Is there no way of making the XML parser assume that you mean a 'Plane' if you call the element 'plane'? Or do I have to make the choice explicit? I would just like to keep my design DRY - if you have any other suggestions (like groups or so) - i would love to hear them.

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  • Move from JSON to Protobuf. Is it worth it?

    - by katit
    We have REST webservices that can serve XML or JSON (WCF). I'm toying with idea of implementing Protobufs. Why? PROS Less load on servers. Smaller message size - less traffic. It is easier to switch now than later. CONS Need to be implemented Going to be harder to troubleshoot/sniff messages for debugging. I can enable GZip on server and JSON will consume as much traffic What is your suggestion and/or experience on this?

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  • Xpath question Xml Xpath

    - by Ibrar Afzal
    I need an xpath expression that would return the value of I need to get the value of this node. the value to extract is my xpath expression is //rates/rate[loantype='30-Year Fixed Rate'] The issue hre is that there are three value each node has a subtype element. Beside fileter for loantype I also need to filter for subtype. I am not sure how to do it in xpath. I have the following xml 40-Year Fixed Rate A 3 5.375 1.000 5.491 0 1 40-Year Fixed Rate B 5.500 0.500 5.579 0 1 40-Year Fixed Rate C 5.625 0.000 5.667 0 1 30-Year Fixed Rate A 3 5.000 1.000 5.134 0 1 30-Year Fixed Rate B 5.125 0.500 5.215 0 1 30-Year Fixed Rate C 5.250 0.000 5.297 0 1 20-Year Fixed Rate A 3 4.875 1.000 5.055 0 1 20-Year Fixed Rate B 5.000 0.500 5.121 0 1 20-Year Fixed Rate C 5.125 0.000 5.187 0 1 15-Year Fixed Rate A 3 4.250 1.000 4.467 0 1 15-Year Fixed Rate B 4.375 0.500 4.512 0 1 15-Year Fixed Rate C 4.500 0.000 4.570 0 1 10-Year Fixed Rate A 3 4.125 1.000 4.435 0 1 10-Year Fixed Rate B 4.250 0.500 4.454 0 1 10-Year Fixed Rate C 4.375 0.000 4.473 0 1 High-Balance 15-Year Fixed Rate D 3 4.250 1.000 4.461 0 1 High-Balance 15-Year Fixed Rate B 4.375 0.500 4.512 0 1 High-Balance 15-Year Fixed Rate C 4.500 0.000 4.563 0 1 High-Balance 30-Year Fixed Rate D 3 5.000 1.000 5.130 0 1 High-Balance 30-Year Fixed Rate B 5.125 0.500 5.211 0 1 High-Balance 30-Year Fixed Rate C 5.250 0.000 5.293 0 1 30-Year Fixed Rate Jumbo A 2 5.125 1.000 5.254 1 1 30-Year Fixed Rate Jumbo B 5.250 0.500 5.336 1 1 30-Year Fixed Rate Jumbo C 5.375 0.000 5.417 1 1 -- 15-Year Fixed Rate Jumbo A 2 5.000 1.000 5.220 1 1 15-Year Fixed Rate Jumbo B 5.125 0.500 5.270 1 1 15-Year Fixed Rate Jumbo C 5.250 0.000 5.320 1 1 -- 3/1 30-Year Adjustable Rate A 3 3.625 1.000 3.431 0 0 3/1 30-Year Adjustable Rate B 3.875 0.500 3.448 0 0 3/1 30-Year Adjustable Rate C 4.125 0.000 3.465 0 0 3/1 40-Year Adjustable Rate A 3 3.875 1.000 3.438 0 0 3/1 40-Year Adjustable Rate B 4.125 0.500 3.453 0 0 3/1 40-Year Adjustable Rate C 4.375 0.000 3.467 0 0 5/1 30-Year Adjustable Rate A 3 3.375 1.000 3.401 0 0 5/1 30-Year Adjustable Rate B 3.625 0.500 3.457 0 0 5/1 30-Year Adjustable Rate C 3.875 0.000 3.514 0 0 5/1 40-Year Adjustable Rate A 3 3.625 1.000 3.441 0 0 5/1 40-Year Adjustable Rate B 3.875 0.500 3.481 0 0 5/1 40-Year Adjustable Rate C 4.125 0.000 3.531 0 0 7/1 30-Year Adjustable Rate A 3 3.875 1.000 3.670 0 0 7/1 30-Year Adjustable Rate B 4.125 0.500 3.755 0 0 7/1 30-Year Adjustable Rate C 4.375 0.000 3.841 0 0 10/1 30-Year Adjustable Rate A 3 4.375 1.000 4.092 0 0 10/1 30-Year Adjustable Rate B 4.625 0.500 4.217 0 0 10/1 30-Year Adjustable Rate C 4.875 0.000 4.342 0 0 -- 2/2 ARM 30-Year (Purchase only) DH 5.250 0.000 3.709 0 0 -- High-Balance 5/1 30-Year Adjustable Rate D 3 3.375 1.000 3.366 0 0 High-Balance 5/1 30-Year Adjustable Rate B 3.625 0.500 3.404 0 0 High-Balance 5/1 30-Year Adjustable Rate C 3.875 0.000 3.454 0 0 High-Balance 7/1 30-Year Adjustable Rate D 3 3.875 1.000 3.670 0 0 High-Balance 7/1 30-Year Adjustable Rate B 4.125 0.500 3.755 0 0 High-Balance 7/1 30-Year Adjustable Rate C 4.375 0.000 3.841 0 0 3/1 30-Year Jumbo Adjustable Rate A 2 4.875 1.000 3.719 1 0 3/1 30-Year Jumbo Adjustable Rate B 5.000 0.500 3.708 1 0 3/1 30-Year Jumbo Adjustable Rate C 5.125 0.000 3.704 1 0 -- 3/1 40-Year Jumbo Adjustable Rate A 2 5.250 1.000 3.733 1 0 3/1 40-Year Jumbo Adjustable Rate B 5.375 0.500 3.727 1 0 3/1 40-Year Jumbo Adjustable Rate C 5.500 0.000 3.725 1 0 -- 5/1 30-Year Jumbo Adjustable Rate A 3 4.375 1.000 3.791 1 0 5/1 30-Year Jumbo Adjustable Rate B 4.500 0.500 3.803 1 0 5/1 30-Year Jumbo Adjustable Rate C 4.625 0.000 3.814 1 0 5/1 40-Year Jumbo Adjustable Rate A 2 5.000 1.000 3.922 1 0 5/1 40-Year Jumbo Adjustable Rate B 5.125 0.500 3.925 1 0 5/1 40-Year Jumbo Adjustable Rate C 5.250 0.000 3.936 1 0 -- 7/1 30-Year Jumbo Adjustable Rate A 3 4.950 1.000 4.261 1 0 7/1 30-Year Jumbo Adjustable Rate B 5.075 0.500 4.286 1 0 7/1 30-Year Jumbo Adjustable Rate C 5.200 0.000 4.311 1 0 2/2 ARM 30-Year Jumbo (Purchase only) DH 6.500 0.000 4.260 1 0 -- 30 Due in 7 Fixed Rate JUMBO Balloon A 6.375 1.000 6.613 1 0 30 Due in 7 Fixed Rate JUMBO Balloon B 6.500 0.500 6.625 1 0 40 due in 7 Fixed Rate offer1 5.250 0.000 5.374 0 0 1 40 Due in 7 Fixed Rate JUMBO Balloon offer2 6.500 0.000 6.625 1 0 1 Interest Only HELOC A To 80% LTV 3.250 0 1 Home Equity Loan - 7Yrs A Up to $100,000.00 Up to 75% LTV 6.000 6.000 0 2 Home Equity Loan - 7Yrs A $100,000.01 - $250,000.00 Up to 75% LTV 6.00 6.153 0 2 Home Equity Loan - 7Yrs A Up to $100,000.00 Up to 80% LTV 6.250 6.250 0 2 Home Equity Loan - 7Yrs A $100,000.01 - $250,000.00 Up to 80% LTV 6.25 6.403 0 2 Home Equity Loan - 7Yrs B $100,000.01 - $250,000.00 Up to 90% LTV 6.99 7.145 0 2 Home Equity Loan - 10,15Yrs C $5,000-$250,000.00 To 75% LTV 6.50 6.612 0 2 Home Equity Loan - 10,15Yrs C $5,000-$250,000.00 To 80% LTV 6.75 6.863 0 2 Home Equity Loan - 10,15Yrs D $5,000-$250,000.00 Up to 90% LTV 7.50 7.614 0 2 Home Equity Loan - 20Yrs E $5,000-$250,000.00 To 75% LTV 7.50 7.566 0 2 Home Equity Loan - 20Yrs E $5,000-$250,000.00 To 80% LTV 7.75 7.817 0 2 Home Equity Loan - 20Yrs F $5,000-$250,000.00 Up to 90% LTV 8.50 8.569 0 2 Equity Edge $5,000-$25,000.00 Up to 125% LTV 12.00 12.188 Current Index 0.350 Prime Index 3.250 03/26/2010

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  • Need help with a Linq XML conditional grouping query

    - by FiveTools
    I have the following xml fragment: <BANNER ID="Banner 2" ROW_WIDTH="200"> <BANNER_TEXTS ID="BANNER_TEXTS"> <BANNER_TEXT UNDERLINE="false" SPAN_COL="1" WIDTHT="78px"></BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="234px">Years In Practice</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="234px">Internet Usage</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="4" WIDTHT="312px">Sales Reps Seen / Week</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="234px">Prescription Volume</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="222px">Patient Load</BANNER_TEXT> </BANNER_TEXTS> <BANNER_TEXTS ID="COLUMN_TEXTS"> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Total</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">&#60; 11 years</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">11-20 years</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">21-30 years</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Light 1-5 hrs</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Medium 6-10 hrs</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Heavy &#62;10 hrs</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">0</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">1-2</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">3-5</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">&#62;5</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">1-100</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">101-150</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">&#62;150</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="74px">1-100</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="74px">101-200</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="74px">&#62;200</BANNER_TEXT> </BANNER_TEXTS> <BANNER_TEXTS ID="COLUMN_TEXTS"> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(A)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(B)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(C)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(D)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(E)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(F)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(G)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(H)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(I)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(J)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(K)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(L)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(M)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(N)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(O)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(P)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(Q)</COLUMN_TEXT> </BANNER_TEXTS> </BANNER> I would like to group all the 'BANNER_TEXT' in the second sequence using the first sequence 'BANNER_TEXT' as the key (only include elements where string is not null or empty). The span_col attribute in the first 'BANNER_TEXT' sequence indicates which elements by position in the 2nd sequence are related. An example: 'Years in Practice' would be the first key and the attribute SPAN_COL=3 for that element indicates it would contain '< 11 years', '11-20 years', '21-30 years' (the first grouping of string.empty = Total would be skipped).

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  • What does a well formed XML or Schema look like for InfoPath form creation?

    - by Keith Sirmons
    Howdy, Are there any resources out there that defines how a well formed XML or Schema may look like for InfoPath? When designing a new form, there is an option to base the new form off of an existing XML document or XML Schema as the data source. I am looking for any guidelines or rules that will help me make sure the structure of the XML file I use to create the form will work the best it could work. I am creating the XML structure for another project, but we want to make sure the XML that is created would be InfoPath friendly for possible future applications. Thank you, Keith

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  • Can I use XText for a DSL involving an XML file type?

    - by Chris
    I have defined a small DSL that is mostly written in the form of different types of XML files in conjuction with some property files. This works very well but I wish to create an Eclipse Editor to make editing these files easier for beginners (I already have a working parser). The main XML file can reference some items from the .properties files and vice-versa. THe main xml file can also reference other XML files. Certain options should only be available in the main xml file based on the contents of the .properties files and based on some osgi plugins that can be added to the DSL project (the syntax is dynamic depending on context). The structure of the language is fixed but the options available in each attribute or the choice of attributes themselves changes depending on metadata contained in plugin .jar files. Questions: Does XText support dynamic syntax (validation changes depending on external factors)? Does XText support XML files / .properties files? Thank you very much for your help in advance.

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  • Hierarchical Data in MySQL is as fast as XML to retrieve?

    - by ajsie
    i've got a list of all countries - states - cities (- subcities/villages etc) in a XML file and to retrieve for example a state's all cities it's really quick with XML (using xml parser). i wonder, if i put all this information in mysql, is retrieving a state's all cities as fast as with XML? cause XML is designed to store hierarchical data while relational databases like mysql are not. the list contains like 500 000 entities. so i wonder if its as fast as XML using either of: Adjacency list model Nested Set model And which one should i use? Cause (theoretically) there could be unlimited levels under a state (i heard that adjacency isn't good for unlimited child-levels). And which is fastest for this huge dataset? Thanks!

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  • How can I extract and save values from an XML file in Perl?

    - by Freddy
    Here is what I am trying to do in a Perl script: $data=""; sub loadXMLConfig() { $filename="somexml.xml" $data = $xml-XMLin($filename); } sub GetVariable() { ($FriendlyName) = @_; switch($FriendlyName) { case "My Friendly Name" {print $data-{my_xml_tag_name}} .... .... .... } } The problem is I am using Perl just because I am reading from an XML file, but I need to get these variables by a shell script. So, here is what I am using: $ perl -e 'require "scrpt.pl"; loadConfigFile(); GetVariable("My Variable")' This works exactly as expected, but I need to read the XML file every time I am getting a variable. Is there a way I could "preserve" $data across shell calls? The idea is that I read the XML file only once. If no, is there is a more simple way I could do this? These are the things I can't change: Config File is an XML Need the variables in a shell script

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  • How Do I Set XML Content-Type in Flex 3?

    - by Laxmidi
    Hi, I've got a Flex 3 project. Flex makes an ExternalCall to some Javascript. The Javascript is then turned into XML. But, my xml isn't parsing in IE. It works in all other browsers. I think that the problem is that I haven't set the XML's content-type and IE doesn't like that. So my code looks like: myReturn = '<myXMLReturn>' + myReturn + '</myXMLReturn>'; myReturn = '<?xml version="1.0" encoding="UTF-8"?>' + myReturn; xmlReturn = new XML(myReturn); How would I set: header('Content-type: application/xml'); in Actionscript? As I understand it IE requires that the Content-type be set. Is this correct? Thank you. -Laxmidi

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  • How to make a file with .pt extension, with xml syntax highlighting and vim's plugin snipmate load p

    - by Somebody still uses you MS-DOS
    I have the following in my .vimrc: au BufNewFile,BufRead *.pt set filetype=xml This is needed because although I'm editing a file with *.pt extension, it's indeed a valid xml file: setting the filetype like this I can have syntax highlighting. I'm using vim's snipmate plugin, and tried to create pt.snippets to specific needs since these files are Zope Page Templates (ZPT with TAL). Now, I have a problem: I don't want to create these snippets in xml.snippets, since they aren't really generic xml snippets, but my *.pt files are set to xml, so when I define my pt snippets they aren't loaded unless I run :set filetype=pt on my pt file on vim - but then I lose syntax highlighting. I would like to be able to have a pt file, with xml syntax highlighting, to be able to load a pt.snippets file from snipmate. How can I do it? (I would like to avoid putting my snippets in a generic snippet file, I would like it to be present only in pt.snippets to be easier to maintain.)

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  • Loading an XML file with todays date in the filename... need to fallback to old file if one with tod

    - by arala22
    So here is my question. Using javascript/jQuery I am currently loading in an XML file that has a file name such as carousel_large_2010-06-08.xml.. the way I am doing it is checked for todays date then grabbing a file that has that date in the filename... the issue is sometimes they wont be uploading a new file for a given day so it needs to fallback to a older date that exists.. Wondering how to do it? Here is my code: // set date for xml file var currentTime = new Date(), month = currentTime.getMonth() + 1, day = currentTime.getDate(), year = currentTime.getFullYear(); if(month.toString().length == 1){ month = '0'+month.toString(); } if(day.toString().length == 1){ day = '0'+day.toString(); } var dateObject = year+"-"+month+"-"+day; // start magic $jq.ajax({ type: "GET", url: "_xml/carousel/home/carousel_large_"+dateObject+".xml", dataType: "xml", success: HPCarousels.heroCarousel.parseXML, error: function(){ alert('Error Loading XML Content'); } });

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  • In SQL Server, can multiple inserts be replaced with a single insert that takes an XML parameter?

    - by Mayo
    So I have an existing ASP.NET solution that uses LINQ-to-SQL to insert data into SQL Server (5 tables, 110k records total). I had read in the past that XML could be passed as a parameter to SQL Server but my google searches turn up results that store the XML directly into a table. I would rather take that XML parameter and insert the nodes as records. Is this possible? How is it done (i.e. how is the XML parameter used to insert records in T-SQL, how should the XML be formatted)? Note: I'm researching other options like SQL bulk copy and I know that SSIS would be a good alternative. I want to know if this XML approach is feasible.

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  • Ten Problems with XQuery and the SQL/XML Standard

    XQuery and SQL/XML standard are processors for XML. SQL/XML was designed to try to match the capabilities of XQuery as closely as possible and XQuery was designed not only to support XML, but also to support relational processing. Read on to learn why this may have a negative influence on their capabilities.

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  • Why my browsers display XML files as blank pages?

    - by n1313
    Every time I open an XML file, all I get is blank page instead of tag tree. The file itself is correct and loads okay, I can see it via View Source or in the Firebug. I've tried turning off all my addons and tried running Firefox in safe mode, but the problem was not solved. I'm guessing that I've messed up my configuration somehow and Firefox now tries to render XML files as HTML ones. I've tried googling, but with no success. Help, please? UPD: example file: http://lj.lain.ru/3/1273657698603.sample.xml Also I've noticed that somehow all of the browsers on the machine are now acting the same, so I'm changing the question accordingly

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  • Why my browsers display XML files as blank pages?

    - by n1313
    Every time I open an XML file, all I get is blank page instead of tag tree. The file itself is correct and loads okay, I can see it via View Source or in the Firebug. I've tried turning off all my addons and tried running Firefox in safe mode, but the problem was not solved. I'm guessing that I've messed up my configuration somehow and Firefox now tries to render XML files as HTML ones. I've tried googling, but with no success. Help, please? UPD: example file: http://lj.lain.ru/3/1273657698603.sample.xml Also I've noticed that somehow all of the browsers on the machine are now acting the same, so I'm changing the question accordingly

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  • Saxon XSLT-Transformation: How to change serialization of an empty tag from <x/> to <x></x>?

    - by Ben
    Hello folks! I do some XSLT-Transformation using Saxon HE 9.2 with the output later being unmarshalled by Castor 1.3.1. The whole thing runs with Java at the JDK 6. My XSLT-Transformation looks like this: <xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ns="http://my/own/custom/namespace/for/the/target/document"> <xsl:output method="xml" encoding="UTF-8" indent="no" /> <xsl:template match="/"> <ns:item> <ns:property name="id"> <xsl:value-of select="/some/complicated/xpath" /> </ns:property> <!-- ... more ... --> </xsl:template> So the thing is: if the XPath-expression /some/complicated/xpath evaluates to an empty sequence, the Saxon serializer writes <ns:property/> instead of <ns:property></ns:property>. This, however, confuses the Castor unmarshaller, which is next in the pipeline and which unmarshals the output of the transformation to instances of XSD-generated Java-code. So my question is: How can I tell the Saxon-serializer to output empty tags not as standalone tags? Here is what I am proximately currently doing to execute the transformation: import net.sf.saxon.s9api.*; import javax.xml.transform.*; import javax.xml.transform.sax.SAXSource; // ... // read data XMLReader xmlReader = XMLReaderFactory.createXMLReader(); // ... there is some more setting up the xmlReader here ... InputStream xsltStream = new FileInputStream(xsltFile); InputStream inputStream = new FileInputStream(inputFile); Source xsltSource = new SAXSource(xmlReader, new InputSource(xsltStream)); Source inputSource = new SAXSource(xmlReader, new InputSource(inputStream)); XdmNode input = processor.newDocumentBuilder().build(inputSource); // initialize transformation configuration Processor processor = new Processor(false); XsltCompiler compiler = processor.newXsltCompiler(); compiler.setErrorListener(this); XsltExecutable executable = compiler.compile(xsltSource); Serializer serializer = new Serializer(); serializer.setOutputProperty(Serializer.Property.METHOD, "xml"); serializer.setOutputProperty(Serializer.Property.INDENT, "no"); serializer.setOutputStream(output); // execute transformation XsltTransformer transformer = executable.load(); transformer.setInitialContextNode(input); transformer.setErrorListener(this); transformer.setDestination(serializer); transformer.setSchemaValidationMode(ValidationMode.STRIP); transformer.transform(); I'd appreciate any hint pointing in the direction of a solution. :-) In case of any unclarity I'd be happy to give more details. Nightly greetings from Germany, Benjamin

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  • How to redirect sitemap.xml used depending on the domain?Undo edits

    - by Agustín Sabater
    How I can redirect sitemap.xml file access to different subfolders, if it can be reached from three different domains? domain1/sitemap.xml - dominio1/es/sitemap.xml domain2/sitemap.xml - dominio1/de/sitemap.xml domain3/sitemap.xml - dominio1/uk/sitemap.xml domain1, domain2, and domain3 target to the same folder. Is it possible? How can I do this? Should do it with PHP ? PS: The server is a linux running apache, the web platform is a wordpress.

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  • XSLT Transforming sequential XML to hierarchical XML

    - by Jean-Paul Smit
    I have a requirement to transform a sequential XML node list into a hierarchical, but I run into some XSLT specific knowledge gap. The input XML contains articles, colors and sizes. In the sample below 'Record1' is an article, 'Record2' represents a color and 'Record3' are the sizes. The number of colors and sizes (record2 and record3) elements can vary. <root> <Record1>...</Record1> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record1>...</Record1> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> </root> All fields are on the same hierarchical level, but still I have to create this structure as output: <root> <article> -> Record1 <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> </article> <article> -> Record1 <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> </article> </root> I've tried to iterate the nodes sequentially but for example the 'article' (=record1) node tag needs to remain unclosed while 'color' (=record2) nodes are processed. The same counts for processing 'size' (=record3) having 'color' unclosed, but that is not allowed by XSLT. My next idea was to call a template for every article, color and size level, but I don't know how to select for example all 'record3' nodes between the current 'record2' and the next article represented by 'record1'. I've also got a limitation on the XSLT version because I need this transformation in BizTalk Server which only supports XSLT 1.0 Can someone push me in the right direction?

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  • How do you traverse and store XML in Blackberry Java app?

    - by Greg
    I'm having a problem accessing the contents of an XML document. My goal is this: Take an XML source and parse it into a fair equivalent of an associative array, then store it as a persistable object. the xml is pretty simple: <root> <element> <category_id>1</category_id> <name>Cars</name> </element> <element> <category_id>2</category_id> <name>Boats</name> </element> </root> Basic java class below. I'm pretty much just calling save(xml) after http response above. Yes, the xml is properly formatted. import java.io.IOException; import java.util.Hashtable; import org.w3c.dom.Document; import org.w3c.dom.Node; import org.w3c.dom.NodeList; import java.util.Vector; import net.rim.device.api.system.PersistentObject; import net.rim.device.api.system.PersistentStore; import net.rim.device.api.xml.parsers.DocumentBuilder; import net.rim.device.api.xml.parsers.DocumentBuilderFactory; public class database{ private static PersistentObject storeVenue; static final long key = 0x2ba5f8081f7ef332L; public Hashtable hashtable; public Vector venue_list; String _node,_element; public database() { storeVenue = PersistentStore.getPersistentObject(key); } public void save(Document xml) { venue_list = new Vector(); storeVenue.setContents(venue_list); Hashtable categories = new Hashtable(); try{ DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory. newInstance(); DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder(); docBuilder.isValidating(); xml.getDocumentElement ().normalize (); NodeList list=xml.getElementsByTagName("*"); _node=new String(); _element = new String(); for (int i=0;i<list.getLength();i++){ Node value=list.item(i).getChildNodes().item(0); _node=list.item(i).getNodeName(); _element=value.getNodeValue(); categories.put(_element, _node); } } catch (Exception e){ System.out.println(e.toString()); } venue_list.addElement(categories); storeVenue.commit(); } The code above is the work in progress, and is most likely heavily flawed. However, I have been at this for days now. I can never seem to get all child nodes, or the name / value pair. When I print out the vector as a string, I usually end up with results like this: [{ = root, = element}] and that's it. No "category_id", no "name" Ideally, I would end up with something like [{1 = cars, 2 = boats}] Any help is appreciated. Thanks

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  • What is the recommended way of parsing an XML feed with multiple namespaces with ActionScript 3.0?

    - by dafko
    I have seen the following methods to be used in several online examples, but haven't found any documentation on the recommended way of parsing an XML feed. Method 1: protected function xmlResponseHandler(event:ResultEvent):void { var atom:Namespace = new Namespace("http://www.w3.org/2005/Atom"); var microsoftData:Namespace = new Namespace("http://schemas.microsoft.com/ado/2007/08/dataservices"); var microsoftMetadata:Namespace = new Namespace("http://schemas.microsoft.com/ado/2007/08/dataservices/metadata"); var ac:ArrayCollection = new ArrayCollection(); var keyValuePairs:KeyValuePair; var propertyList:XMLList = (event.result as XML)..atom::entry.atom::content.microsoftMetadata::properties; for each (var properties:XML in propertyList) { keyValuePairs = new KeyValuePair(properties.microsoftData::FieldLocation, properties.microsoftData::Locationid); ac.addItem(keyValuePairs); } cb.dataProvider = ac; } Method 2: protected function xmlResponseHandler(event:ResultEvent):void { namespace atom = "http://www.w3.org/2005/Atom"; namespace d = "http://schemas.microsoft.com/ado/2007/08/dataservices"; namespace m = "http://schemas.microsoft.com/ado/2007/08/dataservices/metadata"; use namespace d; use namespace m; use namespace atom; var ac:ArrayCollection = new ArrayCollection(); var keyValuePairs:KeyValuePair; var propertyList:XMLList = (event.result as XML)..entry.content.properties; for each (var properties:XML in propertyList) { keyValuePairs = new KeyValuePair(properties.FieldLocation, properties.Locationid); ac.addItem(keyValuePairs); } cb.dataProvider = ac; } Sample XML feed: <?xml version="1.0" encoding="iso-8859-1" standalone="yes"?> <feed xml:base="http://www.test.com/Test/my.svc/" xmlns:d="http://schemas.microsoft.com/ado/2007/08/dataservices" xmlns:m="http://schemas.microsoft.com/ado/2007/08/dataservices/metadata" xmlns="http://www.w3.org/2005/Atom"> <title type="text">Test_Locations</title> <id>http://www.test.com/test/my.svc/Test_Locations</id> <updated>2010-04-27T20:41:23Z</updated> <link rel="self" title="Test_Locations" href="Test_Locations" /> <entry> <id>1</id> <title type="text"></title> <updated>2010-04-27T20:41:23Z</updated> <author> <name /> </author> <link rel="edit" title="Test_Locations" href="http://www.test.com/id=1" /> <category term="MySQLModel.Test_Locations" scheme="http://schemas.microsoft.com/ado/2007/08/dataservices/scheme" /> <content type="application/xml"> <m:properties> <d:FieldLocation>Test Location</d:FieldLocation> <d:Locationid>test0129</d:Locationid> </m:properties> </content> </entry> <entry> <id>2</id> <title type="text"></title> <updated>2010-04-27T20:41:23Z</updated> <author> <name /> </author> <link rel="edit" title="Test_Locations" href="http://www.test.com/id=2" /> <category term="MySQLModel.Test_Locations" scheme="http://schemas.microsoft.com/ado/2007/08/dataservices/scheme" /> <content type="application/xml"> <m:properties> <d:FieldLocation>Yet Another Test Location</d:FieldLocation> <d:Locationid>test25</d:Locationid> </m:properties> </content> </entry> </feed>

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