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  • You do not have sufficient permissions to access this page.

    - by WmasterJ
    I recently set up a local copy of Wordpress, added some content and created a child theme. Then I moved it to my webserver, changed the config file, changed the "localhost" occurences in my SQL file to my online URL. I also changed my database prefix from what I had locally on all tables and in the config file. Everything works well on the outside. But then as I log-in is get the: You do not have sufficient permissions to access this page.

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  • Hoe to convert a JSON array of paths to images stored on a server into a javaScript array to display them? Using AJAX

    - by MichaelF
    I need for html file/ ajax code to take the JSON message and store the PATHS as a javaScript array. Then my buildImage function can display the first image in the array. I'm new to AJAX and believe my misunderstanding lies within the converting of the JSON to Javascript. I'm confused also about if my code creates a JSON array or object or either. I might need also to download a library to my app to understand JSON? Below is a PHP file loading the paths of the images. I believe json ecode is converting the PHP Array in a Json message. <?php include("mysqlconnect.php"); $select_query = "SELECT `ImagesPath` FROM `offerstbl` ORDER by `ImagesId` DESC"; $sql = mysql_query($select_query) or die(mysql_error()); $data = array(); while($row = mysql_fetch_array($sql,MYSQL_BOTH)){ $data[] = $row['ImagesPath']; } echo $images = json_encode($data); ?> Below is the script in is going to be loaded on an Cordova app. <!DOCTYPE html> <html> <head> <link rel="stylesheet" href="css/styles.css"> <link rel="stylesheet" href="css/cascading.css"> <script> function importJson(str) { // console.log(typeof xmlhttp.responseText); if (str=="") { document.getElementById("content").innerHTML=""; return; } if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else { // code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4) { //var images = JSON.parse(xmlhttp.responseText); document.getElementById("content").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","http://server/content.php"); xmlhttp.send(); } function buildImage(src) { var img = document.createElement('img') img.src = src alert("1"); document.getElementById('content').appendChild(img); } for (var i = 0; i < images.length; i++) { buildImage(images[i]); } </script> </head> <body onload= "importJson();"> <div class="contents" id="content" ></div> <img src="img/logo.png" height="10px" width="10px" onload= "buildImage();"> </body>

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  • How to access Excel Max Column value?

    - by Phsika
    i try to create table from excel rows. however; excel columns : column1 has max 200 character row column2 has max 300 character row column3 has max 500 character row So i need to create sql create MyTable column3 nvarchar(500) according to Excel Max Character.

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  • Parse error in PHP login form

    - by user225269
    I'm trying to have a login form in php. But my current code doesnt work. Here is the form: <form name="form1" method="post" action="loginverify.php"> <td><font size="3">Username:</td> <td></td> <td><input type="text" name="uname" value="" maxlength="15"/><br/></td> <td><font size="3">Password:</td> <td></td> <td><input type="text" name="pword" value="" maxlength="15"/><br/></td> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login" /></td> </form> And the verify.php <?php session_start(); ?> <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="login"; $tbl="users"; $connection=mysql_connect($host, $username, $password) or die("cannot connect"); mysql_select_db($db_name, $connection) or die("cannot select db"); $user=$_POST['uname'] $pass=$_POST['pword'] $sql="SELECT Username, Password from users where Username='$user' and Password='$pass'"; $result=mysql_query[$sql]; $count=mysql_num_rows($result); if($count==1){ $SESSION['Username']=$user; echo"<a href='searchmain.php'> CONTINUE</a>"; } else{ echo"wrong username or password"; echo"<a href='loginform.php'>Back</a>"; } ?> Is there something wrong with my code. I get this parse error at line 15, which is this: $pass=$_POST['pword'] But when I try to remove it.It goes to line 16 or line 17 again. What do I do

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  • Problem using generics in function

    - by JAVA
    Hi all, I have this functions and need to make it one function. The only difference is type of input variable sourceColumnValue. This variable can be String or Integer but the return value of function must be always Integer. I know I need to use Generics but can't do it. public Integer selectReturnInt(String tableName, String sourceColumnName, String sourceColumnValue, String targetColumnName) { Integer returned = null; String query = "SELECT "+targetColumnName+" FROM "+tableName+" WHERE "+sourceColumnName+"='"+sourceColumnValue+"' LIMIT 1"; try { Connection connection = ConnectionManager.getInstance().open(); java.sql.Statement statement = connection.createStatement(); statement.execute(query.toString()); ResultSet rs = statement.getResultSet(); while(rs.next()){ returned = rs.getInt(targetColumnName); } rs.close(); statement.close(); ConnectionManager.getInstance().close(connection); } catch (SQLException e) { System.out.println("???????? ?? ???? ?? ???? ?????????!"); System.out.println(e); } return returned; } // SELECT (RETURN INTEGER) public Integer selectIntReturnInt(String tableName, String sourceColumnName, Integer sourceColumnValue, String targetColumnName) { Integer returned = null; String query = "SELECT "+targetColumnName+" FROM "+tableName+" WHERE "+sourceColumnName+"='"+sourceColumnValue+"' LIMIT 1"; try { Connection connection = ConnectionManager.getInstance().open(); java.sql.Statement statement = connection.createStatement(); statement.execute(query.toString()); ResultSet rs = statement.getResultSet(); while(rs.next()){ returned = rs.getInt(targetColumnName); } rs.close(); statement.close(); ConnectionManager.getInstance().close(connection); } catch (SQLException e) { System.out.println("???????? ?? ???? ?? ???? ?????????!"); System.out.println(e); } return returned; }

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  • dotnet nuke mysql

    - by user311166
    windows server 2003. i have an existing dotnetnuke website. ms sql is currently running and being used by dotnetnuke. i want to use mysql for other purposes. would installing mysql on the same server interfere with dotnetnuke? it seems that shortly after installing dotnetnuke our website stopped populating pages.

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  • NHibernate and MySql Keywords

    - by jalchr
    Why Nibernate HQL can not handle the following query: from Deal D where (D.ApprovalDate + INTERVAL 1 Year) < current_timestamp() < (D.RenewalDate + INTERVAL -1 Year) knowing that INTERVAL and YEAR are keywords in MySQL, so this is kind of mixing Sql within Hql (unless Hql can handle date functions like so and I don't know) . The dialect is MySQLDialect Its perfectly valid to execute this query SELECT '2005-01-01' + INTERVAL 1 Year;

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  • need some tips about distributed c# desktop application

    - by amipax
    Hi , my doubt is the following, I have a network with 5 pcs, each machine has XP installed, I don't know much about distributed desktop applications, so what i want is to create a C# application using sql server 2005 database and visual studio 2008. I want that each pc can have access to create/update/delete data on the one XP machine that will store the database files. Do i need WServer2003 or any special network technology?? thanks in advance

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  • .NET platform web hosting

    - by netmajor
    What should I do to host on my own machine a .NET web application(ASP.NET, Silverlight) with support Sql Server and services(RIA, WCF)? What should I install and configure so others can interact with my application via the internet ? It's some administration API which I can install on a PC and by which I can upload my app like in professional hosting? Thanks for the help!

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  • @Resource annotation is null at run-time.

    - by Andrew
    I'm using GlassFish v3. The following field is declared in a class: @Resource private javax.sql.DataSource _data_source; The following is declare in web.xml: <data-source <namejava:app/env/data</name <class-namecom.mysql.jdbc.Driver</class-name <server-namelocalhost</server-name <port-number3306</port-number <usermyUser</user <passwordmyPass</password </data-source At run-time _data_source is empty. What am I doing wrong?

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  • Increment my id in my insert request

    - by Mercer
    hello, i have a table with some rows. idClient, name, adress,country,... i want to know how i can do an insert into this table with auto increment my idClient in my sql request..? Thx. edit: i want do a request like this insert into Client values((select max(idClient),...)

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  • Maintain case sensitivity when importing db into windows

    - by razass
    I have an export from a MYSQL database on a linux machine however when importing that database into MYSQL on windows all of the table names that were camel cased are now all lower case. The sql dump has the correct case in it but the importing via phpmyadmin seams to remove these. How can I import it and keep the case? Thanks

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  • How to disable activerecord cache logging in rails

    - by user1508459
    I'm trying to disable logging of caching in production. Have succeeded in getting SQL to stop logging queries, but no luck with caching log entries. Example line in production log: CACHE (0.0ms) SELECT merchants.* FROM merchants WHERE merchants.id = 1 LIMIT 1 I do not want to disable all logging, since I want logger.debug statements to show up in the production log. Using rails 3.2.1 with Mysql and Apache. Any suggestions?

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  • php parse error always on the last line

    - by is0lated
    I'm trying to read a comment that is stored in a mysql table. For some reason I always get a parse error on the last line of the file even if the last line is blank. I'm not sure if it's relevant but the connect.php works for putting the comment into the database. I'm using wampserver to host it and coding it by hand. I think that's it's something to do with the while loop, when I comment out the while(){ and the } near the end I just get a few missing variable errors as you would expect. I'm quite new to php coding so I'm pretty sure the problem will be something simple that I've either missed or not understood properly. Anyway, here's my code: <?php include "connect.php"; ?> <?php $sql = "SELECT * FROM main"; $result = mysql_query($sql) or die("Could not get posts from table"); while($rows=mysql_fetch_array($result)){ ?> <table bgcolor="green" align="center"> <tr> <td></td> </tr> <tr> <td><strong> <? echo $rows['name']; ?> </strong></td> </tr> <tr> <td> <? echo $rows['email']; ?> </td> </tr> <tr> <td> <? echo $rows['comment']; ?> </td> </tr> </table> <? } ?> Thanks for the help. :)

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  • Pass windows authentication username to asp variable

    - by Darren Cook
    Hi, I have a site that processes orders taken by phone into a SQL database. Access to the portal uses Windows Authentication and I would like to pass the username of the order processor along with the order so that I can record who has taken the order. How can I pass the user name to a form element? The pages are written in classic asp. Thanks.

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