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  • Understanding the Microsoft Public License (MS-PL)

    - by J.r. Hounddog
    I'm looking at using a few open source products in a commercial software application I'm working on. One of them is licensed under MIT, which I understand as allowing commercial software linking. However, the other open source product is licensed under MS-PL but I don't understand if that license is fully compatible with commercial software. So the question is, can I use MS-PL licensed OSS in a commercial/proprietary/for-sale application? Thanks.

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  • Did Microsoft Add Wiretapping Capability to Skype?

    Ryan Gallagher, writing for Slate, put two and two together from a lot of no comments. He noted that back in 2007, German police forces said that they couldn't tap into Skype calls because of of its strong encryption and complicated peer-to-peer network connections; in fact, Skype bluntly stated at the time that, due to its encryption and architecture techniques, it couldn't conduct wiretaps. But that may have changed. Gallagher cited a Forbes article that claims the hacker community is talking about recent changes to Skype's architecture and whether they will allow users to be wiretapped. ...

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  • Extending Expression Blend 4 &amp; Blend for Visual Studio 2012

    - by Chris Skardon
    Just getting this off the bat, I presume this will also work for Blend 5, but I can’t confirm it… Anyhews, I imagine you’re here because you want to know how to create an addin for Blend, so let’s jump right in there! First, and foremost, we’re going to need to ensure our development environment has the right setup, so the checklist: Visual Studio 2012 Blend for Visual Studio 2012 OK, let’s create a new project (class library, .NET 4.5): Hello.Extension The ‘.Extension’ bit is very very important. The addin will not work unless it is named in this way. You can put whatever you want at the front, but it has to have the extension bit. OK, so now we have a solution with one project. To this project we need to add references to the following things: Microsoft.Expression.Extensibility (from c:\program files\Microsoft Visual Studio 11.0\Blend\   -- x86 folder if you are on an x64 windows install) Microsoft.Expression.Framework (same location as above) PresentationCore PresentationFramework WindowsBase System.ComponentModel.Composition Got them? ACE. Let’s now add a project to contain our control, so, create a new WPF Application project, cunningly named something like ‘Hello.Control’… (I’m creating a WPF application here, because I’m too lazy to dig up the correct references, and this will add all the ones I need ) Once that is created, delete the App.xaml and MainWindow.xaml files, we won’t be needing them. You will also need to change the properties of the project itself, so it is only a class library. Once that is done, let’s add a new UserControl, which will be this: <UserControl x:Class="Hello.Control.HelloControl" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" mc:Ignorable="d" d:DesignHeight="300" d:DesignWidth="300"> <Grid> <TextBlock Text="HELLO!!!"/> </Grid> </UserControl> Impressive eh? Now, let’s reference the WPF project from the Extension library. All that’s left now is to code up our extension… So, add a class to the Extension project (name wise doesn’t matter), and make it implement the IPackage interface from the Microsoft.Expression.Extensibility library: public class HelloExtension : IPackage { /**/ } We’ll implement the two methods we need to: public class HelloExtension : IPackage { public void Load(IServices services) { } public void Unload() { } } We’re only really concerned about the Load method in this case, as let’s face it, the extension we have doesn’t need to do a lot to bog off. The interesting thing about the Load method is that it receives an IServices instance. This allows us to get access to all the services that Expression provides, in this case we’re interested in one in particular, the ‘IWindowService’ So, let’s get that bad boy… private IWindowService _windowService; public void Load(IServices services) { _windowService = services.GetService<IWindowService>(); } Nailed it… But why? The WindowService allows us to register our UserControl with Blend, which in turn allows people to activate and see it, which is a big plus point. So, let’s do that… We’ll create an ‘Initialize’ method to create our new control, and add it to the WindowService: private HelloControl _helloControl; public void Initialize() { _helloControl = new HelloControl(); if (_windowService.PaletteRegistry["HelloPanel"] == null) _windowService.RegisterPalette("HelloPanel", _helloControl, "Hello Window"); } First we check that we’re not already registered, and if we’re not we register, the first argument is the identifier used by the service to, well, identify your extension. The second argument is the actual control, the third argument is the name that people will see in the ‘Windows’ menu of Blend itself (so important note here – don’t put anything embarrassing or (need I say it?) sweary…) There are only two things to do now - Call ‘Initialize()’ from our Load method, and Export the class This is easy money – add [Export(typeof(IPackage))] to the top of our class… The full code will (should) look like this: [Export(typeof (IPackage))] public class HelloExtension : IPackage { private HelloControl _helloControl; private IWindowService _windowService; public void Load(IServices services) { _windowService = services.GetService<IWindowService>(); Initialize(); } public void Unload() { } public void Initialize() { _helloControl = new HelloControl(); if (_windowService.PaletteRegistry["HelloControl"] == null) _windowService.RegisterPalette("HelloControl", _helloControl, "Hello Window"); } } If you build this and copy it to your ‘Extensions’ folder in Blend (c:\program files\microsoft visual studio 11.0\blend\) and start Blend, you should see ‘Hello Window’ listed in the Window menu: That as they say is it!

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  • Problem with evaluating XPath expression in Java

    - by JSteve
    Can somebody help me find the mistake I am doing in evaluating following XPath expression? I want to get all "DataTable" nodes under the node "Model" in my xml through XPath. Here is my XML doc: <?xml version="1.0" encoding="UTF-8"?> <Root> <Application> <Model> <DataSet name="ds" primaryTable="Members" openRows="1"> <DataTable name="Members" openFor="write"> <DataColumn name="id" type="String" mandatory="true" primaryKey="true" valueBy="user"/> <DataColumn name="name" type="String" mandatory="true" valueBy="user"/> <DataColumn name="address" type="String" mandatory="false" valueBy="user"/> <DataColumn name="city" type="String" mandatory="false" valueBy="user"/> <DataColumn name="country" type="String" mandatory="false" valueBy="user"/> </DataTable> </DataSet> </Model> <View> <Composite> <Grid> <Label value="ID:" row="0" column="0" /> <Label value="Name:" row="1" column="0" /> <Label value="Address:" row="2" column="0" /> <Label value="City:" row="3" column="0" /> <Label value="Country:" row="4" column="0" /> <TextField name="txtId" row="0" column="1" /> <TextField name="txtName" row="1" column="1" /> <TextField name="txtAddress" row="2" column="1" /> <TextField name="txtCity" row="3" column="1" /> <TextField name="txtCountry" row="4" column="1" /> </Grid> </Composite> </View> </Application> </Root> Here the Java code to extract required node list: try { DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance(); domFactory.setNamespaceAware(true); domFactory.setIgnoringComments(true); domFactory.setIgnoringElementContentWhitespace(true); DocumentBuilder builder = domFactory.newDocumentBuilder(); Document dDoc = builder.parse("D:\TEST\myFile.xml"); XPath xpath = XPathFactory.newInstance().newXPath(); NodeList nl = (NodeList) xpath.evaluate("//Model//DataTable", dDoc, XPathConstants.NODESET); System.out.println(nl.getLength()); }catch (Exception ex) { System.out.println(ex.getMessage()); } There is no problem in loading and parsing xml file and I can see correct nodes in dDoc. Problem is with xpath that returns nothing on evaluating my expression. I tried many other expressions for testing purpose but every time resulting NodeList "nl" does not have any item

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  • Mix2010: Search Engine Optimization (SEO) for Microsoft Silverlight

    I had a great time today in my Mix2010 session on SEO for Silverlight.   You can find all the slides (more than I was able to cover in the talk) here.  and the the full play-by-play of the demo (include a link to the completed solution).    I started off talking why SEO matters Then I talked about three tips   You can view the site live by using Bing for my foodie Explorer Cooking Class with Joe.. or the other guys search engine equally well. ...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Education and Career Resources from Microsoft and the Community

    - by KKline
    Sometimes I'm timely in getting the news out on useful resources. And, other times, I'm a bit slower on the draw. As I told my friends back at New Year's Day, "As an official member of the Procrastinators Club, welcome to 2008!" On the other hand, it's always good to remind folks of great resources that are still available and on the shelf. Why? Well, the Internet hits us with such a deluge of constantly new material, that we often forget about the old(ish) stuff that's still really useful. Darth...(read more)

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  • Microsoft Visual Studio Professional 2010

    Visualize your workspace with new multiple monitor support, powerful Web development, new SharePoint support with tons of templates and Web parts, and more accurate targeting of any version of the .NET Framework. Get set to unleash your creativity.

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  • Microsoft Visual Studio Professional 2010

    Visualize your workspace with new multiple monitor support, powerful Web development, new SharePoint support with tons of templates and Web parts, and more accurate targeting of any version of the .NET Framework. Get set to unleash your creativity.

    Read the article

  • How to get better at solving Dynamic programming problems

    - by newbie
    I recently came across this question: "You are given a boolean expression consisting of a string of the symbols 'true', 'false', 'and', 'or', and 'xor'. Count the number of ways to parenthesize the expression such that it will evaluate to true. For example, there is only 1 way to parenthesize 'true and false xor true' such that it evaluates to true." I knew it is a dynamic programming problem so i tried to come up with a solution on my own which is as follows. Suppose we have a expression as A.B.C.....D where '.' represents any of the operations and, or, xor and the capital letters represent true or false. Lets say the number of ways for this expression of size K to produce a true is N. when a new boolean value E is added to this expression there are 2 ways to parenthesize this new expression 1. ((A.B.C.....D).E) ie. with all possible parenthesizations of A.B.C.....D we add E at the end. 2. (A.B.C.(D.E)) ie. evaluate D.E first and then find the number of ways this expression of size K can produce true. suppose T[K] is the number of ways the expression with size K produces true then T[k]=val1+val2+val3 where val1,val2,val3 are calculated as follows. 1)when E is grouped with D. i)It does not change the value of D ii)it inverses the value of D in the first case val1=T[K]=N.( As this reduces to the initial A.B.C....D expression ). In the second case re-evaluate dp[K] with value of D reversed and that is val1. 2)when E is grouped with the whole expression. //val2 contains the number of 'true' E will produce with expressions which gave 'true' among all parenthesized instances of A.B.C.......D i) if true.E = true then val2 = N ii) if true.E = false then val2 = 0 //val3 contains the number of 'true' E will produce with expressions which gave 'false' among all parenthesized instances of A.B.C.......D iii) if false.E=true then val3=( 2^(K-2) - N ) = M ie. number of ways the expression with size K produces a false [ 2^(K-2) is the number of ways to parenthesize an expression of size K ]. iv) if false.E=false then val3 = 0 This is the basic idea i had in mind but when i checked for its solution http://people.csail.mit.edu/bdean/6.046/dp/dp_9.swf the approach there was completely different. Can someone tell me what am I doing wrong and how can i get better at solving DP so that I can come up with solutions like the one given above myself. Thanks in advance.

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