Search Results

Search found 4072 results on 163 pages for 'front runner'.

Page 94/163 | < Previous Page | 90 91 92 93 94 95 96 97 98 99 100 101  | Next Page >

  • Looking for algorithms regarding scaling and moving

    - by user1806687
    I've been bashing my head for the past couple of weeks trying to find algorithms that would help me accomplish, on first look very easy task. So, I got this one object currently made out of 5 cuboids (2 sides, 1 top, 1 bottom, 1 back), this is just for an example, later on there will be whole range of different set ups. I have included three pictures of this object(as said this is just for an example). Now, the thing is when the user scales the whole object this is what should happen: X scale: top and bottom cuboids should get scaled by a scale factor, sides should get moved so they are positioned just like they were before(in this case at both ends of top and bottom cuboids), back should get scaled so it fits like before(if I simply scale it by a scale factor it will leave gaps on each side). Y scale: sides should get scaled by a scale factor, top and bottom cuboid should get moved, and back should also get scaled. Z scale: sides, top and bottom cuboids should get scaled, back should get moved. Here is an image of the example object (a thick walled box, with one face missing, where each wall is made by a cuboid): Front of the object: Hope you can help,

    Read the article

  • Repository query conditions, dependencies and DRY

    - by vFragosop
    To keep it simple, let's suppose an application which has Accounts and Users. Each account may have any number of users. There's also 3 consumers of UserRepository: An admin interface which may list all users Public front-end which may list all users An account authenticated API which should only list it's own users Assuming UserRepository is something like this: class UsersRepository extends DatabaseAbstraction { private function query() { return $this->database()->select('users.*'); } public function getAll() { return $this->query()->exec(); } // IMPORTANT: // Tons of other methods for searching, filtering, // joining of other tables, ordering and such... } Keeping in mind the comment above, and the necessity to abstract user querying conditions, How should I handle querying of users filtering by account_id? I can picture three possible roads: 1. Should I create an AccountUsersRepository? class AccountUsersRepository extends UserRepository { public function __construct(Account $account) { $this->account = $account; } private function query() { return parent::query() ->where('account_id', '=', $this->account->id); } } This has the advantage of reducing the duplication of UsersRepository methods, but doesn't quite fit into anything I've read about DDD so far (I'm rookie by the way) 2. Should I put it as a method on AccountsRepository? class AccountsRepository extends DatabaseAbstraction { public function getAccountUsers(Account $account) { return $this->database() ->select('users.*') ->where('account_id', '=', $account->id) ->exec(); } } This requires the duplication of all UserRepository methods and may need another UserQuery layer, that implements those querying logic on chainable way. 3. Should I query UserRepository from within my account entity? class Account extends Entity { public function getUsers() { return UserRepository::findByAccountId($this->id); } } This feels more like an aggregate root for me, but introduces dependency of UserRepository on Account entity, which may violate a few principles. 4. Or am I missing the point completely? Maybe there's an even better solution? Footnotes: Besides permissions being a Service concern, in my understanding, they shouldn't implement SQL query but leave that to repositories since those may not even be SQL driven.

    Read the article

  • How to search the web for programming related solutions?

    - by Bob
    I have the impression that Google has become unusable when searching for programming related questions. Example: I'm Googling for XML-RPC Redstone Cookie I'm expecting results where all three terms are contained. I don't care for results where one term misses. I guess until some months ago Google just worked this way, i.e. all terms were included. Somehow this feature is gone now (Google apparently thinks it is more intelligent than the user and knows what the user is searching for). So I helped myself putting a + in front of every word. This is, however, a bit cumbersome. And for the last weeks, it even doesn't work anymore in all cases, Google ignores the +. So how do you search for progamming related problems? Do you still use Google? If yes, which techniques do you use to get the right results? Or do you use another search engine? Which one?

    Read the article

  • Bad previous code. To fix or not to fix?

    - by Viniyo Shouta
    As a freelancer programmer I am often asked to edit part of an application source code in order to add functionalities, fix bugs etc. While I'm on my adventure journey to study the source to do what I'm asked correctly I run into code like: World::User* GetWorld() { map<DWORD,World*>::iterator it = mapWld.find( m_userWorldId ) if( it != mapWld.end() ) return &it->second; return NULL; } if( pUser->GetWorld()->GetId() == 250 ) If I investigate further I end up finding that the DWORD class member of User, userWorldId can be a value non-found in the map mapWld, which will lead to a casuality as also known as crash! The obviously valid way to do it is: World* pWorld = pUser->GetWorld(); if( pWorld && pWorld->GetId() == 250 )//... Sometimes when it's something just 'small' I end up sort of 'fixing' it. But sometimes when I'm on a 500 thousand line source code and this kind of code is everywhere there is no much can do. The question is if it's politically correct to fix some of these things. Think of it; You are not paid to fix it. Perhaps you think it's right, but it was necessarily done that way for some reason and you should not be messing with it. You do not have authorization, you do not own the source and none of the copyrights belong to you. You have authorization to edit issues accordingly to the owners but you're in a hurry, you have many other projects to do, it's the end of the month, you must pay the bills. Sincerely, I think of it as seeing an animal die from a disease in front of you, you have the cure in your hands but you do nothing. What is the best to do in this scenario?

    Read the article

  • Cocos2D: Change animation based on joystick direction

    - by Blade
    I'm trying to get my figure to look in the right directions, based on the input of the joystick. So if I tilt left it looks left and the left animation is used, if I used right, it looks right and right animation is used, if up, then up, down, down and so on. I just get animation for front and back. Also if I press up I see the back of the figure correctly, but it won't go back into the original state when I don't press up anymore. -(void)applyJoystick:(SneakyJoystick *)aJoystick forTimeDelta:(float) deltaTime { CGPoint scaledVelocity = ccpMult(aJoystick.velocity, 128.0f); CGPoint oldPosition = [self position]; CGPoint newPosition = ccp(oldPosition.x + scaledVelocity.x * deltaTime, oldPosition.y + scaledVelocity.y * deltaTime); [self setPosition:newPosition]; id action = nil; int extra = 50; if ((int) aJoystick.degrees > 180 - extra && aJoystick.degrees < 180 + extra) { action = [CCAnimate actionWithAnimation:walkingAnimLeft restoreOriginalFrame:NO]; } else if ((int) aJoystick.degrees > 360 - extra && aJoystick.degrees < 360 + extra) { action = [CCAnimate actionWithAnimation:walkingAnimRight restoreOriginalFrame:NO]; } else if ((int) aJoystick.degrees > 90 - extra && aJoystick.degrees < 90 + extra) { action = [CCAnimate actionWithAnimation:walkingAnimBack restoreOriginalFrame:NO]; } else if ((int) aJoystick.degrees > 270 - extra && aJoystick.degrees < 270 + extra) { action = [CCAnimate actionWithAnimation:walkingAnimFront restoreOriginalFrame:NO]; } if (action != nil) { [self runAction:action]; } } }

    Read the article

  • Simple C: How do I scan this information in properly?

    - by Doc
    OK this is a simple question but for some reason I just can't get it right. I have to scan from a file hundreds of lines of code and store it in a array (which I can normally do a ok job with) however At one point the code will specify a number that then corresponds to the next batch of chars ints and floats going into various arrays. As I know I am not describing this correctly here is a example. one line of the file I am reading will contain something close to this. 0221 T 2 S P 850 150 0.90 0.75 500 24 2 2012 G A 7 9600.00 0.1 1000 Name_of_place 0104 L 1 F 400 1.00 0.75 500 24 2 2012 G A 7 9600.00 0.1 1000 Ballroom the problem I am having is This part here 0221 T 2 S P 850 150 0.90 0.75 500 24 2 2012 G A 7 9600.00 0.1 1000 Name_of_place 0104 L 1 F 400 1.00 0.75 500 24 2 2012 G A 7 9600.00 0.1 1000 Ballroom The rest after this is Generally the exact same however at this point the number at the front descides all the values that are going in. I am almost completely lost on how to write a way that can scan this and store the data into arrays correctly

    Read the article

  • Selecting objects on a 2D map

    - by Dave
    I have a object selection function by checking the mouse click and getting the relevant object. How ever there is a rare situation where if one object is partially behind the other then both objects are in the given area so im wondering how I can make the game know which one was selected, as currently my method does not know. This is my function that works it out: function getobj(e){ mx = e.pageX - curleft; //mouse click x my = e.pageY - curtop; //mouse click y function searchSprites(sprites, x, y) { var matches = [], i = 0, data = null; for (i = 0; i < spritea.length; ++i) { data = spritea[i].data; if (x > data[0] && y > data[1] && x < data[2] && y < data[3]) { var imageData = ctx2.getImageData(x, y, 1, 1); if(imageData.data[3] !== 0){ return [spritea[i].id]; i = spritea.length; } } } } res = searchSprites(spritea, mx, my); bid = res[0]; if(bid === '1'){ alert('You selected the skyscraper in front!'); }else if(bid === '3'){ alert('You selected the skyscraper behind!'); } } Image of the map: It keeps telling me I clicked the skyscraper behind which is not necessarily what the user is trying to do. How can I improve the accuracy of this ?

    Read the article

  • How you choose your first job as a programmer? [on hold]

    - by sliter
    For Brief I am a recently graduated CS student. I am looking for a job these days, but I have no idea what kind of software development jobs I like(embedded system,web development or else...). And I am looking for your advice. Here is a little more While I was a student, I had an one year internship experience as a system engineer in a semi-conductor company where I wrote Linux driver, tuned system performance, etc.. I was happy about this experience as it allowed me to deepen my understanding of the operating system and different low level things. And I thought "Em, I will continue in the embedded area after I graduate". At the end of my study, I am doing an another internship in web development, both front-end and back-end. And I also enjoys a lot the process of learning new things and making it work (Backbone, Node, socketio, etc..). Now, when I am looking for a software development position, I do not know what to apply! All I know is that I want a job which allows me to keep up with the trends instead of repeating. But besides this, I've no idea what specific type of job I want to do. Turn back to embedded system? Continue with web development? Change to other promising areas(data mining)? All these development positions makes no big difference to me. But I think this is not good and I need some criteria at choosing. So I am looking for advice and I would really appreciate if you can share your experience.

    Read the article

  • To program in free time as a programmer, is to show that programming is passion. If not, is the programmer good? [closed]

    - by SonofWatson
    Possible Duplicate: I don't program in my spare time. Does that make me a bad developer? A lot of blogs and advice on the web seem to suggest that in order to become a great developer, doing just your day job is not enough. For example, you should contribute to open source projects in your spare time, write smartphone apps, etc. In fact a lot of this advice seems to suggest that if you don't love programming enough to do it all day long then you're probably in the wrong career. That doesn't ring true with me. I enjoy my work, but when I come home from the office I'm not in the mood to jump straight back onto the computer and start coding away until bedtime. I only have a certain number of hours free time each day, and I'd rather spend them on other hobbies, seeing friends or going outside than in front of the computer. I do get a kick out of programming, and do hack around outside of work occasionally. I'm committed to my personal development and spend time reading tech blogs and books as a way to keep learning and becoming better. But that doesn't extend so far as to my wanting to use all my spare time for coding. Does this mean I'm not a 'true' software developer at heart? Is it possible to become a good software developer without doing extra outside your job? I'd be very interested to hear what you think.

    Read the article

  • Getting expired domain name - most effective route?

    - by kcdwayne
    There is a domain name I have been wanting for years that was used as a parked page (read: cybersquatted) that has entered into WHOIS's redemptionPeriod stage. The domain has been expired for 61 days now - after contacting the Registar, they informed me that it would stay in redemption for 75 days. After which, it would either be sold to resellers, or sent back to the public registry. (I have since sent a followup message requesting the reseller they use.) My question is: What is the best way to proceed? I know there is at least one competitor that would love to have this name, but I'm unsure if they even know it's expiring. I did not tell the Registar the domain in question, as they seem geared towards cybersquatting, and I do not trust them. Domain Front Running sucks. Should I use a backorder service? Should I just take my chances and try to grab it after75 days? I checked an auctionhouse by manually browsing their expired domains - it wasn't there.

    Read the article

  • Using mod_rewrite for a Virtual Filesystem vs. Real Filesystem

    - by philtune
    I started working in a department that uses a CMS in which the entire "filesystem" is like this: create a named file or folder - this file is given a unique node (ex. 2345) as well as a default "filename" (ex. /WelcomeToOurProductsPage) and apply a template assign one or more aliases to the file for a URL redirect (ex. /home-page-products - can also be accessed by /home-page-products.aspx) A new Rewrite command is written on the .htaccess file for each and every alias Server accesses either /WelcomeToOurProductsPage or /home-page-products and redirects to something like /template.aspx?tmp=2&node=2345 (here I'm guessing what it does - I only have front-end access for now - but I have enough clues to strongly assume) Node 2345 grabs content stored in a SQL Db and applies it to the template. Note: There are no actual files being created on the filesystem. It's entirely virtual. This is probably a very common thing, but since I have never run across this kind of system before two months ago, I wanted to explain it in case it isn't common. I'm not a fan at all of ASP or closed-sourced systems, so it may be that this is common practice for ASP developers. My question, that has taken far too long to ask, is: what are the benefits of this kind of system, as opposed to creating an actual file hierarchy? Are there any drawbacks to having every single file server call redirected? To having the .htaccess file hold rewrite rules for every single alias?

    Read the article

  • Is this too much to ask for a game programming and developing enthusiast? Am I doing this wrong?

    - by I_Question_Things_Deeply
    I have been a computer-fanatic for almost a decade now. I've always loved and wondered how computers work, even from the purest, lowest hardware level to the very smallest pixel on the screen, and all the software around that. That seems to be my problem though ... as I try to write code (I'm pretty fluent at C++) I always sit there enormous amounts of time in front of a text-editor wondering how every line, statement, datum, function, etc. will correspond to every Assembly and machine instruction performed to do absolutely everything necessary for the kernel to allocate memory to run my compiled program, and all of the other hardware being used as well. For example ... I would write cout << "Before memory changed" << endl; and run the debugger to get the Assembly for this, and then try and reverse disassemble the Assembly to machine code based on my ISA, and then research every .dll, library file, linked library, linking process, linker source code of the program, the make file, the kernel I'm using's steps of processing this compilation, the hardware's part aside from the processor (e.g. video card, sound card, chipset, cache latency, byte-sized registers, calling convention use, DDR3 RAM and disk drive, filesystem functioning and so many other things). Am I going about programming wrong? I mean I feel I should know everything that goes on underneath English syntax on a computer program. But the problem is that the more I research every little thing the less I actually accomplish at all. I can never finish anything because of this mentality, yet I feel compelled to know everything... what should I do?

    Read the article

  • Are you satisfied with your programming? [closed]

    - by Richart Bremer
    If you are a programmer, are you satisfied with it? I really love to code. I code all kinds of things. I used to play computer games but they are not that interesting compared to developing a new search algorithm or similar. But sometimes I look into the future and see myself being 80 years old, sitting in front of a computer and everything I will have written will be rewritten because the programming languages do not exist anymore. I look back on my life and think "that's it?". Everything I wrote in the past is virtual and ultimately gone. I tried other things but coding is the only thing that does it for me. And at the same time I think I am wasting my life. What about you? Disclaimer: I presume this is the best forum for this question. If you don't agree suggest better place to migrate the question. If you can't, don't close it. Thank you.

    Read the article

  • How can I port msvc++ code with non-dependent names in templates to Linux?

    - by user352382
    I can deal with porting platform dependent functions. I have a problem that the compilers I tried on Linux (clang and g++) do not accept the following code, while the msvc++ compiler does: template <class T> class Base { protected: T Value; }; template <class T> class Derived : public Base<T> { public: void setValue(const T& inValue){ Value = inValue; } }; int main(int argc, char const *argv[]) { Derived<int> tmp; tmp.setValue(0); return 0; } g++ error: main.cpp: In member function ‘void Derived<T>::setValue(const T&)’: main.cpp:11:3: error: ‘Value’ was not declared in this scope I believe this due to the use of a non-dependent name (Value) in the second class. More information. The problem is that I have a very large code base, in which this type of code is used very often. I understand that it is wrong when looking at the standard. However it is very convenient not having to write this-> or Base<T>:: in front of every use of Value. Even writing using Base<T>::Value; at the start of the derived class is problematic when you use ~20 members of the base class. So my question is: are there compilers for Linux that allow this kind of code (with or without extra compiler switches)? Or are there small modifications that will allow this code to compile on Linux?

    Read the article

  • Help with selecting objects on a map

    - by Dave
    I have a object selection function by checking the mouse click and getting the relevant object. How ever there is a rare situation where if one object is partially behind the other then both objects are in the given area so im wondering how i can make the game know which one was selected, as currently my method does not know. This is my function that works it out: function getobj(e){ mx = e.pageX - curleft; //mouse click x my = e.pageY - curtop; //mouse click y function searchSprites(sprites, x, y) { var matches = [], i = 0, data = null; for (i = 0; i < spritea.length; ++i) { data = spritea[i].data; if (x > data[0] && y > data[1] && x < data[2] && y < data[3]) { var imageData = ctx2.getImageData(x, y, 1, 1); if(imageData.data[3] !== 0){ return [spritea[i].id]; i = spritea.length; } } } } res = searchSprites(spritea, mx, my); bid = res[0]; if(bid === '1'){ alert('You selected the skyscraper in front!'); }else if(bid === '3'){ alert('You selected the skyscraper behind!'); } } Image of the map: http://i.imgur.com/qcKij.jpg It keeps telling me i clicked the skyscraper behind which is not necessarily what the user is trying to do... how can i improve the accuracy of this ?

    Read the article

  • Please help! Every Post link links to the most recent post Wordpress

    - by kwek-kwek
    I got the site up on time, with one blog post up. Later I added another one and tested it. Big problem! Any link that used to take you to the old post (ie: side-bar "Recent Posts" links) now takes you to the newest one. I tested it by adding a third post, and got the same result. This is a custom wordpress theme and I have a, page.php <?php get_header(); ?> <?php if (have_posts()) : while (have_posts()) : the_post(); ?> <div id="BodyWrap"> <!--MAIN CONT--> <div id="mainCont"> <?php get_sidebar(); ?> <?php if (is_page(array('home'))) { ;?> <div id="rotateBanner"> <div id="slide-holder"> <div id="slide-runner"> <img id="slide-img-1" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial2.jpg" class="slide" alt="" /> <img id="slide-img-5" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial5.jpg" class="slide" alt="" /> <img id="slide-img-2" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial1.jpg" class="slide" alt="" /> <img id="slide-img-6" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial6.jpg" class="slide" alt="" /> <img id="slide-img-3" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial3.jpg" class="slide" alt="" /> <img id="slide-img-7" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial7.jpg" class="slide" alt="" /> <img id="slide-img-4" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial4.jpg" class="slide" alt="" /> <img id="slide-img-8" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial8.jpg" class="slide" alt="" /> <div id="slide-controls"> <p id="slide-client" class="text" style="display:none;"><span></span></p> <p id="slide-desc" class="text" style="display:none;"></p> <p id="slide-nav" style="display:none;"></p> </div> </div> <script type="text/javascript"> if(!window.slider) var slider={};slider.data=[{"id":"slide-img-1","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-5","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-2","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-6","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-3","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-7","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-4","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-8","client":"nature beauty","desc":"nature beauty photography"}]; </script> </div> </div> <?php } ?> <?php if (is_page(array('accueil'))) { ;?> <div id="rotateBanner"> <div id="slide-holder"> <div id="slide-runner"> <img id="slide-img-1" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial1-fr.jpg" class="slide" alt="" /> <img id="slide-img-5" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial5-fr.jpg" class="slide" alt="" /> <img id="slide-img-2" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial2-fr.jpg" class="slide" alt="" /> <img id="slide-img-6" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial6-fr.jpg" class="slide" alt="" /> <img id="slide-img-3" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial3-fr.jpg" class="slide" alt="" /> <img id="slide-img-7" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial7-fr.jpg" class="slide" alt="" /> <img id="slide-img-4" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial4-fr.jpg" class="slide" alt="" /> <img id="slide-img-8" src="<?php bloginfo('template_url'); ?>/images/banner/testimonial8-fr.jpg" class="slide" alt="" /> <div id="slide-controls"> <p id="slide-client" class="text" style="display:none;"><span></span></p> <p id="slide-desc" class="text" style="display:none;"></p> <p id="slide-nav" style="display:none;"></p> </div> </div> <script type="text/javascript"> if(!window.slider) var slider={};slider.data=[{"id":"slide-img-1","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-5","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-2","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-6","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-3","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-7","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-4","client":"nature beauty","desc":"nature beauty photography"},{"id":"slide-img-8","client":"nature beauty","desc":"nature beauty photography"}]; </script> </div> </div> <?php } ?> <?php if (is_page(array('contact-us'))) { ;?> <div id="rotateBanner"> <?php custom_field_image() ?> </div> <?php } ?> <div id="mainCopy"> <div id="content"> <h2> <?php if (is_page('home','accueil')) : ?> <?php else : ?> <?php single_post_title(); ?> <?php endif; ?></h2> <?php the_content('<p class="serif">Read the rest of this page &raquo;</p>'); ?> <?php wp_link_pages(array('before' => '<p><strong>Pages:</strong> ', 'after' => '</p>', 'next_or_number' => 'number')); ?> </div> </div> <?php if (is_page(array('home','accueil'))) { ;?> <div id="rightCol2"> <div id="Fworks"> <h2>Featured work</h2> <li><img src="<?php bloginfo('template_url'); ?>/images/portage-thumb.jpg" width="234" height="92" border="0" alt="" /></li> <li><a href="<?php bloginfo('url'); ?>our-work/foundation-on-antivirals"><img src="<?php bloginfo('template_url'); ?>/images/fav-thumb.jpg" width="234" height="92" border="0" alt="" /></a></li> <li><img src="<?php bloginfo('template_url'); ?>/images/danslejardin-thumb.jpg" width="234" height="92" border="0" alt="" /></li> </div> <div id="NewEvents"> <?php if ( (strtolower(ICL_LANGUAGE_CODE) == 'en') ) {echo("<h2>News &amp; Events</h2");} ?> <?php if ( (strtolower(ICL_LANGUAGE_CODE) == 'fr')) echo("<h2>Nouvelles</h2") ?> <div id="NewsListings"> <ul> <?php //dbem_get_events_list("limit=5&scope=al&order=DESC"); ?> <?php include('events.php');?> </ul> </div> </div> </div> <?php } ?> </div> </div> <?php endwhile; endif; ?> <?php get_footer(); ?> single.php <?php /** * @package WordPress * @subpackage Default_Theme */ get_header(); ?> <div id="BodyWrap"> <!--MAIN CONT--> <div id="mainCont"> <?php get_sidebar(); ?> <?php if (is_page(array('home','contact-us'))) { ;?> <div id="rotateBanner"> <?php custom_field_image() ?> </div> <?php } ?> <div id="mainCopy"> <div id="content" class="widecolumn" role="main"> <?php if (have_posts()) : while (have_posts()) : the_post(); ?> <!-- <div class="navigation"> <div class="alignleft"><?php previous_post_link('&laquo; %link') ?></div> <div class="alignright"><?php next_post_link('%link &raquo;') ?></div> </div> <br class="clr" />--> <div <?php post_class() ?> id="post-<?php the_ID(); ?>"> <h2><?php the_title(); ?></h2> <div class="entry"> <?php the_content('<p class="serif">Read the rest of this entry &raquo;</p>'); ?> <?php wp_link_pages(array('before' => '<p><strong>Pages:</strong> ', 'after' => '</p>', 'next_or_number' => 'number')); ?> <?php the_tags( '<p>Tags: ', ', ', '</p>'); ?> <!--<p class="postmetadata alt"> <small> This entry was posted <?php /* This is commented, because it requires a little adjusting sometimes. You'll need to download this plugin, and follow the instructions: http://binarybonsai.com/wordpress/time-since/ */ /* $entry_datetime = abs(strtotime($post->post_date) - (60*120)); echo time_since($entry_datetime); echo ' ago'; */ ?> on <?php the_time('l, F jS, Y') ?> at <?php the_time() ?> and is filed under <?php the_category(', ') ?>. You can follow any responses to this entry through the <?php post_comments_feed_link('RSS 2.0'); ?> feed. <?php if ( comments_open() && pings_open() ) { // Both Comments and Pings are open ?> You can <a href="#respond">leave a response</a>, or <a href="<?php trackback_url(); ?>" rel="trackback">trackback</a> from your own site. <?php } elseif ( !comments_open() && pings_open() ) { // Only Pings are Open ?> Responses are currently closed, but you can <a href="<?php trackback_url(); ?> " rel="trackback">trackback</a> from your own site. <?php } elseif ( comments_open() && !pings_open() ) { // Comments are open, Pings are not ?> You can skip to the end and leave a response. Pinging is currently not allowed. <?php } elseif ( !comments_open() && !pings_open() ) { // Neither Comments, nor Pings are open ?> Both comments and pings are currently closed. <?php } edit_post_link('Edit this entry','','.'); ?> </small> </p>--> </div> </div> <?php comments_template(); ?> <?php endwhile; else: ?> <p>Sorry, no posts matched your criteria.</p> <?php endif; ?> </div> </div> </div> </div> <?php get_footer(); ?> index.php <?php get_header(); ?> <!--MAIN WRAP--> <div id="BodyWrap"> <!--MAIN CONT--> <div id="mainCont"> <?php get_sidebar(); ?> <div id="mainCopy"> <div id="content"> <?php if ( have_posts() ) : while ( have_posts() ) : the_post(); ?> <div id="BGHeadTitle"><h2><a href="<?php the_permalink() ?>"><?php the_title(); ?></a></h2></div> <?php the_content(); ?> <p><?php the_time('F j, Y'); ?> at <?php the_time('g:i a'); ?> | <?php the_category(', '); ?> | <?php comments_number('No comment', '1 comment', '% comments'); ?></p> <?php comments_template(); // Get wp-comments.php template ?> <?php endwhile; else: ?> <h2>Woops...</h2> <p>Sorry, no posts we're found.</p> <?php endif; ?> <p align="center"><?php posts_nav_link(); ?></p> </div> </div> </div> </div> <?php get_footer(); ?> my recent post code : <ul> <?php query_posts('cat=3,4,5&posts_per_page=5&order=ASC&orderby=date'); if ( have_posts() ) : while ( have_posts() ) : the_post()?> <li> <span class="date"><?php the_time('M j') ?></span> <a href="<?php the_permalink(); ?>" title="<?php the_title(); ?>"><?php the_title(); ?></a> </li> <?php endwhile; ?> <?php rewind_posts(); ?> </ul> I am really stuck the site went live and when I was working on the testserver I only noticed it.view the site here »

    Read the article

  • Resque Runtime Error at /workers: wrong number of arguments for 'exists' command

    - by Superflux
    I'm having a runtime errror when i'm looking at the "workers" tab on resque-web (localhost). Everything else works. Edit: when this error occurs, i also have some (3 or 4) unknown workers 'not working'. I think they are responsible for the error but i don't understand how they got here Can you help me on this ? Did i do something wrong ? Config: Resque 1.8.5 as a gem in a rails 2.3.8 app on Snow Leopard redis 1.0.7 / rack 1.1 / sinatra 1.0 / vegas 0.1.7 file: client.rb location: format_error_reply line: 558 BACKTRACE: * /Library/Ruby/Gems/1.8/gems/redis-1.0.7/lib/redis/client.rb in format_error_reply * 551. when DOLLAR then format_bulk_reply(line) 552. when ASTERISK then format_multi_bulk_reply(line) 553. else raise ProtocolError.new(reply_type) 554. end 555. end 556. 557. def format_error_reply(line) 558. raise "-" + line.strip 559. end 560. 561. def format_status_reply(line) 562. line.strip 563. end 564. 565. def format_integer_reply(line) * /Library/Ruby/Gems/1.8/gems/redis-1.0.7/lib/redis/client.rb in format_reply * 541. 542. def reconnect 543. disconnect && connect_to_server 544. end 545. 546. def format_reply(reply_type, line) 547. case reply_type 548. when MINUS then format_error_reply(line) 549. when PLUS then format_status_reply(line) 550. when COLON then format_integer_reply(line) 551. when DOLLAR then format_bulk_reply(line) 552. when ASTERISK then format_multi_bulk_reply(line) 553. else raise ProtocolError.new(reply_type) 554. end 555. end * /Library/Ruby/Gems/1.8/gems/redis-1.0.7/lib/redis/client.rb in read_reply * 478. disconnect 479. 480. raise Errno::EAGAIN, "Timeout reading from the socket" 481. end 482. 483. raise Errno::ECONNRESET, "Connection lost" unless reply_type 484. 485. format_reply(reply_type, @sock.gets) 486. end 487. 488. 489. if "".respond_to?(:bytesize) 490. def get_size(string) 491. string.bytesize 492. end * /Library/Ruby/Gems/1.8/gems/redis-1.0.7/lib/redis/client.rb in process_command * 448. return pipeline ? results : results[0] 449. end 450. 451. def process_command(command, argvv) 452. @sock.write(command) 453. argvv.map do |argv| 454. processor = REPLY_PROCESSOR[argv[0].to_s] 455. processor ? processor.call(read_reply) : read_reply 456. end 457. end 458. 459. def maybe_lock(&block) 460. if @thread_safe 461. @mutex.synchronize(&block) 462. else * /Library/Ruby/Gems/1.8/gems/redis-1.0.7/lib/redis/client.rb in map * 446. end 447. 448. return pipeline ? results : results[0] 449. end 450. 451. def process_command(command, argvv) 452. @sock.write(command) 453. argvv.map do |argv| 454. processor = REPLY_PROCESSOR[argv[0].to_s] 455. processor ? processor.call(read_reply) : read_reply 456. end 457. end 458. 459. def maybe_lock(&block) 460. if @thread_safe * /Library/Ruby/Gems/1.8/gems/redis-1.0.7/lib/redis/client.rb in process_command * 446. end 447. 448. return pipeline ? results : results[0] 449. end 450. 451. def process_command(command, argvv) 452. @sock.write(command) 453. argvv.map do |argv| 454. processor = REPLY_PROCESSOR[argv[0].to_s] 455. processor ? processor.call(read_reply) : read_reply 456. end 457. end 458. 459. def maybe_lock(&block) 460. if @thread_safe * /Library/Ruby/Gems/1.8/gems/redis-1.0.7/lib/redis/client.rb in raw_call_command * 435. @sock.write(command) 436. return true 437. end 438. # The normal command execution is reading and processing the reply. 439. results = maybe_lock do 440. begin 441. set_socket_timeout!(0) if requires_timeout_reset?(argvv[0][0].to_s) 442. process_command(command, argvv) 443. ensure 444. set_socket_timeout!(@timeout) if requires_timeout_reset?(argvv[0][0].to_s) 445. end 446. end 447. 448. return pipeline ? results : results[0] 449. end * /Library/Ruby/Gems/1.8/gems/redis-1.0.7/lib/redis/client.rb in synchronize * 454. processor = REPLY_PROCESSOR[argv[0].to_s] 455. processor ? processor.call(read_reply) : read_reply 456. end 457. end 458. 459. def maybe_lock(&block) 460. if @thread_safe 461. @mutex.synchronize(&block) 462. else 463. block.call 464. end 465. end 466. 467. def read_reply 468. * /Library/Ruby/Gems/1.8/gems/redis-1.0.7/lib/redis/client.rb in maybe_lock * 454. processor = REPLY_PROCESSOR[argv[0].to_s] 455. processor ? processor.call(read_reply) : read_reply 456. end 457. end 458. 459. def maybe_lock(&block) 460. if @thread_safe 461. @mutex.synchronize(&block) 462. else 463. block.call 464. end 465. end 466. 467. def read_reply 468. * /Library/Ruby/Gems/1.8/gems/redis-1.0.7/lib/redis/client.rb in raw_call_command * 432. end 433. # When in Pub/Sub mode we don't read replies synchronously. 434. if @pubsub 435. @sock.write(command) 436. return true 437. end 438. # The normal command execution is reading and processing the reply. 439. results = maybe_lock do 440. begin 441. set_socket_timeout!(0) if requires_timeout_reset?(argvv[0][0].to_s) 442. process_command(command, argvv) 443. ensure 444. set_socket_timeout!(@timeout) if requires_timeout_reset?(argvv[0][0].to_s) 445. end 446. end * /Library/Ruby/Gems/1.8/gems/redis-1.0.7/lib/redis/client.rb in call_command * 336. # try to reconnect just one time, otherwise let the error araise. 337. def call_command(argv) 338. log(argv.inspect, :debug) 339. 340. connect_to_server unless connected? 341. 342. begin 343. raw_call_command(argv.dup) 344. rescue Errno::ECONNRESET, Errno::EPIPE, Errno::ECONNABORTED 345. if reconnect 346. raw_call_command(argv.dup) 347. else 348. raise Errno::ECONNRESET 349. end 350. end * /Library/Ruby/Gems/1.8/gems/redis-1.0.7/lib/redis/client.rb in method_missing * 385. connect_to(@host, @port) 386. call_command([:auth, @password]) if @password 387. call_command([:select, @db]) if @db != 0 388. @sock 389. end 390. 391. def method_missing(*argv) 392. call_command(argv) 393. end 394. 395. def raw_call_command(argvp) 396. if argvp[0].is_a?(Array) 397. argvv = argvp 398. pipeline = true 399. else * /Library/Ruby/Gems/1.8/gems/redis-namespace-0.4.4/lib/redis/namespace.rb in send * 159. args = add_namespace(args) 160. args.push(last) if last 161. when :alternate 162. args = [ add_namespace(Hash[*args]) ] 163. end 164. 165. # Dispatch the command to Redis and store the result. 166. result = @redis.send(command, *args, &block) 167. 168. # Remove the namespace from results that are keys. 169. result = rem_namespace(result) if after == :all 170. 171. result 172. end 173. * /Library/Ruby/Gems/1.8/gems/redis-namespace-0.4.4/lib/redis/namespace.rb in method_missing * 159. args = add_namespace(args) 160. args.push(last) if last 161. when :alternate 162. args = [ add_namespace(Hash[*args]) ] 163. end 164. 165. # Dispatch the command to Redis and store the result. 166. result = @redis.send(command, *args, &block) 167. 168. # Remove the namespace from results that are keys. 169. result = rem_namespace(result) if after == :all 170. 171. result 172. end 173. * /Library/Ruby/Gems/1.8/gems/resque-1.8.5/lib/resque/worker.rb in state * 416. def idle? 417. state == :idle 418. end 419. 420. # Returns a symbol representing the current worker state, 421. # which can be either :working or :idle 422. def state 423. redis.exists("worker:#{self}") ? :working : :idle 424. end 425. 426. # Is this worker the same as another worker? 427. def ==(other) 428. to_s == other.to_s 429. end 430. * /Library/Ruby/Gems/1.8/gems/resque-1.8.5/lib/resque/server/views/workers.erb in __tilt_a2112543c5200dbe0635da5124b47311 * 46. <tr> 47. <th>&nbsp;</th> 48. <th>Where</th> 49. <th>Queues</th> 50. <th>Processing</th> 51. </tr> 52. <% for worker in (workers = resque.workers.sort_by { |w| w.to_s }) %> 53. <tr class="<%=state = worker.state%>"> 54. <td class='icon'><img src="<%=u state %>.png" alt="<%= state %>" title="<%= state %>"></td> 55. 56. <% host, pid, queues = worker.to_s.split(':') %> 57. <td class='where'><a href="<%=u "workers/#{worker}"%>"><%= host %>:<%= pid %></a></td> 58. <td class='queues'><%= queues.split(',').map { |q| '<a class="queue-tag" href="' + u("/queues/#{q}") + '">' + q + '</a>'}.join('') %></td> 59. 60. <td class='process'> * /Library/Ruby/Gems/1.8/gems/resque-1.8.5/lib/resque/server/views/workers.erb in each * /Library/Ruby/Gems/1.8/gems/resque-1.8.5/lib/resque/server/views/workers.erb in __tilt_a2112543c5200dbe0635da5124b47311 * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/tilt.rb in send * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/tilt.rb in evaluate * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/tilt.rb in render * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in render * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in erb * /Library/Ruby/Gems/1.8/gems/resque-1.8.5/lib/resque/server.rb in show * /Library/Ruby/Gems/1.8/gems/resque-1.8.5/lib/resque/server.rb in GET /workers * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in call * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in route * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in instance_eval * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in route_eval * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in route! * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in catch * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in route! * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in each * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in route! * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in dispatch! * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in call! * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in instance_eval * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in invoke * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in catch * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in invoke * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in call! * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in call * /Volumes/Donnees/Users/**/.gem/ruby/1.8/gems/rack-1.1.0/lib/rack/showexceptions.rb in call * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in call * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in synchronize * /Library/Ruby/Gems/1.8/gems/sinatra-1.0/lib/sinatra/base.rb in call * /Volumes/Donnees/Users/**/.gem/ruby/1.8/gems/rack-1.1.0/lib/rack/content_length.rb in call * /Volumes/Donnees/Users/**/.gem/ruby/1.8/gems/rack-1.1.0/lib/rack/chunked.rb in call * /Volumes/Donnees/Users/**/.gem/ruby/1.8/gems/rack-1.1.0/lib/rack/handler/mongrel.rb in process * /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8/gems/mongrel-1.1.5/lib/mongrel.rb in process_client * /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8/gems/mongrel-1.1.5/lib/mongrel.rb in each * /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8/gems/mongrel-1.1.5/lib/mongrel.rb in process_client * /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8/gems/mongrel-1.1.5/lib/mongrel.rb in run * /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8/gems/mongrel-1.1.5/lib/mongrel.rb in initialize * /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8/gems/mongrel-1.1.5/lib/mongrel.rb in new * /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8/gems/mongrel-1.1.5/lib/mongrel.rb in run * /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8/gems/mongrel-1.1.5/lib/mongrel.rb in initialize * /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8/gems/mongrel-1.1.5/lib/mongrel.rb in new * /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8/gems/mongrel-1.1.5/lib/mongrel.rb in run * /Volumes/Donnees/Users/**/.gem/ruby/1.8/gems/rack-1.1.0/lib/rack/handler/mongrel.rb in run * /Library/Ruby/Gems/1.8/gems/vegas-0.1.7/lib/vegas/runner.rb in run! * /Library/Ruby/Gems/1.8/gems/vegas-0.1.7/lib/vegas/runner.rb in start * /Library/Ruby/Gems/1.8/gems/resque-1.8.5/bin/resque-web in new * /Library/Ruby/Gems/1.8/gems/resque-1.8.5/bin/resque-web in nil * /usr/bin/resque-web in load

    Read the article

  • Error running java -jar command

    - by dmantamp
    Hi all, I created a jar file using the following ANT script <manifestclasspath property="jar.classpath" jarfile="${bin.dir}/${jar.app.name}" maxparentlevels="0"> <classpath refid="main.class.path" /> </manifestclasspath> <target name="jar"> <mkdir dir="${build.dir}/lib/isp"/> <mkdir dir="${build.dir}/lib/jasper"/> <copy todir="${build.dir}/lib/jasper"> <fileset dir="${lib.jasper.dir}"> <include name="**/*.jar" /> </fileset> </copy> <copy todir="${build.dir}/lib/isp"> <fileset dir="${lib.isp.dir}"> <include name="**/*.jar" /> </fileset> </copy> <jar jarfile="${bin.dir}/${jar.app.name}" index="true" basedir="${classes.dir}" excludes="lib/mytest.jar " > <manifest> <attribute name="Main-Class" value="${main.class}" /> <attribute name="Class-Path" value="${jar.classpath}" /> </manifest> </jar> </target> The resulting jar file has the following MANIFEST.MF entry. Main-Class: dm.jb.Main Class-Path: lib/isp/OfficeLnFs_2.2.jar lib/isp/RXTXcomm.jar lib/isp/ba rbecue-1.0.6d.jar lib/isp/commons-logging-1.1.jar lib/isp/forms-1.0.5 .jar lib/isp/gnujaxp.jar lib/isp/helpUI.jar lib/isp/inspInstaller.jar lib/isp/itext-2.0.1.jar lib/isp/itext-2.0.2.jar lib/isp/jcalendar-1. 3.2.jar lib/isp/jcl.jar lib/isp/jcommon-1.0.10.jar lib/isp/jcommon-1. 0.9.jar lib/isp/jdnc-0_7-all.jar lib/isp/jdnc-runner.jar lib/isp/jdom .jar lib/isp/jfreechart-1.0.6.jar lib/isp/jlfgr-1_0.jar lib/isp/junit .jar lib/isp/log4j-1.2.9.jar lib/isp/looks-1.3.2.jar lib/isp/msbase.j ar lib/isp/mssqlserver.jar lib/isp/msutil.jar lib/isp/mysql-connector When I try to run the command java -jar mytest.jar, it fails and throws error saying dm.jb.Main not found. But I could run the class by specifying the classpath java -classpath dm.jb.Main Please help me DM

    Read the article

  • Letters in base-conversion

    - by tech_geek23
    I have this code written so far and is correct, aside from not using A-F when the value is over 10: public class TenToAny { private int base10; private int newBase; public TenToAny() { } public TenToAny(int ten, int base) { base10 = ten; newBase = base; } public void setNums(int ten, int base) { base10 = ten; newBase = base; } public String getNewNum() { String newNum=""; int orig = base10; //int first = newBase - 1; while(orig > 0) { newNum = orig%newBase + newNum; orig = orig/newBase; } return newNum; } public String toString() { String complete = base10 + " base 10 is " + getNewNum() + " in base " + newBase; return complete; } } Obviously I don't have anything relating to values over 10 converting to A-F as I've never dealt with these before. Any help is appreciated. Here's my runner class: public class Lab09i { public static void main( String args[] ) { TenToAny test = new TenToAny(234, 9); out.println(test); test.setNums(100, 2); out.println(test); test.setNums(10, 2); out.println(test); test.setNums(15, 2); out.println(test); test.setNums(256, 2); out.println(test); test.setNums(100, 8); out.println(test); test.setNums(250, 16); out.println(test); test.setNums(56, 11); out.println(test); test.setNums(89, 5); out.println(test); test.setNums(23, 3); out.println(test); test.setNums(50, 5); out.println(test); test.setNums(55, 6); out.println(test); test.setNums(2500, 6); out.println(test); test.setNums(2500, 13); out.println(test); } } this is what my results should be: 234 base 10 is 280 in base 9 100 base 10 is 1100100 in base 2 10 base 10 is 1010 in base 2 15 base 10 is 1111 in base 2 256 base 10 is 100000000 in base 2 100 base 10 is 144 in base 8 250 base 10 is FA in base 16 56 base 10 is 51 in base 11 89 base 10 is 324 in base 5 23 base 10 is 212 in base 3 50 base 10 is 302 in base 4 55 base 10 is 131 in base 6 2500 base 10 is 9C4 in base 16 2500 base 10 is 11A4 in base 13

    Read the article

  • How to force VS 2010 to skip "builds" of projects which haven't changed?

    - by Ladislav Mrnka
    Our product's solution has more than 100+ projects (500+ksloc of production code). Most of them are C# projects but we also have few using C++/CLI to bridge communication with native code. Rebuilding the whole solution takes several minutes. That's fine. If I want to rebuilt the solution I expect that it will really take some time. What is not fine is time needed to build solution after full rebuild. Imagine I used full rebuild and know without doing any changes to to the solution I press Build (F6 or Ctrl+Shift+B). Why it takes 35s if there was no change? In output I see that it started "building" of each project - it doesn't perform real build but it does something which consumes significant amount of time. That 35s delay is pain in the ass. Yes I can improve the time by not using build solution but only build project (Shift+F6). If I run build project on particular test project I'm currently working on it will take "only" 8+s. It requires me to run project build on correct project (the test project to ensure dependent tested code is build as well). At least ReSharper test runner correctly recognizes that only this single project must be build and rerunning test usually contains only 8+s compilation. My current coding Kata is: don't touch Ctrl+Shift+B. The test project build will take 8s even if I don't do any changes. The reason why it takes 8s is because it also "builds" dependencies = in my case it "builds" more than 20 projects but I made changes only to unit test or single dependency! I don't want it to touch other projects. Is there a way to simply tell VS to build only projects where some changes were done and projects which are dependent on changed ones (preferably this part as another build option)? I worry you will tell me that it is exactly what VS is doing but in MS way ... I want to improve my TDD experience and reduce the time of compilation (in TDD the compilation can happen twice per minute). To make this even more frustrated I'm working in a team where most of developers used to work on Java projects prior to joining this one. So you can imagine how they are pissed off when they must use VS in contrast to full incremental compilation in Java. I don't require incremental compilation of classes. I expect working incremental compilation of solutions. Especially in product like VS 2010 Ultimate which costs several thousands dollars. I really don't want to get answers like: Make a separate solution Unload projects you don't need etc. I can read those answers here. Those are not acceptable solutions. We're not paying for VS to do such compromises.

    Read the article

  • Multiplying matrices: error: expected primary-expression before 'struct'

    - by justin
    I am trying to write a program that is supposed to multiply matrices using threads. I am supposed to fill the matrices using random numbers in a thread. I am compiling in g++ and using PTHREADS. I have also created a struct to pass the data from my command line input to the thread so it can generate the matrix of random numbers. The sizes of the two matrices are also passed in the command line as well. I keep getting: main.cpp:7: error: expected primary-expression before 'struct' my code @ line 7 =: struct a{ int Arow; int Acol; int low; int high; }; My inpust are : Sizes of two matrices ( 4 arguments) high and low ranges in which o generate the random numbers between. Complete code: [headers] using namespace std; void *matrixACreate(struct *); void *status; int main(int argc, char * argv[]) { int Arow = atoi(argv[1]); // Matrix A int Acol = atoi(argv[2]); // WxX int Brow = atoi(argv[3]); // Matrix B int Bcol = atoi(argv[4]); // XxZ, int low = atoi(argv[5]); // Range low int high = atoi(argv[6]); struct a{ int Arow; // Matrix A int Acol; // WxX int low; // Range low int high; }; pthread_t matrixAthread; //pthread_t matrixBthread; pthread_t runner; int error, retValue; if (Acol != Brow) { cout << " This matrix cannot be multiplied. FAIL" << endl; return 0; } error = pthread_create(&matrixAthread, NULL, matrixACreate, struct *a); //error = pthread_create(&matrixAthread, NULL, matrixBCreate, sendB); retValue = pthread_join(matrixAthread, &status); //retValue = pthread_join(matrixBthread, &status); return 0; } void matrixACreate(struct * a) { struct a *data = (struct a *) malloc(sizeof(struct a)); data->Arow = Arow; data->Acol = Acol; data->low = low; data->high = high; int range = ((high - low) + 1); cout << Arow << endl<< Acol << endl; }// just trying to print to see if I am in the thread

    Read the article

  • Capistrano Error

    - by Casey van den Bergh
    I'm Running CentOS 5 32 bit version. This is my deploy.rb file on my local computer: #======================== #CONFIG #======================== set :application, "aeripets" set :scm, :git set :git_enable_submodules, 1 set :repository, "[email protected]:aeripets.git" set :branch, "master" set :ssh_options, { :forward_agent => true } set :stage, :production set :user, "root" set :use_sudo, false set :runner, "root" set :deploy_to, "/var/www/#{application}" set :app_server, :passenger set :domain, "aeripets.co.za" #======================== #ROLES #======================== role :app, domain role :web, domain role :db, domain, :primary => true #======================== #CUSTOM #======================== namespace :deploy do task :start, :roles => :app do run "touch #{current_release}/tmp/restart.txt" end task :stop, :roles => :app do # Do nothing. end desc "Restart Application" task :restart, :roles => :app do run "touch #{current_release}/tmp/restart.txt" end end And this the error I get on my local computer when I try to cap deploy. executing deploy' * executingdeploy:update' ** transaction: start * executing deploy:update_code' executing locally: "git ls-remote [email protected]:aeripets.git master" command finished in 1297ms * executing "git clone -q [email protected]:aeripets.git /var/www/seripets/releases/20111126013705 && cd /var/www/seripets/releases/20111126013705 && git checkout -q -b deploy 32ac552f57511b3ae9be1d58aec54d81f78f8376 && git submodule -q init && git submodule -q sync && export GIT_RECURSIVE=$([ ! \"git --version\" \\< \"git version 1.6.5\" ] && echo --recursive) && git submodule -q update --init $GIT_RECURSIVE && (echo 32ac552f57511b3ae9be1d58aec54d81f78f8376 > /var/www/seripets/releases/20111126013705/REVISION)" servers: ["aeripets.co.za"] Password: [aeripets.co.za] executing command ** [aeripets.co.za :: err] sh: git: command not found command finished in 224ms *** [deploy:update_code] rolling back * executing "rm -rf /var/www/seripets/releases/20111126013705; true" servers: ["aeripets.co.za"] [aeripets.co.za] executing command command finished in 238ms failed: "sh -c 'git clone -q [email protected]:aeripets.git /var/www/seripets/releases/20111126013705 && cd /var/www/seripets/releases/20111126013705 && git checkout -q -b deploy 32ac552f57511b3ae9be1d58aec54d81f78f8376 && git submodule -q init && git submodule -q sync && export GIT_RECURSIVE=$([ ! \"git --version`\" \< \"git version 1.6.5\" ] && echo --recursive) && git submodule -q update --init $GIT_RECURSIVE && (echo 32ac552f57511b3ae9be1d58aec54d81f78f8376 /var/www/seripets/releases/20111126013705/REVISION)'" on aeripets.co.za

    Read the article

  • The Product Owner

    - by Robert May
    In a previous post, I outlined the rules of Scrum.  This post details one of those rules. Picking a most important part of Scrum is difficult.  All of the rules are required, but if there were one rule that is “more” required that every other rule, its having a good Product Owner.  Simply put, the Product Owner can make or break the project. Duties of the Product Owner A Product Owner has many duties and responsibilities.  I’ll talk about each of these duties in detail below. A Product Owner: Discovers and records stories for the backlog. Prioritizes stories in the Product Backlog, Release Backlog and Iteration Backlog. Determines Release dates and Iteration Dates. Develops story details and helps the team understand those details. Helps QA to develop acceptance tests. Interact with the Customer to make sure that the product is meeting the customer’s needs. Discovers and Records Stories for the Backlog When I do Scrum, I always use User Stories as the means for capturing functionality that’s required in the system.  Some people will use Use Cases, but the same rule applies.  The Product Owner has the ultimate responsibility for figuring out what functionality will be in the system.  Many different mechanisms for capturing this input can be used.  User interviews are great, but all sources should be considered, including talking with Customer Support types.  Often, they hear what users are struggling with the most and are a great source for stories that can make the application easier to use. Care should be taken when soliciting user stories from technical types such as programmers and the people that manage them.  They will almost always give stories that are very technical in nature and may not have a direct benefit for the end user.  Stories are about adding value to the company.  If the stories don’t have direct benefit to the end user, the Product Owner should question whether or not the story should be implemented.  In general, technical stories should be included as tasks in User Stories.  Technical stories are often needed, but the ultimate value to the user is in user based functionality, so technical stories should be considered nothing more than overhead in providing that user functionality. Until the iteration prior to development, stories should be nothing more than short, one line placeholders. An exercise called Story Planning can be used to brainstorm and come up with stories.  I’ll save the description of this activity for another blog post. For more information on User Stories, please read the book User Stories Applied by Mike Cohn. Prioritizes Stories in the Product Backlog, Release Backlog and Iteration Backlog Prioritization of stories is one of the most difficult tasks that a Product Owner must do.  A key concept of Scrum done right is the need to have the team working from a single set of prioritized stories.  If the team does not have a single set of prioritized stories, Scrum will likely fail at your organization.  The Product Owner is the ONLY person who has the responsibility to prioritize that list.  The Product Owner must be very diplomatic and sincerely listen to the people around him so that he can get the priorities correct. Just listening will still not yield the proper priorities.  Care must also be taken to ensure that Return on Investment is also considered.  Ultimately, determining which stories give the most value to the company for the least cost is the most important factor in determining priorities.  Product Owners should be willing to look at cold, hard numbers to determine the order for stories.  Even when many people want a feature, if that features is costly to develop, it may not have as high of a return on investment as features that are cheaper, but not as popular. The act of prioritization often causes conflict in an environment.  Customer Service thinks that feature X is the most important, because it will stop people from calling.  Operations thinks that feature Y is the most important, because it will stop servers from crashing.  Developers think that feature Z is most important because it will make writing software much easier for them.  All of these are useful goals, but the team can have only one list of items, and each item must have a priority that is different from all other stories.  The Product Owner will determine which feature gives the best return on investment and the other features will have to wait their turn, which means that someone will not have their top priority feature implemented first. A weak Product Owner will refuse to do prioritization.  I’ve heard from multiple Product Owners the following phrase, “Well, it’s all got to be done, so what does it matter what order we do it in?”  If your product owner is using this phrase, you need a new Product Owner.  Order is VERY important.  In Scrum, every release is potentially shippable.  If the wrong priority items are developed, then the value added in each release isn’t what it should be.  Additionally, the Product Owner with this mindset doesn’t understand Agile.  A product is NEVER finished, until the company has decided that it is no longer a going concern and they are no longer going to sell the product.  Therefore, prioritization isn’t an event, its something that continues every day.  The logical extension of the phrase “It’s all got to be done” is that you will never ship your product, since a product is never “done.”  Once stories have been prioritized, assigning them to the Release Backlog and the Iteration Backlog becomes relatively simple.  The top priority items are copied into the respective backlogs in order and the task is complete.  The team does have the right to shuffle things around a little in the iteration backlog.  For example, they may determine that working on story C with story A is appropriate because they’re related, even though story B is technically a higher priority than story C.  Or they may decide that story B is too big to complete in the time available after Story A has tasks created, so they’ll work on Story C since it’s smaller.  They can’t, however, go deep into the backlog to pick stories to implement.  The team and the Product Owner should work together to determine what’s best for the company. Prioritization is time consuming, but its one of the most important things a Product Owner does. Determines Release Dates and Iteration Dates Product owners are responsible for determining release dates for a product.  A common misconception that Product Owners have is that every “release” needs to correspond with an actual release to customers.  This is not the case.  In general, releases should be no more than 3 months long.  You  may decide to release the product to the customers, and many companies do release the product to customers, but it may also be an internal release. If a release date is too far away, developers will fall into the trap of not feeling a sense of urgency.  The date is far enough away that they don’t need to give the release their full attention.  Additionally, important tasks, such as performance tuning, regression testing, user documentation, and release preparation, will not happen regularly, making them much more difficult and time consuming to do.  The more frequently you do these tasks, the easier they are to accomplish. The Product Owner will be a key participant in determining whether or not a release should be sent out to the customers.  The determination should be made on whether or not the features contained in the release are valuable enough  and complete enough that the customers will see real value in the release.  Often, some features will take more than three months to get them to a state where they qualify for a release or need additional supporting features to be released.  The product owner has the right to make this determination. In addition to release dates, the Product Owner also will help determine iteration dates.  In general, an iteration length should be chosen and the team should follow that iteration length for an extended period of time.  If the iteration length is changed every iteration, you’re not doing Scrum.  Iteration lengths help the team and company get into a rhythm of developing quality software.  Iterations should be somewhere between 2 and 4 weeks in length.  Any shorter, and significant software will likely not be developed.  Any longer, and the team won’t feel urgency and planning will become very difficult. Iterations may not be extended during the iteration.  Companies where Scrum isn’t really followed will often use this as a strategy to complete all stories.  They don’t want to face the harsh reality of what their true performance is, and looking good is more important than seeking visibility and improving the process and team.  Companies like this typically don’t allow failure.  This is unhealthy.  Failure is part of life and unless we learn from it, we can’t improve.  I would much rather see a team push out stories to the next iteration and then have healthy discussions about why they failed rather than extend the iteration and not deal with the core problems. If iteration length varies, retrospectives become more difficult.  For example, evaluating the performance of the team’s estimation efforts becomes much more difficult if the iteration length varies.  Also, the team must have a velocity measurement.  If the iteration length varies, measuring velocity becomes impossible and upper management no longer will have the ability to evaluate the teams performance.  People external to the team will no longer have the ability to determine when key features are likely to be developed.  Variable iterations cause the entire company to fail and likely cause Scrum to fail at an organization. Develops Story Details and Helps the Team Understand Those Details A key concept in Scrum is that the stories are nothing more than a placeholder for a conversation.  Stories should be nothing more than short, one line statements about the functionality.  The team will then converse with the Product Owner about the details about that story.  The product owner needs to have a very good idea about what the details of the story are and needs to be able to help the team understand those details. Too often, we see this requirement as being translated into the need for comprehensive documentation about the story, including old fashioned requirements documentation.  The team should only develop the documentation that is required and should not develop documentation that is only created because their is a process to do so. In general, what we see that works best is the iteration before a team starts development work on a story, the Product Owner, with other appropriate business analysts, will develop the details of that story.  They’ll figure out what business rules are required, potentially make paper prototypes or other light weight mock-ups, and they seek to understand the story and what is implied.  Note that the time allowed for this task is deliberately short.  The Product Owner only has a single iteration to develop all of the stories for the next iteration. If more than one iteration is used, I’ve found that teams will end up with Big Design Up Front and traditional requirements documents.  This is a waste of time, since the team will need to then have discussions with the Product Owner to figure out what the requirements document says.  Instead of this, skip making the pretty pictures and detailing the nuances of the requirements and build only what is minimally needed by the team to do development.  If something comes up during development, you can address it at that time and figure out what you want to do.  The goal is to keep things as light weight as possible so that everyone can move as quickly as possible. Helps QA to Develop Acceptance Tests In Scrum, no story can be counted until it is accepted by QA.  Because of this, acceptance tests are very important to the team.  In general, acceptance tests need to be developed prior to the iteration or at the very beginning of the iteration so that the team can make sure that the tasks that they develop will fulfill the acceptance criteria. The Product Owner will help the team, including QA, understand what will make the story acceptable.  Note that the Product Owner needs to be careful about specifying that the feature will work “Perfectly” at the end of the iteration.  In general, features are developed a little bit at a time, so only the bit that is being developed should be considered as necessary for acceptance. A weak Product Owner will make statements like “Do it right the first time.”  Not only are these statements damaging to the team (like they would try to do it WRONG the first time . . .), they’re also ignoring the iterative nature of Scrum.  Additionally, a weak product owner will seek to add scope in the acceptance testing.  For example, they will refuse to determine acceptance at the beginning of the iteration, and then, after the team has planned and committed to the iteration, they will expand scope by defining acceptance.  This often causes the team to miss the iteration because scope that wasn’t planned on is included.  There are ways that the team can mitigate this problem.  For example, include extra “Product Owner” time to deal with the uncertainty that you know will be introduced by the Product Owner.  This will slow the perceived velocity of the team and is not ideal, since they’ll be doing more work than they get credit for. Interact with the Customer to Make Sure that the Product is Meeting the Customer’s Needs Once development is complete, what the team has worked on should be put in front of real live people to see if it meets the needs of the customer.  One of the great things about Agile is that if something doesn’t work, we can revisit it in a future iteration!  This frees up the team to make the best decision now and know that if that decision proves to be incorrect, the team can revisit it and change that decision. Features are about adding value to the customer, so if the customer doesn’t find them useful, then having the team make tweaks is valuable.  In general, most software will be 80 to 90 percent “right” after the initial round and only minor tweaks are required.  If proper coding standards are followed, these tweaks are usually minor and easy to accomplish.  Product Owners that are doing a good job will encourage real users to see and use the software, since they know that they are trying to add value to the customer. Poor product owners will think that they know the answers already, that their customers are silly and do stupid things and that they don’t need customer input.  If you have a product owner that is afraid to show the team’s work to real customers, you probably need a different product owner. Up Next, “Who Makes a Good Product Owner.” Followed by, “Messing with the Team.” Technorati Tags: Scrum,Product Owner

    Read the article

  • Sorting Algorithms

    - by MarkPearl
    General Every time I go back to university I find myself wading through sorting algorithms and their implementation in C++. Up to now I haven’t really appreciated their true value. However as I discovered this last week with Dictionaries in C# – having a knowledge of some basic programming principles can greatly improve the performance of a system and make one think twice about how to tackle a problem. I’m going to cover briefly in this post the following: Selection Sort Insertion Sort Shellsort Quicksort Mergesort Heapsort (not complete) Selection Sort Array based selection sort is a simple approach to sorting an unsorted array. Simply put, it repeats two basic steps to achieve a sorted collection. It starts with a collection of data and repeatedly parses it, each time sorting out one element and reducing the size of the next iteration of parsed data by one. So the first iteration would go something like this… Go through the entire array of data and find the lowest value Place the value at the front of the array The second iteration would go something like this… Go through the array from position two (position one has already been sorted with the smallest value) and find the next lowest value in the array. Place the value at the second position in the array This process would be completed until the entire array had been sorted. A positive about selection sort is that it does not make many item movements. In fact, in a worst case scenario every items is only moved once. Selection sort is however a comparison intensive sort. If you had 10 items in a collection, just to parse the collection you would have 10+9+8+7+6+5+4+3+2=54 comparisons to sort regardless of how sorted the collection was to start with. If you think about it, if you applied selection sort to a collection already sorted, you would still perform relatively the same number of iterations as if it was not sorted at all. Many of the following algorithms try and reduce the number of comparisons if the list is already sorted – leaving one with a best case and worst case scenario for comparisons. Likewise different approaches have different levels of item movement. Depending on what is more expensive, one may give priority to one approach compared to another based on what is more expensive, a comparison or a item move. Insertion Sort Insertion sort tries to reduce the number of key comparisons it performs compared to selection sort by not “doing anything” if things are sorted. Assume you had an collection of numbers in the following order… 10 18 25 30 23 17 45 35 There are 8 elements in the list. If we were to start at the front of the list – 10 18 25 & 30 are already sorted. Element 5 (23) however is smaller than element 4 (30) and so needs to be repositioned. We do this by copying the value at element 5 to a temporary holder, and then begin shifting the elements before it up one. So… Element 5 would be copied to a temporary holder 10 18 25 30 23 17 45 35 – T 23 Element 4 would shift to Element 5 10 18 25 30 30 17 45 35 – T 23 Element 3 would shift to Element 4 10 18 25 25 30 17 45 35 – T 23 Element 2 (18) is smaller than the temporary holder so we put the temporary holder value into Element 3. 10 18 23 25 30 17 45 35 – T 23   We now have a sorted list up to element 6. And so we would repeat the same process by moving element 6 to a temporary value and then shifting everything up by one from element 2 to element 5. As you can see, one major setback for this technique is the shifting values up one – this is because up to now we have been considering the collection to be an array. If however the collection was a linked list, we would not need to shift values up, but merely remove the link from the unsorted value and “reinsert” it in a sorted position. Which would reduce the number of transactions performed on the collection. So.. Insertion sort seems to perform better than selection sort – however an implementation is slightly more complicated. This is typical with most sorting algorithms – generally, greater performance leads to greater complexity. Also, insertion sort performs better if a collection of data is already sorted. If for instance you were handed a sorted collection of size n, then only n number of comparisons would need to be performed to verify that it is sorted. It’s important to note that insertion sort (array based) performs a number item moves – every time an item is “out of place” several items before it get shifted up. Shellsort – Diminishing Increment Sort So up to now we have covered Selection Sort & Insertion Sort. Selection Sort makes many comparisons and insertion sort (with an array) has the potential of making many item movements. Shellsort is an approach that takes the normal insertion sort and tries to reduce the number of item movements. In Shellsort, elements in a collection are viewed as sub-collections of a particular size. Each sub-collection is sorted so that the elements that are far apart move closer to their final position. Suppose we had a collection of 15 elements… 10 20 15 45 36 48 7 60 18 50 2 19 43 30 55 First we may view the collection as 7 sub-collections and sort each sublist, lets say at intervals of 7 10 60 55 – 20 18 – 15 50 – 45 2 – 36 19 – 48 43 – 7 30 10 55 60 – 18 20 – 15 50 – 2 45 – 19 36 – 43 48 – 7 30 (Sorted) We then sort each sublist at a smaller inter – lets say 4 10 55 60 18 – 20 15 50 2 – 45 19 36 43 – 48 7 30 10 18 55 60 – 2 15 20 50 – 19 36 43 45 – 7 30 48 (Sorted) We then sort elements at a distance of 1 (i.e. we apply a normal insertion sort) 10 18 55 60 2 15 20 50 19 36 43 45 7 30 48 2 7 10 15 18 19 20 30 36 43 45 48 50 55 (Sorted) The important thing with shellsort is deciding on the increment sequence of each sub-collection. From what I can tell, there isn’t any definitive method and depending on the order of your elements, different increment sequences may perform better than others. There are however certain increment sequences that you may want to avoid. An even based increment sequence (e.g. 2 4 8 16 32 …) should typically be avoided because it does not allow for even elements to be compared with odd elements until the final sort phase – which in a way would negate many of the benefits of using sub-collections. The performance on the number of comparisons and item movements of Shellsort is hard to determine, however it is considered to be considerably better than the normal insertion sort. Quicksort Quicksort uses a divide and conquer approach to sort a collection of items. The collection is divided into two sub-collections – and the two sub-collections are sorted and combined into one list in such a way that the combined list is sorted. The algorithm is in general pseudo code below… Divide the collection into two sub-collections Quicksort the lower sub-collection Quicksort the upper sub-collection Combine the lower & upper sub-collection together As hinted at above, quicksort uses recursion in its implementation. The real trick with quicksort is to get the lower and upper sub-collections to be of equal size. The size of a sub-collection is determined by what value the pivot is. Once a pivot is determined, one would partition to sub-collections and then repeat the process on each sub collection until you reach the base case. With quicksort, the work is done when dividing the sub-collections into lower & upper collections. The actual combining of the lower & upper sub-collections at the end is relatively simple since every element in the lower sub-collection is smaller than the smallest element in the upper sub-collection. Mergesort With quicksort, the average-case complexity was O(nlog2n) however the worst case complexity was still O(N*N). Mergesort improves on quicksort by always having a complexity of O(nlog2n) regardless of the best or worst case. So how does it do this? Mergesort makes use of the divide and conquer approach to partition a collection into two sub-collections. It then sorts each sub-collection and combines the sorted sub-collections into one sorted collection. The general algorithm for mergesort is as follows… Divide the collection into two sub-collections Mergesort the first sub-collection Mergesort the second sub-collection Merge the first sub-collection and the second sub-collection As you can see.. it still pretty much looks like quicksort – so lets see where it differs… Firstly, mergesort differs from quicksort in how it partitions the sub-collections. Instead of having a pivot – merge sort partitions each sub-collection based on size so that the first and second sub-collection of relatively the same size. This dividing keeps getting repeated until the sub-collections are the size of a single element. If a sub-collection is one element in size – it is now sorted! So the trick is how do we put all these sub-collections together so that they maintain their sorted order. Sorted sub-collections are merged into a sorted collection by comparing the elements of the sub-collection and then adjusting the sorted collection. Lets have a look at a few examples… Assume 2 sub-collections with 1 element each 10 & 20 Compare the first element of the first sub-collection with the first element of the second sub-collection. Take the smallest of the two and place it as the first element in the sorted collection. In this scenario 10 is smaller than 20 so 10 is taken from sub-collection 1 leaving that sub-collection empty, which means by default the next smallest element is in sub-collection 2 (20). So the sorted collection would be 10 20 Lets assume 2 sub-collections with 2 elements each 10 20 & 15 19 So… again we would Compare 10 with 15 – 10 is the winner so we add it to our sorted collection (10) leaving us with 20 & 15 19 Compare 20 with 15 – 15 is the winner so we add it to our sorted collection (10 15) leaving us with 20 & 19 Compare 20 with 19 – 19 is the winner so we add it to our sorted collection (10 15 19) leaving us with 20 & _ 20 is by default the winner so our sorted collection is 10 15 19 20. Make sense? Heapsort (still needs to be completed) So by now I am tired of sorting algorithms and trying to remember why they were so important. I think every year I go through this stuff I wonder to myself why are we made to learn about selection sort and insertion sort if they are so bad – why didn’t we just skip to Mergesort & Quicksort. I guess the only explanation I have for this is that sometimes you learn things so that you can implement them in future – and other times you learn things so that you know it isn’t the best way of implementing things and that you don’t need to implement it in future. Anyhow… luckily this is going to be the last one of my sorts for today. The first step in heapsort is to convert a collection of data into a heap. After the data is converted into a heap, sorting begins… So what is the definition of a heap? If we have to convert a collection of data into a heap, how do we know when it is a heap and when it is not? The definition of a heap is as follows: A heap is a list in which each element contains a key, such that the key in the element at position k in the list is at least as large as the key in the element at position 2k +1 (if it exists) and 2k + 2 (if it exists). Does that make sense? At first glance I’m thinking what the heck??? But then after re-reading my notes I see that we are doing something different – up to now we have really looked at data as an array or sequential collection of data that we need to sort – a heap represents data in a slightly different way – although the data is stored in a sequential collection, for a sequential collection of data to be in a valid heap – it is “semi sorted”. Let me try and explain a bit further with an example… Example 1 of Potential Heap Data Assume we had a collection of numbers as follows 1[1] 2[2] 3[3] 4[4] 5[5] 6[6] For this to be a valid heap element with value of 1 at position [1] needs to be greater or equal to the element at position [3] (2k +1) and position [4] (2k +2). So in the above example, the collection of numbers is not in a valid heap. Example 2 of Potential Heap Data Lets look at another collection of numbers as follows 6[1] 5[2] 4[3] 3[4] 2[5] 1[6] Is this a valid heap? Well… element with the value 6 at position 1 must be greater or equal to the element at position [3] and position [4]. Is 6 > 4 and 6 > 3? Yes it is. Lets look at element 5 as position 2. It must be greater than the values at [4] & [5]. Is 5 > 3 and 5 > 2? Yes it is. If you continued to examine this second collection of data you would find that it is in a valid heap based on the definition of a heap.

    Read the article

  • Why do we get a sudden spike in response times?

    - by Christian Hagelid
    We have an API that is implemented using ServiceStack which is hosted in IIS. While performing load testing of the API we discovered that the response times are good but that they deteriorate rapidly as soon as we hit about 3,500 concurrent users per server. We have two servers and when hitting them with 7,000 users the average response times sit below 500ms for all endpoints. The boxes are behind a load balancer so we get 3,500 concurrents per server. However as soon as we increase the number of total concurrent users we see a significant increase in response times. Increasing the concurrent users to 5,000 per server gives us an average response time per endpoint of around 7 seconds. The memory and CPU on the servers are quite low, both while the response times are good and when after they deteriorate. At peak with 10,000 concurrent users the CPU averages just below 50% and the RAM sits around 3-4 GB out of 16. This leaves us thinking that we are hitting some kind of limit somewhere. The below screenshot shows some key counters in perfmon during a load test with a total of 10,000 concurrent users. The highlighted counter is requests/second. To the right of the screenshot you can see the requests per second graph becoming really erratic. This is the main indicator for slow response times. As soon as we see this pattern we notice slow response times in the load test. How do we go about troubleshooting this performance issue? We are trying to identify if this is a coding issue or a configuration issue. Are there any settings in web.config or IIS that could explain this behaviour? The application pool is running .NET v4.0 and the IIS version is 7.5. The only change we have made from the default settings is to update the application pool Queue Length value from 1,000 to 5,000. We have also added the following config settings to the Aspnet.config file: <system.web> <applicationPool maxConcurrentRequestsPerCPU="5000" maxConcurrentThreadsPerCPU="0" requestQueueLimit="5000" /> </system.web> More details: The purpose of the API is to combine data from various external sources and return as JSON. It is currently using an InMemory cache implementation to cache individual external calls at the data layer. The first request to a resource will fetch all data required and any subsequent requests for the same resource will get results from the cache. We have a 'cache runner' that is implemented as a background process that updates the information in the cache at certain set intervals. We have added locking around the code that fetches data from the external resources. We have also implemented the services to fetch the data from the external sources in an asynchronous fashion so that the endpoint should only be as slow as the slowest external call (unless we have data in the cache of course). This is done using the System.Threading.Tasks.Task class. Could we be hitting a limitation in terms of number of threads available to the process?

    Read the article

< Previous Page | 90 91 92 93 94 95 96 97 98 99 100 101  | Next Page >