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  • Twitter API with urllib2 in python

    - by Dirk Nachbar
    I want to use the Twitter API in Python to lookup user ids from name using the lookup method. I have done similar requests simply using response = urllib2.urlopen('http://search.twitter.com...') but for this one I need authentication. I don't think I can do it through the Google python twitter API because it doesn't have the lookup method. Any ideas how can I can auth with urllib2??

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  • Authorization error in facebook aplication

    - by bhaskaragr29
    require_login($required_permissions = 'email,photo_upload'); $auth= $facebook-do_get_session($_GET['auth_token']); $facebook-set_user($s['uid'], $s['session_key'], $s['expires'], $s['secret']) ? when ever i tries to login into my app it just refreshed and refresh with wih different auth_tokens. please help

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  • get JSON object attribute name

    - by Laurent Luce
    I know that I can retrieve "session" by using item.fields.name but what if I don't know in advance that the attribute is called "name". How can I retrieve the list of the attributes names in fields first. [ { "pk": 2, "model": "auth.group", "fields": { "name": "session" } } ]

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  • Digest authentication using LDAP only

    - by Elephant
    Is there a way to validate digest authentication using LDAP only? I.e. if I have the following request from a client (stealed from Wikipedia): GET /dir/index.html HTTP/1.0 Host: localhost Authorization: Digest username="Mufasa", realm="[email protected]", nonce="dcd98b7102dd2f0e8b11d0f600bfb0c093", uri="/dir/index.html", qop=auth, nc=00000001, cnonce="0a4f113b", response="6629fae49393a05397450978507c4ef1", opaque="5ccc069c403ebaf9f0171e9517f40e41" could I validate the user against LDAP, meaning if I don't now user password hence is not able to construct a digest hash to compare with the response?

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  • Django context processor gets AnonymousUser

    - by myfreeweb
    instead of User. def myview(request): return render_to_response('tmpl.html', {'user': User.objects.get(id=1}) works fine and passes User to template. But def myview(request): return render_to_response('tmpl.html', {}, context_instance=RequestContext(request)) with a context processor def user(request): from django.contrib.auth.models import User return {'user': User.objects.get(id=1)} passes AnonymousUser, so I can't get the variables I need :( What's wrong?

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  • create hgrc file for all paths on a machine

    - by noam
    I want to create a hgrc file to set the username and password for all paths on some machine, e.g no matter in which directory I am in, hg clone some_path will always work without prompting for a username and a password (this is for an auto-deploy script). I followed the instructions and created a file: /etc/mercurial/hgrc.d/deploy.rc it's contents: [auth] default.prefix= http://myrepo default.username = myuname default.password = pwd But when I do hg clone some_path I get abort: error: Connection refused. What Am i doing wrong?

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  • Android String.equals doesn't work when I trying to match from httpresponse

    - by user469652
    RestClient.post("auth/login/", loginparam, new AsyncHttpResponseHandler() { @Override public void onSuccess(String s) { Toast.makeText(getApplicationContext(), String.valueOf(s.toLowerCase().equals("ok")), Toast.LENGTH_LONG).show(); if (s.equals("ok")) { startActivity(new Intent(getApplication(), HomeActivity.class)); } } }); This is the code I used for login in android app, In the Toast text, I can see the server did returned "ok", but s.equals always failed in my case, can someone explain that? Thank you.

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  • How to protect an ASP Classic Page?

    - by SH
    How can I protect an ASP Classic page with either HTTP AUTH (you must provide a username and password to service) or a randomly generated access key that will be included as one of the parameters of the HTTP POST using the variable name access_key. Can anybody provide asp classic code in this regard? Quick help will be appreciated... PS: OrderGroove is a 3rd party service... neglect it.

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  • authlogic rails question - how to code for an API

    - by phil swenson
    I have authlogic going on my app, but now I need to have an an API. I don't want to establish a session, just want a user to send in data in a json request such as: {"type":"address","password":"mypassword","name":"my notificaiton name goes here","user":"myusername","text":"my interesting stuff goes here"} So questions - 1) is this a decent approach? 2) how do i do the auth inside my rails controller?

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  • Twitter + Grackle, determining the logged in user

    - by JP
    This is crazy, but I'm stumped! Once my user has logged into twitter via OAuth how do I determine their username using grackle? @twitter = Grackle::Client.new(:auth => { :type => :oauth, :consumer_key => consumer_key, :consumer_secret => consumer_secret, :token => @access_token.token, :token_secret => @access_token.secret }) username = @twitte.something_here?

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  • What is the best way to go about obscuring Java code?

    - by Waltzy
    Well, I'm planning on releasing a Jar into the world but would prefer if the code was not readably available to anyone with a Java Decompiler as I want to control access to the program with usernames / auth codes etc. After some Googling I haven't found any software to do this for me, so I was wondering what steps to take from here; if anyone can point me at any software or information on methodologies of obscurification I would be grateful. Cheers again Stack Overflow.

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  • How to stop Django "app not found" error?

    - by cml
    When I run python ./manage.py sql grading my django site comes up with: Error: App with label grading could not be found. Are you sure you INSTALLED_APPS setting is correct? I have the app grading with __init__.py and everything, and my INSTALLED APPS is: INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.admin', 'teachline.courses', 'teachline.grading', ) Why isn't this working?

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  • Extract Data from a Website using PHP

    - by 01jayss
    I am trying to get PHP to extract the TOKEN (the uppercase one), USERID (uppercase), and the USER NAME (uppercase) from a web page with the following text. {"rsp":{"stat":"ok","auth":{"token":"**TOKEN**","perms":"read","user":{"id":"**USERID**","username":"**USER NAME**","fullname":"**NAME OF USER**"}}}} (This is from the RTM api, getting the authentication token of the user). How would I go about doing this? Thanks!

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  • Web service security not working. Java

    - by Nitesh Panchal
    Hello, I have a ejb module which contains my ejbs as well as web services. I am using Netbeans 6.8 and Glassfish V3 I right clicked on my web service and clicked "edit web service attributes" and then checked "secure service" and then selected keystore of my server. This is my sun-ejb-jar.xml file :- <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE sun-ejb-jar PUBLIC "-//Sun Microsystems, Inc.//DTD Application Server 9.0 Servlet 2.5//EN" "http://www.sun.com/software/appserver/dtds/sun-web-app_2_5-0.dtd"> <sun-ejb-jar> <security-role-mapping> <role-name>Admin</role-name> <group-name>Admin</group-name> </security-role-mapping> <security-role-mapping> <role-name>General</role-name> <group-name>General</group-name> </security-role-mapping> <security-role-mapping> <role-name>Member</role-name> <group-name>Member</group-name> </security-role-mapping> <enterprise-beans> <ejb> <ejb-name>MemberBean</ejb-name> <webservice-endpoint> <port-component-name>wsMember</port-component-name> <login-config> <auth-method>BASIC</auth-method> <realm>file</realm> </login-config> </webservice-endpoint> </ejb> </enterprise-beans> </sun-ejb-jar> Here MemberBean is my ejb and wsMember is my webservice. Then i made another project and added web service client and again right clicked on "edit web service attributes" and gave password as test and test. This username and password (test) is in Glassfish server in file realm. But when i try to invoke my webservice i always get SEC5046: Audit: Authentication refused for [test]. SEC1201: Login failed for user: test What am i doing wrong? Am i missing something?

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  • sending data from appcontroller to default.ctp - CakePHP

    - by Astral Projection Forum
    I want to send the below data to default.ctp, I want to display menus in all the pages, I'm using Auth, The problem is if I'm logged in I get the Menus correctly, but if I logout, I'm getting error saying variable'$topMenu' not found. The MenuController can be accessed only if logged in. $this->loadModel('Menu'); $this->set('topMenu',$this->Menu->find('all')); Any help on how to solve this?

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  • How to project an ASP Classic Page?

    - by SH
    How to project an ASP Classic page with either HTTP AUTH (you must provide a username and password to OrderGroove) or a randomly generated access key that will be included as one of the parameters of the HTTP POST using the variable name access_key. Can anybody provide asp classic code in this regard? Quick help will be appreciated...

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  • How can I access the "through" object of a Django ManyToManyField?

    - by Macha
    I have the following models in my Django app. How can I from the Team model find all the User objects who have accepted as True in the Membership model? I know I need to use Team.objects.filter(), but I'm not sure how to check the value of the accepted field. from django.contrib.auth.models import User class Team(models.Model): members = models.ManyToManyField(User, through="Membership") class Membership(models.Model): user = models.ForeignKey(User) team = models.ForeignKey(Team) accepted = models.BooleanField(default=False)

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  • spring-security and jsf

    - by Mike
    Hi! i am developing in JSF a Spring Security application. the login form is fine. however, when i try to retrieve the authentication object, in future code, i always get the authentication pricipal as anonymous. i try to fetch is like this: Authentication auth = SecurityContextHolder.getContext().getAuthentication();

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