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• jQuery plugin Tablesorter 2.0 behaves weird

  - by gunther-von-goetzen-sanchez

  I downloaded the jQuery plugin Tablesorter 2.0 from http://tablesorter.com/jquery.tablesorter.zip and modified the example-pager.html which is in tablesorter/docs directory I wrote additional Rollover effects: $(function() { $("table") .tablesorter({widthFixed: true, widgets: ['zebra']}) .tablesorterPager({container: $("#pager")}); /** Additional code */ $("tr").mouseover(function () { $(this).addClass('over'); }); $("tr").mouseout(function () { $(this).removeClass('over'); }); $("tr").click(function () { $(this).addClass('marked'); }); $("tr").dblclick(function () { $(this).removeClass('marked'); }); /** Additional code END */ }); And of course modified the themes/blue/style.css file: /* Additional code */ table.tablesorter tbody tr.odd td { background-color: #D1D1F0; } table.tablesorter tbody tr.even td { background-color: #EFDEDE; } table.tablesorter tbody tr.over td { background-color: #FBCA33; } table.tablesorter tbody tr.marked td { background-color: #FB4133; } /* Additional code END*/ All this works fine BUT when I go to further pages i.e. page 2 3 or 4 the effects are gone! I really appreciate your help

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• Javascript: prototypal inheritance and the prototype property

  - by JanD

  Hi, I have a simple code fragment in JS working with prototype inheritance. function object(o) { function F() {} F.prototype = o; return new F(); } //the following code block has a alternate version var mammal = { color: "brown", getColor: function() { return this.color; } } var myCat = object(mammal); myCat.meow = function(){return "meow";} that worked fine but adding this: mammal.prototype.kindOf = "predator"; does not. ("mammal.prototype is undefined") Since I guessed that object maybe have no prototype I rewrote it, replacing the var mammal={... block with: function mammal() { this.color = "brown"; this.getColor = function() { return this.color; } } which gave me a bunch of other errors: "Function.prototype.toString called on incompatible object" and if I try to call _myCat.getColor() "myCat.getColor is not a function" Now I am totally confused. After reading Crockford, and Flanagan I did not get the solution for the errors. So it would be great if somebody knows... - why is the prototype undefined in the first example (which is foremost concern; I thought the prototype of explicitly set in the object() function) - why get I these strange errors trying to use the mammal function as prototype object in the object() function? Edit by the Creator of the Question: These two links helped a lot too: Prototypes_in_JavaScript on the spheredev wiki explains the way the prototype property works relativily simple. What it lacks is some try-out code examples. Some good examples are provided by Morris John's Article. I personally find the explanations are not that easy as in the first link, but still very good. The most difficult part even after I actually got it is really not to confuse the .prototype propery with the internal [[Prototype]] of an object.

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• .NET RichTextBox: unable to change Rtf property.

  - by Dave

  Hey guys, Perhaps I'm missing something real simple here, but I've been struggling to change the RTF property of my RichTextBox in order to apply some color coding to my text. Probably the most straight-forward example of the problem I'm having is setting the Rtf property to include a color table in its header. The default RTF string returned by the Rtf property: {\rtf1\ansi\ansicpg1252\deff0\deflang1033{\fonttbl{\f0\fnil\fcharset0 Microsoft Sans Serif;}}\viewkind4\uc1\pard\f0\fs17\par} And the new RTF string I'd like to set with my color table: {\rtf1\ansi\ansicpg1252\deff0\deflang1033{\fonttbl{\f0\fnil\fcharset0 Microsoft Sans Serif;}{\colortbl;\red128\green0\blue0;\red0\green128\blue0;\red0\green0\blue255;}}\viewkind4\uc1\pard\f0\fs17\par} And I set this using: RichTextBox richTextBox = new RichTextBox(); richTextBox.Rtf = rtfStr; // My new RTF string, as seen above. However, via debugger, it can be observed the that Rtf property stubbornly refuses to change; no exceptions are thrown, it just refuses to change. Same issue happens when I string.Replace() words to include RTF color tags around them. I've also tried turning off any ReadOnly properties on the text box. Any suggestions would be most helpful, thanks! Dave

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• Silverlight: Binding a child controls property to a property in a user control

  - by Jeremy

  If I have a user control defined: public partial class MainFooter : UserControl { public System.Windows.Media.Color BkColor; } and it's xaml: <UserControl x:Class="Test.MainFooter"> <Grid x:Name="LayoutRoot"> <Rectangle x:Name="rctBottom_Background2" HorizontalAlignment="Stretch" Grid.Row="2"> <Rectangle.Fill> <LinearGradientBrush EndPoint="0.82,0.895" StartPoint="0.911,-0.442"> <GradientStop Color="{**How can I bind this to the BkColor property?}"/**> <GradientStop Color="#00FFFFFF" Offset="1"/> </LinearGradientBrush> </Rectangle.Fill> </Rectangle> </Grid> </UserControl> and used: <MyControls:MainFooter x:Name="rcrMainFooter" BkColor="#FFE2B42A"> </MyControls:MainFooter> How would I go about binding the GradientStop Color in the Rectangle to the value of the it's user controls BkColor property?

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• Problems with jQuery plugin Tablesorter 2.0

  - by gunther-von-goetzen-sanchez

  I downloaded the jQuery plugin Tablesorter 2.0 from http://tablesorter.com/jquery.tablesorter.zip and modified the example-pager.html which is in tablesorter/docs directory I wrote additional Rollover effects: $(function() { $("table") .tablesorter({widthFixed: true, widgets: ['zebra']}) .tablesorterPager({container: $("#pager")}); $("tr").mouseover(function () { $(this).addClass('over'); }); $("tr").mouseout(function () { $(this).removeClass('over'); }); $("tr").click(function () { $(this).addClass('marked'); }); $("tr").dblclick(function () { $(this).removeClass('marked'); }); }); And of course modified the themes/blue/style.css file: /* Additional code */ table.tablesorter tbody tr.odd td { background-color: #D1D1F0; } table.tablesorter tbody tr.even td { background-color: #EFDEDE; } table.tablesorter tbody tr.over td { background-color: #FBCA33; } table.tablesorter tbody tr.marked td { background-color: #FB4133; } /* Additional code END*/ All this works fine BUT when I go to further pages i.e. page 2 3 or 4 the effects are gone! I really appreciate your help

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• Why is graphviz drawing two arrows, and using a weird order?

  - by dmd

  Why is graphviz drawing two arrows from uncap_spike to peel, and why is it drawing peel to the right of hang? I want uncap_spike - peel - hang - spike, in that order, with one edge between each. digraph hangers { compound=true fontname="Gill Sans" node [fontname="Gill Sans" shape=box fillcolor=white style="rounded, filled"] edge [fontname="Gill Sans"] subgraph cluster_prep { style="filled" label=Prep gather [shape=Mrecord label="{gather | EtOH swab\nvented tubing}"] uncap_bottle [label="uncap bottle"] uncap_spike [label="uncap spike"] swab [shape=Mrecord label="{swab EtOH | wait 30 seconds for sterility}"] gather -> uncap_bottle -> swab -> uncap_spike {rank=same gather uncap_bottle swab uncap_spike} } subgraph cluster_hang { style=filled label=Hang {rank=same peel hang} } {rank=same uncap_spike -> peel -> hang -> spike -> prime} hang -> rip [color=firebrick] rip [label="eyelet\nripped" style="filled" shape=octagon regular fontcolor=white fontsize=10 width=.5 fixedsize color=firebrick fillcolor=firebrick ] swab -> not_sterile [color=firebrick] not_sterile [label="not\nsterile" style="filled" shape=octagon regular fontcolor=white fontsize=10 width=.5 fixedsize color=firebrick fillcolor=firebrick ] }

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• CSS buttons and crossbrowser issue

  - by Jason

  I have a class 'button' that I want to use for button, input and a tags. The problem is that both button and input tags have a greater line height than the anchor tag does. I have attached an example here so you can play around with it in firebug or whatever. http://28dev.com/stackoverflow/css-buttons.html But for those who just want to see the css/html, here it is: .button { font-family : helvetica, arial, sans-serif; -moz-border-radius: 3px; -webkit-border-radius: 3px; background : url(/images/ui-bg_glass_75_e6e6e6_1x400.png) repeat-x scroll 50% 50% #E6E6E6; border-color : #636363 #888888 #888888 #636363; border-right : 1px solid #888888; border-style : solid; border-width : 1px; cursor : pointer; display : block; float : left; font-size : 12px; font-weight : normal; line-height : 100%; min-width : 100px; padding : 3px 12px; text-align : center; } .button, .button a { color : #282828; text-decoration : none; } .button:hover, .button:hover a { border-color : #343434; color : #080808; } .marginR { margin-right : 5px; } <button class='button marginR' type='submit'>button.button</button> <input type="submit" value="input.button" class="button marginR" /> <a class="button" href="">a.button</a>

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• Following code overflows my browser window

  - by oneat

  Why following HTML (CSS) code: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title></title> </head> <body> <style type="text/css"> *{margin:0px 0px 0px 0px; padding:0px 0px 0px 0px;} div#header{width:100%;height:10%;min-width:100px;height:30%;background-color:red;} div#left_bar{width:20%;height:85%;float:left;background-color:green;} div#content{width:80%;height:85%;float:left;background-color:yellow;} div#foot{width:100%;height:5%;clear:both;background-color:black;} </style> <div id="header">a</div> <div id="left_bar">s</div> <div id="content">d</div> <div id="foot">f</div> </body> </html> Fails to fill my browser's (firefox 3.6.13 linux) window? I mean that I have to scroll down to see bottom. Any ideas?

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• Help to resolve 'Out of memory' exception when calling DrawImage

  - by Jack Juiceson

  Hi guys, About one percent of our users experience sudden crash while using our application. The logs show below exception, the only thing in common that I've seen so far is that, they all have XP SP3. Thanks in advance Out of memory. at System.Drawing.Graphics.CheckErrorStatus(Int32 status) at System.Drawing.Graphics.DrawImage(Image image, Rectangle destRect, Int32 srcX, Int32 srcY, Int32 srcWidth, Int32 srcHeight, GraphicsUnit srcUnit, ImageAttributes imageAttrs, DrawImageAbort callback, IntPtr callbackData) at System.Drawing.Graphics.DrawImage(Image image, Rectangle destRect, Int32 srcX, Int32 srcY, Int32 srcWidth, Int32 srcHeight, GraphicsUnit srcUnit, ImageAttributes imageAttr, DrawImageAbort callback) at System.Drawing.Graphics.DrawImage(Image image, Rectangle destRect, Int32 srcX, Int32 srcY, Int32 srcWidth, Int32 srcHeight, GraphicsUnit srcUnit, ImageAttributes imageAttr) at System.Windows.Forms.ControlPaint.DrawBackgroundImage(Graphics g, Image backgroundImage, Color backColor, ImageLayout backgroundImageLayout, Rectangle bounds, Rectangle clipRect, Point scrollOffset, RightToLeft rightToLeft) at System.Windows.Forms.Control.PaintBackground(PaintEventArgs e, Rectangle rectangle, Color backColor, Point scrollOffset) at System.Windows.Forms.Control.PaintBackground(PaintEventArgs e, Rectangle rectangle) at System.Windows.Forms.Control.OnPaintBackground(PaintEventArgs pevent) at System.Windows.Forms.ScrollableControl.OnPaintBackground(PaintEventArgs e) at System.Windows.Forms.Control.PaintTransparentBackground(PaintEventArgs e, Rectangle rectangle, Region transparentRegion) at System.Windows.Forms.Control.PaintBackground(PaintEventArgs e, Rectangle rectangle, Color backColor, Point scrollOffset) at System.Windows.Forms.Control.PaintBackground(PaintEventArgs e, Rectangle rectangle) at System.Windows.Forms.Control.OnPaintBackground(PaintEventArgs pevent) at System.Windows.Forms.ScrollableControl.OnPaintBackground(PaintEventArgs e) at System.Windows.Forms.Control.PaintTransparentBackground(PaintEventArgs e, Rectangle rectangle, Region transparentRegion) at System.Windows.Forms.Control.PaintBackground(PaintEventArgs e, Rectangle rectangle, Color backColor, Point scrollOffset) at System.Windows.Forms.Control.PaintBackground(PaintEventArgs e, Rectangle rectangle) at System.Windows.Forms.Control.OnPaintBackground(PaintEventArgs pevent) at System.Windows.Forms.Control.PaintWithErrorHandling(PaintEventArgs e, Int16 layer, Boolean disposeEventArgs) at System.Windows.Forms.Control.WmPaint(Message& m) at System.Windows.Forms.Control.WndProc(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m) at System.Windows.Forms.NativeWindow.Callback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam) Operation System Information ---------------------------- Name = Windows XP Edition = Home Service Pack = Service Pack 3 Version = 5.1.2600.196608 Bits = 32

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• How can I fetch Google static maps with TIdHTTP?

  - by cloudstrif3

  I'm trying to return content from maps.google.com from within Delphi 2006 using the TIdHTTP component. My code is as follows procedure TForm1.GetGoogleMap(); var t_GetRequest: String; t_Source: TStringList; t_Stream: TMemoryStream; begin t_Source := TStringList.Create; try t_Stream := TMemoryStream.Create; try t_GetRequest := 'http://maps.google.com/maps/api/staticmap?' + 'center=Brooklyn+Bridge,New+York,NY' + '&zoom=14' + '&size=512x512' + '&maptype=roadmap' + '&markers=color:blue|label:S|40.702147,-74.015794' + '&markers=color:green|label:G|40.711614,-74.012318' + '&markers=color:red|color:red|label:C|40.718217,-73.998284' + '&sensor=false'; IdHTTP1.Post(t_GetRequest, t_Source, t_Stream); t_Stream.SaveToFile('google.html'); finally t_Stream.Free; end; finally t_Source.Free; end; end; However I keep getting the response HTTP/1.0 403 Forbidden. I assume this means that I don't have permission to make this request but if I copy the url into my web browser IE 8, it works fine. Is there some header information that I need or something else?

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• Question about creating device-compatible bitmaps in C#

  - by MusiGenesis

  I am storing bitmap-like data in a two-dimensional int array. To convert this array into a GDI-compatible bitmap (for use with BitBlt), I am using this function: public IntPtr GetGDIBitmap(int[,] data) { int w = data.GetLength(0); int h = data.GetLength(1); IntPtr ret = IntPtr.Zero; using (Bitmap bmp = new Bitmap(w, h)) { for (int x = 0; x < w; x++) { for (int y = 0; y < h; y++) { Color color = Color.FromArgb(data[x, y]); bmp.SetPixel(x, y, color); } } ret = bmp.GetHbitmap(); } return ret; } This works as expected, but the call to bmp.GetHbitmap() has to allocate memory for the returned bitmap. I'd like to modify this method in two (probably related) ways: I'd like to remove the intermediate Bitmap from the above code entirely, and go directly from my int[,] array to the device-compatible bitmap (i.e. the IntPtr). I presume this would involve calling CreateCompatibleBitmap, but I don't know how to go from that call to actually manipulating the pixel values. This should logically follow from the answer to the first, but I'd also like my method to re-use existing GDI bitmap handles (instead of creating a new bitmap each time). How can I do this? NOTE: I don't really use Bitmap.SetPixel(), as its performance could best be described as "glacial". The code is just for illustration.

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• How to include frameset under CGI.pm

  - by neversaint

  I want to have a cgi-script that does two things. Take the input from a form. Generate results base on the input values on a frame. Primarily I want the frame exist only after the results is generated/printed. Below is the simplified code of what I want to do. But somehow it doesn't work. What's the right way to do it? #!/usr/local/bin/perl use CGI ':standard'; print header; print start_html('A Simple Example'), h1('A Simple Example'), start_form, "What's your name? ",textfield('name'), p, "What's the combination?", p, checkbox_group(-name=>'words', -values=>['eenie','meenie','minie','moe'], -defaults=>['eenie','minie']), p, "What's your favorite color? ", popup_menu(-name=>'color', -values=>['red','green','blue','chartreuse']), p, submit, end_form, hr; if (param()) { # begin create the frame print <<EOF; <html><head><title>$TITLE</title></head> <frameset rows="10,90"> <frame src="$script_name/query" name="query"> <frame src="$script_name/response" name="response"> </frameset> EOF # Finish creating frame print "Your name is: ",em(param('name')), p, "The keywords are: ",em(join(", ",param('words'))), p, "Your favorite color is: ",em(param('color')), hr; } print end_html;

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• Silverlight graphics pixel side position?

  - by Tuukka

  I try to port simple game to silverlight (SameGame). The problem is that my old source code used pixel sizes to allight game marks to board. I draw simple grid using lines and game mark (using rectangle). How i can set rentacle position correctly? Example 20 20 pixels to upper left corner). private void DrawGrid() { LayoutRoot.Children.Clear(); Rectangle r = new Rectangle(); r.Width = 20; r.Height = 20; r.Fill = new SolidColorBrush(Color.FromArgb(255, 0, 255, 0)); r.Stroke = new SolidColorBrush(Color.FromArgb(255, 0, 255, 0)); r.SetValue(Canvas.LeftProperty, (double)0); r.SetValue(Canvas.TopProperty, (double)0); LayoutRoot.Children.Add(r); Color GridColor = Color.FromArgb(0xFF, 0x00, 0x00, 0x00); for (int y = 0; y < 11; y++) { Line l = new Line(); l.X1 = 0; l.Y1 = 30 * y - 1; l.X2 = 20 * 30; l.Y2 = 30 * y - 1; l.Stroke = new SolidColorBrush(GridColor); l.StrokeThickness = 1; LayoutRoot.Children.Add(l); } for (int x = 0; x < 21; x++) { Line l = new Line(); l.X1 = 30 * x; l.Y1 = 0; l.X2 = 30 * x; l.Y2 = 10 * 30; l.Stroke = new SolidColorBrush(GridColor); l.StrokeThickness = 1; LayoutRoot.Children.Add(l); } }

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• please convert this PHP code in ruby

  - by Arpit Vaishnav

  <?php // amcharts.com export to image utility // set image type (gif/png/jpeg) $imgtype = 'jpeg'; // set image quality (from 0 to 100, not applicable to gif) $imgquality = 100; // get data from $_POST or $_GET ? $data = &$_POST; // get image dimensions $width = (int) $data['width']; $height = (int) $data['height']; // create image object $img = imagecreatetruecolor($width, $height); // populate image with pixels for ($y = 0; $y < $height; $y++) { // innitialize $x = 0; // get row data $row = explode(',', $data['r'.$y]); // place row pixels $cnt = sizeof($row); for ($r = 0; $r < $cnt; $r++) { // get pixel(s) data $pixel = explode(':', $row[$r]); // get color $pixel[0] = str_pad($pixel[0], 6, '0', STR_PAD_LEFT); $cr = hexdec(substr($pixel[0], 0, 2)); $cg = hexdec(substr($pixel[0], 2, 2)); $cb = hexdec(substr($pixel[0], 4, 2)); // allocate color $color = imagecolorallocate($img, $cr, $cg, $cb); // place repeating pixels $repeat = isset($pixel[1]) ? (int) $pixel[1] : 1; for ($c = 0; $c < $repeat; $c++) { // place pixel imagesetpixel($img, $x, $y, $color); // iterate column $x++; } } } // set proper content type header('Content-type: image/'.$imgtype); header('Content-Disposition: attachment; filename="chart.'.$imgtype.'"'); // stream image $function = 'image'.$imgtype; if ($imgtype == 'gif') { $function($img); } else { $function($img, null, $imgquality); } // destroy imagedestroy($img); ?

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• CSS renders Input in firefox mac vs firefox PC. can i detect os via javascript? or maybe a CSS hack

  - by adardesign

  I have a input[type="text"] the that has padding applied to it behaves differently in firefox PC then on a mac. Any hacks that can target firefox PC? These styles are what its seen on firefox PC firebug .searchContainer input { border-color:#7C7C7C #C3C3C3 #DDDDDD; border-style:solid; border-width:1px; color:#555555; float:left; height:12px; padding:3px; } These styles are what its seen on firefox PC firebug .searchContainer input { border-color:#7C7C7C #C3C3C3 #DDDDDD; border-style:solid; border-width:1px; color:#555555; float:left; height:12px; padding:3px; } No other styles are applied to these inputs. Here is a snapshot of FF PC http://tinyurl.com/2wdxmq5 Here is a snapshot of FF mac http://tinyurl.com/2u7f2nl any suggestions?

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• Jquery Tabs Help

  - by Jacinto

  So I am trying to make a tabs in a menu but cant make the whole width of each of the tabs 219px. it only allows me to make the li 219 but I wanna make the li a 219px. I cant seem to figure it out. Also is there a way to make a next button or would the best way to go to each tab and literally put in the next tab in a type of way? any help would be greatly appreciated Css .servicesNavigation li { float: left; list-style: none; width: 219px; } ul.servicesNavigation li a { padding: 3px 5px; background-color: #ccc; color: #000; text-decoration: none; width: 219px; } ul.servicesNavigation li a.selected, ul.tabNavigation li a:hover { background-color: #333; color: #fff; padding-top: 7px; } ul.servicesNavigation li a:focus { outline: 0; } HTML <ul class="servicesNavigation"> <li><a href="#Web">Web</a></li> <li><a href="#Print">Print</a></li> <li><a href="#DynamicContent">Dynamic Content</a></li> <li><a href="#Hosting">Hosting</a></li> </ul> Jquery var tabContainers = $('div.servicesInfo > div'); tabContainers.hide().filter(':first').show(); $('div.servicesInfo ul.servicesNavigation a').click(function () { tabContainers.hide(); tabContainers.filter(this.hash).show(); $('div.servicesInfo ul.servicesNavigation a').removeClass('selected'); $(this).addClass('selected'); return false; }).filter(':first').click();

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• How to modulate every texture unit in OpenGL ES 1.1?

  - by Jesse Beder

  I have two textures and a "blend factor", and I'd like to mix them, modulated by the current color; in effect, I want to use the following shader: gl_FragColor = gl_Color * mix(tex0, tex1, blendFactor); I'm using OpenGL ES 1.1, targeting all versions of the iPhone, so I can't use shaders, and I have two texture units. My best attempt is: // texture 0 glActiveTexture(GL_TEXTURE0); image1.Bind(); glTexEnvi(GL_TEXTURE_ENV, GL_TEXTURE_ENV_MODE, GL_MODULATE); // texture 1 glActiveTexture(GL_TEXTURE1); image2.Bind(); glTexEnvi(GL_TEXTURE_ENV, GL_TEXTURE_ENV_MODE, GL_COMBINE); glTexEnvi(GL_TEXTURE_ENV, GL_COMBINE_RGB, GL_INTERPOLATE); glTexEnvi(GL_TEXTURE_ENV, GL_SRC0_RGB, GL_PREVIOUS); glTexEnvi(GL_TEXTURE_ENV, GL_OPERAND0_RGB, GL_SRC_COLOR); glTexEnvi(GL_TEXTURE_ENV, GL_SRC1_RGB, GL_TEXTURE); glTexEnvi(GL_TEXTURE_ENV, GL_OPERAND1_RGB, GL_SRC_COLOR); glTexEnvi(GL_TEXTURE_ENV, GL_SRC2_RGB, GL_CONSTANT); glTexEnvi(GL_TEXTURE_ENV, GL_OPERAND2_RGB, GL_SRC_ALPHA); glTexEnvi(GL_TEXTURE_ENV, GL_COMBINE_ALPHA, GL_INTERPOLATE); glTexEnvi(GL_TEXTURE_ENV, GL_SRC0_ALPHA, GL_PREVIOUS); glTexEnvi(GL_TEXTURE_ENV, GL_OPERAND0_ALPHA, GL_SRC_ALPHA); glTexEnvi(GL_TEXTURE_ENV, GL_SRC1_ALPHA, GL_TEXTURE); glTexEnvi(GL_TEXTURE_ENV, GL_OPERAND1_ALPHA, GL_SRC_ALPHA); glTexEnvi(GL_TEXTURE_ENV, GL_SRC2_ALPHA, GL_CONSTANT); glTexEnvi(GL_TEXTURE_ENV, GL_OPERAND2_ALPHA, GL_SRC_ALPHA); const float factor[] = { 0, 0, 0, blendFactor }; glTexEnvfv(GL_TEXTURE_ENV, GL_TEXTURE_ENV_COLOR, factor); This has the effect of the shader: gl_FragColor = mix(gl_Color * tex0, tex1, blendFactor); but I don't see how to module texture 1 by the color. Is there any way to have the color provided by a texture unit automatically modulated by the incoming primary color? Or any other way to do what I want that I'm missing? Multiple passes are definitely allowed, but they have to have the proper blend effect; I have glBlend(GL_ONE, GL_ONE_MINUS_SRC_ALPHA); enabled, so it can be tricky to get right with multiple passes.

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• How to draw some lines in a view element defined in the xml layout

  - by Nils

  Hello, I have problems drawing some simple lines in a view object (Android programming). First I created the layout with the view element(kind of painting area) in it (XML file). [...] < View android:id="@+id/viewmap" android:layout_width="572px" android:layout_height="359px" android:layout_x="26px" android:layout_y="27px" [...] ... and tried then to access it to draw some lines. Unfortunately the program is running and other UI elements like buttons are displayed, but I can't see the drawings. What's wrong ? [...] viewmap = (View) findViewById(R.id.viewmap); Canvas canvas = new Canvas(); viewmap.draw(canvas); Paint p = new Paint(); p.setColor(Color.BLUE); p.setStyle(Paint.Style.STROKE); canvas.drawColor(Color.WHITE); p.setColor(Color.BLUE); canvas.drawLine(4, 4, 29, 5, p); p.setColor(Color.RED); viewmap.draw(canvas); [...] Thanks for help :) !

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• Sending an email with browser capabilities and screen size etc.

  - by talkingnews

  A lot of my visitors are blind (with it being a site for the blind), and often when trying to diagnose problems, I'd like to know what version of browser etc they're using, whether flash is installed. Because more often than not, someone will swear they are using X, when in fact Y is installed. Currently, I'm using http://jsbrwsniff.sourceforge.net/usage.html piped into an email, but I've got 2 problems here: First of all, jsbrwsniff is quite "heavy" and hasn't been updated since early 2007, so there's a lot of -1's in the result. Secondly, if I call it as follows, the page reloads: <a href="#" onclick="sendEmail()">Email feedback</a> And if I call it like this, the page goes blank and looks like it's trying to infinitely load a blank page: <a href="javascript:sendEmail()">Email feedback</a> See the nightmare for yourself here: http://kingston.talking-newspapers.co.uk/ Now, I know there are 1001 articles and comments here and elsewhere saying "don't use browser sniffers, they can be spoofed (etc)", but honestly, you'll have to trust me that this is a significantly useful tool when you're talking someone in their more "senior years" and using a screenreader through "help about", when they've clicked the wrong window to start with! I'm using jquery anyway in the site, and I'm aware of $jQuery.browser and $jQuery.support, but these don't tell me the elements I need (like whether Flash is installed, and what version etc). I've looked everywhere for a jquery plugin for my needs, with no luck. Finally, if I have to stick to the current method of jsbrwsniff then it's not the end of the world, but if anyone knows a way of launching the user's email client populated with the information I need but WITHOUT refreshing or blanking the page, I'd love to know. BTW - there's a good reason for not using a webform, which is simply because it's easier for the screen-reader user to use an email client they are used to. Thanks!

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• Javascript: prototypeal inheritance and the prototype property

  - by JanD

  Hi, I have a simple code fragment in JS working with prototype inheritance. function object(o) { function F() {} F.prototype = o; return new F(); } //the following code block has a alternate version var mammal = { color: "brown", getColor: function() { return this.color; } } var myCat = object(mammal); myCat.meow = function(){return "meow";} that worked fine but adding this: mammal.prototype.kindOf = "predator"; does not. ("mammal.prototype is undefined") Since I guessed that object maybe have no prototype I rewrote it, replacing the var mammal={... block with: function mammal() { this.color = "brown"; this.getColor = function() { return this.color; } } which gave me a bunch of other errors: "Function.prototype.toString called on incompatible object" and if I try to call _myCat.getColor() "myCat.getColor is not a function" Now I am totally confused. After reading Crockford, and Flanagan I did not get the solution for the errors. So it would be great if somebody knows... - why is the prototype undefined in the first example (which is foremost concern; I thought the prototype of explicitly set in the object() function) - why get I these strange errors trying to use the mammal function as prototype object in the object() function?

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• How can I mix SVG and HTML into a page?

  - by John Duff

  I've been using the jQuery.svg plugin to do some SVG rendering and it works perfectly but I also want to have the server render some SVG into the page and I can't get that to work. How do I add some SVG like below into the page so that Firefox will render it? <svg xmlns="http://www.w3.org/2000/svg" version="1.1" preserveAspectRatio="none" viewBox="0 0 100 100"> <linearGradient id="background_gradient_black" x1="0%" y1="10" x2="0%" y2="90" gradientUnits="userSpaceOnUse"> <stop offset="0%" stop-color="#000" stop-opacity="1" /> <stop offset="45%" stop-color="#444" stop-opacity="1" /> <stop offset="55%" stop-color="#444" stop-opacity="1" /> <stop offset="100%" stop-color="#000" stop-opacity="1" /> </linearGradient> <rect x="0" y="0" width="100" height="100" fill="url(#background_gradient_black)"" /> </svg> Do I need a meta tag saying that there is SVG content in the page or define the SVG namespace somehow?

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• "Outward" border-radius in css?

  - by MaxMackie

  Currently, the links at the top of my website look like this: However, I am trying to "round" the bottom edges of the buttons to make it look like they are coming out of the page and into the ribbon at the top. I am aware that you can hack it and add a "separator" div with rounded corners between each entry, but this would be difficult to do seeing at the borders used are not all from the same div. Also, it wouldn't be easy seeing as my buttons are very close to each other. The css for the "button": .button { border-top: 3px solid #A1C1BE; border-left: 3px solid #A1C1BE; border-right: 3px solid #A1C1BE; border-bottom: 0px; padding: 5px 8px 5px 8px; margin: 0 0 -9px 0; border-radius: 5px 5px 0 0; font-size: 12px; font-family: 'PT Sans', sans-serif; background-color: #f8f8ff; color: #484848; } css for the "ribbon": #top-wrapper { border-bottom: 5px solid #A1C1BE; width: 100%; background-color: #59554E; padding: 10px 0 0 0; color: #C0C0A8; } As you can see, the thicker border belongs to the ribbon which stretches the length of the webpage, whereas the thinner blue border is part of the button.

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• Jquery and PHP rating function problem

  - by Sergio

  I know that I was already posted similar question but I just can't find the answer and figure it out how to solve this problem. I'm trying to customize Jquery Star Rating plugin (link text) but I do not know what to do to show the message based on response of PHP script. Jquery script successfully send rating data to PHP scripts that query the database and based on that echo message of proper or improper rating. What should I add to an existing JS code so I can get echo from PHP and base on that write a message on some DIV beside rating star? Jquery: $('#gal').rating('gl.php?gal_no=<?=$gal_no;?>&id=<?=$id;?>', {maxvalue:10,increment:.5, curvalue: <?=$cur;?>}); Simplified PHP code: $br=mysql_query("SELECT count(gal) as total FROM ...") if ... { echo '0'; } else echo '1'; } Jquery code successfully transmitted data to PHP script and when the PHP done with checking data echo the result ('1' or '0'). How can I get this PHP result back to Jquery and based on them write a message? Something like: if(data=="1") { $("#error").show("fast").html('not correct').css({'background-color':'#F5F5F5','border-color' : '#F69'}); }else{ $("#error").show("fast").html('correct').css({'background-color' : '#FFF','border-color' : '#3b5998'}); } If someone has an idea...I would appreciate it.

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• css style remains after click

  - by rod

  Hi All, I have a simple test page with a single styled button. I'm using a:hover when you hover over the button. However, when you click the button the a:hover style remains until I click on something else. How would I fix this and why is this happening? Thanks, rod. <asp:Content ID="indexContent" ContentPlaceHolderID="MainContent" runat="server"> <% using (Ajax.BeginForm(new AjaxOptions { })) { %> <div id="detailActions"> <a href="#">Delete User</a> </div> <% } %> </asp:Content> My CSS: #detailActions { margin-bottom: 7px; padding: 3px 0px 5px 0px; } #detailActions { padding: 1px 7px 1px 7px; margin: 0px 5px 0px 0px; border: solid 1px gray; background-color: #ADD8E6; cursor: pointer; width: auto !important; font-weight: bold; text-decoration: none; color: #003366; font-size: 1.2em; } #detailActions a:hover, #detailActions a:active, #detailActions a:focus { color: White; background-color: #00008B; }

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• jQuery weirdness. Div becomes attached to chained element markup?

  - by Scott B

  I've got a div in my app that is displayed each time my theme options panel is "saved". The markup is... <form method="post"> <?php if ( $_REQUEST['saved']) { ?> <div id="message" class="updated fade"><p>Sweet! The settings were saved :)</p></div> <script type="text/javascript"> $('#message').delay(3000).fadeOut(3000);</script> <?php }?> This has the effect of showing the div (which is absolutely positioned to overlay the interface). I'm also using jQuery to fade the message offscreen after 3 seconds. This works fine, however, when I add a bit of script to my jQuery chain (see the commented out block below), the message div is only visible when the jPicker popup appears. $(function() { $("#carousel").jCarouselLite ( { btnNext: ".next", btnPrev: ".prev", visible: 6, speed: 700 } ); $('#carousel').show(); $('#myTheme').change ( function() { var myImage = $('#myTheme :selected').text(); $('.selectedImage img').attr('src','../wp-content/themes/myTheme/styles/'+myImage+'/screenshot.jpg'); } ); $('#carousel ul li').click ( function(e) { var myOption = $(this).children('img').attr('title'); $("#myTheme option[value='"+myOption+"']").attr('selected', 'selected'); $("#myTheme").css('backgroundColor', '#A9A9A9').animate({backgroundColor: "#ffffff"}, 'slow'); } ); $('#carousel ul li').hover ( function(e) { var img_src = $(this).children('img').attr('src'); $('.selectedImage img').attr('src',img_src); } ,function() { $('.selectedImage img').attr('src', '<?php echo $selectedThumb; ?>'); } ); /* $('#myTheme_sidebar_color').jPicker ( {}, function(color) { $(this).val(color.get_Hex()); }, function(color) { $(this).val(color.get_Hex()); } ); */ });

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