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  • How to use the Zend_Log instance that was created using the Zend_Application_Resource_Log in a model

    - by Alex
    Our Zend_Log is initialized by only adding the following lines to application.ini resources.log.stream.writerName = "Stream" resources.log.stream.writerParams.mode = "a" So Zend_Application_Resource_Log will create the instance for us. We are already able to access this instance in controllers via the following: public function getLog() { $bootstrap = $this->getInvokeArg('bootstrap'); //if (is_null($bootstrap)) return false; if (!$bootstrap->hasPluginResource('Log')) { return false; } $log = $bootstrap->getResource('Log'); return $log; } So far, so good. Now we want to use the same log instance in model classes, where we can not access the bootstrap. Our first idea was to register the very same Log instance in Zend_Registry to be able to use Zend_Registry::get('Zend_Log') everywhere we want: in our Bootstrap class: protected function _initLog() { if (!$this->hasPluginResource('Log')) { throw new Zend_Exception('Log not enabled'); } $log = $this->getResource('Log'); assert( $log != null); Zend_Registry::set('Zend_Log', $log); } Unfortunately this assertion fails == $log IS NULL --- but why?? It is clear that we could just initialize the Zend_Log manually during bootstrapping without using the automatism of Zend_Application_Resource_Log, so this kind of answers will not be accepted.

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  • When I log on to my company desktop, I log on to a domain. How is this domain name installed?

    - by learnerforever
    Hi, When I have to work on my machine in company, I have noticed that I log on to a domain (named on the basis of company name) and not really on that computer. From, what I understand, this has a few advantages, the primary being that I just need one password for the domain and can work through any of the machines in company. My questions are : What software on desktop/network have to be installed so that the desktop recognizes and gives me option of logging into a domain. I would guess that a software can be installed on desktop, and there we can configure the IP address of domain server of company and port number, which handles authentication. Is this correct? This takes me to another question that how are softwares installed on end machines in a company. Going to each machine physically and installing looks very unweildy from administrator point of view. An obvious solution would be to install softwares (and updates) over network. My question on this are: What protocols,keywords come into picture when administrator installs OS,softwares,updates from his administrator machine to end machine through network. Thanks,

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  • error in auth.log but can login; LDAP/PAM

    - by Peter
    I have a server running OpenLDAP. When I start a ssh-session I can log in without problems, but an error appears in the logs. This only happens when I log in with a LDAP account (so not with a system account such as root). Any help to eliminate these errors would be much appreciated. The relevant piece from /var/log/auth.log sshd[6235]: pam_unix(sshd:auth): authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=example.com user=peter sshd[6235]: Accepted password for peter from 192.168.1.2 port 2441 ssh2 sshd[6235]: pam_unix(sshd:session): session opened for user peter by (uid=0) pam common-session session [default=1] pam_permit.so session required pam_unix.so session optional pam_ldap.so session required pam_mkhomedir.so skel=/etc/skel umask=0022 session required pam_limits.so session required pam_unix.so session optional pam_ldap.so pam common-auth auth [success=1 default=ignore] pam_ldap.so auth required pam_unix.so nullok_secure use_first_pass auth required pam_permit.so session required pam_mkhomedir.so skel=/etc/skel umask=0022 silent auth sufficient pam_unix.so nullok_secure use_first_pass auth requisite pam_succeed_if.so uid >= 1000 quiet auth sufficient pam_ldap.so use_first_pass auth required pam_deny.so pam common-account account [success=2 new_authtok_reqd=done default=ignore] pam_ldap.so account [success=1 default=ignore] pam_unix.so account required pam_unix.so account sufficient pam_succeed_if.so uid < 1000 quiet account [default=bad success=ok user_unknown=ignore] pam_ldap.so account required pam_permit.so account sufficient pam_ldap.so account sufficient pam_unix.so

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  • How do I connect to the serial console port os a Sunfire 280R?

    - by DrStalker
    We have a Sunfire 280R (old SPARC/Solaris server) that is refusing to come up after being relocated. We're trying to connect to the serial console port, but all we get is random gibberish on the screen. We've tried both connecting with a DB25DB9 adapter and using a DB-25-RJ45 adapter with a cisco RJ45-DB9 adapter to a windows laptop. We're configuring the laptop to 9600 baud, 8 bit, 1 stop bit, no parity. We've tried both no flow control and Xon/Xoff. We get the same results hooking up to the serial port on a working SPARC server, so it's probably something in our setup rather than a fault with the server. How do we get access to to serial console so we can work out what is stopping this box from getting to the network? Is there a special sun adapter we need to get/make to get the serial link working?

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  • Configured Samba to join our domain, but logon fails from Windows machine

    - by jasonh
    I've configured a Fedora 11 installation to join our domain. It seems to join successfully (though it reports a DNS update failure) but when I try to access \\fedoraserver.test.mycompany.com I'm prompted for a password. So I enter adminuser and the password and that fails, so I try test.mycompany.com\adminuser and that too fails. What am I missing? EDIT (Update 9/1/09): I can now connect to the machine and see the shares on it (see my response to djhowell's answer) but when I try to connect, I get an error saying The network path was not found. I checked the log entry on the Fedora computer for the computer I'm connecting from (/var/log/samba/log.ComputerX) and it reads: [2009/09/01 12:02:46, 1] libads/cldap.c:recv_cldap_netlogon(157) no reply received to cldap netlogon [2009/09/01 12:02:46, 1] libads/ldap.c:ads_find_dc(417) ads_find_dc: failed to find a valid DC on our site (Default-First-Site-Name), trying to find another DC Config files as of 9/1/09: smb.conf: [global] Workgroup = TEST realm = TEST.MYCOMPANY.COM password server = DC.TEST.MYCOMPANY.COM security = DOMAIN server string = Test Samba Server log file = /var/log/samba/log.%m max log size = 50 idmap uid = 15000-20000 idmap gid = 15000-20000 windbind use default domain = yes cups options = raw client use spnego = no server signing = auto client signing = auto [share] comment = Test Share path = /mnt/storage1 valid users = adminuser admin users = adminuser read list = adminuser write list = adminuser read only = No I also set the krb5.conf file to look like this: [logging] default = FILE:/var/log/krb5libs.log kdc = FILE:/var/log/krb5kdc.log admin_server = FILE:/var/log/kadmind.log [libdefaults] default_realm = test.mycompany.com dns_lookup_realm = false dns_lookup_kdc = false ticket_lifetime = 24h forwardable = yes [realms] TEST.MYCOMPANY.COM = { kdc = dc.test.mycompany.com admin_server = dc.test.mycompany.com default_domain = test.mycompany.com } [domain_realm] dc.test.mycompany.com = test.mycompany.com .dc.test.mycompany.com = test.mycompany.com [appdefaults] pam = { debug = false ticket_lifetime = 36000 renew_lifetime = 36000 forwardable = true krb4_convert = false } I realize that there might be an issue with EXAMPLE.COM in there, however if I change it to TEST.MYCOMPANY.COM then it fails to join the domain with a preauthentication failure. As of 9/1/09, this is no longer the case.

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  • Does a USB to RJ-45 console cable exist?

    - by Carl Flippin
    I am aware of the RJ-45 to DB9 adapter commonly used on cisco routers to access console. I am aware of the USB to DB9 adapters to allow laptops without serial to get a serial port. I am looking for a USB to RJ-45 adapter so I don't have to chain two adapters together. I have searched everywhere but even the pre-packaged solutions seem to have the two adapters chained together. Does such a thing exist? If it doesn't is there some technical reason it cannot? It seems like a manufacturer would just have to wire the DB9 end of the USB adapter differently and it would work just fine plugged straight into the console port of the router.

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  • nginx with ssl: I get a 403 and log "directory index of '...dir...' is forbidden" log message. works fine with unencrypted connection

    - by user72464
    As mentioned in the title, I had nginx working fine with my rails app, until I tried to add the ssl server. The unencrypted connection still works but the ssl always returns me a 403 page with the following line in the error log: directory index of "/home/user/rails/" is forbidden, client: [my ip], server: _, request: "GET / HTTP/1.1", host: "[server ip]" Below my nginx.conf server block: server { listen 80; listen 443 ssl; ssl_certificate /etc/ssl/server.crt; ssl_certificate_key /etc/ssl/server.key; client_max_body_size 4G; keepalive_timeout 5; root /home/user/rails; try_files $uri/index.html $uri.html $uri @app; location @app { proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header X-Forwarded-Proto $scheme; proxy_set_header Host $http_host; proxy_redirect off; proxy_pass http://0.0.0.0:8080; } error_page 500 502 503 504 /500.html; location = /500.html { root /home/user/rails; } } the /home/user/rails directory and it's parent have all read to all rights. and they belong to the user nginx. the certificate and key file have the following rights: -rw-r--r-- 1 nginx root 830 Nov 8 09:09 server.crt -rw--w---- 1 nginx root 887 Nov 8 09:09 server.key any clue?

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  • How can I open a console application with a given window size?

    - by Oliver Salzburg
    The application I want to start is MongoDB. If I would start it normally, it looks like this: I don't like the amount of line breaks and I have a lot of screen space, so I would like to utilize said space to get rid of the line breaks. I can change the size of the console window with MODE, so I wrote a batch file like this: @ECHO OFF MODE con:cols=140 lines=70 %~dp0mongodb\bin\mongod --dbpath %~dp0data --rest So far, so good. When I start this batch file, I get a larger window, as desired. But when I now press Ctrl+C to exit MongoDB, I get the annoying prompt: Terminate batch job (Y/N)? Which is useless, because the command I just exited out of was the last command in the batch job anyway and no matter what I answer, the result is the same. So, how can I get a larger console window for the application without having that prompt when I hit Ctrl+C?

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  • Modifying Exchange 2003 accounts in Exchange 2010 management console?

    - by MartinC
    You can look at Exchange 2003 accounts via the 2010 Management console but is modifying supported? No warnings that it is not, and all is held in Active Directory. Adding an additional email address works... But results in Error 4, Keywords "classic" Task Get-MailboxStatistics writing error when processing record of index 0. Error: Microsoft.Exchange.Management.Tasks.MdbAdminTaskException: Mailbox 'domain/OU/account name' doesn't exist in an Exchange 2007 or later mailbox database. Management Console has the updated change, as does ADUC in 2003.

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  • JBoss admin-console fails to load - missing Log4J jar?

    - by Jack
    I downloaded JBoss 5.1 and unzipped to ~/jboss/ such that JBoss is installed into: ~/jboss/jboss-5.1.0.GA/ I run the default deployment by using the following command found in jboss/jboss-5.1.0.GA/bin ./run.sh -c default While JBoss starts (http://127.0.0.1:8080/), admin-console is not deployed. The log file: jboss/jboss-5.1.0.GA/server/default/log shows the following information: DEPLOYMENTS IN ERROR: Deployment "vfsfile:/Users/jackwootton/jboss/jboss-5.1.0.GA/server/default/deploy/admin-console.war/" is in error due to the following reason(s): org.jboss.deployers.spi.DeploymentException: URL file:/Users/jackwootton/jboss/jboss-5.1.0.GA/server/default/tmp/az6n6v-tjilfb-h32fokxn-1-h32fosuo-v/admin-console.war/ deployment failed Deployment "vfszip:/Users/jackwootton/jboss/jboss-5.1.0.GA/server/default/deploy/quartz-ra.rar/" is in error due to the following reason(s): org.apache.commons.logging.LogConfigurationException: User-specified log class 'org.apache.commons.logging.impl.Log4JLogger' cannot be found or is not useable. The Log4J jar file exists in: jboss/jboss-5.1.0.GA/lib/jboss-logging-log4j.jar I have three questions: Have I understood the problem correctly (i.e. that admin-console cannot find the required Log4j JAR file and therefore is not deployed)? What can I do to fix this problem? Why would an out-of-the-box deployment have this problem in the first place?

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  • Custom fail2ban Filter

    - by Michael Robinson
    In my quest to block excessive failed phpMyAdmin login attempts with fail2ban, I've created a script that logs said failed attempts to a file: /var/log/phpmyadmin_auth.log Custom log The format of the /var/log/phpmyadmin_auth.log file is: phpMyadmin login failed with username: root; ip: 192.168.1.50; url: http://somedomain.com/phpmyadmin/index.php phpMyadmin login failed with username: ; ip: 192.168.1.50; url: http://192.168.1.48/phpmyadmin/index.php Custom filter [Definition] # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; phpMyAdmin jail [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 6 The fail2ban log contains: 2012-10-04 10:52:22,756 fail2ban.server : INFO Stopping all jails 2012-10-04 10:52:23,091 fail2ban.jail : INFO Jail 'ssh-iptables' stopped 2012-10-04 10:52:23,866 fail2ban.jail : INFO Jail 'fail2ban' stopped 2012-10-04 10:52:23,994 fail2ban.jail : INFO Jail 'ssh' stopped 2012-10-04 10:52:23,994 fail2ban.server : INFO Exiting Fail2ban 2012-10-04 10:52:24,253 fail2ban.server : INFO Changed logging target to /var/log/fail2ban.log for Fail2ban v0.8.6 2012-10-04 10:52:24,253 fail2ban.jail : INFO Creating new jail 'ssh' 2012-10-04 10:52:24,253 fail2ban.jail : INFO Jail 'ssh' uses poller 2012-10-04 10:52:24,260 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,260 fail2ban.filter : INFO Set maxRetry = 6 2012-10-04 10:52:24,261 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,261 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,279 fail2ban.jail : INFO Creating new jail 'ssh-iptables' 2012-10-04 10:52:24,279 fail2ban.jail : INFO Jail 'ssh-iptables' uses poller 2012-10-04 10:52:24,279 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set maxRetry = 5 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,280 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,287 fail2ban.jail : INFO Creating new jail 'fail2ban' 2012-10-04 10:52:24,287 fail2ban.jail : INFO Jail 'fail2ban' uses poller 2012-10-04 10:52:24,287 fail2ban.filter : INFO Added logfile = /var/log/fail2ban.log 2012-10-04 10:52:24,287 fail2ban.filter : INFO Set maxRetry = 3 2012-10-04 10:52:24,288 fail2ban.filter : INFO Set findtime = 604800 2012-10-04 10:52:24,288 fail2ban.actions: INFO Set banTime = 604800 2012-10-04 10:52:24,292 fail2ban.jail : INFO Jail 'ssh' started 2012-10-04 10:52:24,293 fail2ban.jail : INFO Jail 'ssh-iptables' started 2012-10-04 10:52:24,297 fail2ban.jail : INFO Jail 'fail2ban' started When I issue: sudo service fail2ban restart fail2ban emails me to say ssh has restarted, but I receive no such email about my phpmyadmin jail. Repeated failed logins to phpMyAdmin does not cause an email to be sent. Have I missed some critical setup? Is my filter's regular expression wrong? Update: added changes from default installation Starting with a clean fail2ban installation: cp /etc/fail2ban/jail.conf /etc/fail2ban/jail.local Change email address to my own, action to: action = %(action_mwl)s Append the following to jail.local [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 4 Add the following to /etc/fail2ban/filter.d/phpmyadmin.conf # phpmyadmin configuration file # # Author: Michael Robinson # [Definition] # Option: failregex # Notes.: regex to match the password failures messages in the logfile. The # host must be matched by a group named "host". The tag "<HOST>" can # be used for standard IP/hostname matching and is only an alias for # (?:::f{4,6}:)?(?P<host>\S+) # Values: TEXT # # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; # Option: ignoreregex # Notes.: regex to ignore. If this regex matches, the line is ignored. # Values: TEXT # # Ignore our own bans, to keep our counts exact. # In your config, name your jail 'fail2ban', or change this line! ignoreregex = Restart fail2ban sudo service fail2ban restart PS: I like eggs

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  • Custom fail2ban Filter for phpMyadmin bruteforce attempts

    - by Michael Robinson
    In my quest to block excessive failed phpMyAdmin login attempts with fail2ban, I've created a script that logs said failed attempts to a file: /var/log/phpmyadmin_auth.log Custom log The format of the /var/log/phpmyadmin_auth.log file is: phpMyadmin login failed with username: root; ip: 192.168.1.50; url: http://somedomain.com/phpmyadmin/index.php phpMyadmin login failed with username: ; ip: 192.168.1.50; url: http://192.168.1.48/phpmyadmin/index.php Custom filter [Definition] # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; phpMyAdmin jail [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 6 The fail2ban log contains: 2012-10-04 10:52:22,756 fail2ban.server : INFO Stopping all jails 2012-10-04 10:52:23,091 fail2ban.jail : INFO Jail 'ssh-iptables' stopped 2012-10-04 10:52:23,866 fail2ban.jail : INFO Jail 'fail2ban' stopped 2012-10-04 10:52:23,994 fail2ban.jail : INFO Jail 'ssh' stopped 2012-10-04 10:52:23,994 fail2ban.server : INFO Exiting Fail2ban 2012-10-04 10:52:24,253 fail2ban.server : INFO Changed logging target to /var/log/fail2ban.log for Fail2ban v0.8.6 2012-10-04 10:52:24,253 fail2ban.jail : INFO Creating new jail 'ssh' 2012-10-04 10:52:24,253 fail2ban.jail : INFO Jail 'ssh' uses poller 2012-10-04 10:52:24,260 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,260 fail2ban.filter : INFO Set maxRetry = 6 2012-10-04 10:52:24,261 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,261 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,279 fail2ban.jail : INFO Creating new jail 'ssh-iptables' 2012-10-04 10:52:24,279 fail2ban.jail : INFO Jail 'ssh-iptables' uses poller 2012-10-04 10:52:24,279 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set maxRetry = 5 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,280 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,287 fail2ban.jail : INFO Creating new jail 'fail2ban' 2012-10-04 10:52:24,287 fail2ban.jail : INFO Jail 'fail2ban' uses poller 2012-10-04 10:52:24,287 fail2ban.filter : INFO Added logfile = /var/log/fail2ban.log 2012-10-04 10:52:24,287 fail2ban.filter : INFO Set maxRetry = 3 2012-10-04 10:52:24,288 fail2ban.filter : INFO Set findtime = 604800 2012-10-04 10:52:24,288 fail2ban.actions: INFO Set banTime = 604800 2012-10-04 10:52:24,292 fail2ban.jail : INFO Jail 'ssh' started 2012-10-04 10:52:24,293 fail2ban.jail : INFO Jail 'ssh-iptables' started 2012-10-04 10:52:24,297 fail2ban.jail : INFO Jail 'fail2ban' started When I issue: sudo service fail2ban restart fail2ban emails me to say ssh has restarted, but I receive no such email about my phpmyadmin jail. Repeated failed logins to phpMyAdmin does not cause an email to be sent. Have I missed some critical setup? Is my filter's regular expression wrong? Update: added changes from default installation Starting with a clean fail2ban installation: cp /etc/fail2ban/jail.conf /etc/fail2ban/jail.local Change email address to my own, action to: action = %(action_mwl)s Append the following to jail.local [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 4 Add the following to /etc/fail2ban/filter.d/phpmyadmin.conf # phpmyadmin configuration file # # Author: Michael Robinson # [Definition] # Option: failregex # Notes.: regex to match the password failures messages in the logfile. The # host must be matched by a group named "host". The tag "<HOST>" can # be used for standard IP/hostname matching and is only an alias for # (?:::f{4,6}:)?(?P<host>\S+) # Values: TEXT # # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; # Option: ignoreregex # Notes.: regex to ignore. If this regex matches, the line is ignored. # Values: TEXT # # Ignore our own bans, to keep our counts exact. # In your config, name your jail 'fail2ban', or change this line! ignoreregex = Restart fail2ban sudo service fail2ban restart PS: I like eggs

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  • How should I log time spent on multiple tasks?

    - by xenoterracide
    In Joel's blog on evidence based scheduling he suggests making estimates based on the smallest unit of work and logging extra work back to the original task. The problem I'm now experiencing is that I'll have create object A with subtask method A which creates object B and test all of the above. I create tasks for each of these that seems to be resulting in ok-ish estimates (need practice), but when I go to log work I find that I worked on 4 tasks at once because I tweak method A and find a bug in the test and refactor object B all while coding it. How should I go about logging this work? should I say I spent, for example, 2 hours on each of the 4 tasks I worked on in the 8 hour day?

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  • Subterranean IL: Compiling C# exception handlers

    - by Simon Cooper
    An exception handler in C# combines the IL catch and finally exception handling clauses into a single try statement: try { Console.WriteLine("Try block") // ... } catch (IOException) { Console.WriteLine("IOException catch") // ... } catch (Exception e) { Console.WriteLine("Exception catch") // ... } finally { Console.WriteLine("Finally block") // ... } How does this get compiled into IL? Initial implementation If you remember from my earlier post, finally clauses must be specified with their own .try clause. So, for the initial implementation, we take the try/catch/finally, and simply split it up into two .try clauses (I have to use label syntax for this): StartTry: ldstr "Try block" call void [mscorlib]System.Console::WriteLine(string) // ... leave.s End EndTry: StartIOECatch: ldstr "IOException catch" call void [mscorlib]System.Console::WriteLine(string) // ... leave.s End EndIOECatch: StartECatch: ldstr "Exception catch" call void [mscorlib]System.Console::WriteLine(string) // ... leave.s End EndECatch: StartFinally: ldstr "Finally block" call void [mscorlib]System.Console::WriteLine(string) // ... endfinally EndFinally: End: // ... .try StartTry to EndTry catch [mscorlib]System.IO.IOException handler StartIOECatch to EndIOECatch catch [mscorlib]System.Exception handler StartECatch to EndECatch .try StartTry to EndTry finally handler StartFinally to EndFinally However, the resulting program isn't verifiable, and doesn't run: [IL]: Error: Shared try has finally or fault handler. Nested try blocks What's with the verification error? Well, it's a condition of IL verification that all exception handling regions (try, catch, filter, finally, fault) of a single .try clause have to be completely contained within any outer exception region, and they can't overlap with any other exception handling clause. In other words, IL exception handling clauses must to be representable in the scoped syntax, and in this example, we're overlapping catch and finally clauses. Not only is this example not verifiable, it isn't semantically correct. The finally handler is specified round the .try. What happens if you were able to run this code, and an exception was thrown? Program execution enters top of try block, and exception is thrown within it CLR searches for an exception handler, finds catch Because control flow is leaving .try, finally block is run The catch block is run leave.s End inside the catch handler branches to End label. We're actually running the finally before the catch! What we do about it What we actually need to do is put the catch clauses inside the finally clause, as this will ensure the finally gets executed at the correct time (this time using scoped syntax): .try { .try { ldstr "Try block" call void [mscorlib]System.Console::WriteLine(string) // ... leave.s End } catch [mscorlib]System.IO.IOException { ldstr "IOException catch" call void [mscorlib]System.Console::WriteLine(string) // ... leave.s End } catch [mscorlib]System.Exception { ldstr "Exception catch" call void [mscorlib]System.Console::WriteLine(string) // ... leave.s End } } finally { ldstr "Finally block" call void [mscorlib]System.Console::WriteLine(string) // ... endfinally } End: ret Returning from methods There is a further semantic mismatch that the C# compiler has to deal with; in C#, you are allowed to return from within an exception handling block: public int HandleMethod() { try { // ... return 0; } catch (Exception) { // ... return -1; } } However, you can't ret inside an exception handling block in IL. So the C# compiler does a leave.s to a ret outside the exception handling area, loading/storing any return value to a local variable along the way (as leave.s clears the stack): .method public instance int32 HandleMethod() { .locals init ( int32 retVal ) .try { // ... ldc.i4.0 stloc.0 leave.s End } catch [mscorlib]System.Exception { // ... ldc.i4.m1 stloc.0 leave.s End } End: ldloc.0 ret } Conclusion As you can see, the C# compiler has quite a few hoops to jump through to translate C# code into semantically-correct IL, and hides the numerous conditions on IL exception handling blocks from the C# programmer. Next up: catch-all blocks, and how the runtime deals with non-Exception exceptions.

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  • How To Log Into The Desktop, Add a Start Menu, and Disable Hot Corners in Windows 8

    - by Chris Hoffman
    If you don’t have a touchscreen computer and spend all your time on the desktop, Windows 8’s new interface can seem intrusive. Microsoft won’t allow you to disable the new interface, but Classic Shell provides the options Microsoft didn’t. In addition to providing a Start button, Classic Shell can take you straight to the desktop when you log in and disable the hot corners that activate the charms and metro app switcher. There are other programs that do this, but Classic Shell is free and open-source. Many of the alternatives, such as Start8 and RetroUI, are commercial apps that cost money. We’ve covered Classic Shell in the past, but it’s come a long way since then. How Hackers Can Disguise Malicious Programs With Fake File Extensions Can Dust Actually Damage My Computer? What To Do If You Get a Virus on Your Computer

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  • Changed username. Now I cannot log on or view my previous files

    - by Lauren
    I want to change my username and followed the instructions from How do I change my username? by creating a temp user with admin privileges. While logged in as temp, I did : sudo usermod -l newname oldname sudo usermod -d /home/newname -m newname Now I cannot log in under newname and /home only lists newname and temp Reading through other sites now, it seems I should have used usermod -d /home/newname -m oldname Based on this, I think I may have deleted the contents of my previous home folder?? I'm sure I'm not the first person to do some stupid while changing username, but any help is greatly appreciated. Thank you!

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  • Why am I getting messages from cloudfront in my error log?

    - by JK01
    I frequently have messages like this in my websites error log: "Script error.". URL: https://e3m4drct5m1ays.cloudfront.net/items/loaders /loader_21.js?pid=21&systemid=13504281c5a501837196c23300f84e66&aoi=1327214632& zoneid=16620&cid=HK&rid=Hong%20Kong%20(general)&ccid=Kowloon&dma=0. Line number: 0 Error name: Stack: Now I don't actually know what cloudfront is or what it does. And I do not refer to this script in my site. So why would I be getting js error logged as if it was a script being run on my own site? This is using elmah logging.

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  • Is there a pattern or logical structure I can follow for Event Log Numbers?

    - by makerofthings7
    What are some ideas or structure I can use when assigning EventID to events that will be saved to the Event Log? Some options I've considered Sequential (0... int.Max) Multiple of 10, where the "0" is replaced with how noisy the debugLevel is set. xxx0 may represent exceptions, critical information, start, stop etc. ...? What numbering approach gives you the most insight when a user describes the event in an email or phone? What is the most useful to support staff?

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  • Run a script with user interaction on log out / shutdown?

    - by lumbric
    I'd like to run a script on shut down, which interrupts the logout process and and pops up a window with zenity. My target is to get autofsck working with lightdm. It seems to work with 12.04 after installing the old *.deb file, if one runs the check script manually. In order to use it, it should run automatically on log out and ask the user if she/he wants to check the disc on shutdown. There is the option session-cleanup-script in the file /etc/lightdm/lightdm.conf which seems to work, if a bash file with full path is used (I can't place the command directly there). But if I press shutdown, there is no time for a user choice. Is there any other option to solve this problem?

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  • C# Dev Challenge Part 1 of n &ndash; Beginner Edition

    - by mbcrump
    I developed this challenge to test one’s knowledge of C Sharp. I am planning on creating several challenges with different skill sets, so don’t get mad if this challenge doesn’t well challenge you... I noticed that most people like short quizzes so this one only contains 5 questions. All of the challenges are clear and concise of what I am asking you to do. No smoke and mirrors here, meaning that none of the code has syntax errors. The purpose of this exercise is to test several OOP concepts and see how much of the C# language you really know. Question #1 – Lets start off Easy… Will the following code snippet compile successfully? What does this question test? - Can this compile without a namespace? Do you have to have an entry point of “static void Main()”? class Test { static int Main() { System.Console.WriteLine("Developer Challenge"); return 0; } } Answer (select text in box below): Yes, it will compile successfully. Question #2 – What is the value of the Console.WriteLine statements? What does this question test? – Do I understand reference types/value types? If a variable is declared with the @ symbol and its not a reserved keyword does the application compile successfully? using System; internal struct MyStruct { public int Value; } internal class MyClass { public int Value; } class Test { static void Main() { MyStruct @struct1 = new MyStruct(); MyStruct @struct2 = @struct1; @struct2.Value = 100; MyClass @ref1 = new MyClass(); MyClass @ref2 = @ref1; @ref2.Value = 100; Console.WriteLine("Value Type: {0} {1}", @struct1.Value, @struct2.Value); Console.WriteLine("Reference Type: {0} {1}", @ref1.Value, @ref2.Value); } } Answer (select text in box below): Value Type: 0 100 Reference Type: 100 100 Question #3 – What is the value of the Console.WriteLine statements? What does this question test? – Can 2 objects reference the same point in memory? using System; class Test { static void Main() { string s1 = "Testing2"; string t1 = s1; Console.WriteLine(s1 == t1); Console.WriteLine((object)s1 == (object)t1); } } Answer (select text in box below): True True Question #4 – What is the value of the Console.WriteLine statements? What does this question test? – How does the “Stack” work – LIFO or FIFO?   using System; using System.Collections; class Test { static void Main() { Stack a = new Stack(5); a.Push("1"); a.Push("2"); a.Push("3"); a.Push("4"); a.Push("5"); foreach (var o in a) { Console.WriteLine(o); } } } Answer (select text in box below): 5 4 3 2 1 Question #5 – What is the value of the Console.WriteLine statements? What does this question test? – Array and General Looping Knowledge. using System; namespace ConsoleApplication5 { class Program { static void Main(string[] args) { int[] J_LIST = new int[5] { 1, 2, 3, 4, 5 }; int K = 10; int L = 5; foreach (var J in J_LIST) { K = K - J; L = K + 2 * J; Console.WriteLine("J = {0, 5} K = {1, 5} L = {2, 5}", J, K, L); } Console.ReadLine(); } } } Answer (select text in box below): J = 1 K = 9 L = 11 J = 2 K = 7 L = 11 J = 3 K = 4 L = 10 J = 4 K = 0 L = 8 J = 5 K = -5 L = 5 Stay Tuned for more challenges!

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  • How to log frame times in an existing OpenGL game? [on hold]

    - by J Collins
    I have been using FRAPS for some time to benchmark instantaneous frame rates in an OpenGL game for which I am creating maps. Until recently it had been quite reliable. Now however, the bench marking shortcut has been unresponsive and I can't explain why. Ideally I could have a logging system automatically start logging whenever the game had focus, but can't find a good tool to do so. So option a) find out how to make FRAPS reliable again or b) find a new tool. Could one of you kind folks help me? Edit: Concise questions Is there a widely recognised tool to log frame drawing times and rates for compiled applications? If the answer is universally the FRAPs tool, are there any clear cases in which logging will not or should not be expected to work?

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  • After installing ubuntu, all my partitions are gone. Boot-repair log

    - by user211079
    I have an HP Pavilion Sleekbook that came with windows 8 pre-installed. I had trouble dual booting after installing ubuntu, so I disabled safeboot on bios and proceeded to try boot-repair, nothing happened. No dual boot yet. So I tried to reinstall ubuntu, but without the manual partitioning. So I chose to erase ubuntu 13 and reinstall it. Instead it deleted all my HP recovery partitions and windows as well. Here is the log of boot-repair. http://paste.ubuntu.com/6354919/ Gparted and fdisk only show one partition: /dev/sda1 I am wondering if you could suggest any way of recovering my windows partition and have a working windows 8 again? I need some information there with urgency. If you could help me I will be welcome. I am desperated. Thanks

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  • Why am I missing the Ubuntu icon on the log-in screen?

    - by dtdlurch
    I am running Ubuntu 12.10. On the log-in screen, there is no Ubuntu icon for me to click on to change desktop environments. I know where it should be, but it is simply not there. Why is this? And how can I get it back??? I just installed Cinnamon and I would very much like to switch to this environment. I apologize if this is has been addressed elsewhere, but I honestly did try to research before asking. I found several similar questions, but nothing that has answers that helped my situation. And an hour of Googling did not produce anything helpful at all. Thank you for your help.

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  • What else is needed to get iptables to log into this file I created?

    - by anthony01
    I want to create the logging of iptables DROP's and intrusion attemps. First, I put --log-prefix "iptables: " at the end of every iptables rules in my iptables rules file. But this doesn't work, as it says there is a syntax error. So where should I put that command? (I would want to have it included in the saved rules file) Secondly, I created a file iptables.conf within /etc/rsyslog.d/, and I put the following inside of it: :msg, startswith, "iptables: " -/var/log/iptables.log & ~ I assume that at this stage, I'm supposed to restart the rsyslog daemon. What else is needed to do what I'm attempting? Thanks a lot

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  • How to analyze CBS.log file by SFC command to detect corrupt files in Windows 7?

    - by energydream2007
    Hey I have some problems with my Win7 so I've ran sfc /scannow and I got this message: "Windows Resource Protection found corrupt files and was unable to fix some of them..." I also told to look at the folder of the log file to find the cbs.log. After that I've ran this command to pull out the actual problems/corrupt files: findstr /c:"[SR]" %windir%\Logs\CBS\CBS.log >"%userprofile%\Desktop\sfcdetails.txt" This command have created an sfcdetails text file (download). Can someone help me to analyze this file? I haven't found a detailed article about it so far.

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