Search Results

Search found 15563 results on 623 pages for 'django model'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 95/623 | < Previous Page | 91 92 93 94 95 96 97 98 99 100 101 102  | Next Page >

  • django: grouping in an order_by query?

    - by AP257
    Hi all, I want to allocate rankings to users, based on a points field. Easy enough you'd think with an order_by query. But how do I deal with the situation where two users have the same number of points and need to share the same ranking? Should I use annotate to find users with the same number of points? My current code, and a pseudocode description of what I'd like to do, are below. top_users = User.objects.filter(problem_user=False).order_by('-points_total') # Wrong - in pseudocode, this should be # Get the highest points_total, find all the users with that points_total, # if there is more than one user, set status to 'Joint first prize', # otherwise set status to 'First prize' top_users[0].status = "First prize" if (top_users[1]): top_users[1].status = "Second prize" if (top_users[2]): top_users[2].status = "Third prize" if (top_users[3]): top_users[3:].status = "Highly commended" The code above doesn't deal with the situation where two users have the same number of points and need to share second prize. I guess I need to create a query that looks for unique values of points_total, and does some kind of nested ranking? It also doesn't cope with the fact that sometimes there are fewer than 4 users - does anyone know how I can do (in pseudocode) 'if top_users[1] is not null...' in Python?

    Read the article

  • Django TestCase testing order

    - by ziang
    If there are several methods in the test class, I found that the order to execute is alphabetical. But I want to customize the order of execution. How to define the execution order? For example: testTestA will be loaded first than testTestB. class Test(TestCase): def setUp(self): ... def testTestB(self): #test code def testTestA(self): #test code

    Read the article

  • Modify Django settings variables in a middleware

    - by jack
    I set a variable MAX_REQUEST = 100 in settings.py I write a middleware which may lower this value for request origining from a proxy ip address by the following code: settings.MAX_REQUEST = 10 However, looks like the above modification affects all legitimate users. Is it normal?

    Read the article

  • django manual login and redirect

    - by Zayatzz
    Hello I have such view that handles user registration. After creating new user i want to manually authenticate it and log it in.: def register(request): ... ... if form.is_valid(): username = form.cleaned_data['username'] password = form.cleaned_data['password1'] email = '' newuser = User.objects.create_user(username, email, password) user = authenticate(username=username, password=password) login (request, user) I have set LOGIN_REDIRECT_URL to '/profile/', but after authenticating and logging user in, it redirects me back to the same view not to /profile/, why? And how can i specify where to redirect after logging in? If i add HttpResponseRedirect('/profile/') After login line - nothing happens. The script never ends up there. Alan.

    Read the article

  • django media url is not resolved in 500 internal server error template

    - by Tom Tom
    Hi, I'm using a 500.html template for my app, which is an identical copy of the 404.html with some minor text changes. Interestingly the {{ media_url }} context variable will not be resolved by the server if the 500.html is presented (e.g. when I force an internal server error), resulting in a page without any css loaded. An easy way to circumvent this would be to hardcode the links to the css, but I m just curious why the media_url is not resolved. Probably it is because the server encounters a internal server error and that leads to context variables not any more available!?

    Read the article

  • Django: test failing on a view with @login_required

    - by Esteban Feldman
    Hi all, I'm trying to build a test for a view that's decorated with @login_required, since I failed to make it work, I did a simple test and still can't make it pass. Here is the code for the simple test and the view: def test_login(self): user = self._create_new_user() self.assertTrue(user.is_active) login = self.client.login(username=user.username, password=self.data['password1']) self.failUnless(login, 'Could not log in') response = self.client.get('/accounts/testlogin/') self.assertEqual(response.status_code, 200) @login_required def testlogin(request): print 'testlogin !! ' return HttpResponse('OK') _create_new_user() is saving the user and there is a test inside that method to see that is working. The test fails in the response.status_code, returning 302 and the response instance is of a HttpResponseRedirect, is redirecting it as if not logged in. Any clue? I'm missing something? Regards Esteban

    Read the article

  • Django/Python best practice template_dict

    - by fredrik
    Hi, After just been coding for about 6-9 months. I probably changed my coding style a number of times after reading some code or read best practices. But one thing I haven't yet come a cross is a good why to populate the template_dict. As of now I pass the template_dict across a number of methods (that changes/modifies it) and returns is. The result is that every methods takes template_dict as first argument and the returns it and this in my eyes doesn't seems to be the best solution. An idea is to have a method that handles all the changes. But I'm curios if there's a best practice for this? Or is it "do what you feel like"-type of thing? The 2 things I think is pretty ugly is to send as an argument and return it in all methods. And the just the var name is written xxx number of times in the code :) ..fredrik

    Read the article

  • Django: Named URLs / Same Template, Different Named URL

    - by TheLizardKing
    I have a webapp that lists all of my artists, albums and songs when the appropriate link is clicked. I make extensive use of generic views (object_list/detail) and named urls but I am coming across an annoyance. I have three templates that pretty much output the exact same html that look just like this: {% extends "base.html" %} {% block content %} <div id="content"> <ul id="starts-with"> {% for starts_with in starts_with_list %} <li><a href="{% url song_list_x starts_with %}">{{ starts_with|upper }}</a></li> {% endfor %} </ul> <ul> {% for song in songs_list %} <li>{{ song.title }}</li> {% endfor %} </ul> </div> {% endblock content %} My artist and album template look pretty much the same and I'd like to combine the three template's into one. The fact that my variables start with song can easily be changed to the default obj. It's my <ul id="starts-with"> named url I don't know how to correct. Obviously I want it to link to a specific album/artist/song using the named urls in my urls.py but I don't know how to make it context aware. Any suggestions? urlpatterns = patterns('tlkmusic.apps.tlkmusic_base.views', # (r'^$', index), url(r'^artists/$', artist_list, name='artist_list'), url(r'^artists/(?P<starts_with>\w)/$', artist_list, name='artist_list_x'), url(r'^artist/(?P<artist_id>\d+)/$', artist_detail, name='artist_detail'), url(r'^albums/$', album_list, name='album_list'), url(r'^albums/(?P<starts_with>\w)/$', album_list, name='album_list_x'), url(r'^songs/$', song_list, name='song_list'), url(r'^songs/(?P<starts_with>\w)/$', song_list, name='song_list_x'), )

    Read the article

  • Django openid authentication with google

    - by Zayatzz
    Hello I am looking into authenticating via google. I dont understand how it works:http://code.google.com/apis/accounts/docs/OpenID.html#Samples If i do that 2nd request by entering the data as one url with params into browser i get back XML file. Should i not get back sample response nr3? Can somebody explain this to me? The problem is, that im trying to sort through some third party app that uses google openid authentication and its not recieving authenticated users e-mail back, like in sample response 3. Alan PS i have read through similar questions and their responses and gone through pages like: http://stackoverflow.com/questions/353880/how-does-openid-authentication-works http://www.windley.com/archives/2006/04/how_does_openid.shtml http://tinisles.blogspot.com/2008/02/how-does-openid-work.html http://openid.net/pres/protocolflow-1.1.png etc..

    Read the article

  • Django template not loading properly

    - by fmsf
    Hey, When this one runs everything goes fine: (r"^newobject$", "views.myobjects.newobject"), All the CSS + JS files are properly fetched from: static/css/... static/js/... When this one runs: (r"^mybjects/(([a-z]|[A-Z]|[0-9])+)$","views.myobjects.loadobject"), All the css and JS files that are being fetched, are run trough the urlpatterns and are returning my defailt page: (r"", 'views.main.index'), This makes all my CSS and JS code to actualy be HTML. My guess is that i'm giving some noob mistake. Is there any common reason why this should happen? And how to fix it?

    Read the article

  • Subclassing Satchmo's Category model, but then getting the error "'Manager' object has no attribute 'root_categories'"

    - by hellsgate
    I'm using Satchmo as part of a website I'm currently building. At the moment I'm trying add more functions to the Satchmo Category class, but obviously I'm not going to make any changes to the Satchmo files. So, I thought that subclassing the Category class would give me a new class which contains all the Satchmo Category properties and methods while allowing me to add my own. However, either Python subclassing doesn't work like that, or I am doing it wrong. Here is the code I'm using to subclass Category: from product.models import Category class MyCategory(Category): """ additional functions to pull data from the Satchmo store app """ One of the methods I can normally use from the Category class is: Category.objects.root_categories() however, when I try to access MyCategory.objects.root_categories() I get the following error: AttributeError: 'Manager' object has no attribute 'root_categories' Can anyone point me in the right direction for solving this?

    Read the article

  • Django LFS - custom views

    - by owca
    For all those ligthning fast shop users. I'm trying to implement my own first page view that will list all products from shop ( under '/' address). So I have a template : {% extends "lfs/shop/shop_base.html" %} {% block content %} <div id="najnowsze_produkty"> <ul> {% for obj in objects %} <li> {{ obj.name }} </li> {% endfor %} </ul> </div> {% endblock %} and then I've edited main shop view : from lfs.catalog.models import Category from lfs.catalog.models import Product def shop_view(request, template_name="lfs/shop/shop.html"): products = Product.objects.all() shop = lfs_get_object_or_404(Shop, pk=1) return render_to_response(template_name, RequestContext(request, { "shop" : shop, "products" : products })) but it just shows nothing. When I do Product.objects.all() query in shell I get results. Any ideas what could cause the problem ? Maybe I should filter products with 'active' status only ? But I'm not sure if it can influence all objects in any way.

    Read the article

  • django link to any user profile in social comunity

    - by dana
    i am trying to build a virtual comunity, and i have a profile page, and a personal page. In the profile page, one can see only the posts of one user(the user whos profile is checked), in the personal page one can see his posts, plus all the posts he has subscribed to (just like in Facebook) it's a little confusing for me how i can link to the profile of one user, i mean when anybody clicks on a username, it should link to his personal profile page. for example, if someone searches name "abc", the rsult would be "abc",and link to his profile. How can i pass to one function the username or id of a linked user? i mean, showing the profile of the logged in user who is checking his profile is quite easy.But how about another user profile, if one wants to access it? thanks a lot!

    Read the article

  • Django microblog showing a logged in user only his posts

    - by dana
    i have a miniblog application, with a class named New(refering to a new post), having a foreign key to an user(who has posted the entry). above i have a method that displays all the posts from all the users. I'd like to show to the logged in user, only his posts How can i do it? Thanks in advance! def paginate(request): paginator = New.objects.all() return render_to_response('news/newform.html', { 'object_list': paginator, }, context_instance=RequestContext(request))

    Read the article

  • Django stupid mark_safe?

    - by Mark
    I wrote this little function for writing out HTML tags: def html_tag(tag, content=None, close=True, attrs={}): lst = ['<',tag] for key, val in attrs.iteritems(): lst.append(' %s="%s"' % (key, escape_html(val))) if close: if content is None: lst.append(' />') else: lst.extend(['>', content, '</', tag, '>']) else: lst.append('>') return mark_safe(''.join(lst)) Which worked great, but then I read this article on efficient string concatenation (I know it doesn't really matter for this, but I wanted consistency) and decided to update my script: def html_tag(tag, body=None, close=True, attrs={}): s = StringIO() s.write('<%s'%tag) for key, val in attrs.iteritems(): s.write(' %s="%s"' % (key, escape_html(val))) if close: if body is None: s.write(' />') else: s.write('>%s</%s>' % (body, tag)) else: s.write('>') return mark_safe(s.getvalue()) But now my HTML get escaped when I try to render it from my template. Everything else is exactly the same. It works properly if I replace the last line with return mark_safe(unicode(s.getvalue())). I checked the return type of s.getvalue(). It should be a str, just like the first function, so why is this failing?? Also fails with SafeString(s.getvalue()) but succeeds with SafeUnicode(s.getvalue()). I'd also like to point out that I used return mark_safe(s.getvalue()) in a different function with no odd behavior.

    Read the article

  • Django template not loading javascript and css properly due to urlpatterns

    - by fmsf
    Hey, When this one runs everything goes fine: (r"^newobject$", "views.myobjects.newobject"), All the CSS + JS files are properly fetched from: static/css/... static/js/... When this one runs: (r"^mybjects/(([a-z]|[A-Z]|[0-9])+)$","views.myobjects.loadobject"), All the css and JS files that are being fetched, are run trough the urlpatterns and are returning my defailt page: (r"", 'views.main.index'), This makes all my CSS and JS code to actualy be HTML. My guess is that i'm giving some noob mistake. Is there any common reason why this should happen? And how to fix it?

    Read the article

  • django accepting GET parameters

    - by tipu
    I want the index page to accept parameters, whether it be mysite.com/search/param_here or mysite.com/?search=param_here I have this in my URL patterns but I can't get it to work.. any suggestions? urlpatterns = patterns('', (r'^$/(?P<tag>\w+)', 'twingle.search.views.index'), )

    Read the article

  • Cannot use "image.save" on django

    - by zjm1126
    My error is: IOError at /mytest/photo/upload/ [Errno 2] No such file or directory: u'/mytest/photo/upload/2.png' And my view is: UPLOAD_URL = '/mytest/photo/upload/' def upload(request): buf = request.FILES.get('photo', None) print buf if buf: #data = buf.read() #f = StringIO.StringIO(data) image = Image.open(buf) #image = image.convert('RGB') name = '%s%s' % (UPLOAD_URL, buf.name) image.save(file(name, 'wb'), 'PNG') return HttpResponse('ok') return HttpResponse('no') And my urls.py is: urlpatterns = patterns('mytest.views', url(r'^photo/upload/$','upload',name="") ) How can I fix this?

    Read the article

  • Dynamic choices for Django SelectMultiple Widget

    - by PhilGo20
    I'm building a form (not modelForm) where i'd like to use the SelectMultiple Widget to display choices based on a query done during the init of the form. I can think of a few way to do this but I am not exactly clear on the right way to do it. I see different options. I get the "choices" I should pass to the widget in the form init but I am not sure how I should pass them. class NavigatorExportForm(forms.Form): def __init__(self,user, app_id, *args,**kwargs): super (NavigatorExportForm,self ).__init__(*args,**kwargs) # populates the form language_choices = Navigator.admin_objects.get(id=app_id).languages.all().values_list('language', flat=True) languages = forms.CharField(max_length=2, widget=forms.SelectMultiple(choices=???language_choices))

    Read the article

  • Django dislaying upload file content

    - by dana
    hello, i have an application that loads different documents to the server, and allows users to read documents' content. i am uploading the documents to the server, and then i try to read the courses by id, like: def view_course(request,id): u = Courses.objects.get(pk=id) etc But i don't find anywhere : how can i actually read the content of a /.doc/.pdf/.txt and display it on a web page? thanks in advance!

    Read the article

  • django file upload in 2 steps

    - by alexarsh
    Hi, I want to upload a file in 2 steps. First I want to upload it and show the errors and on the second step I want actually to save the file data in the database. So I made a simple form and my problem is how to pass the same file to the form on the second step? I mean how to insert request.FILES data in the same form again. Or maybe there is a better way? Thanks, Arshavski Alexander.

    Read the article

  • Django: tinyMCE and cross site javascript

    - by pistacchio
    Hi, follow this question, I was able to set some textareas in my admin page as richtext inputs. The most voted answer suggests to follow an example and is what i did. Also, it talks about a problem concerning "blank pages". I'm having the same problem and I'm not able to solve it. I have my media files served by a different server, so MEDIA_URL points to a different host with a different port. To simulate this in my dev environment, I also serve media files from a different port. Debugging the failing javascript, Chrome yelds: Unsafe JavaScript attempt to access frame with URL http://localhost:8000/admin/blog/post/add/ from frame with URL http://localhost:88/s3mangerie/js/tiny_mce/themes/advanced/image.htm. Domains, protocols and ports must match. How to solve this problem? Thanks

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 91 92 93 94 95 96 97 98 99 100 101 102  | Next Page >