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  • How to join the results of two tables in django python

    - by user1787524
    I have two models class Weather(model.model): region = models.ForeignKey(Region) district = models.ForeignKey(District) temp_max = models.IntegerField(blank=True, null=True, verbose_name='Max temperature (C)') temp_min = models.IntegerField(blank=True, null=True, verbose_name='Min temperature (C)') and class Plan(model.model): name = tinymce_models.HTMLField(blank=True, null=True) region = models.ForeignKey(Region) district = models.ForeignKey(District) Provided for every region and district have unique row. I want to combine the result so that i can get all the columns of both tables These two Models are not related to each other. ' I need to make the join like join weather w on w.region = A.region and w.distric = A.district so that result contains all the columns in everyobject like obj.temp_max etc

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  • Python/Django tests running only one test at a time

    - by user2876296
    I have a unittest for my view class TestFromAllAdd(TestCase): fixtures = ['staging_accounts_user.json', 'staging_main_category.json', 'staging_main_dashboard.json', 'staging_main_location.json', 'staging_main_product.json', 'staging_main_shoppinglist.json'] def setUp(self): self.factory = RequestFactory() self.c = Client() self.c.login(username='admin', password='admin') def from_all_products_html404_test(self): request = self.factory.post('main/adding_from_all_products', {'product_id': ''}) request.user = User.objects.get(username= 'admin') response = adding_from_all_products(request) self.assertEqual(response.status_code, 404) But I have a few more classes with tests and I cant run them all at the same time: python manage.py test main doesnt run tests, but if i run; python manage.py test main.TestFromAllAdd.from_all_products_html404_test , runs one test;

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  • Django forms: where is POST data received?

    - by Rosarch
    I have a widget that allows user to enter data for a model field. The data in the form can't be directly converted to Python - it requires some coercion. Where do I put this code? Is the widget responsible for translating its post data to a python value? The field itself? I thought that maybe value_from_datadict() would be correct, but now it looks like that serves a different purpose. (I'm using the form in the admin interface, if it makes any difference.)

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  • Django get() query not working

    - by pimcoooooooo
    this_category = Category.objects.get(name=cat_name) gives error: get() takes exactly 2 non-keyword arguments (1 given) I am using the appengine helper, so maybe that is causing problems. Category is my model. Category.objects.all() works fine. Filter is also similarily not working. Thanks,

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  • Deleting files associated with model - django

    - by alexBrand
    I have the following code in one of my models class PostImage(models.Model): post = models.ForeignKey(Post, related_name="images") # @@@@ figure out a way to have image folders per user... image = models.ImageField(upload_to='images') image_infowindow = models.ImageField(upload_to='images') image_thumb = models.ImageField(upload_to='images') image_web = models.ImageField(upload_to='images') description = models.CharField(max_length=100) order = models.IntegerField(null=True) IMAGE_SIZES = { 'image_infowindow':(70,70), 'image_thumb':(100,100), 'image_web':(640,480), } def delete(self, *args, **kwargs): # delete files.. self.image.delete(save=False) self.image_thumb.delete(save=False) self.image_web.delete(save=False) self.image_infowindow.delete(save=False) super(PostImage, self).delete(*args, **kwargs) I am trying to delete the files when the delete() method is called on PostImage. However, the files are not being removed. As you can see, I am overriding the delete() method, and deleting each ImageField. For some reason however, the files are not being removed.

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  • How to setup a django site with Cherokee, DynDNS and virtual_env?

    - by e-satis
    I have a django project running with the dev server, and would like to try run it in a production environment. I wanted to try Cherokee for a change, so I installed it. We don't have a domain name yet, so I set up a DynDNS looking like stuff.gotdns.org. It works fine, I can see the Cherokee welcome page (so red, I first believed I got an error :-p). I ran the wizard to create a new virtual server for Django. No everything is setup, but I have nothing. Still the default Cherokee welcome page. What should I do now if I want to go to "http://stuff.gotdns.org" and see my website? What should I do now if I next want to make it available only at "http://project.stuff.gotdns.org"? Important fact, I use virtual_env, so your can call Python directly, you have to activate it first.

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  • Django, wsgi, py. what's the difference?

    - by Kenny
    I'm trying to get a django application up and running on my cpanel system. I've installed mod_wsgi, and am following the guide here: http://www.nerdydork.com/setting-up-django-on-a-whm-cpanel-vps-liquidweb.html However, I'm now confused as I don't know what to do next. The application has .py files, and I am able to run it via this: python manage.py runserver 211.144.131.148:8000 However, that's via command line and binds to port 8000. I want to use Apache instead. The question is, that tutorial doesn't go further into how to get apache to recognize .py files and run the application as I want it. What do I do next?

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  • What is a good CPU/PC setup to speed up intensive C++/templates compilation?

    - by ApplePieIsGood
    I currently have a machine with an Opteron 275 (2.2Ghz), which is a dual core CPU, and 4GB of RAM, along with a very fast hard drive. I find that when compiling even somewhat simple projects that use C++ templates (think boost, etc.), my compile times can take quite a while (minutes for small things, much longer for bigger projects). Unfortunately only one of the cores is pegged at 100%, so I know it's not the I/O, and it would seem that there is no way to take advantage of the other core for C++ compilation?

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  • What are the Rails best practices for javascript templates in restful/resourceful controllers?

    - by numbers1311407
    First, 2 common (basic) approaches: # returning from some FoosController method respond_to do |format| # 1. render the javascript directly format.js { render :json => @foo.to_json } # 2. render the default template, say update.js.erb format.js { render } end # in update.js.erb $('#foo').html("<%= escape_javascript(render(@foo)) %>") These are obviously simple cases but I wanted to illustrate what I'm talking about. I believe that these are also the cases expected by the default responder in rails 3 (either the action-named default template or calling to_#{format} on the resource.) The Issues With 1, you have total flexibility on the view side with no worries about the template, but you have to manipulate the DOM directly via javascript. You lose access to helpers, partials, etc. With 2, you have partials and helpers at your disposal, but you're tied to the one template (by default at least). All your views that make JS calls to FoosController use the same template, which isn't exactly flexible. Three Other Approaches (none really satisfactory) 1.) Escape partials/helpers I need into javascript beforehand, then inserting them into the page after, using string replacement to tailor them to the results returned (subbing in name, id, etc). 2.) Put view logic in the templates. For example, looking for a particular DOM element and doing one thing if it exists, another if it does not. 3.) Put logic in the controller to render different templates. For example, in a polymorphic belongs to where update might be called for either comments/foo or posts/foo, rendering commnts/foos/update.js.erb versus posts/foos/update.js.erb. I've used all of these (and probably others I'm not thinking of). Often in the same app, which leads to confusing code. Are there best practices for this sort of thing? It seems like a common enough use-case that you'd want to call controllers via Ajax actions from different views and expect different things to happen (without having to do tedious things like escaping and string-replacing partials and helpers client side). Any thoughts?

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  • Hooking up Sproutcore frontend and custom Python backend

    - by Suvir
    Hello everyone, I am building a web-based application. The frontend has been designed in Sproutcore. For the backend, we have our own python API which handles all transactions with multiple databases. What is the best way to hook up the front-end with the back-end. AFAIK django is pretty monolithic (correct me if i am wrong) and it would be cumbersome if I dont use its native ORM...I would prefer a python-based solution..any ideas? thanks! Suvir

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  • Why don't these class attributes register?

    - by slypete
    I have a factory method that generates django form classes like so: def get_indicator_form(indicator, patient): class IndicatorForm(forms.Form): #These don't work! indicator_id = forms.IntegerField(initial=indicator.id, widget=forms.HiddenInput()) patient_id = forms.IntegerField(initial=patient.id, widget=forms.HiddenInput()) def __init__(self, *args, **kwargs): forms.Form.__init__(self, *args, **kwargs) self.indicator = indicator self.patient = patient #These do! setattr(IndicatorForm, 'indicator_id', forms.IntegerField(initial=indicator.id, widget=forms.HiddenInput())) setattr(IndicatorForm, 'patient_id', forms.IntegerField(initial=patient.id, widget=forms.HiddenInput())) for field in indicator.indicatorfield_set.all(): setattr(IndicatorForm, field.name, copy(field.get_field_type())) return type('IndicatorForm', (forms.Form,), dict(IndicatorForm.__dict__)) I'm trying to understand why the top form field declarations don't work, but the setattr method below does work. I'm fairly new to python, so I suspect it's some language feature that I'm misunderstanding. Can you help me understand why the field declarations at the top of the class don't add the fields to the class? In a possibly related note, when these classes are instantiated, instance.media returns nothing even though some fields have widgets with associated media. Thanks, Pete

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  • Search over multiple fields

    - by schneck
    Hi there, I think I don't unterstand django-haystack properly: I have a data model containing several fields, and I would to have two of them searched: class UserProfile(models.Model): user = models.ForeignKey(User, unique=True, default=None) twitter_account = models.CharField(max_length=50, blank=False) My search index settings: class UserProfileIndex(SearchIndex): text = CharField(document=True, model_attr='user') twitter_account = CharField(model_attr='twitter_account') def get_queryset(self): """Used when the entire index for model is updated.""" return UserProfile.objects.all() But when I perform a search, only the field "username" is searched; "twitter_account" is ignored. When I select the Searchresults via dbshell, the objects contain the correct values for "user" and "twitter_account", but the result page shows a "no results": {% if query %} <h3>Results</h3> {% for result in page.object_list %} <p> <a href="{{ result.object.get_absolute_url }}">{{ result.object.id }}</a> </p> {% empty %} <p>No results</p> {% endfor %} {% endif %} Any ideas?

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  • How do I prevent a ManyToManyField('self') from linked an object to itself?

    - by dyve
    Consider this model (simplified for this question): class SecretAgentName(models.Model): name = models.CharField(max_length=100) aliases = ManyToManyField('self') I have three names, "James Bond", "007" and "Jason Bourne". "James Bond" and "007" are aliases of each other. This works exactly like I want it to, except for the fact that every instance can also be an alias of itself. This I want to prevent. So, there can be many SecretAgentNames, all can be aliases of each other as long as "James Bond" does not show up as an alias for "James Bond". Can I prevent this in the model definition? If not, can I prevent it anywhere else, preferably so that the Django Admin understands it?

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  • Removing a result from Queryset

    - by Enrico
    Is there a simple way to discard/remove the last result in a queryset without affecting the db? I am trying to paginate results in Django, but don't know the total number of objects for a given query. I was planning on using next/previous or older/newer links, so I only need to know if this is the first and/or last page. First is easy to check. To check for the last page I can compare the number of results with the pagesize or make a second query. The first method fails to detect the last page when the number of results in the last set equals the pagesize (ie 100 records get broken into 10 pages with the last page containing exactly 10 results) and I would like to avoid making a second query. My current thought is that I should fetch pagesize + 1 results from the db. If the queryset length equals 11, I know this is not the last page and I want to discard the last result in the queryset before passing the queryset to the template.

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  • Quering distinct values throught related model

    - by matheus.emm
    Hi! I have a simple one-to-many (models.ForeignKey) relationship between two of my model classes: class TeacherAssignment(models.Model): # ... some fields year = models.CharField(max_length=4) class LessonPlan(models.Model): teacher_assignment = models.ForeignKey(TeacherAssignment) # ... other fields I'd like to query my database to get the set of distinct years of TeacherAssignments related to at least one LessonPlan. I'm able to get this set using Django query API if I ignore the relation to LessonPlan: class TeacherAssignment(models.Model): # ... model's fields def get_years(self): year_values = self.objects.all().values_list('year').distinct().order_by('-year') return [yv[0] for yv in year_values if len(yv[0]) == 4] Unfortunately I don't know how to express the condition that the TeacherAssignment must be related to at least one LessonPlan. Any ideas how I'd be able to write the query? Thanks in advance.

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