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  • python multiprocessing member variable not set

    - by Jake
    In the following script, I get the "stop message received" output but the process never ends. Why is that? Is there another way to end a process besides terminate or os.kill that is along these lines? from multiprocessing import Process from time import sleep class Test(Process): def __init__(self): Process.__init__(self) self.stop = False def run(self): while self.stop == False: print "running" sleep(1.0) def end(self): print "stop message received" self.stop = True if __name__ == "__main__": test = Test() test.start() sleep(1.0) test.end() test.join()

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  • Javascript private member on prototype...

    - by Wilq32
    Well I tried to figure out is this possible in any way. Here is code: a=function(text) { var b=text; if (!arguments.callee.prototype.get) arguments.callee.prototype.get=function() { return b; } else alert('already created!'); } var c=new a("test"); // creates prototype instance of getter var d=new a("ojoj"); // alerts already created alert(c.get()) // alerts test alert(d.get()) // alerts test from context of creating prototype function :( As you see I tried to create prototype getter. For what? Well if you write something like this: a=function(text) { var b=text; this.getText=function(){ return b} } ... everything should be fine.. but in fact every time I create object - i create getText function that uses memory. I would like to have one prototypical function lying in memory that would do the same... Any ideas? EDIT: I tried solution given by Christoph, and it seems that its only known solution for now. It need to remember id information to retrieve value from context, but whole idea is nice for me :) Id is only one thing to remember, everything else can be stored once in memory. In fact you could store a lot of private members this way, and use anytime only one id. Actually this is satisfying me :) (unless someone got better idea). someFunc = function() { var store = new Array(); var guid=0; var someFunc = function(text) { this.__guid=guid; store[guid++]=text; } someFunc.prototype.getValue=function() { return store[this.__guid]; } return someFunc; }() a=new someFunc("test"); b=new someFunc("test2"); alert(a.getValue()); alert(b.getValue());

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  • Introducing the Metro User Interface on Windows 2012

    - by andywe
    Although I am a big fan of using PowerShell to do many of my server operations, that aspect is well covered by those far more knowledgeable than I, and there is vast information around the web already on that. The new Metro interface, and getting around both Windows 8 and Windows Server 2012 though is relatively new, even for those whop ran the previews. What is this? A blank Desktop!   Where did the start button go? Well, it is still there...sort of. It is hidden, and acts like an auto hidden component that appear only when the mouse is hovered over the lower left corner of the screen. Those familiar with Gnome or OSX can relate this to the "Hot Corners" functions. To get to the start button, hover your mouse in the very left corner of the task bar. Let it sit there a moment, and a small blue square with colored tiles in it called start will appear. Click it. I clicked it and now I have all the tiles..What is this?   Welcome to the Metro interface. This is a much more modern look, and although at first seems weird and cumbersome, I have actually found that it is a bit more extensible, allowing greater organization and customization than the older explorer desktop. If you look closely, you'll see each box represents either a program, or program group. First, a few basics about using the start view. First and foremost, a right mouse click will bring up a bar on the bottom, with an icon towards the right. Notice it is titled “All Apps”. An even easier way in many places is to hover your mouse in the exact opposite corner, in the upper right. A sidebar will open and expose what used to be a widget bar (remember Vista?), and there are options for Search, Start, and Settings.   Ok Great, but where is everything? It’s all there…Click the All Apps icon.   Look better? Notice the scroll bar at the bottom. Move it right..your desktop is sized to your content..so you can have a smaller, or larger amount of programs exposed. Each icon can be secondary clicked (right mouse click for most of us, and an options bar at the bottom, rather than the old small context menu, is opened with some very familiar options.   Notice the top of the Windows Explorer window has some new features. You still have your right mouse click functions, but since the shortcuts for these items already exist..just copy them. There are many ways, but here is a long way to show you more of the interface. 1. Right mouse click a program icon, and select the Open File Location option. 2. Trusty file manager opens…but if you look closely up at top edge of the window, you’ll see a nifty enhancement. An orange colored box that is titled Shortcut Tools and another lavender box Title Application tools. Each of these adds options at the top of the file manager window to make selection easy. Of course, you can still secondary click an item in the listing window too. 3. Click shortcut tools, right click your app shortcut and copy it. Then simply paste it into the desktop outside the File Explorer window Also note some of the newer features. The large icons up top below the menu that has many common operations. The options change as you select each menu item. Well, that’s it for this installment. I hope this helps you out.

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  • Ubuntu server 12.04 on AWS - How does the passwordless sudo work for the ubuntu user?

    - by aychedee
    I'm using Ubuntu server 12.04 on Amazon. I want to add a new user that has the same behaviour as the default ubuntu user. Specifically I want passwordless sudo for this new user. So I've added a new user and went to edit /etc/sudoers (using visudo of course). From reading that file it seemed like the default ubuntu user was getting it's passwordless sudo from being a member of the admin group. So I added my new user to that. Which didn't work. Then I tried adding the NOPASSWD directive to sudoers. Which also didn't work. Anyway, now I'm just curious. How does the ubuntu user get passwordless privileges if they aren't defined in /etc/sudoers. What is the mechanism that allows this?

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  • LINQ-to-SQL - Join, Count

    - by ile
    I have following query: var result = ( from role in db.Roles join user in db.Users on role.RoleID equals user.RoleID where user.CreatedByUserID == userID orderby user.FirstName ascending select new UserViewModel { UserID = user.UserID, PhotoID = user.PhotoID.ToString(), FirstName = user.FirstName, LastName = user.LastName, FullName = user.FirstName + " " + user.LastName, Email = user.Email, PhoneNumber = user.Phone, AccessLevel = role.Name }); Now, I need to modify this query... Other table I have is table Deals. I would like to count how many deals user created last month and last year. I tried something like this: var result = ( from role in db.Roles join user in db.Users on role.RoleID equals user.RoleID //join dealsYear in db.Deals on date.Year equals dealsYear.DateCreated.Year join dealsYear in ( from deal in db.Deals group deal by deal.DateCreated into d select new { DateCreated = d.Key, dealsCount = d.Count() } ) on date.Year equals dealsYear.DateCreated.Year into dYear join dealsMonth in ( from deal in db.Deals group deal by deal.DateCreated into d select new { DateCreated = d.Key, dealsCount = d.Count() } ) on date.Month equals dealsMonth.DateCreated.Month into dMonth where user.CreatedByUserID == userID orderby user.FirstName ascending select new UserViewModel { UserID = user.UserID, PhotoID = user.PhotoID.ToString(), FirstName = user.FirstName, LastName = user.LastName, FullName = user.FirstName + " " + user.LastName, Email = user.Email, PhoneNumber = user.Phone, AccessLevel = role.Name, DealsThisYear = dYear, DealsThisMonth = dMonth }); but here is even syntax not correct. Any idea? Btw, is there any good book of LINQ to SQL with examples?

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  • Prompt for user group when logging into OSX domain

    - by mattdwen
    When a user is a member of more than one group, when logging in to a 10.6 machine, it shows a prompt asking for what group to apply settings for. We're using the groups to mount different shares, e.g. Production and Accounts, based on user membership. Often, a user is a member of more than one group, and needs all the drives available. The Open Directory server is running 10.6 also. Is there a way to skip this prompt and apply settings for all groups. I can foresee that there may be conflicts between group settings, but perhaps a priority can be set too? Or is this totally the wrong way to go about this?

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  • ASP.NET Scheduler: How To Implement End-User Restrictions

    Check out this 2 step approach to prevent users from editing appointments in the ASPxScheduler: Step 1: Choose Restriction First decide which action in the ASPxScheduler you want to prevent. Heres a list of the available ones: AllowAppointmentConflicts AllowAppointmentCopy AllowAppointmentCreate AllowAppointmentDelete AllowAppointmentDrag AllowAppointmentDragBetweenResources AllowAppointmentEdit AllowAppointmentMultiSelect AllowAppointmentResize AllowInplaceEditor...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • SVN:Team member can checkout, commit; can't update

    - by Casey K.
    Hi all, got a weird problem for you: I've set up an svn server on a home machine, which is accessible to the members of my game team over DynDNS. So far so good- everyone was able to checkout the repo no problem. In addition, several team members and I were able to update and commit just fine. The conundrum is this: One of my team members, who is able to both checkout and commit, is unable to update. TortoiseSVN proffers: Error Could not open the requested SVN filesystem Has anyone dealt with this problem before? This isn't my first SVN rodeo, but I have to admit I'm stumped. Thanks!

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  • User authentication in Django. Problems with is_authenticated

    - by tim
    I have one problem with users menu. So, I want, that authenticated user can see his/her profile page and logout (links) in menu. It works (when I logging in) on index page: index, page1, profile, logout ,but, if I go to the, for example, page1 I can see in menu: index, page1, login, not profile and logout. How to fix it? in urls: url(r'^accounts/login/$', 'django.contrib.auth.views.login' ), url(r'^accounts/logout/$', 'django.contrib.auth.views.logout_then_login' ), url(r'^accounts/profile/$', 'my_app.views.profile' ), in views: def profile(request): if not request.user.is_authenticated(): return HttpResponseRedirect("/accounts/login/") else: user = request.user.is_authenticated() return render_to_response('profile.html',locals()) Part of index.html: {% if user.is_authenticated or request.user.is_authenticated %} <li><a href="/accounts/profile/">Profile</a></li> <li><a href="/accounts/logout/">logout</a></li> {% else %} <li><a href="/accounts/login/">login</a></li> {% endif %} login.html: {% extends "index.html" %} {% load url from future %} {% block application %} {% if form.errors %} <p>Try one more time</p> {% endif %} <form method="post" action="{% url 'django.contrib.auth.views.login' %}"> {% csrf_token %} <table> <tr> <td>{{ form.username.label_tag }}</td> <td>{{ form.username }}</td> </tr> <tr> <td>{{ form.password.label_tag }}</td> <td>{{ form.password }}</td> </tr> </table> <input type="submit" value="Login" /> <input type="hidden" name="next" value="{{ next }}" /> </form> {% endblock %} profile.html: {% extends "index.html" %} {% block application %} {% if request.user.is_authenticated %} <p>Welcome, {{ request.user.username }}. Thanks for logging in.</p> {% else %} <p>Welcome, new user. Please log in.</p> {% endif %} {% endblock %}

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  • Block complete network access for one local user

    - by tumchaaditya
    Well, this is quite trivial question but I could not find a satisfactory answer even after trying many search queries both here and on Google. I want to share my PC with my room-mate. And I don't want him to access ANY network(LAN included). So, I can create an account for him and block network access for the same. I would prefer avoiding any third-party tools as far as possible. It's a simple home PC hooked up to a router for internet. No domain and other stuff. (Technically, guest account can achieve this. But somehow, the guest account on my PC has network access!)

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  • Derived template override return type of member function C++

    - by Ruud v A
    I am writing matrix classes. Take a look at this definition: template <typename T, unsigned int dimension_x, unsigned int dimension_y> class generic_matrix { ... generic_matrix<T, dimension_x - 1, dimension_y - 1> minor(unsigned int x, unsigned int y) const { ... } ... } template <typename T, unsigned int dimension> class generic_square_matrix : public generic_matrix<T, dimension, dimension> { ... generic_square_matrix(const generic_matrix<T, dimension, dimension>& other) { ... } ... void foo(); } The generic_square_matrix class provides additional functions like matrix multiplication. Doing this is no problem: generic_square_matrix<T, 4> m = generic_matrix<T, 4, 4>(); It is possible to assign any square matrix to M, even though the type is not generic_square_matrix, due to the constructor. This is possible because the data does not change across children, only the supported functions. This is also possible: generic_square_matrix<T, 4> m = generic_square_matrix<T, 5>().minor(1,1); Same conversion applies here. But now comes the problem: generic_square_matrix<T, 4>().minor(1,1).foo(); //problem, foo is not in generic_matrix<T, 3, 3> To solve this I would like generic_square_matrix::minor to return a generic_square_matrix instead of a generic_matrix. The only possible way to do this, I think is to use template specialisation. But since a specialisation is basically treated like a separate class, I have to redefine all functions. I cannot call the function of the non-specialised class as you would do with a derived class, so I have to copy the entire function. This is not a very nice generic-programming solution, and a lot of work. C++ almost has a solution for my problem: a virtual function of a derived class, can return a pointer or reference to a different class than the base class returns, if this class is derived from the class that the base class returns. generic_square_matrix is derived from generic_matrix, but the function does not return a pointer nor reference, so this doesn't apply here. Is there a solution to this problem (possibly involving an entirely other structure; my only requirements are that the dimensions are a template parameter and that square matrices can have additional functionality). Thanks in advance, Ruud

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  • Returning a reference from a Class member?

    - by nebukadnezzar
    Hi, I've a class that basically looks like this: class App { public function newTemplate($filename, $vars=array()) { $smarty = new Smarty; $smarty->compile_dir = $this->template_compile_path; if(count($vars) > 0) { foreach($vars as $v_key => $v_name) { $smarty->assign($v_key, $v_name); } } return $smarty; } } However, when I create a Instance of 'App', the reference to $smarty seems broken, as every call to the membermethods don't seem to do anything: $app = new App; $tpl = $app->newTemplate("index.tmpl"); $tpl->assign("foo", "bar"); // {$foo} does not appear with "bar" in the template Now I wonder why? Of course I tried to use references: ... public function &newTemplate() ... ... But that doesn't work. Variable references don't seem to work either: ... $tpl = &$app->newTemplate("index.tmpl"); ... What is causing PHP here not to return a proper reference? Help is very appreciated!

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  • Problem accessing base member in derived constructor

    - by LeopardSkinPillBoxHat
    Given the following classes: class Foo { struct BarBC { protected: BarBC(uint32_t aKey) : mKey(aKey) mOtherKey(0) public: const uint32_t mKey; const uint32_t mOtherKey; }; struct Bar : public BarBC { Bar(uint32_t aKey, uint32_t aOtherKey) : BarBC(aKey), mOtherKey(aOtherKey) // Compile error here }; }; I am getting a compilation error at the point indicated: error: class `Foo::Bar' does not have any field named `mOtherKey'. Can anyone explain this? I suspect it's a syntactical problem due to my Bar class being defined within the Foo class, but can't seem to find a way around it. This is simple public inheritance, so mOtherKey should be accessible from the Bar constructor. Right? Or is it something to do with the fact that mOtherKey is const and I have already initialised it to 0 in the BarBC constructor?

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  • Cannot see user desktop when I log in

    - by Jesi
    I am very new to Ubuntu. I recently got a new laptop running Windows 7. I am using Virtual Box and just installed the Ubuntu 12.10 ISO as a new Virtual Machine within Virtual Box. Everything seemed to install just fine and I even added the Guest Additions under Devices. The problem is that I cannot see the menus and my login information. The virtual machine says it is running; however, I do not have the Applications, Places, System, etc. tray to select from. Is there something I am supposed to do after logging in to get this? I entered my password and everything seemed fine, I just don't have those drop-down menus available... Thank You! Jesi

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  • dao as a member of a servlet - normal?

    - by EugeneP
    I guess, DAO is thread safe, does not use any class members. So can it be used without any problem as a private field of a Servlet ? We need only one copy, and multiple threads can access it simultaneously, so why bother creating a local variable, right?

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  • Unity no longer loads in 13.04 for main user

    - by user152973
    When Ubuntu starts up, Unity fails to load (I can only see my desktop with no unity sidebar and no system bar in the top right). I tried the advice of Unity does not start in Ubuntu 13.04 which recommended the following commands: dconf reset -f /org/compiz/ unity --reset-icons &disown I ran the commands without errors an restarted the computer, but the problem persists. I am currently running Gnome. I have looked at other pages from the Google search "ubuntu unity failed to load 13.04", but the advice was similar to above and seems to be concerned with a system upgrade in April 18, 2013. I suspect my issue is something far more recent. Please give me advice on how to restore Unity on my account or at least figure out what the problem is. Thank you. Some information that might be relevant: -Unity has worked fine on 13.04 for the 6 months that I've had it until today. (November 10, 2013) -I have set up the update tool to automatically update when available. It is very possible that the system applied some updates without my knowledge. -Interestingly, Unity works fine on the Guest account. -I have made it so the system automatically logs me in at start-up. -This is a personal laptop. No one else has access to it. -I was not doing anything with the system settings or the terminal and have not installed any new software for the past 3 days. -I am running the System76 native Linux laptop Ultra Lemur. I did not contact their support yet because it seemed unlikely that this is a System76-specific error.

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  • Tips on how to notify a user of new features in your game (Android)

    - by brent777
    I have noticed a problem when releasing new features for a game that I wrote for Android and published on Google Play Store. Because my game is "stage-based" - and not a game like Hay Day, for example, where users will just go into the game every day since it can't really be finished - my users are not aware of new features that I release for the game. For example, if I publish a new version of my game and it contains a couple new stages, most of their devices will just auto-update the game and they don't even notice this and think to check out what's new. So this is why an approach like popping open a dialog that showcases the new feature(s) when they open the game for the first time after the update was done is not really sufficient. I am looking for some tips on an approach that will draw my users back into the game and then they could read more detail about new features on such a dialog. I was thinking of something like a notification that tells them to check out the new features after an update is done but I am not sure if this is a good idea. Any suggestions to help me solve this problem would be awesome.

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  • Call to a member function fetch_assoc() on a non-object

    - by Joann
    I'm a super beginner. I did find related questions here but I think they're too advanced for my skills. :-( Here's my function: function get_fname($un){ $registerquery = $this->conn->query("SELECT f_name FROM tz_members WHERE usr='".$un."'"); while ($row = $registerquery->fetch_assoc()) { return $fname = $row[$un]; } } Any help plsss??

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  • Request for member Name in something not a structure or Union

    - by Ashutosh
    Hey Folks, I am trying to Call the webservices in my app and while checking it in console it's showing the number of objects. (as i am using the Mutable array) and then while trying to display the name of the objects (here it's location) it's giving me an error in this line for (SDZArrayOfLocationWithLatestGrades* location in a) { NSLog(@" - %@", location.Name); // error here and a is the mutable array } PLease help me with this and Happy New Year to All!!!!!! Thanks,

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  • any ways saving user information without db

    - by hguser
    Hi: I have a application which require login,but the number of user who use the application is no more than 40. And In the application,I get some data from the sql server database where I juse have read permission,also I can not create a table in the db for user validate. ALso I do not think it is a good idea to create a user table in other database on another machine.(for example,I can create a user table in the mysql another machine,but is it desireable just for user validating)? Now I just save the user info in a .properties file,any other good idea? BTW,the programe language used in my application is java.

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  • Reducing unnecessary same values in Class member variables ....

    - by Freshblood
    class A { public int a; public int c; } i will create 10 instances from A.Then i will create 15 instances from A again... go on. first 10 instance will have same value for a variable and next 15 instances will have again same value for a.But I don't mean that both group has same values for a .Problem is create same a value 10 times in first group and 15 times in second group on memory unnecessary. What would be Best solution or solutions for reduce unnecessary datas in this situation?

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