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  • Memory management for "id<ProtocolName> variableName" type properties

    - by Malakim
    Hi, I'm having a problem with properties of the following type: id<ProtocolName> variableName; ..... ..... @property (nonatomic, retain) id<ProtocolName> variableName; I can access and use them just fine, but when I try to call [variableName release]; I get compiler warnings: '-release' not found in protocol(s) Do I need to define a release method in the interface, or how do I release the memory reserved for the variable? Thanks!

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  • How do I play a video through .net in windows 7

    - by Mykroft
    I had setup an app to play a video using the library suggested here this worked great for me for a long time until my machine was upgraded. In windows 7 I get the following exception that I'd never seen under XP: `System.BadImageFormatException: is not a valid Win32 application. (Exception from HRESULT: 0x800700C1) at MainApp.Controls.MediaControl.StopVideo() at System.Windows.Forms.Form.WmClose(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m) at System.Windows.Forms.NativeWindow.Callback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam)` I've installed the June 2010 DirectX SDK and I'm still getting this error. Is there a different library I should be using or some setting that needs to be changed?

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  • C++ static classes & shared_ptr memory leaks

    - by HardCoder1986
    Hello! I can't understand why does the following code produce memory leaks (I am using boost::shared_ptr with static class instance). Could someone help me? #include <crtdbg.h> #include <boost/shared_ptr.hpp> using boost::shared_ptr; #define _CRTDBG_MAP_ALLOC #define NEW new(_NORMAL_BLOCK, __FILE__, __LINE__) static struct myclass { static shared_ptr<int> ptr; myclass() { ptr = shared_ptr<int>(NEW int); } } myclass_instance; shared_ptr<int> myclass::ptr; int main() { _CrtSetDbgFlag(_CRTDBG_ALLOC_MEM_DF | _CRTDBG_LEAK_CHECK_DF | _CRTDBG_CHECK_ALWAYS_DF | _CrtSetDbgFlag(_CRTDBG_REPORT_FLAG)); return 0; }

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  • how free of memory happen in this case???

    - by Riyaz
    #include <stdio.h> void func(int arr[],int xNumOfElem) { int j; for(j=0; j<xNumOfElem; j++) { arr[j] = j + arr[j]; printf("%d\t",arr[j]); } printf("\n"); } int main() { int *a,k; a = (int*) malloc(sizeof(int)*10); for(k = 0; k<10; k++) { a[k] = k; printf("%d\t",a[k]); } printf("\n"); func(a,10); //Func call free(a); } Inside the the function "func" who will allocate/deallocate memory for dynamic array "arr". arr is an function argument.

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  • Why is memory management so visible in Java?

    - by Emil
    I'm playing around with writing some simple Spring-based web apps and deploying them to Tomcat. Almost immediately, I run into the need to customize the Tomcat's JVM settings with -XX:MaxPermSize (and -Xmx and -Xms); without this, the server easily runs out of PermGen space. Why is this such an issue for Java compared to other garbage collected languages? Comparing counts of "tune X memory usage" for X in Java, Ruby, Perl and Python, shows that Java has easily an order of magnitude more hits in Google than the other languages combined.

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  • Controlling read and write access width to memory mapped registers in C

    - by srking
    I'm using and x86 based core to manipulate a 32-bit memory mapped register. My hardware behaves correctly only if the CPU generates 32-bit wide reads and writes to this register. The register is aligned on a 32-bit address and is not addressable at byte granularity. What can I do to guarantee that my C (or C99) compiler will only generate full 32-bit wide reads and writes in all cases? For example, if I do a read-modify-write operation like this: volatile uint32_t* p_reg = 0xCAFE0000; *p_reg |= 0x01; I don't want the compiler to get smart about the fact that only the bottom byte changes and generate 8-bit wide read/writes. Since the machine code is often more dense for 8-bit operations on x86, I'm afraid of unwanted optimizations. Disabling optimizations in general is not an option.

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  • Formula for Live Video Streaming Bitrate

    - by MD
    I am simply looking for the formula that should be used here. All the results I've found base "finding the bitrate" off of already existing video. I'm talking about LIVE streaming. (indeterminate length) So, I know some basic parts of it, but I just need to know if I'm right or missing anything. For Kbps: Resolution * Framerate / 1024 Is it really that simple? Audio would be a separate element for our purposes here. Am I missing anything from this formula? (Coming up with a proposal of what amount of bandwidth would be required, relative to possible resolution options, so I just need to be sure that I'm not missing anything or inaccurate about it)

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  • c: memory allocation (what's going on)

    - by facha
    Hi, everyone Please take a look at this piece of code. I'm allocating one byte for the first variable and another byte for the second one. However, it seems like the compiler allocates more (or I'm missing something). The program outputs both strings, even though their length is more the one byte. void main() { char* some1 = malloc(1); sprintf(some1,"cool"); char* some2 = malloc(1); sprintf(some2,"face"); printf("%s ",some1); printf("%s\n",some2); } Please, could anyone spot some light on what's going on when memory is being allocated.

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  • Allocating memory for a array to char pointer

    - by nunos
    The following piece of code gives a segmentation fault when allocating memory for the last arg. What am I doing wrong? Thanks. int n_args = 0, i = 0; while (line[i] != '\0') { if (isspace(line[i++])) n_args++; } for (i = 0; i < n_args; i++) command = malloc (n_args * sizeof(char*)); char* arg = NULL; arg = strtok(line, " \n"); while (arg != NULL) { arg = strtok(NULL, " \n"); command[i] = malloc ( (strlen(arg)+1) * sizeof(char) ); strcpy(command[i], arg); i++; } Thanks.

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  • Kepping object in memory (iPhone SDK)

    - by Chris
    I am trying to create a UIImageView called theImageView in the touchesBegan method that I can then then move to a new location in touchesMoved. Currently I am receiving an "undeclared" error in touchesMoved where I set the new location for theImageView. What can I do to keep theImageView in memory between these two methods? - (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { ... UIImageView *theImageView = [[UIImageView alloc] initWithImage:[UIImage imageNamed:@"image.png"]]; theImageView.frame = CGRectMake(263, 228, 193, 300); [theImageView retain]; ... } - (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { ... theImageView.frame = CGRectMake(300, 300, 193, 300); ... }

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  • What is the cost of memory access?

    - by Jurily
    We like to think that a memory access is fast and constant, but on modern architectures/OSes, that's not necessarily true. Consider the following C code: int i = 34; int *p = &i; // do something that may or may not involve i and p {...} // 3 days later: *p = 643; What is the estimated cost of this last assignment in CPU instructions, if i is in L1 cache, i is in L2 cache, i is in L3 cache, i is in RAM proper, i is paged out to an SSD disk, i is paged out to a traditional disk? Where else can i be? Of course the numbers are not absolute, but I'm only interested in orders of magnitude. I tried searching the webs, but Google did not bless me this time.

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  • Referencing invalid memory locations with C++ Iterators

    - by themoondothshine
    I am a big fan of GCC, but recently I noticed a vague anomaly. Using __gnu_cxx::__normal_iterator (ie, the most common iterator type used in libstdc++, the C++ STL) it is possible to refer to an arbitrary memory location and even change its value without causing an exception! Is this expected behavior? If so, isn't a security loophole? Here's an example: #include <iostream> using namespace std; int main() { basic_string<char> str("Hello world!"); basic_string<char>::iterator iter = str.end(); iter += str.capacity() + 99999; *iter = 'x'; cout << "Value: " << *iter << endl; }

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  • Keeping object in memory (iPhone SDK)

    - by Chris
    I am trying to create a UIImageView called theImageView in the touchesBegan method that I can then then move to a new location in touchesMoved. Currently I am receiving an "undeclared" error in touchesMoved where I set the new location for theImageView. What can I do to keep theImageView in memory between these two methods? - (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { ... UIImageView *theImageView = [[UIImageView alloc] initWithImage:[UIImage imageNamed:@"image.png"]]; theImageView.frame = CGRectMake(263, 228, 193, 300); [theImageView retain]; ... } - (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { ... theImageView.frame = CGRectMake(300, 300, 193, 300); ... }

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  • Read data from specific memory address

    - by rapid
    Hello. How can I read (and put into new variable) data stored at specific memory address? For instance I know that: <nfqueue.queue; proxy of <Swig Object of type 'queue *' at 0xabd2b00> > And I want to have data stored at 0xabd2b00 in new variable so that I can work and use all functionalities of the object. Let's assume that I don't have access to the original variable that created this object.

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  • An explanation of memory usage on Windows server 2003

    - by Rich
    Hi, We've been working on a bit of puzzle at work. We have an application service installed on two machines, both running Windows server 2003. These services do exactly the same thing. However once loaded, one of the services uses 200mb less than the other service. We're at a bit of a loss to what might be causing this discrepancy. I was wondering if there was some kind of server setting that would cause an application to use more memory (heap block size) or anything to explain this. If anyone has any ideas on what may be causing this, or how to find out what is causing this I'd be very grateful. Cheers Rich

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  • How to find out where my memory is going

    - by the_mandrill
    I've got the situation where the cycle of loading and then closing a document eats up a few Mb of RAM. This memory isn't being leaked as something owns it and cleans it up when the app exits (Visual Leak Detector and the Mac Leaks tool show agreement on this). However, I'd like to find out where it's going. I'm assuming it's some sort of cache in the application that gets populated when the document loads but not freed when the document is closed. Which methods or tools could I use to find out where these allocations are being made?

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  • Convert .3GP and .3G2 Files to AVI / MPEG for Free

    - by DigitalGeekery
    3GP and .3G2 are common video capture formats used on many mobile phones, but they may not be supported by your favorite media player. Today we’ll show you a quick and easy way to convert those files to AVI or MPG format with the free Windows application, Pazera Free 3GP to AVI Converter. Download the Pazera Free 3GP to AVI Converter. You’ll have to unzip the download folder, but there is no need to install the application. Just double-click the 3gptoavi.exe file to run the application. To add your 3GP or 3G2 files to the queue to be converted, click on the Add files  button at the top left. Browse for your file, and click Open.   Your video will be added to the Queue. You can add multiple files to the queue and convert them all at one time.   Most users will find it preferable to use one of the pre-configured profiles for their conversion settings. To load a profile, choose one from the Profile drop down list and then click the Load button. You will see the profile update the settings in the panels at the bottom of the application. We tested Pazera Free 3GP to AVI Converter with 3GP files recorded on a Motorola Droid, and found the AVI H.264 Very High Q. profile to return the best results for AVI output, and the MPG – DVD NTSC: MPEG-2 the best results for MPG output. Other profiles produced smaller file sizes, but at a cost of reduced quality video output.   More advanced users may tweak video and audio settings to their liking in the lower panels. Click on the AVI button under Output file format / Video settings to adjust settings AVI… Or the MPG button to adjust the settings for MPG output. By default, the converted file will be output to the same location as the input directory. You can change it by clicking the text box input radio button and browsing for a different folder. When you’ve chosen your settings, click Convert to begin the conversion process.   A conversion output box will open and display the progress. When finished, click Close. Now you’re ready to enjoy your video in your favorite media player. Pazera Free 3GP to AVI Converter isn’t the most robust media conversion tool, but it does what it is intended to do. It handles the task of 3GP to AVI / MPG conversion very well. It’s easy enough for the beginner to manage without much trouble, but also has enough options to please more experienced users. Download Pazera Free 3GP to AVI Converter Similar Articles Productive Geek Tips How To Convert Video Files to MP3 with VLCEasily Change Audio File Formats with XRECODEConvert PDF Files to Word Documents and Other FormatsConvert Video and Remove Commercials in Windows 7 Media Center with MCEBuddy 1.1Compress Large Video Files with DivX / Xvid and AutoGK TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Install, Remove and HIDE Fonts in Windows 7 Need Help with Your Home Network? Awesome Lyrics Finder for Winamp & Windows Media Player Download Videos from Hulu Pixels invade Manhattan Convert PDF files to ePub to read on your iPad

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  • How to avoid reallocation using the STL (C++)

    - by Tue Christensen
    This question is derived of the topic: http://stackoverflow.com/questions/2280655/vector-reserve-c I am using a datastructur of the type vector<vector<vector<double> > >. It is not possible to know the size of each of these vector (except the outer one) before items (doubles) are added. I can get an approximate size (upper bound) on the number of items in each "dimension". A solution with the shared pointers might be the way to go, but I would like to try a solution where the vector<vector<vector<double> > > simply has .reserve()'ed enough space (or in some other way has allocated enough memory). Will A.reserve(500) (assumming 500 is the size or, alternatively an upper bound on the size) be enough to hold "2D" vectors of large size, say [1000][10000]? The reason for my question is mainly because I cannot see any way of reasonably estimating the size of the interior of A at the time of .reserve(500). An example of my question: vector A; A.reserve(500+1); vector temp2; vector temp1 (666,666); for(int i=0;i<500;i++) { A.push_back(temp2); for(int j=0; j< 10000;j++) { A.back().push_back(temp1); } } Will this ensure that no reallocation is done for A? If temp2.reserve(100000) and temp1.reserve(1000) where added at creation will this ensure no reallocation at all will occur at all? In the above please disregard the fact that memory could be wasted due to conservative .reserve() calls. Thank you all in advance!

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  • is this uibutton autoreleased ?

    - by dubbeat
    HI This is just a question to check my sanity really. I'm hunting memory leaks that show up in instruments but not the static analyzer. In one spot the analyzer is pointing to this block of code UIButton *randomButton = [UIButton buttonWithType:UIButtonTypeRoundedRect ]; randomButton.frame = CGRectMake(205, 145, 90, 22); // size and position of button [randomButton setTitle:@"Random" forState:UIControlStateNormal]; randomButton.backgroundColor = [UIColor clearColor]; randomButton.adjustsImageWhenHighlighted = YES; [randomButton addTarget:self action:@selector(getrandom:) forControlEvents:UIControlEventTouchUpInside]; [self.view addSubview:randomButton]; For some reason I thought the above code would auto release the button because I'm not calling init or alloc? If I add [randombutton release] at the bottom of the code my button fails to show. Could somebody describe to me the correct way to release a button from memory that is created in the above way? Or would I be better off making the button a class variable and sticking the release in the dealloc method?

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  • Traditional IO vs memory-mapped

    - by Senne
    I'm trying to illustrate the difference in performance between traditional IO and memory mapped files in java to students. I found an example somewhere on internet but not everything is clear to me, I don't even think all steps are nececery. I read a lot about it here and there but I'm not convinced about a correct implementation of neither of them. The code I try to understand is: public class FileCopy{ public static void main(String args[]){ if (args.length < 1){ System.out.println(" Wrong usage!"); System.out.println(" Correct usage is : java FileCopy <large file with full path>"); System.exit(0); } String inFileName = args[0]; File inFile = new File(inFileName); if (inFile.exists() != true){ System.out.println(inFileName + " does not exist!"); System.exit(0); } try{ new FileCopy().memoryMappedCopy(inFileName, inFileName+".new" ); new FileCopy().customBufferedCopy(inFileName, inFileName+".new1"); }catch(FileNotFoundException fne){ fne.printStackTrace(); }catch(IOException ioe){ ioe.printStackTrace(); }catch (Exception e){ e.printStackTrace(); } } public void memoryMappedCopy(String fromFile, String toFile ) throws Exception{ long timeIn = new Date().getTime(); // read input file RandomAccessFile rafIn = new RandomAccessFile(fromFile, "rw"); FileChannel fcIn = rafIn.getChannel(); ByteBuffer byteBuffIn = fcIn.map(FileChannel.MapMode.READ_WRITE, 0,(int) fcIn.size()); fcIn.read(byteBuffIn); byteBuffIn.flip(); RandomAccessFile rafOut = new RandomAccessFile(toFile, "rw"); FileChannel fcOut = rafOut.getChannel(); ByteBuffer writeMap = fcOut.map(FileChannel.MapMode.READ_WRITE,0,(int) fcIn.size()); writeMap.put(byteBuffIn); long timeOut = new Date().getTime(); System.out.println("Memory mapped copy Time for a file of size :" + (int) fcIn.size() +" is "+(timeOut-timeIn)); fcOut.close(); fcIn.close(); } static final int CHUNK_SIZE = 100000; static final char[] inChars = new char[CHUNK_SIZE]; public static void customBufferedCopy(String fromFile, String toFile) throws IOException{ long timeIn = new Date().getTime(); Reader in = new FileReader(fromFile); Writer out = new FileWriter(toFile); while (true) { synchronized (inChars) { int amountRead = in.read(inChars); if (amountRead == -1) { break; } out.write(inChars, 0, amountRead); } } long timeOut = new Date().getTime(); System.out.println("Custom buffered copy Time for a file of size :" + (int) new File(fromFile).length() +" is "+(timeOut-timeIn)); in.close(); out.close(); } } When exactly is it nececary to use RandomAccessFile? Here it is used to read and write in the memoryMappedCopy, is it actually nececary just to copy a file at all? Or is it a part of memorry mapping? In customBufferedCopy, why is synchronized used here? I also found a different example that -should- test the performance between the 2: public class MappedIO { private static int numOfInts = 4000000; private static int numOfUbuffInts = 200000; private abstract static class Tester { private String name; public Tester(String name) { this.name = name; } public long runTest() { System.out.print(name + ": "); try { long startTime = System.currentTimeMillis(); test(); long endTime = System.currentTimeMillis(); return (endTime - startTime); } catch (IOException e) { throw new RuntimeException(e); } } public abstract void test() throws IOException; } private static Tester[] tests = { new Tester("Stream Write") { public void test() throws IOException { DataOutputStream dos = new DataOutputStream( new BufferedOutputStream( new FileOutputStream(new File("temp.tmp")))); for(int i = 0; i < numOfInts; i++) dos.writeInt(i); dos.close(); } }, new Tester("Mapped Write") { public void test() throws IOException { FileChannel fc = new RandomAccessFile("temp.tmp", "rw") .getChannel(); IntBuffer ib = fc.map( FileChannel.MapMode.READ_WRITE, 0, fc.size()) .asIntBuffer(); for(int i = 0; i < numOfInts; i++) ib.put(i); fc.close(); } }, new Tester("Stream Read") { public void test() throws IOException { DataInputStream dis = new DataInputStream( new BufferedInputStream( new FileInputStream("temp.tmp"))); for(int i = 0; i < numOfInts; i++) dis.readInt(); dis.close(); } }, new Tester("Mapped Read") { public void test() throws IOException { FileChannel fc = new FileInputStream( new File("temp.tmp")).getChannel(); IntBuffer ib = fc.map( FileChannel.MapMode.READ_ONLY, 0, fc.size()) .asIntBuffer(); while(ib.hasRemaining()) ib.get(); fc.close(); } }, new Tester("Stream Read/Write") { public void test() throws IOException { RandomAccessFile raf = new RandomAccessFile( new File("temp.tmp"), "rw"); raf.writeInt(1); for(int i = 0; i < numOfUbuffInts; i++) { raf.seek(raf.length() - 4); raf.writeInt(raf.readInt()); } raf.close(); } }, new Tester("Mapped Read/Write") { public void test() throws IOException { FileChannel fc = new RandomAccessFile( new File("temp.tmp"), "rw").getChannel(); IntBuffer ib = fc.map( FileChannel.MapMode.READ_WRITE, 0, fc.size()) .asIntBuffer(); ib.put(0); for(int i = 1; i < numOfUbuffInts; i++) ib.put(ib.get(i - 1)); fc.close(); } } }; public static void main(String[] args) { for(int i = 0; i < tests.length; i++) System.out.println(tests[i].runTest()); } } I more or less see whats going on, my output looks like this: Stream Write: 653 Mapped Write: 51 Stream Read: 651 Mapped Read: 40 Stream Read/Write: 14481 Mapped Read/Write: 6 What is makeing the Stream Read/Write so unbelievably long? And as a read/write test, to me it looks a bit pointless to read the same integer over and over (if I understand well what's going on in the Stream Read/Write) Wouldn't it be better to read int's from the previously written file and just read and write ints on the same place? Is there a better way to illustrate it? I've been breaking my head about a lot of these things for a while and I just can't get the whole picture..

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  • Memory limit for running external executables within Asp.net

    - by itsbalur
    I am using WkhtmltoPdf in my C# web application running in .NET 4.0 to generate PDFs from HTML files. In general everything works fine except when the size of the HTML file is below 250KB. Once the HTML file size increases beyond that, the process which runs the wkhtmltopdf.exe gives an exception as below. On the Task Manager, I have seen that the Memory value for the wkhtmltopdf.exe process does not increase beyond a value of 40,096 K, which I believe is the reason why the process is abandoned in between. How can we configure such that the memory limit for external exes can be increased? Is there any other way of solving this issue? More info: When I run the conversion from the command line directly, the PDF is generated fine. So, its unlikely to be a problem with WkhtmlToPdf. The error is from localhost. I have tried the same on the DEV server, with the same result. Exception: > [Exception: Loading pages (1/6) [> > ] 0% [======> ] > 10% [======> ] 11% > [=======> ] 13% > [=========> ] 15% > [==========> ] 18% > [============> ] 20% > [=============> ] 22% > [==============> ] 24% > [===============> ] 26% > [=================> ] 29% > [==================> ] 31% > [===================> ] 33% > [=====================> ] 35% > [======================> ] 37% > [========================> ] 40% > [=========================> ] 42% > [==========================> ] 44% > [============================> ] 47% > [=============================> ] 49% > [==============================> ] 51% > [============================================================] 100% > Counting pages (2/6) > [============================================================] Object > 1 of 1 Resolving links (4/6) > [============================================================] Object > 1 of 1 Loading headers and footers (5/6) > Printing pages (6/6) [> > ] Preparing [=> > ] Page 1 of 49 [==> > ] Page 2 of 49 [===> > ] Page 3 of 49 [====> > ] Page 4 of 49 [======> > ] Page 5 of 49 [=======> > ] Page 6 of 49 [========> > ] Page 7 of 49 [=========> > ] Page 8 of 49 [==========> > ] Page 9 of 49 [============> > ] Page 10 of 49 [=============> > ] Page 11 of 49 [==============> > ] Page 12 of 49 [===============> > ] Page 13 of 49 [================> > ] Page 14 of 49 [==================> > ] Page 15 of 49 [===================> > ] Page 16 of 49 [====================> > ] Page 17 of 49 [=====================> > ] Page 18 of 49 [======================> > ] Page 19 of 49 [========================> > ] Page 20 of 49 [=========================> > ] Page 21 of 49 [==========================> > ] Page 22 of 49 [===========================> > ] Page 23 of 49 [============================> > ] Page 24 of 49 [==============================> > ] Page 25 of 49 [===============================> > ] Page 26 of 49 [=================================> > ] Page 27 of 49 [==================================> > ] Code that I use: var fileName = " - "; var wkhtmlDir = ConfigurationManager.AppSettings[Constants.AppSettings.ExportToPdfExecutablePath]; var wkhtml = ConfigurationManager.AppSettings[Constants.AppSettings.ExportToPdfExecutablePath] + "\\wkhtmltopdf.exe"; var p = new Process(); string switches = ""; switches += "--print-media-type "; switches += "--margin-top 10mm --margin-bottom 10mm --margin-right 5mm --margin-left 5mm "; switches += "--page-size A4 "; switches += "--disable-smart-shrinking "; var startInfo = new ProcessStartInfo { CreateNoWindow = true, FileName = wkhtml, Arguments = switches + " " + url + " " + fileName, UseShellExecute = false, RedirectStandardOutput = true, RedirectStandardError = true, RedirectStandardInput=true, WorkingDirectory=wkhtmlDir }; p.StartInfo = startInfo; p.Start();

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  • Using the Onboard VGA output with a PCIe video card. Both nVidia

    - by sebikul
    I have 2 video cards, one On board, a nVidia 6150SE nForce 430 and a PCIe nVidia GeForce GT 220 1GB DDR2 RAM I have already configured the PCIe card to use the dual monitor feature, using the VGA and HDMI ports, but now I want to add a third monitor, using the On board VGA port I have managed to enable the On board graphics processor, which is taking 400MB of ram, but I cant manage to use it, nvidia-settings does not detect it, like it's not usable (but is there) My questions are the following: How can I manage to get the On board VGA display to work together with the PCIe graphics card? If possible, how can I recover those 400 MB the on board card is taking (even without being used) or how can I get it to use the PCIe card available memory? System Details: Linux 2.6.35-28-generic i686 Ubuntu 10.10 (All updates installed) NVIDIA Driver Version: 260.19.06 (Official) If more info is needed please let me know. Here is the lspci output when the On board card is disabled: 00:00.0 RAM memory: nVidia Corporation MCP61 Memory Controller (rev a1) 00:01.0 ISA bridge: nVidia Corporation MCP61 LPC Bridge (rev a2) 00:01.1 SMBus: nVidia Corporation MCP61 SMBus (rev a2) 00:01.2 RAM memory: nVidia Corporation MCP61 Memory Controller (rev a2) 00:01.3 Co-processor: nVidia Corporation MCP61 SMU (rev a2) 00:02.0 USB Controller: nVidia Corporation MCP61 USB Controller (rev a3) 00:02.1 USB Controller: nVidia Corporation MCP61 USB Controller (rev a3) 00:04.0 PCI bridge: nVidia Corporation MCP61 PCI bridge (rev a1) 00:05.0 Audio device: nVidia Corporation MCP61 High Definition Audio (rev a2) 00:06.0 IDE interface: nVidia Corporation MCP61 IDE (rev a2) 00:07.0 Bridge: nVidia Corporation MCP61 Ethernet (rev a2) 00:08.0 IDE interface: nVidia Corporation MCP61 SATA Controller (rev a2) 00:09.0 PCI bridge: nVidia Corporation MCP61 PCI Express bridge (rev a2) 00:0b.0 PCI bridge: nVidia Corporation MCP61 PCI Express bridge (rev a2) 00:0c.0 PCI bridge: nVidia Corporation MCP61 PCI Express bridge (rev a2) 00:0d.0 VGA compatible controller: nVidia Corporation C61 [GeForce 6150SE nForce 430] (rev a2) 00:18.0 Host bridge: Advanced Micro Devices [AMD] K8 [Athlon64/Opteron] HyperTransport Technology Configuration 00:18.1 Host bridge: Advanced Micro Devices [AMD] K8 [Athlon64/Opteron] Address Map 00:18.2 Host bridge: Advanced Micro Devices [AMD] K8 [Athlon64/Opteron] DRAM Controller 00:18.3 Host bridge: Advanced Micro Devices [AMD] K8 [Athlon64/Opteron] Miscellaneous Control 01:09.0 Ethernet controller: Intel Corporation 82557/8/9/0/1 Ethernet Pro 100 (rev 08) 02:00.0 VGA compatible controller: nVidia Corporation GT216 [GeForce GT 220] (rev a2) 02:00.1 Audio device: nVidia Corporation High Definition Audio Controller (rev a1) And this is when both are enabled: 00:00.0 RAM memory: nVidia Corporation MCP61 Memory Controller (rev a1) 00:01.0 ISA bridge: nVidia Corporation MCP61 LPC Bridge (rev a2) 00:01.1 SMBus: nVidia Corporation MCP61 SMBus (rev a2) 00:01.2 RAM memory: nVidia Corporation MCP61 Memory Controller (rev a2) 00:01.3 Co-processor: nVidia Corporation MCP61 SMU (rev a2) 00:02.0 USB Controller: nVidia Corporation MCP61 USB Controller (rev a3) 00:02.1 USB Controller: nVidia Corporation MCP61 USB Controller (rev a3) 00:04.0 PCI bridge: nVidia Corporation MCP61 PCI bridge (rev a1) 00:05.0 Audio device: nVidia Corporation MCP61 High Definition Audio (rev a2) 00:06.0 IDE interface: nVidia Corporation MCP61 IDE (rev a2) 00:07.0 Bridge: nVidia Corporation MCP61 Ethernet (rev a2) 00:08.0 IDE interface: nVidia Corporation MCP61 SATA Controller (rev a2) 00:09.0 PCI bridge: nVidia Corporation MCP61 PCI Express bridge (rev a2) 00:0b.0 PCI bridge: nVidia Corporation MCP61 PCI Express bridge (rev a2) 00:0c.0 PCI bridge: nVidia Corporation MCP61 PCI Express bridge (rev a2) 00:0d.0 VGA compatible controller: nVidia Corporation C61 [GeForce 6150SE nForce 430] (rev a2) 00:18.0 Host bridge: Advanced Micro Devices [AMD] K8 [Athlon64/Opteron] HyperTransport Technology Configuration 00:18.1 Host bridge: Advanced Micro Devices [AMD] K8 [Athlon64/Opteron] Address Map 00:18.2 Host bridge: Advanced Micro Devices [AMD] K8 [Athlon64/Opteron] DRAM Controller 00:18.3 Host bridge: Advanced Micro Devices [AMD] K8 [Athlon64/Opteron] Miscellaneous Control 01:09.0 Ethernet controller: Intel Corporation 82557/8/9/0/1 Ethernet Pro 100 (rev 08) 02:00.0 VGA compatible controller: nVidia Corporation GT216 [GeForce GT 220] (rev a2) 02:00.1 Audio device: nVidia Corporation High Definition Audio Controller (rev a1) Output of lshw -class display: *-display description: VGA compatible controller product: GT216 [GeForce GT 220] vendor: nVidia Corporation physical id: 0 bus info: pci@0000:02:00.0 version: a2 width: 64 bits clock: 33MHz capabilities: pm msi pciexpress vga_controller bus_master cap_list rom configuration: driver=nvidia latency=0 resources: irq:18 memory:df000000-dfffffff memory:c0000000-cfffffff memory:da000000-dbffffff ioport:ef80(size=128) memory:def80000-deffffff *-display description: VGA compatible controller product: C61 [GeForce 6150SE nForce 430] vendor: nVidia Corporation physical id: d bus info: pci@0000:00:0d.0 version: a2 width: 64 bits clock: 66MHz capabilities: pm msi vga_controller bus_master cap_list rom configuration: driver=nvidia latency=0 resources: irq:22 memory:dd000000-ddffffff memory:b0000000-bfffffff memory:dc000000-dcffffff memory:deb40000-deb5ffff If what I'm looking for is not possible, please tell me, so I can disable the On board card and recover those 400MB of wasted RAM Thanks for your help!

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  • Is it the address bus size or the data bus size that determines "8-bit , 16-bit ,32-bit ,64-bit " systems?

    - by learner
    My simple understanding is as follows. Memory (RAM) is composed of bits, groups of 8 which form bytes, each of which can be addressed ,and hence byte addressable memory. Address Bus stores the location of a byte of memory. If an address bus is of size 32 bits, that means it can hold upto 232 numbers and it hence can refer upto 232 bytes of memory = 4GB of memory and any memory greater than that is useless. Data bus is used to send the value to be written to/read off the memory. If I have a data bus of size 32 bits, it means a maximum of 4 bytes can be written to/read off the memory at a time. I find no relation between this size and the maximum memory size possible. But I read here that: Even though most systems are byte-addressable, it makes sense for the processor to move as much data around as possible. This is done by the data bus, and the size of the data bus is where the names 8-bit system, 16-bit system, 32-bit system, 64-bit system, etc.. come from. When the data bus is 8 bits wide, it can transfer 8 bits in a single memory operation. When the data bus is 32 bits wide (as is most common at the time of writing), at most, 32 bits can be moved in a single memory operation. This says that the size of the data bus is what gives an OS the name, 8bit, 16bit and so on. What is wrong with my understanding?

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  • GA 8KNXP Rev1.0: 4 GB installed, only 3.5 GB recognized by BIOS

    - by hurikhan77
    I've installed 2x 1 GB and 4x 512 MB memory into my GA-8KNXP system which would sum up to 4 GB. The specification from the manual says: Maximum memory support: 4 GB. If all six slots are utilized, slot 5+6 may only equipped with single-sided RAM modules. And so I did. Anyway: The BIOS counts up to 3.5 GB and finishes there. Also my Linux system reports only 3.5 GB of memory although 4 GB memory support is activated in the kernel. So I suppose this is a memory mapping issue or a hardware issue. I've tried removing only on of the 512 MB memory modules leaving 5 modules in place. But that just stopped the system from powering on correctly (screen stays black although fans and leds come to live). Dual Channel was detected and enabled so the system technically found all 6 modules. "dmidecode" in Linux reports only memory in slots 1 to 4 and ignores slots 5+6, so it only detects 3 GB of memory. It also says the system would support up to 16 GB of memory with 4 GB modules per slot. I think technically the chipset should be able to offer and utilize the complete 4 GB memory range. Any clues what else I could check? Or do I have just to live with 0.5 GB wasted memory?

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