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  • How to properly match the following message id format in a case statement

    - by hsatterwhite
    I'm trying to get this regex pattern working in a case statement to match a particular type of ID, which could be passed to the script. I need to match the exact number of alphanumeric characters with the dashes to differentiate this message id from anything else, which may be passed to this bash script. An example of the message id format: c7c3e910-c9d2-71e1-0999-0aec446b0000 #!/bin/bash until [ -z "$1" ] do case "$1" in "") echo "No value passed" ;; [a-z0-9]\{8\}-[a-z0-9]\{4\}-[a-z0-9]\{4\}-[a-z0-9]\{4\}-[a-z0-9]\{12\}) echo "Found message ID: $1" ;; *) echo "Server $1" ;; esac shift done

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  • jQuery wildcard selection

    - by Yuval A
    Suppose you have some <div>s: <div id="div_num1"></div> <div id="div_num2"></div> <div id="div_num3"></div> You can select all those divs by choosing $("div[id^='div_num']"). How can you buld a function that references the number succeeding the prefix? For example, a function which will alert the number 3 for "div_num3". More generally, how can you use full-blown regex in jQuery selectors?

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  • Why doesn't Python's `re.split()` split on zero-length matches?

    - by Tim Pietzcker
    One particular quirk of the (otherwise quite powerful) re module in Python is that re.split() will never split a string on a zero-length match, for example if I want to split a string along word boundaries: >>> re.split(r"\s+|\b", "Split along words, preserve punctuation!") ['Split', 'along', 'words,', 'preserve', 'punctuation!'] instead of ['', 'Split', 'along', 'words', ',', 'preserve', 'punctuation', '!'] Why does it have this limitation? Is it by design? Do other regex flavors behave like this?

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  • lookahead and group

    - by Istao
    Hi, In Java, on a text like foo <on> bar </on> thing <on> again</on> now, I should want a regex with groups wich give me with a find "foo", "bar", empty string, then "thing", "again", "now". If I do (.*?)<on>(.*?)</on>(?!<on>), I get only two group (foo bar, thing again, and I've not the end "now"). if I do (.*?)<on>(.*?)</on>((?!<on>)) I get foo bar empty string, then thing again and empty string (here I should want "now"). Please what is the magical formula ? Thanks.

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  • Working with multiple jQuery libraries and Prototype.

    - by Derek
    Ok, i saw some other posts about this sort of thing, but not exactly related. This is not what I want to do, but need to do unfortunately. We have in this order right now Prototype 1.6 jQuery 1.2.6 with noConflict on jQuery with j I need to add jQuery 1.4.2 in that mix as well. It will always be the last one loaded. No option. Is there anyway i can do this currently? I know this is not good, yada, yada, but it has to be done for now unfortunately. Thanks, Derek

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  • Regular Expression: Changes HTML Attributes Value to some pattern

    - by brain90
    Dear Engineers, I'm a newbie in RegEx I have thousands html tags, have wrote like this: <input type="text" name="CustomerName" /> <input type="text" name="SalesOrder"/> I need to match every name attribute values and convert them all to be like this: CustomerName -> cust[customer_name] SalesOrder -> cust[sales_order] So the results will be : <input type="text" name="cust[customer_name]" /> <input type="text" name="cust[sales_order]" /> My best try have stuck in this pattern: name=\"[a-zA-Z0-9]*\" - just found name="CustomerName" Please guide me wrote some Regular Expression magics to done this, I'm using Netbeans PDT. Thanks in advance for any pointers!.

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  • template static classes across dynamic linked libraries

    - by user322274
    Hello, I have a templated class with a static value, like this: template <class TYPE> class A{ static TYPE value; }; in the code of a dll I assign the static value: code of DLL_1 A<float>::value = 2.0; I wish the value to be shared by all the dlls I'm using, i.e. I want that: code of DLL_2 printf("value on DLL_2 %f",A<float>::value); print out "2.0" any clues? thx

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  • The conventional location for storing my Java libraries and applications in UNIX based systems

    - by Bytecode Ninja
    I usually store the Java applications and JAR files that I download from the Web in the ~/Java folder on my computer (an OS X machine). I have been doing this since the days when I was a Windows user. However I think in UNIX based systems user local apps are conventionally stored in another directory. I have a feeling that this directory should either be /usr/local/, /usr/local/USERNAME, /opt/local, or /opt/local/USERNAME but I am not sure. Any ideas which directory can I use for this purpose? Please note that, I am talking about archive files that I download from the Web, unpack and use locally and not programs that have installation scripts or MacPorts, etc.

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  • Recommendations for java captcha libraries

    - by skaffman
    I'm looking for a replacement for JCaptcha, which doesn't seem to be maintained any more, and isn't very good to begin with. The replacement has to integrate nicely with JavaEE webapps. As I can see it, there are three options: JCaptcha - No longer maintained, crude API SimpleCaptcha - much nicer API, nicer captchas, but seems to be Java6 only ReCaptcha - easy to use, uses remote web-service to generate captchas, but not much control over look and feel Has anyone used any others, that they'd recommend?

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  • replace capturing group

    - by Don
    Hi, If I have a regex with a capturing group, e.g. foo(_+f). If I match this against a string and want to replace the first capturing group in all matches with baz so that foo___f blah foo________f is converted to: foobaz blah foobaz There doesn't appear to be any easy way to do this using the standard libraries. If I use Matcher.replaceAll() this will replace all matches of the entire pattern and convert the string to baz blah baz Obviously I can just iterate through the matches, store the start and end index of each capturing group, then go back and replace them, but is there an easier way? Thanks, Don

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  • Exclude subexpression from regexec in c++

    - by wyatt
    Suppose I was trying to match the following expression using regex.h in C++, and trying to obtain the subexpressions contained: /^((1|2)|3) (1|2)$/ Suppose it were matched against the string "3 1", the subexpressions would be: "3 1" "3" "1" If, instead it were matched against the string "2 1", the subexpressions would be: "2 1" "2" "2" "1" Which means that, depending on how the first subexpression evaluates, the final one is in a different element in the pmatch array. I realise this particular example is trivial, as I could remove one of the sets of brackets, or grab the last element of the array, but it becomes problematic in more complicated expressions. Suppose all I want are the top-level subexpressions, the ones which aren't subexpressions of other subexpressions. Is there any way to only get them? Or, alternatively, to know how many subexpressions are matched within a subexpression, so that I can traverse the array irrespective of how it evaluates? Thanks

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  • Java replace all capturing groups

    - by Don
    Hi, If I have a regex with a capturing group, e.g. foo(g.*f). If I match this against a string and want to replace the first capturing group in all matches with baz so that foog___f blah foog________f is converted to: foobaz blah foobaz There doesn't appear to be any easy way to do this using the standard libraries, because the Matcher.replaceAll() method will only replace all matches of the entire pattern, am I missing something? Obviously I can just iterate through the matches, store the start and end index of each capturing group, then go back and replace them, but is there an easier way? Thanks, Don

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  • Writing Ruby Libraries - hiding methods from outside the module

    - by JP
    Hi all, I'm writing a Ruby library which has a module with a bunch of classes inside it. Many of these classes need to be usable and modifiable by calling scripts, but I don't want (some of) the initializers to be visible/callable: module MyLib class Control def initialize # They can use this end def do_stuff Helper.new('things') end end class Helper # Shouldn't be visible def initialize(what) @what = what end def shout @what end end end c = MyLib::Control.new h = c.do_stuff p h.shout # => "things" # ^ All of this is desired # v This is undesirable p MyLib::Helper.new('!') # => <MyLib::Helper @what='!'> If it's a simple thing, then I'd also appreciate the generated RDoc not even include the .new method for the Helper class either. Any ideas? Thanks for reading!

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  • How do I remove specific numbers from a string?

    - by user1666900
    I have this string in PHP Hopelessly Incredible |SPG:M| 766 STEAM_0:1:20130600 " banned "A Blatantly Obvious Hacker 740 STEAM_0:1:55386073 " (minutes "0") (reason "Multi-Hack") The Format of the string is: Name1 Number(0-3 digits) Steam_0:x:xxxx offense (banned/kicked/mute etc) Name2 Number(0-3 digits) Steam_0:x:xxxx time reason My goal is to remove the values 766 and 740 because it is just garbage. Those values can have single, double, and triple digits. The next step would be to strip STEAM_0:1:20130600 and STEAM_0:1:55386073 out of the string and capture it in a new variable. The only constant is STEAM_0: the rest can change. I am still learning regex but I fear this is a bit complicated for me to do. Some guidance would be most appreciative.

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  • issue with regex in C#

    - by Dilip
    my file is > A B C D unuse data <begin> Addd as ss 1 My name is 2323 33 text > </end> 34344 no need and my code is StringBuilder mSb = new StringBuilder(); StreamReader sr = new StreamReader(@"E:\check.txt"); String line; while (sr.ReadLine() != null) { mSb.AppendLine(sr.ReadLine()); } string matc = new Regex(@"(<begin>)(\n?.*)*</end>)?").Match(mSb.ToString()).ToString(); here it reading all file , but i just want till if i am removing ? from end , my program is crashing .. Thanks

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  • Sed substitution not doing what I want and think it should do

    - by nategoose
    I have am trying to use sed to get some info that is encoded within the path of a file which is passed as a parameter to my script (Bourne sh, if it matters). From this example path, I'd like the result to be 8 PATH=/foo/bar/baz/1-1.8/sing/song I first got the regex close by using sed as grep: echo $PATH | sed -n -e "/^.*\/1-1\.\([0-9][0-9]*\).*/p" This properly recognized the string, so I edited it to make a substitution out of it: echo $PATH | sed -n -e "s/^.*\/1-1\.\([0-9][0-9]*\).*/\1/" But this doesn't produce any output. I know I'm just not seeing something simple, but would really appreciate any ideas about what I'm doing wrong or about other ways to debug sed regular expressions.

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  • Regular Expression; Find whether a line contains any word with more than X characters.

    - by Simpsoid
    Hi, I am trying to use a Validator on a ASP.NET site and need to find whether the Street Address textbox contains a valid entry. Entries with words that are longer than X characters (in this case 25, with no punctuation or spaces) will cause the HTML on a printed A4 page to not wrap properly and therefore not to confrom to certain sizes correctly pushing the margins off. For a street address I want to match that something like "201 Long Road" is valid but "235 ReallyLongAndNarrowWindingRoadBesideTheRiver Street" is invalid. Using a Microsoft .Net Regular Expression Validator I need to know what the RegEx pattern might be. I think if it does find a match the Validator will fire correctly however if there is no match the Validator won't fire and the Update button (in this case) won't fire. Since Street addresses can contain Capital Letters and numbers etc. it will need to accomodate for that and also Spaces, Commas, Semi-Colons and Colons and Hyphens are valid characters too. Any help would be greatly appreciated as I am really stuck with this problem. Thanks, David

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  • Regular Expression to recognise truncated forms of search string?

    - by Moonshield
    I'm trying to formulate a regular expression which will recognise the search term truncated by any number of characters from the right. For example, if the search term is "pickle", the regex should recognise "pi", "pick" but not "pickaxe". Initially I came up with the following: p(i(c(k(l(e)?)?)?)?)? That works perfectly, but seems a crude way of doing it. Is there a better way of doing this? I had a look around for something similar to what I want, but I'm not entirely sure what to search for.

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  • Assistance with regular expressions in Python

    - by da5id
    I am still learning REGEX, and I've run into an issue ... I am trying to separate a string that is composed of a mixture of letters and numbers that are in decimal format: AB0.500CD1.05EF2.29 Into something like this: list1 = AB,CD,EF list2 = 0.500,1.05,2.29 A complication to all this is that I also have strings that look like this: AB1CD2EF3 Which I'd also like to separate into this: list1 = AB,CD,EF list2 = 1,2,3 A previous inquiry yielded the following snippet, import re pattern = re.compile(r'([a-zA-Z]+)([0-9]+)') for (letters, numbers) in re.findall(pattern,cmpnd): print numbers print letters This example works fine for strings of the 2nd kind, but only "finds" the leading digit in the numbers that contain decimal places in the strings of the first kind. I've attempted an approach using the following line: pattern = re.compile(r'([a-zA-Z]+)([0-9]+(\.[0-9]))') But this results in an error: "ValueError: too many values to unpack" Thanks for any and all assistance!

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  • Can AC_CHECK_LIB be used for unconventionally named libraries?

    - by aleph
    AC_CHECK_LIB accepts as an argument the base name of the shared library that you want to check for. So for a library named "libxyz.so" you would specify the base name of the library "xyz" as an argument to AC_CHECK_LIB. If I have a library named xyz.so (Note: Not libxyz.so), how do I check for the availability/usability of this library with autoconf ?

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  • jQuery sanitizing comments and linkifying URLs

    - by iWasRobbed
    In terms of jQuery (or Javascript), what happens behind the scenes when a person posts a comment on Facebook, Twitter, or a blog? For instance, do they sanitize the text first, and then pattern match URL's into an actual link? Are there other items of concern that the client-side should check in addition to doing some checks on the backend? I have found a few regex's for turning URL's into links, but I'm not sure if there are better solutions. I'm trying to wrap my head around the problem, but I'm having a difficult time knowing where to start. Any guidance you can provide is greatly appreciated!

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  • Perl - string matching issue

    - by user2886545
    I have a problem I cannot understand. I have this string: gene_id "siRNA_Z27kG1_20543"transcript_id "siRNA_Z27kG1_20543_X_1";tss_id "TSS124620" And I want to change the gene_id. So, I have the following code: if ($line =~ /;transcript_id "([A-Za-z0-9:\-._]*)(_[oxOX][_.][0-9]*)";/) { $num = $2; $line =~ s/gene_id "([A-Za-z0-9:\-._]*)";/gene_id "$1$num";/g; print $new $line."\n"; } The aim of my code is to change siRNA_Z27kG1_20543 for siRNA_Z27kG1_20543_X_1. However, my code does not produce that output. Why? I can't understand that. My regex needs to be as it is because I match other strings (this time with success). Thanks.

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  • Regexp in iOS to find comments

    - by SteveDolphin23
    I am trying to find and process 'java-style' comments within a string in objective-C. I have a few regex snippets which almost work but I am stuck on one hurdle: different options seem to make the different styles work. For example, I am using this to match: NSArray* matches = [[NSRegularExpression regularExpressionWithPattern:expression options:NSRegularExpressionAnchorsMatchLines error:nil] matchesInString:string options:0 range:searchRange]; The options here allow me successfully find and process single line comments (//) but not multiline (/* */), if I change the option to NSRegularExpressionDotMatchesLineSeparators then I can make multiline work fine but I can't find the 'end' of a single line comment. I suppose really I need dot-matches-line-separators but I need a better way of finding the end of a single line comment? The regexp I have so far are: @"/\\*.*?\\*/" @"//.*$" it's clear to see if dot matches a line separator then the second one (single line) never 'finishes' but how do I fix this? I found some suggestions for single line that were more like: @"(\/\/[^"\n\r]*(?:"[^"\n\r]*"[^"\n\r]*)*[\r\n])" But that doesn't' seem to work at all! Thanks in advance for any pointers.

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