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  • how do I use fitnesse ActionFixture with C#?

    - by JDPeckham
    I tried to make an action fixture and it’s not working. (c# with Slim runner) Basically it seems like it's trying to interpret it as a column fixture. |!-Fitnesse.BuyActions-! | |Start|!-Fitnesse.BuyActions-!| |check|total |0.0 | |enter|price |12.00 | |press|buy | |check|total |12.00 | |enter|price |100.00 | |press|buy | |check|total |112.00 | Fitnesse.BuyActions Start Fitnesse.BuyActions check Method setStart not found in Fitnesse.BuyActions using fit; namespace Fitnesse { public class BuyActions : ActionFixture { public BuyActions() : base() { this.targetObject = this; } } }

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  • Checkbox:Issue in checkchanged event

    - by user290621
    -I have a check box: -and i have subscribed for checkchanged event, i have an handler inturn and doing some operation there - i check and uncheck this checkbox programmatically(ex:chkbx_Name.Checked = true), (Obviously checkchanged evt gets fired) -I want this event to be fired only when i manually check or uncheck it - is there any way to avoid firing of this event when i check.uncheck it programmatically

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  • what will be the code to move to previous textfield ?

    - by rajesh
    i have the code if i press down button it goes to next textfield but to go to previous textfield what should be the code ... <html> <head> <script language="JavaScript"> function handleKeyDownEvent(elementRef,eventRef) { var charCode = (window.event) ? eventRef.keyCode : eventRef.which; //alert(charCode); // Arrow keys (37:left, 38:up, 39:right, 40:down)... if (charCode == 40) { if (window.event) window.event.keyCode = 9; else event.which = 9; return true; } return true; } </script> </head> <body> <table width="433" border="1" cellspacing="0" cellpadding="0"> <tr> <td width="235" align="center"><input type="text" onKeyDown="handleKeyDownEvent(this,event);" onKeyUp="handleKeyUpEvent(this,event);"></td> <td width="235" align="center"><input type="text" onKeyDown="handleKeyDownEvent(this,event);" onKeyUp="handleKeyUpEvent(this,event);"></td> </tr> <tr> <td width="235" align="center"><input type="text" onKeyDown="handleKeyDownEvent(this,event);" onKeyUp="handleKeyUpEvent(this,event);"></td> <td width="235" align="center"><input type="text" onKeyDown="handleKeyDownEvent(this,event);" onKeyUp="handleKeyUpEvent(this,event);"></td> </tr> <tr> <td> <input type="radio" id="check" name="check" checked> </td> <td> <input type="radio" id="check" name="check" checked> </td> </tr> <tr> <td><input type="checkbox" id="check" name="check"></td> <td><input type="checkbox" id="check" name="check"></td> </tr> </table> </body> </html>

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  • Problems Enforcing Referential Integrity on SQL Server Tables

    - by SidC
    Hello All, I have a SQL Server 2005 database comprised of Customer, Quote, QuoteDetail tables. I want/need to enforce referential integrity such that when an insert is made on quotedetail, the quote and customer tables are also affected. I have tried my best to set up primary/foreign keys on my tables but need some help. Here's the scripts for my tables as they stand now (please don't laugh): Customers: USE [Diel_inventory] GO /****** Object: Table [dbo].[Customers] Script Date: 05/08/2010 03:39:04 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE TABLE [dbo].[Customers]( [pkCustID] [int] IDENTITY(1,1) NOT NULL, [CompanyName] [nvarchar](50) NULL, [Address] [nvarchar](50) NULL, [City] [nvarchar](50) NULL, [State] [nvarchar](2) NULL, [ZipCode] [nvarchar](5) NULL, [OfficePhone] [nvarchar](12) NULL, [OfficeFAX] [nvarchar](12) NULL, [Email] [nvarchar](50) NULL, [PrimaryContactName] [nvarchar](50) NULL, CONSTRAINT [PK_Customers] PRIMARY KEY CLUSTERED ([pkCustID] ASC)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] Quotes: USE [Diel_inventory] GO /****** Object: Table [dbo].[Quotes] Script Date: 05/08/2010 03:30:46 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE TABLE [dbo].[Quotes]( [pkQuoteID] [int] IDENTITY(1,1) NOT NULL, [fkCustomerID] [int] NOT NULL, [QuoteDate] [timestamp] NOT NULL, [NeedbyDate] [datetime] NULL, [QuoteAmt] [decimal](6, 2) NOT NULL, [QuoteApproved] [bit] NOT NULL, [fkOrderID] [int] NOT NULL, CONSTRAINT [PK_Bids] PRIMARY KEY CLUSTERED ( [pkQuoteID] ASC)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO ALTER TABLE [dbo].[Quotes] WITH CHECK ADD CONSTRAINT [fkCustomerID] FOREIGN KEY([fkCustomerID]) REFERENCES [dbo].[Customers] ([pkCustID]) GO ALTER TABLE [dbo].[Quotes] CHECK CONSTRAINT [fkCustomerID] QuoteDetail: USE [Diel_inventory] GO /****** Object: Table [dbo].[QuoteDetail] Script Date: 05/08/2010 03:31:58 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE TABLE [dbo].[QuoteDetail]( [ID] [int] IDENTITY(1,1) NOT NULL, [fkQuoteID] [int] NOT NULL, [fkCustomerID] [int] NOT NULL, [fkPartID] [int] NULL, [PartNumber1] [float] NOT NULL, [Qty1] [int] NOT NULL, [PartNumber2] [float] NULL, [Qty2] [int] NULL, [PartNumber3] [float] NULL, [Qty3] [int] NULL, [PartNumber4] [float] NULL, [Qty4] [int] NULL, [PartNumber5] [float] NULL, [Qty5] [int] NULL, [PartNumber6] [float] NULL, [Qty6] [int] NULL, [PartNumber7] [float] NULL, [Qty7] [int] NULL, [PartNumber8] [float] NULL, [Qty8] [int] NULL, [PartNumber9] [float] NULL, [Qty9] [int] NULL, [PartNumber10] [float] NULL, [Qty10] [int] NULL, [PartNumber11] [float] NULL, [Qty11] [int] NULL, [PartNumber12] [float] NULL, [Qty12] [int] NULL, [PartNumber13] [float] NULL, [Qty13] [int] NULL, [PartNumber14] [float] NULL, [Qty14] [int] NULL, [PartNumber15] [float] NULL, [Qty15] [int] NULL, [PartNumber16] [float] NULL, [Qty16] [int] NULL, [PartNumber17] [float] NULL, [Qty17] [int] NULL, [PartNumber18] [float] NULL, [Qty18] [int] NULL, [PartNumber19] [float] NULL, [Qty19] [int] NULL, [PartNumber20] [float] NULL, [Qty20] [int] NULL, CONSTRAINT [PK_QuoteDetail] PRIMARY KEY CLUSTERED ( [ID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO ALTER TABLE [dbo].[QuoteDetail] WITH CHECK ADD CONSTRAINT [FK_QuoteDetail_Customers] FOREIGN KEY ([fkCustomerID]) REFERENCES [dbo].[Customers] ([pkCustID]) GO ALTER TABLE [dbo].[QuoteDetail] CHECK CONSTRAINT [FK_QuoteDetail_Customers] GO ALTER TABLE [dbo].[QuoteDetail] WITH CHECK ADD CONSTRAINT [FK_QuoteDetail_PartList] FOREIGN KEY ([fkPartID]) REFERENCES [dbo].[PartList] ([RecID]) GO ALTER TABLE [dbo].[QuoteDetail] CHECK CONSTRAINT [FK_QuoteDetail_PartList] GO ALTER TABLE [dbo].[QuoteDetail] WITH CHECK ADD CONSTRAINT [FK_QuoteDetail_Quotes] FOREIGN KEY([fkQuoteID]) REFERENCES [dbo].[Quotes] ([pkQuoteID]) GO ALTER TABLE [dbo].[QuoteDetail] CHECK CONSTRAINT [FK_QuoteDetail_Quotes] Your advice/guidance on how to set these up so that customer ID in Customers is the same as in Quotes (referential integrity) and that CustomerID is inserted on Quotes and Customers when an insert is made to QuoteDetial would be much appreciated. Thanks, Sid

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  • Issue in CheckedChanged event

    - by Gaddigesh
    I have a check box and I have subscribed for the CheckedChanged event. The handler does some operations in there. I check and uncheck the checkbox programmatically (ex: chkbx_Name.Checked = true), and the CheckedChanged event gets fired. I want this event to be fired only when I manually check or uncheck it. Is there any way to avoid firing of this event when i check/uncheck it programmatically?

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  • version of ldap installed - one liner

    - by PJ
    HI, I am using LDAP which is installed in a solaris machine. To check the version of LDAP i go to /ldap and check the version installed as if it is version 5 then there is a directory of the name v5.0 and so on. After getting into the directory i check the directory structure. Can anybody tell me is there any shortest way or one liner to check the version of ldap installed in my machine. Thanks in advance.

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  • PHP & MySQL checked checkbox problem

    - by BeepU
    I'm trying to check if the checkbox has been checked and display the check mark for the user to see when they check there account settings. I want to know how can I fix this problem using PHP so that the check mark is displayed every time the user views their account settings? Here is the HTML. <input type="checkbox" name="privacy_policy" id="privacy_policy" value="yes" />

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  • Is throwing an exception a healthy way to exit?

    - by ramaseshan
    I have a setup that looks like this. class Checker { // member data Results m_results; // see below public: bool Check(); private: bool Check1(); bool Check2(); // .. so on }; Checker is a class that performs lengthy check computations for engineering analysis. Each type of check has a resultant double that the checker stores. (see below) bool Checker::Check() { // initilisations etc. Check1(); Check2(); // ... so on } A typical Check function would look like this: bool Checker::Check1() { double result; // lots of code m_results.SetCheck1Result(result); } And the results class looks something like this: class Results { double m_check1Result; double m_check2Result; // ... public: void SetCheck1Result(double d); double GetOverallResult() { return max(m_check1Result, m_check2Result, ...); } }; Note: all code is oversimplified. The Checker and Result classes were initially written to perform all checks and return an overall double result. There is now a new requirement where I only need to know if any of the results exceeds 1. If it does, subsequent checks need not be carried out(it's an optimisation). To achieve this, I could either: Modify every CheckN function to keep check for result and return. The parent Check function would keep checking m_results. OR In the Results::SetCheckNResults(), throw an exception if the value exceeds 1 and catch it at the end of Checker::Check(). The first is tedious, error prone and sub-optimal because every CheckN function further branches out into sub-checks etc. The second is non-intrusive and quick. One disadvantage is I can think of is that the Checker code may not necessarily be exception-safe(although there is no other exception being thrown anywhere else). Is there anything else that's obvious that I'm overlooking? What about the cost of throwing exceptions and stack unwinding? Is there a better 3rd option?

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  • Unusual Template Behavior with XSL

    - by bobber205
    Experiencing some very odd behavior with, what should be, a very simple use of XSL and XSLT. Here's a code sample. <xsl:template match="check"> <div class="check"> <xsl:apply-templates mode="check"> <xsl:with-param name="checkName">testVariable</xsl:with-param> </xsl:apple-templates> </div> </xsl:template> The template called above <xsl:template match="option" mode="check"> <xsl:param name="checkName" /> <div class="option"> <input type="checkbox"> </input> <label> testText </label> </div> </xsl:template> Pretty simple right? It should, for each instance of a instance in the XML create a checkbox in a with a hard coded label. However, what I'm getting is <div class="check"></div> <div class="option>Checkbox stuff here</div> <div class="option>Checkbox stuff here</div> <div class="option>Checkbox stuff here</div> <div class="option>Checkbox stuff here</div> <div class="check"></div> <div class="option>Checkbox stuff here</div> <div class="option>Checkbox stuff here</div> <div class="option>Checkbox stuff here</div> <div class="option>Checkbox stuff here</div> Here's some sample XML <check><option key="1"/><option key="0"/><option key="0"/><option key="0"/><option key="0"/></check> Anyone know what's going on? :D

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  • Look up or insert new element to string list in Haskell

    - by nightscream
    So I want to have a function that takes a String and a list as an argument, and checks if that element is already on the list, if it is, returns the same list, if it isnt, adds it to the list and returns it, 'im a begginer with haskell so heres what I have tried with no sucess: check:: String ->[String] ->[String] check x [] = []++[x] check x (y:xs) | x==y = (y:xs) | otherwise = check x xs Can someone point me the way ? thks

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  • Nginx + Haproxy + Thin + Rails - 503 Service Unavailable -

    - by Luca G. Soave
    I don't know how troubleshoot this. I get "503 Service Unavailable" http error for all "nginx upstreams" proxy passing calls to haproxy fast_thin and slow_thin ( server 127.0.0.1:3100 and server 127.0.0.1:3200 ), which loadbalance on 6 Thin servers ( 127.0.0.1:3000 .. 3005 ). Static files like /blog are currently fine. The falldown is: nginx on port 80 - haproxy on 3100 and 3200 - thin on 3000 .. 3005 and then Rails. Here it is /etc/nginx/nginx.conf : user nginx; worker_processes 2; pid /var/run/nginx.pid; events { worker_connections 1024; } http { include /etc/nginx/mime.types; default_type application/octet-stream; log_format main '$remote_addr - $remote_user [$time_local] "$request" ' '$status $body_bytes_sent "$http_referer" ' '"$http_user_agent" "$http_x_forwarded_for"'; sendfile on; tcp_nopush on; keepalive_timeout 65; tcp_nodelay on; include /etc/nginx/conf.d/*.conf; } then /etc/nginx/conf.d/default.conf upstream fast_thin { server 127.0.0.1:3100; } upstream slow_thin { server 127.0.0.1:3200; } server { listen 80; server_name www.gitwatcher.com; rewrite ^/(.*) http://gitwatcher.com/$1 permanent; } server { listen 80; server_name gitwatcher.com; access_log /var/www/gitwatcher/log/access.log; error_log /var/www/gitwatcher/log/error.log; root /var/www/gitwatcher/public; # index index.html; location /about { proxy_pass http://fast_thin; break; } location /trends { proxy_pass http://slow_thin; break; } location /categories { proxy_pass http://slow_thin; break; } location /signout { proxy_pass http://slow_thin; break; } location /auth/github { proxy_pass http://slow_thin; break; } location / { proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header Host $http_host; proxy_redirect off; if (-f $request_filename/index.html) { rewrite (.*) $1/index.html break; } if (-f $request_filename.html) { rewrite (.*) $1.html break; } if (!-f $request_filename) { proxy_pass http://slow_thin; break; } } } then haproxy config file /etc/haproxy/haproxy.cfg : global log 127.0.0.1 local0 log 127.0.0.1 local1 notice #log loghost local0 info maxconn 4096 #chroot /usr/share/haproxy user haproxy group haproxy daemon #debug #quiet nbproc 1 # number of processing cores defaults log global retries 3 maxconn 2000 contimeout 5000 mode http clitimeout 60000 # maximum inactivity time on the client side srvtimeout 30000 # maximum inactivity time on the server side timeout connect 4000 # maximum time to wait for a connection attempt to a server to succeed option httplog option dontlognull option redispatch option httpclose # disable keepalive (HAProxy does not yet support the HTTP keep-alive mode) option abortonclose # enable early dropping of aborted requests from pending queue option httpchk # enable HTTP protocol to check on servers health option forwardfor # enable insert of X-Forwarded-For headers balance roundrobin # each server is used in turns, according to assigned weight stats enable # enable web-stats at /haproxy?stats stats auth haproxy:pr0xystats # force HTTP Auth to view stats stats refresh 5s # refresh rate of stats page listen rails_proxy 127.0.0.1:3100 # - equal weights on all servers # - maxconn will queue requests at HAProxy if limit is reached # - minconn dynamically scales the connection concurrency (bound my maxconn) depending on size of HAProxy queue # - check health every 20000 microseconds server web1 127.0.0.1:3000 weight 1 minconn 3 maxconn 6 check inter 20000 server web1 127.0.0.1:3001 weight 1 minconn 3 maxconn 6 check inter 20000 server web1 127.0.0.1:3002 weight 1 minconn 3 maxconn 6 check inter 20000 listen slow_proxy 127.0.0.1:3200 # cluster for slow requests, lower the queues, check less frequently server slow1 127.0.0.1:3003 weight 1 minconn 1 maxconn 3 check inter 40000 server slow2 127.0.0.1:3004 weight 1 minconn 1 maxconn 3 check inter 40000 server slow3 127.0.0.1:3005 weight 1 minconn 1 maxconn 3 check inter 40000 and the Thin config file /etc/thin/gitwatcher.yml : --- chdir: /var/www/gitwatcher environment: production address: 0.0.0.0 port: 3000 timeout: 30 log: log/thin.log pid: tmp/pids/thin.pid max_conns: 1024 max_persistent_conns: 100 require: [] wait: 30 servers: 6 daemonize: true if I look into open listen ports, I got the following : root@fullness:/var/www/gitwatcher# lsof | grep TCP | egrep "nginx|haproxy|thin" nginx 834 root 8u IPv4 921 0t0 TCP *:http (LISTEN) nginx 835 nginx 8u IPv4 921 0t0 TCP *:http (LISTEN) nginx 837 nginx 8u IPv4 921 0t0 TCP *:http (LISTEN) haproxy 1908 haproxy 4u IPv4 11699 0t0 TCP localhost:3100 (LISTEN) haproxy 1908 haproxy 6u IPv4 11701 0t0 TCP localhost:3200 (LISTEN) root@fullness:/var/www/gitwatcher# iptables -L get me the following : Chain INPUT (policy DROP) target prot opt source destination ACCEPT all -- anywhere anywhere state RELATED,ESTABLISHED ACCEPT all -- anywhere anywhere state RELATED,ESTABLISHED ACCEPT tcp -- anywhere anywhere tcp dpt:22222 ACCEPT tcp -- anywhere anywhere tcp dpt:http ACCEPT tcp -- anywhere anywhere tcp dpt:https ACCEPT all -- anywhere anywhere DROP all -- anywhere anywhere Chain FORWARD (policy ACCEPT) target prot opt source destination Chain OUTPUT (policy ACCEPT) target prot opt source destination ACCEPT all -- anywhere anywhere Any help ?

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  • Could not find rake-10.1.0 in any of the sources

    - by spuder
    I've got a ruby on rails application (gitlab) which is installed via puppet. Everything on the test system runs fine, but production generates an error about rake Running /home/git/gitlab-shell/bin/check Could not find rake-10.1.0 in any of the sources Run bundle install to install missing gems. Here is the full rake check: root@gitlab:/home/git# sudo -u git -H bundle exec rake gitlab:check RAILS_ENV=production Checking Environment ... Git configured for git user? ... yes Has python2? ... yes python2 is supported version? ... yes Checking Environment ... Finished Checking GitLab Shell ... GitLab Shell version >= 1.7.1 ? ... OK (1.7.1) Repo base directory exists? ... yes Repo base directory is a symlink? ... no Repo base owned by git:git? ... yes Repo base access is drwxrws---? ... yes update hook up-to-date? ... yes update hooks in repos are links: ... Could not find rake-10.1.0 in any of the sources Run `bundle install` to install missing gems. gitlab-shell self-check failed Try fixing it: Make sure GitLab is running; Check the gitlab-shell configuration file: sudo -u git -H editor /home/git/gitlab-shell/config.yml Please fix the error above and rerun the checks. Checking GitLab Shell ... Finished Checking Sidekiq ... Running? ... yes Number of Sidekiq processes ... 1 Checking Sidekiq ... Finished Checking GitLab ... Database config exists? ... yes Database is SQLite ... no All migrations up? ... yes GitLab config exists? ... yes GitLab config outdated? ... no Log directory writable? ... yes Tmp directory writable? ... yes Init script exists? ... yes Init script up-to-date? ... yes projects have namespace: ... Spencer Owen / bar ... yes Projects have satellites? ... Spencer Owen / bar ... can't create, repository is empty Redis version >= 2.0.0? ... yes Your git bin path is "/usr/bin/git" Git version >= 1.7.10 ? ... yes (1.8.4) Checking GitLab ... Finished The step 'gitlab-shell check' effectively runs the following command. If I run that command manually, everything passes. root@gitlab:/home/git/gitlab# sudo -u git -H /home/git/gitlab-shell/bin/check Check GitLab API access: OK Check directories and files: /home/git/repositories: OK /home/git/.ssh/authorized_keys: OK I have verified that rake is in fact installed root@gitlab:/home/git/gitlab# gem install rake -v 10.1.0 root@gitlab:/home/git/gitlab# bundle install root@gitlab:/home/git/gitlab# sudo -u git -H gem install rake -v 10.1.0 root@gitlab:/home/git/gitlab# sudo -u git -H bundle install Ruby is installed with update alternatives root@gitlab:/home/git/gitlab# sudo -u git -H ruby --version ruby 1.9.3p0 (2011-10-30 revision 33570) [x86_64-linux] root@gitlab:/home/git/gitlab# sudo -u git -H ls -l `which ruby` lrwxrwxrwx 1 root root 22 Oct 8 20:26 /usr/bin/ruby -> /etc/alternatives/ruby root@gitlab:/home/git/gitlab# sudo -u git -H gem --version 2.1.10 root@gitlab:/home/git/gitlab# sudo -u git -H ls -l `which gem` lrwxrwxrwx 1 root root 21 Oct 10 20:50 /usr/bin/gem -> /etc/alternatives/gem I've tried the solution mentioned below, to allow shared gems http://stackoverflow.com/questions/19284914/bundle-exec-fails-with-could-not-find-rake-10-1-0-in-any-of-the-sources http://stackoverflow.com/questions/18978002/could-not-find-rake-with-bundle-exec root@gitlab:/home/git/gitlab# cat /home/git/gitlab/.bundle/config --- BUNDLE_FROZEN: '1' BUNDLE_PATH: vendor/bundle BUNDLE_WITHOUT: development:test:postgres BUNDLE_DISABLE_SHARED_GEMS: '1' I've exhausted google, so I'm hoping for someone more familiar with ruby to offer any ideas how to resolve the error. Could not find rake-10.1.0 in any of the sources

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  • GitLab on a fresh Ubuntu 13 EC2 instance

    - by Polly
    I've spun up a fresh Amazon EC2 instance for a micro Ubuntu 13 server to be used as a GitLab server. I know the specs are a little low, but it should serve well for my purposes. It has an elastic (static) IP address that I have created an A record for git.mydomain.com. The first thing I did to the instance was add 1GB of swap to keep it happy from a memory perspective. I then set the hostname of the box to be git.mydomain.com and followed https://github.com/gitlabhq/gitlabhq/blob/6-2-stable/doc/install/installation.md to the letter. Everything seems to have worked, except for the web server side of things. Doing a gitlab:check shows the following: Checking Environment ... Git configured for git user? ... yes Has python2? ... yes python2 is supported version? ... yes Checking Environment ... Finished Checking GitLab Shell ... GitLab Shell version >= 1.7.4 ? ... OK (1.7.4) Repo base directory exists? ... yes Repo base directory is a symlink? ... no Repo base owned by git:git? ... yes Repo base access is drwxrws---? ... yes update hook up-to-date? ... yes update hooks in repos are links: ... can't check, you have no projects Running /home/git/gitlab-shell/bin/check Check GitLab API access: /usr/local/lib/ruby/2.0.0/net/http.rb:878:in `initialize': Connection refused - connect(2) (Errno::ECONNREFUSED) from /usr/local/lib/ruby/2.0.0/net/http.rb:878:in `open' from /usr/local/lib/ruby/2.0.0/net/http.rb:878:in `block in connect' from /usr/local/lib/ruby/2.0.0/timeout.rb:52:in `timeout' from /usr/local/lib/ruby/2.0.0/net/http.rb:877:in `connect' from /usr/local/lib/ruby/2.0.0/net/http.rb:862:in `do_start' from /usr/local/lib/ruby/2.0.0/net/http.rb:851:in `start' from /home/git/gitlab-shell/lib/gitlab_net.rb:62:in `get' from /home/git/gitlab-shell/lib/gitlab_net.rb:29:in `check' from /home/git/gitlab-shell/bin/check:11:in `<main>' gitlab-shell self-check failed Try fixing it: Make sure GitLab is running; Check the gitlab-shell configuration file: sudo -u git -H editor /home/git/gitlab-shell/config.yml Please fix the error above and rerun the checks. Checking GitLab Shell ... Finished Checking Sidekiq ... Running? ... yes Number of Sidekiq processes ... 1 Checking Sidekiq ... Finished Checking GitLab ... Database config exists? ... yes Database is SQLite ... no All migrations up? ... yes GitLab config exists? ... yes GitLab config outdated? ... no Log directory writable? ... yes Tmp directory writable? ... yes Init script exists? ... yes Init script up-to-date? ... yes projects have namespace: ... can't check, you have no projects Projects have satellites? ... can't check, you have no projects Redis version >= 2.0.0? ... yes Your git bin path is "/usr/bin/git" Git version >= 1.7.10 ? ... yes (1.8.3) Checking GitLab ... Finished It seems like I'm very nearly there. Searching on this error I have only found advice that unfortunately hasn't helped. I'm not using any kind of SSL setup, which a lot of the posts I found were about. I have tried appending 127.0.0.1 git.mydomain.com to /etc/hosts and giving the instance a reboot but there was no change. My config/gitlab.yml file has host: git.mydomain.com in it, and my gitlab-shell/config.yml has gitlab_url: "http://git.mydomain.com/" in it. I'm sure I'm missing something simple, but I've been through every relevant link I can find and have had no positive results; thank you in advance for any help!

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  • ASP.NET MVC Custom Profile Provider

    - by Ben Griswold
    It’s been a long while since I last used the ASP.NET Profile provider. It’s a shame, too, because it just works with very little development effort: Membership tables installed? Check. Profile enabled in web.config? Check. SqlProfileProvider connection string set? Check.  Profile properties defined in said web.config file? Check. Write code to set value, read value, build and test. Check. Check. Check.  Yep, I thought the built-in Profile stuff was pure gold until I noticed how the user-based information is persisted to the database. It’s stored as xml and, well, that was going to be trouble if I ever wanted to query the profile data.  So, I have avoided the super-easy-to-use ASP.NET Profile provider ever since, until this week, when I decided I could use it to store user-specific properties which I am 99% positive I’ll never need to query against ever.  I opened up my ASP.NET MVC application, completed steps 1-4 (above) in about 3 minutes, started writing my profile get/set code and that’s where the plan broke down.  Oh yeah. That’s right.  Visual Studio auto-generates a strongly-type Profile reference for web site projects but not for ASP.NET MVC or Web Applications.  Bummer. So, I went through the steps of getting a customer profile provider working in my ASP.NET MVC application: First, I defined a CurrentUser routine and my profile properties in a custom Profile class like so: using System.Web.Profile; using System.Web.Security; using Project.Core;   namespace Project.Web.Context {     public class MemberPreferencesProfile : ProfileBase     {         static public MemberPreferencesProfile CurrentUser         {             get             {                 return (MemberPreferencesProfile)                     Create(Membership.GetUser().UserName);             }         }           public Enums.PresenceViewModes? ViewMode         {             get { return ((Enums.PresenceViewModes)                     ( base["ViewMode"] ?? Enums.PresenceViewModes.Category)); }             set { base["ViewMode"] = value; Save(); }         }     } } And then I replaced the existing profile configuration web.config with the following: <profile enabled="true" defaultProvider="MvcSqlProfileProvider"          inherits="Project.Web.Context.MemberPreferencesProfile">        <providers>     <clear/>     <add name="MvcSqlProfileProvider"          type="System.Web.Profile.SqlProfileProvider, System.Web,          Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a"          connectionStringName="ApplicationServices" applicationName="/"/>   </providers> </profile> Notice that profile is enabled, I’ve defined the defaultProvider and profile is now inheriting from my custom MemberPreferencesProfile class.  Finally, I am now able to set and get profile property values nearly the same way as I did with website projects: viewMode = MemberPreferencesProfile.CurrentUser.ViewMode; MemberPreferencesProfile.CurrentUser.ViewMode = viewMode;

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  • How to interact with checkbox actions ? (QTableView with QStandardItemModel)

    - by Claire Huang
    I'm using QTableView and QStandardItemModel to show some data. For each row, there is a column which has a check Box, this check box is inserted by setItem, the code is as follows: int rowNum; QStandardItemModel *tableModel; QStandardItem* __tmpItem = new QStandardItem(); __tmpItem->setCheckable(true); __tmpItem->setCheckState(Qt::Unchecked); tableModel->setItem(rowNum,0,__tmpItem); Now I want to interact with the check box. If a check box changes its state by user (from checked to unchecked or vice versa), I want to do something on the corresponding data row. I know I can use signal-slot to catch the change of checkbox, but since there are lots of data row, I don't want to connect each row one by one. Is there anyway to interact with the check action more effectively? Thanks :)

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  • SQL SERVER – Identifying guest User using Policy Based Management

    - by pinaldave
    If you are following my recent blog posts, you may have noticed that I’ve been writing a lot about Guest User in SQL Server. Here are all the blog posts which I have written on this subject: SQL SERVER – Disable Guest Account – Serious Security Issue SQL SERVER – Force Removing User from Database – Fix: Error: Could not drop login ‘test’ as the user is currently logged in SQL SERVER – Detecting guest User Permissions – guest User Access Status SQL SERVER – guest User and MSDB Database – Enable guest User on MSDB Database One of the requests I received was whether we could create a policy that would prevent users unable guest user in user databases. Well, here is a quick tutorial to answer this. Let us see how quickly we can do it. Requirements Check if the guest user is disabled in all the user-created databases. Exclude master, tempdb and msdb database for guest user validation. We will create the following conditions based on the above two requirements: If the name of the user is ‘guest’ If the user has connect (@hasDBAccess) permission in the database Check in All user databases, except: master, tempDB and msdb Once we create two conditions, we will create a policy which will validate the conditions. Condition 1: Is the User Guest? Expand the Database >> Management >> Policy Management >> Conditions Right click on the Conditions, and click on “New Condition…”. First we will create a condition where we will validate if the user name is ‘guest’, and if it’s so, then we will further validate if it has DB access. Check the image for the necessary configuration for condition: Facet: User Expression: @Name = ‘guest’ Condition 2: Does the User have DBAccess? Expand the Database >> Management >> Policy Management >> Conditions Right click on Conditions and click on “New Condition…”. Now we will validate if the user has DB access. Check the image for necessary configuration for condition: Facet: User Expression: @hasDBAccess = False Condition 3: Exclude Databases Expand the Database >> Management >> Policy Management >> Conditions Write click on Conditions and click on “New Condition…” Now we will create condition where we will validate if database name is master, tempdb or msdb and if database name is any of them, we will not validate our first one condition with them. Check the image for necessary configuration for condition: Facet: Database Expression: @Name != ‘msdb’ AND @Name != ‘tempdb’ AND @Name != ‘master’ The next step will be creating a policy which will enforce these conditions. Creating a Policy Right click on Policies and click “New Policy…” Here, we justify what condition we want to validate against what the target is. Condition: Has User DBAccess Target Database: Every Database except (master, tempdb and MSDB) Target User: Every User in Target Database with name ‘guest’ Now we have options for two evaluation modes: 1) On Demand and 2) On Schedule We will select On Demand in this example; however, you can change the mode to On Schedule through the drop down menu, and select the interval of the evaluation of the policy. Evaluate the Policies We have selected OnDemand as our policy evaluation mode. We will now evaluate by means of executing Evaluate policy. Click on Evaluate and it will give the following result: The result demonstrates that one of the databases has a policy violation. Username guest is enabled in AdventureWorks database. You can disable the guest user by running the following code in AdventureWorks database. USE AdventureWorks; REVOKE CONNECT FROM guest; Once you run above query, you can already evaluate the policy again. Notice that the policy violation is fixed now. You can change the method of the evaluation policy to On Schedule and validate policy on interval. You can check the history of the policy and detect the violation. Quiz I have created three conditions to check if the guest user has database access or not. Now I want to ask you: Is it possible to do the same with 2 conditions? If yes, HOW? If no, WHY NOT? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Best Practices, CodeProject, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Technology Tagged: Policy Management

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  • SQL SERVER – Simple Example of Incremental Statistics – Performance improvements in SQL Server 2014 – Part 2

    - by Pinal Dave
    This is the second part of the series Incremental Statistics. Here is the index of the complete series. What is Incremental Statistics? – Performance improvements in SQL Server 2014 – Part 1 Simple Example of Incremental Statistics – Performance improvements in SQL Server 2014 – Part 2 DMV to Identify Incremental Statistics – Performance improvements in SQL Server 2014 – Part 3 In part 1 we have understood what is incremental statistics and now in this second part we will see a simple example of incremental statistics. This blog post is heavily inspired from my friend Balmukund’s must read blog post. If you have partitioned table and lots of data, this feature can be specifically very useful. Prerequisite Here are two things you must know before you start with the demonstrations. AdventureWorks – For the demonstration purpose I have installed AdventureWorks 2012 as an AdventureWorks 2014 in this demonstration. Partitions – You should know how partition works with databases. Setup Script Here is the setup script for creating Partition Function, Scheme, and the Table. We will populate the table based on the SalesOrderDetails table from AdventureWorks. -- Use Database USE AdventureWorks2014 GO -- Create Partition Function CREATE PARTITION FUNCTION IncrStatFn (INT) AS RANGE LEFT FOR VALUES (44000, 54000, 64000, 74000) GO -- Create Partition Scheme CREATE PARTITION SCHEME IncrStatSch AS PARTITION [IncrStatFn] TO ([PRIMARY], [PRIMARY], [PRIMARY], [PRIMARY], [PRIMARY]) GO -- Create Table Incremental_Statistics CREATE TABLE [IncrStatTab]( [SalesOrderID] [int] NOT NULL, [SalesOrderDetailID] [int] NOT NULL, [CarrierTrackingNumber] [nvarchar](25) NULL, [OrderQty] [smallint] NOT NULL, [ProductID] [int] NOT NULL, [SpecialOfferID] [int] NOT NULL, [UnitPrice] [money] NOT NULL, [UnitPriceDiscount] [money] NOT NULL, [ModifiedDate] [datetime] NOT NULL) ON IncrStatSch(SalesOrderID) GO -- Populate Table INSERT INTO [IncrStatTab]([SalesOrderID], [SalesOrderDetailID], [CarrierTrackingNumber], [OrderQty], [ProductID], [SpecialOfferID], [UnitPrice],   [UnitPriceDiscount], [ModifiedDate]) SELECT     [SalesOrderID], [SalesOrderDetailID], [CarrierTrackingNumber], [OrderQty], [ProductID], [SpecialOfferID], [UnitPrice],   [UnitPriceDiscount], [ModifiedDate] FROM       [Sales].[SalesOrderDetail] WHERE      SalesOrderID < 54000 GO Check Details Now we will check details in the partition table IncrStatSch. -- Check the partition SELECT * FROM sys.partitions WHERE OBJECT_ID = OBJECT_ID('IncrStatTab') GO You will notice that only a few of the partition are filled up with data and remaining all the partitions are empty. Now we will create statistics on the Table on the column SalesOrderID. However, here we will keep adding one more keyword which is INCREMENTAL = ON. Please note this is the new keyword and feature added in SQL Server 2014. It did not exist in earlier versions. -- Create Statistics CREATE STATISTICS IncrStat ON [IncrStatTab] (SalesOrderID) WITH FULLSCAN, INCREMENTAL = ON GO Now we have successfully created statistics let us check the statistical histogram of the table. Now let us once again populate the table with more data. This time the data are entered into a different partition than earlier populated partition. -- Populate Table INSERT INTO [IncrStatTab]([SalesOrderID], [SalesOrderDetailID], [CarrierTrackingNumber], [OrderQty], [ProductID], [SpecialOfferID], [UnitPrice],   [UnitPriceDiscount], [ModifiedDate]) SELECT     [SalesOrderID], [SalesOrderDetailID], [CarrierTrackingNumber], [OrderQty], [ProductID], [SpecialOfferID], [UnitPrice],   [UnitPriceDiscount], [ModifiedDate] FROM       [Sales].[SalesOrderDetail] WHERE      SalesOrderID > 54000 GO Let us check the status of the partition once again with following script. -- Check the partition SELECT * FROM sys.partitions WHERE OBJECT_ID = OBJECT_ID('IncrStatTab') GO Statistics Update Now here has the new feature come into action. Previously, if we have to update the statistics, we will have to FULLSCAN the entire table irrespective of which partition got the data. However, in SQL Server 2014 we can just specify which partition we want to update in terms of Statistics. Here is the script for the same. -- Update Statistics Manually UPDATE STATISTICS IncrStatTab (IncrStat) WITH RESAMPLE ON PARTITIONS(3, 4) GO Now let us check the statistics once again. -- Show Statistics DBCC SHOW_STATISTICS('IncrStatTab', IncrStat) WITH HISTOGRAM GO Upon examining statistics histogram, you will notice that now the distribution has changed and there is way more rows in the histogram. Summary The new feature of Incremental Statistics is indeed a boon for the scenario where there are partitions and statistics needs to be updated frequently on the partitions. In earlier version to update statistics one has to do FULLSCAN on the entire table which was wasting too many resources. With the new feature in SQL Server 2014, now only those partitions which are significantly changed can be specified in the script to update statistics. Cleanup You can clean up the database by executing following scripts. -- Clean up DROP TABLE [IncrStatTab] DROP PARTITION SCHEME [IncrStatSch] DROP PARTITION FUNCTION [IncrStatFn] GO Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: PostADay, SQL, SQL Authority, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL Tagged: SQL Statistics, Statistics

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  • What is a “pretty and proper OO” way for handling sessions and authentication?

    - by asdfqwer
    Is coupling these two concepts a bad approach? As of right now I'm delegating all session handling and whether or not a user desires to logout in my config.inc file. As I was writing my Auth class I started wondering whether or not my Auth class should be taking care of most of the logic in my config.inc. Regardless, I'm sure there's a more elegant way of handling this... Here is what I have in my config.inc (also a large chunk of this code is based on a reply I found on SO except I can't find the source ._.): ini_set('session.name', 'SID'); # session management session_set_cookie_params(24*60*60); // set SID cookie lifetime session_start(); if(isset($_SESSION['LOGOUT']) { session_destroy(); // destroy session data $_SESSION = array(); // destroy session data sanity check setcookie('SID', '', time() - 24*60*60); // destroy session cookie data #header('Location: '.DOCROOT); } elseif(isset($_SESSION['SID_AUTH'])) { // verify user has authenticated if (!isset($_SESSION['SID_CREATED'])) { $_SESSION['SID_CREATED'] = time(); } elseif (time() - $_SESSION['SID_CREATED'] > 6*60*60) { // session started more than 6 hours ago session_regenerate_id(); // reset SID value $_SESSION['SID_CREATED'] = time(); // update creation time } if (isset($_SESSION['SID_MODIFIED']) && (time() - $_SESSION['SID_MODIFIED'] > 12*60*60)) { // last request was more than 12 hours ago session_destroy(); // destroy session data $_SESSION = array(); // destroy session data sanity check setcookie('SID', '', time() - 24*60*60); // destroy session cookie data } $_SESSION['SID_MODIFIED'] = time(); // update last activity time stamp }

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  • Borland Starteam incorrect files status

    - by Kate
    I have some project saved in starteam. As there are a lot of obsolete files I can't check in or check out all project, only changed files. Now I copy project from one computer to another for other developer. I expect starteam treats copied project as new item for check in and check out, but it don't. Forexample: I modified file on fist computer. I update list of files on second computer and see this file in "check in" list, as I modified it on second computer. It is inncorrect. I think there is some configuration file or something like, that saves computer (or user) settings. So when project is copied, settings is copied too. Do anybody know how to change this configuration to set copied project as new instance of starteam???

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  • webui for mercurial (hg)

    - by Extreme
    i'm looking for a good webui tool for mercurial. i've found this link Mercurial with WebUI but what i'm looking for is something that has the ability to do check-in and check-out per file like the PVCS. any suggestions? thanks Edit: Here's the link for PVCS. http://en.wikipedia.org/wiki/PVCS It's been around 4 years since I last used PVCS and a lot has probably changed but here's as far as I remember. It has a web application wherein a developer can check out a single file. If this file is checked-out, it will be locked to this developer and no other developer can check it out. Then can download the source but they won't be able to check it in unless the original developer (that checked-out the file) checks it in.

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  • When is a scala partial function not a partial function?

    - by Fred Haslam
    While creating a map of String to partial functions I ran into unexpected behavior. When I create a partial function as a map element it works fine. When I allocate to a val it invokes instead. Trying to invoke the check generates an error. Is this expected? Am I doing something dumb? Comment out the check() to see the invocation. I am using scala 2.7.7 def PartialFunctionProblem() = { def dream()() = { println("~Dream~"); new Exception().printStackTrace() } val map = scala.collection.mutable.HashMap[String,()=>Unit]() map("dream") = dream() // partial function map("dream")() // invokes as expected val check = dream() // unexpected invocation check() // error: check of type Unit does not take parameters }

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  • Read out result of a PageMethod into a jQuery-script

    - by Jan-Frederik Carl
    Hello, I am quite a jQuery novice and try to read out the result of a PageMethod into my jQuery script. I have a ScriptManager installed and the following WebMethod: [WebMethod(EnableSession = true)] public static string CheckSystemDefault(string _id) { int id = Convert.ToInt16(_id); addressTypeRepository = new AddressTypeRepository(); AddressType addressType = addressTypeRepository.GetById(id); if (addressType.IsSystemDefault == true) return "IsSystemDefault"; else return "IsNotSystemDefault"; } I use this to check if an object has the property IsSystemDefault. In the script, I hand over the id from the url and want to evaluate the result: var id = $(document).getUrlParam("id"); var check = PageMethods.CheckSystemDefault(id); if (check == "IsSystemDefault") { ... } if (check == "IsNotSystemDefault") { ... } But as a result, the variable "check" is undefined. What do I have to change?

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  • Versioning APIs

    - by Sharon
    Suppose that you have a large project supported by an API base. The project also ships a public API that end(ish) users can use. Sometimes you need to make changes to the API base that supports your project. For example, you need to add a feature that needs an API change, a new method, or requires altering of one of the objects, or the format of one of those objects, passed to or from the API. Assuming that you are also using these objects in your public API, the public objects will also change any time you do this, which is undesirable as your clients may rely on the API objects remaining identical for their parsing code to work. (cough C++ WSDL clients...) So one potential solution is to version the API. But when we say "version" the API, it sounds like this also must mean to version the API objects as well as well as providing duplicate method calls for each changed method signature. So I would then have a plain old clr object for each version of my api, which again seems undesirable. And even if I do this, I surely won't be building each object from scratch as that would end up with vast amounts of duplicated code. Rather, the API is likely to extend the private objects we are using for our base API, but then we run into the same problem because added properties would also be available in the public API when they are not supposed to be. So what is some sanity that is usually applied to this situation? I know many public services such as Git for Windows maintains a versioned API, but I'm having trouble imagining an architecture that supports this without vast amounts of duplicate code covering the various versioned methods and input/output objects. I'm aware that processes such as semantic versioning attempt to put some sanity on when public API breaks should occur. The problem is more that it seems like many or most changes require breaking the public API if the objects aren't more separated, but I don't see a good way to do that without duplicating code.

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