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  • php mysql parallel array checkboxes

    - by gramware
    I have an array of checkboxes that I edit at once to set up a 'tinyint' field. the problem comes in when i uncheck the checkbox and post the vales to mysql. since it posts an array of checkboxes and another parallel array of values to edit, unchecking a checkbox results in the 0 value been ignored by PHP_POST and hence the checkbox array will be less by the number of unchecked values in the form while the array to be edited will have all the records in the form. here is the submit code while($row=mysql_fetch_array($result)) { $checked = ($row[active]==1) ? 'checked="checked"' : ''; ... echo "<input type='hidden' name='TrID[]' value='$TrID'>"; echo "<input type='checkbox' name='active1[]' value='$row[active]''$checked' >"; ... and the processing php script $userid = ($_POST['TrID']); $checked= ($_POST['active']); $i=0; foreach ($userid as $usid) { if ($checked[$i]==1){ $check = 1; } else{ $check = 0; } $qry1 ="UPDATE `epapers`.`clientelle` SET `active` = '$check' WHERE `clientelle`.`user_id` = '$usid' "; $result = mysql_query($qry1); $i++; }

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  • Django ModelFormSet with Google app engine

    - by Eric
    I'm using Django with google app engine. I'm using the google furnished django app engine helper project. I'm attempting to create a Django modelformset like this: #MyModel inherits from BaseModel MyFormSet = modelformset_factory(models.MyModel) However, it's failing with this error: 'ModelOptions' object has no attribute 'fields' Apparently modelformset_factory() is expecting MyModel to implement a 'fields' accessor. Anybody successfully used a modelformset with GAE datastore? Or is this a fundamental incompatibility between Django and GAE?

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  • FormsAuthentication.SetAuthCookie

    - by Miral
    hi we are using FormsAuthentication.SetAuthCookie(profile.Id, false); Now the question is when does this cookie expires? It ofcourse expires once i close all the browsers but it doesn't i keep the browser open and i dont know the timelimit.

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  • Storing JSON in an SQL Server database?

    - by JKirchartz
    I'm developing a form generator, and wondering if it would be bad mojo to store JSON in an SQL Server database? I want to keep my database & tables simple, so I was going to have `pKey, formTitle, formJSON` on a table, and then store {["firstName":{"required":"true","type":"text"},"lastName":{"required":"true","type":"text"}} in formJSON. would this slow down the DB server too much to set live? Any input is appreciated.

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  • Center aligned form with equal width labels

    - by James Goodwin
    I have a very simple web form which consists of labels and input fields, however I can not seem to find a way of aligning the form in the center of the page and for the labels to have an equal width so that they appear neatly next to each other, one under the other. The structure of my page is basically: <body> <div class="form"> <form method="post"> <fieldset> <label>Mobile:</label><input type="text" name="msisdn"><br/> <label>Code:</label><input type="text" name="code"><br/> <br/> <input type="image" src="submit-button.gif" alt="Submit"> <br/> <input type="checkbox" name="ts_and_cs"><label> Accept Terms and Conditions</label> <br/><br/> </fieldset> </form> </div> </body> Usually I would fix this by doing float:left on the label fields and setting a width on the labels, however for this I need the labels and input fields to be centered on the page. Also I am not able to set the width of the page (or any containing divs) as the page will be displayed on mobile devices with different screen sizes. Any suggestions as to how best style the form? Thanks

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  • Using javascript to add form fields, but what will the new name be?

    - by user1322844
    After reading this post: using javascript to add form fields.. but below, not to the side? I've made the button work! But I don't know how to receive the output. This is what I entered. var counter = 0; function addNew() { // Get the main Div in which all the other divs will be added var mainContainer = document.getElementById('mainContainer'); // Create a new div for holding text and button input elements var newDiv = document.createElement('div'); // Create a new text input var newText = document.createElement('input'); newText.type = "input"; newText.maxlength = "50"; newText.maxlimit = "50"; newText.size = "60"; newText.value = counter; // Create a new button input var newDelButton = document.createElement('input'); newDelButton.type = "button"; newDelButton.value = "Delete"; // Append new text input to the newDiv newDiv.appendChild(newText); // Append new button input to the newDiv newDiv.appendChild(newDelButton); // Append newDiv input to the mainContainer div mainContainer.appendChild(newDiv); counter++; // Add a handler to button for deleting the newDiv from the mainContainer newDelButton.onclick = function() { mainContainer.removeChild(newDiv); } } </script> With this in the form: <input type="button" size="3" cols="30" value="Add" onClick="addNew()"> So, what will the new field names be? I don't understand enough of the coding to figure out what I'm telling it to. Good thing there are other smart folks out there for me to lean on! Thanks for any answers.

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  • Usability standards when combining AJAX and regular POST-based form saves

    - by mcrider
    I'm working on a project where on certain pages (e.g. settings pages) we combine AJAX and regular fill-out-the-form-then-submit POST based operations. I'm curious if anyone has advice on improving the usability of such a page. One of my ideas is that when the user enters/modifies a value in a non-ajax part of the page, some sort of div would appear (say in a fashion similar to Growl) indicating that the user needs to save by pressing 'Submit' at the bottom of the page (and possibly putting up a modal dialog if the user navigates away from the page before saving, though that might be a bit too intrusive). I'm sure this type of interaction exists, but I can't find any examples.

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  • Post ASP.Net Form data to another page

    - by william
    I have an ASP.Net Page, aspx with its default form. I have a Submit Button for it. Upon clicking, it will post the data to itself. In other words, Button Click Event() from code behind will execute the necessary. After that, I would like to post the same data to another ASp.Net Page, aspx from another domain. So, how can I do it? I tried creating a Form in Button Click Event and a javascript to Submit the Form so that it will post. But the Form is not appearing hence there is already aForm` on the page. Is there anyway to do it?

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  • Simulated click on "add more value" button of multi value cck field causes whole content form to sub

    - by ninja
    Hi I have a multi value cck field in my cck content type. I want to simulate click on "add another item" using jquery. which is like $('#edit-field-supp-quan-field-supp-quan-add-more').trigger('click'); but it causes whole content form to submit instead of adding extra multi value cck field. Manuall clicks are working perfectly. Can anyone tell me why behavior of manual clicks and simulated clicks are different. thanks ----Update ---- This is the code I was using:- $('#edit-field-freightamount-0-value').click(function(){ alert('hello'); $('#edit-field-supp-quan-field-supp-quan-add-more').trigger('click'); //$('.form-submit ahah-processed').trigger('click'); }); I actually intended to call this from inside some other function but I just wanted to test it before that . So i wrote this dummy function which is like if i click inside a texrfield it should simulate a click on "add more item" How do we prevent default action of click?

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  • does sfWidgetFormSelect provide a string or an int of the selected item?

    - by han
    Hey guys, I'm having an annoying problem. I'm trying to find out what fields of a form were changed, and then insert that into a table. I managed to var_dump in doUpdateObjectas shown in the following public function doUpdateObject($values) { parent::doUpdateObject($values); var_dump($this->getObject()->getModified(false)); var_dump($this->getObject()->getModified(true)); } And it seems like $this-getObject()-getModified seems to work in giving me both before and after values by setting it to either true or false. The problem that I'm facing right now is that, some how, sfWidgetFormSelect seems to be saving one of my fields as a string. before saving, that exact same field was an int. (I got this idea by var_dump both before and after). Here is what the results on both var dumps showed: array(1) {["annoying_field"]=> int(3)} array(1) {["annoying_field"]=>string(1)"3"} This seems to cause doctrine to think that this is a modification and thus gives a false positive. In my base form, I have under $this->getWidgets() 'annoying_field' => new sfWidgetFormInputText(), under $this->setValidators 'annoying_field' => new sfValidatorInteger(array('required' => false)), and lastly in my configured Form.class.php I have reconfigured the file as such: $this->widgetSchema['annoying_field'] = new sfWidgetFormSelect(array('choices' => $statuses)); statuses is an array containing values like {""a", "b", "c", "d"} and I just want the index of the status to be stored in the database. And also how can I insert the changes into another database table? let's say my Log table? Any ideas and advice as to why this is happen is appreciated, I've been trying to figure it out and browsing google for various keywords with no avail. Thanks! Edit: ok so I created another field, integer in my schema just for testing. I created an entry, saved it, and edited it. this time the same thing happened!

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  • How come my form input sometimes moves when I refresh the page?

    - by samoz
    On a page that I'm designing I have a form with one input of type text. Normally, this form and input render properly in my browser, Chrome, but occasionally, it renders about 20 pixels to the left of where it is supposed to be. When I refresh the page, it goes back to the original, correct place. I have only tested in Chrome so far, so this isn't a cross-browser issue (it happens in the same browser). Is there anything wrong with my code below? Here's my HTML code: <!DOCTYPE htmls> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <link rel="stylesheet" href="style.css" type="text/css" /> <title>Test Site</title> </head> <body > <div id="supercontainer" class="style1"> <img class="floater" src="top.jpg" alt="Top" /> <img class="floater" src="left.jpg" alt="Left" /> <div id="content"> <p id="theText"> Welcome. Please type a username. </p> <form id="prompt"> <div><input type="text" name="promptLine" autocomplete="off" id="promptLine" onkeypress="return submitenter(event);" value="% " /></div> </form> </div> <img class="floater" src="right.jpg" alt="Right" /> <img class="floater" src="bottom.jpg" alt="Bottom" /> </div> Here's my CSS code: #supercontainer { margin: 0 auto; width: 900px; display: block; } img.floater { display: inline; float: left; } #content { background-color:black; display: inline; float: left; padding-left:5px; padding-right:5px; min-height:458px; max-height:458px; min-width: 803px; max-width: 803px; color: lime; } #theText { text-align:left; margin-bottom:0; margin-top:0; line-height: 0.3; font-family:"Courier New", Courier, monospace; } #prompt { position: fixed; top: 470px; } #promptLine { width: 100%; background-color: black; color: lime; border: none; outline:none; }

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  • Why always fires OnFailure when return View() to Ajax Form ?

    - by Wahid Bitar
    I'm trying to make a log-in log-off with Ajax supported. I made some logic in my controller to sign the user in and then return simple partial containing welcome message and log-Off ActionLink my Action method looks like this : public ActionResult LogOn(LogOnModel model, string returnUrl) { if (ModelState.IsValid) { if (MembershipService.ValidateUser(model.UserName, model.Password)) { FormsService.SignIn(model.UserName, model.RememberMe); if (Request.IsAjaxRequest()) { //HERE IS THE PROBLEM :( return View("LogedInForm"); } else { if (!String.IsNullOrEmpty(returnUrl)) return Redirect(returnUrl); else return RedirectToAction("Index", "Home"); } } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); if (Request.IsAjaxRequest()) { return Content("There were an error !"); } } } return View(model); } and I'm trying to return this simple partial : Welcome <b><%= Html.Encode(Model.UserName)%></b>! <%= Html.ActionLink("Log Off", "LogOff", "Account") %> and of-course the two partial are strongly-typed to LogOnModel. But if i returned View("PartialName") i always get OnFailure with status code 500. While if i returned Content("My Message") everything is going right. so please tell me why i always get this "StatusCode = 500" ??. where is the big mistake ??. By the way in my Site MasterPage i rendered partial to show long-on simple form this partial looks like this : <script type="text/javascript"> function ShowErrorMessage(ajaxContext) { var response = ajaxContext.get_response(); var statusCode = response.get_statusCode(); alert("Sorry, the request failed with status code " + statusCode); } function ShowSuccessMessage() { alert("Hey everything is OK!"); } </script> <div id="logedInDiv"> </div> <% using (Ajax.BeginForm("LogOn", "Account", new AjaxOptions { UpdateTargetId = "logedInDiv", InsertionMode = InsertionMode.Replace, OnSuccess = "ShowSuccessMessage", OnFailure = "ShowErrorMessage" })) { %> <%= Html.TextBoxFor(m => m.UserName)%> <%= Html.PasswordFor(m => m.Password)%> <%= Html.CheckBoxFor(m => m.RememberMe)%> <input type="submit" value="Log On" /> < <% } %>

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  • radio value lost by $_post array

    - by YsoL8
    Hello I have this simple form: <form method="post" action="?step=2"> <label>A4 - Colour / Colour <input type="radio" name="leaflet" value="1"></label><br> <label>A5 - Colour / Black <input type="radio" name="leaflet" value="2"></label><br> <input type="submit" name="leaflet" value="Select"> </form> When I apply print_r ($_POST); to the submission though, I only get the submit button data. I don't even see the radio name. What could do that?

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  • How can I split a PHP form into two sections, before submission to a database?

    - by Daniel Smith
    Hi guys, I have set up a PHP form for a competition, for users to enter and all information to be stored in a database. I used the following NetTut+ tutorial to do so: http://tr.im/SwAd. I've got the form submitting to the database as required, but with so many additional questions being asked, I would like to split the form into two separate sections. Obviously the first page would say continue to the next step before the second step allowing for the form to be submitted to the database. The content that the user sees should be split, but should all be a part of the same form. Step 1 Step 2 before submission. Would anyone know of or recommend any methods to do this? I'm a beginner so please be nice. :) Cheers, Daniel

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  • Inline Form Validation in Django

    - by allanhenderson
    Newbie request that seems difficult to implement. I would like to make an entire inline formset within an admin change form compulsory.. so in my current scenario when I hit save on an Invoice form (in Admin) the inline Order form is blank. I'd like to stop people creating invoices with no orders associated. Anyone know an easy way to do that? Normal validation like (required=True) on the model field doesn't appear to work in this instance. Thanks!!

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  • Symfony 1.3: how to force as inline the choices generated by renderLabel()

    - by user248959
    Hi, this line: <li><?php echo $form['genero']->renderLabel() ?></li> is generating <li> <label for="usuario_genero">Genero</label> <ul class="radio_list"> <li> <!-- this li doesn't have any id--> <input type="radio" checked="checked" id="usuario_genero_0" value="0" name="usuario[genero]">&nbsp;<label for="usuario_genero_0">Chico</label> </li> <li> <!-- this li doesn't have any id--> <input type="radio" id="usuario_genero_1" value="1" name="usuario[genero]">&nbsp;<label for="usuario_genero_1">Chica</label> </li> </ul> </li> I'd like to force the choices as inline, but the li's generated don't have the 'id' attribute. What should i do? Regards Javi

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  • Form Validation using javascript in joomla

    - by Ankur
    I want to use form validation. I have used javascript for this and I have downloaded the com_php0.1alpha-J15.tar component for writing php code but the blank entries are goes to the database. Please guide me... sample code is here... <script language="javascript" type="text/javascript"> function Validation() { if(document.getElementById("name").value=="") { document.getElementById("nameerr").innerHTML="Enter Name"; document.getElementById("name").style.backgroundColor = "yellow"; } else { document.getElementById("nameerr").innerHTML=""; document.getElementById("name").style.backgroundColor = "White"; } if(document.getElementById("email").value=="") { document.getElementById("emailerr").innerHTML="Enter Email"; document.getElementById("email").style.backgroundColor = "yellow"; } else { document.getElementById("emailerr").innerHTML=""; document.getElementById("email").style.backgroundColor = "White"; } if(document.getElementById("phone").value=="") { document.getElementById("phoneerr").innerHTML="Enter Contact No"; document.getElementById("phone").style.backgroundColor = "yellow"; } else { document.getElementById("phoneerr").innerHTML=""; document.getElementById("phone").style.backgroundColor = "White"; } if(document.getElementById("society").value=="") { document.getElementById("societyerr").innerHTML="Enter Society"; document.getElementById("society").style.backgroundColor = "yellow"; } else { document.getElementById("societyerr").innerHTML=""; document.getElementById("society").style.backgroundColor = "White"; } if(document.getElementById("occupation").value=="") { document.getElementById("occupationerr").innerHTML="Enter Occupation"; document.getElementById("occupation").style.backgroundColor = "yellow"; } else { document.getElementById("occupationerr").innerHTML=""; document.getElementById("occupation").style.backgroundColor = "White"; } if(document.getElementById("feedback").value=="") { document.getElementById("feedbackerr").innerHTML="Enter Feedback"; document.getElementById("feedback").style.backgroundColor = "yellow"; } else { document.getElementById("feedbackerr").innerHTML=""; document.getElementById("feedback").style.backgroundColor = "White"; } if(document.getElementById("name").value=="" || document.getElementById("email").value=="" || document.getElementById("phone").value=="" || document.getElementById("society").value=="" || document.getElementById("occupation").value=="" || document.getElementById("feedback").value=="") return false; else return true; } </script> <?php if(isset($_POST['submit'])) { $conn = mysql_connect('localhost','root',''); mysql_select_db('society_f',$conn); $name = $_POST['name']; $email = $_POST['email']; $phone = $_POST['phone']; $society = $_POST['society']; $occupation = $_POST['occupation']; $feedback = $_POST['feedback']; $qry = "insert into feedback values(null". ",'" . $name . "','" . $email . "','" . $phone . "','" . $society . "','" . $occupation . "','" . $feedback . "')" ; $res = mysql_query($qry); if(!$res) { echo "Could not run a query" . mysql_error(); exit(); } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> <style type="text/css"> .td{ background-color:#FFFFFF; color:#000066; width:100px; } .text{ border:1px solid #0033FF; color:#000000; } </style> </head> <body> <form id="form1" method="post"> <input type="hidden" name="check" value="post"/> <table border="0" align="center" cellpadding="2" cellspacing="2"> <tr> <td colspan="3" style="text-align:center;"><span style="font-size:24px;color:#000066;">Feedback Form</span></td> </tr> <tr> <td class="td">Name</td> <td><input type="text" id="name" name="name" class="text" ></td> <td style="font-style:italic;color:#FF0000;" id="nameerr"></td> </tr> <tr> <td class="td">E-mail</td> <td><input type="text" id="Email" name="Email" class="text"></td> <td style="font-style:italic;color:#FF0000;" id="emailerr"></td> </tr> <tr> <td class="td">Contact No</td> <td><input type="text" id="Phone" name="Phone" maxlength="15" class="text"></td> <td style="font-style:italic;color:#FF0000;" id="Phoneerr"></td> </tr> <tr> <td class="td">Your Society</td> <td><input type="text" id="society" name="society" class="text"></td> <td style="font-style:italic;color:#FF0000;" id="societyerr"></td> </tr> <tr> <td class="td">Occupation</td> <td><input type="text" id="occupation" name="occupation" class="text"></td> <td style="font-style:italic;color:#FF0000;" id="occupationerr"></td> </tr> <tr> <td class="td">Feedback</td> <td><textarea name="feedback" id="feedback" class="text"></textarea></td> <td style="font-style:italic;color:#FF0000;" id="feedbackerr"></td> </tr> <tr> <td colspan="3" style="text-align:center;"> <input type="submit" value="Submit" id="submit" onClick="Validation();" /> <input type="reset" value="Reset" onClick="Resetme();" /> </td> </tr> </table> </form> </body> </html>

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  • 'button_to' gives me an ugly URL!

    - by Tyler
    Im trying to get an 'add to cart' button to work. When I use <%= button_to "Add to Cart", :acton = "add_to_cart", :id = @product % and then click the button, I get a URL that puts the action after the ID, like this: 'http://localhost:3000/store/show/1?acton=add_to_cart.' The cart page does not load. What I need is a URL that looks like this: 'http://localhost:3000/store/add_to_cart/1'. I can get that result (and the cart to work) if I don't use 'button_to': <% form_for @product, :url = {:action = "add_to_cart", :id = @product} do |f| % <% end % But, what the heck? Why can't I use 'button_to'?

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  • How to lock non-browser clients from submitting a request?

    - by Thomas Kohl
    I want to block non-browser clients from accessing certain pages / successfully making a request. The website content is served to authenticated users. What happens is that our user gives his credentials to our website to 3rd party - it can be another website or a mobile application - that performs requests on his behalf. Say there is a form that the user fills out and sends a message. Can I protect this form so that the server processing the submission can tell whether the user has submitted it directly from the browser or not? I don't want to use CAPTCHA for usability reasons. Can I do it with some javascript?

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  • Can a simple web form like this get hacked?

    - by Haskella
    Hi I have a web form that sends a string to one php file which redirects them to a corresponding URL. I've searched about web form hacking and I've only received information about PHP and SQL... my site only uses a single PHP file, very basic etc. Would it be open to any exploits? I'm obviously not going to post the URL, but here is some code I was working on for the php file: http://stackoverflow.com/questions/2888077/newbie-php-coding-problem-header-function-maybe-i-need-someone-to-check-my-cod Thanks

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  • Storing JSON in an msSQL database?

    - by JKirchartz
    I'm developing a form generator, and wondering if it would be bad mojo to store JSON in an SQL database? I want to keep my database & tables simple, so I was going to have `pKey, formTitle, formJSON` on a table, and then store {["firstName":{"required":"true","type":"text"},"lastName":{"required":"true","type":"text"}} in formJSON. would this slow down the DB server too much to set live? Any input is appreciated.

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