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  • Inline Form Validation in Django

    - by allanhenderson
    Newbie request that seems difficult to implement. I would like to make an entire inline formset within an admin change form compulsory.. so in my current scenario when I hit save on an Invoice form (in Admin) the inline Order form is blank. I'd like to stop people creating invoices with no orders associated. Anyone know an easy way to do that? Normal validation like (required=True) on the model field doesn't appear to work in this instance. Thanks!!

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  • radio value lost by $_post array

    - by YsoL8
    Hello I have this simple form: <form method="post" action="?step=2"> <label>A4 - Colour / Colour <input type="radio" name="leaflet" value="1"></label><br> <label>A5 - Colour / Black <input type="radio" name="leaflet" value="2"></label><br> <input type="submit" name="leaflet" value="Select"> </form> When I apply print_r ($_POST); to the submission though, I only get the submit button data. I don't even see the radio name. What could do that?

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  • does sfWidgetFormSelect provide a string or an int of the selected item?

    - by han
    Hey guys, I'm having an annoying problem. I'm trying to find out what fields of a form were changed, and then insert that into a table. I managed to var_dump in doUpdateObjectas shown in the following public function doUpdateObject($values) { parent::doUpdateObject($values); var_dump($this->getObject()->getModified(false)); var_dump($this->getObject()->getModified(true)); } And it seems like $this-getObject()-getModified seems to work in giving me both before and after values by setting it to either true or false. The problem that I'm facing right now is that, some how, sfWidgetFormSelect seems to be saving one of my fields as a string. before saving, that exact same field was an int. (I got this idea by var_dump both before and after). Here is what the results on both var dumps showed: array(1) {["annoying_field"]=> int(3)} array(1) {["annoying_field"]=>string(1)"3"} This seems to cause doctrine to think that this is a modification and thus gives a false positive. In my base form, I have under $this->getWidgets() 'annoying_field' => new sfWidgetFormInputText(), under $this->setValidators 'annoying_field' => new sfValidatorInteger(array('required' => false)), and lastly in my configured Form.class.php I have reconfigured the file as such: $this->widgetSchema['annoying_field'] = new sfWidgetFormSelect(array('choices' => $statuses)); statuses is an array containing values like {""a", "b", "c", "d"} and I just want the index of the status to be stored in the database. And also how can I insert the changes into another database table? let's say my Log table? Any ideas and advice as to why this is happen is appreciated, I've been trying to figure it out and browsing google for various keywords with no avail. Thanks! Edit: ok so I created another field, integer in my schema just for testing. I created an entry, saved it, and edited it. this time the same thing happened!

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  • How to post Arabic characters in PHP

    - by Peter Stuart
    Okay, So I am writing an OpenCart extension that must allow Arabic characters when posting data. Whenever I post ????? the print_r($_POST) returns with this: u0645u0631u062du0628u0627 I check the HTML header and it has this: <meta charset="UTF-8" /> I checked the PHP file that triggers all SQL queries and it has this code: mysql_query("SET NAMES 'utf8'", $this->link); mysql_query("SET CHARACTER SET utf8", $this->link); mysql_query("SET CHARACTER_SET_CONNECTION=utf8", $this->link); This is in my form tag: <form action="<?php echo $action; ?>" method="post" enctype="multipart/form-data" id="form" accept-charset="utf-8"> I can't think of what else I am doing wrong. The rest of the OpenCart framework supports UTF8 and arabic characters. It is just in this instance where I can't post anything arabic? Could someone please help me? Many Thanks Peter

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  • Django ModelFormSet with Google app engine

    - by Eric
    I'm using Django with google app engine. I'm using the google furnished django app engine helper project. I'm attempting to create a Django modelformset like this: #MyModel inherits from BaseModel MyFormSet = modelformset_factory(models.MyModel) However, it's failing with this error: 'ModelOptions' object has no attribute 'fields' Apparently modelformset_factory() is expecting MyModel to implement a 'fields' accessor. Anybody successfully used a modelformset with GAE datastore? Or is this a fundamental incompatibility between Django and GAE?

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  • Drupal 7: File field causes error with Dependable Dropdowns

    - by LoneWolfPR
    I'm building a Form in a module using the Form API. I've had a couple of dependent dropdowns that have been working just fine. The code is as follows: $types = db_query('SELECT * FROM {touchpoints_metric_types}') -> fetchAllKeyed(0, 1); $types = array('0' => '- Select -') + $types; $selectedType = isset($form_state['values']['metrictype']) ? $form_state['values']['metrictype'] : 0; $methods = _get_methods($selectedType); $selectedMethod = isset($form_state['values']['measurementmethod']) ? $form_state['values']['measurementmethod'] : 0; $form['metrictype'] = array( '#type' => 'select', '#title' => t('Metric Type'), '#options' => $types, '#default_value' => $selectedType, '#ajax' => array( 'event' => 'change', 'wrapper' => 'method-wrapper', 'callback' => 'touchpoints_method_callback' ) ); $form['measurementmethod'] = array( '#type' => 'select', '#title' => t('Measurement Method'), '#prefix' => '<div id="method-wrapper">', '#suffix' => '</div>', '#options' => $methods, '#default_value' => $selectedMethod, ); Here are the _get_methods and touchpoints_method_callback functions: function _get_methods($selected) { if ($selected) { $methods = db_query("SELECT * FROM {touchpoints_m_methods} WHERE mt_id=$selected") -> fetchAllKeyed(0, 2); } else { $methods = array(); } $methods = array('0' => "- Select -") + $methods; return $methods; } function touchpoints_method_callback($form, &$form_state) { return $form['measurementmethod']; } This all worked fine until I added a file field to the form. Here is the code I used for that: $form['metricfile'] = array( '#type' => 'file', '#title' => 'Attach a File', ); Now that the file is added if I change the first dropdown it hangs with the 'Please wait' message next to it without ever loading the contents of the second dropdown. I also get the following error in my JavaScript console: "Uncaught TypeError: Object function (a,b){return new p.fn.init(a,b,c)} has no method 'handleError'" What am I doing wrong here?

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  • Post ASP.Net Form data to another page

    - by william
    I have an ASP.Net Page, aspx with its default form. I have a Submit Button for it. Upon clicking, it will post the data to itself. In other words, Button Click Event() from code behind will execute the necessary. After that, I would like to post the same data to another ASp.Net Page, aspx from another domain. So, how can I do it? I tried creating a Form in Button Click Event and a javascript to Submit the Form so that it will post. But the Form is not appearing hence there is already aForm` on the page. Is there anyway to do it?

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  • How do I retain uploaded files after POsting a form with a file upload?

    - by Ali
    Hi guys is it possible to be able to retain an uploaded file AFTER its been uploaded I mean I'm building a compose email application. Users can upload files as attachments. AT times out of 10 uploaded files one of them isn't uploaded correctly or the submitted form is invalid the compose page would be displayed again however the user would ned to upload the file again this time. Is it possible to somehow maintain the uploaded files somewhere on the first upload and if the form is invalid - be able to display links to the file uploaded or so?

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  • php mysql parallel array checkboxes

    - by gramware
    I have an array of checkboxes that I edit at once to set up a 'tinyint' field. the problem comes in when i uncheck the checkbox and post the vales to mysql. since it posts an array of checkboxes and another parallel array of values to edit, unchecking a checkbox results in the 0 value been ignored by PHP_POST and hence the checkbox array will be less by the number of unchecked values in the form while the array to be edited will have all the records in the form. here is the submit code while($row=mysql_fetch_array($result)) { $checked = ($row[active]==1) ? 'checked="checked"' : ''; ... echo "<input type='hidden' name='TrID[]' value='$TrID'>"; echo "<input type='checkbox' name='active1[]' value='$row[active]''$checked' >"; ... and the processing php script $userid = ($_POST['TrID']); $checked= ($_POST['active']); $i=0; foreach ($userid as $usid) { if ($checked[$i]==1){ $check = 1; } else{ $check = 0; } $qry1 ="UPDATE `epapers`.`clientelle` SET `active` = '$check' WHERE `clientelle`.`user_id` = '$usid' "; $result = mysql_query($qry1); $i++; }

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  • Editting ForeignKey from "child" table

    - by profuel
    I'm programming on py with django. I have models: class Product(mymodels.Base): title = models.CharField() price = models.ForeignKey(Price) promoPrice = models.ForeignKey(Price, related_name="promo_price") class Price(mymodels.Base): value = models.DecimalField(max_digits=10, decimal_places=3) taxValue = models.DecimalField("Tax Value", max_digits=10, decimal_places=3) valueWithTax = models.DecimalField("Value with Tax", max_digits=10, decimal_places=3) I want to see INPUTs for both prices when editing product, but cannot find any possibility to do that. inlines = [...] works only from Price to Product, which is stupid in this case. Thanx for adnvance.

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  • How can I split a PHP form into two sections, before submission to a database?

    - by Daniel Smith
    Hi guys, I have set up a PHP form for a competition, for users to enter and all information to be stored in a database. I used the following NetTut+ tutorial to do so: http://tr.im/SwAd. I've got the form submitting to the database as required, but with so many additional questions being asked, I would like to split the form into two separate sections. Obviously the first page would say continue to the next step before the second step allowing for the form to be submitted to the database. The content that the user sees should be split, but should all be a part of the same form. Step 1 Step 2 before submission. Would anyone know of or recommend any methods to do this? I'm a beginner so please be nice. :) Cheers, Daniel

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  • Why always fires OnFailure when return View() to Ajax Form ?

    - by Wahid Bitar
    I'm trying to make a log-in log-off with Ajax supported. I made some logic in my controller to sign the user in and then return simple partial containing welcome message and log-Off ActionLink my Action method looks like this : public ActionResult LogOn(LogOnModel model, string returnUrl) { if (ModelState.IsValid) { if (MembershipService.ValidateUser(model.UserName, model.Password)) { FormsService.SignIn(model.UserName, model.RememberMe); if (Request.IsAjaxRequest()) { //HERE IS THE PROBLEM :( return View("LogedInForm"); } else { if (!String.IsNullOrEmpty(returnUrl)) return Redirect(returnUrl); else return RedirectToAction("Index", "Home"); } } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); if (Request.IsAjaxRequest()) { return Content("There were an error !"); } } } return View(model); } and I'm trying to return this simple partial : Welcome <b><%= Html.Encode(Model.UserName)%></b>! <%= Html.ActionLink("Log Off", "LogOff", "Account") %> and of-course the two partial are strongly-typed to LogOnModel. But if i returned View("PartialName") i always get OnFailure with status code 500. While if i returned Content("My Message") everything is going right. so please tell me why i always get this "StatusCode = 500" ??. where is the big mistake ??. By the way in my Site MasterPage i rendered partial to show long-on simple form this partial looks like this : <script type="text/javascript"> function ShowErrorMessage(ajaxContext) { var response = ajaxContext.get_response(); var statusCode = response.get_statusCode(); alert("Sorry, the request failed with status code " + statusCode); } function ShowSuccessMessage() { alert("Hey everything is OK!"); } </script> <div id="logedInDiv"> </div> <% using (Ajax.BeginForm("LogOn", "Account", new AjaxOptions { UpdateTargetId = "logedInDiv", InsertionMode = InsertionMode.Replace, OnSuccess = "ShowSuccessMessage", OnFailure = "ShowErrorMessage" })) { %> <%= Html.TextBoxFor(m => m.UserName)%> <%= Html.PasswordFor(m => m.Password)%> <%= Html.CheckBoxFor(m => m.RememberMe)%> <input type="submit" value="Log On" /> < <% } %>

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  • Facebook charset detection mechanism?

    - by Void
    Today, I have looked into HTML code of facebook.com, and found something like this: <input type="hidden" value="€,´,€,´,?,?,?" name="charset_test"/> It's repeated two times inside the <form>...</form>. Any idea what this code might be useful for - some kind of server-side client charset detection? As far as I know, browser charset is being transmitted in HTTP request anyway (an "Accept-Charset" header).

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  • Symfony 1.3: how to force as inline the choices generated by renderLabel()

    - by user248959
    Hi, this line: <li><?php echo $form['genero']->renderLabel() ?></li> is generating <li> <label for="usuario_genero">Genero</label> <ul class="radio_list"> <li> <!-- this li doesn't have any id--> <input type="radio" checked="checked" id="usuario_genero_0" value="0" name="usuario[genero]">&nbsp;<label for="usuario_genero_0">Chico</label> </li> <li> <!-- this li doesn't have any id--> <input type="radio" id="usuario_genero_1" value="1" name="usuario[genero]">&nbsp;<label for="usuario_genero_1">Chica</label> </li> </ul> </li> I'd like to force the choices as inline, but the li's generated don't have the 'id' attribute. What should i do? Regards Javi

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  • Simulated click on "add more value" button of multi value cck field causes whole content form to sub

    - by ninja
    Hi I have a multi value cck field in my cck content type. I want to simulate click on "add another item" using jquery. which is like $('#edit-field-supp-quan-field-supp-quan-add-more').trigger('click'); but it causes whole content form to submit instead of adding extra multi value cck field. Manuall clicks are working perfectly. Can anyone tell me why behavior of manual clicks and simulated clicks are different. thanks ----Update ---- This is the code I was using:- $('#edit-field-freightamount-0-value').click(function(){ alert('hello'); $('#edit-field-supp-quan-field-supp-quan-add-more').trigger('click'); //$('.form-submit ahah-processed').trigger('click'); }); I actually intended to call this from inside some other function but I just wanted to test it before that . So i wrote this dummy function which is like if i click inside a texrfield it should simulate a click on "add more item" How do we prevent default action of click?

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  • Best way to create a preview functionality in rails

    - by slythic
    Hi all, I'm looking to implement a preview functionality in my posts scaffold. All I need to do is allow a user to enter information in the new view (/posts/new) and then replace the submit button with a preview button. Once the preview button is clicked, the user is routed to the preview page (probably /posts/new/preview). If the user wants to make a change they would click 'go back' or if they are happy with the post they can then submit the post. I found this article (http://eyedeal.team88.org/node/105) but it seems dated. Any ideas on what the best approach for this would be? Many thanks, Tony

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  • [C#] Closing a MenuStrip programatically

    - by Nilbert
    I have a MenuStrip that I have added to a form, and in one of the dropdown menus in it, I have a text box. When I hit enter on the textbox, I want a function to run, then the drop down menu to close. I know how to get the enter part done, but I have no idea how to close the MenuStrip dropdown menu. Does anybody know how to do this?

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  • How come my form input sometimes moves when I refresh the page?

    - by samoz
    On a page that I'm designing I have a form with one input of type text. Normally, this form and input render properly in my browser, Chrome, but occasionally, it renders about 20 pixels to the left of where it is supposed to be. When I refresh the page, it goes back to the original, correct place. I have only tested in Chrome so far, so this isn't a cross-browser issue (it happens in the same browser). Is there anything wrong with my code below? Here's my HTML code: <!DOCTYPE htmls> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <link rel="stylesheet" href="style.css" type="text/css" /> <title>Test Site</title> </head> <body > <div id="supercontainer" class="style1"> <img class="floater" src="top.jpg" alt="Top" /> <img class="floater" src="left.jpg" alt="Left" /> <div id="content"> <p id="theText"> Welcome. Please type a username. </p> <form id="prompt"> <div><input type="text" name="promptLine" autocomplete="off" id="promptLine" onkeypress="return submitenter(event);" value="% " /></div> </form> </div> <img class="floater" src="right.jpg" alt="Right" /> <img class="floater" src="bottom.jpg" alt="Bottom" /> </div> Here's my CSS code: #supercontainer { margin: 0 auto; width: 900px; display: block; } img.floater { display: inline; float: left; } #content { background-color:black; display: inline; float: left; padding-left:5px; padding-right:5px; min-height:458px; max-height:458px; min-width: 803px; max-width: 803px; color: lime; } #theText { text-align:left; margin-bottom:0; margin-top:0; line-height: 0.3; font-family:"Courier New", Courier, monospace; } #prompt { position: fixed; top: 470px; } #promptLine { width: 100%; background-color: black; color: lime; border: none; outline:none; }

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  • Can a simple web form like this get hacked?

    - by Haskella
    Hi I have a web form that sends a string to one php file which redirects them to a corresponding URL. I've searched about web form hacking and I've only received information about PHP and SQL... my site only uses a single PHP file, very basic etc. Would it be open to any exploits? I'm obviously not going to post the URL, but here is some code I was working on for the php file: http://stackoverflow.com/questions/2888077/newbie-php-coding-problem-header-function-maybe-i-need-someone-to-check-my-cod Thanks

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  • 'button_to' gives me an ugly URL!

    - by Tyler
    Im trying to get an 'add to cart' button to work. When I use <%= button_to "Add to Cart", :acton = "add_to_cart", :id = @product % and then click the button, I get a URL that puts the action after the ID, like this: 'http://localhost:3000/store/show/1?acton=add_to_cart.' The cart page does not load. What I need is a URL that looks like this: 'http://localhost:3000/store/add_to_cart/1'. I can get that result (and the cart to work) if I don't use 'button_to': <% form_for @product, :url = {:action = "add_to_cart", :id = @product} do |f| % <% end % But, what the heck? Why can't I use 'button_to'?

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