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  • Need to find a find a fast/multi-user database program

    - by user65961
    Our company is currently utilizing Excel and have been encountering a series of issues for starters we have multiple users sharing this application. We utilize it write our schedules for our employees and generate staffing levels. May someone give me please or inform me what are the pros and cons of this program and offer suggestions for another database that allows multiple users to share and also give the pros and cons need something that will hold massive data and allow sharing, protecting capabilities.

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  • Cygwin file and directory user and group

    - by dvanaria
    I use Cygwin as my main development environment on both my home and work computers. In order to share files between the two computers, I use Dropbox, which is installed in the following folder on both computers: c:\cygwin\home\dvanaria\dropbox Everything works great, except for one thing. When I'm working on my home computer and do an ls -l on any directory, all the files show up as owned by dvanaria of group Users. But when I work from my work computer, an ls -l shows all files as being owned by Administrators and of group Domain Users. I know Cygwin uses some kind of mapping between Windows users and permissions to the /etc/passwd file. But to be honest I have no idea how this file works or how it maps to Windows under Cygwin. Could anyone help figure this out? The main problem is that I can't edit any files when using my work computer, only read them.

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  • Sub-viewController doesn't get autorotation notifications, bug?

    - by Shizam
    If I have a view (and its controller) and I override the willAnimateRotationToInterfaceOrientation method so I can respond to autorotation events everything works fine and dandy. Now if I create another viewController and add its view to the first viewController's view via: [firstViewController.view addSubview:secondViewController.view] The secondViewController's willAnimateRotationToInterfaceOrientation method isn't called. What gives? Thanks, Sam

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  • Ubuntu server 12.04 on AWS - How does the passwordless sudo work for the ubuntu user?

    - by aychedee
    I'm using Ubuntu server 12.04 on Amazon. I want to add a new user that has the same behaviour as the default ubuntu user. Specifically I want passwordless sudo for this new user. So I've added a new user and went to edit /etc/sudoers (using visudo of course). From reading that file it seemed like the default ubuntu user was getting it's passwordless sudo from being a member of the admin group. So I added my new user to that. Which didn't work. Then I tried adding the NOPASSWD directive to sudoers. Which also didn't work. Anyway, now I'm just curious. How does the ubuntu user get passwordless privileges if they aren't defined in /etc/sudoers. What is the mechanism that allows this?

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  • Introducing the Metro User Interface on Windows 2012

    - by andywe
    Although I am a big fan of using PowerShell to do many of my server operations, that aspect is well covered by those far more knowledgeable than I, and there is vast information around the web already on that. The new Metro interface, and getting around both Windows 8 and Windows Server 2012 though is relatively new, even for those whop ran the previews. What is this? A blank Desktop!   Where did the start button go? Well, it is still there...sort of. It is hidden, and acts like an auto hidden component that appear only when the mouse is hovered over the lower left corner of the screen. Those familiar with Gnome or OSX can relate this to the "Hot Corners" functions. To get to the start button, hover your mouse in the very left corner of the task bar. Let it sit there a moment, and a small blue square with colored tiles in it called start will appear. Click it. I clicked it and now I have all the tiles..What is this?   Welcome to the Metro interface. This is a much more modern look, and although at first seems weird and cumbersome, I have actually found that it is a bit more extensible, allowing greater organization and customization than the older explorer desktop. If you look closely, you'll see each box represents either a program, or program group. First, a few basics about using the start view. First and foremost, a right mouse click will bring up a bar on the bottom, with an icon towards the right. Notice it is titled “All Apps”. An even easier way in many places is to hover your mouse in the exact opposite corner, in the upper right. A sidebar will open and expose what used to be a widget bar (remember Vista?), and there are options for Search, Start, and Settings.   Ok Great, but where is everything? It’s all there…Click the All Apps icon.   Look better? Notice the scroll bar at the bottom. Move it right..your desktop is sized to your content..so you can have a smaller, or larger amount of programs exposed. Each icon can be secondary clicked (right mouse click for most of us, and an options bar at the bottom, rather than the old small context menu, is opened with some very familiar options.   Notice the top of the Windows Explorer window has some new features. You still have your right mouse click functions, but since the shortcuts for these items already exist..just copy them. There are many ways, but here is a long way to show you more of the interface. 1. Right mouse click a program icon, and select the Open File Location option. 2. Trusty file manager opens…but if you look closely up at top edge of the window, you’ll see a nifty enhancement. An orange colored box that is titled Shortcut Tools and another lavender box Title Application tools. Each of these adds options at the top of the file manager window to make selection easy. Of course, you can still secondary click an item in the listing window too. 3. Click shortcut tools, right click your app shortcut and copy it. Then simply paste it into the desktop outside the File Explorer window Also note some of the newer features. The large icons up top below the menu that has many common operations. The options change as you select each menu item. Well, that’s it for this installment. I hope this helps you out.

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  • Select most recent record in sub child

    - by Omar
    I have the following tables/columns: Parent: ParentID Child: ChildID ParentID SubChild: SubChildID ChildID Date Parent has 1 to Many relationship with Child Child has 1 to Many relationship with SubChild For every Parent, I need to get the SubChild with the most recent Date value. How can I do this using SQL. I've tried using MAX(Date), but I can't seem to figure out how to join Parent and Child successfully. The ideal result set would contain all the Parents joined with all the SubChild columns of the latest record. Note: using MS SQL 2005+

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  • ASP.NET Scheduler: How To Implement End-User Restrictions

    Check out this 2 step approach to prevent users from editing appointments in the ASPxScheduler: Step 1: Choose Restriction First decide which action in the ASPxScheduler you want to prevent. Heres a list of the available ones: AllowAppointmentConflicts AllowAppointmentCopy AllowAppointmentCreate AllowAppointmentDelete AllowAppointmentDrag AllowAppointmentDragBetweenResources AllowAppointmentEdit AllowAppointmentMultiSelect AllowAppointmentResize AllowInplaceEditor...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Retrieving data from a JSON sub array in javascript, where identifier starts with an integer

    - by Archie Ec
    I must be missing something simple here, but I'm having trouble retrieving data from a JSON array response. I can access objects with identifiers that start with letters, but not ones that start with numbers. For example, I can access data.item[0].specs.overview.details But I can't access data.item[0].specs.9a99.details If anyone can point me in the right direction, I'd really appreciate it. Thanks.

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  • User authentication in Django. Problems with is_authenticated

    - by tim
    I have one problem with users menu. So, I want, that authenticated user can see his/her profile page and logout (links) in menu. It works (when I logging in) on index page: index, page1, profile, logout ,but, if I go to the, for example, page1 I can see in menu: index, page1, login, not profile and logout. How to fix it? in urls: url(r'^accounts/login/$', 'django.contrib.auth.views.login' ), url(r'^accounts/logout/$', 'django.contrib.auth.views.logout_then_login' ), url(r'^accounts/profile/$', 'my_app.views.profile' ), in views: def profile(request): if not request.user.is_authenticated(): return HttpResponseRedirect("/accounts/login/") else: user = request.user.is_authenticated() return render_to_response('profile.html',locals()) Part of index.html: {% if user.is_authenticated or request.user.is_authenticated %} <li><a href="/accounts/profile/">Profile</a></li> <li><a href="/accounts/logout/">logout</a></li> {% else %} <li><a href="/accounts/login/">login</a></li> {% endif %} login.html: {% extends "index.html" %} {% load url from future %} {% block application %} {% if form.errors %} <p>Try one more time</p> {% endif %} <form method="post" action="{% url 'django.contrib.auth.views.login' %}"> {% csrf_token %} <table> <tr> <td>{{ form.username.label_tag }}</td> <td>{{ form.username }}</td> </tr> <tr> <td>{{ form.password.label_tag }}</td> <td>{{ form.password }}</td> </tr> </table> <input type="submit" value="Login" /> <input type="hidden" name="next" value="{{ next }}" /> </form> {% endblock %} profile.html: {% extends "index.html" %} {% block application %} {% if request.user.is_authenticated %} <p>Welcome, {{ request.user.username }}. Thanks for logging in.</p> {% else %} <p>Welcome, new user. Please log in.</p> {% endif %} {% endblock %}

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  • Block complete network access for one local user

    - by tumchaaditya
    Well, this is quite trivial question but I could not find a satisfactory answer even after trying many search queries both here and on Google. I want to share my PC with my room-mate. And I don't want him to access ANY network(LAN included). So, I can create an account for him and block network access for the same. I would prefer avoiding any third-party tools as far as possible. It's a simple home PC hooked up to a router for internet. No domain and other stuff. (Technically, guest account can achieve this. But somehow, the guest account on my PC has network access!)

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  • Windows user trying install Git on Solaris

    - by nahab
    Is there simply way to install Git on Solaris as on Windows without installing any side libraries and compiling source files? And if not, why? UPD. Yes I'm looking for single package that will be easy to install. We have ~8 solaris zones using for development those we need simple way to install git fast on they. Installation should be easy because each member of team possibly will be do it and it should be fast because of big count of zones.

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  • LINQ-to-SQL - Join, Count

    - by ile
    I have following query: var result = ( from role in db.Roles join user in db.Users on role.RoleID equals user.RoleID where user.CreatedByUserID == userID orderby user.FirstName ascending select new UserViewModel { UserID = user.UserID, PhotoID = user.PhotoID.ToString(), FirstName = user.FirstName, LastName = user.LastName, FullName = user.FirstName + " " + user.LastName, Email = user.Email, PhoneNumber = user.Phone, AccessLevel = role.Name }); Now, I need to modify this query... Other table I have is table Deals. I would like to count how many deals user created last month and last year. I tried something like this: var result = ( from role in db.Roles join user in db.Users on role.RoleID equals user.RoleID //join dealsYear in db.Deals on date.Year equals dealsYear.DateCreated.Year join dealsYear in ( from deal in db.Deals group deal by deal.DateCreated into d select new { DateCreated = d.Key, dealsCount = d.Count() } ) on date.Year equals dealsYear.DateCreated.Year into dYear join dealsMonth in ( from deal in db.Deals group deal by deal.DateCreated into d select new { DateCreated = d.Key, dealsCount = d.Count() } ) on date.Month equals dealsMonth.DateCreated.Month into dMonth where user.CreatedByUserID == userID orderby user.FirstName ascending select new UserViewModel { UserID = user.UserID, PhotoID = user.PhotoID.ToString(), FirstName = user.FirstName, LastName = user.LastName, FullName = user.FirstName + " " + user.LastName, Email = user.Email, PhoneNumber = user.Phone, AccessLevel = role.Name, DealsThisYear = dYear, DealsThisMonth = dMonth }); but here is even syntax not correct. Any idea? Btw, is there any good book of LINQ to SQL with examples?

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  • How to reorder table rows (drag-and-drop) along with their sub rows

    - by Eirik Johansen
    I have a table which looks like this (simplified for the example): <table> <tr class="lvl_1"> <td> Level 1 </td> </tr> <tr class="lvl_2"> <td> Level 2 </td> </tr> <tr class="lvl_3"> <td> Level 3 </td> </tr> <tr class="lvl_1"> <td> Level 1 </td> </tr> <tr class="lvl_2"> <td> Level 2 </td> </tr> <tr class="lvl_3"> <td> Level 3 </td> </tr> The content in the rows with the lvl_3 class are children of the previous lvl_2 row, and the lvl_2 rows are children of the previous lvl_1. Had the data been a list, it would have looked something like this: Level 1 -- Level 2 ---- Level 3 Level 1 -- Level 2 ---- Level 3 I'm not looking to implement drag-and-drop sorting functionality, make it possible to rearrange the level 1 and two rows. The tricky part is that once I start moving a row, the corresponding children (and grand-children, if any) should move along with it. Is this even possible with the current markup, or do I have to rearrange the code? Thanks in advance !

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  • OQL - Find certain (sub)-members of a given object

    - by Pentius
    I'm analyzing heap dumps in a Portal App. With the help of OQL I found the MemorySessionData Object with its address. Now I want to find all SerializableViewState Objects, that are hold by Objects hold by this MemorySessionData object. In other words: My MemorySessionData Object holds several objects, these hold objects again and so on... I want to find all SerializableViewState Objects in this tree. How would the OQL look like? :-/

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  • Cannot see user desktop when I log in

    - by Jesi
    I am very new to Ubuntu. I recently got a new laptop running Windows 7. I am using Virtual Box and just installed the Ubuntu 12.10 ISO as a new Virtual Machine within Virtual Box. Everything seemed to install just fine and I even added the Guest Additions under Devices. The problem is that I cannot see the menus and my login information. The virtual machine says it is running; however, I do not have the Applications, Places, System, etc. tray to select from. Is there something I am supposed to do after logging in to get this? I entered my password and everything seemed fine, I just don't have those drop-down menus available... Thank You! Jesi

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  • Mysql on duplicate key update + sub query

    - by jwzk
    Using the answer from this question: http://stackoverflow.com/questions/662877/need-mysql-insert-select-query-for-tables-with-millions-of-records new_table * date * record_id (pk) * data_field INSERT INTO new_table (date,record_id,data_field) SELECT date, record_id, data_field FROM old_table ON DUPLICATE KEY UPDATE date=old_table.data, data_field=old_table.data_field; I need this to work with a group by and join.. so to edit: INSERT INTO new_table (date,record_id,data_field,value) SELECT date, record_id, data_field, SUM(other_table.value) as value FROM old_table JOIN other_table USING(record_id) ON DUPLICATE KEY UPDATE date=old_table.data, data_field=old_table.data_field, value = value; I can't seem to get the value updated. If I specify old_table.value I get a not defined in field list error.

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  • Unity no longer loads in 13.04 for main user

    - by user152973
    When Ubuntu starts up, Unity fails to load (I can only see my desktop with no unity sidebar and no system bar in the top right). I tried the advice of Unity does not start in Ubuntu 13.04 which recommended the following commands: dconf reset -f /org/compiz/ unity --reset-icons &disown I ran the commands without errors an restarted the computer, but the problem persists. I am currently running Gnome. I have looked at other pages from the Google search "ubuntu unity failed to load 13.04", but the advice was similar to above and seems to be concerned with a system upgrade in April 18, 2013. I suspect my issue is something far more recent. Please give me advice on how to restore Unity on my account or at least figure out what the problem is. Thank you. Some information that might be relevant: -Unity has worked fine on 13.04 for the 6 months that I've had it until today. (November 10, 2013) -I have set up the update tool to automatically update when available. It is very possible that the system applied some updates without my knowledge. -Interestingly, Unity works fine on the Guest account. -I have made it so the system automatically logs me in at start-up. -This is a personal laptop. No one else has access to it. -I was not doing anything with the system settings or the terminal and have not installed any new software for the past 3 days. -I am running the System76 native Linux laptop Ultra Lemur. I did not contact their support yet because it seemed unlikely that this is a System76-specific error.

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  • I need to simplify a MySQL sub query for performance - please help

    - by Richard
    I have the following query which is takin 3 seconds on a table of 1500 rows, does someone know how to simplify it? SELECT dealers.name, dealers.companyName, dealer_accounts.balance FROM dealers INNER JOIN dealer_accounts ON dealers.id = dealer_accounts.dealer_id WHERE dealer_accounts.id = ( SELECT id FROM dealer_accounts WHERE dealer_accounts.dealer_id = dealers.id AND dealer_accounts.date < '2010-03-30' ORDER BY dealer_accounts.date DESC, dealer_accounts.id DESC LIMIT 1 ) ORDER BY dealers.name I need the latest dealer_accounts record for each dealer by a certain date with the join on the dealer_id field on the dealer_accounts table. This really should be simple, I don't know why I am struggling to find something.

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  • jquery : ul, li parent multiple child sub-child toggling

    - by user360826
    hello, my main question is as follows: how to show only the first subchild of a ul or li upon clicking the enclosing parent. eg: <ul> Grandparent <li> Child1 <li> Grandchild11</li></li> <li> Child2 <li>GrandChild21</li><li>grandchild22</li></li> </ul> so, for example I would like something to the effect of <script> $('ul').click(function(){ $('ul').children('first li').toggle() }); $('li').click(function(){ $('li').children('first li').toggle() }); </script> meaning: when i click ul, i only see the first child node (child1 and child2 will be shown, but not the grandchildren). when i click child1 or child2 i see the respective grandchild. grandchild is not shown upon clicking grandparent, only upon clicking child1 or child2. i know i am reinventing the wheel of some pre-coded solution, but any help would be largely appreciated!

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  • Tips on how to notify a user of new features in your game (Android)

    - by brent777
    I have noticed a problem when releasing new features for a game that I wrote for Android and published on Google Play Store. Because my game is "stage-based" - and not a game like Hay Day, for example, where users will just go into the game every day since it can't really be finished - my users are not aware of new features that I release for the game. For example, if I publish a new version of my game and it contains a couple new stages, most of their devices will just auto-update the game and they don't even notice this and think to check out what's new. So this is why an approach like popping open a dialog that showcases the new feature(s) when they open the game for the first time after the update was done is not really sufficient. I am looking for some tips on an approach that will draw my users back into the game and then they could read more detail about new features on such a dialog. I was thinking of something like a notification that tells them to check out the new features after an update is done but I am not sure if this is a good idea. Any suggestions to help me solve this problem would be awesome.

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  • Match Anything Except a Sub-pattern

    - by Tim Lytle
    I'd like to accomplish what this (invalid I believe) regular expression tries to do: <p><a>([^(<\/a>)]+?)<\/a></p>uniquestring Essentially match anything except a closing anchor tag. Simple non-greedy doesn't help here because `uniquestring' may very well be after another distant closing anchor tag: <p><a>text I don't <tag>want</tag> to match</a></p>random data<p><a>text I do <tag>want to</tag> match</a></p>uniquestring more matches <p><a>of <tag>text I do</tag> want to match</a></p>uniquestring So I have more tag in between the anchor tags. And I'm using the presence of uniquestring to determine if I want to match the data. So a simple non-greedy ends up matching everything from the start of the data I don't want to the end of the data I do want. I know I'm edging close to the problems regular expressions (or at least my knowledge of them) aren't good at solving. I could just through the data at an HTML/XML parser, but it is just one simple(ish) search. Is there some easy way to do this that I'm just missing?

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