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  • Adding to database. No repeat on refresh

    - by kevstarlive
    I have this code: Episode.php <?$feedback = new feedback; $articles = $feedback->fetch_all(); if (isset($_POST['name'], $_POST['post'])) { $cast = $_GET['id']; $name = $_POST['name']; $email = $_POST['email']; $post = nl2br ($_POST['post']); $ipaddress = $_SERVER['REMOTE_ADDR']; if (empty($name) or empty($post)) { $error = 'All Fields Are Required!'; }else{ $query = $pdo->prepare('INSERT INTO comments (cast, name, email, post, ipaddress) VALUES(?, ?, ?, ?, ?)'); $query->bindValue(1, $cast); $query->bindValue(2, $name); $query->bindValue(3, $email); $query->bindValue(4, $post); $query->bindValue(5, $ipaddress); $query->execute(); } }?> <div align="center"> <strong>Give us your feedback?</strong><br /><br /> <?php if (isset($error)) { ?> <small style="color:#aa0000;"><?php echo $error; ?></small><br /><br /> <?php } ?> <form action="episode.php?id=<?php echo $data['cast_id']; ?>" method="post" autocomplete="off" enctype="multipart/form-data"> <input type="text" name="name" placeholder="Name" /> / <input type="text" name="email" placeholder="Email" /><small style="color:#aa0000;">*</small><br /><br /> <textarea rows="10" cols="50" name="post" placeholder="Comment"></textarea><br /><br /> <input type="submit" onclick="myFunction()" value="Add Comment" /> <br /><br /> <small style="color:#aa0000;">* <b>Email will not be displayed publicly</b></small><br /> </form> </div> Include.php class feedback { public function fetch_all(){ global $pdo; $query = $pdo->prepare("SELECT * FROM comments"); $query->bindValue(1, $cast); $query->execute(); return $query->fetchAll(); } } This code updates to the database as it is suppose to. But after submission it reloads the current page as mentioned in the form action. But when I refresh the page to see the comment being added it asks to re submit. If I hit submit then the comment adds again. How can I stop this from happening? Maybe I could hide the comment box and display a thank you message but that would not stop a repeat entry. Please help. Thank you. Kev

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  • set an input value from jquery function

    - by user1499220
    I'm simply trying to set a value for an input but it doesn't work. Here is my jquery function : function display_form() { try { $('#start_date').val('2012/08/21'); }catch (e){ alert('error'); } window.alert( $('[name=start_date]').val() ); } This shows "undefined". Here is my form : <input id="start_date" name="start_date" type="text" size="6" /> Should I put somewhere the id of the form that I want to use? I just followed what is said in the documentation of jquery but it doesn't seem to work. Could anyone help me ?

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  • Pass PHP variables without being seen when working with a database generated list

    - by Wilcoholic
    Looking for any help regarding the problem. Here's the deal: I have a database that has a teams table and it contains team_id. On one of my pages, I generate a list of links that contain the team_id of the creator in their get URL. I need the team_id on the next page but can't figure out how to pass it through any other way. Using a form and POST isn't an option because this method would only pass through the last links data on the list. Storing in a session isn't an option either because there is no way to discretely pass the the variables I need to a function to set the session variables. I have tried and it can pretty easily be viewed from viewing the source code. So here's some sample code to see exactly what I'm dealing with. <? if(mysql_num_rows($result2)>0){ ?> <a class="fltrt btn btn-danger btn-small" onclick="test()" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=cancel">Cancel Match</a> <?}else{?> <a class="fltrt btn btn-success btn-small" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=accept">Accept Match</a> <?} ?> The code above is generated multiple times on a page via a while loop that was excluded. I want to pass the match_id and team_id variables without being seen anywhere. If I made this a form, it wouldn't pass the correct variables unless there is only one result at the time (not likely). I'm sure there has to be an easy method that is eluding me, so please share thoughts on how to solve this. I feel as though I am not explaining it well enough, but it's not really easy to explain. I basically want something that works like GET but acts like POST and can be hidden from people viewing source code or link locations. Thanks

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  • How to take value from radio selection and pass that value into a hidden inputs value attribute?

    - by Matthew
    Hello guys, I need to know if this can be done and if so can someone push me in the right direction. Okay I have a series of radio buttons: <input type="radio" name="level_id" id="radio1" value="XXXX" class="radio1" /> <label for="radio1">choice 1</label> <input type="radio" name="level_id" id="radio2" value="XXXX" class="radio2" /> <label for="radio2">choice 2</label> <input type="radio" name="level_id" id="radio3" value="XXXX" class="radio3" /> <label for="radio3">choice 3</label> <label for="radio4">second choice1</label> <input type="radio" name="level_id" id="radio4" value="1" class="radio4" /> <label for="radio5">second choice2</label> <input type="radio" name="level_id" id="radio5" value="2" class="radio5" /> <label for="radio6">second choice3</label> <input type="radio" name="level_id" id="radio6" value="3" class="radio6" /> Now what I am looking to do is if someone selects CHOICE 1 and then selects SECOND CHOICE1 I would like to pass the value of SECOND CHOICE1 into the value of a hidden input. <input type="hidden" name="sub_source" id="sub_source" value="" /> So that when the form is ready to submit the value that gets passed would be: <input type="hidden" name="sub_source" id="sub_source" value="1" />

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  • Change Image in Resources at Runtime

    - by zaidwaqi
    Hi, My understanding of Resources is that I can combine resources i.e. images and my program into single executable. Let's say I have image pic1.png and I put it into Resource of my project, and is accessible with Properties.Resource.pic1. For example, PictureBox pb = new PictureBox(); pb.Image = Properties.Resource.pic1; What I want to do is for that my program will be able to replace this image at runtime. For example, my program runs, and locate newPicture.png, and use this new image to replace pic1.png that was originally used. Maybe my question is better reworded as "Can I include new image into Resources at runtime?" Please help. Thanks.

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  • Form validation in JAvascript with Regexp

    - by Nikita Barsukov
    I have a webpage with an input field where only digits are allowed. The input field has an onkeyup event that starts this validating function: function validate() { var uah_amount = document.getElementById("UAH").value; var allowed = /^\d+$/; document.getElementById("error").innerHTML = document.getElementById("UAH").value; if (!allowed.test(uah_amount)) { document.getElementById("error").style.backgroundColor = "red"; } } Everything works as I expect until I hit Backspace button to remove some characters. In this case function always behaves as if I entered letters. How to correct this?

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  • how to filter text of the selected value in drop down

    - by Carlos
    I have a drop down menu. Has product types. Product types have associated value (from drop down) values correspond to machine groups. So each option should have three variables--Machine name, values, machine group. I can get the Machine name and I can get the machine value (and display them in a different field)...what I have not been able to figure out is how to change the value into the Machine group. jQuery('#MachineName').bind('change', function() { //get selected value from drop down; var selectedValue = jQuery("#MachineName").val(); //populate a text field with the selected drop down value jQuery("#MachineValue").val(selectedValue); What I would like to do is keep that MachineValue but then populate another text field with the sorted MachineGroup I have been trying to run it through something like switch(jQuery(this).val()){ case "236" : newVal = "8"; break; But I don't want to "change" the value I just want to do an "if then" type filter, so maybe something like: '236' => "8", '237' => "5", I just don't know how to properly say "assign the MachineGroup based on the MachineValue" (and then have it populate a different text field) In the end I would have three fields. The drop down, the MachineValue and the MachineGroup. Drop down and value are done, I just need to do Group. (And I can sort Group based on MachineName...just not sure which would be easier)

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  • Rails: validate presence of parent_id in has_many association

    - by deb
    I have a projects resource that has many tasks. I want to ensure that every task has a project_id by adding validates_presence_of :project_id to the tasks model. However, when creating a new project with tasks, the project_id won't be available until the record saves, therefore I can't use validates_presence_of :project_id. So my question is, how do I validate presence of project_id in the task model? I want to ensure every task has a parent. ... class Project < ActiveRecord::Base has_many :tasks, :dependent => :destroy accepts_nested_attributes_for :tasks, :allow_destroy => true ... class Task < ActiveRecord::Base belongs_to :project validates_presence_of :project_id

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  • Edit form not being instanciated

    - by 47
    I have two models like this: class OptionsAndFeatures(models.Model): options = models.TextField(blank=True, null=True) entertainment = models.TextField(blank=True, null=True) seats_trim = models.TextField(blank=True, null=True) convenience = models.TextField(blank=True, null=True) body_exterior = models.TextField(blank=True, null=True) lighting = models.TextField(blank=True, null=True) safety = models.TextField(blank=True, null=True) powertrain = models.TextField(blank=True, null=True) suspension_handling = models.TextField(blank=True, null=True) specs_dimensions = models.TextField(blank=True, null=True) offroad_capability = models.TextField(blank=True, null=True) class Vehicle(models.Model): ... options_and_features = models.ForeignKey(OptionsAndFeatures, blank=True, null=True) I have a model form for the OptionsAndFeaturesclass that I'm using in both the add and edit views. In the add view it works just fine. But the edit view renders the OptionsAndFeatures as blank. The code for the edit view is as follows: def edit_vehicle(request, stock_number=None): vehicle = get_object_or_404(Vehicle, stock_number=stock_number) if request.method == 'POST': # save info else: vehicle_form = VehicleForm(instance=vehicle) photos = PhotosFormSet(instance=vehicle) options = OptionsForm(instance=vehicle) #render_to_reponse What could be the problem here?

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  • form validation with jquery and livevalidation

    - by ImpY
    I'm trying to do some form validation with livevaldation & jquery. I've a formular with an input field like that: <div id="prenameDiv" class="control-group"> `<input id="prename" name="prename" class="input-large" placeholder="Max" >` </div> So if there's an error on validation 'livevalidaton' adds the class 'LV_invalid_field' to the input - it looks like that: <div id="prenameDiv" class="control-group"> <input id="prename" name="prename" class="input-large LV_invalid_field" placeholder="Max" > </div> That's ok, but now I'll add another class 'error' to the div 'prenameDiv' when the DOM changes that it looks like that: <div id="prenameDiv" class="control-group error"> `<input id="prename" name="prename" class="input-large LV_invalid_field" placeholder="Max" ` </div> I tried it that way: if ($("#prenameDiv").bind("DOMSubtreeModified")){ `if ($("#prename").hasClass("LV_invalid_field")) {` $("#prenameDiv").addClass("error"); } } But nothing changes? Do you have some ideas?

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  • undefined method `model_name' for NilClass:Class - Rails application

    - by user1270259
    So I have seen other articles here on stack about this and a lot of the time people are not doing @post = post.new. I read some where to use the plural...?? any ways I am getting this error on my discussion code: Discussion Controller class DiscussionsController < ApplicationController def index @discussion = Discussion.new @discussions = Discussion.all end def create @discussion = Discussion.create(params[:discussion]) if @discussion.save redirect_to tasks_path, :flash => {:success => 'Created a new discussion'} else redirect_to tasks_path, :flash => {:error => 'Failed to create a discussion'} end end end Discussion Form <%= form_for @discussion do |f| %> <p><%= f.label :title %> <%= f.text_field :title %></p> <p><%= f.label :content %> <%= f.text_area :content %></p> <% end %> Discussion Routes resources :discussions do resources :comments end Now as far as I know I am doing this right, because I have a task form set up essentially the same way - but I have looked at my code for hours and have googled and tried other examples and now i see this: undefined method `model_name' for NilClass:Class Extracted source (around line #1): 1: <%= form_for @discussion do |f| %> 2: 3: <p><%= f.label :title %> 4: <%= f.text_field :title %></p> Which should mean that I am missing something from my controller.....is it as asilly as a spelling mistake? .

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  • Two part form in Rails

    - by samuel02
    I have some two nested resources, so that a Product can have many Bookings. On one page in a different controller I want to create a new booking and since it's a "general" booking I want a select menu to appear in a modal window where the user is able to pick one of the existing products and then go to the booking page. How can I do this? I have no problem setting up the modal and the "New booking" page is already there. What I need is a form that generates a list of existing products, picks the selected product id and then gets /products/:product_id/bookings/new . Any help appreciated! I realize my title does not describe my problem very good so better suggestions are highly welcome!

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  • Directions and Opinions on Creating Update System for the Application.

    - by AlwaysBeCoding
    Hi people. I just try to figure out a good solution on designing the update process for a windows form application i created. I think of a button inside the app for manual checking of an update and checking when starting the app. Only I'm not familiar with technics. I though to have the update setup file in a FTP Server and checking the server for an update with a txt file in there with filename and version info. When app is finished downloading the update, closing and starting the update setup file. Any suggestions, opinions on the subject?

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  • Best approach to store username & password

    - by Zerotoinfinite
    Hi All, I have created a site in asp.net 3.5 & my query is this that I have only 2 or 3 login Id (user) who can login to my website, then what would be the better way to save the login details. What I know I am writing below, please let me know which would be the correct approach to achieve this also if their is any nice approach to get this done: 1: to save username and password in web.config file 2: to create a text file in directory and modify it 3: To use form authentication Please let me know the approach I can use to solve it. thanks in advance P.S. : I have to create only 2-3 users, or in future may be 1-2 more, that's it.

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  • Best way to manage the persistence of a form state, to and from a database

    - by Laurent.B
    In a JSP/Servlet webapp, I have to implement a functionality that allows a user to save or restore a form state, that latter containing for instance some search criteria. In other words, the user must be able to save or restore field values of a form, at any time. On the same page that contains that form, there's also another little form that allows him to name his form state before saving it. Then, later he'll be able to recall that state, via a combobox, and refill dynamically the form with the state he selected. I know how to implement that by hand but I would prefer not to reinvent the wheel then I'd like to know if there are some frameworks managing that kind of functionality ? A mix between JSP taglib, filter class, jQuery or other JavaScript frameworks... My research has not give anything yet. Thank you in advance.

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  • Results page in other window.

    - by xRobot
    I have this simple form: <form method="post" action"."> <input type="text" name="title"> <input type="submit" name"send"> </form> I want that when a user click on submit, then will be open another window of browser with the results. Is it possible ?

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  • django - where to clean extra whitespace from form field inputs?

    - by Westerley
    I've just discovered that Django doesn't automatically strip out extra whitespace from form field inputs, and I think I understand the rationale ('frameworks shouldn't be altering user input'). I think I know how to remove the excess whitespace using python's re: #data = re.sub('\A\s+|\s+\Z', '', data) data = data.strip() data = re.sub('\s+', ' ', data) The question is where should I do this? Presumably this should happen in one of the form's clean stages, but which one? Ideally, I would like to clean all my fields of extra whitespace. If it should be done in the clean_field() method, that would mean I would have to have a lot of clean_field() methods that basically do the same thing, which seems like a lot of repetition. If not the form's cleaning stages, then perhaps in the model that the form is based on? Thanks for your help! W.

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  • URL decoding Japanese characters etc. in Java

    - by DanieL
    I have a servlet that receives some POST data. Because this data is x-www-form-urlencoded, a string such as ???? would be encoded to &#12469;&#12508;&#12486;&#12531;. How would I unencode this string back to the correct characters? I have tried using URLDecoder.decode("encoded string", "UTF-8"); but it doesn't make a difference. The reason I would like to unencode them, is because, before I display this data on a webpage, I escape & to &amp; and at the moment, it is escaping the &s in the encoded string so the characters are not showing up properly.

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  • c# getting value from other form

    - by djuzla123
    Situation i have: textbox(to input your name) on form1. From that form1 on button click i go to form2. From form2 button click to form3. On form3 on button click i need to writte me in empty textbox value from textbox on form1 that user wrote down. example: on form1 in textbox1 i write my name "Djuzla". When i go to form3 and click button to see what name i wrote in form1 it should show in empty textbox3 form3 "Djuzla". I'm stuck with this few hours now, and it stupid problem but i have no idea what to do next.. tried all from zillion theards on net :p

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  • Cloning whole form elements after clicking button

    - by FreshPro
    I have this following form <form action="" class="form-horizontal"> <div id="wrapper"> <div class="row-fluid"> <div class="span6"> <div class="control-group"> <label class="control-label"><?=$core->l("default_comm_type");?></label> <div class="controls"> <select id="fld_default_comm_type" name="fld_default_comm_type[]" defaultValue="-1" class="m-wrap span10" field="fld_default_comm_type" appEditor="true"> <?=combo_creator::render_default_comm_types()?> </select> </div> </div> </div> <div class="span4 checkerAlign"> <div class="control-group"> <div class="controls"> <?=$core->l("is_active");?> </div> </div> </div> <div class="span2 checkerAlign"><input type="checkbox" name="fld_active[]" id="fld_active" editType="booleanEdit" appEditor="true"/></div> </div> <div><a href="#" id="addMore">Add Row</a></div> </div> The question is when user clicks Add Row button, I need to create a copy of this form elements inside <div id="wrapper"> How can i do that? EDIT: SOLVED <form action="" class="form-horizontal" id="wrapper"> <div class="row-fluid"> <div class="span6"> <div class="control-group"> <label class="control-label"><?=$core->l("default_comm_type");?></label> <div class="controls"> <select id="fld_default_comm_type" name="fld_default_comm_type[]" defaultValue="-1" class="m-wrap span10" field="fld_default_comm_type" appEditor="true"> <?=combo_creator::render_default_comm_types()?> </select> </div> </div> </div> <div class="span4 checkerAlign"> <div class="control-group"> <div class="controls"> <?=$core->l("is_active");?> </div> </div> </div> <div class="span2 checkerAlign"><input type="checkbox" name="fld_active[]" id="fld_active" editType="booleanEdit" appEditor="true"/></div> </div> <a href="#" data-action="add">add</a> <a href="#" data-action="delete">delete</a> </form> In the Js part: jQuery("#addMore").click(function(){ var contents = jQuery("form").html(); jQuery("#test").append(contents); }); When add is clicked it inserts form elements just as I wanted and when delete is clicked it deletes elements. Thank you for the tips guys Problem solved! Thanks guys.

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  • maintain formatting entered into an html form?

    - by NickG77
    Im setting up a web form, and I'm trying to have it where visitors can paste their resumes into a text area. Then I want to email the info using php mail(). But the resume info is just stored in the variable as one long string with no formatting. Is there a way I can send the pasted resume text to the client in the resume format? Maintaining all the line breaks and stuff? He wants to avoid having people upload resumes.

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  • Centering form elements with left alignment

    - by user1766797
    I would like to center the elements in my form without moving the text or buttons from being aligned on the left. So it would look like this: The bottom square is supposed to be a button. I want it centered, but the <center> tag moves the text and button so they're centered to the input box. Here is my code: <form action="login.php" method="post"> <div class="aside"> <div id="center"> Username:<br> <input type="text" name="username"><br> Password:<br> <input type="password" name="passwor"><br> <input type="submit" class="button" name="submit" value="Login"><br><br> </div> </div> </form> and the css: #center{ width: 250px; margin-left: auto; margin-right: auto; float: center; } div.aside { margin-left: 15px; margin-top: 10px; width: 250px; background: #f5f5f5; border: 1px solid #e9e9e9; line-height: 150%; } div.aside .button{ padding:3px; width: 50px; margin-top: 3px; background-color: #00A1E6; border: 1px solid #0184BC; text-decoration:none; color: #ffffff; text-align: center; -webkit-appearance: none; }

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