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  • Drupal: How to Render Results of Form on Same Page as Form

    - by Aaron
    How would I print the results of a form submission on the same page as the form itself? Relevant hook_menu: $items['admin/content/ncbi_subsites/paths'] = array( 'title' => 'Paths', 'description' => 'Paths for a particular subsite', 'page callback' => 'ncbi_subsites_show_path_page', 'access arguments' => array( 'administer site configuration' ), 'type' => MENU_LOCAL_TASK, ); page callback: function ncbi_subsites_show_path_page() { $f = drupal_get_form('_ncbi_subsites_show_paths_form'); return $f; } Form building function: function _ncbi_subsites_show_paths_form() { // bunch of code here $form['subsite'] = array( '#title' => t('Subsites'), '#type' => 'select', '#description' => 'Choose a subsite to get its paths', '#default_value' => 'Choose a subsite', '#options'=> $tmp, ); $form['showthem'] = array( '#type' => 'submit', '#value' => 'Show paths', '#submit' => array( 'ncbi_subsites_show_paths_submit'), ); return $form; } Submit function (skipped validate function for brevity) function ncbi_subsites_show_paths_submit( &$form, &$form_state ) { //dpm ( $form_state ); $subsite_name = $form_state['values']['subsite']; $subsite = new Subsite( $subsite_name ); //y own class that I use internally in this module $paths = $subsite->normalized_paths; // build list $list = theme_item_list( $paths ); } If I print that $list variable, it is exactly what I want, but I am not sure how to get it into the page with the original form page built from 'ncbi_subsites_show_path_page'. Any help is much appreciated!

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  • Adding new records in Access without wrecking the form

    - by Matt Parker
    I'm working on a simple Access 2003 application to keep track of things that need to be done for clients for some colleagues. Each colleague has a set of clients, and each client has a set of actions that need to be taken by a certain date. I've set up a form that consists of a combobox for client ID (indexed), a drop-down for the person who is handling that client's case, and a button for adding new clients (a standard Access-created Add Record button). The actions are listed in a subform below these three elements. The problem I've run into is that the first person I tested this on clicked the button to add a new record, then didn't fill it out and tried to select another client from the drop-down list. Access interprets this as an attempt to set the selected Client ID as the ID for the new record and rightfully throws an error for duplicate primary keys. I can think of a couple of ways around this problem, but I'd much rather hear your elegant solutions than kludge together some junk in a language I don't know. Let me know if you have any questions. Thank you.

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  • Displaying form validation errors in a template (Symfony)

    - by Jay
    Hi, let's say I have a blog with a module "post". now I display a post like this: post/index?id=1 in the index-action i generate a new CommentForm and pass it as $this-form to the template and it is being displayed at the bottom of a post (it's just a textfield, nothing special). form action is set to "post/addcomment". How can I display the validation errors in this form? using setTemplate('index') doesn't work because I would have to pass the id=1 to it... thanks

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  • Iteratively creating multiple file input fields in Rails

    - by David
    I have a column of product views in a database (e.g. top, bottom, front, back). I'm trying to generate a series of file inputs to allow the user to upload an image for each view. This is the result I'm after: ... <label>Top</label> <input type="file" name="image[Top]"><br> <label>Bottom</label> <input type="file" name="image[Bottom]"><br> <label>Front</label> <input type="file" name="image[Front']"><br> ... This is what I'm trying: <%= views = View.order('name ASC').all.map { |view| [view.name, view.id] } %> <%= views.each { |view| label(view); file_field('image', view) } %> However, all this does is print out the views array a couple of times. Hopefully you Rails experts can point me in the right direction. (I apologize in advance if I'm butchering Ruby.)

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  • can't save form content to database, help plsss!!

    - by dana
    i'm trying to save 100 caracters form user in a 'microblog' minimal application. my code seems to not have any mystakes, but doesn't work. the mistake is in views.py, i can't save the foreign key to user table models.py looks like this: class NewManager(models.Manager): def create_post(self, post, username): new = self.model(post=post, created_by=username) new.save() return new class New(models.Model): post = models.CharField(max_length=120) date = models.DateTimeField(auto_now_add=True) created_by = models.ForeignKey(User, blank=True) objects = NewManager() class NewForm(ModelForm): class Meta: model = New fields = ['post'] # widgets = {'post': Textarea(attrs={'cols': 80, 'rows': 20}) def save_new(request): if request.method == 'POST': created_by = User.objects.get(created_by = user) date = request.POST.get('date', '') post = request.POST.get('post', '') new_obj = New(post=post, date=date, created_by=created_by) new_obj.save() return HttpResponseRedirect('/') else: form = NewForm() return render_to_response('news/new_form.html', {'form': form},context_instance=RequestContext(request)) i didn't mention imports here - they're done right, anyway. my mistake is in views.py, when i try to save it says: local variable 'created_by' referenced before assignment it i put created_py as a parameter, the save needs more parameters... it is really weird help please!!

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  • breaking datetime into constituent parts ASP.NET MVC form

    - by nick
    hi guys, i have searched the web relentlessly for this and have not found anything - which is surprising because i would think it is such a common scenario! Basically, on my model i have a DateTime field which i wish the user to populate through a form. I am using the Html helper to render all other parts of the form (along with validation) So this question is in two parts... Html Helper Firstly, is there any way to use the Html helper to split the DateTime field to be rendered as the three constituent parts of a date: day, month, year (since i do not care about the time part). This could be rendered as text boxes, drop down lists or a combination of both. Model Binding And then when the form is posted, what is the best approach for binding back up to the model? I have seen Scott Hanselmann's solution to this, but it seems a little bloated for what i need - i was hoping for a slightly more elegant solution. Is it recommended to extend DefaultModelBinder and set that as default binder (since all dates would be handled in this way) or write a class that implements IModelBionder and set it as the default binder for the DateTime type? Thanks for all the help in advance :-) i'm loving MVC but it's infuriating me that something so trivial is causing so much headaches!

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  • Get Data from Windows Form into C# program

    - by Jimmy
    I want my C# program to collect data. Then, when the OK button is clicked, I want this data to be loaded into my program -- such as into variables in Main(), or into data members of a class I have constructed, and I want the form to then go away -- not be hidden, but actually closed. Alas, read as I might in the book I have, the data collected by the form stays in the form, execution proceeds within the form, and the same form is used to display the result of the program's computations. Sheesh. All I want is to capture the form's information, close the form and proceed with my program. I would appreciate some tips on geting data from a form into Main() or into a class's data members. Thanks, Lucky

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  • Why is this jquery dialog window not displaying?

    - by user338413
    I've got a form that is using jquery validation. When the user clicks the submit button, I've got some jquery that intercepts the submit and should display a dialog window asking the user to verify the information they entered on the form. This dialog window should only display if the form has validated. Here is my code: $('#form').submit(function(){ fillVerificationDialog(); /* This loads up the dialog with form data */ if (('#form').valid()){ $('verification_dialog').dialog('open'); return false; } }); My dialog window is not displaying. It just submits the form. And I've verified that the form is valid by using an alert that checks the value of $('#form').valid() If I remove the if statement and just have the line that opens the dialog, the dialog displays. However, it will display even if the form has errors which is what I'm trying to prevent.

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  • ZF2 Vertical Form

    - by yunhasnawa
    I created a simple form in typical ZF2 application. The form class code is just a modified code provided by Zend's Album example. <?php namespace Admin\Form; use Zend\Form\Form; class CityForm extends Form { public function __construct($name = null) { parent::__construct('city'); $this->setAttribute('method', 'post'); $this->add(array( 'name' => 'id', 'attributes' => array( 'type' => 'hidden', ), )); $this->add(array( 'name' => 'name', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Name', ), )); $this->add(array( 'name' => 'province', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Province', ), )); $this->add(array( 'name' => 'country', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Country', ), )); $this->add(array( 'name' => 'coordinate', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Coordinate', ), )); $this->add(array( 'name' => 'submit', 'attributes' => array( 'type' => 'submit', 'value' => 'Save', 'id' => 'submitButton', ), )); } } And call it like this in CityController, a typical controller extends AbstractActionController: public function addAction() { $form = new CityForm(); $viewData = array( 'form' => $form ); return new ViewModel($viewData); } Finally in view I echo it like this: <?php $title = 'Add New City'; ?> <?php $this->headtitle($title); ?> <h1><?php echo $this->escapehtml($title); ?></h1> <?php $form = $this->form; ?> <?php $form->setAttribute('action', $this->url('city', array('action' => 'add'))); ?> <?php $form->prepare(); ?> <?php echo $this->form()->openTag($form); echo $this->formHidden($form->get('id')); echo $this->formRow($form->get('name')); echo $this->formRow($form->get('province')); echo $this->formRow($form->get('country')); echo $this->formRow($form->get('coordinate')); echo $this->formSubmit($form->get('submit')); echo $this->form()->closeTag(); ?> What I expected to see is a vertical form like this: But what i got is an ugly form like this: What's wrong with my code? Please help. EDIT: When I inspect element, the form generated is strange. The <input> element is inside the <label> element. <form id="city" name="city" method="post" action="/karciscus/public/admin/city/add"> <input type="hidden" value="" name="id"> <label> <span>Name</span><input type="text" value="" name="name"> </label> <label> <span>Province</span><input type="text" value="" name="province"> </label> <label> <span>Country</span><input type="text" value="" name="country"> </label> <label> <span> Coordinate</span><input type="text" value="" name="coordinate"> </label> <input type="submit" value="Save" id="submitButton" name="submit"> </form> I'm pretty sure it is the cause of my ugly rendered form. I think it is not supposedly like that. How to fix it?

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  • Javascript: Perform function on form submit

    - by flight643
    Hopefully this is a pretty simple question! I've got the code working in jQuery to listen for a specific form on a page to be submitted and perform an alert when it is.. I.e.: The form itself doesn't have a name so I am targetting the form within a specific form ID. $("#content form").submit(function() { alert("lorem ipsum dolor?"); }); What would be the syntax for performing this in javascript alone without using jquery? For example, I have this code (below) and just am unsure of how to listen for the form to be submitted to perform an action.. var submitform = document.getElementById("content").getElementsByTagName("form"); Thanks!

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  • How can I get jquery .val() AFTER keypress event?

    - by werner5471
    I got: $(someTextInputField).keypress(function() { alert($(this).val()); }); Now the alert always returns the value BEFORE the keypress (e.g. the field is empty, I type 'a' and the alert gives me ''. Then I type 'b' and the alert gives me 'a'...). But I want the value AFTER the keypress - how can I do that? Background: I'd like to enable a button as soon as the text field contains at least one character. So I run this test on every keypress event, but using the returned val() the result is always one step behind. Using the change() event is not an option for me because then the button is disabled until you leave the text box. If there's a better way to do that, I'm glad to hear it!

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  • Stop an input field in a form from being submitted

    - by Acorn
    I'm writing some javascript that will insert some input fields into a form on a website. The thing is, I don't want those input fields to affect the form in any way, I don't want them to be submitted when the form is submitted, I only want my javascript to have access to their values. Is there some way I could add some input fields into the middle of a form and not have them submitted when the form is submitted? Obviously the ideal thing would be for the input fields to not be in the form element, but I want the layout of my resulting page to have my inserted input fields appear between elements of the original form.

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  • How to set the ReturnUrl for the Login link in MVC 3 app?

    - by user762196
    using System; using Microsoft.Practices.Unity; namespace <MyNameSpace> { public class UrlFactory { public static UrlFactory Current { get { return HttpApplicationUnityContext.Current.Resolve<UrlFactory>(); } } public string GetLoginUrl() { return String.Format("{0}/login?ReturnUrl={1}", MyConfig.BaseHttpUrl, <GET_PAGE_URL>); } } The user can be on any page on the site and click the Login link. But the ReturnUrl must always point to the exact page where he clicked it. I must take the user back to the page he clicked the login link. In my code above, how do I get the page url in <GET_PAGE_URL>? Thanks

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  • HTML table manipulation using jQuery

    - by Daniel
    I'm building a site using CakePHP and am currently working on adding data to two separate tables at the same time.. not a problem. The problem I have is that I'm looking to dynamically alter the form that accepts the input values, allowing the click of a button/link to add an additional row of form fields. At the moment I have a table that looks something like this: <table> <thead> <tr> <th>Campus</th> <th>Code</th> </tr> </thead> <tbody> <tr> <td> <select id="FulltimeCourseCampusCode0CampusId" name="data[FulltimeCourseCampusCode][0][campus_id]"> <option value=""></option> <option value="1">Evesham</option> <option value="2">Malvern</option> </select> </td> <td> <input type="text" id="FulltimeCourseCampusCode0CourseCode" name="data[FulltimeCourseCampusCode][0][course_code]"> </td> </tr> </tbody> What I need is for the row within the tbody tag to be replicated, with the minor change of having all the zeros (i.e. such as here FulltimeCourseCampusCode0CampusId and here data[FulltimeCourseCampusCode][0][campus_id]) incremented. I'm very new to jQuery, having done a few minor bits, but nothing this advanced (mostly just copy/paste stuff). Can anyone help? Thank you.

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  • codeigniter populate form from database

    - by Delirium tremens
    In the controller, I have... function update($id = null) { $this->load->database(); // more code $data = array(); $data = $this->db->get_where( 'users', array( 'id' => $id ) ); $data = $data->result_array(); $data = $data[0]; // more code $this->load->view('update', $data); } In the view, I have... <h5>Username</h5> <input type="text" name="username" value="<?php echo set_value('username'); ?>" size="50" /> <h5>Email</h5> <input type="text" name="email" value="<?php echo set_value('email'); ?>" size="50" /> <h5>Email Confirmation</h5> <input type="text" name="emailconf" value="<?php echo set_value('emailconf'); ?>" size="50" /> <h5>Password</h5> <input type="text" name="password" value="<?php echo set_value('password'); ?>" size="50" /> <h5>Password Confirmation</h5> <input type="text" name="passconf" value="<?php echo set_value('passconf'); ?>" size="50" /> set_value() isn't reading $data search for value="" at http://codeigniter.com/forums/viewthread/103837/ The poster uses only the set_value() function between "" in value="". I'm wondering how to do the same, but I can't get it to work. Help?

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  • How to nest a form in an ASP.NET page (which has a form wrapped around it)

    - by Josh
    I am writing HTML to an ASP.NET page (from a web service response), and the HTML has tags. Unfortunately, because the ASP.NET page already has a wrapped around it, a lot of the buttons on the page break. Does anyone know how I can nest the form inside the ASP.NET page without breaking the top-level form? Note: the HTML I am bringing in is a form with a bunch of hidden fields inside of it, and it has to be placed within the ASP.NET page, and thus nested in the top-level form. Thanks

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  • Contact form with php-script does not work

    - by elajjas
    I'm new to the forum and I have been trying to find a thread that could be helpful but nothing have been working out so far. I recently uploaded my site via FTP, and it works fine. Except for one thing, my contact form. The contact form is crucial and it is almost the whole point of the website. I don't get any emails "from the form", either in my spam-folder or inbox. Please have a look at the website which is: http://www.adspot.se The contact form is situated on: http://www.adspot.se/contact.html The php script looks like this: <?php if (isset($_REQUEST['email'])) //if "email" is filled out, send email { //send email $name = $_REQUEST['name'] ; $email = $_REQUEST['email'] ; $message = $_REQUEST['message'] ; mail("[email protected]", $name, $message, "From:" . $email); } ?> I've already tried different types of php-scripts, but it still doesn't seem to work. UPDATE: Changed the form code to: <form method="POST" action="email.php"> <div class="row half"> <div class="6u"> <input name="name" placeholder="Name" type="text" class="text" /> </div> <div class="6u"> <input name="email" placeholder="Email" type="text" class="text" /> </div> </div> <div class="row half"> <div class="12u"> <textarea name="message" placeholder="Message"></textarea> </div> </div> <div class="row half"> <div class="12u"> <ul class="action"> <input type="submit" class="action"> </ul> </div> </div> </form> Now it redirects me to www.adspot.se/email.php but still no emails received...

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  • Setting a form field's value during validation

    - by LaundroMat
    I read about this issue already, but I'm having trouble understanding why I can't change the value of a form's field during validation. I have a form where a user can enter a decimal value. This value has to be higher than the initial value of the item the user is changing. During clean(), the value that was entered is checked against the item's previous value. I would like to be able to re-set the form field's value to the item's initial value when a user enters a lower value. Is this possible from within the clean() method, or am I forced to do this in the view? Somehow, it doesn't feel right to do this in the view... (To make matters more complicated, the form's fields are built up dynamically, meaning I have to override the form's clean() method instead of using the clean_() method).

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  • single sign on in asp.net

    - by gopal
    Hi , We have developed implemented single sign on methodology to authenticate user. When a page is requested, if it is not authenticated then a login page will be redirected. Once they logged in the requested page will be shown. this is working when we don't assign a domain to the virtual directory. But when we assign the domain to virtual directory after the authentication the application is not redirecting to the requested page. We are using FormsAuthentication.GetRedirectUrl method to redirect the requested page. Why this is happening? How can we resolve this issue?

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  • Form Arrays support across browsers

    - by Stomped
    I'm not even sure if form arrays is the proper term, but it looks a bit like this: <input name='element[]' type='text' /> <input name='element[]' type='text' /> Which is then retrieved in PHP as an array stored in $_POST['element'] -- in this case with 2 values. I've tested it in the browsers I have available to me, but I've never seen this before and I'm wondering is this supported pretty much in all browsers? Or is this something very old that I've just not run into? Thanks!

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  • PHP Form - Empty input enter this text - Validation

    - by James Skelton
    No doubt very simple question for someone with php knowledge. I have a form with a datepicker, all is fine when a user has selected a date the email is send with: Date: 2012 04 10 But i would like if the user has skipped this and left blank (as i have not made this required) to send as: Date: Not Entered (<-- Or something) Instead at the minute of course it reads: Date: Form input <input type="text" class="form-control" id="datepicker" name="datepicker" size="50" value="Date Of Wedding" /> This is the validator $(document).ready(function(){ //validation contact form $('#submit').click(function(event){ event.preventDefault(); var fname = $('#name').val(); var validInput = new RegExp(/^[a-zA-Z0-9\s]+$/); var email = $('#email').val(); var validEmail = new RegExp(/^([a-zA-Z0-9_\.\-])+\@(([a-zA-Z0-9\-])+\.)+([a-zA-Z0-9]{2,4})+$/); var message = $('#message').val(); if(fname==''){ showError('<div class="alert alert-danger">Please enter your name.</div>', $('#name')); $('#name').addClass('required'); return;} if(!validInput.test(fname)){ showError('<div class="alert alert-danger">Please enter a valid name.</div>', $('#name')); $('#name').addClass('required'); return;} if(email==''){ showError('<div class="alert alert-danger">Please enter an email address.</div>', $('#email')); $('#email').addClass('required'); return;} if(!validEmail.test(email)){ showError('<div class="alert alert-danger">Please enter a valid email.</div>', $('#email')); $('#email').addClass('required'); return;} if(message==''){ showError('<div class="alert alert-danger">Please enter a message.</div>', $('#message')); $('#message').addClass('required'); return;} // setup some local variables var request; var form = $(this).closest('form'); // serialize the data in the form var serializedData = form.serialize(); // fire off the request to /contact.php request = $.ajax({ url: "contact.php", type: "post", data: serializedData }); // callback handler that will be called on success request.done(function (response, textStatus, jqXHR){ $('.contactWrap').show( 'slow' ).fadeIn("slow").html(' <div class="alert alert-success centered"><h3>Thank you! Your message has been sent.</h3></div> '); }); // callback handler that will be called on failure request.fail(function (jqXHR, textStatus, errorThrown){ // log the error to the console console.error( "The following error occured: "+ textStatus, errorThrown ); }); }); //remove 'required' class and hide error $('input, textarea').keyup( function(event){ if($(this).hasClass('required')){ $(this).removeClass('required'); $('.error').hide("slow").fadeOut("slow"); } }); // show error showError = function (error, target){ $('.error').removeClass('hidden').show("slow").fadeIn("slow").html(error); $('.error').data('target', target); $(target).focus(); console.log(target); console.log(error); return; } });

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  • MYSQL/PHP: Inserting data via HTML form, same "input name"

    - by Camen
    I'm new to MySQL and as a learning project I'd like to make a recipe database. I'd like to the user to be able to enter ingredients through a simple HTML form but I'm stuck in how to label the form so that I can enter several ingredients into the database at once. I'd like to do something like this: <form method="post" action="insert.php"> Ingredient 1: <input type="text" name="ingredient"><br /> Ingredient 2: <input type="text" name="ingredient"><br /> Ingredient 3: <input type="text" name="ingredient"><br /> <input type="submit" value="Submit"> </form> When I do this, I add rows to the table but they're all empty. I know it's got something to do with me using "ingredient" (the table value where I want to add the ingredient name) several times in the form, but I just don't know how to solve it. I would absolutely love some input on how to make it work.

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  • How do I select an option using Spring's form:select tag?

    - by Dave
    I'm using Spring 3.1.1.RELEASE. Using the form:select tag, how do I specify which option should be selected? I want the first one to be selected, but when I put <form:select path="parentOrganization"> <form:option value="" label="Select an Org Type or Parent Org" /> <form:options items="${orgTypesWoParents}" itemValue="id" itemLabel="description" /> <form:option value="" label="=======================" /> </form:select> the last one is selected. I want to preserve the order of how everything is displayed, which is why I've arranged things in this way.

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