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  • Under what circumstances are linked lists useful?

    - by Jerry Coffin
    Most times I see people try to use linked lists, it seems to me like a poor (or very poor) choice. Perhaps it would be useful to explore the circumstances under which a linked list is or is not a good choice of data structure. Ideally, answers would expound on the criteria to use in selecting a data structure, and which data structures are likely to work best under specified circumstances.

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  • converting linq query to icollection

    - by bergin
    Hi there. I need to take the results of a query: var query = from m in db.SoilSamplingSubJobs where m.order_id == id select m; and prepare as an ICollection so that I can have something like ICollection<SoilSamplingSubJob> subjobs at the moment I create a list, which isnt appropriate to my needs: query.ToList(); what do I do - is it query.ToIcollection() ?

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  • How to display an array's content in colomns, like ls -C does.

    - by Arko
    I wanted to display a long list of strings from an array. Right now, my script run through a for loop echoing each value to the standard output: for value in ${values[@]} do echo $value done Yeah, that's pretty ugly! And the one column listing is pretty long too... I was wondering if i can find a command or builtin helping me to display all those values in columns, like the ls command does by default when listing a directory (ls -C).

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  • Prolog - generate correct bracketing

    - by Henrik Bak
    I'd like to get some help in the following exam problem, i have no idea how to do this: Input: a list of numbers, eg.: [1,2,3,4] Output: every possible correct bracketing. Eg.: (in case of input [1,2,3,4]): ((1 2) (3 4)) ((1 (2 3)) 4) (1 ((2 3) 4)) (1 (2 (3 4))) (((1 2) 3) 4) Bracketing here is like a method with two arguments, for example multiplication - then the output is the possible multiplication orders. Please help, i'm stuck with this one. Any help is appreciated, thanks!

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  • Addind link with existin href.

    - by Dom
    Hello gurus, Im trying to create link inside my list tag that will have href inherited from link that already exists in this list tag. Don't know how much sense does it makes, but i have this: <ul> <li><a href="page1.html">Support</a></li> <li><a href="page2.html">Products</a></li> <li><a href="page3.html">Management</a></li> <li><a href="page4.html">Others</a></li> </ul> and I need soothing like this: <ul> <li> <a href="page1.html">Support</a> <div class="slideLink"><a href="page1.html">Click Here</a></div> </li> <li> <a href="page2.html">Products</a> <div class="slideLink"><a href="page2.html">Click Here</a></div> </li> <li> <a href="page3.html">Management</a> <div class="slideLink"><a href="page3.html">Click Here</a></div> </li> <li> <a href="page4.html">Others</a> <div class="slideLink"><a href="page4.html">Click Here</a></div> </li> </ul> So far I have managed to add div with class and link within it with "click here" text, but i don't have a clue how to grab link href and add it to my new link. $('ul li a').each(function(){ $(this).after("<div class='slideLink'><a href=" + Link + ">Read more</div>"); }); Thank you for your help in advance. Best Regards Dom

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  • Take the intersection of an arbitrary number of lists in python

    - by thepandaatemyface
    Suppose I have a list of lists of elements which are all the same (i'll use ints in this example) [range(100)[::4], range(100)[::3], range(100)[::2], range(100)[::1]] What would be a nice and/or efficient way to take the intersection of these lists (so you would get every element that is in each of the lists)? For the example that would be: [0, 12, 24, 36, 48, 60, 72, 84, 96]

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  • embed youtube custom playlist name

    - by John Stockton
    I found a nice article: http://911-need-code-help.blogspot.com/2012/07/youtube-iframe-embeds-video-playlist-and-html5.html I am using the last option (Custom Playlist). But how to edit the embed code: <iframe width="560" height="315" src="http://www.youtube.com/embed/T0Jqdjbed40?playlist=SyoA4LXQco4,6l6PPvUhR4c" frameborder="0" allowfullscreen></iframe> in order to show my playlist name above thumbinails? i tried to add listname="name", name="name", list="name" but it don't work

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  • Java - PriorityQueue vs sorted LinkedList

    - by msr
    Hello, Which implementation is less "heavy": PriorityQueue or a sorted LinkedList (using a Comparator)? I want to have all the items sorted. The insertion will be very frequent and ocasionally I will have to run all the list to make some operations. Thank you!

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  • When to use LinkedList<> over ArrayList<>?

    - by sdellysse
    I've always been one to simply use List<String> names = new ArrayList<String>(); I use the interface as the type name for portability, so that when I ask questions such as these I can rework my code. When should LinkedList should be used over ArrayList and vice-versa?

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  • Generate a sequence of Fibonacci number in Scala

    - by qin
    def fibSeq(n: Int): List[Int] = { var ret = scala.collection.mutable.ListBuffer[Int](1, 2) while (ret(ret.length - 1) < n) { val temp = ret(ret.length - 1) + ret(ret.length - 2) if (temp >= n) { return ret.toList } ret += temp } ret.toList } So the above is my code to generate a Fibonacci sequence using Scala to a value n. I am wondering if there is a more elegant way to do this in Scala?

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  • LinkedList insert tied to inserted object

    - by wrongusername
    I have code that looks like this: public class Polynomial { List<Term> term = new LinkedList<Term>(); and it seems that whenever I do something like term.add(anotherTerm), with anotherTerm being... another Term object, it seems anotherTerm is referencing the same thing as what I've just inserted into term so that whenever I try to change anotherTerm, term.get(2) (let's say) get's changed too. How can I prevent this from happening?

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  • Data structure for an ordered set with many defined subsets; retrieve subsets in same order

    - by Aaron
    I'm looking for an efficient way of storing an ordered list/set of items where: The order of items in the master set changes rapidly (subsets maintain the master set's order) Many subsets can be defined and retrieved The number of members in the master set grow rapidly Members are added to and removed from subsets frequently Must allow for somewhat efficient merging of any number of subsets Performance would ideally be biased toward retrieval of the first N items of any subset (or merged subset), and storage would be in-memory (and maybe eventually persistent on disk)

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  • How to test an iPhone application update?

    - by sfkaos
    I already have an iPhone application (version 1.0) available in the App Store and am ready to submit a newer version (version 1.1). How do I test the new upgrade to make sure that the current sqlite database and property list files on the earlier version do not get deleted/overwritten etc? The new version assumes the old data in both the sqlite database and property lists remain. Or better yet, is there a resource I can use to walk me through what to watch for when developing an application update?

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  • Is it alright to call len() in a loop's conditional statement?

    - by DormoTheNord
    In C, it is considered bad practice to call strlen like this: for ( i = 0; strlen ( str ) != foo; i++ ) { // stuff } The reason, of course, is that it is inefficient since it "counts" the characters in a string multiple times. However, in Python, I see code like this quite often: for i in range ( 0, len ( list ) ): # stuff Is this bad practice? Should I store the result of len() in a variable and use that?

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  • How to extract List<int> from Dictionary<int, string>?

    - by DaveDev
    I have a method that takes a List<int>, which is a list of IDs. The source of my data is a Dictionary<int, string> where the integers are what I want a list of. Is there a better way to get this than the following code? var list = new List<int>(); foreach (var kvp in myDictionary) { list.Add(pair.Key); } ExecuteMyMethod(list);

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  • List<T> and IEnumerable difference

    - by Jonas Elfström
    While implementing this generic merge sort, as a kind of Code Kata, I stumbled on a difference between IEnumerable and List that I need help to figure out. Here's the MergeSort public class MergeSort<T> { public IEnumerable<T> Sort(IEnumerable<T> arr) { if (arr.Count() <= 1) return arr; int middle = arr.Count() / 2; var left = arr.Take(middle).ToList(); var right = arr.Skip(middle).ToList(); return Merge(Sort(left), Sort(right)); } private static IEnumerable<T> Merge(IEnumerable<T> left, IEnumerable<T> right) { var arrSorted = new List<T>(); while (left.Count() > 0 && right.Count() > 0) { if (Comparer<T>.Default.Compare(left.First(), right.First()) < 0) { arrSorted.Add(left.First()); left=left.Skip(1); } else { arrSorted.Add(right.First()); right=right.Skip(1); } } return arrSorted.Concat(left).Concat(right); } } If I remove the .ToList() on the left and right variables it fails to sort correctly. Do you see why? Example var ints = new List<int> { 5, 8, 2, 1, 7 }; var mergeSortInt = new MergeSort<int>(); var sortedInts = mergeSortInt.Sort(ints); With .ToList() [0]: 1 [1]: 2 [2]: 5 [3]: 7 [4]: 8 Without .ToList() [0]: 1 [1]: 2 [2]: 5 [3]: 7 [4]: 2 Edit It was my stupid test that got me. I tested it like this: var sortedInts = mergeSortInt.Sort(ints); ints.Sort(); if (Enumerable.SequenceEqual(ints, sortedInts)) Console.WriteLine("ints sorts ok"); just changing the first row to var sortedInts = mergeSortInt.Sort(ints).ToList(); removes the problem (and the lazy evaluation). EDIT 2010-12-29 I thought I would figure out just how the lazy evaluation messes things up here but I just don't get it. Remove the .ToList() in the Sort method above like this var left = arr.Take(middle); var right = arr.Skip(middle); then try this var ints = new List<int> { 5, 8, 2 }; var mergeSortInt = new MergeSort<int>(); var sortedInts = mergeSortInt.Sort(ints); ints.Sort(); if (Enumerable.SequenceEqual(ints, sortedInts)) Console.WriteLine("ints sorts ok"); When debugging You can see that before ints.Sort() a sortedInts.ToList() returns [0]: 2 [1]: 5 [2]: 8 but after ints.Sort() it returns [0]: 2 [1]: 5 [2]: 5 What is really happening here?

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