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  • Sorting a list of numbers with modified cost

    - by David
    First, this was one of the four problems we had to solve in a project last year and I couldn’t find a suitable algorithm so we handle in a brute force solution. Problem: The numbers are in a list that is not sorted and supports only one type of operation. The operation is defined as follows: Given a position i and a position j the operation moves the number at position i to position j without altering the relative order of the other numbers. If i j, the positions of the numbers between positions j and i - 1 increment by 1, otherwise if i < j the positions of the numbers between positions i+1 and j decreases by 1. This operation requires i steps to find a number to move and j steps to locate the position to which you want to move it. Then the number of steps required to move a number of position i to position j is i+j. We need to design an algorithm that given a list of numbers, determine the optimal (in terms of cost) sequence of moves to rearrange the sequence. Attempts: Part of our investigation was around NP-Completeness, we make it a decision problem and try to find a suitable transformation to any of the problems listed in Garey and Johnson’s book: Computers and Intractability with no results. There is also no direct reference (from our point of view) to this kind of variation in Donald E. Knuth’s book: The art of Computer Programing Vol. 3 Sorting and Searching. We also analyzed algorithms to sort linked lists but none of them gives a good idea to find de optimal sequence of movements. Note that the idea is not to find an algorithm that orders the sequence, but one to tell me the optimal sequence of movements in terms of cost that organizes the sequence, you can make a copy and sort it to analyze the final position of the elements if you want, in fact we may assume that the list contains the numbers from 1 to n, so we know where we want to put each number, we are just concerned with minimizing the total cost of the steps. We tested several greedy approaches but all of them failed, divide and conquer sorting algorithms can’t be used because they swap with no cost portions of the list and our dynamic programing approaches had to consider many cases. The brute force recursive algorithm takes all the possible combinations of movements from i to j and then again all the possible moments of the rest of the element’s, at the end it returns the sequence with less total cost that sorted the list, as you can imagine the cost of this algorithm is brutal and makes it impracticable for more than 8 elements. Our observations: n movements is not necessarily cheaper than n+1 movements (unlike swaps in arrays that are O(1)). There are basically two ways of moving one element from position i to j: one is to move it directly and the other is to move other elements around i in a way that it reaches the position j. At most you make n-1 movements (the untouched element reaches its position alone). If it is the optimal sequence of movements then you didn’t move the same element twice.

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  • Is a server an infinite loop running as a background process?

    - by Tony
    Is a server essentially a background process running an infinite loop listening on a port? For example: while(1){ command = read(127.0.0.1:xxxx); if(command){ execute(command); } } When I say server, I obviously am not referring to a physical server (computer). I am referring to a MySQL server, or Apache, etc. Full disclosure - I haven't had time to poke through any source code. Actual code examples would be great!

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  • How to implement event listener in background of the main program in java?

    - by Johny
    Hi im a beginner so sorry for my question if it sounds naive. I want to implement a thread that runs in the background and listens all the time. By listening i mean, say it keeps check on a value returned from main thread and if the vaue exceeds certain figure, it executes some method, or say exits the program. If you could give me some idea or at least refer me to something useful, that'll be great.

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  • Monad in plain English? (For the OOP programmer with no FP background)

    - by fig-gnuton
    In terms that an OOP programmer would understand (without any functional programming background), what is a monad? What problem does it solve and what are the most common places it's used? EDIT: To clarify the kind of understanding I was looking for, let's say you were converting an FP application that had monads into an OOP application. What would you do to port the responsibilities of the monads into the OOP app?

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  • How to make an tiled background like on the web?

    - by mystify
    On the iPhone, how could I achieve the same tiled background effect? For example, I have an pattern image which I want to repeat only horizontally. Would I have to go the route in -drawRect: by myself and loop over to draw the pattern, or is there a convenient method to do that?

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  • An html5 canvas element in the background of my page?

    - by fx42
    Is it possible to have a full screen canvas element in the background of a webpage and "normal" markup elements like a table in front of it? like the following snippet (if it wouldn't be used as alternative content): <canvas id=&#34;imageView&#34; width=100%; height=100%;> <table>...</table> </canvas>

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  • change background of an ImageView (the old image stays there!)

    - by nourdine
    how can I change the background of an ImageView from java? I have an ImageView and at a certain point I need to change the image that it displays (set in the styles). I tried to do it like this: placeHolder.setImageDrawable(myDrawb); but it looks like the old image remains there and it is partially covered but the new one (which in my case has different shape). hope you guys can help! cheers

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  • jQuery: How to position one element relative to another?

    - by paul
    I have a hidden DIV which contains a toolbar-like menu. I have a number of DIVs which are enabled to show the menu DIV when the mouse hovers over them. Is there a built-in function which will move the menu DIV to the top right of the active (mouse hover) DIV? I'm looking for something like $(menu).position("topright", targetEl);

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  • jQuery animate slidding background image using mouse position wont stop... just keeps going

    - by simian
    I have a neat little jQuery script I am working on. Goal: parent div with overflow hidden holds a larger div with image. When I move the mouse to the left or right of the parent div, the div with image changes margin-left to move left or right. Problem is... if I move the mouse out of the parent div (left or right), the image keeps going. I need the image to stop when the mouse is not on the inside left or right edge of the parent div. Any ideas? <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"></script> <script type="text/javascript"> //<![CDATA[ jQuery.noConflict (); jQuery(document).ready(function(){ jQuery('#container').mousemove(function(e){ var parentWidth = jQuery('#container').width(); var parentWidthLeft = Math.round(.1 * jQuery('#container').width()); var parentWidthRight = Math.round(jQuery('#container').width() - parentWidthLeft); var parentHeight = jQuery('#container').height(); var parentOffset = jQuery('#container').offset(); var X = Math.round(e.pageX - parentOffset.left); var Y = Math.round(e.pageY - parentOffset.top); if (X<parentWidthLeft) { jQuery('#image').animate({'left': '-' + parentWidth }, 5000); } if (X>parentWidthRight) { jQuery('#image').animate({'left': parentWidth }, 5000); } if (X<=parentWidthRight && X>=parentWidthLeft) { jQuery('#image').stop(); } if (X<1) { jQuery('#image').stop(); } }); jQuery('#container').mouseleave(function(){ jQuery('#image').stop(); }); }); // ]]> </script> </head> <body> <div id="container" style="width: 500px; height: 500px; overflow: hidden; border: 10px solid #000; position: relative; margin: auto auto;"> <div id="image" style="position: absolute; left: 0; top: 0;"><img src="http://dump4free.com/imgdump/1/Carmen-Electra_1wallpaper1024x768.jpg" alt="" /></div> </div> </body> </html>

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  • How do I make image hyperlinks have a background image?

    - by Richard
    I want all .jpg links to have a certain background image. so a link on a page like 'http://mysite/myimage.jpg' would automatically be prefixed with a small icon. Actually all links to images, ie .gif .png as well with the same icon. If the link is to a website, ie .htm/.php/.html/.asp it should have a different image. I want it to be through classes in CSS. Any help appreciated. TIA

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  • Is the W3 standard a major factor when google decides SERP position?

    - by Camran
    I have a dynamic php website which index only has around 800 errors according to the w3 validator online. I have tried checking major websites like ebay, stackoverflow and others also, all with around 400 errors. So my first thought is, what good is that validator when it always displays errors? Secondly, will the errors affect my SERP ranking? ie, will me fixing these errors as good as I can increase my Google search position? Thanks

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  • Can <Setter.Value> have multiple grids inside it

    - by Subhen
    Hi, I want to define the background for my application in App.XAML. The background was previously defined in another xaml page,which have multiple Grids inside it like following: <Grid x:Key="GridGeneric" d:LayoutOverrides="Width, Height"> <Grid.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF00172E" Offset="1"/> <GradientStop Color="#FF004074" Offset="0.433"/> <GradientStop Color="#FF081316"/> <GradientStop Color="#FF001D3F" Offset="0.215"/> <GradientStop Color="#FF002043" Offset="0.818"/> <GradientStop Color="#FF003B6C" Offset="0.642"/> </LinearGradientBrush> </Grid.Background> <Grid> <Grid.Background> <RadialGradientBrush RadiusY="0.973" GradientOrigin="0.497,-0.276" RadiusX="1.003"> <GradientStop Color="#FFB350EE" Offset="0"/> <GradientStop Color="#001D3037" Offset="0.847"/> </RadialGradientBrush> </Grid.Background> </Grid> ------ ----- </Grid> Now I want to place the same in my App.xaml like following: <Style x:Key="backgroundStyle" TargetType="Grid"> <Setter Property="Background"> <Setter.Value> <Grid> <Grid.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF00172E" Offset="1"/> <GradientStop Color="#FF004074" Offset="0.433"/> <GradientStop Color="#FF081316"/> <GradientStop Color="#FF001D3F" Offset="0.215"/> <GradientStop Color="#FF002043" Offset="0.818"/> <GradientStop Color="#FF003B6C" Offset="0.642"/> </LinearGradientBrush> </Grid.Background> <Grid> <Grid.Background> <RadialGradientBrush RadiusY="0.973" GradientOrigin="0.497,-0.276" RadiusX="1.003"> <GradientStop Color="#FFB350EE" Offset="0"/> <GradientStop Color="#001D3037" Offset="0.847"/> </RadialGradientBrush> </Grid.Background> </Grid> --------- --------- </Grid> </Setter.Value> </Setter> </Style> But While doing this I am getting the following Exception.

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