Search Results

Search found 5493 results on 220 pages for 'boost regex'.

Page 98/220 | < Previous Page | 94 95 96 97 98 99 100 101 102 103 104 105  | Next Page >

• replace capturing group

  - by Don

  Hi, If I have a regex with a capturing group, e.g. foo(_+f). If I match this against a string and want to replace the first capturing group in all matches with baz so that foo___f blah foo________f is converted to: foobaz blah foobaz There doesn't appear to be any easy way to do this using the standard libraries. If I use Matcher.replaceAll() this will replace all matches of the entire pattern and convert the string to baz blah baz Obviously I can just iterate through the matches, store the start and end index of each capturing group, then go back and replace them, but is there an easier way? Thanks, Don

  Read the article

• Exclude subexpression from regexec in c++

  - by wyatt

  Suppose I was trying to match the following expression using regex.h in C++, and trying to obtain the subexpressions contained: /^((1|2)|3) (1|2)$/ Suppose it were matched against the string "3 1", the subexpressions would be: "3 1" "3" "1" If, instead it were matched against the string "2 1", the subexpressions would be: "2 1" "2" "2" "1" Which means that, depending on how the first subexpression evaluates, the final one is in a different element in the pmatch array. I realise this particular example is trivial, as I could remove one of the sets of brackets, or grab the last element of the array, but it becomes problematic in more complicated expressions. Suppose all I want are the top-level subexpressions, the ones which aren't subexpressions of other subexpressions. Is there any way to only get them? Or, alternatively, to know how many subexpressions are matched within a subexpression, so that I can traverse the array irrespective of how it evaluates? Thanks

  Read the article

• Java replace all capturing groups

  - by Don

  Hi, If I have a regex with a capturing group, e.g. foo(g.*f). If I match this against a string and want to replace the first capturing group in all matches with baz so that foog___f blah foog________f is converted to: foobaz blah foobaz There doesn't appear to be any easy way to do this using the standard libraries, because the Matcher.replaceAll() method will only replace all matches of the entire pattern, am I missing something? Obviously I can just iterate through the matches, store the start and end index of each capturing group, then go back and replace them, but is there an easier way? Thanks, Don

  Read the article

• Sed substitution not doing what I want and think it should do

  - by nategoose

  I have am trying to use sed to get some info that is encoded within the path of a file which is passed as a parameter to my script (Bourne sh, if it matters). From this example path, I'd like the result to be 8 PATH=/foo/bar/baz/1-1.8/sing/song I first got the regex close by using sed as grep: echo $PATH | sed -n -e "/^.*\/1-1\.\([0-9][0-9]*\).*/p" This properly recognized the string, so I edited it to make a substitution out of it: echo $PATH | sed -n -e "s/^.*\/1-1\.\([0-9][0-9]*\).*/\1/" But this doesn't produce any output. I know I'm just not seeing something simple, but would really appreciate any ideas about what I'm doing wrong or about other ways to debug sed regular expressions.

  Read the article

• How do I remove specific numbers from a string?

  - by user1666900

  I have this string in PHP Hopelessly Incredible |SPG:M| 766 STEAM_0:1:20130600 " banned "A Blatantly Obvious Hacker 740 STEAM_0:1:55386073 " (minutes "0") (reason "Multi-Hack") The Format of the string is: Name1 Number(0-3 digits) Steam_0:x:xxxx offense (banned/kicked/mute etc) Name2 Number(0-3 digits) Steam_0:x:xxxx time reason My goal is to remove the values 766 and 740 because it is just garbage. Those values can have single, double, and triple digits. The next step would be to strip STEAM_0:1:20130600 and STEAM_0:1:55386073 out of the string and capture it in a new variable. The only constant is STEAM_0: the rest can change. I am still learning regex but I fear this is a bit complicated for me to do. Some guidance would be most appreciative.

  Read the article

• issue with regex in C#

  - by Dilip

  my file is > A B C D unuse data <begin> Addd as ss 1 My name is 2323 33 text > </end> 34344 no need and my code is StringBuilder mSb = new StringBuilder(); StreamReader sr = new StreamReader(@"E:\check.txt"); String line; while (sr.ReadLine() != null) { mSb.AppendLine(sr.ReadLine()); } string matc = new Regex(@"(<begin>)(\n?.*)*</end>)?").Match(mSb.ToString()).ToString(); here it reading all file , but i just want till if i am removing ? from end , my program is crashing .. Thanks

  Read the article

• Regular Expression; Find whether a line contains any word with more than X characters.

  - by Simpsoid

  Hi, I am trying to use a Validator on a ASP.NET site and need to find whether the Street Address textbox contains a valid entry. Entries with words that are longer than X characters (in this case 25, with no punctuation or spaces) will cause the HTML on a printed A4 page to not wrap properly and therefore not to confrom to certain sizes correctly pushing the margins off. For a street address I want to match that something like "201 Long Road" is valid but "235 ReallyLongAndNarrowWindingRoadBesideTheRiver Street" is invalid. Using a Microsoft .Net Regular Expression Validator I need to know what the RegEx pattern might be. I think if it does find a match the Validator will fire correctly however if there is no match the Validator won't fire and the Update button (in this case) won't fire. Since Street addresses can contain Capital Letters and numbers etc. it will need to accomodate for that and also Spaces, Commas, Semi-Colons and Colons and Hyphens are valid characters too. Any help would be greatly appreciated as I am really stuck with this problem. Thanks, David

  Read the article

• Regular Expression to recognise truncated forms of search string?

  - by Moonshield

  I'm trying to formulate a regular expression which will recognise the search term truncated by any number of characters from the right. For example, if the search term is "pickle", the regex should recognise "pi", "pick" but not "pickaxe". Initially I came up with the following: p(i(c(k(l(e)?)?)?)?)? That works perfectly, but seems a crude way of doing it. Is there a better way of doing this? I had a look around for something similar to what I want, but I'm not entirely sure what to search for.

  Read the article

• Assistance with regular expressions in Python

  - by da5id

  I am still learning REGEX, and I've run into an issue ... I am trying to separate a string that is composed of a mixture of letters and numbers that are in decimal format: AB0.500CD1.05EF2.29 Into something like this: list1 = AB,CD,EF list2 = 0.500,1.05,2.29 A complication to all this is that I also have strings that look like this: AB1CD2EF3 Which I'd also like to separate into this: list1 = AB,CD,EF list2 = 1,2,3 A previous inquiry yielded the following snippet, import re pattern = re.compile(r'([a-zA-Z]+)([0-9]+)') for (letters, numbers) in re.findall(pattern,cmpnd): print numbers print letters This example works fine for strings of the 2nd kind, but only "finds" the leading digit in the numbers that contain decimal places in the strings of the first kind. I've attempted an approach using the following line: pattern = re.compile(r'([a-zA-Z]+)([0-9]+(\.[0-9]))') But this results in an error: "ValueError: too many values to unpack" Thanks for any and all assistance!

  Read the article

• Regexp in iOS to find comments

  - by SteveDolphin23

  I am trying to find and process 'java-style' comments within a string in objective-C. I have a few regex snippets which almost work but I am stuck on one hurdle: different options seem to make the different styles work. For example, I am using this to match: NSArray* matches = [[NSRegularExpression regularExpressionWithPattern:expression options:NSRegularExpressionAnchorsMatchLines error:nil] matchesInString:string options:0 range:searchRange]; The options here allow me successfully find and process single line comments (//) but not multiline (/* */), if I change the option to NSRegularExpressionDotMatchesLineSeparators then I can make multiline work fine but I can't find the 'end' of a single line comment. I suppose really I need dot-matches-line-separators but I need a better way of finding the end of a single line comment? The regexp I have so far are: @"/\\*.*?\\*/" @"//.*$" it's clear to see if dot matches a line separator then the second one (single line) never 'finishes' but how do I fix this? I found some suggestions for single line that were more like: @"(\/\/[^"\n\r]*(?:"[^"\n\r]*"[^"\n\r]*)*[\r\n])" But that doesn't' seem to work at all! Thanks in advance for any pointers.

  Read the article

• Perl - string matching issue

  - by user2886545

  I have a problem I cannot understand. I have this string: gene_id "siRNA_Z27kG1_20543"transcript_id "siRNA_Z27kG1_20543_X_1";tss_id "TSS124620" And I want to change the gene_id. So, I have the following code: if ($line =~ /;transcript_id "([A-Za-z0-9:\-._]*)(_[oxOX][_.][0-9]*)";/) { $num = $2; $line =~ s/gene_id "([A-Za-z0-9:\-._]*)";/gene_id "$1$num";/g; print $new $line."\n"; } The aim of my code is to change siRNA_Z27kG1_20543 for siRNA_Z27kG1_20543_X_1. However, my code does not produce that output. Why? I can't understand that. My regex needs to be as it is because I match other strings (this time with success). Thanks.

  Read the article

• jQuery sanitizing comments and linkifying URLs

  - by iWasRobbed

  In terms of jQuery (or Javascript), what happens behind the scenes when a person posts a comment on Facebook, Twitter, or a blog? For instance, do they sanitize the text first, and then pattern match URL's into an actual link? Are there other items of concern that the client-side should check in addition to doing some checks on the backend? I have found a few regex's for turning URL's into links, but I'm not sure if there are better solutions. I'm trying to wrap my head around the problem, but I'm having a difficult time knowing where to start. Any guidance you can provide is greatly appreciated!

  Read the article

• Qt/C++ regular expression library with unicode property support

  - by Dave

  I'm converting an application from the .Net framework to Qt using C++. The application makes extensive use of regular expression unicode properties, i.e. \p{L}, \p{M}, etc. I've just discovered that the QRegExp class lacks support for this among other things (lookbehinds, etc.) Can anyone recommend a C++ regular expression library that: Supports unicode properties Is unicode-aware in other respects (i.e. \w matches more than ASCII word characters) As a bonus, supports lookbehinds. Please don't point me to the wikipedia article; I don't trust it. That article says that QRegExp supports unicode properties. Unless I'm really doing something wrong, it doesn't. I'm looking for someone actually using unicode properties with a regex library in a project.

  Read the article

• Do word boundaries work on symbol characters?

  - by Shawn31313

  I'm trying to implement word boundaries in my emoticons feature for a chat. But for some reason I can't seem to get the word boundaries to work. I am new to regex. So when I do: var reg = /\b\Hi\b/gi; var str = 'HiHiHi Hi HiHiHi Hi'; alert(str.replace(reg, '')); This happens: Jsfiddle It actually works fine, and does remove those 2 Hi's that are standing alone. But when I change the reg to an escaped smiley and then change the string: var reg = /\b\:\)\b/gi; var str = 'HiHi:) :) HiHiHi :)'; alert(str.replace(reg, '')); This happens: Jsfiddle It just doesn't work. The string stays the same. Is it that word boundaries can't be used on symbols? If so, how does Facebook do it on their chats?

  Read the article

• Question about regex in linux commands.

  - by smwikipedia

  I ran the following command at linux bash: apt-cache search hex.*(view|edit) My intention was to find any software packages whose name/description contains the pattern 'hex.*(view|edit)'. But among the results I got this: kipi-plugins - image manipulation/handling plugins for KIPI aware programs How could this be in the results list? I didn't see any matching string in this result. Is this a bug of the apt-cache search command? Or do I mis-understand how the regex is used by this command? Many thanks.

  Read the article

• Regular Expression to get the size value of a CSS property?

  - by thiesdiggity

  I wrote a regular expression to get the size from a CSS property: /(([+-]?\d*\.?\d+(\s)*(px|em|ex|pt|in|pc|mm|cm)?)|thin|medium|thick)(\s|;|$)/i but for some reason its not working as intended. For example, when I run the following: preg_match_all('/(([+-]?\d*\.?\d+(\s)*(px|em|ex|pt|in|pc|mm|cm)?)|thin|medium|thick)(\s|;|$)/i', "border-bottom:1px solid #99999;", $matches); It outputs: 1px 99999; But I only want the 1px value returned. I understand why its returning the above but can't seem to figure out how to only return the size and not the color value. I tried using the following negative lookbehind but it's not working either: /(((?<!#\d{3}|#\d{6})[+-]?\d*\.?\d+(\s)*(px|em|ex|pt|in|pc|mm|cm)?)|thin|medium|thick)(\s|;|$)/i I want to use preg_match_all for those CSS properties that can have multiple size values (i.e. margin). Anyone have any ideas how to get this regex to return only the size values? Thanks for your help!

  Read the article

• RegularExpressionValidator always fails, but ValidationExpression works in testing

  - by Jerph

  I found the answer to this, but it's a bit of a gotcha so I wanted to share it here. I have a regular expression that validates passwords. They should be 7 to 60 characters with at least one numeric and one alpha character. Pretty standard. I used positive lookaheads (the (?= operator) to implement it: (?=^.{7,60}$)(?=.*[0-9].*)(?=.*[a-zA-Z].*) I checked this expression in my unit tests using Regex.IsMatch(), and it worked fine. However, when I use it in a RegularExpressionValidator, it always fails. Why?

  Read the article

• comma in regex in String.replaceAll() method?

  - by kknight

  My code tries to replace "," with "/" in a string. Should I escape "," in the regex string? Both of the two code snippets generated the same results, so I am confused. Code snippet 1: String test = "a,bc,def"; System.out.println(test.replaceAll("\\,", "/")); Code snippet 2: String test = "a,bc,def"; System.out.println(test.replaceAll(",", "/")); Should I use "," or "\,"? Which is safer? Thanks.

  Read the article

• Need to create regular expression in Javascript to check the valid conditional string

  - by user1796078

  I want to create the regular expression in javascript which will check the valid conditional string like -1 OR (1 AND 2) AND 1 -1 OR (1 AND 2) -1 OR 2 -1 OR 1 OR 1 -1 AND 1 AND 1 The string should not contain 'AND' and 'OR'. For example - 1 OR 2 AND 3 is invalid. -It should be (1 OR 2) AND 3 or 1 or (2 AND 3). I tried the following Regex. It works for most of the conditions but it is failing to check the above condition. /^(\s*\(\d+\s(AND|OR)\s\d+\)|\s*\d+)((\s*(AND|OR)\s*)(\(\d+\s(AND|OR)\s\d+\)|\s*\d+))*$/ Can anyone please help me to sort out the above problem.

  Read the article

• .net equivalent for php preg_replace

  - by Hath

  What is the c#.net equivalent for php's preg_replace function? php code is like this: const ALLOW_VALUES = '[^a-z0-9àáâäèéêëìíîïòóôöùûwýÿyÁÂÄÈÉÊËÌÎÏÒÓÔÖÙÛÜWYÝ]'; public function streetTownHash($data, $hashCheck = false, $updateRecord = false) { foreach($data as $key=>$value){ try{ $value = mb_convert_case($value, MB_CASE_LOWER, "UTF-8"); } catch(Exception $e) { echo "Requires extension=php_mbstring.dll enabled ! - $e"; } $valueConcat .= preg_replace('/'.self::ALLOW_VALUES.'/','',$value); # Remove punctuation etc } $streetTownHash = sha1($valueConcat); .... this is as far as i've got but not sure about it.. private SHA1 hash = SHA1.Create(); private string hashAllowed = "[^a-z0-9àáâäèéêëìíîïòóôöùûwýÿyÁÂÄÈÉÊËÌÎÏÒÓÔÖÙÛÜWYÝ]"; public string HashString(string value) { value = // = regex not sure this part var bytes = ASCIIEncoding.UTF8.GetBytes(value); var hashed = hash.ComputeHash(bytes); return ASCIIEncoding.UTF8.GetString(hashed); }

  Read the article

• Boost Shared Pointer: Simultaneous Read Access Across Multiple Threads

  - by Nikhil

  I have a thread A which allocates memory and assigns it to a shared pointer. Then this thread spawns 3 other threads X, Y and Z and passes a copy of the shared pointer to each. When X, Y and Z go out of scope, the memory is freed. But is there a possibility that 2 threads X, Y go out of scope at the exact same point in time and there is a race condition on reference count so instead of decrementing it by 2, it only gets decremented once. So, now the reference count newer drops to 0, so there is a memory leak. Note that, X, Y and Z are only reading the memory. Not writing or resetting the shared pointer. To cut a long story short, can there be a race condition on the reference count and can that lead to memory leaks?

  Read the article

• regular expression

  - by Altariste

  Hi, I need to find all invocations of some logging macros in the code. The macro invocation is of the form: DEBUG[1-5] ( "methodName: the logged message", arguments) But the new versions of the macros are prepending the name of the method automatically, so my task is to write a Python script that will remove the duplicate function names specified already by the programmer. I'm using the sub function from the re module. I plan to substitute the part indicated by || signs below : ||DEBUG[1-5] ("methodName: || the logged message", arguments) with simply DEBUG[1-5](" The problem is following: To find the expressions I want to substitute, I use the following regular expression: ((DEBUG | INFO | all other macros names )[1-5]*)\s*\(\"\w+: But it doesn't match the whole expression ( from DEBUG right to the colon ), but only the macro name, that is for example DEBUG5. Is my expression wrong or there is some quirk in the Python regex processing? ( maybe the fact that I use the DEBUG[1-5] as a subgroup has something to do with this? ) Help from anyone more knowledgable than me appreciated :).

  Read the article

• String contains all the elements of a list

  - by CSSS

  I am shifting to Python, and am still relatively new to the pythonic approach. I want to write a function that takes a string and a list and returns true if all the elements in the list occur in the string. This seemed fairly simple. However, I am facing some difficulties with it. The code goes something like this: def myfun(str,list): for a in list: if not a in str: return False return True Example : myfun('tomato',['t','o','m','a']) should return true myfun('potato',['t','o','m','a']) should return false myfun('tomato',['t','o','m']) should return true Also, I was hoping if someone could suggest a possible regex approach here. I am trying out my hands on them too.

  Read the article

• Jquery Match() IP Address?

  - by user1635970

  I'm using a jquery script to validate form fields. This works well, but I'd like to change the validation of one field to check for IP Addresses. The regex I want to use is : \b(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b How do I amend the below to work with this ? (This is how the validation works for email address) jQuery("#Email").validate({ expression: "if (VAL.match(/^[^\\W][a-zA-Z0-9\\_\\-\\.]+([a-zA-Z0-9\\_\\-\\.]+)*\\@[a-zA-Z0-9_]+(\\.[a-zA-Z0-9_]+)*\\.[a-zA-Z]{2,4}$/)) return true; else return false;", message: "Should be a valid Email id" });

  Read the article

• Why are regular expressions such a complicated, cryptic mess?

  - by steffenj

  Often when I see regular expressions, I only see a total mess of characters. Why does it have to be this way? I guess what I really want to know is: are there alternatives to regular expressions that basically do the same thing but are implemented in a human readable language? [UPDATE] Thanks for all the great responses and inspiration! I wanted to highlight this particular link which shows how a (working) alternative would look like, which may also be a good starting point for learning or "simple" regex expressions. But you also quickly get a feel for the verbosity tradeoff.

  Read the article

< Previous Page | 94 95 96 97 98 99 100 101 102 103 104 105  | Next Page >