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  • How to execute a "name.desktop" file? [duplicate]

    - by Pubudug
    This question already has an answer here: Running a .desktop file in the terminal 10 answers #!/usr/bin/env xdg-open [Desktop Entry] Version=1.0 Type=Link Name=ShareFolder Icon=/usr/share/icons/DPL/NetworkShare.png Name[en_US]=ShareFolder URL=smb://servername/sharefolder This is my .desktop file which has a URL. How do I execute this desktop shortcut in the terminal? If i double click it works perfectly, but I need to execute this in terminal. I tried Running a .desktop file in the terminal. That didn't work for me either but it does if its an "application" shortcut. I'm trying here to execute "link" .desktop file, where you define in the type section (Type=Link) and (URL=smb://servername/sharefolder)

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  • VCS for single user using file sync service

    - by StackUnder
    I'm trying to setup a version control for my one man project. My project files are in sync thanks to live mesh (but I could be using dropbox for that matter), between my laptop, my home pc and my office pc. I'm now using Netbeans with local file history. Sometimes it helps to revert to a previous state of one file. But imagine a situation when multiple files have problems. Correct me if I'm wrong but I would have to go to every file and revert to previous "safe" state. I don't like this approach, so I'm considering using a version control between SVN and GIT. I have some previous experience with SVN (TortoiseSVN) and I know that I can create a file:// repo. So, what a want to do is setup a VCS inside my synced folder just to have the ability to "revert" to a previous version if something goes wrong. Since everything's been synced to all computers, I wouldn't ever need to run an update. The file tree organization would be the following: C:...\SyncedFolder\MyProject\ Inside MyProject folder are all the project files plus a directory that has SVN or GIT info of my project (the repo/master). What VCS is best for this situation: SVN or GIT? Does SVN need to store all files from HEAD revision, thus "duplicating" all my project inside my synced folder? Does GIT eliminates this problem? Is this the best approach?

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  • implementing a download manager that supports resuming

    - by Idan K
    hi, I intend on writing a small download manager in C++ that supports resuming (and multiple connections per download). From the info I gathered so far, when sending the http request I need to add a header field with a key of "Range" and the value "bytes=startoff-endoff". Then the server returns a http response with the data between those offsets. So roughly what I have in mind is to split the file to the number of allowed connections per file and send a http request per splitted part with the appropriate "Range". So if I have a 4mb file and 4 allowed connections, I'd split the file to 4 and have 4 http requests going, each with the appropriate "Range" field. Implementing the resume feature would involve remembering which offsets are already downloaded and simply not request those. Is this the right way to do this? What if the web server doesn't support resuming? (my guess is it will ignore the "Range" and just send the entire file) When sending the http requests, should I specify in the range the entire splitted size? Or maybe ask smaller pieces, say 1024k per request? When reading the data, should I write it immediately to the file or do some kind of buffering? I guess it could be wasteful to write small chunks. Should I use a memory mapped file? If I remember correctly, it's recommended for frequent reads rather than writes (I could be wrong). Is it memory wise? What if I have several downloads simultaneously? If I'm not using a memory mapped file, should I open the file per allowed connection? Or when needing to write to the file simply seek? (if I did use a memory mapped file this would be really easy, since I could simply have several pointers). Note: I'll probably be using Qt, but this is a general question so I left code out of it.

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  • Calculate total batch upload transfer percent with limited information

    - by GONeale
    Hi there, I have a system which uploads to a server file by file and displays a progress bar on file upload progress, then underneath a second progress bar which I want to indicate percentage of batch complete across all files queued to upload. Information and algorithms I can work out are: Bytes Sent / Total Bytes To Send = First progress bar (eg. 512KB of 1024KB (50%)) That works fine. However supposing I have two other files left to upload, but both file sizes are unknown (as this is only known once the file is about to commence upload, at which point it is compressed and file size is determined) how would I go about making my third progress bar? I didn't think this would be possible as I would need "Total Bytes Sent" / "Total Bytes To Send", to replicate the logic of my first progress bar on a larger scale, however I did get a version working: "Current file number we are on" / "total number of files to send" returning the percentage through the batch, however obviously will not incrementally update and it's pretty crude. So on further thinking I thought if I could incorporate the current file % with this algorithm I could perhaps get the correct progress percentage of my batch's current point. I tried this algorithm, but alas to no such avail (sorry to any math heads, it's probably quite apparent why it won't work) ("Current file number we are on" / "total number of files to send") * ("Bytes Sent" / "Total Bytes To Send") For example I thought I was on the right track when testing with this example: 2/3 (2nd of 3rd file) = 66% (this is right so far) but then when I added * 0.20 (for indicating only 20% of 2nd file has uploaded) we went back to 13%. What I need is only a little over 33%! I did try the inverse at 0.80 and a (2/3 * (2/3 * 0.2)) Can this be done without knowing entire bytes in batch to upload? Please help! Thank you!

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  • Force Download Files Broken Headers wrong?

    - by Sinan
    if($_POST['mode']=="save") { $root = $_SERVER['DOCUMENT_ROOT']; $path = "/mcboeking/"; $path = $root.$path; $file_path = $_POST['path']; $file = $path.$file_path; if(!file_exists($file)) { die('file not found'); } else { header("Cache-Control: public"); header("Content-Description: File Transfer"); header('Content-Type: application/force-download'); header("Content-Disposition: attachment; filename=\"".basename($file)."\";" ); header("Content-Length: ".filesize($file)); readfile($file);}} As soon as i download the file and open it i get an error message. When i try to open a .doc i get the message : file structure is invalid. And when i try to open a jpg : This file can not be opened. It may be corrupt or a file format that Preview does not recognize. But when i download PDF files, they open without any problem. Can someone help me? P.s. i tried different headers including : header('Content-Type: application/octet-stream');

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  • Read/Write Files from the Content Provider

    - by drum
    I want to be able to create a file from the Content Provider, however I get the following error: java.io.Filenotfoundexception: /0: open file failed: erofs (read-only file system) What I am trying to do is create a file whenever an application calls the insert method from my Provider. This is the excerpt of the code that does the file creation: FileWriter fstream = new FileWriter(valueKey); BufferedWriter out = new BufferedWriter(fstream); out.write(valueContent); out.close(); Originally I wanted to use openFileOutput() but the function appears to be undefined. Anyone has a workaround to this problem? EDIT: I found out that I had to specify the directory as well. Here is a more complete snippet of the code: File file = new File("/data/data/Project.Package.Structure/files/"+valueKey); file.createNewFile(); FileWriter fstream = new FileWriter(file); BufferedWriter out = new BufferedWriter(fstream); out.write(valueContent); out.close(); I also enabled the permission <uses-permission android:name="android.permission.WRITE_INTERNAL_STORAGE" /> This time I got an error saying: java.io.IOException: open failed: ENOENT (No such file or directory)

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  • PHP: parse $_FILES[] data in multidimesional array

    - by superUntitled
    I having been looking around for an answer to this and have not found an answer anywhere, I am hoping someone has done this before! I have a form that allows for dynamic duplication of the form fields. The form allows for file uploads and text input, so the data is sent in both $_POST and $_FILES arrays. The the initial set of inputs look like this: <input type="text" name="primary[1][text]" /> <input type="file" name="primary[1][file]" /> <input type="text" class="a" name="secondary[1][text][]" /> <input type="file" name="secondary[1][file][]" /> When duplicated the fields are incremented, they look like this: <input type="text" name="primary[2][text]" /> <input type="file" name="primary[2][file]" /> <input type="text" class="a" name="secondary[2][text][]" /> <input type="file" name="secondary[2][file][]" /> To complicate matters, the "secondary" form fields can also be duplicated (thus the [] at the end of the secondary name array. How can I parse the posted $_FILES array? I have tried something like this: foreach ($_FILES['question'] as $f_num) { echo $f['file']['name']; } but I get an "Undefined index: file... " error.

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  • Javascript - why do I sometimes fail to read file content with GDownloadUrl?

    - by Daj pan spokój
    Hi everybody. I try to read some file with google's GDownloadUrl and it works only from time to time. failure means fileRows == "blah blah" success means fileRows == (real file content) I've noticed, however, that when I cease (with Firebug) the execution on line 3 for a couple of seconds, it succeeds more often. Maybe it is some kind of threading bug, then? Do You guys have any tip or idea? 1 var fileContent = "blah blah"; 2 availabilityFile = "input/available/" + date + ".csv"; 3 GDownloadUrl(availabilityFile, function(fileData) { 4 fileContent = fileData; 5 }); 6 fileRows = fileContent.split("\n");

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  • Parsing JPEG file format: Format of entropy-coded segment (ECS) segments?

    - by me2
    I'm having difficulty understanding the ITU-T T.81 spec for the JPEG file format. Hopefully someone else here has tried to parse JPEG files and/or knows about the details of this file format. The spec indiates that the ECS0 segment starts after the SOS segment but I can't find where in the spec it actually talks about the format of the ECS0 segment or how do detect its start. Simple JPEG implementations online are of limited help because they assume many things about the JPEGs they parse. Can anyone point me in the right direction?

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  • Are there cloud network drives that let users lock files or mark them as "in use"?

    - by Brandon Craig Rhodes
    Having spent several hours reading about the features and limitations of services like DropBox and Jungle Disk and the hundreds of competitors they seem to have (as though everyone with an AWS account these days goes ahead and writes a file sharing application just for fun), I have yet to find one that would let a team of people at a small business collaborate without stepping all over each other's toes. At a small business there are often many small documents per project — estimates, contracts, project plans, budgets — and team members frequently have to open and edit them, with all sorts of problems happening if two people edit a file at once. Even if a sharing service is smart enough to keep both versions of the file created, most small-business software (like word processors, spreadsheets, estimating software, or billing systems) has no way to compare — much less to merge! — the changes in two rival versions of a file that two people edited at the same time without each other's knowledge. So, my question: are their cloud-based file sharing solutions that not only provide a virtual network drive that people can access, but that also let users lock files — even if it's not a real lock but just a flag or indicator — that could possibly prevent remote workers from both editing the same file at once? Having one person wait for another person to finish editing is a very, very small inconvenience compared to the hour or more than it can take to compare two estimates by hand until you find and resolve the rival changes. Given this fact, I am surprised that almost none of the popular file sharing solutions seem to recognize this problem and provide some solution! Does anyone know of a service that does?

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  • Are there cloud network drives that let users lock files or mark them as "in use"?

    - by Brandon Craig Rhodes
    Having spent several hours reading about the features and limitations of services like DropBox and Jungle Disk and the hundreds of competitors they seem to have (as though everyone with an AWS account these days goes ahead and writes a file sharing application just for fun), I have yet to find one that would let a team of people at a small business collaborate without stepping all over each other's toes. At a small business there are often many small documents per project — estimates, contracts, project plans, budgets — and team members frequently have to open and edit them, with all sorts of problems happening if two people edit a file at once. Even if a sharing service is smart enough to keep both versions of the file created, most small-business software (like word processors, spreadsheets, estimating software, or billing systems) has no way to compare — much less to merge! — the changes in two rival versions of a file that two people edited at the same time without each other's knowledge. So, my question: are their cloud-based file sharing solutions that not only provide a virtual network drive that people can access, but that also let users lock files — even if it's not a real lock but just a flag or indicator — that could possibly prevent remote workers from both editing the same file at once? Having one person wait for another person to finish editing is a very, very small inconvenience compared to the hour or more than it can take to compare two estimates by hand until you find and resolve the rival changes. Given this fact, I am surprised that almost none of the popular file sharing solutions seem to recognize this problem and provide some solution! Does anyone know of a service that does?

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  • Unlock a file with unlocker from a WinForms App?

    - by netadictos
    I am trying to unlock a file from a C# program, using unlocker. In my UI, I put a button to unlock the file the app couldn't delete. When the user pushes the button, I want unlocker (the famous app) to be opened. I have read about in the Unlocker web, and there is some explanations about the commandline to use but nothing works. I write the following code but nothing happens: "c:\Program Files\unlocker\unlocker.exe" -L "PATHFORTHEFILE.doc" Nothing happens. I have tried without parameters and with -LU. Any idea? Something more efficient than unlocker to integrate it with software?

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  • How can I read/write data from a file?

    - by samy
    I'm writing a simple chrome extension. I need to create the ability to add sites URLs to a list, or read from the list. I use the list to open the sites in the new tabs. I'm looking for a way to have a data file I can write to, and read from. I was thinking on XML. I read there is a problem changing the content of files with Javascript. Is XML the right choice for this kinda thing? I should add that there is no web server, and the app will run locally, so maybe the problem websites are having are not same as this. Before I wrote this question, I tried one thing, and started to feel insecure because it didn't work. I made a XML file called Site.xml: <?xml version="1.0" encoding="utf-8" ?> <Sites> <site> <url> http://www.sulamacademy.com/AddMsgForum.asp?FType=273171&SBLang=0&WSUAccess=0&LocSBID=20375 </url> </site> <site> <url> http://www.wow.co.il </url> </site> <site> <url> http://www.Google.co.il </url> </site> I made this script to read the data from him, and put in on the html file. function LoadXML() { var ajaxObj = new XMLHttpRequest(); ajaxObj.open('GET', 'Sites.xml', false); ajaxObj.send(); var myXML = ajaxObj.responseXML; document.write('<table border="2">'); var prs = myXML.getElementsByTagName("site"); for (i = 0; i < prs.length; i++) { document.write("<tr><td>"); document.write(prs[i].getElementsByName("url")[0].childNode[0].nodeValue); document.write("</td></tr>"); } document.write("</table"); }

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  • Filesystem fragmentation on the level of set of files

    - by trismarck
    The file is stored in blocks by the file system. The block is the smallest amount of data the file system can assign to store a file. The classical definition of a fragmented file is that the file is stored in blocks that are 'scattered' (that are physically non-contiguous) around the hard drive. What I want to ask about is this second type of fragmentation I've came up with. Lets suppose we install a program. This program has very many files. When the program starts, the program always loads the contents of those files sequentially. Now, even if the hard disk is defragmented, there is still a possibility that the files (but not the blocks building up to files) will be scattered on the disk and thus the program launch time will be longer. Actually, this time could be longer due to defragmentation of the disk, as the defragmentation process not only glues fragmented files but also moves some files to optimize free space chunks. The questions: is the type of fragmentation I mentioned relevant for the file system? is it possible to remedy this kind of fragmentation and if yes, how would you do it? Also, I'm not sure if this question should belong to superuser or to serverfault (as I guess the filesystem fragmentation is more important in the server environment).

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  • plupload not working in wordpress theme files

    - by Kedar B
    This is my code for image upload.... <a id="aaiu-uploader" class="aaiu_button" href="#"><?php _e('*Select Images (mandatory)','wpestate');?></a> <input type="hidden" name="attachid" id="attachid" value="<?php echo $attachid;?>"> <input type="hidden" name="attachthumb" id="attachthumb" value="<? php echo $thumbid;?>"> i want upload functionality more than one time in single page in wordpress.i have add js code for that same as first upload block but its not working. This is js code for image upload.... jQuery(document).ready(function($) { "use strict"; if (typeof(plupload) !== 'undefined') { var uploader = new plupload.Uploader(ajax_vars.plupload); uploader.init(); uploader.bind('FilesAdded', function (up, files) { $.each(files, function (i, file) { // console.log('append'+file.id ); $('#aaiu-upload-imagelist').append( '<div id="' + file.id + '">' + file.name + ' (' + plupload.formatSize(file.size) + ') <b></b>' + '</div>'); }); up.refresh(); // Reposition Flash/Silverlight uploader.start(); }); uploader.bind('UploadProgress', function (up, file) { $('#' + file.id + " b").html(file.percent + "%"); }); // On erro occur uploader.bind('Error', function (up, err) { $('#aaiu-upload-imagelist').append("<div>Error: " + err.code + ", Message: " + err.message + (err.file ? ", File: " + err.file.name : "") + "</div>" ); up.refresh(); // Reposition Flash/Silverlight }); uploader.bind('FileUploaded', function (up, file, response) { var result = $.parseJSON(response.response); // console.log(result); $('#' + file.id).remove(); if (result.success) { $('#profile-image').css('background-image','url("'+result.html+'")'); $('#profile-image').attr('data-profileurl',result.html); $('#profile-image_id').val(result.attach); var all_id=$('#attachid').val(); all_id=all_id+","+result.attach; $('#attachid').val(all_id); $('#imagelist').append('<div class="uploaded_images" data- imageid="'+result.attach+'"><img src="'+result.html+'" alt="thumb" /><i class="fa deleter fa-trash-o"></i> </div>'); delete_binder(); thumb_setter(); } }); $('#aaiu-uploader').click(function (e) { uploader.start(); e.preventDefault(); }); $('#aaiu-uploader2').click(function (e) { uploader.start(); e.preventDefault(); }); } });

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  • How do file references within a PHP Objects work?

    - by bender
    I'm trying to create an PHP object that can load objects in other files on demand when needed. My problem is that when I reference the files based on file location for the class definition, it can not find the files. So file structure: /Test.php /os/os.php (extends kernel) /os/kernel.php /os/libraries/lib1.php /os/libraries/lib2.php /os/libraries/lib3.php In kernel.php, the libraries are referenced as 'libraries/lib1.php'. If I create an "os" object in Test.php. The lib files are not found.

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  • How to save Chinese Characters to file with java ?

    - by Frank
    I use the following code to save Chinese characters into a .txt file, but when I opened it with wordpad, I can't read it. StringBuffer Shanghai_StrBuf=new StringBuffer("\u4E0A\u6D77"); boolean Append=true; FileOutputStream fos; fos=new FileOutputStream(FileName,Append); for (int i=0;i<Shanghai_StrBuf.length();i++) fos.write(Shanghai_StrBuf.charAt(i)); fos.close(); What can I do ? I know if I cut and paste Chinese characters into a wordpad I can save it into a .txt file. How to do that with java ?

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  • How to remove the file extension in a zsh completion?

    - by meeselet
    I want to adjust zsh so that I can tab complete: myprog <tab> using all *.foo files in ~/somedir, but have it so that it displays them without the .foo extension. Is there any way to do this? This is what I have so far: #compdef myprog typeset -A opt_args local context state line local -a mydirs mydirs="(. ~/somedir)" _arguments -s -S \ "*:name:->foos" \ && return 0 case $state in (foos) _files -W ${mydirs} -g '*.foo(:r)' && return 0 ;; esac return 1 However, this displays double the output for every file (that is, each .foo file is listed with and without its extension). Is there any way around this?

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  • Unlock a file with unlocker from a c# App?

    - by netadictos
    I am trying to unlock a file from a C# program, using unlocker. In my UI, I put a button to unlock the file the app couldn't delete. When the user pushes the button, I want unlocker (the famous app) to be opened. I have read about in the Unlocker web, and there is some explanations about the commandline to use but nothing works. I write the following code but nothing happens: "c:\Program Files\unlocker\unlocker.exe" -L "PATHFORTHEFILE.doc" Nothing happens. I have tried without parameters and with -LU. Any idea? Something more efficient than unlocker to integrate it with software?

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  • What ASP.NET Web Config entries could limit certain file access by date and time?

    - by Dr. Zim
    What entries in a web.config could allow certain files to become publicly accessible after a certain date and time? Specifically, we have these files starting with AB_.jpg where the _ could be anything. We put them in a folder on April 27th for example, but they shouldn't be accessible until April 30th at 11:59:59 PM. I think the web.config in part works like Unix's FTP .htaccess file to define file security. For example, this web.config entry allows directory browsing: <?xml version="1.0" encoding="UTF-8"?> <configuration> <system.webServer> <directoryBrowse enabled="true" /> </system.webServer> </configuration>

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  • Append to a file in Java. Is it a joke?

    - by Roman
    I need to append some data to existing file. I started to browse Internet to find out how to do it. And I found this mini (as they say) application to do that: http://www.devdaily.com/java/edu/qanda/pjqa00009.shtml Well I was already annoyed by the fact how complicated are things in Java (in comparison with Python, for example). But this is too much! I just want to add to a file! It should be one line! Not 50! Or do I get something wrong?

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  • Writing a simple batch file to setup a variable?

    - by Sam
    I want to write a simple batch file where i want to setup a environment variable based on the machine architecture. It is as below: set ARCH=%PROCESSOR_ARCHITECTURE% echo %ARCH% if %ARCH%==x86 ( set JAVA_ROOT=C:\Progra~1\Java\j2re1.4.2_13 ) else ( set JAVA_ROOT=C:\Progra~2\Java\j2re1.4.2_13 ) echo JAVA_ROOT is %JAVA_ROOT% On 64-bit machine where the architecture is 'AMD64' the JAVA_ROOT will be displayed as 'C:\Progra~2\Java\j2re1.4.2_13' at the echo statement. But when i run an application that uses this file, the first value of JAVA_ROOT would be picked up 'C:\Progra~1\Java\j2re1.4.2_13'. I don't have any idea why it goes in the 'if' part even though i am running this on 64-bit Windows7. When i echoed the

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  • Setting umask for all users

    - by Yarin
    I'm trying to set the default umask to 002 for all users including root on my CentOS box. According to this and other answers, this can be achieved by editing /etc/profile. However the comments at the top of that file say: It's NOT a good idea to change this file unless you know what you are doing. It's much better to create a custom.sh shell script in /etc/profile.d/ to make custom changes to your environment, as this will prevent the need for merging in future updates. So I went ahead and created the following file: /etc/profile.d/myapp.sh with the single line: umask 002 Now, when I create a file logged in as root, the file is born with 664 permissions, the way I had hoped. But files created by my Apache wsgi application, or files created with sudo, still default to 644 permissions... $ touch newfile (as root): Result = 664 (Works) $ sudo touch newfile: Result = 644 (Doesn't work) Files created by Apache wsgi app: Result = 644 (Doesn't work) Files created by Python's RotatingFileHandler: Result = 644 (Doesn't work) Why is this happening, and how can I ensure 664 file permissions system wide, no matter what creates the file? UPDATE: I ended up finding a cleaner solution to this on a per-directory basis using ACLs, which I describe here.

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