Search Results

Search found 34595 results on 1384 pages for 'form post'.

Page 98/1384 | < Previous Page | 94 95 96 97 98 99 100 101 102 103 104 105  | Next Page >

  • jQuery $.post & $.append & IE6

    - by Jim
    I'm having a weird problem with jQuery and IE6. Script works on IE7+ and with all other browsers I have tried it. I can't post the full script, but what it does is this: $.post("file.php",{'foo':'bar'},function(data){ $('#target').append(data) }) When I run the code in IE6, #target just shows ? and a white char with a hole in the middle. I have no idea what this second char is. My initial thought was that this was some sort of content-type problem because the file.php just echoes answer without any header information. I added Content-type: text/html with header() but didn't help. Any suggestions?

    Read the article

  • jQuery blockUI and AJAX POST

    - by oompahloompah
    I am using jQuery BlockUI in a project. For a particular user action, I want to block the UI, and then POST data to the server. When the timeout event occurs OR the server returns, I want to unblock the page. I can't seem to implement this behaviour. This is what I have so far (not working) $(document).ready(function(){ $('#test').click(function(event){ $.blockUI({ message: $('#syntax-chk') }); $.ajax({ type: 'POST', url: 'www.example.com', data: somedata, dataType: "json" }); setTimeout(function() { $.unblockUI({ onUnblock: function(){ alert('onUnblock'); } }); }, 2000); }); can anyone spot what I may be doing wrong?

    Read the article

  • list all likes to a certain post coming from my friends

    - by Max Favilli
    I know I can get posts (paginated, 25 at times) of a certain user with this: https://graph.facebook.com/575128756/posts And the likes of a certain post (paginated, 25 at times) with this GRAPH api call (I omit the first part of the url): /575128756_176517292390301/likes But if I want to get the likes from friends of the post user only? FQL could be an alternative (from table like and subqueries for friend and stream), but FQL seems so buggy in my tests I don't feel comfortable using it in a productive system. Is there anyway to achieve my target using the GRAPH api?

    Read the article

  • cannot set a variable to base on user input post method

    - by user1318960
    Hello i´m trying to set info from a post method into a variable that sets a session named name the value that the user input. I get the following error: Notice: Undefined index: name in F:\xampp\htdocs\Impossible game\index.php on line 18 This is line 18: $session = $_POST['name']; <form action="ms1.php" method="POST"> Name <input type="text" name="name"> <input type="Submit" value="Begin"> </form> <?php $session = $_POST['name']; session_start(); $_SESSION['name'] = $session;

    Read the article

  • How to post XML document to HTTP with VB.Net

    - by Joshua McGinnis
    I'm looking for help with posting my XML document to a url in VB.NET. Here's what I have so far ... Public Shared xml As New System.Xml.XmlDocument() Public Shared Sub Main() Dim root As XmlElement root = xml.CreateElement("root") xml.AppendChild(root) Dim username As XmlElement username = xml.CreateElement("username") username.InnerText = _username root.AppendChild(username) xml.Save(Console.Out) Dim url = "https://mydomain.com" Dim req As WebRequest = WebRequest.Create(url) req.Method = "POST" req.ContentType = "application/xml" req.Headers.Add("Custom: API_Method") Console.WriteLine(req.Headers.ToString()) This is where things go awry: I want to post the xml, and then print the results to console. Dim newStream As Stream = req.GetRequestStream() xml.Save(newStream) Dim response As WebResponse = req.GetResponse() Console.WriteLine(response.ToString()) End Sub

    Read the article

  • What could trigger a change of http status to 500 on the client's end?

    - by VexedPanda
    We have a PHP web application that posts data to itself, and either displays an updated page based on that data, or redirects to another page. An example of this is a script with a paged list on it, where clicking on the Next link causes a post to the same page, which then returns an updated version of the page showing the new set of list items. One client is reporting that IE is displaying friendly error messages when the page updates itself instead of the correct behavior of displaying the updated page. Turning friendly error messages off "corrects" this problem, and displays the updated page normally, indicating no actual server error occurred. When testing from any location other than this client's our web app does not produce any http error statuses, and in this specific situation only produces 200 statuses. (According to Fiddler.) What could be interfering with the HTTP POST and changing the response's http status code to 500 (or another code that would trigger friendly errors in IE)? Are there certain proxies or other network tools that could be misconfigured or buggy in this manner? Is there any way we can alter our application (apart from avoiding posts to the same script, which is not feasible) to get around this misbehavior?

    Read the article

  • JQuery post to php

    - by RussP
    Why is it that I can never get JQuery serialize to work properly. I guess I must be missing something. I can serialize a form data and it shows in an alert: var forminfo = $j('#frmuserinfo').serialize(); alert(forminfo); I then post to my PHP page thus: $j.ajax({ type: "POST", url: "cv-user-process.php", data: "forminfo="+forminfo, cache: false, complete: function(data) { } }); But WHENEVER (not the first time) I try to insert/update the data in the DB I only ever get 1 varaible passed: Here is my PHP script: $testit = mysql_query("UPDATE cv_usersmeta SET inputtest='".$_POST['forminfo']."' WHERE user='X'"); the data passed only ever gets the first variable. why? I think it is more the way I deal with the php but it drives me nuts and always takes me far too long to find where I am going wrong.

    Read the article

  • Post-back + Page Refresh. Post/Redirect/Get pattern alternatives?

    - by Andrew Florko
    When user posts back a web form and then tries to refresh the page - dialog "would you like to resend information" pops up (Opera works silently though). To avoid this we can redirect browser to the page we'd like to show after postback. Now, when user refreshes the page, he duplicates get-request and no pop-ups. Everything is ok but post/redirect/get approach requires additional roundtrip. Is there better alternatives. Send form data with ajax aynchronously, for example? Thank you in advance!

    Read the article

  • WHY HAVE YOU ROMOVED MY POST? [closed]

    - by Eddy Freeman
    I posted a question about how to rotate a tile in BufferedImage. I did it in the morning and you removed it. Why have you removed it again? What is wrong with the posts? Tell me before i become angry. You have removed the post twice without informing/telling me the problem. with the posts What is wrong? Tell me. Reply to this post and tell me what is wrong.

    Read the article

  • ajax post sending parameter failed

    - by kawtousse
    hi, in order to send to servlet parameter in post methos i am using ajax like the following: var xhr = getXhr(); xhr.onreadystatechange = function(){ if(xhr.readyState == 4 && xhr.status == 200) {alert("ok"); } }; xhr.open("POST","ServletEdition",true); xhr.setRequestHeader('Content-Type','application/x-www-form-urlencoded'); id = document.getElementById('idIdden').value; xhr.send("id="+id) In the servet the following: String hd=request.getParameter("id"); System.out.println("idDailyTimeSheet est::" +hd); But it failes every time and the problem that i didn't see the cause. thanks

    Read the article

  • php cURL POST how to follow location

    - by One Stuck Pixel
    I am in a bit of a rut with a cURL issue. The post works greate, the data is POSTED just fine and received ok, but the url of the posted page never appears in the browser after the cURL session is executed, for example look at the following code: $ch = curl_init("http://localhost/eterniti/cart-step-1.php"); curl_setopt($ch, CURLOPT_HEADER, false); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, "error=1&em=$em&fname=$fname&lname=$lname&email1=$email1&email2=$email2&code=$code&area=$area&number=$num&mobile=$mobile&address1=$address1&address2=$address2&address3=$address3&suburb=$suburb&postcode=$postcode&country=$country"); curl_exec($ch); curl_close($ch); The post works fine and I am taken to the cart-step-1.php where I can process the posted data, HOWEVER the location in the URL address bar of the browser remains that of the script page, in this case proc_xxxxxx.php Any ideas how to get the URL address to reflect the page I am actually POSTED to? Thanks a mill

    Read the article

  • Post and Comment with the same Model.

    - by xRobot
    I have created a simple project where everyone can create one or more Blog. I want to use this models for Post and for Comment: class Post_comment(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField(_('object ID')) content_object = generic.GenericForeignKey() # Hierarchy Field parent = models.ForeignKey('self', null=True, blank=True, default=None, related_name='children') # User Field user = models.ForeignKey(User) # Date Fields date_submitted = models.DateTimeField(_('date/time submitted'), default = datetime.now) date_modified = models.DateTimeField(_('date/time modified'), default = datetime.now) title = models.CharField(_('title'), max_length=60, blank=True, null=True) post_comment = models.TextField(_('post_comment')) markup = models.IntegerField(choices=MARKUP_CHOICES, default=DEFAULT_MARKUP, null=True, blank=True) if it is a comment the parent is not null. So in most case the text field will contain a little bit of text. Can I use this model for both Post and Comment ?

    Read the article

  • Post values in PHP Headers

    - by kumar
    Hi.. I want send some data to a remote webpage from my site. Actually it can be achieved through form hidden variables. but for security reason, i want set as post variables in header and then send to that webpage. i use this code $post_data = 'var1=123&var2=456'; $content_length = strlen($post_data); header('POST http://localhost/testing/test.php HTTP/1.1'); header('Host: localhost'); header('Connection: close'); header('Content-type: application/x-www-form-urlencoded'); header('Content-length: ' . $content_length); header($post_data); but my code doesn't work properly. help me...

    Read the article

  • display result in status after it post

    - by nisardotnet
    my question is continuation of what i have posted here i want to know how to display a result status based on my return result from Web Method here is my post code: beforeSubmit: function(data) { var myData = { "firstName": escape($('#txtFirstName').val()), "lastName": escape($('#txtLastName').val()) }; $.ajax(<br> { type: "POST", url: "VisitorWS.asmx/AddVisitors", data: JSON.stringify(myData), contentType: "application/json; charset=utf-8", dataType: "json", success: function(data) { $("#status").fadeTo(500, 1, function() { $(this).html("You are now registered!").fadeTo(5000, 0); }) }, error: function(data) { $("#status").fadeTo(5000, 1, function() { $(this).html("Failed!").fadeTo(5000, 0); }) } }); WebMethod [WebMethod] public bool AddVisitors(string firstName, string lastName) { if (firstName == "test") { return true; } return false; } so based on true or false i want to display a message on the client side.

    Read the article

  • jquery, ajax, load post result to div

    - by mike
    Hello, I have a form that I need to post and show the result in a div. I'm not having any problems making the ajax call but I can't seem to figure out how to load the result to a div. I have tried: $.ajax({ type: 'POST', data: $('#someForm').serialize(), url: 'http://somedomain.com/my/url', success: function(data) { $('#someDiv').load(data); } }); but it does not seem to work properly. I'm nit sure if this should even work but the result is the the page i'm posting from being loaded into the div and not the url I'm posting to. Any help would be great! Thanks!

    Read the article

  • post selextbox values to php page in jquery

    - by JPro
    I am using jquery button click to post all the values in a selectbox to a PHP page, but this code does not seem to work. Can anyone please help? <script type="text/javascript"> $(function() { $("#btn1").click(function () { var arr= new Array; $("#target_select option").each (function () { // You can push the array on an array arr.push( $(this).val() ); //alert( $(this).val() ); not getting the alert to display too }); $.post("test.php", { name: arr } ); }); }); </script> Generate

    Read the article

  • PHP Form (post) Repeating input in a tabel

    - by Sef
    Hello, I have a form (with post method) that takes the following input: - a certain name - a number - 3 checkboxes All this input gets generated and calculated in a table.(html code within the php) Everything gets properly calculated and displayed in a table. So my question: How do i make it possible after giving all those input to give in more input? Meaning i have made a hyperlink that goes back to the form itself (where i can give the input). So i can give in new data, and after submiting that again the table now contains 2 rows of values insteed of just 1. Not really sure what exactly i need for this. Regards.

    Read the article

  • Uploading files using HTTP Post Request

    - by Nakago
    Hi All, I want to upload files to a server which is also owned by me. I could think of two ways, of how this can be achieved. Method1: Use HTTP POST request to upload the files. The standard way of uploading files. Method2: Its a two step process. First the client does a POST request with all the details of the file, to the server. Then the server issues Get request(s) onto the client to get the contents of the file. Here method2 seems to be more secure, as the server is in control. The server can request data from the server only when the server feels it to be appropriate, and restrict the amount of data that needs to be transferred. Still i am confused as i am not an expert in this area. Anyone with more hindsight thoughts on this can you please share. Thanks

    Read the article

  • InputStreamBody in HttpMime 4.0.3 settings for content-length

    - by Ram
    I am trying to send a multi part formdata post through my java code. Can someone tell me how to set Content Length in the following?? There seem to be headers involved when we use InputStreamBody which implements the ContentDescriptor interface. Doing a getContentLength on the InputStreamBody gives me -1 after i add the content. I subclassed it to give contentLength the length of my byte array but am not sure if other headers required by ContentDescriptor will be set for a proper POST. HttpClient httpclient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(myURL); ContentBody cb = new InputStreamBody(new ByteArrayInputStream(bytearray), myMimeType, filename); //ContentBody cb = new ByteArrayBody(bytearray, myMimeType, filename); MultipartEntity mpentity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE); mpentity.addPart("key", new StringBody("SOME_KEY")); mpentity.addPart("output", new StringBody("SOME_NAME")); mpentity.addPart("content", cb); httpPost.setEntity(mpentity); HttpResponse response = httpclient.execute(httpPost); HttpEntity resEntity = response.getEntity();

    Read the article

  • Java - Post to Twitter

    - by Ibolit
    Hi. I've written a simple web application, which i want to post tweets. I have seen some java libraries for working with twitter, and they all seem like too much of work for something that seemingly simple. But it is possible that i am missing something. And I am yet to make any of them work... Is there any simple way to post a tweet in twitter from a web-app in java with only a few lines of code? Thank you very much.

    Read the article

  • Customizing the post to facebook in Sharekit2.0

    - by laksh
    I have integrated the latest code in sharekit into my project. I am able to click in to go to the facebook and able to see the text i am going to post. The image looks like this: I would like to change two things. Firstly, I am not able to see the cancel or post button because of my app picture at top. So i would like to set the view to be scrollable. How do i change that? Secondly, I would like to remove the keyboard after i press return, or i want a way to remove the keyboard. Need some help on this..Thanks..

    Read the article

< Previous Page | 94 95 96 97 98 99 100 101 102 103 104 105  | Next Page >